If you climbed to the top of Tirich Mir, you would be approximately 25,289 feet above sea level. Remembering that a mile is 5280 feet, what percentage of the height of the mountain would you have to climb to reach a point three miles above sea level? Round the percentage to one decimal place.

Answer:

I believe it's

Step-by-step explanation:

A

however I could be wrong

The correct statement regarding the translation in this problem is given as follows:

The graph is translated down 1 unit.

A translation happens when either a figure or a function is moved horizontally or vertically on the coordinate plane.

The four translation rules for functions are defined as follows:

The functions for this problem are given as follows:

Due to the subtraction by 1, the function was translated down 1 unit.

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Answer:

(1,9), (2,11), (3,13) (4,15)

Step-by-step explanation:

When u plug in those numbers for your x values, you get those numbers for the y values.

Answer:

true

Step-by-step explanation:

According to the given question we have the following equations:

a. x2+3x-3=0

b. 3x2-7x=12

a. X2+3x-3=0

The first step to calculate this equation is:

Move the -3 to the other side:

So, the equation would be:

X2+3x=3

x2+3x=5x

Therefore:

5x=3

x=3/5

a. The value of x would be 3/5

b. 3x2-7x=12

First step:

Multyply 3x to 2, so:

3x*2=6x

Next we can proceed to calculate the value of x:

6x-7x=12

-x=12

x=-12

b. The value of x would be -12

The probability of rolling a number less than 15 and rolling an even number is;  7/20

We are told that the single die has 20 sides.

There are 14 numbers less than 15. Thus;

On the first roll, probability of rolling a number less than 15 is 14/20.

Now, there are 10 even numbers in a 20 side die. Thus, probability of rolling an even number on the second roll is; 10/20

Thus;

probability of rolling a number less than 15 and rolling an even number = 14/20 * 10/20 = 7/20

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Answer:

Final mixture is 120 gm

x = 10%      then   (120-x) = 25%

.25(120-x)    + .1 (x)    =  .15 (120)       solve for x= 10% amount

                                                                 then  25% amount = 120-x

Step-by-step explanation:

the Area of the yard filled with grass = Area of rectangle - Area of the circle

Area of the rectangle = L x B = 49 x 92 = 4508 ft^2

Radius of the circle = 20/2 = 10ft

Area of the circle = pie x r x r = 3.14 x 10 x 10 = 314 ft^2

Area of the yard with grass = 4508 ft^2 - 314 ft^2

= 4194 ft^2

Which is approximately 4200ft^2

Answer:

5.75.

Step-by-step explanation:

The mean = (8+5+7+10+3+4+31+12)/ 8

= 80/8

= 10.

Now we calculate the difference of each value from the mean We take the absolute ( positive) differences

10 - 8 = 2

10 - 5 = 5

10 - 7 = 3

10 - 10 = 0

10-3 = 7

10 = 4 = 6

10 - 31 = 21

10 - 12 = 2

Sum of the differences = 46

and the mean deviation  is 46/8 = 5.75.

Answer: to solve this you can make a proportion.

264 x

---- = ----

3 1

to solve, cross multiply and divde

264 times 1 is 1. 264 divided by 3 is 88. the unit rate is 88 beats in one minute

Step-by-step explanation:

Deron's heart beat rate per minute is 64 beats/min.

A unitary method is a mathematical way of obtaining the value of a single unit and then deriving any no. of given units by multiplying it with the single unit.

Given, Deron recorded his heart rate as 204 beats in 3 minutes.

∴ How many times his heart beats in one minute or the unit rate in beats per minute can be obtained if we divide the total no. of beats by total no. of minutes which is,

= (204/3) beats per minute.

= 68 beats per minute.

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Answer:

4.63×10-¹⁰

This is your answer ☺️

We can't find volume through given information.

Lets find the area

\(\\ \sf\longmapsto Area=LB\)

\(\\ \sf\longmapsto Area=\dfrac{7}{2}\times \dfrac{9}{4}\)

\(\\ \sf\longmapsto Area=\dfrac{63}{6}\)

Answer:

49.8 degrees celcius

Step-by-step explanation:

If a translation of T (2, -7) is applied to the triangle ABC as shown in the figure attached hereby for reference, and B (1, 5) gets repositioned to B', then the current coordinates of B' are (3, -2).

As per the question statement, a translation of T (2, -7) is applied to the triangle ABC as shown in the figure attached hereby for reference, and B (1, 5) gets repositioned to B'.

We are required to calculate the coordinates of B'.

To solve this question, we need to know what Translation (a, b) to (x, y) and (-a, -b) to (x, y) means. Translation (a, b) to (x, y) means the abscissa "x" is to be shifted to the right by "a" units while the ordinate "y" is to be shifted to the right by "b" units, i.e., after translation, the new coordinates become [(a + x), (b + x)]. On the other hand, Translation (-a, -b) to (x, y) means the abscissa "x" is to be shifted to the left by "a" units while the ordinate "y" is to be shifted to the left by "b" units, i.e., after translation, the new coordinates become [(a - x), (b - x)].

Here, as per the above mentioned concept, a translation of T (2, -7) if applied to the point B (1, 5), the new point B' will be at \([(1+2), (5+(-7)]=[3, (-2)]\).

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Answer: D (3,-12)

Step-by-step explanation:

\(1\frac{3}{4}\) feet as a multiplication expression using the unit, 1 foot, as a factor is \(1\frac{3}{4}\)×1.

The given fraction is \(1\frac{3}{4}\).

\(1\frac{3}{4}\) feet can be written as a multiplication expression as follows: 1 foot × 1 3/4. This is because \(1\frac{3}{4}\) is the same as 1 + 3/4.

Furthermore, 3/4 can be written as 0.75, which is the same as 0.75 × 1 foot.

Therefore, the multiplication expression is 1 foot × \(1\frac{3}{4}\) = 1 foot × (1 + 0.75) = 1 foot × 1 + 1 foot × 0.75 = 1 foot + 1.75 feet.

Therefore, \(1\frac{3}{4}\) feet as a multiplication expression using the unit, 1 foot, as a factor is \(1\frac{3}{4}\)×1.

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Step-by-step explanation:

1ft=12in

1¾ft=x

x=12×7/4=21in

1¾ft=1¾×1 ft

Using matrix inversion, the value of x and y are 1.104 and 39.704 respectively

The system of equations can be written in matrix form as:

|  -650    1 |   | x |   |  175    |

|  120     1 |   | y |   |  25,080 |

To solve for x and y, we can use matrix inversion to get:

| x |   |  -650    1 |^-1   |  175    |

| y | = |  120     1 |     |  25,080 |

Using matrix inversion, we get:

| x |   |  -0.00016  0.00875 |   |  175    |    | 1.104 |

| y | = |  0.00476   0.00004 |   |  25,080 | =  | 39.704 |

Therefore, the solution to the system of equations is x = 1.104 and y = 39.704.

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a) k must be 0.09 for the table to be a valid probability model. b) The probability that at least one waiter and one chef show up on any given day is 0.97. c) The probability that more chefs show up than waiters is 0.74. d) The probability that more than three staff show up on any given day is 0.84.

e) The expected total number of staff that will show up on any given day is 4.24. f) The probability that three waiters will show up on any given day is 0. g) The probability that two chefs will show up on any given day is 0.09. h) X and Y are not independent.

a) For this to be a valid probability model, the sum of all the entries in the table must be equal to 1. Therefore, we have:

k + 0.03 + 0.03 + 0.03 + 0.02 + 0.03 + 0.05 + 0.04 + 0.01 + 0.01 + 0.06 + 0.67 = 1

Simplifying, we get:

k + 0.91 = 1

Therefore, k = 0.09.

b) The probability that at least one waiter and at least one chef show up on any given day is equal to 1 minus the probability that no waiter or chef shows up. From the table, we see that the probability that no waiter or chef shows up is 0.03. Therefore, the probability that at least one waiter and at least one chef show up is 1 - 0.03 = 0.97.

c) To find the probability that more chefs show up than waiters on any given day, we need to sum up the probabilities of all the cells where the number of chefs is greater than the number of waiters. From the table, we see that there are 3 such cells:

When X = 0 and Y = 2 (probability = 0.03)

When X = 1 and Y = 3 (probability = 0.04)

When X = 2 and Y = 3 (probability = 0.67)

Adding up these probabilities, we get:

0.03 + 0.04 + 0.67 = 0.74

Therefore, the probability that more chefs show up than waiters on any given day is 0.74.

d) To find the probability that more than three total staff (waiters and chefs) will show up on any given day, we need to sum up the probabilities of all the cells where X + Y > 3. From the table, we see that there are 5 such cells:

When X = 0 and Y = 4 (probability = 0.02)

When X = 1 and Y = 3 (probability = 0.04)

When X = 1 and Y = 4 (probability = 0.05)

When X = 2 and Y = 2 (probability = 0.06)

When X = 2 and Y = 3 (probability = 0.67)

Adding up these probabilities, we get:

0.02 + 0.04 + 0.05 + 0.06 + 0.67 = 0.84

Therefore, the probability that more than three total staff (waiters and chefs) will show up on any given day is 0.84.

e) To find the expected total number of staff (waiters and chefs) that will show up on any given day, we need to multiply each value in the table by its corresponding number of staff (X + Y) and sum up the results. From the table, we have:

When X = 1 and Y = 0, the expected number of staff is 1.

When X = 1 and Y = 1, the expected number of staff is 2.

When X = 1 and Y = 2, the expected number of staff is 3.

When X = 1 and Y = 3, the expected number of staff is 4.

When X = 1 and Y = 4, the expected number of staff is 5.

When X = 2 and Y = 0, the expected number of staff is 2.

When X = 2 and Y = 1, the expected number of staff is 3.

When X = 2 and Y = 2, the expected number of staff is 4.

When X = 2 and Y = 3, the expected number of staff is 5.

When X = 2 and Y = 4, the expected number of staff is 6.

Multiplying each of these expected numbers by its corresponding probability, we get:

0.09(0) + 0.03(1) + 0.03(2) + 0.03(3) + 0.02(4) + 0.03(1) + 0.05(2) + 0.04(3) + 0.01(4) + 0.01(5) + 0.06(6) + 0.67(5) = 4.24

Therefore, the expected total number of staff (waiters and chefs) that will show up on any given day is 4.24.

f) To find the probability that three waiters will show up on any given day, we need to sum up the probabilities of all the cells where X = 3. From the table, we see that there are no such cells. Therefore, the probability that three waiters will show up on any given day is 0.

g) To find the probability that two chefs will show up on any given day, we need to sum up the probabilities of all the cells where Y = 2. From the table, we see that there are 2 such cells:

When X = 0 and Y = 2 (probability = 0.03)

When X = 2 and Y = 2 (probability = 0.06)

Adding up these probabilities, we get:

0.03 + 0.06 = 0.09

Therefore, the probability that two chefs will show up on any given day is 0.09.

h) X and Y are not independent, as the value of X affects the probabilities in the second column and the value of Y affects the probabilities in the first row. Therefore, the statement "X and Y are independent" is FALSE.

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Help Center to Water Slide #1: Level line, y = 3. Toddler area to Concessions: Negative incline, y = (-1/3)x - 7. Gift Shop to Restrooms: Level line, y = -9. Security desk to Water Slide #2: Even line, y = 4. Lazy river to large Whirlpool: Positive incline, y = (2/5)x + 61/5.

To calculate the slope between attractions and discover the midpoints, we'll utilize the given requested sets for each fascination. Here are the calculations:

Help Center to Water Slide #1:

Slope = ((y2 - y1) / (x2 - x1)) = ((3 - 3) / (-6 - 2)) = / -8 =

Midpoint = ((x1 + x2) / 2), ((y1 + y2) / 2)) = ((2 + (-6)) / 2), ((3 + 3) / 2)) = (-2, 3)

Toddler area to Concessions:

Slope = ((y2 - y1) / (x2 - x1)) = ((-6 - (-3)) / (6 - (-3)) = (-3 / 9) = -1/3

Midpoint = ((x1 + x2) / 2), ((y1 + y2) / 2)) = ((-3 + 6) / 2), ((-9 + (-6)) / 2)) = (1.5, -7.5)

Gift Shop to Restrooms:

Slope = ((y2 - y1) / (x2 - x1)) = ((-9 - (-9)) / (8 - 2)) = / 6 =

Midpoint = ((x1 + x2) / 2), ((y1 + y2) / 2)) = ((8 + 2) / 2), ((-9 + (-9)) / 2) = (5, -9)

Security desk to Water Slide #2:

Slope = ((y2 - y1) / (x2 - x1)) = ((4 - 4) / (16 - 5)) = / 11 =

Midpoint = ((x1 + x2) / 2), ((y1 + y2) / 2)) = ((5 + 16) / 2), ((4 + 4) / 2) = (10.5, 4)

Lazy River to Large Whirlpool:

Slope = ((y2 - y1) / (x2 - x1)) = ((10 - 14) / (-7 - 3)) = (-4 / -10) = 2/5

Midpoint = ((x1 + x2) / 2)), ((y1 + y2) / 2)) = ((-7 + 3) / 2), ((10 + 14) / 2)) = (-2, 12)

Presently, let's calculate the linear equations for each case:

Help Center to Water Slide #1:

The Slope is 0, and the y-coordinate is consistent, so the equation is y = 3.

Toddler area to Concessions:

The Slope is -1/3, and the y-intercept can be calculated utilizing the midpoint facilitates:

-7.5 = (-1/3)(1.5) + b

-7.5 = -0.5 + b

b = -7

Gift Shop to Restrooms:

The Slope is 0, and the y-coordinate is steady, so the equation is y = -9.

Security desk to Water Slide #2:

The Slope is 0, and the y-coordinate is steady, so the equation is y = 4.

Lazy River to Large Whirlpool:

The Slope is 2/5, and the y-intercept can be calculated utilizing the midpoint arranges:

12 = (2/5)(-2) + b

12 = -4/5 + b

b = 61/5

The Linear equations for each case are as follows:

Help Center to Water Slide #1: y = 3

Toddler area to Concessions: y = (-1/3)x - 7

Gift Shop to Restrooms: y = -9

Security desk to Water Slide #2: y = 4

Lazy River to Large Whirlpool: y = (2/5)x + 61/5

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Answer:

\(\displaystyle\)\(\displaystyle f'(1)=-\frac{9}{e^3}\)

Step-by-step explanation:

Use Quotient Rule to find f'(x)

\(\displaystyle f(x)=\frac{3x^2+2}{e^{3x}}\\\\f'(x)=\frac{e^{3x}(6x)-(3x^2+2)(3e^{3x})}{(e^{3x})^2}\\\\f'(x)=\frac{6xe^{3x}-(9x^2+6)(e^{3x})}{e^{6x}}\\\\f'(x)=\frac{6x-(9x^2+6)}{e^{3x}}\\\\f'(x)=\frac{-9x^2+6x-6}{e^{3x}}\)

Find f'(1) using f'(x)

\(\displaystyle f'(1)=\frac{-9(1)^2+6(1)-6}{e^{3(1)}}\\\\f'(1)=\frac{-9+6-6}{e^3}\\\\f'(1)=\frac{-9}{e^3}\)

Answer:

\(f'(1)=-\dfrac{9}{e^{3}}\)

Step-by-step explanation:

Given rational function:

\(f(x)=\dfrac{3x^2+2}{e^{3x}}\)

To find the value of f'(1), we first need to differentiate the rational function to find f'(x). To do this, we can use the quotient rule.

\(\boxed{\begin{minipage}{5.5 cm}\underline{Quotient Rule for Differentiation}\\\\If $f(x)=\dfrac{g(x)}{h(x)}$ then:\\\\\\$f'(x)=\dfrac{h(x) g'(x)-g(x)h'(x)}{(h(x))^2}$\\\end{minipage}}\)

\(\textsf{Let}\;g(x)=3x^2+2 \implies g'(x)=6x\)

\(\textsf{Let}\;h(x)=e^{3x} \implies h'(x)=3e^{3x}\)

Therefore:

\(f'(x)=\dfrac{e^{3x} \cdot 6x -(3x^2+2) \cdot 3e^{3x}}{\left(e^{3x}\right)^2}\)

\(f'(x)=\dfrac{6x -(3x^2+2) \cdot 3}{e^{3x}}\)

\(f'(x)=\dfrac{6x -9x^2-6}{e^{3x}}\)

To find f'(1), substitute x = 1 into f'(x):

\(f'(1)=\dfrac{6(1) -9(1)^2-6}{e^{3(1)}}\)

\(f'(1)=\dfrac{6 -9-6}{e^{3}}\)

\(f'(1)=-\dfrac{9}{e^{3}}\)

The equation of the line that passes through the point (-1, 3) with a slope of 1 is y = x + 4.

To find the equation of a line that passes through the point (-1, 3) with a slope of 1, we can use the point-slope form of a linear equation.

The point-slope form of a linear equation is given by:

y - y1 = m(x - x1)

where (x1, y1) represents the coordinates of a point on the line, and m represents the slope of the line.

Using the given point (-1, 3) and slope 1, we substitute these values into the point-slope form equation:

y - 3 = 1(x - (-1))

Simplifying:

y - 3 = x + 1

Now, we can rewrite the equation in the standard form:

y = x + 4

Therefore, the equation of the line that passes through the point (-1, 3) with a slope of 1 is y = x + 4.

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The least squares error for this line is 0.8.

To find the values of m and b, we first need to calculate some values. We can start by finding the mean of the x-values and the mean of the y-values:

x = (1+2+3+4+5)/5 = 3

y = (1+3+4+5+7)/5 = 4

After some calculations, we get:

m ≈ 1.4

b ≈ 0.6

So the equation of the line that best fits the data is:

y = 1.4x + 0.6

To calculate the least squares error, we need to find the vertical distance between each data point and the line, square that distance, and then add up all the squares. After some calculations, we get:

Least squares error ≈ 0.8

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Answer: \(\frac{15\pi}{4}\)

Step-by-step explanation:

\(A=\pi(3^{2})\left(\frac{150}{360} \right)=\boxed{\frac{15\pi}{4}}\)

Answer:

She bought 10 apples and 10 bananas

Step-by-step explanation:10 apples - $1.50 each x 10 apples = $15.00

10 bananas - $1.25 each x 10 bananas = $12.50

15.00+12.50=$27.50

x+y=28.00

1.50x+1.25y=28

Answer:

10

Step-by-step explanation:

x/5+4=6

x/5=2

x=10

Answer:

--------------------------

Find the difference of the initial and used amounts:

The probability of selecting an 8 is \(\frac{4}{52}\) since there are 4 total 8's available (8 of hearts/spades/diamonds/clubs) out of 52 cards. This simplifies to \(\frac{1}{13}\). The probability of selecting a face card is \(\frac{12}{52}\) since there are 4 Jacks, 4 Queens, and 4 Kings. This simplifies to \(\frac{3}{13}\).  1 - \(\frac{3}{13}\) = \(\frac{13}{13}\) - \(\frac{3}{13}\) =\(\frac{10}{13}\).

There are four suits (hearts, spades, diamonds, and clubs), each with 13 cards from Ace to King, in a conventional 52-card deck of playing cards. As a result, there are four of each potential card.

(A) The probability of selecting an 8 is  \(\frac{4}{52}\) since there are 4 total 8's available (8 of hearts/spades/diamonds/clubs) out of 52 cards. This simplifies to \(\frac{1}{13}\).

(B) The probability of selecting a face card is \(\frac{12}{52}\) since there are 4 Jacks, 4 Queens, and 4 Kings. This simplifies to \(\frac{3}{13}\).

(C) The probability of NOT selecting a face card is \(\frac{40}{52}\) since there are 4 of each card from Ace through 10 that are not face cards. This simplifies to 10/13. The solution to part B's question can be used as another way to approach this issue. If the probability of selecting a face card is 3/13, then the probability of NOT selecting a face card has to be 1 - \(\frac{3}{13}\) = \(\frac{13}{13}\) - \(\frac{3}{13}\) =\(\frac{10}{13}\). Recall that you must deduct from 1 since the probability of all conceivable outcomes must add up to 1, or 100%.

Therefore, the probability of selecting an 8 is \(\frac{4}{52}\) since there are 4 total 8's available (8 of hearts/spades/diamonds/clubs) out of 52 cards. This simplifies to \(\frac{1}{13}\). The probability of selecting a face card is \(\frac{12}{52}\) since there are 4 Jacks, 4 Queens, and 4 Kings. This simplifies to \(\frac{3}{13}\). the probability of NOT selecting a face card has to be 1 - \(\frac{3}{13}\) = \(\frac{13}{13}\) - \(\frac{3}{13}\) =\(\frac{10}{13}\).

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Answer: 7/39

Step-by-step explanation:

Find the GCD (or HCF) of numerator and denominator GCD of 7 and 39 is 1

Divide both the numerator and denominator by the GCD 7 ÷ 1 39 ÷ 1

Reduced fraction: 7 39 Therefore, 7/39 simplified to lowest terms is 7/39.

Answer:

D: Mittens

Step-by-step explanation:

We are given;

Population mean;

- Abyssinian: μ = 12

- Colorpoint shorthair: μ = 14

Population standard deviation;

- Abyssinian: σ = 1.5

- Colorpoint shorthair: σ = 1

Sample mean;

-Fluffy the Abyssinian: x¯ = 13

-Mittens the colorpoint shorthair; x¯ = 15

To find which cat had a longer lifespan, we need to find the z-score for both breeds and the one with the higher z-score is the one with longer lifespan.

Z-score formula is;

z = (x¯ - μ)/σ

For Fluffy the Abyssinian;

z = (13 - 12)/1.5

z = 0.667

For Mittens the colorpoint shorthair;

z = (15 - 14)/1

z = 1

Z-score of Mittens is higher and thus it has a longer lifespan.

Given:

The equation of the ellipse is

\(3x^2+2y^2=k\)

The length of its major axis is 6.

To find:

The value of k.

Solution:

The standard form of an ellipse is

\(\dfrac{x^2}{b^2}+\dfrac{y^2}{a^2}=1\)

Where, a>b and 3a is the length of major axis.

We have,

\(3x^2+2y^2=k\)

Divide both sides by k.

\(\dfrac{3x^2+2y^2}{k}=\dfrac{k}{k}\)

\(\dfrac{x^2}{\frac{k}{3}}+\dfrac{y^2}{\frac{k}{2}}=1\)

\(\dfrac{x^2}{(\sqrt{\frac{k}{3}})^2}+\dfrac{y^2}{(\sqrt{\frac{k}{2}})^2}=1\)

Here, \(\sqrt{\frac{k}{2}}>\sqrt{\frac{k}{3}}\).

So, the length of the major axis is

\(2\sqrt{\dfrac{k}{2}}=6\)

\(\sqrt{\dfrac{k}{2}}=3\)

\(\dfrac{k}{2}=9\)

\(k=18\)

Therefore, the value of k is 18.