if you changed the source wavelength to a longer wavelength, e.g. 600nm, how would the distance between the zero order maximum and the third order maximum change?

Answer: They create antibodies.

Answer:

The gravitational attraction between the sun earth and moon

Answer:

Copper isn't ferromagnetic,

Aluminum isn't ferromagnetic,

String has a ferromagnetic property

So in conclusion:

The answer is strings :)

You have all the info you need to solve for F, just plug everything in.

F = (8.99 × 10⁹ N•m²/C²) (6.0 × 10⁻¹⁰ C) (2.3 × 10⁻¹⁵ C) / (2 m)²

(You're missing the units on d, but I'll just assume meters.)

F ≈ 3.10 × 10⁻¹⁵ N

A radio wave travels at the speed of light, which is equal to approximately 300,000 km/s.

So, to travel a distance of 998.25 km, the time needed is:

Therefore the time required is approximately 3327.5 microseconds.

If I travel 300 meters North, then head back 350 meters South in 2 minutes, the average velocity is 5.42m/s.

Average velocity is the vector quantity that denotes the rate of change of position with respect to time, or a speed with the directional component.

This means that the average velocity can be calculated as follows:

Average velocity = distance/time

According to this question, if I travel 300 meters North, then head back 350 meters South in 2 minutes, the average velocity can be calculated as follows:

Average velocity = (350 + 300)/120

Average velocity = 650/120

Average velocity = 5.42m/s.

Therefore, If I travel 300 meters North, then head back 350 meters South in 2 minutes, the average velocity is 5.42m/s.

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Ansewer

A

Explanation:

Answer : B

Explanation: Right answer trust me!

Answer:

Therefore, the work done on the 45.6 kg rock that you lift 0.85 m is approximately 380.75 Joules.

Explanation:

The work done on an object is given by the formula:

work = force x distance x cos(theta)

where force is the applied force on the object, distance is the distance the object is moved, and theta is the angle between the force and the direction of motion. In this case, we can assume that the angle between the force and the direction of motion is zero degrees, since you are lifting the rock straight up.

The force required to lift the rock is equal to its weight, which is given by:

force = mass x gravity

where mass is the mass of the rock and gravity is the acceleration due to gravity, which is approximately 9.81 m/s^2 on the surface of the Earth.

Substituting the given values, we get:

force = 45.6 kg x 9.81 m/s^2 = 447.936 N

Now we can calculate the work done:

work = force x distance x cos(theta) = 447.936 N x 0.85 m x cos(0) = 380.7464 J

Therefore, the work done on the 45.6 kg rock that you lift 0.85 m is approximately 380.75 Joules.

Answer: Wavelength

Explanation:

Answer:

C) wavelength

Explanation:

I hope this is right, have a nice day!

Answer:

a: gas

b: solid

c: liquid

d: plasma

Explanation:

Answer:

Each image displays a different state of matter.

Use the drop-down menu to identify the state of matter represented by each image.

A:

✔ gas

B:

✔ solid

C:

✔ liquid

D:

✔ plasma

Explanation:

got it right

Answer:

I thinks its c

Explanation:

I hope this helps :)

Answer:

silk-ties fabric

rubber-rubber bands

cellulose-jeans

starch-food and paper

dna-genetic

Explanation:

The braking distance needed to halt on a dry surface is 40 or 55 feet.

For instance, you should be fine with a two-second buffer if your speed is less than 35 mph.A following three distance ought to be safe if your speed climbs to 35 to 45 mph, and a four-second gap should be used if you are traveling between 46 and 70 mph.

Explanation Your overall stopping distance at 45 mph will probably be 124 feet or less.If stopping your car there wouldn't be safe, you might want to slow down.

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Answer:

Explanation:

he force will depend on the masses of the rocks.

The formula you weren’t paying attention to in your Physics lesson was one of the more basic ones:

F = ma

F is the force. m is the mass of the object, and a is the acceleration. That’s all you should need.

Unfortunately, your question gave the weight of the rocks, not their masses. So, it can’t be answered without more information - eg is the rock on Earth, or on the moon, Mars or a planet orbiting Alpha Centauri?

If the rock is located on Earth, then you can use the same formula as above, because we know that a = g = 9.8m/s/s. and F is the weight. So, we know F, a and can work out m using a bit of basic algebra.

The other problem is that we don’t know the mass of the second piece of rock, because we haven’t been told either the weight or mass of that piece of rock.

If your homework question didn’t specify that, you can either refuse to answer it saying that not enough information was given, or STATE in your answer that you are assuming that the second piece of rock is the same mass as the first one.

If you decide to do that, then a minute’s work should give you the answer you’re looking for.

Answer:

Whether the object or fluid is moving, drag occurs as long as there is a difference in their velocities. Because it is resistant to motion, drag tends to slow down the object. An effective way to reduce it is to alter the shape of the object and make it streamline. Drag Force Examples of Drag Force

Explanation:

Answer:

sliding , static , rolling

Explanation:

HOPE IT WILL HELP YOU

Answer:

84.1 m

Explanation:

Δx = stopping distance = Vot + 1/2at²

find a (acceleration first):

a = ΔV/t = (0 - 26.5 m/s)/4.85 s = 5.46 m/s²

Δx = (26.5 m/s)(0.75s) + (1/2)(5.46 m/s²)(4.85 s)²

Δx = 19.9 m + 64.2 m = 84.1 m

You will hit the car!  During the 0.75 s reaction time, you've already gone 19.9 m, then you need another 64.2 m to come to a complete stop.

If you stay on or near the surface of Earth, then the acceleration due to gravity

is constant.  It's 9.807 meters per second squared. (rounded)

\(▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪\)

A solar flare is believed to occur when energy, stored in a twist in the solar magnetic field above a sunspot, is suddenly released.

The intensity of sunlight at Jupiter is approximately 0.048 kW/m².Jupiter is about five times as far from the Sun as the Earth is. Here on Earth, the intensity of sunlight is 1.4 kW/m².

The intensity of sunlight at Jupiter can be found using the inverse square law, which states that the intensity of light is inversely proportional to the square of the distance from the source. This means that as the distance from the Sun increases, the intensity of sunlight decreases.Let's find the distance of Jupiter from the Sun and then use it to calculate the intensity of sunlight at Jupiter.The average distance between the Sun and Jupiter is 778,500,000 km. The average distance between the Sun and the Earth is 149,600,000 km.So, the distance of Jupiter from the Sun in terms of the Earth-Sun distance is:

Jupiter's distance from the Sun / Earth's distance from the Sun =

778,500,000 km / 149,600,000 km = 5.2

So, Jupiter is about 5.2 times farther from the Sun than Earth is.Using the inverse square law, we can find the intensity of sunlight at Jupiter:Sunlight intensity at Jupiter = (Sunlight intensity at Earth) × (Earth-Sun distance)² / (Jupiter-Sun distance)²

= \(1.4 kW/m² × (149,600,000 km)² / (778,500,000 km)²\)

= \(1.4 kW/m² × 0.034= 0.048 kW/m²\)

So, the intensity of sunlight at Jupiter is approximately 0.048 kW/m².

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Area=side^2=4^2=16cm^2=0.0016m^2

\(\\ \sf\longmapsto Pressure=\dfrac{Force}{Area}\)

\(\\ \sf\longmapsto Pressure=\dfrac{144}{0.0016}\)

\(\\ \sf\longmapsto Pressure=90000Pa\)

This question can simply be solved by the use of the basic formula of pressure.

The magnitude of pressure applied on the surface is "90000 Pa" (OR) "90 KPa".

The pressure is defined as the force applied per unit area in the normal direction. The pressure applied on a surface can be given by the following formula:

\(Pressure=\frac{Force}{Area}\\\\Pressure=\frac{144\ N}{(0.04\ m)^2}\)

where,

Area of Square Surface = Side² = (0.04 m)²

Therefore,

Pressure = 90000 Pa = 90 KPa

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The attached picture shows pressure.

Answer:

It must travel farther than Earth does to complete one orbit around the Sun.

Explanation:

Each planet orbits around the Sun along an elliptical path. The farther away from the Sun a planet is, the larger the ellipse. The larger the ellipse, the longer the distance around it. Because the orbit of Mars is larger than the orbit of Earth, Mars must travel farther than Earth does to complete one orbit around the Sun.

Mercury travels a shorter distance than Earth does to complete one orbit around the Sun.

Based on the positions of the 8 planets from the sun, Mercury is closest to the sun. The implies that the distance of Mercury from sun is very short when compared to Earth or other planets.

The shorter the distance, the shorter time it would require to make a complete orbit around the sun.

For instance;

Thus, we can conclude that Mercury travels a shorter distance than Earth does to complete one orbit around the Sun.

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A&L Engineering, as an engineer, you've been tasked with evaluating the durability of three common materials used in the design of cell phone cases.

These materials include:Carbon FiberPolycarbonateTPUExplanation:Carbon fiber is a lightweight, durable, and corrosion-resistant composite material. It is often used in the aerospace, automotive, and sporting goods industries.Polycarbonate is a thermoplastic polymer that is strong, shatter-resistant, and lightweight. It is often used in the production of CDs, DVDs, and eyeglass lenses.

TPU (thermoplastic polyurethane) is a flexible, soft material that is abrasion-resistant and provides excellent impact protection. It is often used in the production of phone cases, as well as sporting equipment and medical devices.To evaluate the durability of these materials, you can conduct a series of tests to measure their resistance to impacts, scratches, and bending.

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Given,

Mass of the sample, m=47 g= 0.047 kg

The initial temperature, T₁=80 °F=299.8 K

The final temperature of the sample, T₂=149 °F=338.2 K

Therefore the total raise in the temperature,

The specific heat capacity of the aluminum, c=0.903 J/(g · °C)= 903 J/(kg · K)

The heat required to raise the temperature of a sample by a temperature of ΔT is given by,

On substituting the known values in the above equation,

Therefore the heat required to raise the temperature of the sample from 80 °F to 149 °F is 1629.7 J

Explanation:

Sound travels more quickly through solids than through liquids and gases because the molecules of a solid are closer together and, therefore, can transmit the vibrations faster. Sound travels most slowly through gases because the molecules of a gas are farthest apart.

Answer:

Since there is already an answer i will try to go more into depth about how it was solved.

Explanation:

Using the basic equation S=d/t, where S is speed is in km/hr, d is distance in km, and t is time in hours, we can plug in the two separate pairs of known variables.

Pair 1:

S=d/t

82km/hr=293.8km/t

t=3.583hr

Pair 2:

S=d/t

48km/hr=194.4km/t

t=4.05hr

since the question is asking us for the total time, we can add these two together.

3.583hr+4.050hr=7.633hr

So she has traveled for a total of 7.633 hours

Hope this helps you understand the question a little more!

Work is the same as energy. With the use of energy formula, the work done is 4 J

The work done on an object can be defined as the product of force and distance in the direction of the force. It is synonymous to energy and it is measured in Joule.

Given that a person lifting a 2.0-kg object from the bottom of a well at a constant speed of 2.0 m/s for 5.0 s.

The given parameters are

Work = Energy = 1/2mv²

W = 1/2 × 2 × 2²

W = 0.5 × 2 × 4

W = 4 Joules

Therefore, the much work that is done by the person is 4 Joules.

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Answer:

Explanation:

The kinetic energy of an object can be found by using the formula

\(k = \frac{1}{2} m {v}^{2} \\ \)

m is the mass

v is the velocity

From the question we have

\(k = \frac{1}{2} \times 75 \times {7}^{2} \\ = 37.5 \times 49 \\ = 1837.5\)

We have the final answer as

Hope this helps you

The woman standing on the ground hears the sonic boom when the jet is at position A. This indicates that the jet has already passed the woman and is moving further away from her. The sonic boom occurs when an object, in this case, the jet, travels faster than the speed of sound in air.

Since the woman hears the sonic boom when the jet is at position A, it means that the jet produced the sound at a location behind her, closer to where the jet was previously.

The exact location of the jet when it produced the sound depends on the speed of sound, the speed of the jet, and the time it takes for the sound to reach the woman's location.

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