If You are given 14 moles of C2H5OH(Ethanol) and 13 moles of O2( Oxygen), how
many moles of the limiting reactant is produce? C2H5OH + O2 -> CH3COOH +
H2O

We must use a solubility chart or graph specifically for NaNO3 to ascertain the solubility of NaNO3 in 250 grammes of water at 10°C. The amount of solute (NaNO3) that can dissolve in 100 grammes of water at a specific temperature is used to measure the solubility of NaNO3.

We may use a ratio to get the solubility in 250 grammes of water by assuming that the solubility of NaNO3 in water at 10°C is 90 grammes per 100 grammes of water:

90 g NaNO3 to 100 g water equals x g NaNO3 to 250 g water.

After cross-multiplying and finding x, we obtain:

250 grammes of water with 225 grammes of sodium nitrate equals x.

As a result, 250 grammes of water at 10°C can dissolve around 225 grammes of NaNO3.

The temperature at which 25 grammes of HCl will dissolve into a saturated solution in 50 grammes of water is required to answer the second question. Understanding how HCl dissolves in water at various temperatures is necessary for this.

The solubility of HCl in water is normally expressed in terms of grammes of solute per 100 grammes of water, despite the fact that it is a highly soluble molecule. The maximum concentration in mol/L at a specific temperature is typically supplied as an alternative.

Without specific solubility data, it is not possible to provide an accurate temperature at which 25 grams of HCl would create a saturated solution in 50 grams of water. Additional solubility information is needed to make a precise determination.

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The specific heat of this metal is  0.385 j/g°C.

The Specific heat ability of a substance is the heat potential of a pattern of the substance divided by the mass of the sample, also sometimes called massic heat ability.

The specific warmth ability is defined as the quantity of warmth (J) absorbed consistently with the unit mass (kg) of the cloth whilst its temperature will increase 1 k (or 1 °C), and its gadgets are J/(kg k) or J/(kg °C).

Specific heat is described by the quantity of warmth had to increase the temperature of 1 gram of a substance 1 diploma Celsius (°C). Water has a high precise heat, which means it takes more power to grow the temperature of water compared to different materials.

calculation:-

heat = msΔt

s = heat/mΔt

  =  14,014 /  2,800 × 13

   = 0.385 j/g°C

Hence the specific heat of this metal is = 0.385 j/g°C

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d. The polymorphic form of fat crystals is in a glassy state is NOT true.

The statement that the polymorphic form of fat crystals is in a glassy state is not true. Polymorphism refers to the ability of a substance to exist in multiple crystal structures or forms. Lipids, including fats, can exhibit polymorphism, meaning they can crystallize in different arrangements or crystal forms.

When it comes to the texture of foods containing lipids, the polymorphic form of fat crystals does play a significant role. The specific crystal form and arrangement of the lipids can affect the texture of the food, influencing factors such as mouthfeel, creaminess, and stability.

The solid fat content versus temperature profile is an essential factor in determining texture, as stated in option a. The morphology of the crystals formed, as mentioned in option b, also plays a crucial role in texture. Option c is true as well, as foods containing partially crystalline lipids can exhibit a "plastic" texture.

However, option d is not accurate because the polymorphic form of fat crystals can exist in various states, including crystalline and semi-crystalline states, but not in a glassy state. Glassy states are typically associated with amorphous materials rather than crystalline structures.

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Answer:

Explanation:

Edmentum

The arrangement of electrons within an atom's orbitals is known as its electronic configuration. The atomic number, which is equal to the number of protons in every neutral atom, is the set quantity of electrons that make up each neutral atom.

The distribution of an element's atoms' electrons throughout several atomic orbitals is symbolically represented by the electronic configuration of that element.

A standardized nomenclature is used for expressing electron configurations, in which the energy level and type of orbital are written first, followed by the number of electrons in the orbital, which is expressed in superscript.

The correct matches are:

Zn: [Ar] 3d¹⁰ 4s²

Fe: [Ar] 3d⁶ 4s²

Sn: [Kr] 4d¹⁰5s²5p²

Cl: [Ne] 3s² 3p⁵

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Among the given options, the tests that are left-tailed are H0:μ≥18, Ha:μ<18, H0:μ≥11.3, Ha:μ<11.3, and H0:μ≥3.7, Ha:μ<3.7.

In these tests, the null hypothesis (H0) states that the population mean (μ) is greater than or equal to a specific value, while the alternative hypothesis (Ha) suggests that the population mean is less than that value.

A left-tailed test is used when the alternative hypothesis suggests that the population parameter is less than a certain value.

This indicates a left-tailed test, where the critical region is in the left tail of the distribution. These tests focus on detecting a significant decrease or difference in the population mean.

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Complete question :

Which of the hypothesis tests listed below is a left-tailed test? Select all correct answers.

Select all that apply: H0:μ≥18, Ha:μ<18 H0:μ≤19.3, Ha:μ>19.3 H0:μ=8, Ha:μ≠8 H0:μ≥11.3, Ha:μ<11.3 H0:μ≥3.7, Ha:μ<3.7

Answer:

isostatic adjustment movement

The nucleus of an atom is held together by the strong nuclear force to hold together protons and neutrons. The strong nuclear force is stronger than electricity and gravity. It's even the strongest out of the four fundamental forces.

Answer:

(i) Ionization enthalpy:

Alkaline earths have higher ionization enthalpy values than alkali metals. This is because the atomic size of alkaline earths is smaller than that of alkali metals.

(ii) Basicity of oxides:

On dissolution in water, the oxides of alkali metals and alkaline earth metals form basic hydroxides. The basicity of alkali metal oxides is higher than that of alkaline earth metal oxides due to lower ionization enthalpy of alkali metals than that of corresponding alkaline earths. Due to this, the M-OH bond in alkali metal hydroxides can more easily ionize.

(iii) Solubility of hydroxides:

Alkaline earths have larger lattice energies than alkali metals due to small size and high charge. Hence, alkaline earth metal hydroxides have lower solubility than alkali metals.

Comparison between the alkali and alkaline earth metals are that alkali metals are soft, have high M.P. & shows magnetism and alkaline are hard, have low M.P. & no magnetism.

Alkali earth metals are those elements which are present in the first period of the periodic table and alkaline earth metals are those which are present on the second group of the periodic table.

Hence the comparison between them are discussed above.

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Answer:

Because the atmospheric pressure at higher altitudes is lower than at sea level.

Water, or any liquid for that matter, boils when its vapor pressure equals the external pressure above the liquid.

Answer:

calcium+ethanoic acid= carbon dioxide + water

Zinc + ethanoic acid= zinc ethanoate+water

Answer:

calcium + ethanoic acid → calcium ethanoate + water

zinc + ethanoic acid → zinc ethanoate + water

When steel and zinc were connected, zinc is the cathode. The term cathode refers to the electrode that is reduced during an electrochemical reaction.

The electrons are moved from the anode to the cathode during an electrochemical reaction in order to maintain a current in the wire that links the two electrodes.

According to the galvanic series, zinc is more active than iron, meaning that it is more likely to lose electrons and be oxidized. As a result, when steel and zinc are connected, zinc will act as the anode and lose electrons, whereas iron (steel) will act as the cathode and receive the electrons transferred by zinc.

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Answer:

oh no!! I can't do this ;(

Explanation:

oopsie "BrO" I can't do this pleaseee.

don't be selfish next time and maybe people will help you...

The substance in the image above would be classified as a mixture of elements (option E).

A compound is a substance formed by chemical bonding of two or more elements in definite proportions by weight.

On the other hand, a mixture is made when two or more substances are combined, but they are not combined chemically.

According to this question, an image is shown with two different substances or elements as distinguished by coloration (white and purple). These elements are combined but not chemically bonded, hence, is a mixture.

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Answer:

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

mass = Density × volume

From the question we have

mass = 75 × 2.86

We have the final answer as

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Glyphosate was initially thought to have no effect on human health because it primarily targets enzymes found only in plants and bacteria, not humans.

Additionally, the compound was believed to have a low toxicity level and was considered to be safe when used according to the labeled instructions.

However, recent scientific studies have suggested potential health risks associated with glyphosate exposure, including links to cancer and other health issues.

These studies have prompted further investigation and controversy surrounding the safety of glyphosate in herbicides.

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Answer:

2, strong acid

Explanation:

Data obtained from the question. This includes:

[H+] = 0.01 M

pH =?

pH of a solution can be obtained by using the following formula:

pH = –Log [H+]

pH = –Log 0.01

pH = 2

The pH of a solution ranging between 0 and 6 is declared to be an acid solution. The smaller the pH value, the stronger the acid.

Since the pH of the above solution is 2, it means the solution is a strong acid.

Answer:

A is correct

Explanation:

AU=2x2=4           Au=1x4=4

O=3x2=6              O=2x3=6

Answer:

Acrylic

Acrylic is the synthetic fibre feels like wool and used as a substitute for wool.

(a) To get the pH of the media to 5.8, you would add NaOH solution. NaOH is used as a basic solution, and when it is added to a solution, it will increase the pH of the solution.

(b) The molecular weight of BA is 225.3. To prepare a 1M solution, you would have to weigh out 225.3 grams of BA.(c) To convert a 1M solution of BA to mg/mL, you can use the following equation: 1 mole = molecular weight in grams; 1000 millimoles = 1 mole. So, 1 M = 1000 mg/mL. Therefore, a 1M solution of BA is equivalent to 1000 mg/mL .(d) To convert a concentration of 1000 mg/mL .

Therefore, to calculate the weight required for a 5 mM solution, use the following formula :Mass of BA = molarity × volume × molecular weight= 5 × 0.001 × 225.3= 1.1265 grams(f) To convert a concentration of 5 mM to mg/mL, we use the following formula: Concentration (mg/mL) = (Concentration (mM) × Molecular weight) / 1000= (5 × 225.3) / 1000= 1.1265 mg/mL(g)

To convert a concentration of 1.1265 mg/mL to mg/L, we multiply by 1000, so 1.1265 mg/mL = 1126.5 mg/L.(h) Given that the stock solution of BA is 5 mM and the working solution is 0.2 mg/mL.

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The atomic number of an element is determined by the number of protons in the nucleus. The number of neutrons, on the other hand, can differ. The difference between two atoms of carbon with the same number of neutrons is that they may have different atomic masses.

Carbon-12, carbon-13, and carbon-14 are the three most common isotopes of carbon. Carbon-12 is the most common isotope, and it has six protons and six neutrons. Carbon-13, which has one extra neutron, has an atomic mass of 13 atomic mass units (amu).

Carbon-14 is absorbed by plants through photosynthesis and enters the food chain. When an animal eats a plant, it absorbs the carbon-14 from the plant. Carbon-14 undergoes radioactive decay over time, with a half-life of around 5,700 years. As a result, carbon-14 dating is used to date items up to 50,000 years old based on the amount of carbon-14 remaining.

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group j neptunium Atomic number 93

Answer:

0.72 good luck with the answer

Metals :-

Group 1A - Alkali metals ( highly reactive metals)

Non-metals :-

Group 17 - Halogens ( highly reactive non-metals )

Answer:

Explanation:

The sound waves are bocing off the walls.  

The study focuses on an effective addition circuit and incorporates carry-lookahead arithmetic approaches.

The work showed an effective addition circuit that used methods from the traditional carry-lookahead arithmetic circuit. Two n-bit values are input into the quantum carry-lookahead (QCLA) adder, which adds them in O(log n) depth with On supplementary qubits. It typically offered a few variants that add modulo 2n and modulo 2n - 1, as well as in-place and out-of-place versions.

The method of choice incorporated in the past has been the ripple-carry addition circuit with linear depth. Our innovation significantly lowers the cost of addiction while just slightly increasing the number of qubits needed. Current modular multiplication circuits can significantly shorten the run-time of Shor's algorithm by utilising the QCLA adder.

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Complete Question:

Explain the study of t. g. draper. a logarithmic-depth quantum carry-lookahead adder. quantum inf. comput., 6(4):351, 2006.

Step 1

The reaction:

Ca(OH)2 (aq) + 2 HBr (aq) => CaBr2 (aq) + 2 H2O (l) (compelted and balanced)

----------------

Step 2

Information provided:

0.0105 M HBr

125 mL of 0.0100 M Ca(OH)2

----------------

Step 3

The number of moles of Ca(OH)2:

Molarity (mol/L) = moles of Ca(OH)2/volume of the solution (L)

Volume = 125 mL x (1 L/1000 mL) = 0.125 L

Therefore,

Molarity x volume (L) = moles

0.0100 mol/L x 0.125 L = 1.25x10^-3 moles of Ca(OH)2

-----------------

Step 4

The number of moles of HBr, by stoichiometry:

Ca(OH)2 (aq) + 2 HBr (aq) => CaBr2 (aq) + 2 H2O (l)

1 mol Ca(OH)2 ------ 2 moles HBr

1.25x10^-3 moles ------ X

X = 1.25x10^-3 moles x 2 moles HBr/1 mol Ca(OH)2

X = 2.5x10^-3 moles HBr

----------------

Step 5

The volume of HBr needed:

Molarity = moles of HBr/volume of solution (L)

Volume = moles of HBr/molarity

Volume = 2.5x10^-3 moles HBr/0.0105 mol/L

Volume = 0.238 L

Volume = 0.238 L x (1000 mL/1 L) = 238 mL

Answer: 238 mL or 0.238 L (there are no matches)

Answer:

laws:)

Explanation:

Answer:

The answer should be A

Explanation:

because the definition of a subscript is that they indicate the number of atoms of an element present in am molecule or formula unit.

Answer:

The first choice. The rule is go left. Those subscript numbers always talk about the element to the left of them.

Explanation:

The straight forward answer is the first one.

You should always answer that when reading the chemical make up of molecules. Let's look at some examples.

C8 H18

Consider the 8. It must be describing how many carbons there are. If it was meant for the hydrogen, then what  does the 18 mean? You wouldn't know.

Now look at something a lot more complicated.

Mg3(PO4)2

Use the going left rule. That satisfies Mg doesn't it? There are 3 of them and 3 is correct.

The two at the end is also straightforward if you think about it. It must be telling you how many molecules are in the brackets. If that were not so, then you wouldn't be able to tell what it did. So there are 2 PO4

But you still have the 4 to deal with. Use the going left rule again. 4 must be telling you how many oxygens you have inside the brackets. There are 4 of them.

If more \(H_{2}\) and \(N_{2}\) are added to the reaction 3\(H_{2}\) + N2 → 2\(NH_{3}\) after it reaches equilibrium, two events will occur Shift in Equilibrium and Increased Yield of \(NH_{3}\)

1. Shift in Equilibrium: According to Le Chatelier's principle, when additional reactants are added, the equilibrium will shift in the forward direction to consume the added reactants and establish a new equilibrium. In this case, more \(NH_{3}\) will be produced to counteract the increase in \(H_{2}\) and \(N_{2}\).

2. Increased Yield of \(NH_{3}\): The shift in equilibrium towards the forward reaction will result in an increased yield of \(NH_{3}\). As more \(H_{2}\) and \(N_{2}\) are added, the reaction will favor the production of \(NH_{3}\) to maintain equilibrium. This will lead to an increase in the concentration of \(NH_{3}\) compared to the initial equilibrium state.

It is important to note that the equilibrium position will ultimately depend on factors such as the concentrations of \(H_{2}\), \(N_{2}\), and \(NH_{3}\), as well as the temperature and pressure of the system. By adding more reactants, the equilibrium will adjust to achieve a new balance, favoring the formation of more \(NH_{3}\).

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Which of the below is NOT TRUE about ionic and covalent bonds.

Answer : Ionic bonds are stronger than covalent bonds.

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