As the distance from the centre grows, a system bound together by gravity has "constant rotational speed" or "constant angular velocity." Galaxies and whirling objects exhibit this phenomena.
Dark matter is commonly found in flat rotation curves with constant rotational speed. It implies that dark matter is needed to explain the observed rotating behaviour in astrophysics.
In such instances, the system is in rotational equilibrium because the centripetal forces induced by rotation balance the gravitational forces. This equilibrium maintains a constant rotational speed regardless of distance from the centre.
The conservation of angular momentum explains this behaviour. Unless torques act on a system, its total angular momentum remains constant. To balance gravitational and centripetal forces and preserve total angular momentum, the rotational speed may need to decrease as the distance from the centre rises.
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Why do tin roofs make creaking sounds on hot days?
Answer: Yes, on many slate-roofed homes as temperatures change, such as cooling at night or heating during the day, thermal expansion or contraction of the slates may cause movement that in turn causes snapping, popping, or cracking noises, even bangs and clanks or clicks from the roof.
Explanation:
Answer:
because of its mealting
Explanation:
hope it helps you
The latent heat of fusion for Aluminium is 3.97 x 105. How much energy would be required to melt 0.75 kg of it?
Answer:
\(E = 2.9775\times10^5 J\)
Explanation:
Given: The latent heat of fusion for Aluminum is \(L = 3.97\times10^5 J/Kg\)
mass to be malted m = 0.75 Kg
Energy require to melt E = mL
\(E = 3.97\times10^5\times0.75 = 2.9775\times10^5 J\)
Therefore, energy required to melt 0.75 Kg aluminum
\(E = 2.9775\times10^5 J\)
Describe the processes necessary for social learning to occur.
Please HELP!!!!!!!
Answer:
Social learning occurs when four processes are present: 1) Attention: The learning organism must be paying attention to the modeled behavior. If there is no attention, the behavior cannot be processed into memory. 2) Retention: The learning organism must remember the behavior that was modeled.
Explanation:
Hope this helps.
Answer:
Social learning occurs when four processes are present:
1) Attention: The learning organism must be paying attention to the modeled behavior. If there is no attention, the behavior cannot be processed into memory.
2) Retention: The learning organism must remember the behavior that was modeled. If the behavior is not retained, it cannot be replicated.
3) Reproduction: The learning organism must be capable of producing the behavior. If the behavior is too skilled or impossible for the organism to replicate, then the reproduction will be unskilled or halting.
4) Motivation: The learning organism must be motivated to perform the behavior, or motivated not to perform the behavior. If the organism is not motivated to perform the behavior, and even if the organism is able to perform the behavior and knows how, it may not.
Please help
How would you explain 2 m/s/s [1
(1 Point)
Enter your answer
1. Given a list of atomic model descriptions:
A: electron shells outside a central nucleus
B: hard, indivisible sphere
C: mostly empty space
Which list of atomic model descriptions represents
the order of historical development from the earliest
to most recent?
A) A, B, CBA, C, B
CB, C, A D) B, A, C
Answer: A: electron shells outside a central nucleus
B: hard, indivisible sphere
C: mostly empty space
Which list of atomic model descriptions represents
the order of historical development from the earliest
to most recent?
Explanation:
3
Atomic models have been proposed throughout history describing the possible arrangements of different particles inside the atoms.
The very first model for atom was given by Dalton known as the solid sphere model that was an indivisible hard sphere.The model given by Rutherford that was known as nuclear model mostly included empty space.The model given by Shrodinger showed electron shells as being outside the central nucleus.Thus, the correct order of atom model is B C A. Hence, the correct answer is option C.
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pls someone help me
Answer:
Can't see the pic
Explanation:
density of water? And tin?
Answer:
the density of water is 1 and tin is 7.31 if i remember right
Explanation:
What are the four layers of the earth
Answer:
earth's crust
meatle
outercore
innercore
Answer:
the crust
the mantle core
the outer core
the inner core
Which waves can
travel though space
Answer: Radio waves
Explanation:
Radio waves can travel through space. So, if you're wearing a space suit that contains a radio unit and one of your buddies sends you a radio message that there's pizza in the space station, you'd be able to hear it. That's because radio waves aren't mechanical -- they're electromagnetic. Electromagnetic waves can transmit energy through a vacuum.
If a fish is trying to capture insect hovering above the surface of water – how will it jump to catch it? Will it aim above or below what it sees? Explain.
Answer:
Above
Explanation:
yes
identify the phases of the moon if at sunset in the northern hemisphere the moon is in each of the following positions.
The phases of the moon if at sunset in the northern hemisphere the moon is in each of the following positions: Near the eastern horizon: Full moon; High in the southern sky: First quarter; In the southeastern sky: Waxing gibbous ; In the southwestern sky: Waning gibbous.
The moon's phases are determined by the position of the moon relative to the sun. At sunset, the moon is always on the opposite side of the Earth from the sun. So, the phase of the moon will depend on how much of the moon's illuminated side is facing the Earth.
If the moon is near the eastern horizon at sunset, then the entire illuminated side of the moon is facing the Earth. This means that the moon is full.
If the moon is high in the southern sky at sunset, then half of the illuminated side of the moon is facing the Earth. This means that the moon is in its first quarter phase.
If the moon is in the southeastern sky at sunset, then more than half of the illuminated side of the moon is facing the Earth. This means that the moon is in its waxing gibbous phase.
If the moon is in the southwestern sky at sunset, then less than half of the illuminated side of the moon is facing the Earth. This means that the moon is in its waning gibbous phase.
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What constant acceleration is required to increase the speed of a car from 26 mi/h to 51 mi/h in 5 seconds
2.25 m/s² of acceleration is required to increase the speed of a car from 26 mi/h to 51 mi/h in 5 seconds.
To find the answer, we need to know about the acceleration.
What is acceleration?Acceleration is given as the ratio of velocity to time.Mathematically, acceleration= velocity/time.What is the acceleration required to increase the speed of a car from 26 mi/h to 51 mi/h in 5 seconds?Here change in velocity of the car is 51-26= 25 mi/h. As 1 mi/h = 0.45 m/s. So 25mi/h = 11.25 m/s.Acceleration= (11.25m/s)/5s = 2.25 m/s².Thus, we can conclude that the constant acceleration is 2.25 m/s².
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Which mass is undergoing the greatest amount of acceleration?.
The mass of 2 kg is undergoing the greatest amount of acceleration in this scenario.
According to Newton’s second law of motion, force is equal to mass times acceleration.
The formula can be mathematically represented as:Force = mass × accelerationOr acceleration = force / massWhen a force is applied to an object, it causes acceleration.
The acceleration of an object depends on its mass and the amount of force applied to it.
In this scenario, two masses of 2 kg and 6 kg respectively are being acted upon by two different forces of 8 N and 24 N respectively.
Using the above formula, we can calculate the acceleration of both the masses as follows:For 2 kg mass,Acceleration = Force / MassAcceleration = 8 N / 2 kgAcceleration = 4 m/s²For 6 kg mass,Acceleration = Force / MassAcceleration = 24 N / 6 kgAcceleration = 4 m/s²
Therefore, both the masses are undergoing the same amount of acceleration.
Summary:So, the mass of 2 kg is undergoing the greatest amount of acceleration in this scenario.
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Why is an astronical unit used to measure distances in the solar system?
In our solar system, distances are really great. Therefore, astronomers frequently avoid using miles or kilometers when describing the distances to planets, asteroids, comets, or spacecraft.
What is astronomical unit?They substitute astronomical units, or AU, which represent the typical separation of the Earth from the sun. That translates to around 93 million miles, 150 million kilometers, or 8 light-minutes.
It is simpler to visualize relative distances in space when thinking in terms of astronomical units. An astronomical unit is 92,955,807 miles in exact distance (149,597,871 km).
The orbit of the Earth around the sun is not a complete circle. Consequently, during the year, Earth's distance from the sun varies. Earth is approximately 0.983 AU from the sun when it is at perihelion, which occurs in January.
Therefore, In our solar system, distances are really great. Therefore, astronomers frequently avoid using miles or kilometers when describing the distances to planets, asteroids, comets, or spacecraft.
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A thin 5.0-kg wheel of radius 32 cm is weighted to one side by a 1.45-kg weight, small in size, placed 23 cm from the center of the wheel.
B)Calculate the moment of inertia about an axis through its cm, perpendicular to its face.
Express your answer using two significant figures.
The moment of inertia of the wheel and the weight together is \(0.59 \ kg m^2\).
To calculate the moment of inertia of the wheel with a weighted side, we'll first find the moment of inertia of the wheel and the weight separately, and then sum them up.
The moment of inertia (I) of a thin wheel (or a hoop) is given by the formula:
\(I_{wheel} = M_{wheel} * R_{wheel}^2\)
where \(M_{wheel}\) is the mass of the wheel (5.0 kg) and \(R_{wheel}\) is its radius (0.32 m).
\(I_{wheel} = 5.0 \ kg \times (0.32\ m)^2 = 5.0 \ kg \times 0.1024 \ m^2 = 0.512 \ kg m^2\)
Next, we'll find the moment of inertia of the small weight, which can be considered as a point mass. The formula for the moment of inertia of a point mass is:
\(I_{weight} = M_{weight} \times r^2\)
where M_weight is the mass of the weight (1.45 kg) and r is the distance from the center of the wheel (0.23 m).
\(I_{weight} = 1.45 \ kg \times (0.23 \ m)^2 = 1.45 \ kg \times 0.0529 \ m^2 = 0.0767 \ kg m^2\)
Now, we'll add the moments of inertia of the wheel and the weight to find the total moment of inertia about the axis through the wheel's center of mass (cm), perpendicular to its face:
\(I_{total} = I_{wheel} + I_{weight} = 0.512 \ kg m^2 + 0.0767 \ kg m^2 = 0.5887 \ kg m^2\)
Expressing the answer using two significant figures, the total moment of inertia is \(0.59 \ kg m^2\).
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A 20kg object acceleration by a force of 200N with coefficient of kineticfriction is 0.4 what is acceleration of the object?
Answer:
Given - M = 20 kg
k = 0.4
F = 200 N
To find - acceleration
Solution -
F= kMA
200 = 0.4 * 20 * acceleration
200 = 8 * a
a = 8/200
a = 0.04 m s²
a = 0.04 m s²what property of earthquakes does the richter scale measure?
The Richter scale measures the magnitude of an earthquake, which is a measure of the energy released by the seismic waves generated by the earthquake.
What is the measures ?Measures are the steps taken to achieve a desired outcome. They can be in the form of legislation, policies, regulations, practices, procedures, and processes. They are used to implement and enforce objectives, goals, and strategies, and can be both proactive and reactive. Measures can be utilized by governments, businesses, and individuals to ensure desired outcomes are achieved in a timely and cost-effective manner. Measures can also be used to monitor progress and evaluate the effectiveness of policies and procedures.
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A truck drives to a rock quarry at a speed of 20 m/s. The truck takes on a load of rocks, which doubles its mass, and leaves at the same speed of 20 m/s. Quantitatively compare the kinetic energy of the truck as it left the quarry with its kinetic energy on the way to the quarry. Explain your answer.
Given that,
A truck drives to a rock quarry at a speed of 20 m/s. The truck takes on a load of rocks, which doubles its mass, and leaves at the same speed of 20 m/s.
To find,
Comparison of the kinetic energy of the truck as it left the quarry with its kinetic energy on the way to the quarry.
Solution,
Kinetic energy of an object is given by:
\(K=\dfrac{1}{2}mv^2\)
m is the mass of the truck
\(K=\dfrac{1}{2}m\times (20)^2\\\\K=200m\ J\)
If mass is doubled and speed is same i.e. 20 m/s, neew kinetic energy is given by :
\(K=\dfrac{1}{2}\times (2m)\times 20^2\\\\K=400m\ J\)
It can be seen that when mass of truck is doubled, its kinetic energy gets doubled.
As light from a star spreads out and weakens, do gaps form between the photons?
Can momentum be hidden to human eyes like how kinetic energy can be hidden as heat?
Answer:
This is one of the mysteries of quantum mechanics - a single photon in classical mechanics is sent out in a circular arc - but when the arc interacts with a distant object the entire wave front collapses and delivers the entire energy of the photon to the object in question.
An analogy has been give as a pop bottle thrown into the water in New York with its energy spreading out in a circular arc and at some time later the wave front strikes a pop bottle in the water in Japan with the result of the wave front delivering its entire energy to the bottle with the bottle jumping out of the water.
4. As a 500 N woman sits on the floor, the floor exerts a force on her of
ext
a) 1000 N.
b) 500 N.
c) 250 N.
d) 50 N.
e) 5 N.
Answer: 1000
Explanation:
Its double her weight
Determine the work performed by a person with a weight of 750N, while climbing 20 stairs, if it is known that the height of each step is 20 cm.
Answer:
3000J
Explanation:
- formula work done is force x perpendicular distance.
- convert 20cm to m, so 20 divide by 100 equals 0.2.
- since there is 20 stairs, 20 multiply by 0.2m.
- lastly, 750N x 4m equals 3000J
(b) In an x-ray twbe, an electron is accelerated from rest towards a metal farget tyy a 30 kV source. Calculate the kinetic energy of the electron. e=1.6\times 10^(-19)C
The kinetic energy of the electron accelerated by a 30 kV source is approximately 4.8 x 10^(-14) Joules.
Voltage (V) = 30 kV = 30,000 volts
Charge of an electron (e) = \(1.6 x 10^(-19) C\)
Calculating the potential energy -
P = e x V
An object's motion gives it kinetic energy, which is a type of energy. It is described as the amount of effort required to accelerate a body of a specific mass from rest to its specified velocity. As Potential energy is equal to kinetic energy, therefore calculating the kinetic energy:
Potential Energy = Kinetic Energy = e x V
Substituting the value -
\(= (1.6 x 10^(-19) C) x (30,000 V)\)
\(= 4.8 x 10^(-14) J\)
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In Part C, how would the effects differ if you connected the galvanometer to the primary coil and the battery/switch to the secondary
N₂ / N₁ = 13.3
A transformer is a device that changes the voltage in the primary, causing a voltage to be induced in the secondary. The expression for this voltage ratio is
ΔV₂ = N₂ /N₁ ΔV₁
where N is the number of windings on each side and V2 and V1 are the voltages in the secondary and primary, respectively.
They state that the primary voltage in this instance is 9.0 V and the secondary voltage is 120 V.
ΔV₂ /ΔV₁ = N₂ / N₁
N₂ / N₁ = 120/9
N₂ / N₁ = 13.3
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A 9.0-V battery (with nonzero resistance) and switch are connected in series across the primary coil of a transformer. The secondary coil is connected to a light bulb that operates on 120 V. Determine the ratio of the secondary to primary turns needed for the bell's transformer. Determine the ratio of the secondary to primary turns needed for the bells transformer. Ns/Np=?
a particle with charge +4.20 nc is in a uniform electric field e⃗ directed to the left. the charge is released from rest and moves to the left; after it has moved 6.00 cm, its kinetic energy is +2.20×10−6 j.
(a) The work done is 1.50 x 10^-6 J
(b) The potential of the starting point with respect to the endpoint is 357.14 V.
(c) The magnitude of E is 5952.38 N/C.
Given that,
Charge = 4.20 nC
Distance = 6.00 cm
Kinetic energy K.E = 1.50 x 10^-6 J
The particle start from rest. So, the initial kinetic energy i zero.
(A) We need to calculate the work by the electric force
Using formula of work done
W = ∆K.E
W = K.Ef - K.Ei
Put the value into the formula
W = 1.50 × 10^-6 - 0
W = 1.50 x 10^-6 J
The work done is 1.50 x 10^-6 J
(B). We need to calculate the potential of the starting point with respect to the endpoint
We know that.
Change in potential energy = change in kinetic energy
∆P.E = ∆K.E
So, U = 1.50 x 10^-6
Using formula of potential
V = U/q
Put the value into the formula
V = 1.50 × 10^-6/4.20 x 10^-9
V = 357.14 V
The potential of the starting point with respect to the endpoint is 357.14 V
(C) We need to calculate the magnitude of E
Using formula of work done
W = F x r (1)
Using formula of force
F = qE
Put the value in the equation (1)
W = qE x r
E = W/q x r
Put the value into the formula
E = 1.50 x 10^-6/4.20 x 10^-9 x 6.00 x10^-2
E = 5952.38 N/C
Hence, The magnitude of E is
5952.38 N/C
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Help, make sure to include units of measurement.
\(f=(9.0\times{10}^{9}\frac{N.{m}^{2} }{ {c}^{2} })\frac{(3.2 \times{10}^{ - 9}c) \: (9.6 \times {10}^{ - 9}c) }{(0.32 m)^{2}} \\ \\ f=(9.0\times{10}^{9}\frac{N.{m}^{2} }{ {c}^{2} })\ \frac{ \: 30.72 \times {10}^{ - 18} \: {c}^{2} }{ \: 0.1024 \: {m}^{2} } \\ \\f = \frac{9.0 \times {10}^{9} \times 30.72 \times {10}^{ - 18} }{0.1024} \: ( \frac{N.{m}^{2} }{ {c}^{2} } \: \times \frac{ {c}^{2} }{ {m}^{2} } )\\ \\ f = \frac{276.48 \times {10}^{ - 9} }{0.1024} \: ( \frac{N.{m}^{2} }{ {c}^{2} } \: \times \frac{ {c}^{2} }{ {m}^{2} } )\\ \\ f = 2700 \times {10}^{ - 9} N \\ \\ f = 2.7 \times {10}^{ - 6} N\)
I hope I helped you^_^
A horse runs 350 meters in 23 seconds. What was the average speed of the horse? Round your answer to a tenth
Answer:
Horse/Speed
55 mph
rounded to the tenth? either 60 or 50
but 350 would stay like that i believe!
Explanation:
Two trains traveling towards one another on a straight track are 300m apart when the engineers on both trains become aware of the impending Collision and hit their brakes. The eastbound train, initially moving at 97.0 km/h Slows down at 3.50ms^2. The westbound train, initially moving at 127 km/h slows down at 4.20 m/s^2. What is the distance between them once they stop (express your answer to the two significant figures)
Answer:
48 m
Explanation:
Two trains traveling towards one another on a straight track are 300m apart when the engineers on both trains become aware of the impending Collision and hit their brakes. The eastbound train, initially moving at 97.0 km/h Slows down at 3.50ms^2. The westbound train, initially moving at 127 km/h slows down at 4.20 m/s^2.
The eastbound train
First convert km/h to m/s
(97 × 1000)/3600
97000/3600
26.944444 m/s
As the train is decelerating, final velocity V = 0 and acceleration a will be negative. Using third equation of motion
V^2 = U^2 - 2as
O = 26.944^2 - 2 × 3.5 S
726 = 7S
S = 726/7
S1 = 103.7 m
The westbound train
Convert km/h to m/s
(127×1000)/3600
127000/3600
35.2778 m/s
Using third equation of motion
V^2 = U^2 - 2as
0 = 35.2778^2 - 2 × 4.2 × S
1244.52 = 8.4S
S = 1244.52/8.4
S2 = 148.2 m
S1 + S2 = 103.7 + 148.2 = 251.86
The distance between them once they stop will be
300 - 251.86 = 48.14 m
Therefore, the distance between them once they stop is 48 metres approximately.
How are the molecules in a gas different from molecules in other states of matter?
Answer: The molecules in gases are different from other states of matter
Explanation:
The molecules in gases are different from other states of matter because unlike, for example, a solid, they move around freely and are much more spread apart. A gas can fill up any container, but once the container is unsealed, the gasses will immedietly be let out. Gases can be compressed much more easily than a solid or a liquid.
please help mee I’ll give brainliest
Answer:
It has potential energy and then the eg=nergy goes to the bug killing it becay=use of the force
Explanation:
"use the force luke"
Answer:
It has potential energy and then the energy goes to the bug killing it because of the force
Explanation:
a block that weighs 40.0 n is released from a height of 12 m. what is the change in potential energy when the ball falls to the ground?
The change in potential energy when the block falls to the ground is 477.7 J.
The change potential energy can be calculated using the formula ΔPE = mgh, where ΔPE is the change in potential energy, m is the mass of the block, g is the acceleration due to gravity, and h is the height the block falls from.
In this scenario, the block weighs 40.0 N, which is equivalent to a mass of approximately 4.08 kg (since weight = mass x acceleration due to gravity). The acceleration due to gravity is approximately 9.81 m/s^2. The block falls from a height of 12 m. Therefore, using the formula ΔPE = mgh, we can calculate the change in potential energy:
ΔPE = (4.08 kg)(9.81 m/s^2)(12 m) = 477.7 J
The change in potential energy when the block falls to the ground is 477.7 J.
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