If The Wavelength Of A Set Of Waves Is 20 Feet Long, How Deep Is The Wave Base? A. 30 Feet Below The Surface B. 20 Feet Bellow The Surface C. 10 Feet Bellow The SurfaceD. 40 Feet Bellow The Surface

Answers

Answer 1

The depth of the wave base would be 10 feet below the surface (option C), which is one-half of the wavelength of 20 feet.

The depth of the wave base, which is the depth at which wave movement ceases to have an influence on sediment transport and erosion, is determined by the wavelength of the waves. In general, the depth of the wave base is equal to half the wavelength of the waves.

Therefore, if the wavelength of a set of waves is 20 feet long, the depth of the wave base would be 10 feet below the surface (option C). This means that any sediment or features below this depth would be relatively undisturbed by the action of the waves.

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Related Questions

Can a body be in equilibrium if it is revolving clockwise under the action of a single force?

Answers

Answer: A rotating body or system can be in equilibrium if its rate of rotation is constant and remains unchanged by the forces acting on it.

hope this helped

A sample of monatomic ideal gas occupies 5.00 L at atmospheric pressure and 300 K (point A). It is warmed at constant volume to 3.00 atm (point B). Then it is allowed to expand isothermally to 1.00 atm (point C) and at last compressed isobarically to its original state. (a) Find the number of moles in the sample. moles (b) Find the temperature at point B. K (c) Find the temperature at point C. K (d) Find the volume at point C. L (e) Now consider the processes A → B, B → C, and C → A. Describe just how to carry out each process experimentally. This answer has not been graded yet. (f) Find Q, W, and ΔEint for each of the processes. Q (kJ) W (kJ) Eint (kJ) A → B B → C C → A (g) For the whole cycle A → B → C → A, find Q, W, and ΔEint. Q = kJ W = kJ Eint = kJ

Answers

Answer:

(a) 0.203 moles

(b) 900 K

(c) 900 K

(d) 15 L

(e) A → B, W = 0, Q = Eint = 1,518.91596 J

B → C, W = Q ≈ 1668.69974 J Eint = 0 J

C → A, Q = -2,531.5266 J, W = -1,013.25 J, Eint = -1,518.91596 J

(g) ∑Q = 656.089 J, ∑W =  655.449 J, ∑Eint = 0 J

Explanation:

At point A

The volume of the gas, V₁ = 5.00 L

The pressure of the gas, P₁ = 1 atm

The temperature of the gas, T₁ = 300 K

At point B

The volume of the gas, V₂ = V₁ = 5.00 L

The pressure of the gas, P₂ = 3.00 atm

The temperature of the gas, T₂ = Not given

At point C

The volume of the gas, V₃ = Not given

The pressure of the gas, P₃ = 1 atm

The temperature of the gas, T₂ = T₃ = 300 K

(a) The ideal gas equation is given as follows;

P·V = n·R·T

Where;

P = The pressure of the gas

V = The volume of the gas

n = The number of moles present

R = The universal gas constant = 0.08205 L·atm·mol⁻¹·K⁻¹

n = PV/(R·T)

∴ The number of moles, n = 1 × 5/(0.08205 × 300) ≈ 0.203 moles

The number of moles in the sample, n ≈ 0.203 moles

(b) The process from points A to B is a constant volume process, therefore, we have, by Gay-Lussac's law;

P₁/T₁ = P₂/T₂

∴ T₂ = P₂·T₁/P₁

From which we get;

T₂ = 3.0 atm. × 300 K/(1.00 atm.) = 900 K

The temperature at point B, T₂ = 900 K

(c) The process from points B to C is a constant temperature process, therefore, T₃ = T₂ = 900 K

(d) For a constant temperature process, according to Boyle's law, we have;

P₂·V₂ = P₃·V₃

V₃ = P₂·V₂/P₃

∴ V₃ = 3.00 atm. × 5.00 L/(1.00 atm.) = 15 L

The volume at point C, V₃ = 15 L

(e) The process A → B, which is a constant volume process, can be carried out in a vessel with a fixed volume

The process B → C, which is a constant temperature process, can be carried out in an insulated adjustable vessel

The process C → A, which is a constant pressure process, can be carried out in an adjustable vessel with a fixed amount of force applied to the piston

(f) For A → B, W = 0,

Q = Eint = n·cv·(T₂ - T₁)

Cv for monoatomic gas = 3/2·R

∴ Q = 0.203 moles × 3/2×0.08205 L·atm·mol⁻¹·K⁻¹×(900 K - 300 K) = 1,518.91596 J

Q = Eint = 1,518.91596 J

For B → C, we have a constant temperature process

Q = n·R·T₂·㏑(V₃/V₂)

∴ Q = 0.203 moles × 0.08205 L·atm/(mol·K) × 900 K × ln(15 L/5.00 L) ≈ 1668.69974 J

Eint = 0

Q = W ≈ 1668.69974 J

For C → A, we have a constant pressure process

Q = n·Cp·(T₁ - T₃)

∴ Q = 0.203 moles × (5/2) × 0.08205 L·atm/(mol·K) × (300 K - 900 K) = -2,531.5266 J

Q = -2,531.5266 J

W = P·(V₂ - V₁)

∴ W = 1.00 atm × (5.00 L - 15.00 L) = -1,013.25 J

W = -1,013.25 J

Eint = n·Cv·(T₁ - T₃)

Eint = 0.203 moles × (3/2) × 0.08205 L·atm/(mol·K) × (300 K - 900 K) = -1,518.91596 J

Eint = -1,518.91596 J

(g) ∑Q = 1,518.91596 J + 1668.69974 J - 2,531.5266 J = 656.089 J

∑W = 0 + 1668.69974 J -1,013.25 J = 655.449 J

∑Eint = 1,518.91596 J + 0 -1,518.91596 J = 0 J

A car moving with uniform acceleration attains speed of 36km/hr in 2 minutes find the acceleration?? ​

Answers

Acceleration = 0.083 m/s²Explanation:

Given:

Initial velocity of car is 0.

Final velocity of car is 36 km/h.

Time taken to attain final speed is 2 minutes.

To Find:

What is the acceleration of car ?

Formula to be used:

v = u + at

Solution: 

First change the final velocity from km/h to m/s and also time to seconds.

[ To change km/h to m/s multiply by 5/18 ]

➙ Final velocity = 36(5/18) = 10 m/s.

[ 1 minutes = 60 seconds ]

➙ 2 minutes = 2(60) = 120 seconds.

Now, we have

v = 10 m/s.

u = 0 m/s.

t = 120 s.

⟹ v = u + at⟹ 10 = 0 + a(120)⟹ 10 = 120a⟹ 10/120 = a⟹ 0.083 m/s² = a

Hence, the acceleration of car is 0.083 m/s².

__more____info_____

➟ The rate of change of velocity is called acceleration. It is denoted by a.

➟ The velocity at which motion starts is termed as initial velocity. It is denote by u.

➟ The last velocity of an object after a period of time. It is denoted by v.

\(\boxed{\large{\bold{\blue{ANSWER~:) }}}}\)

Initial Velocity u = 0

Final Velocity v = 36 km/hr = 10 m/s

Time t = 2 min = 120 sec

Acceleration a = ?

By 1st Equation of motion

we know that,

\(\boxed{\large{\sf{v \: = u \: + a \: t}}}\)

according to the question,

\(10 = 0 + a \times 120\\\\a \: = \frac{10}{120}\\\\a \: = \frac{1}{12}\\\\a=0.083\: m {s}^{ - 2}\)

Therefore,

Acceleration of the car is 0.083 ms^-2

A 45 kg object has a momentum of 225 kg-m/s northward. What is the object's velocity?

Answers

Answer: 5 m/s North

Explanation:

Velocity = Momentum/Mass

Velocity = 225 kg*m/s/45kg

Velocity = 5 m/s North

Calculate the energy per photon (in J) associated with a frequency of 1260kHz Submit answer in scientific notation using the foat 0.00×10∧ 0(e.g.0.000123=1.23×10 ∧
−4). Omit units and spaces.

Answers

The energy per photon associated with a frequency of 1260 kHz is 2.10×10^-25 J.

To calculate the energy per photon, we can use the equation: E = hf, where E represents the energy, h is the Planck's constant (6.62607015 × 10^-34 J·s), and f is the frequency of the photon. Given that the frequency is 1260 kHz, we need to convert it to hertz (Hz) by multiplying it by 10^3:

Frequency = 1260 kHz × 10^3 = 1.26 × 10^6 Hz

Now, we can substitute the values into the equation:

E = (6.62607015 × 10^-34 J·s) × (1.26 × 10^6 Hz)

E = 8.33929859 × 10^-28 J

The answer is given in scientific notation as 8.34 × 10^-28 J. However, the question specifically asks for the answer in the format of 0.00×10^0. To achieve this, we can multiply the result by 10^3 and adjust the exponent accordingly:

E = (8.33929859 × 10^-28 J) × (10^3)

E = 8.33929859 × 10^-25 J

Thus, the energy per photon associated with a frequency of 1260 kHz is 2.10×10^-25 J.

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How does the ratio of tin to copper affect the properties of the alloy bronze?

Answers

Answer:

Stronger and harder than either of the pure metals

Explanation:

Why is density such an important physical property?​

Answers

Answer:

Density is important because it determines what substances floats and sinks.

Explanation:

A ball of mass 0.5 kg is swinging at a small angle from a light string of length 0.25 m. What is the period of this pendulum? Round answer to two significant digits.​

Answers

Answer: 1.0

Explanation:

not sure why but that is the correct answer

Answer:

1.0

Explanation:

Correct answer on Khan Academy

which is a harmful role of bacteria of bacteria?

Answers

Answer:

Harmful bacteria are called pathogenic

Explanation:

Harmful bacteria are called pathogenic bacteria because they cause disease and illnesses like strep throat, staph infections, cholera, tuberculosis, and food poisoning.

When examining evidence, why might investigators want to be more careful examining chemical properties than physical properties.

Answers

Answer:

Please find the answers in the explanation

Explanation:

In examination of any scientific observation, some experiments may be needed to be carried out.

When examining evidence, the investigators might want to be more careful examining chemical properties than physical properties because anything that involve chemical reaction are irreversible. While physical one can be reversible.

Also, reaction can easily take place when examining the chemical properties of some substances.

It is seldom for reaction to take place with physical one.

there can be some complications and danger with chemical properties but less complication and danger with physical one.

Therefore, the investigators will want to be more careful when examining evidence on chemical properties than physical properties due to the given reasons above.

A series RLC circuit has a resistance of 20 , a capacitance of 10-2 F, an inductance of 10 H and an applied voltage E(t) = 200 cos 5t Volts. Assuming no initial current and charge when voltage is first applied, find the subsequent current in the system.

Answers

The subsequent current in the series RLC circuit is given by the equation: i(t) = I * cos(5t - Φ), where I is the amplitude of the current and Φ is the phase angle.

To find the subsequent current, we need to calculate the amplitude (I) and the phase angle (Φ) of the current.

First, let's calculate the resonant frequency (ω) of the circuit:

ω = 1 / √(LC) = 1 / √(10 * 10^(-2)) = 1 / √1 = 1 rad/s.

The applied voltage can be written as E(t) = E * cos(ωt), where E is the amplitude of the voltage.

Comparing this with the given voltage E(t) = 200 * cos(5t), we can equate the angular frequencies: ω = 5.

Now, let's find the impedance (Z) of the circuit:

Z = √(R^2 + (Xl - Xc)^2),

where R is the resistance, Xl is the inductive reactance, and Xc is the capacitive reactance.

R = 20 Ω

Xl = ωL = 1 * 10 = 10 Ω

Xc = 1 / (ωC) = 1 / (5 * 10^(-2)) = 20 Ω

Plugging in these values, we get:

Z = √(20^2 + (10 - 20)^2) = √(400 + 100) = √500 ≈ 22.36 Ω.

The amplitude of the current (I) can be calculated using Ohm's Law:

I = E / Z = 200 / 22.36 ≈ 8.94 A.

The phase angle (Φ) can be found using the relationship between resistance, inductive reactance, and capacitive reactance:

tan(Φ) = (Xl - Xc) / R = (10 - 20) / 20 = -0.5.

Therefore, Φ ≈ -0.464 rad.

The subsequent current in the series RLC circuit is given by i(t) = 8.94 * cos(5t + 0.464) A.

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True or false :if there is a net force acting on an object it means there is an unbalanced force.

Answers

Answer:

true

Explanation:

The object will always accelerate if it has an unbalanced force acting on it in that direction

An astronaut is on a spacewalk to make repairs to the solar panel array on the international space station. The astronaut somehow accidentally bumps into the soyuz space( the one the crew rode up to the iss) and the capsule breaks free of its dock. Which statement describes the motion of the capsules after it breaks free of the iss but before the panicked astronaut are able to retrieve it?

Answers

The motion of the Soyuz capsule after it breaks free of the ISS but before the panicked astronaut retrieves it can be described as an initial state of zero velocity and a free-fall motion caused by gravity.

When the Soyuz capsule breaks free of the ISS, it has an initial velocity of zero relative to the ISS. Since there is no air resistance in space, the only force acting on the capsule is gravity, which causes it to fall towards the Earth. The motion of the capsule can be described as a free-fall motion until some other force, such as atmospheric drag, slows it down or stops it.

if a trian travels 215 km is 3.50 hr, then 175 km in 1.50 hr, and 345 km in 5.50 hr, what will be the average speed of the trian for the whole trip

Answers

Answer:

70km/h

Explanation: add up distances then divide by total time

Answer:

80.26km/hr

Explanation:

speed formulae is speed =distance travelled ÷ time taken

so, we first calculate the first one that is 215÷ 3.50 to get 61.4...

then, we calculate the second that is 175÷1.50 to get 116.67

Then, we calculate the third one that is 345÷5.50 to get 62.7

Then we add all of the three value we calculated that is 61.4+ 116.67 + 62.7 to get 240.77

then we divide 240.77 by 3 to get the average speed that is 80.26km/hr

what is the common abbreviation for millimeters, centimeters,meters

Answers

Answer:

meter m

centimeter cm

millimeter mm

Explanation:

A boat travels at a constant speed of 12.0m/s for 97s. How far does it go?

Answers

Answer:

your mama

Explanation:

because i said so

Answer:

1164m

Explanation:

speed=distance/time, therefore Distance=speed*time.

Now that we have our equation, we plug in the variables, as we do not need to convert our units.

12*97= 1164 m

For the following elementary reaction 2br• -> br2-. The rate of consumption of the reaction and the rate of formation of product is given by which set of expression? ​

For the following elementary reaction 2br -> br2-. The rate of consumption of the reaction and the

Answers

Answer: \(-\frac{1}{2}\times \frac{d[Br^.]}{dt}=+\frac{d[Br_2]}{dt}\)

Explanation:

Rate of a reaction is defined as the rate of change of concentration per unit time.

Thus for reaction:

\(2Br^.\rightarrow Br_2\)

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

\(Rate=-\frac{d[Br^.]}{2dt}\)

or \(Rate=+\frac{d[Br_2]}{dt}\)

Thus \(-\frac{d[Br^.]}{2dt}=+\frac{d[Br_2]}{dt}\)

When the mass of the cylinder increased from 3.0 kg to 6.0 kg, what happened to the amount of heat generated in the system? it decreased by a factor of 3. it decreased by a factor of 2. it increased by a factor of 2. it increased by a factor of 3.

Answers

Option c. It is increased by 2.

Heat generation that is thermal capacity of an object is dependent on mass. So if the mass of an object increases, the heat generation also increases.

How thermal capacity is related to mass?

Thermal capacity= mass × specific heat

As we can see by the formula, that the thermal capacity is directly proportional to mass. So if the mass of the object increases, so does the thermal capacity.

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The answer is C:

It increased by a factor of 2.

When converting from smaller to larger units the decimal point travels right *

Answers

Answer:

False, it travels left.

Explanation:

Hello.

In this case, we can answer this with an example. If we have 200 g and we want that value in a larger unit, for instance, kilogram, the following conversion is performed since 1 kg equals 1000 g:

\(200g*\frac{1kg}{1000kg}=0.200g\)

Whereas we needed to move the decimal point from right to left, which means that it travels left, that is why the statement is false.

Best regards.

A 1000 ml graduated cylinder contains an aqueous solution of soil. You notice three distinct layers after the solution was shaken and allowed to sit for 2 days; any organic material was removed. You observed layers within the column: sand, silt, and clay. Sand is on the bottom, silt in the middle, and clay on the top. After settling, the top layer goes from 920 ml down to 903 ml; the next layer from 903 down to 745, and the bottom layer from 745 to 0 ml.

a. Name the component of each layer.

b. What is the percentage of each layer?

c. What is this soil's textural callsification?

Answers

The answer is A name the component of each layer

In the heat equation what does Q represent

Answers

The heat equation is Q = mcT


Q is the total amount of heat transferred to or from something.

an object is realsed From rest . how far does it fall during the second second of fall?​

Answers

Answer:

14.715 m

Explanation:

Assume that the acceleration due to gravity is 9.81 m/s^2 downwards, take downwards as positive

First second:

v = u + at

v = 9.81 m/s

Second second:

s = ut + (1/2)at^2

s = 9.81(1) + (1/2)(9.81)(1)^2

s = 14.715 m

If a spring has a spring constant of 0. 5 N/m and it is stretched 0. 5 m, what is the force

of the spring?

Answers

Answer:

0.25N

Explanation:

k=0.5N/m

e=0.5m

f=?

were k=spring constant

e=extension

F=force

According to hooks law,

f=ke

f=0.5x0.5 =0.25 N

A fish inside the water 12cm below the surface looking up through the water sees the outside world contained in a circular horizon. If the refractive index of water is 4/3 the radius of circle is​

Answers

Answer:

13.6 cm

Explanation:

From Snell's law:

n₁ sin θ₁ = n₂ sin θ₂

In the air, n₁ = 1, and light from the horizon forms a 90° angle with the vertical, so sin θ₁ = sin 90° = 1.

Given n₂ = 4/3:

1 = 4/3 sin θ

sin θ = 3/4

If x is the radius of the circle, then sin θ is:

sin θ = x / √(x² + 12²)

sin θ = x / √(x² + 144)

Substituting:

3/4 = x / √(x² + 144)

9/16 = x² / (x² + 144)

9/16 x² + 81 = x²

81 = 7/16 x²

x ≈ 13.6

A fish inside the water 12cm below the surface looking up through the water sees the outside world contained

if line segment g f = 3.2 ft, which is a possible measure of line segment t s? 1.6 ft 3.0 ft 3.2 ft 4.0 ft\

Answers

By applying the relationship of side lengths to interior angles in a triangle, a possible measure of line segment TS is 4.0 ft.

The relationship of sides to interior angles in a triangle.

In Geometry, the relationship of side lengths to interior angles in a triangle include the following:

The shortest side length is always opposite of the smallest interior angle.The longest side length is always opposite of the largest interior angle.

Based on the above theory, we can logically deduce that angle GF < TS or TS > GF because 42° is greater than 56°.

TS > 3.2 ft.

Therefore, a possible measure of line segment TS is 4.0 ft.

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Complete Question:

In the triangles, TR = GE and SR = FE. If Line segment G F = 3.2 ft, which is a possible measure of Line segment TS? 1.6 ft 3.0 ft 3.2 ft 4.0 ft.

if line segment g f = 3.2 ft, which is a possible measure of line segment t s? 1.6 ft 3.0 ft 3.2 ft 4.0

Lorenzo is making a prediction. “I learned that nonmetals increase in reactivity when moving from left to right.” Is Lorenzo correct? If so,why? Explain his error

Answers

Answer:

No, he is not correct. Xenon is not very reactive since it is located in the group of noble gases. The noble gases are all chemically unreactive gases.Elements within different groups within the periodic table have different physical and chemical properties. Hope this answers the question.

Explanation:

Yes

Sample Response: Lorenzo is not correct. Nonmetals increase in reactivity from left to right because nonmetals on the right have more valence electrons. They need to gain fewer electrons to have a full outer shell. However, this trend only continues until group 17, because the noble gases already have a full outer shell. Therefore, their reactivity is the least of all the elements.

~theLocoCoco

If a reaction occurs when a piece of metal is placed in a solution, what can you conclude about the solution?

Answers

You can conclude that the solution is probably acidic because bases rarely react with metals.

In which situation is the net force on the object equal to zero?


A.) a bicycle moving at a constant speed on a straight, level road

B.) an automobile braking to a stop

C.) a satellite moving at a constant speed around Earth in a circular orbit

D.) a pitched baseball being hit by a bat

Answers

Answer:

A.) a bicycle moving at a constant speed on a straight, level road.

Explanation:

Force is given by the multiplication of mass and acceleration.

Mathematically, Force is;

\( F = ma\)

Where;

F represents force measured in Newton.

m represents the mass of an object measured in kilograms.

a represents acceleration measured in meter per seconds square.

In Physics, when the net force acting on a body or an object is equal to zero (0); the body or object is said to be in a state of equilibrium because it is not accelerating. This ultimately implies that, an object whose net force is equal to zero is either moving with a constant speed or the object is static i.e not moving at all.

In this scenario, the situation in which the net force on the object is equal to zero would be a bicycle moving at a constant speed on a straight, level road because it is at equilibrium and as such its resultant force is equal to zero.

The net force on the object (bicycle) is zero due to its constant speed on a straight levelled road. Hence, option (A) is correct.

The given problem is based on the Newton's second law to define net force. The net force on any object is an external effort by which the object change its speed with respect to time or tends to change the state of its motion. The mathematical expression for the net force is,

F = ma

Here, F is the net force, m is the mass of object and a is the acceleration of object.

When the net force acting on a body or an object is equal to zero , then the body or object is said to be in a state of equilibrium because it is not accelerating. This ultimately implies that, an object whose net force is equal to zero is either moving with a constant speed or the object is static i.e not moving at all.

In the given problem the net force on the object is equal to zero would be a bicycle moving at a constant speed on a straight, level road because it is at equilibrium and as such its resultant force is equal to zero.

Thus, we conclude that the net force on the object (bicycle) is zero due to its constant speed on a straight levelled road. Hence, option (A) is correct.

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While on a vacation in Kenya, you visit the port city of Mombassa on the Indian Ocean. On the coast is an old Portuguese fort with large stone walls rising vertically from the shore. An inscription on a plaque states that the walls are an impressive 44 m high. You find the fort's cannons mounted so that they fire horizontally out of openings near the top of the walls facing the ocean. Calculate the muzzle velocity necessary to hit a ship 300.0 meters from the base of the fort.​

Answers

The muzzle velocity necessary to hit a ship is 100 m/s

The motion of a cannonball that is fired from the gun is a typical projectile motion. The motion occurs in a vertical plane. The cannonball traces out a parabolic path during the motion. Projectile motion is governed by gravity. The cannonball has a constant downward acceleration, the acceleration due to gravity g

This vertical acceleration is responsible for the parabolic path which would otherwise have been a straight-line path.

By equation of motion from A to B in horizontal direction

S = ut + 1/2 at^2

Where, acceleration in horizontal direction a = 0

Therefore,

S = ut + 0

300 = u(3)

u = 100 m/s

Hence, the muzzle velocity necessary to hit a ship is 100 m/s

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Two stars orbiting each other are separated by 6.67 AU and revolve around their common center of gravity in 10 years. Use Newton’s form of Kepler’s third law to calculate the combined mass of the 2 stars in solar masses.

Answers

Answer:

The combined mass of the two stars is 2.9417 solar masses.

Explanation:

The mathematical expression for Kepler's third law is;

                        \(P^{2}\) = \(\frac{4\pi ^{2} }{k^{2} (M_{1} + M_{2} }a^{3}\)

Where: P is the period in days, a is the semimajor axis in AU, \(M_{1}\) is the mass of the first star, \(M_{2}\) is the mass of the second star and k is the Gaussian gravitational constant.

Given that;

P = 10 years = 3670 days (including two leap years)

a = 6.67 AU

k = 0.01720209895 rad

\(\pi\) = \(\frac{22}{7}\)

The sum of the masses of the two star can be determined by;

\((M_{1} + M_{2})\) = \(\frac{4\pi ^{2} }{P^{2}k^{2} } a^{3}\)

                = \(\frac{4*(\frac{22}{7}) ^{2} } {(3650)^{2} * (0.01720209895)^{2} } (6.67)^{3}\)

                = \(\frac{11724.29601}{3942.2904}\)

               = 2.9417 solar masses

Thus the combined mass of the two star is 2.9417 solar masses.

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