If the temperature of a gas in a 2.0 L sealed container with variable volume is doubled, what will the volume of the container increase to?
Answers
Answer:
look below
Explanation:
If the temperature of a gas in a sealed container with a fixed number of molecules is increased, the gas will expand. This is because the increased temperature will cause the gas molecules to move more quickly and collide more frequently with the walls of the container. These collisions will exert a greater force on the walls of the container, causing the volume of the container to increase.
If the volume of the container is allowed to vary (i.e., if it is not sealed), then the volume of the container will increase as the temperature is increased. The exact increase in volume will depend on the size of the container and the specific gas that is being heated.
If the temperature of a gas in a 2.0 L sealed container is doubled, the volume of the container will increase, but it is not possible to determine the exact increase in volume without knowing the specific gas that is being heated and the pressure and temperature at which the gas was originally contained.
Related Questions
In SEC, in what volume would you expect molecules that are much smaller than the fractionation range of the Sephadex SP to elute?A. ViB. VmC. VavD. VrE. Vo
Answers
In SEC, molecules that are much smaller than the fractionation range of the Sephadex SP will elute in the void volume, represented by the symbol (option E)Vo.
In SEC (Size Exclusion Chromatography), the separation of molecules is based on their size. Sephadex SP is a matrix with a specific fractionation range that separates molecules based on their size. Molecules that are much smaller than the fractionation range of the Sephadex SP will not interact with the matrix and will not be separated from the void volume (Vo). Therefore, they will elute in the void volume (Vo) which is the volume of the mobile phase that is not retained by the matrix. Hence, the correct option is E. Vo.
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How many grams of Cl2 will be produced along with 250.0 kJ of heat in the following reaction? Pc 5(g) + 87.9 k/
Answers
Answer:
As per the given chemical equation, 1 mole of Cl₂ is formed when 87.9 kJ of heat is absorbed. 201.64 g of Cl₂ will be produced along with 250.0 kJ of heat in the given reaction.
Explanation:
answer the question.........
mb wrg subject but its biology
Answers
The description of nonpoint source pollution is dirty drainage from city roadways.
The correct option is A.
What is pollution?Pollution describes the presence of substances in the environment that are harmful to the living organisms present in that environment.
Pollution may be classified based on the source of the pollution into:
point source pollution - point source pollution refers to pollution whose origin or source point is easily identifiable such as sewage from homes and industries or smoke from industriesnon-point source pollution - non-point source pollution refers to pollution whose source point is not easily identifiable, rather, it occurs as a result of the runoff or water snow that then carries pollutants from various sources as they flow. For example, after a flood, the flood water carries several pollutants with it as it flows over drainages and the ground.Learn more about nonpoint source pollution at: https://brainly.com/question/1557306
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On average, a well-balanced 2,200-kilocalorie diet is expected to provide ________ of water.
Answers
Answer:
12 cups
Explanation:
explain why it is the freezing point depression of a solvent does depend on the concentration of the solute.
Answers
The reason why the freezing point depression of a solvent depends on the concentration, it is because the solute occupies space between the solvent molecules.
The freezing point depression of a solvent depends on the concentration of the soluteThe freezing point depression of a solvent does depend on the concentration of the solute because the solute occupies space between the solvent molecules, thus reducing the number of molecules that can interact.
When a solute is dissolved in a solvent, it takes up space between the solvent molecules. This reduces the number of molecules that can interact, and thus lowers the freezing point of the solvent. The more concentrated the solution, the greater the effect on the freezing point.
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How would you do this
Answers
The empirical formula = the molecular formula = C₁₀H₂₀O
Further explanationGiven
m = 0.15 g menthol
V = 0.0337 L
T = 150 +273 = 423 K
P = 100.2 kPa =0.99 atm
Required
molar mass
The molecular formula
Solution
Ideal gas law :
PV=nRT
n=PV/RT
n=0.99 x 0.0337/0.082 x 423
n=9.6 x 10⁻⁴
n = mass/Molar mass
Molar mass = mass/n
Molar mass = 0.15/9.6 x 10⁻⁴
Molar mass = 156.25 g/mol
The empirical formula of Menthol : C₁₀H₂₀O
(The empirical formula)n= molecular formula
(C₁₀H₂₀O)n=156.25
(12.011.10+1,007.20+15,999)n=156.25
(156.25)n=156.25
n=1
5) To check the accuracy of our results we will compare our results to the label on the vinegar bottle. The bottle contains 4% vinegar. We will need to change our M results to %% in order to calculate a percent error.
Using the average M and the average volume (you have to change it to LITERS) of the acetic acid find the # of moles of acetic acid using the molarity formula from Table T.
Change moles to grams using the gfm of acetic acid (HC,H,O,).
Divide grams of acetic acid by the average volume (this time in ml.) of acetic acid and then multiply by 100. This is your experimental %.
Calculate the % error.
6. What other indicator could we have used?
7. What adjustment to our calculations would we have needed to make if we used barium hydroxide rather than sodium hydroxide? (It might be helpful to write the formula for barium hydroxide
Answers
5) Convert molarity to percent, calculate moles of acetic acid, convert moles to grams, divide grams by volume in mL, multiply by 100 to obtain experimental percent, and calculate percent error.
6) Phenolphthalein could have been used as an alternative indicator.
7) When using barium hydroxide instead of sodium hydroxide, adjust the calculations by considering the stoichiometry of the reaction and using a molar ratio of 2:1 between acetic acid and barium hydroxide.
5. To calculate the percent error in the concentration of acetic acid, we need to convert our molarity (M) results to percent (%). Using the average molarity and the average volume (converted to liters) of acetic acid, we can calculate the number of moles of acetic acid.
Then, by converting moles to grams using the molar mass of acetic acid (CH3COOH), we can divide the grams of acetic acid by the average volume (in milliliters) of acetic acid and multiply by 100 to obtain the experimental percent.
Finally, we can calculate the percent error by comparing the experimental percent to the labeled percent (4% vinegar on the bottle).
6. An alternative indicator that could have been used is phenolphthalein. Phenolphthalein is commonly used in acid-base titrations and changes color in a specific pH range, indicating the endpoint of the reaction.
6. If barium hydroxide (Ba(OH)2) were used instead of sodium hydroxide (NaOH), the adjustment in calculations would involve the stoichiometry of the reaction. The balanced chemical equation for the reaction between acetic acid and barium hydroxide is:
2CH3COOH + Ba(OH)2 → Ba(CH3COO)2 + 2H2O
The molar ratio between acetic acid and barium hydroxide is 2:1. Therefore, the number of moles of barium hydroxide used would be half the number of moles of acetic acid in the calculation.
The rest of the procedure, including converting moles to grams and calculating the percent, would remain the same.
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Explain the difference between emission and absorption spectra.
Answers
The major distinction between emission and absorption spectra is that an emission spectrum has various colored lines, whereas an absorption spectrum contains dark-colored lines. When electrons return to their original energy levels, this is called emission. When electrons absorb energy, they leap to higher energy levels. When ground-state atoms absorb energy from a radiation source, atomic absorption spectra are created. When neutral atoms in an excited state return to the ground state or a lower-energy state, they release energy, resulting in atomic emission spectra.
determine the best type graph to use if you are trying to compare quantities for four separate options that are not related to the dependent or independent variables and that are not measured over time. explain
Answers
Bar graph is the best type of graph to use if you are trying to compare quantities for four separate options that are not related to the dependent or independent variables and that are not measured over time.
What are bar graphs?Bar graphs are the type of graph that can be used when the data measurement between different variable are not continuous or not measured over time.
The advantages of bar graphs include the following:
Summarizes large data in visual form.Clarifies Trends better than tables. Easily understood by most people. Allows estimation of key values at a glance. Permits visual check of accuracy and reasonableness of calculations. Displays relative numbers or proportions of multiple categories.Therefore, Bar graph is the best type of graph to use if you are trying to compare quantities for four separate options that are not related to the dependent or independent variables and that are not measured over time.
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Suppose you want to search for high-redshift star-forming galaxies using a telescope equipped with a spectrograph able to measure the entire optical spectrum (400-700 nm). Star-forming galaxies contain copious hydrogen gas, from which stars form. Some of this gas will be ionized by the newly-formed stars; the spectra of star-forming galaxies there exhibit bright hydrogen lines in emission. Light from the newly-formed stars is absorbed by neutral hydrogen gas as it passes through the galaxy. a) If you wish to search for Lyman-a emitting galaxies, over what redshift range can you find such galaxies? [3 points] b) If you detect only one line, you cannot be certain that this line is the Lyman-a line, and hence that the galaxy is indeed at the computed redshift. Assuming you can also observe in the infrared (wavelengths >700 nm), how can you change your strategy to make sure that the line you detect is really the Lyman-a line? Give three examples of how you can increase confidence in the correct identification of the Lyman-a line considering only hydrogen gas. [3 points] c) Limited only to optical wavelengths and considering only hydrogen gas, what strategy should you adopt to be certain that the line you detect is really the Lyman-a line while maximizing the redshift range over which you find galaxies? With this strategy, over what redshift range can you find star-forming galaxies? Justify through appropriate computations and reasoning that this is in fact the optimal strategy for maximizing the redshift range of your search. [10 points] d) Apart form hydrogen emission lines, star-forming galaxies also usually exhibit bright [OIII] forbidden lines. Why can such lines be seen from interstellar gas but not the Earth's atmosphere or in the laboratory? [4 points]
Answers
a) The maximum observable range of redshifts that produces Lyman-alpha line is 0 ≤ z ≤ 10.6
b) i) identifying the galaxy with a radio source, ii) looking for other Lyman lines, iii) a coincidence with a continuum break
c)The maximum redshift range over which galaxies can be found using this strategy is z = 7 to z = 15.5.
d)Earth's atmosphere absorbs the radiation, and the laboratory conditions are not the same as interstellar conditions.
a) Lyman-alpha line is produced by the hydrogen atoms that have electrons that are in the ground state being raised to the first excited state. Over a certain range of redshifts, the Lyman-alpha line is redshifted to longer wavelengths that are observable by an optical spectrograph. The maximum observable range of redshifts that produces Lyman-alpha line is 0 ≤ z ≤ 10.6 (depending on the exact details of the galaxy's emission profile).
b) Observing the galaxy in the infrared can help in the identification of the Lyman-alpha line as it is shifted to longer wavelengths. Three ways to increase confidence in the correct identification of the Lyman-alpha line are:
i) identifying the galaxy with a radio source, ii) looking for other Lyman lines, iii) a coincidence with a continuum break.
c) The strategy that needs to be adopted is to look for the Lyman limit, which is the point at which the spectrum is cut off by the absorption of all hydrogen in the galaxy. To be certain that the line you detect is the Lyman-alpha line, you need to look for a decrement in the flux of the galaxy at wavelengths shorter than the line and a decrement in the flux at wavelengths longer than the line. This is because the Lyman limit will be shifted to longer wavelengths at higher redshifts, so to maximize the redshift range over which galaxies can be found, you need to search for the Lyman limit at the longest wavelength possible. The maximum redshift range over which galaxies can be found using this strategy is z = 7 to z = 15.5.
d) The reason why such lines can be seen from interstellar gas but not the Earth's atmosphere or in the laboratory is that the Earth's atmosphere absorbs the radiation, and the laboratory conditions are not the same as interstellar conditions. The forbidden lines from the interstellar gas are not affected by dust absorption because they are produced in regions where dust is not present.
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A compound with an empirical formula of CFBrO and a molar mass of 253.8 grams per mole. Given this data, determine the number of carbon atoms in the compound's molecular formula.
Answers
The compound's molecular formula contains three carbon atoms.
Step 1: The empirical formula CFBrO indicates that there is one carbon atom in the compound.
Step 2: To determine the number of carbon atoms in the molecular formula, we need to find the ratio between the empirical formula mass and the molar mass.
The empirical formula mass is calculated by adding the atomic masses of the constituent elements in the empirical formula:
C = 12.01 g/mol
F = 18.99 g/mol
Br = 79.90 g/mol
O = 16.00 g/mol
Empirical formula mass = (1 x 12.01) + (1 x 18.99) + (1 x 79.90) + (1 x 16.00) = 126.9 g/mol
Next, we divide the molar mass (253.8 g/mol) by the empirical formula mass (126.9 g/mol) to find the ratio:
253.8 g/mol ÷ 126.9 g/mol = 2
This ratio indicates that the compound's molecular formula contains two empirical formula units. Since each empirical formula unit contains one carbon atom, the compound's molecular formula must contain two carbon atoms.
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a 10.0 ml aliquot of a liquid is found to have a mass of 7.883 grams. calculate the density of this liquid.
Answers
The density of the liquid is: 0.7883 g/ml
What is density?It is a physical quantity that expresses the ratio of the body mass to the volume it occupies.
The formula and the procedure we will use is:
d = m/v
Where:
v= volumed= densitym= massInformation about the problem:
m = 7.883 gv = 10.0 mld = ?Applying the density formula we get:
d = m /v
d = 7.883 g /10.0 ml
d = 0.7883 g/ml
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Ribbon diagrams shows secondary structures and appear less detailed than other model types. In one to two sentences, give a reason the chemists would use ribbon diagrams. What type of information do they provide?
Answers
Answer:
They show helixes and proteins
Explanation:
Ribbon diagrams are the Richardson diagrams that represent the protein structures. Chemist prefers using Ribbon diagrams to show the various structure of the proteins.
What are ribbon diagrams?The Ribbon diagram is used to represent the structural organization of the protein in the polypeptide chains or individually. It shows the three-dimensional structure and organization of the protein framework.
The ribbon diagram for the secondary structure of the protein shows the intramolecular and intermolecular structure along with helixes and bonding. It shows the detailed structure of the protein organization including the helix and sheets.
Therefore, the ribbon diagram is used by chemists to determine the structure of the protein as they give the details about the helix and sheet.
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Which structure is found in producers in nearly all ecosystems?
A. stems
B. chloroplasts
C. leaves
D. rhizomes
Answers
when 25 ml of 0.12 m aqueous ammonia is titrated with 0.12 m hydrobromic acid, what is the ph at the equivalence point?
Answers
The pH value will be equal to 3.29 at the equivalence point.
What is titration?Titration is the laboratory method that is performed to determine the concentration of the analyte. An indicator is used to know the equivalence point.
Given the concentration of HBr = 0.12 M
The concentration of ammonia = 0.12 M
The value of Kb for ammonia = 1.8 ×10⁻⁵
The chemical reaction is :\(NH_3 + HCl \longrightarrow NH^+_4 + Cl^-\)
For the ammonia: NH₃ NH₄⁺ H⁺
Initial conc.: 0.12 M ---- -----
Change: - x + x +x
At equilibrium: 0.12-x x x
The acid dissociation constant :\(K_a =\frac{[NH_4][H^+]}{[NH_4^+]}\)
\(\frac{K_w}{K_b} =\frac{[NH_4][H^+]}{[NH_4^+]}\)
\(\frac{1\times 10^{-14}}{1.8\times 10^{-5}} =\frac{(x)(x)}{(0.12-x)}\)
\(5.56\times 10^{-10}=\frac{x^2}{0.12-x}\)
x² + 5.56× 10⁻⁵ x- 46.33 × 10⁻¹⁰ = 0
x = 4.57 × 10⁻⁵
The concentration of hydrogen ions = 4.57 × 10⁻⁵
The pH value = - log [H⁺]
pH = -log [4.57 × 10⁻⁵]
pH = 3.29
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Sn + 2Ha -> SnCl2 + H2
a. synthesis
b. single replacement
C. combustion
d. double replacement
e decomposition
Answers
Answer:
your question is totally wrong. there is no cl2 in reactants.
NaCl solution is an example of a/an ____________.A. ConductorB. MetalloidC. InsulatorD. Nonmetal
Answers
When NaCl is placed in water, it becomes an aqueous solution, one thing that occurs in this situation is that NaCl, which is an ionic compound, will dissociate into Na+ and Cl-, this dissociation into ions will cause the solution to become a good conductor of electricity. Therefore the correct answer will be letter A
Rank the following atoms according to decreasing first ionization energy. (i.e. 1 = highest and 4 = lowest)
Options are Al, P, Mg, K?
Answers
The decreasing order of ionization energy will be Mg >Al >P>K.
Ionization energy sometimes referred to as ionization potential, would be the amount of energy it takes to eliminate an electron from a single, isolated atom or molecule.
On moving top to bottom in the periodic table, ionization energy will decrease rapidly.
Al =13 (group 3)
P =15 (group 5)
Mg =12 (group 2)
K =19 (group 1)
The decreasing order of ionization energy will be Mg >Al >P>K.
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Could a person at the South Pole see the North Star? Explain.
Answers
Answer:
Yes
Explanation:
Because yes
Answer:
Yes, North is a direction and the south pole is a place so yes you can see the north star from the south pole
Explanation:
sulfide is formed when copper and sulfur are heated together. In this reaction, 130 g of copper reacts with 45 g of sulfur. After the reaction is complete, 8.0 g of unreacted sulfur remain. What is the mass of copper(II) sulfide formed?
Answers
The mass of copper(II) sulfide formed when copper and sulfur are heated together is 167g.
How to calculate mass of products and reactants?The law of conservation of mass states that the mass of a substance can neither be created nor destroyed.
This law further explains that in a chemical reaction, the mass of the reactants must equal the mass of the products.
According to this question, sulfide is formed when copper and sulfur are heated together. In a reaction, 130 g of copper reacts with 45 g of sulfur.
However, after the reaction is complete, 8.0 g of unreacted sulfur remain. This suggests that the mass of sulfide produced is as follows:
(130g + 45g) - 8g = 167g
Therefore, the mass of copper(II) sulfide formed when copper and sulfur are heated together is 167g.
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The half-life of Palladium-100 is 4 days. After 16 days a sample of Palladium-100 has been reduced to a mass of 6 mg. What was the initial mass (in mg) of the sample
Answers
Answer:
96mg
Explanation:
Since the half-life of Palladium-100 is 4 days and the sample has been reduced after 16 days, that means the sample has undergone four half-lives. To find the intial mass, just work backwards:
6 x 2= 1212 x 2= 2424 x 2= 48 48 x 2= 96As you see, I've worked backwards from the four half-lives. So the initial mass after 16 days is 96 mg.
Student Name:
Lesson Check: Weather Patterns
Date:.
10) Scientists are monitoring two colliding air masses along a frontal boundary. They are
concerned that a tornado may form.
Which data collected along the frontal boundary would best alert scientists that the two
colliding air masses may cause a tornado?
OA) strong gusty winds and cloudy skies where the fronts meet
OB)
O C)
air masses of the same temperature and altitude coming together where the fronts
meet
large differences in temperature, humidity, and air pressure on either side of where
the fronts meet
D)
many similarities in the altitude of clouds, amount of clouds, and wind direction on
either side of where the fronts meet
Answers
The data collected along the frontal boundary would best alert scientists that the two colliding air masses may cause a tornado is large differences in temperature, humidity, and air pressure on either side of where the fronts meet. Therefore, option C is correct.
What happens when two weather fronts meet?When two different air masses collide, they do not mix. They rub up against each other along a line known as a front. Because warm air is lighter, it rises when it collides with cold air. It cools at high altitude, and the water vapor it contains condenses.
A weather front is a transition zone at the Earth's surface between two different air masses. Each air mass has its own temperature and humidity profile.
Turbulence is common at a front, which is the boundary between two different air masses. Clouds and storms can form as a result of turbulence.
Thus, option C is correct.
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to form ozone in the stratospheric ozone layer, a reaction splits an oxygen molecule (o2) into oxygen atoms, which then combine with oxygen molecules to make an ozone molecule
Answers
To form ozone in the stratospheric ozone layer, a photochemical reaction splits an oxygen molecule (\(O_2\)) into oxygen atoms. These oxygen atoms then combine with other oxygen molecules to form ozone (\(O_3\)). This particular reaction requires ultraviolet (UV) radiation that is present in sunlight.
Here is the process:
1. Ultraviolet (UV) radiation from the sun penetrates the Earth's atmosphere and reaches the stratosphere.
2. When UV radiation interacts with an oxygen molecule (\(O_2\)), it breaks the bond between the two oxygen atoms, resulting in two oxygen atoms.
3. These oxygen atoms are highly reactive and can quickly react with other oxygen molecules (\(O_2\)) in the atmosphere.
4. The oxygen atoms combine with the oxygen molecules to form ozone (\(O_3\)). This reaction releases energy.
5. The ozone molecules that are formed contribute to the formation of the stratospheric ozone layer, which plays a vital role in absorbing and filtering out harmful UV radiation from the sun.
In summary, the photochemical reaction in the stratospheric ozone layer involves the splitting of oxygen molecules by UV radiation from the sun, followed by the combination of oxygen atoms with other oxygen molecules to form ozone. This process helps protect the Earth's surface from excessive UV radiation.
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Complete question: to form ozone in the stratospheric ozone layer, a ________ reaction splits an oxygen molecule (\(O_2\)) into oxygen atoms, which then combine with oxygen molecules to make an ozone molecule (\(O_3\)). This particular reaction requires ________ radiation that is present in sunlight.
The mass number is the average mass of all isotopes of that element, while the atomic mass is the quantity of protons and neutrons within one atom/isotope. true or false
Answers
Answer:
False
Explanation:
Mass number is the quantity of protons and neutrons within one atom while the atomic mass is the average mass of all isotopes of the element.
Answer:
false :)
Explanation:
What is the symbol for an ion with a 3+ charge, 28 electrons, and a mass number of 71
Answers
Answer:
Ga3+ is a gallium cation
How many grams of calcium hydroxide will be needed to completely react with 29.5 grams of sodium phosphate given the reaction below:
3 Ca(OH)2 + 2 Na3PO4 = Ca3(PO4)2 +6 NaOH
Answers
Explanation:
Wyzant
CHEMISTRY
Zoey C. asked • 06/05/19
Calcium hydroxide reacts with sodium phosphate to produce calcium phosphate and sodium hydroxide. If 100 grams of calcium hydroxide reacts with 100 grams of sodium phosphate,
determine the amount of each chemical present when the reaction is complete
Grams calcium hydroxide =?
Grams of sodium phosphate=?
Grams of calcium phosphate=?
Grams of sodium hydroxide?
Mass reactants=?
Mass after reaction?
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J.R. S. answered • 06/06/19
TUTOR 5.0 (133)
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3Ca(OH)2 + 2Na3PO4 ==> Ca3(PO4)2 + 6NaOH ... balanced equation
First, find the limiting reactant:
moles Ca(OH)2 present = 100 g x 1 mole/74.09 g = 1.35 moles (divided by 3-->0.45)
moles Na3PO4 present = 100 g x 1 mole/163.9 g = 0.610 moles (divided by 2-->0.31)
LIMITING reactant is Na3PO4
There will be zero grams Na3PO4 left after the reaction
For grams Ca(OH)2 left: 0.610 mol NaP x 3 mol Ca(OH)2/2 mol NaP = 0.915 mol Ca(OH)3 used up
Grams left over: 1.35 mol - 0.915 mol = 0.435 mol x 74.09 g/mol = 32 g left over (30 g if use 1 sig. fig.)
For grams of calcium phosphate left: 0.610 mol NaP x 1 mol CaP/2 mol NaP = 0.305 mol CaP formed
Grams at end of rx: 0.305 moles CaP x 310 g/mol = 94 g (90 g if use 1 sig. fig.)
For grams NaOH left: 0.610 mol NaP x 6 mol NaOH/2 mol NaP = 1.83 moles NaOH formed
Grams at end of rx: 1.83 moles NaOH x 40 g/mol = 73 g (70 g if use 1 sig. fig.)
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According to stoichiomtry, 19.99 grams of calcium hydroxide will be needed to completely react with 29.5 grams of sodium phosphate.
Stoichiometry is a process of the determination of proportions of elements or compounds that are present in a chemical reaction. The related relations are based on law of conservation of mass and law of combining weights and volumes.
Stoichiometry is often used in quantitative analysis for measuring concentrations of substances which are present in the sample.
As per the stoichiometry of the the given balanced chemical equation,\(222.27\ g\) calcium hydroxide gives \(327.88 \ g\) sodium phosphate, thus,\(29.5 \ g\) sodium phosphate requires,
\(\dfrac{29.5}{327.88}\times{222.27}\\=19.99 \ g\)
Thus, 19.99 grams of calcium hydroxide will be needed to completely react with 29.5 grams of sodium phosphate.
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What is a metamorphic rock?
A. A rock that forms from pieces of other rocks that are cemented together
B. A rock that forms from magma or lava as a result of cooling and hardening
C. A rock that forms from another rock as a result of heat, pressure, or both heat and pressure
D. A rock that forms from the remains of plants or animals that are compacted together
Answers
Answer: Metamorphic rocks arise from the transformation of existing rock types, in a process called metamorphism, which means "change in form". The original rock is subjected to heat and pressure, causing profound physical or chemical change. The protolith may be a sedimentary, igneous, or existing metamorphic rock.
Explanation:
Answer: that will be B I am sorry if it is wrong that what it says for me
Compared to a potassium atom, a potassium ion has
Answers
Explanation:
has lost 1 electron. Therefore, a potassium ion has a smaller radius since it has less electrons.
1.
When 1• 50g of ethanol
was
apparatus 500g of water.
vapour
20°C to 39-5°C
enthalpy of compustion of
combustion
raised the temp forom
the
Calculate
ethanol
the
Answers
The heat that has been taken in by the water is 40.2 kJ.
What is the heat of combustion of the water?We know that when we heat the water the water would be turned from liquid to the vapor state . As such we are interested in the heat that would be evolved when this process would be taking place and we can be ale to write that;
H = mcdT
H = heat that have been evolved or absorbed
m = mass of the water
c = Heat capacity of the water
dT = The temperature change of the water.
As such, we have that;
H = 500 * 4.12 * (39.5 - 20)
H = 40.2 kJ
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what is not a colligative property
Answers
Qualities of a solution known as coagulative qualities rely on the quantity of solute particles present but not on the kind of solute.
Boiling point elevation, osmotic pressure, and vapour pressure depression are a few examples of colligative qualities. Solubility is the response to the query of what is not a collative property.
The amount of a solute that can dissolve in a solvent is known as its solubility, and the solute's type does affect this quantity. Solubility is not a collative quality, then.
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