If the same large amount of heat is added to a 250 g piece of aluminum and a 150 g piece of aluminum, what will happen?

A and C are the correct statements that describe trends in atomic radii for ions.

A cation, which is a positively charged ion, is smaller than its neutral atom because the loss of electrons reduces the electron-electron repulsion, making the remaining electrons closer to the nucleus. On the other hand, an anion, which is a negatively charged ion, is larger than its neutral atom because the increase in electrons leads to greater electron-electron repulsion, which pushes the electrons further away from the nucleus.

Statement B is incorrect because as the number of protons increases, the ion size decreases in an isoelectronic series, as there is a greater positive charge holding the same number of electrons closer to the nucleus.

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Answer:

A

B

A

B

B

Explanation:

B - MIXTURE

A - COMPOUND

The dissociation constant of the acid HA in a 0.1 M solution with a pH of \(1×10^-5 is 3.\)

The pH of a solution made by combining 100 ml of aqueous solution with 0.1 mole of HA acid was discovered to be 3.0. Determine the acid's dissociation constant. A 0.1 M solution of an organic acid has a pH of 4.0.

\(Ka = [H+][A-]/[HA]\)

\(Ka = [H+]^2/[HA]\)

\([H+] = sqrt(Ka*[HA])\)

For an acid with a dissociation constant of \(1×10^-5\), the pKa is given by:

\(pKa = -log10(Ka) = -log10(1×10^-5) = 5\)

Substituting the values into the expression for [H+], we get:

\([H+] = sqrt(1×10^-5 * 0.1) = 1×10^-3 M\)

Taking the negative logarithm of [H+] to find the pH, we get:

\(pH = -log10([H+]) = -log10(1×10^-3) = 3\)

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Based on the hypotheses discussed in Chapter 12 regarding melting points and the forces that hold materials together, we can make a prediction about the forces holding atoms of cesium and lithium together in their solid metal forms.

One hypothesis suggests that stronger forces between atoms result in higher melting points. Another hypothesis proposes that metals are held together by metallic bonds, where positively charged metal ions are surrounded by a sea of delocalized electrons.

Considering these hypotheses, we can infer that cesium atoms would be held together by stronger forces compared to lithium atoms in their solid metal forms. This is because cesium is located further down the periodic table, belonging to Group 1 (alkali metals), whereas lithium is in Group 2 (alkaline earth metals). As we move down a group in the periodic table, the atomic radius generally increases, leading to weaker forces of attraction between atoms.

Therefore, the larger atomic size of cesium compared to lithium would result in weaker interatomic forces, making cesium's solid metal form have a lower melting point compared to lithium.

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A solution containing aqueous dichromate (VI) ions will be a strong enough oxidizing agent to produce aqueous iodine from a solution containing aqueous iodide ions is because dichromate (VI) ions are a strong oxidizing agent that can oxidize iodide ions to form iodine.

In the process, the dichromate (VI) ions are reduced to chromium (III) ions. The reaction between dichromate (VI) ions and iodide ions can be represented by the following equation:

Cr₂O₇²⁻ + 14H⁺ + 6I- → 2Cr₃+ + 3I₂ + 7H₂O

In this reaction, the dichromate (VI) ions are reduced to chromium (III) ions, while the iodide ions are oxidized to form iodine.

Therefore, a solution containing aqueous dichromate (VI) ions would be able to produce aqueous iodine from a solution containing aqueous iodide ions.

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Answer:

friend me on here and imma send you the link Explanation:

Answer:

The correct answer is (C) 0.2 mole MgCl2

Explanation:

Answer:

answer is here bit.^{}ly/3gVQKw3

Answer:

Examples of longitudinal waves include: sound waves. ultrasound waves. seismic P-waves.

Explanation:

A system's equilibrium will move to the right, or toward the side of the products, in accordance with Le Chatelier's principle, if more reactants are added. ... The equilibrium will move to the left if we add more product to a system, producing more reactants.

Solution: By increasing the number of reactants, the equilibrium moves to the right and in the direction of the products.

Thus, if a reactant is added, equilibrium shifts to the right, away from the reactant. Equilibrium shifts to the left, away from the product, when a product is added. If we take away the product, equilibrium returns and produces the product. Reactant is created if reactant is removed, breaking the equilibrium.

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Answer:

C. easily dissociates into ions when I’m solution

Explanation:

Strong acids are compounds that completely decompose when dissolved in water and produce the total number of ions.

Explanation:

a) when zinc burnt in oxygen.

2Zn + O2 -----∆-----> 2ZnO(black residue)

b) when carbon burnt in oxygen.

C+O2----∆---> CO2.

c) when sulphur burnt in oxygen.

S+O2-----∆-----> SO2.

d) when Calcium burnt in oxygen.

2Ca+O2-----∆-----> 2CaO(black residue)

e) when Magnesium burnt in oxygen.

2Mg+O2-----∆----> 2MgO.

f) when sodium burnt in oxygen.

4Na+O2----∆-----> 2Na2O.

hope all these reactions help you.

When a chemical reaction reaches a state where the forward and reverse processes are occurring at the same rate, it is said to be at equilibrium.

At this point, the concentrations of the reactants and products remain constant over time. The equilibrium constant (Kc) is a measure of the ratio of product concentrations to reactant concentrations at equilibrium. If Kc is greater than 1, the reaction favors the products, while if Kc is less than 1, the reaction favors the reactants. Factors such as temperature, pressure, and concentration can affect the equilibrium position of a reaction, leading to shifts in the forward or reverse direction.

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Answer:

Organism: An organism refers to a living thing that has an organised structure, can react to stimuli, reproduce, grow, adapt, and maintain homeostasis.

Example : sea worms, jellyfish, sea anemones, shellfish, squid, octopus and starfish.

Population: A population is a distinct group of individuals, whether that group comprises a nation or a group of people with a common characteristic.

Example:  Risso´s dolphin population, Bottlenose dolphin population, Killer whale population.

Community: an interacting group of various species in a common location.

Example :  1) A  group of dolphin, 2)group of sea anemones and 3) clownfish or 4) group of whales.

Marine ecosystems include: the abyssal plain, polar regions such as the Antarctic and Arctic, coral reefs, the deep sea, kelp forests, mangroves, the open ocean, rocky shores, salt marshes and sandy shores.

The example of an organism, population, and community for a marine ecosystem are small microorganisms like algae the marine plants like hydra to the largest mammal whale these all are marine.

This ecosystem consist of aquatic environments with high level of salts dissolved in it also consist of deep sea ocean and marine costal.

The examples are coral reef, including the fishes like whale and turtles, sea horse many aquatic plants and the microorganism like amoeba. ocean is covered by plants in the 71% of the area.

Therefore, example of an organism, population, and community for a marine ecosystem are small microorganisms like algae the marine plants like hydra to the largest mammal whale these all are marine.

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Answer:

6 valence electrons

Explanation:

Answer:

Hydrogen and Oxygen

Explanation:

The chemical equation for water is H20, meaning Hydrogen and 2 oxygen!

Answer

Explanation

Given:

Quantity of heat, Q = 1.0 BTU

Initial temperature, T₁ = 63 °F

Final temperature, T₂ = 64 °F

What to find:

The mass of water

Step-by-step solution:

1.0 BTU is the amount of heat energy required to raise one pound of water by 1ºF.

The first step is to convert BTU to joules, and °F to °C.

Conversion factor:

1.0 BTU = 1055.06 J

(°F − 32) × 5/9 = °C

So 63 (F = (633F -32) x 5/9 = 17.222C

64°F = (64FF - 32) x 5/9 = 17.787C

8 − 32) × 5/9 = 0°C°°°°°°

Catalase enzyme (Option b) is involved in the detoxification of reactive oxygen species generated within cells. Reactive oxygen species (ROS) are highly reactive molecules that can cause oxidative damage to cellular components.

Catalase is an enzyme that plays a crucial role in cellular defense against ROS. It catalyzes the breakdown of hydrogen peroxide (H2O2) into water (H2O) and molecular oxygen (O2), thus effectively detoxifying the harmful H2O2. By removing excess H2O2, catalase helps prevent oxidative stress and protects cells from oxidative damage.

Glucuronyl transferase enzyme (Option a) is involved in the conjugation of certain substances to glucuronic acid, aiding in their elimination from the body. While this process contributes to detoxification, it is not directly related to the detoxification of reactive oxygen species.

Metallothionein (Option d) is a protein that binds and regulates the intracellular levels of certain metal ions, such as zinc and copper. While it has a role in cellular detoxification, particularly with heavy metal detoxification, it is not directly involved in the detoxification of reactive oxygen species.

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The formula equation includes all the required information of a compound. It has a fixed number of atoms and the amount in which they exist reacting.

Formulas and equations permit chemists to express chemical knowledge efficiently. Both symbol and word equations exist informative. Word equation articulates the formula of the compounds. The state of all the reactants and products exists depicted in the word equation.

A word equation exists as a chemical reaction represented in words rather than chemical formulas. A word equation should express the reactants (starting materials), products (ending materials), and direction of the reaction in a state that could be used to write a chemical equation.

The formula equation includes all the required information of a compound. It has a fixed number of atoms and the amount in which they exist reacting. It furnishes a shorter path to remembering the chemicals and their usable forms.

Whereas the word equation only maintains the nature of reactants and products. It will not provide any opinion about its actual moles and weight. Therefore, formula equations exist more meaningful than word equations.

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The hazardous substance in automobile exhaust that is also present in high concentration in tobacco smoke is acrolein.

Substance that tobacco smoke and the exhaust of automobiles contains a has it is substance called acrolein in very very high concentration.

Inhaling acrolein can give rise to several breathing problems like shortness in breathing and also irritation in lungs.

Acrolein is formed when the fats are overheated apart from automobiles and tobacco a very low amount of acrolein is also found in over used cooking oil.

To reduce acrolein from the automobile exhaust lead based adsorption substances are preferred to be used in automobile exhaust.

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Answer:

the flask feels warm

Explanation:

in exothermic reaction heat is leaving the system and entering the surroundings aka the flask

also i took the quiz

Answer:

33.5 grams of oxygen will be produced

Explanation:

Answer:

a and b

Explanation:

Explanation:

\(2.25mol \times \frac{22.4lit}{1mol} = 50.4 lit o2 \)

The limiting reactant is the reactant that is completely consumed in the reaction, thereby limiting the amount of product that can be formed. To determine the limiting reactant, we need to compare the amount of each reactant present to the stoichiometric ratio of the balanced chemical equation.

In this case, the balanced chemical equation is:

2Al(s) + 3Cu(NO3)2(aq) → 3Cu(s) + 2Al(NO3)3(aq)

From the equation, we can see that the stoichiometric ratio of aluminum to copper(II) nitrate is 2:3. This means that for every 2 moles of aluminum, we need 3 moles of copper(II) nitrate to react completely.

Based on the given information, aluminum is the limiting reactant because it is completely consumed in the reaction, while copper(II) nitrate remains in solution. This is indicated by the colorless solution of aluminum nitrate formed, which indicates that all of the copper(II) nitrate has reacted with aluminum to form copper metal and aluminum nitrate.

Therefore, the correct answer is Aluminum, because it was completely consumed in the reaction.

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Answer:

Valence electrons are electrons located in the outermost energy level (Responsible for bonding.)

Explanation:

Hope this helps :)

Answer:

1.56x10^23 atoms of Mn

Explanation:

250 grams of braunite (Mn3SiO6) is:

  (250 g)/(288.91 g/mole) = 0.865 moles of Mn3SiO6

One mole of Mn3SiO6 would contain 3 moles of Mn, since it appears 3 times in the compound.  Breaking apart 1 mole of Mn3SiO6 into individual atoms of each element would procude 3 moles of Mn atoms (and 1 mole of Si and 6 moles of O atoms),

Since we have 0.865 moles of Mn3SiO6,

we should have:

    (0.865 moles of Mn3SiO6)*((3 moles of Mn)/(1 mole Mn3SiO6))

 this is equal to 2.596 moles of Mn atoms

Since 1 mole is 6.02x10^23 particles of anything, we can write:

(2.596 moles of Mn)*(6.02x10^23 particles Mn atoms/mole) =

          1.56x10^23 atoms of Mn

Answer:

3.5ML

Explanation:

At the constant pressure, the final volume of the carbon dioxide gas was equal to 4.62 ml at a temperature of 0ºC.

Charles's law can be explained as when the pressure of the gas is kept constant, the volume of gas is directly proportional to the temperature of a gas.

The volume of the gas and the temperature of the gas have a direct relationship according to this law.

Therefore, V∝ T

or    V₁/T₁ = V₂/T₂                                               ....................(1)

Given, the initial temperature of the CO₂ gas, T₁ = 22 ºC

T₁ = 22 + 273 = 295 K

The final temperature of the CO₂ gas, T₂ = 0ºC

T₂ = 0 + 273 = 273 K

The initial volume of the gas, V₁ = 5 ml

Substitute the value of V₁, T₁, and T₂ in equation (1 ) to get final volume of CO₂ gas:

5/295 = V₂/273

V₂ = 4.6 ml

Therefore, the final volume of the gas is equal to 4.6 ml at 0 ºC, when there is no change in the pressure.

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While testing two pon sites , students found the water went from pH 7 at site a to pH 6 at site b .the students can conclude that the water at site b is 10x more acidic than the water at site a .

pH is the measure of acidity and basicity of a substance .

pH stands for hydrogen potential . it can be defined as the negative log of hydrogen ion concentration .

it can be measured by a pH scale , which ranges from 0 to 14 .

if the pH value is less than 7 , then the compound is called as acidic .

if the Ph value is greater than 7 , then the compound is called as basic .

if the pH is 7 , then the compound is called as neutral compound .

pH equals to 0 , called strongly acidic solution . pH equals to 14 is called strongly  basic solution .

pH does not have units .

The formula for pH is given by ,

pH = - log[H+]

pH zero for 1N solution of strong acid .

pH is negative for concentrations 2N, 3N ,10N of strong acids .

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The answer of this question is True.

About 20 percent of your daily energy needs is determined by your BMR.

BMR stands for basal metabolic rate.What is Basal Metabolic Rate (BMR)?

BMR is the amount of energy, in calories, used by your body when at rest.

It is an estimation of the number of calories required to keep your body functioning while at rest.

In other words, it is the minimum amount of calories your body requires to carry out its everyday processes, such as breathing and circulating blood, while at rest.

There are several factors that affect BMR, including age, gender, height, weight, and body composition.

A higher BMR implies that the body requires more calories to maintain its energy requirements.

Hence, about 20 percent of your daily energy needs is determined by your BMR.

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Answer: The mole ratio of Zn to ZnO is 3: 3.

Explanation:

According to law of conservation of mass, mass can be neither be created nor be destroyed. The mass on reactant side must be equal to the mass on product side. Thus the atoms of each element on both side of the reaction must be same.

The balanced chemical reaction is:

\(3Zn+2MoO_3\rightarrow Mo_2O_3+3ZnO\)

Here 3 moles of Zn combine with 2 moles of \(MoO_3\) to give 1 mole of \(Mo_2O_3\) and 3 moles of \(ZnO\). Thus the mole ratio of Zn to ZnO is 3: 3.