If the positive charge of an atoms nucleus exactly balances the negative charge of the surrounding electrons the atom is_______


A neutral
B static
C electrified
D positively charged

Answers

Answer 1
The answer is A. Neutral.
Answer 2

If the positive charge of an atoms nucleus exactly balances the negative charge of the surrounding electrons the atom is neutral. Thus, the correct option is A.

What is a Neutral atom?

A neutral atom is an atom which has no charge. In an atom, protons are positively charged species, electrons are the negatively charged species. Neutrons have no charge and are present in the nucleus. Negative and positive charges inside the atom of equal magnitude cancel each other out and the atom becomes neutral.

Any imbalance in the number of protons or electrons in an atom forms an ion. Ions are the charged species, which are of two types: Cation and anion. Cation is a positively charged species and anion is a negatively charged species.

Therefore, the correct option is A.

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Related Questions

8. A hiker walks 2.3 km east and then 4.1 km north. What is her displacement?
A. 6.4 km
B. 6.4 km at 45°
C. 4.7 km at 61°
D. 4.7 km at 29°

Answers

firstly , draw the path 2.3 to east and 4.1 to the north. you’ll get a right - angle triangle . the hypotenuse is the displacement.

to find the distance , use Pythagoras theorem.

let the displacement = c

c ^ 2 = 2.3 ^ 2 + 4.1 ^ 2

c = 4.7 km

then , you need to find the angle.

tan theta = 4.1 / 2.3

theta = 61 degree

i am sorry if my answer was wrong but i hope it helps you and you can understand it : )

a certain amount of nobr(g) is sealed in a flask, and the temperature is raised to 350 k. the following equilibrium is established: nobr(g) uv no(g) 1 12 br2(g) the total pressure in the flask when equilibrium is reached at this temperature is 0.675 atm, and the vapor density is

Answers

The partial pressures of each species of the equilibrium are

NOBr = 0.39 atmNO = 0.19 atm

Vapour density = 2.219 g / L

Temperature = 350 K

Total pressure = 0.675 atm

Since volume of flask is constant and the mass is conserved,

Initial mass of NOBr = 2.219 g

1 mol NOBr = 109.92 g

Number of moles of NOBr = 2.219 / 109.92 = 0.02019 mol

Total number of moles at equilibrium is,

\(n_{total}\) = ( 0.02019 - x ) + x + 0.5 x

\(n_{total}\) = 0.02019 + 0.5 x

Acording to ideal gas equation.

\(n_{total}\)  = P V / R T

\(n_{total}\) = ( 0.675 * 1 ) / ( 0.08206 * 350 )

\(n_{total}\) = 0.00662

Partial pressure of NOBr,

P = ( 0.02019 - x ) * 0.675 / ( 0.02019 + 0.5 x )

P = 0.39 atm

Partial pressure of NO,

P = x * 0.675 / ( 0.02019 + 0.5 x )

P = 0.19 atm

Partial pressure of Br₂,

P = 0.5 x * 0.675 / ( 0.02019 + 0.5 x )

P = 0.095 atm

Therefore, the partial pressures of

NOBr = 0.39 atmNO = 0.19 atmBr₂ = 0.095 atm

The given question is incomplete. The complete question is:

A certain amount of NOBr(g) is sealed in a flask, and the temperature is raised to 350 K. The following equilibrium is established:

NOBr(g) ↔ NO(g) + ½ Br2(g)

NOBr(g)↔NO(g)+½Br2(g)

The total pressure in the flask when equilibrium is reached at this temperature is 0.675 atm, and the vapor density is 2.219 g L^-1. Calculate the partial pressure of each species.

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Question 1 of 10
2 Points
What is the SI unit for gravitational potential energy?
A. Newton
B. Joule
C. Meter
D. Watt

Answers

Answer:

Joule

Explanation:

As any unit of energy (kinetic, potential, etc.), the gravitational potential energy has SI units of Joule. This s the work done by a force of 1 Newton to displace an object 1 meter in the direction of application of the force.

PLEASE HELP ASAP! WILL GIVE BRANLIEST! Pay attention to what happens to the things around you as you go about your day. Describe three examples of Newton’s third law in action. In your examples describe the action and the equal and opposite reaction.

Answers

Answer:

jumping, pulling a elastic band, bouncing a ball

Explanation:

when you jump, your legs apply a force to the ground, and the ground applies and equal and opposite reaction force that propels you into the air.

When we pull an elastic band, it automatically returns to its original position. The more you pull the more force it generates. This is the same when you pull or compress a spring. The action (applied force) is stored as energy and is released as a reaction with an equal and opposite force

A ball is able to bounce because of the reaction from the ground. If there was no reaction then the ball would not bounce but rather stick to the ground.

Suppose a spectral line of hydrogen, normally at 500 nm when measured in a lab on Earth, is observed in the spectrum of a star to be at 500.3 nm. This is called a red shift because the wavelength is longer (and red is on the long-wavelength side of the visible spectrum). How fast is the star moving away from Earth? Give your answer in m/s. Hint: follow example 5.6. Compare in particular to the "Check your learning" calculation, and note that larger Δλ means larger speed.

Answers

The star is moving away from Earth at a velocity of 1.8 x 106 m/s.

The Doppler Effect describes the shift in wavelength of a wave when the source is moving in relation to the observer. The shift can be observed in sound waves, light waves, and other waves.

The Doppler Effect can be used to determine the velocity of objects moving away from an observer, as in the case of stars moving away from Earth.

The velocity of a star moving away from Earth can be determined using the equation:

v = Δλ/λ x c, Where v is the velocity of the star, Δλ is the shift in wavelength of the spectral line, λ is the wavelength of the spectral line measured in the lab on Earth, and c is the speed of light (3.00 x 108 m/s).

In this case, the shift in wavelength of the spectral line is Δλ = 500.3 nm - 500 nm = 0.3 nm.

The wavelength of the spectral line measured in the lab on Earth is λ = 500 nm.

Plugging in these values to the equation above: v = Δλ/λ x cv = (0.3 nm / 500 nm) x (3.00 x 108 m/s) = 1.8 x 106 m/s.

Therefore, velocity of star 1.8 x 106 m/s.

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1. The temperature of the water in each of two beakers measures 50°C. One beaker contains 100 g of water, and the other beaker contains 250 g of water.
a. How does the amount of thermal energy in the two beakers compare? Explain your answer.

b. How does the average kinetic energy of the water molecules in the two beakers compare? How do you know?

Answers

b I’m so so sorry if it’s wrong .

1.Beaker A has less thermal energy than Beaker B

2.The water molecules in both beakers A and B have the same average kinetic energy

The temperature of the water in each of two beakers is same (50°C).

Beaker One contains (\(m_{1}\)) 100 g of water

Beaker Two contains (\(m_{2}\)) 250 g of water

Heat gained and lose by the object is depends on mass, change in temperature and specific heat.

Both beakers are made with same materials so their Specific heats and temperature are same .

Beaker B has more mass then Beaker A  so Beaker A has less thermal energy than Beaker B.

2.The water molecules in both beakers A and B have the same average kinetic energy.

The temperature of an object is a measure of its internal energy. Thermal Energy is a form of Kinetic Energy because it is related to the Molecular Velocity.

When Temperature increases the velocity of the molecules ( increases or decreases) and the Kinetic Energy (increases or decreases) as Temperature decreases the velocity of the molecules ( increases or decreases) and the Kinetic Energy (increases or decreases).

so Kinetic Energy Depends on Velocity and Velocity depends on   the Temperature in this problem Temperature are same so The water molecules in both beakers A and B have the same average kinetic energy.

what do  you mean by Heat capacity of water?

It takes a lot of heat to increase the temperature of liquid water because some of the heat must be used to break hydrogen bonds between the molecules.

In other words, water has a high specific heat capacity, which is defined as the amount of heat needed to raise the temperature of one gram of a substance by one degree Celsius. The amount of heat needed to raise the temperature of 1 g water by 1 °C is has its own name, the calorie.

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You exit the Vet's Office.
What is your position?
What total distance have you travelled?
You walk to the Bank.
What is your new position?
What is your displacement?
What total distance have you travelled?
You walk to the Flower Shop.
What is your new position?
What is your total displacement?
What total distance have you travelled?
You walk to the Vet's Office.
What is your new position?
What is your total displacement?
What total distance have you travelled?

You exit the Vet's Office.What is your position?What total distance have you travelled?You walk to the

Answers

(1) When you exit the office, your position is 60.8 m and the total distance traveled is 60.8 m.

(2) When you walk to the bank, your position is 60.8 m, displacement is 0 and the total distance traveled is 121.6 m.

(3) When you walk to flower shop, your position is 26.9 m, displacement is 0 and the total distance traveled is 148.5 m.

(4) When you walk to the Vet's Office, your position is 60.8 m, displacement is 60.8 m and the total distance traveled is 182.4 m.

You exit the Vet's Office

When you exit the Vet's Office, your position is 60.8 m (assuming your starting position is the bank).

The total distance have you travelled = 26.9 m + 33.9 m = 60.8 m

You walk to the Bank

your new position is 60.8 m

your displacement = 60.8 m - 60.8 m = 0 (assuming your starting position is the bank)

total distance have you travelled = 60.8 m +  60.8 m = 121.6 m

You walk to the Flower Shop

your new position is 26.9 m

your total displacement = 0 + 26.9 m = 26.9 m

total distance have you travelled = 26.9 m + 121.6 m = 148.5 m

You walk to the Vet's Office

your new position is 26.9 m + 33.9 m = 60.8 m

your total displacement = 26.9 m + 33.9 m = 60.8 m

total distance have you travelled = 148.5 m + 33.9 m = 182.4 m

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Two children carry a lightweight 2.4m -long horizontal pole with a water bucket hanging from it. The older child supports twice as much weight as the younger child. How far is the bucket from the older child?

Answers

The bucket is 0.8 meters away from the older child.

In this scenario, we have two children carrying a 2.4-meter long horizontal pole with a water bucket hanging from it. The older child supports twice the weight of the younger child. Let's denote the distance of the bucket from the older child as 'x' and the distance from the younger child as '2.4 - x'.

Since the older child is supporting twice the weight of the younger child, we can relate the forces using a balance of torques. Torque is the force applied at a distance from the pivot point. In this case, the pivot point is where the younger child is holding the pole.

The torque applied by the older child is equal to the weight supported by the older child multiplied by the distance 'x'. Similarly, the torque applied by the younger child is equal to half the weight supported by the older child multiplied by the distance '2.4 - x'. For the pole to be in equilibrium, these two torques must be equal. Therefore:

Older child's torque = Younger child's torque
(weight supported by older child) * x = (1/2 * weight supported by older child) * (2.4 - x)

Since we only need to find 'x', we can cancel out the weight supported by the older child from both sides of the equation:

x = (1/2) * (2.4 - x)

Solving for 'x', we get:

x = 0.8 meters

So, the bucket is 0.8 meters away from the older child.

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A house is heated from 3 ∘ C to 25 ∘ C by an electric heater, and some air escapes through cracks as the heater air in the house expands at constant pressure of 101.3kPa. The house is 3 m wide ×4 m long and 3.5 m high. Given: The specific heat of air at room temperature is cp=1.112 kJ/kg ∘ C The ideal gas constant, R=0.287kPa⋅m 3 /kg⋅K 2.1.1 The amount of heat transfer to the air transfer to the air. 2.1.2 Determine the heat flux, if the house is heated for 30 min.

Answers

The amount of heat transfer to the air is 511.464 kJ/kg

Given data

The initial temperature of the air, T1 = 3 ∘ C

The final temperature of the air, T2 = 25 ∘ C

The specific heat of air at room temperature is cp = 1.112 kJ/kg ∘ C

The pressure of the air, P = 101.3 kPa

The ideal gas constant, R = 0.287 kPa⋅m3/kg⋅K

The volume of the house, V = 3 m × 4 m × 3.5 m = 42 m3(a)

Amount of heat transfer to the air  

We know that the specific heat of air at constant pressure is given by cp= R/ (γ−1) ... [1]

Where

γ is the ratio of the specific heat capacity at constant pressure and constant volumeγ= cp / cv ... [2]

From equation [1],

we have R = cp × (γ-1) ... [3] Substitute equation [3] in equation [2],

we getγ = cp / (cp × (γ-1))γ (γ-1) = 1γ^2 - γ = 1γ^2 - γ - 1 = 0

Solving the above quadratic equation, we getγ = 1.4 ...(a)

The amount of heat transferred to the air is given by Q = m × cp × ΔT ...(b)

Where m is the mass of airΔ

T = T2 - T1 is the change in temperature Substituting the given values in equation [a],

we get cp = 1.112 kJ/kg ∘ C; R = 0.287 kPa⋅m3/kg⋅K

We know that P × V = m × R × Tm = P × V / (R × T) ...(c)Substitute equation [c] in equation [b],

we get Q = (P × V / (R × T)) × cp × ΔT

Q = (101.3 × 10^3 Pa × 42 m3 / (0.287 kPa⋅m3/kg⋅

K × (273 + 3) K)) × 1.112 kJ/kg ∘ C × (25 - 3) ∘ C= 511.464 kJ/kg(b)

The heat flux, if the house is heated for 30 min

The heat flux is given by q = Q / (A × t) ...(a)

Where A is the surface area of the house and t is the time of heating.

Substitute the given values in equation [a],

we get Q = 511.464 kJ

A = 2 × (3 m × 3.5 m) + 2 × (3 m × 4 m) + 2 × (3.5 m × 4 m)

A = 63 m2t = 30 min = 30 × 60 s = 1800 sq = 511.464 kJ / (63 m2 × 1800 s)q = 0.004 kJ/sq m/s

Therefore, the heat flux is 0.004 kJ/sq m/s.

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What is the method of heat transfer sunlight melts a wax crayon left outside.

Answers

Answer:

Hey Friend....

Explanation:

This is ur answer....

Transfer of energy by electromagnetic waves. Radiation doesn't require matter. Sunlight melting a wax crayon left outside is radiation.

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Determine the distance from equilibrium, in m, when the mass moves with a speed half its initial speed.

Answers

To determine the distance from equilibrium when the mass moves with a speed half its initial speed, we need to consider the properties of the system, such as the mass, initial speed, and the restoring force acting on the mass.

The distance from equilibrium can be determined using the principles of simple harmonic motion. In simple harmonic motion, the displacement from equilibrium is directly proportional to the amplitude of the motion.

Given that the mass is initially moving with a certain speed, let's call it V₁. When the mass moves with half its initial speed, the new speed is V₂ = v₁/2.

In simple harmonic motion, the maximum displacement from equilibrium is equal to the amplitude of the motion. Therefore, to find the distance from equilibrium when the mass moves with a speed half its initial speed, we need to determine the amplitude of the motion.

The amplitude can be calculated using the formula A = (2πV₁) / ω, where A is the amplitude, V₁ is the initial speed, and ω is the angular frequency of the system.

Once the amplitude is determined, the distance from equilibrium when the mass moves with a speed half its initial speed is equal to half the amplitude, as the amplitude represents the maximum displacement.

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some properties of the particles that are sources of electric charge include
group of answer choices
electric charge comes in bundles of any size.
electrons usually move freely within a solid material
protons cary a negative charge, electrons carry a positive charge.
electrons cary a negative charge, protons carry a positive charge.
electrons and protons carry the same positive charge.
electric charge only comes in bundles of a specific size.
protons usually move freely within a solid material
electrons and protons carry the same negative charge.

Answers

Electrons, are responsible for the negative charge of an atom. Protons, on the other hand, have a positive charge and are responsible for the positive charge of an atom.  So option: 4 is correct.

Electric charge is a fundamental property of matter that determines how particles interact with each other. There are two types of electric charges: positive and negative. Particles that have the same type of charge repel each other, while particles with opposite charges attract each other. The electric charge of a particle is a conserved quantity, meaning it cannot be created or destroyed, only transferred from one particle to another.  Therefore, the Option:  4, is fundamental concept in understanding the behavior of electric charges and their sources.

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--The complete Question is, Some properties of the particles that are sources of electric charge include group of answer choices

1. electric charge comes in bundles of any size.

2. electrons usually move freely within a solid material

3. protons carry a negative charge, electrons carry a positive charge.

4. electrons carry a negative charge, protons carry a positive charge. --

Which term best describes the basic unit that makes up all matter?
O A. Atomic nuclei
O B. Protons
O C. Atoms
O D. Molecules

Answers

Answer:

C. Atoms

Explanation:

The basic unit of matter and the smallest, indivisible unit of a chemical element. It comprises a nucleus (neutrons + protons) that is surrounded by a cloud of electrons.

Identify each part of this chemical equation that describes the burning of methane and oxygen. B (blue box): D (number): E (purple box):

Answers

Answer:

The correct answer is -

A (the entire green box): Chemical Equation

B (the blue box): Reactants

C (the arrow): Reacts to Form

D (the number): Coefficient

E (the purple box): Products

Explanation:

The chemical reaction of burning methane and oxygen is as follows;

Here, the green part A is the chemical equation that includes various parts that are reactants B, methane, and oxygen, C is an arrow that indicates the formation of products.

2 is here coefficient that indicates the moles of the oxygen which forms carbon dioxide and water in box E is products

Identify each part of this chemical equation that describes the burning of methane and oxygen. B (blue

Answers:

A (the entire green box):  chemical equation

B (the blue box): reactants  

C (the arrow):  reacts to form

D (the number):  coefficient

E (the purple box):  products

Explanation:

As seen in the picture below,

Identify each part of this chemical equation that describes the burning of methane and oxygen. B (blue

Define Eukaryote cells and Prokaryote cells

Answers

Answer:

Ekaryote cells

an organism consisting of a cell or cells in which the genetic material is DNA in the form of chromosomes contained within a distinct nucleus. Eukaryotes include all living organisms other than the eubacteria and archaea.

prokaryote cells

microscopic single-celled organism which has neither a distinct nucleus with a membrane nor other specialized organelles, including the bacteria and cyanobacteria

A CROW BAR WITH LENGTH 200 CM IS USED TO LIFT A LOAD OF 600N . IF THE DISTANCE BETWEEN FULCRUM AND LOAD IS 0.75. CALCULATE ; a, effort b, MA c, VR

Answers

Answer:

a. Effort = 960 Newton

b. Mechanical advantage (M.A) = 0.625

c. Velocity ratio (V.R) = 1.67

Explanation:

Given the following data;

Load = 600 NLength of crowbar = 200 cmLength of load arm = 0.75 m

Conversion:

100 cm = 1 m

X cm = 0.75 m

Cross-multiplying, we have;

X = 0.75 * 100 = 75 cm

First of all, we would find the effort arm;

Effort arm = length of crow bar - length of load arm

Effort arm = 200 - 75

Effort arm = 125 cm

Next, we would determine the mechanical advantage (M.A) of the crow bar;

\( M.A = \frac {Effort \; arm}{Load \; arm} \)

Substituting the values into the formula, we have;

\( M.A = \frac {125}{200} \)

M.A = 0.625

To find the effort of the crow bar;

\( M.A = \frac {Load}{Effort} \)

Making "effort" the subject of formula, we have;

\( Effort = \frac {Load}{M.A} \)

\( Effort = \frac {600}{0.625} \)

Effort = 960 Newton

Lastly, we would determine the velocity ratio (V.R);

\( V.R = \frac {length \; of \; effort \; arm}{length \; of \; load \; arm} \)

\( V.R = \frac {125}{75} \)

V.R = 1.67

Please help with this, Im a little stuck!!

Please help with this, Im a little stuck!!

Answers

Answer:

Jwbsbsbdjeiskbsj3kabajj2jjj1jj2j2j3jkkkk3j3j2

please help i give brainest but i need help asap

please help i give brainest but i need help asap

Answers

Answer:

Surface

Explanation:

Rayleigh Waves—surface waves that move in an elliptical motion, producing both a vertical and horizontal component of motion in the direction of wave propagation. Particle motion consists of elliptical motions (generally retrograde elliptical) in the vertical plane and parallel to the direction of propagation.

A wave traveling in the positive x-direction with a frequency of 50.0 Hz is shown in the figure below. Find the following values for this wave: a. amplitude b. wavelength c. period d. speed

A wave traveling in the positive x-direction with a frequency of 50.0 Hz is shown in the figure below.

Answers

Answer:

Explanation:

a. The amplitude is the measure of the height of the wave from the midline to the top of the wave or the midline to the bottom of the wave (called crests). The midline then divides the whole height in half. Thus, the amplitude of this wave is 9.0 cm.

b. Wavelength is measured from the highest point of one wave to the highest point of the next wave (or from the lowest point of one wave to the lowest point of the next wave, since they are the same). The wavelength of this wave then is 20.0 cm. or \(\lambda=20.0cm\)

c. The period, or T, of a wave is found in the equation

\(f=\frac{1}{T}\) were f is the frequency of the wave. We were given the frequency, so we plug that in and solve for T:

\(50.0=\frac{1}{T}\) so

\(T=\frac{1}{50.0}\) and

T = .0200 seconds to the correct number of sig fig's (50.0 has 3 sig fig's in it)

d. The speed of the wave is found in the equation

\(f=\frac{v}{\lambda}\) and since we already have the frequency and we solved for the wavelength already, filling in:

\(50.0=\frac{v}{20.0}\) and

v = 50.0(20.0) so

v = 1.00 × 10³ m/s

And there you go!

The area under the curve on a Force versus time F vs. t) graph represents & kinetic ener a. impulse. b. momentum. e. none of the above c. work. Q10: Sphere X, of mass 2 kg, is moving to the right at 10 m/s. Sphere Y. of mass 4kg, is moving to the a. twice the magnitude of the impulse of Y on X b. half the magnitude of the impulse of Y on X c. one-fourth the magnitude of the impulse of Y on X d. four times the magnitude of the impulse of Y on X e. the same as the magnitude of the impulse of Y on X

Answers

The area under the curve on a Force versus time (F vs. t) graph represents work. Therefore, the correct answer is (c) work. In Q10, To determine the magnitude of the impulse of Sphere Y on Sphere X,  the correct answer is (e) the same as the magnitude of the impulse of Y on X.

The work done by a force is defined as the product of the magnitude of the force and the displacement of the object in the direction of the force. Mathematically, work (W) is given by the equation:

W = ∫ F(t) dt

The integral represents the area under the curve of the Force versus time graph. By calculating this integral, we can determine the amount of work done by the force.

Impulse, on the other hand, is defined as the change in momentum of an object and is not directly related to the area under the curve on a Force versus time graph. Momentum is the product of an object's mass and its velocity, and it is also not directly related to the area under the curve on a Force versus time graph.

The magnitude of the impulse on X due to Y is equal to the magnitude of the change in momentum of X. It can be calculated using the equation:

Impulse (J) = Change in momentum (Δp)

The change in momentum of X is given by:

Δp = \(m_1 * (v_1 - u_1)\)

Now, let's consider the conservation of momentum equation:

\(m_1 * u_1 + m_2 * u_2 = m_1 * v_1 + m_2 * v_2\)

Since Sphere X is moving to the right and Sphere Y is moving to the left, we can assume that Sphere Y collides with Sphere X and comes to rest.

Therefore, the final velocity of Sphere Y (\(v_2\)) is 0 m/s.

Plugging in the given values and solving the equation, we can find the final velocity of Sphere X (\(v_1\)).

After obtaining the values of \(v_1\) and \(v_2\), we can calculate the impulse (J) using the change in momentum equation mentioned above.

Comparing the magnitudes of the impulses of Y on X and X on Y, we find that they are equal. Therefore, the correct answer is (e) the same as the magnitude of the impulse of Y on X.

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Susie rolls a bowling ball down the alley and knocks over most of the pins. Explain why fewer pins were knocked over when her little brother rolled a basketball, at the same velocity, down the alley.

Answers

Answer:

The force used

Explanation:

This has to be because of the force used. Both Susie and her younger brother might have hit the ball with the same velocity, but they surely couldn't have hit it with the same force. The force with which Susie hurts it is heavier than that with which her younger brother hits it, and as such, Susie gets to fall down more pins than her brother will be able to. The ball has to have a lot of force in it for it to be able to knock off all the pins there. So basically, the more the force, the higher it's chances of hitting all the pins

What is the force applied to a baseball that has a mass of 142kg and has a acceleration of 30m/s to the power of 2

Answers

Mass=m=142kgAcceleration=a=30m/sForce=F

Using Newton's second law

\(\\ \sf\Rrightarrow F=ma\)

\(\\ \sf\Rrightarrow F=142(30)\)

\(\\ \sf\Rrightarrow F=4260N\)

work done per unit time :- a. force b. power c. energy d. momentum​

Answers

The Answer: B. Power

Where would you need to place an object to make its image appear 17.22 cm away from a lens if the lens has a focal length of 3.05 cm?

Answers

Given,

The image distance, v=17.22 cm

The focal length of the lens, f=3.05 cm

From the thin lens formula,

\(\begin{gathered} \frac{1}{f}=\frac{1}{u}+\frac{1}{v} \\ \end{gathered}\)

Where u is the object distance.

On rearranging the above equation,

\(\begin{gathered} \frac{1}{u}=\frac{1}{f}-\frac{1}{v} \\ =\frac{v-f}{vf} \\ \Rightarrow u=\frac{vf}{v-f} \end{gathered}\)

On substituting the known values,

\(\begin{gathered} u=\frac{17.22\times3.05}{17.22-3.05} \\ =3.71\text{ cm} \end{gathered}\)

Thus the object distance should be 3.71 cm

the speed of light is about 186,000 mi/s. the distance from the earth to the sun is about 93 million miles. use this information to find how long it takes for a light ray from the sun to reach the earth.

Answers

The time a sunlight ray needs to travel from the sun to the earth is 500 seconds.

How much time does it take for light to travel 93 million miles from the Sun to the earth?

8 minutes 20 seconds approximately, The Sun is located 150,000,000 km (93,000,000 miles) from Earth on average. A photon of light must therefore travel from the Sun to Earth for a total of 8 minutes and 20 seconds.

The sun's distance from the earth is typically 93 million kilometers. Getting there by car at 65 mph would take 1,430,769 hours.

Distance is calculated using the distance formula, which is d = rt. 93,000,000 = 186,000*t is obtained by substituting the known values. Thus, t = 500 seconds.

The time a sunlight ray needs to travel from the sun to the earth is 500 seconds.          

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consider both the sop and the pos circuits, which was a better realization of the switching function (if any)? why?

Answers

Which of the two circuits—the SOP and the POS—better realised the switching function, if any Why Because POS requires fewer gates to implement the function, it is a superior realisation.

How should SOP and POS be written using the truth table?

The POS equation utilises the sign "prod" to represent taking the product of components, while the SOP equation utilizes the summation symbol "sum" to suggest adding all terms together. After the first symbol, both formulas simply list the researchers or maxterms that are present in the specified truth table.

Provide an illustration of SOP and POS reasoning.

SOP is short for Sum of Products. The abbreviation for this is Product of Sums. 2. The technique entails formulating the boolean phrases as the sum of their component parts. It's a technique for defining logical words as the product of their constituent parts.

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why do you see something as white, black, or another specific color

Answers

     We see something as white, black, or another specific color because the object is reflecting light waves back.

     In a nutshell; If we view an object as red, then the object is:

-> reflecting back red light waves

-> absorbing blue, green, etc light waves.

    What about white and black?

We see white when most all of the light is reflected.

When there is little to no light reflected, we see black.

Answer:

When nearly all light is reflected, you see white. When no light is reflected, you see black.

Explanation:

Part of a single rectangular loop of wire with dimensions shown in the (Figure 1) is situated inside a region of uniform magnetic field of 0.630 T . The total resistance of the loop is 0.590 Ohm. Calculate the force required to pull the loop from the field (to the right) at a constant velocity of 7.10 m/s . Neglect gravity. Express your answer to three significant figures and include the appropriate units.

Answers

The force required to pull the loop from the field at a constant velocity of 7.10 m/s is 2.48 N.

To calculate the force required, we need to use the formula F = BIL, where F is the force, B is the magnetic field, I is the current, and L is the length of the wire. In this case, the length of the wire is the same as the width of the rectangle, which is 0.150 m. The current can be found using Ohm's Law, which is I = V/R, where V is the voltage and R is the resistance.

Since the voltage is not given, we can use the formula P = IV, where P is the power, to find the voltage. The power is P = I^2R, which gives us P = 1.481 W. Substituting this into the formula for power, we get V = sqrt(P*R) = 0.872 V. Finally, we can calculate the current as I = V/R = 1.476 A. Substituting these values into the formula for force, we get F = BIL = 2.48 N, which is the final answer.

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what is the speed of light at 15°c

Answers

Answer:

calculation presented a speed of 125,000 miles per second (200,000 km/s).

Explanation:

An engine using 1 mol of an ideal gas initially at 16.1 L and 325 K performs a cycle
consisting of four steps:
1) an isothermal expansion at 325 K from 16.1 L to 31.5 L ;
2) cooling at constant volume to 163 K ;
3) an isothermal compression to its original volume of 16.1 L; and
4) heating at constant volume to its original temperature of 325 K .
Find its efficiency. Assume that the heat capacity is 21 J/K and the universal gas constant is 0.08206 L · atm/mol/K =8.314 J/mol/K.

Answers

The efficiency of the engine is 1.57%.

Efficiency is a measure of how well a system converts input energy into useful output energy. It is calculated as the ratio of useful output energy to the total input energy.

To find the efficiency of the engine, we need to calculate the work done by the engine and the heat absorbed from the reservoirs during the cycle.

Step 1: Isothermal expansion at 325 K from 16.1 L to 31.5 L

Since this is an isothermal process, the temperature remains constant at 325 K. The work done by the engine during this process is given by:

W1 = nRT ln(V2/V1)

where n is the number of moles of the gas, R is the universal gas constant, and T is the temperature in kelvin.

n = 1 mol

R = 8.314 J/mol/K

T = 325 K

V1 = 16.1 L

V2 = 31.5 L

W1 = (1 mol)(8.314 J/mol/K)(325 K) ln(31.5 L/16.1 L)

W1 = 4527.6 J

The heat absorbed from the reservoir during this process is given by:

Q1 = W1 = 4527.6 J

Step 2: Cooling at constant volume to 163 K

Since this is a constant volume process, no work is done by the engine. The heat absorbed from the reservoir during this process is given by:

Q2 = nCvΔT

where Cv is the heat capacity at constant volume and ΔT is the change in temperature.

n = 1 mol

Cv = 21 J/K

ΔT = 163 K - 325 K = -162 K

Q2 = (1 mol)(21 J/K)(-162 K)

Q2 = -3402 J

Step 3: Isothermal compression to its original volume of 16.1 L

Since this is an isothermal process, the temperature remains constant at 163 K. The work done on the engine during this process is given by:

W3 = -nRT ln(V2/V1)

where V1 = 31.5 L and V2 = 16.1 L.

n = 1 mol

R = 8.314 J/mol/K

T = 163 K

V1 = 31.5 L

V2 = 16.1 L

W3 = -(1 mol)(8.314 J/mol/K)(163 K) ln(16.1 L/31.5 L)

W3 = -4456.5 J

The heat released to the reservoir during this process is given by:

Q3 = -W3 = 4456.5 J

Step 4: Heating at constant volume to its original temperature of 325 K

Since this is a constant volume process, no work is done by the engine. The heat released to the reservoir during this process is given by:

Q4 = nCvΔT

where Cv is the heat capacity at constant volume and ΔT is the change in temperature.

n = 1 mol

Cv = 21 J/K

ΔT = 325 K - 163 K = 162 K

Q4 = (1 mol)(21 J/K)(162 K)

Q4 = 3402 J

The net work done by the engine is given by the sum of the work done during steps 1 and 3:

Wnet = W1 + W3 = 4527.6 J - 4456.5 J = 71.1 J

The net heat absorbed from the reservoirs is given by the sum of the heat absorbed during steps 1 and 2, and the sum of the heat released during steps 3 and 4:

Qnet = Q1 + Q2 + Q3 +Q4 = 4527.6 J - 3402 J + 4456.5 J - 3402 J = 2179.1 J

The efficiency of the engine is given by:

η = Wnet/Q1 = 71.1 J/4527.6 J = 0.0157 or 1.57%

Therefore, the efficiency of the engine is 1.57%.

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