if the magnitude of the net force acting on the particle is fff , how long does it take the particle to acquire its final velocity, 2v2v in the positive y direction?

Hi there!

\(\large\boxed{545N}\)

Since the object is being pulled at a constant velocity, the forces must be balanced.

Since there is no movement vertically, we must take into account the horizontal forces. We can also assume a positive acceleration to be in the direction of motion.

The acceleration and force due to gravity on an incline is:

a = gsinФ

F = MgsinФ

∑F = -MgsinФ + T

Since it is getting pulled at a constant velocity, ∑F = 0. So:

0  = -MgsinФ + T

MgsinФ = T

Solve for T by plugging in values. Let g = 10 m/s²

T = (120)(10)sin(27) ≈ 545 N

N=m.g

N=72 x 9.8 = 705.6 ≈ 706 N

Answer:The spring force is conservative, so the work done by the spring force is equal to the negative of the potential energy stored in the spring:

U = -1/2 k x^2

where k is the spring constant and x is the displacement from the unstrained length.

The initial compression of the spring is 4.10 mm = 0.00410 m, and the additional compression is 6.10 mm = 0.00610 m. The total compression of the spring is therefore x = 0.00410 m + 0.00610 m = 0.0102 m.

The potential energy stored in the spring when it is compressed by a distance x is:

U = -1/2 k x^2

Substituting the given values, we get:

U = -1/2 (216 N/m) (0.0102 m)^2

U = -0.0112 J

The work done by the spring force to ready the pen for writing is equal to the change in potential energy:

W = U_final - U_initial

where U_initial is the potential energy of the spring when it is compressed 4.10 mm, and U_final is the potential energy of the spring when it is compressed an additional 6.10 mm.

U_initial = -1/2 (216 N/m) (0.00410 m)^2 = -0.000090 J

U_final = -1/2 (216 N/m) (0.0102 m)^2 = -0.0112 J

W = U_final - U_initial

W = (-0.0112 J) - (-0.000090 J)

W = -0.0111 J

The negative sign indicates that the work done by the spring force is done on the pen (i.e. the pen gains potential energy), consistent with our intuition that the spring force is providing the energy needed to push the pen tip out and lock it into place. Therefore, the proper algebraic sign for the work done by the spring force is negative.

Explanation:

The wavelength that is associated with lamp 1 is A.

We know that the wavelength has to do with the horizontal distance that is covered by a wave. We can know the wavelength of the light if we can look at the intensity of the light that is emanating from each of the bulbs.

Clearly, the bulb that is labelled 1 is a dim bulb and the wave front that is generated by the bulb is also a small wave front thus the wavelength that is due to the brightness of this bulb would correspond to A.

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Answer:

Explanation:

First, he can add the rock salt to the water and mix it well. Then he can remove the sand by decantation, after the sand has sedimented. He can seperate the water from the salt by evaporation. He should evaporate the water completely and capture the steam. the steam will cool into water. After evaporating completely, the salt will remain in the container

Answer:

The Galactic Center (or Galactic Centre) is the rotational center, the barycenter, of the Milky Way galaxy. Its central massive object is a supermassive black hole of about 4 million solar masses, which powers Sagittarius A*, a compact radio source which is almost exactly at the galactic rotational center.

Answer:

The vehicle safety check indicates the ABS is functioning normally.:

The vectors point along the axis of rotation with a direction determined by an arrow.

There are two types of physical quantity one is a scaler and another one is a vector.

The quantity that requires only megnitude to define is known as the scalar quantity. While the vector quantities need both megnitude and the direction to define.

The vector quantity is represented by an arrow. The vectors point along the axis of rotation with a direction determined by an arrow.

The angular quantities L, omega, and alpha are vector quantities.

Hence arrow is the correct answer for the blank.

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The direction of the vectors of angular momentum and L, angular velocity omega and the mass alpha is determined using the right hand rule.

Righthand rule in physics states that, when we curl our right hand fingers, the direction of the angular momentum and velocity will be in the direction of thumb and curl of fingers determine the axis of rotation.

Angular momentum is a vector quantity defined as the product of moment of inertia and angular velocity where, the angular velocity ω is the rotational analogue of linear velocity i.e.. product of the linear velocity and radius of rotational path.

Therefore, the angular quantities L, angular velocity ω along the axis of rotation can be determined using the right hand rule. Where direction of thump represents the direction of vector components.

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Answer:

each of two or more forms of the same element that contain equal numbers of protons but different numbers of neutrons in their nuclei, and hence differ in relative atomic mass but not in chemical properties; in particular, a radioactive form of an element.

"some elements have only one stable isotope"

Explanation:

there ya go! Pls give me brainliest!

Answer:

3

Explanation:im almost certain thats what it is

Answer:

A

Explanation:

I'm pretty sure that this answer is correct please let me know!

Answer:

well that means they are driving 100 mph

so it will take them less than an hour and a half

The image is located 2.8 meters from the mirror, on the same side as the object (indicated by the negative sign).

To determine the location of the image formed by a convex mirror with a focal length of -2.8m, we need to use ray tracing. Draw a ray from the object parallel to the principal axis, which will reflect off the mirror and pass through the focal point. Draw a second ray from the object towards the center of curvature, which will reflect back on itself.

Step 1: Plug in the given values:
1/(-2.8) = 1/5.6 + 1/di

Step 2: Calculate the reciprocal of the object distance and the focal length:
-1/2.8 = 1/5.6 + 1/di

Step 3: Subtract the reciprocal of the object distance from the reciprocal of the focal length:
-1/2.8 - 1/5.6 = 1/di

Step 4: Find the common denominator and simplify the fraction:
-2/5.6 = 1/di

Step 5: Take the reciprocal of both sides to find the image distance:
di = -5.6/2

Step 6: Simplify the fraction to get the image distance:
di = -2.8 m

The image is located 2.8 meters from the mirror, on the same side as the object (indicated by the negative sign).

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Newton's cradle is described as an almost ideal closed system because it is a system that is nearly isolated from its environment. This means that the system is mostly self-contained and does not exchange matter or energy with its surroundings.

In the case of Newton's cradle, the system consists of a set of metal balls that are suspended from a frame. When one ball is pulled back and released, it strikes the other balls and causes them to swing back and forth. This motion is almost perfectly elastic, which means that the balls do not lose or gain energy during the collision. As a result, the system is nearly closed and does not exchange energy with the surrounding environment.

Overall, Newton's cradle is described as an almost ideal closed system because it is nearly isolated from its environment and does not exchange matter or energy with its surroundings. This allows the system to demonstrate the principles of conservation of momentum and energy in a simple and visual way.

Because it is a system that is almost completely isolated from its surroundings, Newton's cradle is referred to be an almost ideal closed system. This indicates that the system is largely self-contained and does not interact with the environment to exchange matter or energy.

The Newton's Cradle is an apparatus that uses spheres in motion to show how momentum and energy are conserved. One of the stationary spheres at the end is lifted and released, striking them and sending a force through them that forces the final sphere higher.

In order to recreate the effect in the other way, the final sphere swings back and collides with the virtually stationary spheres. The instrument was created by French scientist Edme Mariotte and is named after English scientist Sir Isaac Newton who lived in the 17th century.

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The power factor (PF) of a circuit is the ratio of the real power to the total apparent power consumed by the load. The power factor of a circuit is the cosine of the phase angle between the voltage and current. The formula for power factor is PF = P/S, where P is the real power, and S is the apparent power.

Hence, in a certain electric circuit, if pt = 600 w, st = 1000 va, and qt = 800 var (capacitive), the power factor can be determined as follows: Power factor = P/S = 600 W/1000 VA = 0.6 or 60%. The circuit is capacitive since the reactive power (Q) is positive. The apparent power S can be calculated using the formula

\(S = \sqrt (P^2 + Q^2) = \sqrt (600^2 + 800^2) = \sqrt (360000 + 640000) = \sqrt 1000000 = 1000 VA.\)

The power factor is 0.6 or 60%. The power factor signifies the efficiency of the circuit. It is better to have a power factor that is closer to 1 as this indicates a more efficient circuit. If the power factor of a circuit is less than 1, the circuit has a reactive component, and energy is lost in the form of heat in the transmission lines, transformers, and other components.

In addition, it can also lead to reduced voltage levels, which can damage the equipment. Hence, it is important to ensure that the power factor of a circuit is as close to 1 as possible.

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If Callisto's orbit were circular, then how many days would it take Callisto to complete one full revolution around Jupiter is 16.7 days. If Callisto's orbit were circular, what would its orbital speed be is 8.20 × 10³ m/s.

Radius of Callisto, rc = 2.40 × 10⁶ m

Mean orbital radius, r = 1.88 × 10⁹ m

The time required for Callisto to complete one full revolution around Jupiter is given by: T = 2πr/v

where, T is the period of revolution, v is the speed of Callisto, and r is the mean orbital radius.

If Callisto's orbit were circular, then its speed would be constant, and the time required to complete one full revolution would be the same as its period of revolution.

T = 2πr/v = (2π)(1.88 × 10⁹ m)/(8.20 × 10³ m/s) ≈ 1.67 × 10⁶ s ≈ 16.7 days

The speed of Callisto in a circular orbit is given by:

v = 2πr/T = (2π)(1.88 × 10⁹ m)/(1.67 × 10⁶ s) ≈ 8.20 × 10³ m/s

Hence, Callisto's orbit were circular, then how many days would it take Callisto to complete one full revolution around Jupiter is 16.7 days. If Callisto's orbit were circular, what would its orbital speed be is 8.20 × 10³ m/s.

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Answer:

bhai what is yhis? i dont understand

Part A. We are given that a dart travels from rest to a velocity of 30 m/s with an acceleration of 330 m/s^2 to determine the time we will use the following equation of motion:

Where:

Since the dart is launched from rest this means that the initial velocity is zero, therefore:

Now, we divide both sides by "a":

Now, we plug in the values:

Solving the operation:

Part B. Now, we are asked to determine the distance. To do that we will use the following equation of motion:

Now, we divide both sides by "2a":

Now, we plug in the values:

Solving the operations we get:

Therefore, the distance is 1.36 meters.

Answer:

the answer is 352.8m

Explanation:

Since the gravitational constant is denoted as g

\(g = 9.8 \: \frac{m}{ {s}^{2} }\)

and the ball needed 6 seconds to land, so we can calculate the height of the building as:

\(h = 9.8 \: \frac{m}{ {s}^{2} } \times {(6s)}^{2} = 9.8 \: \frac{m}{ {s}^{2} } \times 36 {s}^{2} = 352.8m\)

Because iron exerts too much pressure, a star cannot be supported by an iron core. Iron cannot produce energy by fusing with other nuclei.

After carbon is used up, even higher mass stars will burn neon. However, fusion stops once iron is reached because it is so tightly bound that no energy can be released by fusion. Iron can fuse, but doing so requires energy absorption, which lowers the core temperature.

The most stable element is iron, though, and it actually requires energy to fuse with heavier elements. Since there is no longer any energy to keep the star from collapsing in on itself due to gravity, the fusion processes are effectively finished with the formation of iron in the core.

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Answer:

1 deg C = 5/9 deg F         (Ex. 212 F - 32) * 5/9 = 100

So deg F = 9/5 deg C = 9/5 * 2.9 = 5.2 deg F

A. The original momentum of the fullback is 450 Kg.m/s

B. The impulse imparted on the fullback is 450 Ns

C. The force exerted on the fullback is 900 N

D. The force exerted on the tackler is -900 N

A. How do I determine the original momentum?

The original momentum of the fullback can be obtained as follow:

Momentum = mass × velocity

Momentum of fullback= 90 Kg × 5 m/s

Momentum of fullback = 450 Kg.m/s

B. How do I determine the impulse imparted?

The impulse imparted, can be obtained as shown below:

Impulse = m(v + u) since the came to rest

Impulse = 90 × (0 + 5)

Impulse = 90 × 5

Impulse = 450 Ns

C. How to determine the force exerted on the fullback?

The force exerted on the fullback can be obtain as follow:

Impulse = force × time

450 = Force × 0.5

Divide both sides by 0.5

Force = 450 / 0.5

Force = 900 N

D. How to determine the force exerted on the tackler?

From Newton's 3rd law of motion which states that to every action, there is an equal an opposite reaction.

Since the force exerted on the fullback is 900 N. Thus, the force exerted on the tackler will be -900N

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To determine which zodiacal constellations are visible in the western sky at 6 am on January 25, refer to the star finder and locate the corresponding positions on the celestial map.

The star finder is a helpful tool for locating celestial objects and obtaining information about the night sky. To use the star finder effectively, it should be held overhead with the compass points aligned to match the actual compass points. Keep in mind that east and west may appear reversed when looking down at the star finder.

The star finder consists of an open ellipse representing the sky for a specific time and date. The edges of the ellipse correspond to the observer's horizon. East and west are not located at the midpoint along the elliptical horizon due to the distortion caused by representing a three-dimensional hemisphere on a flat page. The east and west cardinal points are positioned north along the ellipse from their respective midpoints.

Locating the zenith is essential, as it is directly overhead for all observers and remains stationary. To find the zenith, tape both ends of a string between the north and south points on the star finder, spanning the entire visible sky. Mark a dot on the string midway between the northern and southern horizons using an ink pen. This dot represents the zenith.

By using the star finder and aligning it with the correct date and time, you can identify the zodiacal constellations visible in the western sky at 6 am on January 25. Simply locate the corresponding constellations on the star finder and observe their positions in the western region of the celestial map.

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The wavelength of a 1.0 MHz ultrasound wave traveling through aluminum is approximately 1.5 mm. To express the answer with two significant figures, we round the value to 1.5 mm

To calculate the wavelength, we can use the formula:

wavelength = speed / frequency

In this case, the frequency is given as 1.0 MHz, which is equivalent to 1.0 × 10^6 Hz. The speed of sound in aluminum is approximately 6,320 m/s.

Converting the frequency to Hz and substituting the values into the formula:

wavelength = 6,320 m/s / 1.0 × 10^6 Hz

Simplifying the equation:

wavelength = 6.32 × 10^(-3) m

To express the answer with two significant figures, we round the value to 1.5 mm (since 6.32 has two significant figures).

The wavelength of a 1.0 MHz ultrasound wave traveling through aluminum is approximately 1.5 mm.

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Answer:

It will travel at 1 m/s2

Answer:

It will travel at 1 m/s2

Explanation:

Answer:

Class 1 Levers: Moving the fulcrum closer to the load will increase the mechanical advantage. Moving the effort farther from the fulcrum will increase the mechanical advantage.

Explanation:

Hope it helps you

Answer: There are multiple options:

By varying the supply voltage.

By varying the flux, and by varying the current through the field winding.

By varying the armature voltage, and by varying the armature resistance.

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