if the 140 g ball is moving horizontally at 27 m/s , and the catch is made when the ballplayer is at the highest point of his leap, what is his speed immediately after stopping the ball?

The angular velocity of the ISS is 0.012 rad/s. the height above the Earth's surface at which the ISS orbits is 408 km. the tangential speed of the ISS is 7 km/s.

a) Calculate the angular velocity of the ISS.

The angular velocity of the ISS can be calculated using the following formula:

ω = v / r

where:

ω is the angular velocity in radians per second

v is the tangential velocity in meters per second

r is the radius of the orbit in meters

The tangential velocity of the ISS is the speed at which it travels along the circumference of its orbit. The radius of the ISS's orbit is the distance from the center of the Earth to the ISS.

In this case, the tangential velocity of the ISS is 7.66 kilometers per second. The radius of the ISS's orbit is 6371 kilometers. Therefore, the angular velocity of the ISS is:

ω = 7.66 km/s / 6371 km = 0.012 rad/s

b) Calculate the height above the Earth’s surface at which the ISS orbits.

The height above the Earth's surface at which the ISS orbits can be calculated using the following formula:

h = r * (1 - (1 - e^2)^(1/2))

where:

h is the height above the Earth's surface in meters

r is the radius of the Earth in meters

e is the eccentricity of the orbit

The eccentricity of the ISS's orbit is 0.016. Therefore, the height above the Earth's surface at which the ISS orbits is:

h = 6371 km * (1 - (1 - 0.016^2)^(1/2)) = 408 km

c) Calculate the tangential (linear) speed the ISS must travel to maintain this orbit.

The tangential speed of the ISS can be calculated using the following formula:

v = ω * r

where:

v is the tangential speed in meters per second

ω is the angular velocity in radians per second

r is the radius of the orbit in meters

The angular velocity of the ISS is 0.012 rad/s. The radius of the ISS's orbit is 6371 kilometers. Therefore, the tangential speed of the ISS is:

v = 0.012 rad/s * 6371 km = 7.66 km/s

rounded to the nearest whole number: 7 km/s

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Answer:

Explanation:

Let \(F_{R}\) be the frictional force.

\(F_{net} = F_{applied}-F_{R}\)

2*8=24-\(F_{R}\)

\(F_{R}=24-16=8N\)

\(F_{g}=mg = 2*10 = 20N\)

Coefficient of friction = \(\frac{F_{R}}{F_{g}}\)

=8/20=2/5=0.4

The coefficient of friction = 0.4

Work done is given by the change in kinetic energy of an object

Reason:

Work is done when the total energy of object is affected by the application of force on the object over a distance

Therefore;

Therefore, work is done in the given processes

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The correct terms that fills the box are;

(i) The incident ray

(ii) The normal

(iii) The reflected ray

(iv) The angle of incident

(v) The reflected angle

The terms of the ray diagram is illustrated as follows;

(i) This arrow indicates the incident ray, which is known as the incoming ray.

(ii) This arrow indicates the normal, a perpendicular line to the plane of incidence.

(iii) This arrow indicates the reflected ray; the out going arrow.

(iv) This the angle of incident or incident angle.

(v) This is the reflected angle or angle of reflection.

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Mr. Colb's acceleration down the hallway is 0.91 m/\(s^2\) as per the given data.

Acceleration is the rate at which the speed and direction of a moving object vary over time. A point or object going straight ahead is accelerated when it accelerates or decelerates.

To calculate Mr. Colb's acceleration down the hallway, we can use the formula:

a = (F - f) / m

a = (F - f) / m

a = (950 N - 100 N) / (950 kg * 9.81 m/\(s^2\))

a = 0.91 m/\(s^2\)

To calculate how far from the base of the wall Mr. Colb lands, we can use the equations of motion for a projectile:

y = yo + voyt + 0.5a\(t^2\)

x = xo + voxt

y = yo + voyt + 0.5a\(t^2\)

3.7 m = 0 m + 0 m/s * t + 0.5 * 9.81 \(m/s^2\) x \(t^2\)

t = 0.89 s

Now we can use the horizontal equation of motion to calculate how far Mr. Colb travels horizontally in 0.89 s:

x = xo + vox x t

x = 0 m + 2.8 m/s x 0.89 s

x = 2.49 m

Thus, Mr. Colb lands 2.49 meters away from the base of the wall.

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Answer: mechanical energy to power the train.

Explanation:

Concavelenses have negative focal length and tlways form virtual images.

The focal length is negative as it lies on the left side of lenses.

first one is negative

second is none

third is posotive

last one is negative

left to right order

Answer:

Explanation:

thats the answer

Let's see

Use snells law

\(\\ \rm\Rrightarrow \dfrac{n_1}{n_2}=\dfrac{sini}{sinr}\)

\(\\ \rm\Rrightarrow \mu=\dfrac{sin30}{sin19.9}\)

\(\\ \rm\Rrightarrow \mu=0.5/0.34\)

\(\\ \rm\Rrightarrow \mu=1.47\)

It may be glass

Yes, an object can have zero displacement even if it has moved through a distance.

Displacement is a vector quantity that represents the change in position from the initial point to the final point.Yes, an object can have zero displacement even if it has moved through a distance. It takes into account the direction of motion as well as the magnitude.To illustrate this, consider a scenario where an object moves in a circular path and returns to its initial position. In this case, the object has covered a certain distance along the circumference of the circle. However, since it ends up at the same position it started, the displacement is zero because there is no change in its position relative to the initial point.

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Answer: The charge that flows through the wire in 60 s is 14.87 C.

Explanation: The charge that flows through the wire in 60 s can be calculated using the formula:

Charge = Current x Time

The current can be calculated using Ohm’s law:

Current = Voltage / Resistance

Substituting the given values:

Current = 3.00 V / 12.1 Ohms = 0.2479 A

Charge = 0.2479 A x 60 s = 14.87 C

Hope this helps, and have a great day! =)

Answer:

4m/s²

Explanation:

Initial velocity (u) = 0 m/s

Final velocity (v) = 8 m/s

Time taken (t) = 2 sec

Acceleration (a) = ?

We know

\(a = \frac{v - u}{t} \\ = \frac{8 - 0}{2} \\ = \frac{8}{2} \\ = 4 \: m |s ^{2} \)

Hope it will help :)

As of my knowledge cutoff in September 2021, there is no current or planned space observatory specifically dedicated to observing electromagnetic radiation in the mid-infrared range, roughly from 5 to 20 micrometers (μm) in wavelength. This range is often referred to as the "thermal infrared" as it corresponds to the thermal radiation emitted by objects at room temperature or higher.

While space observatories like the Spitzer Space Telescope have made significant contributions to mid-infrared astronomy, their missions have either ended or are focused on other wavelength ranges. The James Webb Space Telescope (JWST), set to launch in late 2021, will have some capability in the mid-infrared range but will primarily operate in the near-infrared.

However, it's worth noting that the field of mid-infrared astronomy is not neglected. Ground-based observatories and instruments, such as those equipped with adaptive optics or interferometry, continue to advance our understanding of the mid-infrared universe. Additionally, future mission concepts and technology developments may lead to dedicated space observatories for the mid-infrared range.

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Answer:

\(\boxed{ V_{2}= 0.03189 m^3}\)

Explanation:

According to Charles Law

=> \(\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\)

Where \(V_{1}\) = 0.0279 m³, \(T_{1}\) = 280 K and \(T_{2}\) = 320 K

=> \(\frac{0.0279}{280} = \frac{V_{2}}{320}\)

=> \(V_{2}\) = 0.03189 m³

The action-oriented objective in a SMART goal setting system is option D) Increase my distance by one-half mile every other week.

This objective is specific, measurable, achievable, relevant, and time-bound. It is specific because it defines a clear action to be taken (increasing distance), measurable because it includes a specific metric (one-half mile), achievable because it is realistic to increase distance gradually, relevant because it aligns with the goal of completing a marathon, and time-bound because it specifies a regular interval (every other week) for progress tracking. Options A, B, and C are also specific and measurable but lack the regular interval and gradual progression aspects of a SMART goal.

In a SMART goal setting system, an action-oriented objective is one that focuses on specific actions to achieve the desired outcome. Among the given options, B) Run on the trail 4 times a week is the most action-oriented objective. This objective clearly outlines the action (running on the trail) and the frequency (4 times a week), making it easier to track progress and achieve the goal. The other options focus more on outcomes or results, which are important aspects of a goal, but they do not explicitly state the specific actions needed to reach those outcomes.

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The roller coaster will have the greatest amount of gravitational potential energy at the top of the highest point.

Gravitational potential energy is the energy possessed by an object due to its position in a gravitational field. As the roller coaster is transported up the large incline, it gains potential energy, which is converted to kinetic energy as it rolls down the hills, turns, and spirals. At the top of the highest point, the roller coaster has reached its maximum height and thus has the highest potential energy.

As it begins to descend, the potential energy is converted to kinetic energy, allowing the roller coaster to move through the rest of the track until it comes to rest at the passenger loading station.

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--The complete question is, Many roller coasters function by mechanically transporting the cars up a large incline. The cars then roll down and up a series of hills, turns, and spirals until the cars come to rest at the passenger loading station. At which point will the roller coaster have the greatest amount of gravitational potential energy?--

This lamp's estimated current consumption is 8 amperes.

Electric current is the rate of charge (electron) passing in a conductor. The SI unit for electric current is the ampere. As current does not obey vector addition, it is a scalar quantity.

Given information:

amount of charge flowing through the lamp, Q = 28800 C;

The charge flow time was t = 1 hour = 3600 seconds.

Hence, the current passing through the bulb as a result.

I = Q/t

= 28800/3600 ampere,

= 8 ampere

Therefore, this lamp consumes 8 amperes of current.

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Answer:

Boyle's law, Charles's law, and Avogadro's law

Explanation:

It would take Eileen approximately 6.25 years to save for the outright purchase of the car if she used the interest payments from her credit card debt to accumulate savings.

To calculate the time it would take Eileen to save for the outright purchase of the car using the interest payments from her credit card debt, we need to consider the finance charges she pays and the interest she earns on her savings.

Given:

Finance charges paid per year = $1,080

Cost of the car = $9,000

Interest rate on savings = 4%

First, we need to determine how much Eileen can save each year by using the finance charges. This amount is equal to the finance charges paid per year, which is $1,080.

Next, we calculate the interest Eileen can earn on her savings each year. This can be calculated using the interest rate of 4% on her savings.

Now, we can calculate the number of years it would take Eileen to save enough to purchase the car outright by dividing the cost of the car by the savings she can accumulate each year.

Number of years = Cost of the car / (Savings per year + Interest earned per year)

Substituting the given values into the equation:

Number of years = $9,000 / ($1,080 + ($9,000 * 0.04))

To evaluate the number of years it would take Eileen to save for the outright purchase of the car, let's substitute the given values into the equation:

Number of years = $9,000 / ($1,080 + ($9,000 * 0.04))

Number of years = $9,000 / ($1,080 + $360)

Number of years = $9,000 / $1,440

Number of years ≈ 6.25 years

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The separation on the screen between two adjacent peaks would be 4 milliseconds.

The separation on the screen between two adjacent peaks of a sinusoidal voltage depends on the frequency of the signal. The frequency represents the number of complete cycles (peaks) that occur in one second and is measured in Hertz (Hz).

To determine the separation between two adjacent peaks, you need to know the time period or the frequency of the sinusoidal voltage. The time period is the reciprocal of the frequency, given by the formula:

Time Period (T) = 1 / Frequency (f)

Once you have the time period, you can determine the separation between two adjacent peaks by dividing the time period by the number of cycles. For example, if the time period is 0.02 seconds (T = 0.02 s) and there are 5 cycles in this time period, the separation between two adjacent peaks would be:

Separation = Time Period / Number of Cycles

Separation = 0.02 s / 5 = 0.004 s or 4 milliseconds

Therefore, in this example, the separation on the screen between two adjacent peaks would be 4 milliseconds.

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We will have 1.25 kilograms of nitrogen-13 left in the sample after three half-lives, or 2988 minutes, have passed.

The radioactive decay of nitrogen-13 is governed by the following equation:N-13 → C-13 + e+ + ν (1)

The decay of nitrogen-13 to carbon-13 releases a positron and a neutrino. Because mass is conserved in the decay process, the sum of the masses of the nitrogen-13 and positron must be equal to the mass of the carbon-13 and neutrino. Furthermore, the charge must be conserved; the nucleus of the nitrogen-13 has a charge of 7, whereas the carbon-13 nucleus has a charge of 6.

As a result, a proton is transformed into a neutron and a positron is released. Because the half-life of nitrogen-13 is 996 minutes,

the decay constant λ is λ=0.693/t1/2=(0.693/996 minutes) = 0.0006955 min-1

Thus, after t minutes, the quantity N of radioactive nitrogen-13 remaining in the sample is given by:

N = N0 e–λt

where N0 is the initial quantity of nitrogen-13 in the sample.

Initially, we had 10 kilograms of nitrogen-13 in the sample; thus N0=10 kg. We need to find N after 2988 minutes (three half-lives),

so we'll substitute that value into our equation:N = N0 e–λt

N = 10 e–0.0006955 x 2988

N = 10 x 0.125

N = 1.25 kg

After 2988 minutes (three half-lives), 1.25 kilograms of nitrogen-13 will remain in the sample.

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Answer:

no i did not observe anything

Explanation:

Magnification can be achieved with a hologram when viewed with light that has a short wavelength.

In a hologram, light passes through an object and onto a photographic film, producing an interference pattern. The hologram is then illuminated by a laser or other monochromatic light source, causing the interference pattern to be recreated and appear as a three-dimensional image.

Holography is a technique that uses the wave properties of light to produce a three-dimensional image of an object. It was invented by Hungarian-British physicist Dennis Gabor in 1947. Holograms are made by recording the interference pattern produced when a beam of laser light is split into two beams, one of which is shone directly onto a photographic film, and the other of which is made to reflect off an object before reaching the film.

The size of the interference pattern on the film is related to the wavelength of the light used. Shorter wavelengths produce smaller interference patterns, which result in higher magnification. This means that the hologram can be viewed with light that has a short wavelength, such as blue or violet light, in order to achieve magnification. The use of holography has many practical applications, including in medicine, security, and entertainment.

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The magnitude of the change in momentum is therefore 6.12 kg*m/s, and the direction is downward and the floor exerts an average net force of 51 N upward on the ball during the collision.

(a) To find the magnitude and direction of the ball's change in momentum, we need to first find the initial and final momenta of the ball. The initial momentum is given by:

\(p_i = m*v_i\)

where m is the mass of the ball, and \(v_i\) is the initial velocity of the ball before it hits the floor. Substituting the given values, we get:

\(p_i\) = (0.60 kg)(6.0 m/s) = 3.6 kg*m/s

The final momentum is given by:

\(p_f = m*v_f\)

where \(v_f\) is the velocity of the ball after it rebounds from the floor. Substituting the given values, we get:

\(p_f\)= (0.60 kg)(-4.2 m/s) = -2.52 kg*m/s

Note that the negative sign indicates that the direction of the final momentum is opposite to that of the initial momentum.

The change in momentum is given by:

Δp = \(p_f - p_i\)

Substituting the calculated values, we get:

Δp = -2.52 kgm/s - 3.6 kgm/s = -6.12 kg*m/s

The magnitude of the change in momentum is therefore 6.12 kg*m/s, and the direction is downward.

(b) To find the average net force that the floor exerts on the ball, we can use the impulse-momentum theorem:

Δp = \(F_avg\) * Δt

where Δt is the time duration of the collision. Substituting the calculated value of Δp and the given value of Δt, we get:

-6.12 kg*m/s = \(F_avg\) * 0.12 s

Solving for \(F_avg\), we get:

\(F_avg\) = -6.12 kg*m/s / 0.12 s = -51 N

Note that the negative sign indicates that the direction of the average net force is opposite to that of the change in momentum, i.e., upward. Therefore, the floor exerts an average net force of 51 N upward on the ball during the collision.

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A binary star system is made of stars, one of which is brighter than the other. An astronomers are able to detect the dimmer star because its gravity causes the bright star to wobble.

Basically, a star means giant astronomical or celestial object that contains a luminous sphere of plasma and bounded together by its own gravitational force. A binary star system refers to a star system that typically comprises two stars that includes a brighter star and dimmer star.

The dimmer star are easily detectable by astronomers because its gravity causes the bright star to wobble and can be spotted by astronomers through an observation of a phenomenon that is referred to as an eclipsing binary.

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Answer:

1 can damage  chromosomes  

2 reduction in white blood cells ( will recover In Couple of days )

3  sickness

4 Temporary Reduction of Resistance.

Have a great Day!!

Answer:

E=hf

Were, h = Planck constant 6.67*10^11

E=3.8*10^24 * 6.67*10^11= 2.508*q0^36j