If she drove back home using the same path she took out to the university and arrives 7.7 h after she first left home, what was her average speed for the entire trip, in kilometers per hour?

Answer:

The lightbulbs were exploding after several mins of use

Explanation:

Answer:

the lightbulbs were exploding after several minutes of use

Explanation:

a p e x :))

Answer:

Vi = 5 m/s

Explanation:

let (a) acceleration = 0.75 m/s²

(t) time = 20 seconds

Vf = final velocity = 72 km/hr  (convert to m/s to units consistency = 20 m/s)

find Initial velocity (Vi)

       Vf - Vi

a =  -----------

             t

Vi = Vf - (a * t)  = 20 - (0.75 * 20)

Vi = 5 m/s

Answer:

The square of the orbital period of a planet is directly proportional to the cube of the semimajor axis of its orbit.

Explanation:

hope this helps.

Answer:

The amount of heat energy gained by the bullet due to friction as it comes to a stop can be calculated using the equation:

Q = μ * F * x

where Q is the heat energy, μ is the coefficient of friction, F is the frictional force, and x is the distance traveled. However, without more information on the coefficient of friction and the distance traveled, the exact amount of heat energy gained by the bullet cannot be determined.

you have too high of a spin rate with your driver and irons.

The faster the swing speed the longer the distance from the tee. Therefore, to get the ball as far down the fairway as possible, you need to swing as hard as possible without losing balance posture, or control of the club. A softer ball provides more control on off-center shots and more distance on low-impact shots. I downgraded it a bit due to the high price.

These Titleist Tour golf balls are perfect for the beginner golfer who needs a lot of forgiveness on their shots. All in all the Pro is a seasoned athlete who hits the ball so far because he plays on the courts in the best possible conditions. Athletic golf skill maximizes swing speed, thereby maximizing distance. Fairway agronomy, on the other hand, pushes the ball farther. The reason taller golfers hit longer is primarily that their size provides a framework for greater leverage with more muscles and joints.

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Answer:

A

Explanation:

Ultraviolet light occurs after white light;

Do you know why gamma rays are harmful because of their high frequency and short wavelength leading to high intensity.

Though the frequency is higher than that of white light, its because of its intensity.

Ultraviolet rays comes handy from depletion of the earth's ozone layer

Hence harmful Ultraviolet rays from the sun attacks the skin Leading to Sun burn and other things.

Answer:

High frequency is the answer

Explanation:

Took pf test is was 100% correct

Answer:

Explanation:

4 meters east

Joe was experiencing sensory adaptation, while individuals with damage to their visual cortex who could still identify object sizes were engaging in parallel processing. Sally is likely using a visual cliff apparatus to study children's fear of heights.

Joe's experience of not noticing a difference in the weight of the bag of leaves until the end suggests sensory adaptation. Sensory adaptation is the phenomenon where our sensory receptors become less responsive to constant or repetitive stimuli over time. In this case, Joe initially claimed the bag of leaves was not heavy because his sensory receptors adapted to the weight. However, when he noticed a sudden change in weight, he attributed it to the presence of rocks, indicating a difference threshold.

In the second scenario, individuals with damage to their visual cortex should theoretically not be able to see objects presented to them because the visual cortex plays a crucial role in processing visual information. However, when they were able to identify which cup was larger, it indicates that the brain engages in parallel processing. Parallel processing is the ability of the brain to simultaneously process multiple aspects of a stimulus or task. In this case, even though the individuals' visual cortex was damaged, other visual processing pathways or areas in the brain were able to contribute to the identification of object sizes.

Sally's use of a device to determine if children will continue to crawl past a visible edge suggests that she is using a visual cliff apparatus. The visual cliff apparatus is a device used in psychological studies to assess depth perception in infants and young animals. It typically consists of a glass or  plexiglass surface with a visible drop-off, creating the illusion of a cliff. By observing the behavior of children when faced with the visual cliff, researchers can gain insights into their perception of heights and their fear response. The visual cliff apparatus helps to assess if children have developed depth perception and if they perceive the visible edge as a potential danger.

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By using uniform motion, the displacement of a fallen crate after 2.9 seconds is  41.209 meters.

We need to know about uniform motion to solve this problem. The uniform motion is an object's motion under acceleration. It should follow the rule

vt = vo + a . t

vt² = vo² + 2a . s

s = vo . t + 1/2 . a . t²

where vt is final velocity, vo is initial velocity, a is acceleration, t is time and s is displacement.

From the question above, we know that

t = 2.90 s

vo = 0 m/s

a = g = 9.8 m/s²

By substituting the given parameters, we can calculate the displacement with the third equation

s = vo . t + 1/2 . a . t²

s = 0 . 2.9 + 1/2 . 9.8 . 2.9²

s = 0 + 41.209

s = 41.209 m

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Answer:

Acceleration is 0.25m/s^2

Explanation:

Given the following :

Speed = 0.5m/s

Radius(r) of circle = 1m

Acceleration round a circular path is given as :

a = v^2 / r

Where

a = acceleration of the body

v = speed / velocity

r = radius

Therefore,

a = v^2 / r

a = (0.5)^2 / 1

a = 0.25m/s^2

Answer:

i. Cv =3R/2

ii. Cp = 5R/2

Explanation:

i. Cv = Molar heat capacity at constant volume

Since the internal energy of the ideal monoatomic gas is U = 3/2RT and Cv = dU/dT

Differentiating U with respect to T, we have

= d(3/2RT)/dT

= 3R/2

ii. Cp - Molar heat capacity at constant pressure

Cp = Cv + R

substituting Cv into the equation, we have

Cp = 3R/2 + R

taking L.C.M

Cp = (3R + 2R)/2

Cp = 5R/2

Answer:

The automobile tire rotates 91 revolutions

Explanation:

Given;

angular acceleration of the automobile, α = 2.13 rad/s²

time interval, t = 23.2-s

To calculate the number of revolutions, we apply the first kinematic equation;

\(\theta = \omega_i \ + \frac{1}{2} \alpha t^2\)

the initial angular velocity is zero,

\(\theta =0\ + \frac{1}{2} (2.13) (23.2)^2\\\\\theta = 573.2256 \ Rad\)

Find how many revolutions that are in 573.2256 Rad

\(N = \frac{\theta}{2 \pi} = \frac{573.2256}{2\pi} \\\\N = 91 \ revolutions\)

Therefore, the automobile tire rotates 91 revolutions

The statement that a converging lens will send all of the light that it receives from a distant star through a point is true.

This point is known as the focal point of the lens. The way a converging lens works is by bending the light rays that pass through it towards a single point, which is the focal point.

The distance between the lens and the focal point is known as the focal length of the lens. This property of the converging lens is what allows it to form images of distant objects on a screen or in the eye.

It is important to note that the size and position of the image formed by the lens will depend on the distance between the lens and the object being observed, as well as the distance between the lens and the screen or eye.

This is known as the lens equation and can be used to calculate the properties of images formed by lenses.

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All of the following are examples of aerobic exercise except weightlifting, yoga, and stretching exercises.

aerobic exercise is a type of physical activity that increases your heart rate and breathing for an extended period. It helps improve cardiovascular health, endurance, and overall fitness. Some common examples of aerobic exercises include:

These activities involve large muscle groups and can be sustained for a longer duration. They require oxygen to produce energy and help improve the efficiency of the cardiovascular system.

However, there are certain activities that are not considered aerobic exercises. These include weightlifting, yoga, and stretching exercises, as they do not elevate the heart rate and breathing to the same extent as aerobic exercises.

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Cuando se sumerge una piedra en un recipiente con agua, la piedra experimenta dos fuerzas: su peso hacia abajo y una fuerza de empuje hacia arriba que equivale al peso del agua desalojada por la piedra.

Esto se debe al principio de Arquímedes, que establece que un cuerpo sumergido en un fluido experimenta una fuerza de empuje igual al peso del fluido desplazado.

Cuando se sumerge la piedra en el agua, la fuerza de empuje actúa en sentido contrario a la fuerza de gravedad, lo que hace que la piedra parezca "más liviana" en el agua. La magnitud de la fuerza de empuje es igual al peso del agua desplazada por la piedra, según el principio de Arquímedes.

El principio de Arquímedes establece que un cuerpo sumergido en un fluido experimenta una fuerza de empuje dirigida hacia arriba y de magnitud igual al peso del fluido desplazado por el cuerpo. Esto ocurre porque el cuerpo desplaza una cantidad de fluido equivalente a su propio volumen.

En el caso de la piedra sumergida en agua, el volumen del agua desplazada por la piedra es igual al volumen de la piedra. La fuerza de empuje actúa hacia arriba y contrarresta parcialmente la fuerza de gravedad, lo que hace que la piedra parezca "más liviana" en el agua.

Es importante tener en cuenta que la fuerza de empuje depende del volumen del cuerpo y de la densidad del fluido en el que se sumerge. En este caso, al conocer la densidad del agua, podemos determinar la magnitud de la fuerza de empuje como igual al peso del agua desplazada por la piedra.

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Según el principio de Arquímedes, una piedra u otro objeto sumergido en agua experimentará una fuerza de empuje hacia arriba igual al peso del agua que desplaza. Esto hace que el objeto parezca más ligero en el agua que en el aire.

En física, el fenómeno que describes se llama el principio de Arquímedes. Este principio establece que un objeto sumergido en un fluido experimenta una fuerza de empuje hacia arriba que es igual al peso del fluido que desplaza. En este caso, la piedra sumergida en el agua experimentará una disminución en su peso debido a esta fuerza de empuje. Supongamos que la piedra tiene una densidad mucho mayor que el agua, por lo que se hundirá. Sin embargo, sentirá menos peso que en el aire porque el agua empuja hacia arriba contra ella con una fuerza igual al peso del agua que ha desplazado. Este efecto es por el cual los objetos parecen más ligeros cuando están en el agua.

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When vector contain distance and direction it is also known as displacement .

The coil has N 350 turns and therefore the induced EMF in the coil is equal to -89125 times the magnetic field.

When this coil rotates within a magnetic field, it generates an electromotive force (EMF) according to Faraday's law of electromagnetic induction. The formula to calculate the maximum EMF is:

EMF_max = N * A * B * ω * sin(θ)

In this formula, B represents the magnetic field strength and θ is the angle between the magnetic field and the normal to the coil's plane.

The magnetic field causes an induced EMF in the coil, given by the equation:

EMF = -N(wB)A

where N is the number of turns in the coil, w is the angular speed of the coil, B is the magnetic field, and A is the area of the coil. Plugging in the given values, we get:

EMF = -(350)(290)(B)(0.85) = -89125B

So the induced EMF in the coil is equal to -89125 times the magnetic field.

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Planetary orbits are fairly circular and in the same plane.This alignment and circularity of planetary orbits are key characteristics of the structure and dynamics of our solar system.

Kepler's laws of planetary motion describe the characteristics of planetary orbits. According to Kepler's first law, known as the law of elliptical orbits, planetary orbits are shaped like ellipses. However, the eccentricity of these ellipses varies among different planets.

In our solar system, the orbits of most planets are fairly circular. Although they are not perfect circles, the eccentricity of their orbits is relatively low. This means that the shape of the orbit is close to a circle rather than a stretched-out ellipse.

Additionally, all planets in our solar system orbit the Sun in approximately the same plane, known as the ecliptic plane. This plane is determined by the rotational axis of the Sun. The fact that planetary orbits are in the same plane is a consequence of the conservation of angular momentum during the formation of the solar system.

In summary, planetary orbits in our solar system are fairly circular and lie in the same plane. While the orbits are not perfect circles, their eccentricity is relatively low compared to highly stretched-out ellipses. This alignment and circularity of planetary orbits are key characteristics of the structure and dynamics of our solar system.

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The advantages and disadvantages may vary depending on the specific application, material, and the expertise of the personnel conducting the magnetic particle testing.

Advantages of using the magnetic particle method of defect detection:

Sensitivity to Surface and Near-Surface Defects: Magnetic particle testing is highly sensitive to surface and near-surface defects in ferromagnetic materials. It can detect cracks, fractures, and other discontinuities that may not be easily visible to the  eye.

Rapid and Cost-Effective: Magnetic particle testing is a relatively fast and cost-effective method compared to other non-destructive testing techniques.

Real-Time Results: The method provides immediate results, allowing for real-time defect detection. This enables quick decision-making regarding the acceptability of the tested components or structures, leading to faster production cycles and reduced downtime.

Disadvantages of using the magnetic particle method of defect detection:

Limited to Ferromagnetic Materials: Magnetic particle testing is applicable only to ferromagnetic materials, such as iron, nickel, and their alloys. Non-ferromagnetic materials, such as aluminum or copper, cannot be effectively inspected using this method.

Surface Preparation Requirements: Proper surface preparation is crucial for effective magnetic particle testing. The surface must be cleaned thoroughly to remove dirt, grease, and other contaminants that can interfere with the test results. This additional step may require additional time and effort.

Limited Detection Depth: Magnetic particle testing is primarily suited for detecting surface and near-surface defects. It may not be as effective in detecting deeper or internal defects. Other non-destructive testing methods, such as ultrasonic testing or radiographic testing, may be more appropriate for inspecting components with deeper or internal flaws.

It's important to note that the advantages and disadvantages may vary depending on the specific application, material, and the expertise of the personnel conducting the magnetic particle testing.

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An airplane moves 214 m/s as it travels around a vertical circular loop which has a radius of 1.8 km. The magnitude of the normal force on the pilot at the bottom of the loop is 4700 N.

To find the magnitude of the normal force on the pilot at the bottom of the loop, we need to consider the forces acting on the pilot. At the bottom of the loop, there are two main forces acting on the pilot: the gravitational force and the normal force.

The gravitational force is given by the formula F_gravity = m * g, where m is the mass of the pilot and g is the acceleration due to gravity (approximately 9.8 m/s^2).

The normal force is the force exerted by the surface (in this case, the seat) to support the weight of the pilot. At the bottom of the loop, the normal force will be directed upwards to counteract the gravitational force.

In this scenario, the pilot experiences an additional force due to the circular motion. This force is the centripetal force and is provided by the normal force. The centripetal force is given by the formula F_centripetal = m * a_c, where m is the mass of the pilot and a_c is the centripetal acceleration, which is v^2 / r, where v is the velocity of the airplane and r is the radius of the loop.

To find the normal force, we need to calculate the net force acting on the pilot in the vertical direction. At the bottom of the loop, the net force is the sum of the gravitational force and the centripetal force:

Net force = F_gravity + F_centripetal

The normal force is equal in magnitude but opposite in direction to the net force. So, the magnitude of the normal force at the bottom of the loop is:

Magnitude of normal force = |Net force| = |F_gravity + F_centripetal|

Substituting the given values, we have: m = 48 kg v = 214 m/s r = 1.8 km = 1800 m g = 9.8 m/s^2

F_gravity = m * g F_centripetal = m * (v^2 / r)

Net force = F_gravity + F_centripetal Magnitude of normal force = |Net force|

Plugging in the values and performing the calculations, we find that the magnitude of the normal force on the pilot at the bottom of the loop is 4700 N.

An airplane moves 214 m/s as it travels around a vertical circular loop which has a radius of 1.8 km The magnitude of the normal force on the 48 kg pilot at the bottom of the loop is 4700 N. This normal force is required to provide the necessary centripetal force for the pilot to move in a circular path.

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The magnitude of the normal force on the pilot at the bottom of the loop is 5275.2 N.

To determine the magnitude of the normal force on the pilot at the bottom of the loop, we need to consider the forces acting on the pilot. At the bottom of the loop, the pilot experiences two forces: the force of gravity (mg) and the normal force (N).

The force of gravity is given by the equation:

F_gravity = mg,

where m is the mass of the pilot and g is the acceleration due to gravity (approximately 9.8 m/s²).

The normal force is the force exerted by a surface to support the weight of an object resting on it. In this case, it is the force exerted by the seat of the airplane on the pilot. At the bottom of the loop, the normal force will be directed upward and must be large enough to balance the downward force of gravity.

To determine the magnitude of the normal force, we need to consider the net force acting on the pilot at the bottom of the loop. The net force is the vector sum of the gravitational force and the centripetal force.

The centripetal force is provided by the normal force, given by the equation:

F_centripetal = m * v² / r,

where v is the velocity of the airplane and r is the radius of the loop.

At the bottom of the loop, the centripetal force must be equal to the gravitational force plus the normal force:

F_centripetal = F_gravity + N.

Plugging in the values, we have:

m * v² / r = mg + N.

Rearranging the equation to solve for N, we get:

N = m * v² / r - mg.

Now we can substitute the given values:

m = 48 kg (mass of the pilot),

v = 214 m/s (velocity of the airplane),

r = 1.8 km = 1800 m (radius of the loop),

g = 9.8 m/s² (acceleration due to gravity).

N = 48 kg * (214 m/s)² / 1800 m - 48 kg * 9.8 m/s².

Calculating this expression, we find:

N ≈ 5275.2 N.

The magnitude of the normal force on the 48 kg pilot at the bottom of the loop is approximately 5275.2 N

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The wave function for a quantum particle is given by ψ(x)=A exp( −∣x∣ / a) where A and a=0.9 are constants and −[infinity] .

Answer:The given wave function for a quantum particle is ψ(x) = A exp ( −|x| / a). Here, A and a = 0.9 are constants. Given that the length of the box is L = 10 Å, the wave function must vanish outside the box, i.e., at x = ±L / 2.

Thus, ψ (±L / 2) = 0.   ψ (±L / 2) = A exp ( ±L / 2a) = 0.

Thus, ±L / 2a = ∞ ⇒ L = 2a∞/ = 2a/0.   the box's length is L = 2a/0.

The given wave function is ψ(x) = A exp ( −|x| / a)

The wave function vanishes at x = ±L/2

ψ(±L/2) = 0 ⇒ A exp (±L/2a) = 0 This means that ±L/2a = ∞ ⇒ L = 2a/0 , the length of the box is L = 2a/0.

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The question is not complete. The complete question is :

During a certain period of time, the angular position of a rotating object is given by \($\theta =2t^2 +10t+5$\), where θ is in radians and t is in seconds.  Determine the angular position, angular speed, and angular acceleration of the door (a) at t = 0.00 seconds, (b) at t = 3.00 seconds.

Solution :

Given :

Displacement or angular position of the object, \($\theta =2t^2 +10t+5$\)

∴ Angular speed is   \($\omega = \frac{d \theta}{dt}$\)

                                 ω = 10 + 4t

And angular acceleration is \($\alpha = \frac{d \omega}{dt}$\)

                                              α = 4

a). At time, t = 0.00 seconds :

   Angular displacement is \($\theta =2t^2 +10t+5$\)

                                            \($\theta =2(0)^2 +10(0)+5$\)

                                               = 5 rad

  Angular speed is  ω = 10 + 4t

                                 ω = 10 + 4(0)

                                     = 10 rad/s

Angular acceleration is α = 4 \($rad/s^2$\)

b). At time, t = 3.00 seconds :

   Angular displacement is \($\theta =2t^2 +10t+5$\)

                                            \($\theta =2(3)^2 +10(3)+5$\)

                                               = 53 rad

  Angular speed is  ω = 10 + 4t

                                 ω = 10 + 4(3)

                                     = 22 rad/s

Angular acceleration is α = 4 \($rad/s^2$\)

The wavelength of a sound wave with a velocity of 350 meters/second and a frequency of 430 Hz is 0.81 meters.

The relation between velocity(v), frequency(f) and wavelength(lambda) of a sound wave is given by the following formula,

V = (f)(λ)                                                 equation1

We are given that , v = 350 meters/second

f = 430 hertz

By putting the above values in the equation1 , we will get

350 = 430 x (λ)

350/430 = λ

λ = 0.81 meters

Thus, the wavelength of a sound wave with a velocity of 350 meters/second and a frequency of 430 Hz is 0.81 meters.

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If cooking is done using an aluminum pan over an electric burner, decreasing the height of the pan sides will not promote the rate of heat flow from the burner to the food.

Increasing the pan bottom thickness, increasing the pan bottom area, and increasing the burner temperature will all promote the rate of heat flow by providing more conductive material for heat transfer or increasing the temperature gradient. However, decreasing the height of the pan sides does not directly affect the rate of heat flow between the burner and the food. It may affect the distribution of heat within the pan or the exposure of the food to direct heat, but it does not directly promote the transfer of heat from the burner to the food.

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The length of the wire forming the solenoid is approximately 33.43 meters..

To find the length of the wire forming the solenoid, we need to determine the number of turns in the solenoid and then multiply that by the circumference of each turn.

First, we can find the number of turns per meter (n) using the formula for the magnetic field inside the solenoid: B = μ₀ * n * I, where B is the magnetic field, μ₀ is the permeability of free space (4π × 10⁻⁷ Tm/A), n is the number of turns per meter, and I is the current.

Rearranging the formula to solve for n, we have:

n = B / (μ₀ * I)

Plugging in the values given:

n = 20.7 × 10⁻³ T / (4π × 10⁻⁷ Tm/A * 15.0 A)

n ≈ 174.06 turns/m

Since the solenoid is 1.82 m long, the total number of turns (N) is:

N = n * length = 174.06 turns/m * 1.82 m ≈ 316.79 turns (approximately)

Now, we can find the circumference of each turn using the diameter (d) of the solenoid:

Circumference (C) = π * d = π * 3.36 cm

Converting diameter to meters:

C = π * 0.0336 m ≈ 0.1056 m

Finally, to find the length of the wire (L), we multiply the total number of turns by the circumference of each turn:

L = N * C = 316.79 turns * 0.1056 m/turn ≈ 33.43 m

So, the length of the wire is approximately 33.43 meters.

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Answer:

Potential Energy.

Explanation:

Kinetic Energy is when an object is moving and it's the speed when it's released but Potential Energy is when the object is stand still/at rest, like the arrow, as the archer holds the arrow back.

Answer:

True

Explanation:

I just took the test and got 100

(i)Therefore, it takes approximately 9.27 hours to reach its full power output.(ii)It is necessary to have quick-start power sources, this helps maintain a stable and reliable electricity supply even when wind speeds fluctuate.(c)The Bremsstrahlung effect needs to be considered to ensure proper radiation protection.(d) The near-field region is characterized by strong electric and magnetic fields while the far-field region represents the radiation zone.

(i) To calculate the time it takes for the power station to reach its full power output, we can use the formula:

Energy = Power × Time

Given that the power station generates 6120 MWh of energy over a 10-hour period and the rated power at full capacity is 660 MW, we can rearrange the formula to solve for time:

Time = Energy ÷ Power

Converting the energy to watt-hours (Wh):

Energy = 6120 MWh × 1,000,000 Wh/MWh = 6,120,000,000 Wh

Converting the power to watt-hours (Wh):

Power = 660 MW × 1,000,000 Wh/MW = 660,000,000 Wh

Now we can calculate the time:

Time = 6,120,000,000 Wh ÷ 660,000,000 Wh ≈ 9.27 hours

Therefore, it takes approximately 9.27 hours (or 9 hours and 16 minutes) for the power station to reach its full power output.

(ii) The type of power station that can be started up fastest is a gas-fired power station. Gas-fired power stations can reach full power output relatively quickly because they use natural gas combustion to produce energy.

In contrast, other types of power stations, such as coal-fired or nuclear power stations, have longer start-up times. Coal-fired power stations require time to heat up the boiler and generate steam, while nuclear power stations need to go through a complex series of procedures to ensure safe and controlled nuclear reactions.

This is relevant to optimizing the usage of windfarms because wind power is intermittent and dependent on the availability of wind. This helps maintain a stable and reliable electricity supply even when wind speeds fluctuate.

(c) The Bremsstrahlung effect is a phenomenon that occurs when charged particles, such as electrons, are decelerated or deflected by the electric fields of atomic nuclei or other charged particles. As a result, they emit electromagnetic radiation in the form of X-rays or gamma rays.

In shielding design, the Bremsstrahlung effect needs to be considered to ensure proper radiation protection. These materials effectively absorb and attenuate the emitted X-rays and gamma rays, reducing the exposure of individuals to harmful radiation.

(d) The electromagnetic field output from an antenna can be represented by two main regions:

Near-field region: This region is closest to the antenna and is also known as the reactive near-field. It extends from the antenna's surface up to a distance typically equal to one wavelength. In the near-field region, the electromagnetic field is characterized by strong electric and magnetic field components.

Far-field region: Also known as the radiating or the Fraunhofer region, this region extends beyond the near-field region.The electric and magnetic fields are perpendicular to each other and to the direction of propagation.  The far-field region is further divided into the "Fresnel region," which is closer to the antenna and has some characteristics of the near field, and the "Fraunhofer region," which is farther away and exhibits the properties of the far-field.

The transition between the near-field and the far-field regions is gradual and depends on the antenna's size and operating frequency. The size of the antenna and the distance from it determine the boundary between these regions.

In summary, the near-field region is characterized by strong electric and magnetic fields, while the far-field region represents the radiation zone where the energy is radiated away as electromagnetic waves.

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Speed of the Cylinder after it has descended = 3.675m/s

A fundamental principle of physics and chemistry stating that despite internal changes, the overall energy of an isolated system remains constant. The first law of thermodynamics, which is most usually phrased as "energy cannot be created or destroyed," is based on this fundamental idea.

According to the given information

Inertia of gear \($A=10^*(0.125)^{\wedge} 2=0.15625$\)

Inertia of gear \($B=30^*(0.15)^{\wedge} 2=0.675$\)

Let the speed of cylinder be \($\mathrm{v}$\)

angular speed of block \($\mathrm{C}=\mathrm{v} / 0.1 \mathrm{~m} / \mathrm{sec}=10 \mathrm{v}$\)

angular speed of \($\mathrm{A}=(\mathrm{v} / 0.1) * 0.2 / 0.15=13.33 \mathrm{v}$\)

Conserving energy

\($50 * 9.81^* 2=0.5\left(50^* \mathrm{v}^{\wedge} 2+0.15625^*(13.3 \mathrm{v})^{\wedge} 2+0.675^*(10 \mathrm{v})^{\wedge} 2\right)$\)

So,

\($50 * 9.81^* 2=0.5\left(50^* \mathrm{v}^{\wedge} 2+0.15625^*(13.3 \mathrm{v})^{\wedge} 2+0.675^*(10 \mathrm{v})^{\wedge} 2\right)$\)

So,

Speed of the Cylinder after it has descended = 3.675m/s

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