if our goal is to achieve maximum power dissipation across the load resistance, what load is the best choice?

False. A rock does not become permanently deformed when a small amount of stress is applied to it. Rocks can undergo elastic deformation, which means they can deform under stress but return to their original shape once the stress is removed.

Only when the stress exceeds the rock's strength will it undergo plastic deformation, resulting in permanent deformation.
True or false: a rock becomes permanently deformed when even a small amount of stress is applied to it.
Your answer: False. A rock does not become permanently deformed when only a small amount of stress is applied to it. Rocks can often withstand small amounts of stress without undergoing permanent deformation. Permanent deformation usually occurs when a rock is subjected to significant stress over a long period of time or under extreme conditions.

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The given statement is False.

A rock does not become permanently deformed when a small amount of stress is applied to it. Rocks have varying degrees of strength and elasticity, which determine how they respond to stress. When stress is applied to a rock, it may deform elastically, meaning it temporarily changes shape but can return to its original shape once the stress is removed.

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Answer: 25 ft

Explanation:

For a triangle, the area is given by

A = (1/2)base*height

Rearranging,

base = 2A/height

Substituting the given values,

base = 2(350 ft^2)/(28 ft) = 25 ft

A 2 stage piston compressor has an intercooler where compressed air is cooled while passing to the second stage.

Answer: It is  a nominal rate per year

The phenomenon of airplanes experiencing rolling tendencies during transonic flight can be attributed to the aerodynamic effects of compressibility and shock waves.

The airflow around the wings remains mainly connected and smooth during subsonic flight when the airplane's speed is less than the speed of sound. The lift created by the wings is generally uniform, resulting in steady flying with minimal rolling.

These shock waves and supersonic zones can generate an uneven distribution of lift along the wings, causing a transonic buffet. Because of the unequal lift distribution, the airplane may display rolling tendencies that were not evident during subsonic flight.

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In engineering, it is important that all equations be dimensionally consistent, which means that every term must have the same unit.

This ensures that the equation is physically meaningful and that the results are accurate. Dimensional consistency is a key concept in engineering and is used to check the validity of equations and to derive new equations. It is also important for converting units and for making sure that all terms in an equation are in the correct units.

Without dimensional consistency, equations can lead to incorrect results and can cause problems in engineering design and analysis.

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Using the Newton's second law of motion we will see that the acceleration is  0.0875 m/s^2.

The acceleration of a vehicle is determined by the force acting on it and its mass, as described by Newton's second law of motion:

F = m * a

where F is the force acting on the object, m is the mass of the object, and a is the resulting acceleration.

In this case, the force acting on the vehicle is 0.07 N, and the mass of the vehicle is 0.8 kg. Substituting these values into the equation above, we get:

0.07 N = 0.8 kg * a

Solving for a, we get:

a = 0.07 N / 0.8 kg

a = 0.0875 m/s^2

Therefore, the acceleration of the 0.8 kg vehicle powered by 0.07 N of force is 0.0875 m/s^2.

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Answer :

Im not really sure tbh

Explanation:  Water at 15°C is heated by passing it through 2-cm internal-diameter thin-walled copper tubes. Heat is supplied to the water by steam that condenses outside the copper tubes at 120°C. If water is to be heated to 65°C at a rate of 0.2 kg/s, determine (a) the length of the copper tube that needs to be used and (b) the pumping power requirement to overcome pressure losses. Assuming the entire copper tube to be at steam temperature of 120°C

Flashings used in masonry cavity walls can be made of each of the following materials except wood.

Flashings are essential components in masonry cavity walls, designed to prevent water penetration. They can be made from various materials, such as stainless steel, copper, aluminum, lead, and synthetic materials like PVC and EPDM. However, wood is not suitable for flashings, as it lacks the required durability, waterproofing, and corrosion-resistant properties needed for long-term protection against water ingress.

To ensure the effectiveness and longevity of flashings in masonry cavity walls, avoid using wood and opt for materials such as stainless steel, copper, aluminum, lead, or synthetic materials.

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Answer:

1) r12 = r23 ( This signifies that the waves interfere destructively )

2) SiO2 should be chosen  , Thickness = 150 nm

Explanation:

1 ) Prove that; r12 = r23

i) Considering light travelling in medium 1 ( i.e. incident  between layers 1 and 2 )

r₁₂ ( reflection coefficient ) = ( n₁ - n₂ ) / ( n₁ + n₂ )

                                           = ( n₁ - √n₁ n₃ ) / ( n₁ + √n₁ n₃ )

                                           =   \(\frac{1- \sqrt{\frac{n3}{n1} } }{1+ \sqrt{\frac{n3}{n1} } }\)

 ii) considering light travelling in medium 2 ( i.e. incident between layers 2 and 3 )

r₂₃ ( reflection coefficient ) = ( n₂ - n₃ ) / (n₂ + n₃ )

                                            = ( √n₁ n₃  - n₃ ) / ( √n₁ n₃  + n₃ )

                                            = \(\frac{1- \sqrt{\frac{n3}{n1} } }{1+ \sqrt{\frac{n3}{n1} } }\)

hence r12 = r23 ( This signifies that the waves interfere destructively )

2) Determine the antireflection coating to use and the thickness  

Refractive index of SiO2 = 1.5

Refractive index of TiO2 = 2.3

an ideal refractive index for an antireflection coating ( n2 )

= √n₁ n₃ = √(1)(3.5) = 1.87

the refractive index closest to this value = 1.5 ( hence SiO2 will be chosen )

Thickness of SiO2  ( diameter )

= 900 / ( 4*n2 )

= 900 / ( 4 * 1.5 ) =  900 / 6 = 150 nm

The change of volume of the device during the cooling process is 0.0448 m³.

How much does the volume of the device decrease when it is cooled from 106°C to 0°C, given that it initially contains 10 g of oxygen at 20 kPa?

During the cooling process, the volume of the device decreases by 0.0448 m³.

This can be calculated using the ideal gas law, which states that PV = mRT, where P is the pressure, V is the volume, m is the mass, R is the gas constant, and T is the temperature. By rearranging the formula to solve for V, we have V = (mRT) / P.

Plugging in the given values and solving the equation, we find that the change in volume is 0.0448 m³.

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The ways that burton could improve the process of producing snowboards, as well as their operations and their logistics systems are; Explained below

For burton to improve their competitive advantage, they can adopt various business methods to improve their performance as follows;

Logistics and supply chain management are very important factors that can be used to improve upon the competitiveness of business. Thus, snowboards flow should be well managed to gain improvement in efficiency and effectiveness of delivery which will ensure patronage of prospective customers.

Logistics systems perform various operations that leads to the competitive advantage I spoke about earlier. Finally, the production department should ensure that they produce quality products such that customers are motivated to repurchase.

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Answer:Total Voltage = 14V

Explanation: it is possible that a circuit  can contain more than one source of electromotive force which can cause flow of current in the same or opposite direction . When the  connection to  voltage sources  allows for current  from the voltage sources to flow in  same direction,it is termed  Series aiding  Thus, the  Total/effective voltage in a series aiding circuit is  computed as the sum of series aiding voltages .

 Here we have the series aiding voltages to be 5V and 9V ,

therefore,

Total Voltage = 5V + 9V

= 14V

Proper operation of electric deicing boots on individual propeller blades may best be determined by feeling the sequence of boot heating and have an assistant observe the loadmeter indications.

The electrical meters that utility companies install frequently contain a load meter, a gadget. This gauge's main purpose is to show the maximum amount of electricity used since the monitor was last read, typically to see whether there have been any recent power surges that would invalidate the other readings.

The technology can be used by homeowners to figure out how to save energy and when they use electricity the most.

It is simpler to track levels of energy conservation when load meters additionally feature a separate indication that measures the current voltage (amperes) being pulled from the utility company in real time.

Therefore, Proper operation of electric deicing boots on individual propeller blades may best be determined by feeling the sequence of boot heating and have an assistant observe the loadmeter indications.

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Answer:

\(\triangle h=4.935m\)

Explanation:

From the question we are told that:

Liquid density \(\rho=800\)

Diameter of pipe \(d=4cm \approx 0.004m\)

Diameter of venture \(d=10cm \approx 0.010m\)

Specific weight of mercury P_mg \(133 kN/m^3\)

Flow rate \(r=0.05 m^3/s\)

Area A:

            \(A_1=\frac{\pi}{4}0.1^2\\A_1=0.00785m^2\\A_2=\frac{\pi}{4}0.04^2\\A_2=0.001256m^2\\\)

Generally the Bernoulli's equation is mathematically given by

\(\frac{P_1}{\rho_1g}+\frac{V_1^2}{2g}=\frac{P_2}{\rho g}+\frac{V_2^2}{2g}\\\)

Where

\(V_1=\frac{r}{A_1} \\\\ &V_1=\frac{r}{A_2}\)

Therefore

\(P_1-P_2=\frac{Pr^2}{2}(\frac{A_1^2-A_2^2}{A_1^2A_2^2})\)

Generally the equation for pressure difference b/w manometer fluid is given as

\(P_1-P_2=(p_mg-pg)\triangle h\)

Therefore

\((p_mg-pg)\triangle h=\frac{Pr^2}{2}(\frac{A_1^2-A_2^2}{A_1^2A_2^2})\)

\(\triangle h=\frac{\frac{Pr^2}{2}(\frac{A_1^2-A_2^2}{A_1^2A_2^2})}{(p_mg-pg)}\)

\(\triangle h=\frac{\frac{(800)(0.05)^2}{2}(\frac{(0.1)^2-(0.4)^2}{(0.1)^2(0.04)^2})}{(1.33*10^3-800*9.81)}\)

\(\triangle h=4.935m\)

Therefore elevation change is mathematically given by

\(\triangle h=4.935m\)

Answer:

Explanation:

I'm not 100% this is what you want, but here it is:

2

3

13

8

11

A

13

Using the frequency of the radio signal given, the length of the half-wave dipole antenna is 30m

The formula to calculate the length of a half-wave dipole antenna is:

Length (L) = (c / f) / 2

where:

We are given that the frequency of the radio signal is 10 MHz (10,000,000 Hz). Substituting these values into the formula, we get:

L = 3 * 10⁸ / 10 * 10 * 10⁶

L = 30m

Therefore, the length of a half-wave dipole antenna to be used to receive a 10 MHz radio signal is 30 meters.

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The given problem is concerned with a company that has to produce goods for two quarters' period. The company has a regular time capacity and forecast demand, which is given in the table below per month.

We are required to determine the overtime capacity, overtime cost, backorder cost, inventory-holding cost, and the beginning inventory. Given data: Demand | Regular time capacity50 | 50Overtime capacity | 50% of regular time capacity × 1.5= 50% of 50 × 1.5= 25 × 1.5= 37.5 units per month Overtime cost.

Therefore, the overtime cost and backorder cost are zero. Inventory-holding cost= 50 units × R5 per unit= R250Therefore, the company needs to work at 100% of the regular time capacity and 74% of the overtime capacity to meet the forecast demand of 50 units per month for two quarters.

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Answer:

Humans have been on Earth for a very short amount of time.

Explanation:

edgeunity 2021

Answer:

Humans have been on Earth for a very short amount of time<3

D.

Explanation:

The values of h at the two internal boundaries are :

Given data :

Z₁ = Z₂ = Z₃ = 25 m

h top = 120 m

h bottom = 100 m

K₁ = 0.0001 m/s

K₂ = 0.0005 m/s

K₃ = 0.0010 m/s

we will apply the formula below since flow is perpendicular to the bedding plane

Keq = \(\frac{Z1 + Z2 + Z3 }{\frac{Z1}{K1}+\frac{Z2}{K2} + \frac{Z3}{K3} }\)  ----- ( 1 )

Insert values given above into equation 1

Therefore ; Keq = 2.307 * 10⁻⁴ m/s

Hydraulic gradient ( Ieq ) = head loss / length

                                          = ( 120 - 100 ) / 3 * 25

                                   Ieq  = 0.266

Given that the flow is perpendicular to bedding plane

q1 = q2 = q3

V₁ = V₂ = V₃ = V

K₁i₁ = K₂i₂ = K₃i₃ = Keq * ieq

Hence :

V = Keq* Ieq

   = 2.307 * 10⁻⁴ * 0.266

   = 6.15 * 10⁻⁵ m/s .

Also;

K₁i₁ =  Keq * ieq = K₂i₂ = K₃i₃

therefore :

  i₁ = 0.615

  i₂ =  0.123

  i₃ = 0.0615

Pressure at point 1 ( i.e. pressure between first two formations )

h₁ = h top - i₁L₁

   = 120 - 0.615 * 25

   = 104.625 m

Pressure at point 2 ( i.e. pressure between the 2nd and 3rd formation )

h₂ = h₁ - i₂L₂

    = 104.625 - 0.123 * 25

    = 101.55 m

Therefore we can conclude that The values of h at the two internal boundaries are :  h₁ = 104.625 m , h₂ = 101.55 m

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Answer:

Objects that float on water have densities less than the density of water; those that do not float on water have densisties greater than the density of water:

Float on water:  d < 0.0361 lb/in³ (where d denotes denisity)

Do not float on water:  d > 0.0361 lb/in³

Explanation:

I don't know if this works for it or not?

The correct answer to question 40 is d. energy. Energy can be recovered from refuse through incineration in a refractory lined incinerator or water-wall incinerator. Refuse refers to waste or garbage that is generated from households, businesses, or industries.

Incineration is a process that involves burning the refuse in a controlled environment to convert it into ash, gases, and heat. The heat generated can be used to produce steam that drives turbines to generate electricity. Refractory lined incinerators are designed to withstand high temperatures and prevent the escape of harmful gases into the environment. Water-wall incinerators are equipped with water-cooled walls that help to maintain a consistent temperature and minimize the emission of pollutants.

Refractory materials are used to line the walls and floors of incinerators to protect them from the high temperatures and chemical reactions that occur during the combustion process. Therefore, incineration of refuse is an effective method of recovering energy from waste and reducing the volume of waste that goes to landfills.

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The correct code that fixes this bug-filled python code is:

from random import randint

class Character:

   def __init__(self):

       self.name = ""

       self.health = 1

       self.health_max = 1

   def do_damage(self, enemy):

       damage = min(

           max(randint(0, self.health) - randint(0, enemy.health), 0),

           enemy.health)

       enemy.health = enemy.health - damage

       if damage == 0:

           print("%s evades %s's attack." % (enemy.name, self.name))

       else:

           print("%s hurts %s!" % (self.name, enemy.name))

       return enemy.health <= 0

class Enemy(Character):

   def __init__(self, player):

       Character.__init__(self)

       self.name = 'a goblin'

       self.health = randint(1, player.health)

class Player(Character):

   def __init__(self):

       Character.__init__(self)

       self.state = 'normal'

       self.health = 10

       self.health_max = 10

   def quit(self):

       print(

           "%s can't find the way back home, and dies of starvation.\nR.I.P." % self.name)

       self.health = 0

   def help(self): print(Commands.keys())

   def status(self): print("%s's health: %d/%d" %

                           (self.name, self.health, self.health_max))

   def tired(self):

       print("%s feels tired." % self.name)

       self.health = max(1, self.health - 1)

   def rest(self):

       if self.state != 'normal':

           print("%s can't rest now!" % self.name)

           self.enemy_attacks()

       else:

           print("%s rests." % self.name)

           if randint(0, 1):

               self.enemy = Enemy(self)

               print("%s is rudely awakened by %s!" %

                     (self.name, self.enemy.name))

               self.state = 'fight'

               self.enemy_attacks()

           else:

               if self.health < self.health_max:

                   self.health = self.health + 1

               else:

                   print("%s slept too much." % self.name)

                   self.health = self.health - 1

   def explore(self):

       if self.state != 'normal':

           print("%s is too busy right now!" % self.name)

           self.enemy_attacks()

       else:

           print("%s explores a twisty passage." % self.name)

           if randint(0, 1):

               self.enemy = Enemy(self)

               print("%s encounters %s!" % (self.name, self.enemy.name))

               self.state = 'fight'

           else:

               if randint(0, 1):

                   self.tired()

   def flee(self):

       if self.state != 'fight':

           print("%s runs in circles for a while." % self.name)

           self.tired()

       else:

           if randint(1, self.health + 5) > randint(1, self.enemy.health):

               print("%s flees from %s." % (self.name, self.enemy.name))

               self.enemy = None

               self.state = 'normal'

           else:

               print("%s couldn't escape from %s!" %

                     (self.name, self.enemy.name))

               self.enemy_attacks()

   def attack(self):

       if self.state != 'fight':

           print("%s swats the air, without notable results." % self.name)

           self.tired()

       else:

           if self.do_damage(self.enemy):

               print("%s executes %s!" % (self.name, self.enemy.name))

               self.enemy = None

               self.state = 'normal'

               if randint(0, self.health) < 10:

                   self.health = self.health + 1

                   self.health_max = self.health_max + 1

                   print("%s feels stronger!" % self.name)

           else:

               self.enemy_attacks()

   def enemy_attacks(self):

       if self.enemy.do_damage(self):

           print("%s was slaughtered by %s!!!\nR.I.P." %

                 (self.name, self.enemy.name))

Commands = {

   'quit': Player.quit,

   'help': Player.help,

   'status': Player.status,

   'rest': Player.rest,

   'explore': Player.explore,

   'flee': Player.flee,

   'attack': Player.attack,

}

p = Player()

p.name = input("What is your character's name? ")

print("(type help to get a list of actions)\n")

print("%s enters a dark cave, searching for adventure." % p.name)

while(p.health > 0):

   line = input("> ")

   args = line.split()

   if len(args) > 0:

       commandFound = False

       for c in Commands.keys():

           if args[0] == c[:len(args[0])]:

               Commands[c](p)

               commandFound = True

               break

       if not commandFound:

           print("%s doesn't understand the suggestion." % p.name)

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To improve community resilience against natural hazards, mechanisms can be created using an engineering design process.

The engineering design process provides a systematic approach to problem-solving and innovation. When applied to the task of improving community resilience, it enables the creation of effective mechanisms that can safeguard against natural hazards.

The first step in the engineering design process is to define the problem. In this case, the problem is enhancing community resilience against natural hazards. This involves identifying the specific hazards prevalent in the community, such as earthquakes, floods, or hurricanes, and understanding their potential impacts.

The next step is to conduct research and gather information about existing solutions and best practices. This includes studying successful case studies and analyzing the effectiveness of different mechanisms used in other communities facing similar hazards.

Based on the research, the design phase begins. Engineers brainstorm and develop concepts for mechanisms that can mitigate the effects of natural hazards. These mechanisms could include early warning systems, reinforced infrastructure, improved evacuation routes, or resilient building materials.

Once the design concepts are developed, engineers create prototypes and models to test their functionality and effectiveness. These prototypes can be simulated or built on a smaller scale to evaluate their performance.

After testing and refining the prototypes, the final step is implementation. The mechanisms designed to improve community resilience are put into action, taking into account factors like cost, feasibility, and community engagement.

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Answer:

\(\eta =46\%\)

Explanation:

Hello!

In this case, we compute the heat output from coal, given its heating value and the mass flow:

\(Q_H=60\frac{tons}{h}*\frac{1000kg}{1ton}*\frac{1h}{3600s}*\frac{30,000kJ}{kg}\\\\Q_H=500,000\frac{kJ}{s}*\frac{1MJ}{1000J} =500MW\)

Next, since the work done by the power plant is 230 MW, we compute the efficiency as shown below:

\(\eta =\frac{230MW}{500MW}*100\% \\\\\eta =46\%\)

Best regards!

Answer:

1) Visual Communication involves the use of images ans symbolism for the exchange of ideas from a source to the intended audience.

Visual Communication can help enhance the message conveyed by the speaker when the message being conveyed is new to the audience, such as instructional or educational presentation by enable the audience to more quickly understand the the point of view of the speaker

2) A particular situation where it is best to use visual communication is in a communication that involves giving of traffic and way finding details to a tourist

Explanation:

Visual communication can improve the message that is transmitted with the speaker through the transmission of additional concepts to the message, such as gestures, body expressions or communicative looks, which add meanings to the words emitted.

Today, visual communication is extremely developed and is designed to perform several tasks at once. Communication through visual images is progressing thanks to the development of new technologies. Visual communication is one of the key components of modern media and social media.

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