If m<1 = 88 , find the m<3.

Answer:

B. 80, -160

Step-by-step explanation:

The common ratio between these three numbers is -2.

-10 * -2 = 20

20 * - 2 = -40

-40 * -2 = 80

80 * -2 =  -160

Answer:

126 Sq unite

Step-by-step explanation:

I took the assignment

Answer:

126 Sq

Step-by-step explanation:

im taking the test

15 dollars from 1 sidewalk

140 dollars from ? sidewalks

140/15 =9.333(bar)

Dionte needs to shovel 10 sidewalks

The income elasticity of demand is positive, implying that chocolate is a normal good = 0.037

The demand function, Q = 54−5P + 4PA + 0.1Y.

Where Q is the quantity of chocolate demanded, P is the price of chocolate, PA is the price of an apple, and Y is income.

(i) The own-price elasticity of demand for chocolate, we first need to find the expression for it.

The own-price elasticity of demand can be expressed as:

Own-price elasticity of demand = (Percentage change in quantity demanded) / (Percentage change in price)Or,E

P = (ΔQ / Q) / (ΔP / P)E P = dQ / dP * P / Q

Let's calculate the own-price elasticity of demand:

EP= dQ / dP * P / Q= (-5) / (54 - 5P + 4PA + 0.1Y) * 3 / 30

= -0.1667

So, the own-price elasticity of demand for chocolate is -0.1667.

(ii) The cross-price elasticity of demand, we must first determine the expression for it.

The cross-price elasticity of demand can be expressed as:

Cross-price elasticity of demand

= (Percentage change in quantity demanded of chocolate) / (Percentage change in price of apples) Or, E

PA = (ΔQ / Q) / (ΔPA / PA)E PA = dQ / dPA * PA / Q

Let's calculate the cross-price elasticity of demand:

EP = dQ / dPA * PA / Q= (4) / (54 - 5P + 4PA + 0.1Y) * 2 / 30= 0.0296

So, the cross-price elasticity of demand is 0.0296.

(iii) The income elasticity of demand can be expressed as:

Income elasticity of demand = (Percentage change in quantity demanded) / (Percentage change in income)Or,E

Y = (ΔQ / Q) / (ΔY / Y)E Y = dQ / dY * Y / Q

Let's calculate the income elasticity of demand: EY = dQ / dY * Y / Q= (0.1) / (54 - 5P + 4PA + 0.1Y) * 100 / 30

= 0.037

The own-price elasticity of demand is negative, meaning that the quantity demanded of chocolate decreases when the price of chocolate increases.

The cross-price elasticity of demand is positive, indicating that chocolate and apples are substitute goods.

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Answer:

5x^2 +24x +1

Step-by-step explanation:

First you'll want to find the area of the larger rectangle, and then you'll subtract the area of the smaller rectangle (which is not shaded) to get your answer.

Larger Rectangle:

A = length * width

A = (2x + 3)(4x - 5) = (8x^2 - 10x + 12x - 15) = 8x^2 + 2x - 15

Smaller Rectangle:

A = length * width

A = (x - 8)(3x + 2) = (3x^2 + 2x - 24x - 16) = 3x^2 - 22x - 16

Larger Rectangle minus Smaller Rectangle:

(8x^2 + 2x - 15) - (3x^2 - 22x - 16)

5x^2 +24x +1

Answer:0.41

Step-by-step explanation:

The number of elements that are there in the sample space is 6.

It should be noted that sample space simply means the collection or the set of possible outcomes that are in the random experiment.

From the information, in the special deck of cards has 10 cards. four are green, three are blue, and three are red.

Therefore, the sample space will be:

S = GH, GT, BH, BT, RH, RT

It should be noted that H and T represents the head and tail.

Therefore, there are 6 elements.

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Answer:

The volume of the cylinder without the prism is approximately 16.690 cubic centimeters.

Step-by-step explanation:

The volume of the cylinder without the prism can be defined as the volume of the entire cylinder (\(V_{cy}\)), measured in cubic centimeters, minus the volume of the prism (\(V_{pr}\)), measured in cubic centimeters. That is:

\(V = V_{cy}-V_{pr }\) (1)

\(V = \frac{\pi}{4}\cdot D^{2}\cdot h - l^{2}\cdot h\)

\(V = \left(\frac{\pi}{4}\cdot D^{2}-l^{2} \right)\cdot h\) (2)

Where:

\(D\) - Diameter of the cylinder, measured in centimeters.

\(l\) - Side of the square prism, measured in centimeters.

\(h\) - Height of the square prism, measured in centimeters.

If we know that \(D = 2\,cm\), \(l = 0.6\,cm\) and \(h = 6\,cm\), then the volume of the cylinder without the prism is:

\(V = \left[\frac{\pi}{4}\cdot (2\,cm)^{2}-(0.6\,cm)^{2} \right]\cdot (6\,cm)\)

\(V \approx 16.690\,cm^{3}\)

The volume of the cylinder without the prism is approximately 16.690 cubic centimeters.

Answer:?????

Step-by-step explanation:

pls explain it better lol i dont understand

Answer:

B. 45

Step-by-step explanation:

If im wrong please let me know

Have a nice day :)

The statement "Quadrilaterals A and B are both squares" does not provide enough information to determine whether A and B are scale copies of one another.

To determine if two quadrilaterals are scale copies of each other, we need to compare their corresponding sides and angles. If the corresponding sides of two quadrilaterals are proportional and their corresponding angles are congruent, then they are scale copies of each other.

In this case, since both A and B are squares, we know that all of their angles are right angles (90 degrees). However, we do not have any information about the lengths of their sides. Without knowing the lengths of the sides of A and B, we cannot determine if they are scale copies of each other.

Therefore, the statement cannot be determined as true or false based on the given information.

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The probability that the proportion of overweight or obese children in the sample will be greater than 0.57 is less than 50%.

The first paragraph summarizes the answer, stating that the probability is less than 50% because 0.57 is less than the population proportion of 0.60, and the sampling distribution is approximately normal.

In the second paragraph, we can explain the reasoning behind this conclusion. The Central Limit Theorem states that for a large sample size, the sampling distribution of the sample proportion will be approximately normal, regardless of the shape of the population distribution. In this case, the sample was taken in a way that meets the conditions for using the Central Limit Theorem.

Since the population proportion of overweight or obese children is 0.60, any sample proportion below this value is more likely to occur. Therefore, the probability of obtaining a sample proportion greater than 0.57 would be less than 50%. This is because the resulting z-score, which measures how many standard deviations the sample proportion is away from the population proportion, would be negative.

To summarize, the probability of the proportion of overweight or obese children in the sample being greater than 0.57 is less than 50% because 0.57 is less than the population proportion of 0.60, and the sampling distribution is approximately normal.

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Answer:

To solve an equation with a square root in it, first isolate the square root on one side of the equation. Then square both sides of the equation and continue solving for the variable. Don't forget to check your work at the end.

Step-by-step explanation:

Hope this helps!

Answer:  \(z \ge -10\)

Reason: The graph shows all values that are z = -10 or larger.

The closed endpoint at -10 indicates we include it with an "or equal to".

If it was an open hole endpoint, then we'd say z > -10 instead.

The QR decomposition of the given matrix B, B = ⎣⎡​ abc0​ b+1c+2a+31​ c+3a+2b+10​ ⎦⎤​, is possible and can be obtained. QR decomposition decomposes a matrix into an orthogonal matrix (Q) and an upper triangular matrix (R).

To obtain the QR decomposition of the matrix B, we need to find the orthogonal matrix Q and the upper triangular matrix R such that B = QR.

The QR decomposition is possible for any matrix as long as it has full rank and is non-singular. In other words, the matrix should have linearly independent columns.

In this case, the given matrix B does not have a specific structure that guarantees the QR decomposition. Therefore, we need to perform the decomposition through numerical methods such as Gram-Schmidt process or Householder reflections.

The process involves orthogonalizing the columns of B to obtain an orthogonal matrix Q, and then finding the upper triangular matrix R that relates the original matrix B to Q.

However, since the given matrix B is not explicitly provided and only the elements are given in terms of variables (a, b, c), it is not possible to calculate the exact QR decomposition without specific values for a, b, and c.

In conclusion, the QR decomposition of the matrix B is possible, but without the specific values for a, b, and c, we cannot provide the exact orthogonal matrix Q and upper triangular matrix R.

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The value of x in the equation (2+10^x)^0.50=7 is approximately 1.158 (rounded to three decimal places).

To find the value of x, we can start by isolating the term inside the parentheses on the left-hand side of the equation:

(2+10^x)^0.50 = 7

Raising both sides to the power of 2, we get:

2+10^x = 49

Next, we can subtract 2 from both sides:

10^x = 47

To solve for x, we can take the logarithm of both sides using base 10 logarithm:

log10(10^x) = log10(47)

x = log10(47)

Using a calculator, we find that log10(47) is approximately 1.672.

Therefore, the value of x in the equation (2+10^x)^0.50=7 is approximately 1.158 (rounded to three decimal places).

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Answer:

The inequality will be 25.50x ≤ 200

he could by 7 video games.

Step-by-step explanation:

25.50x ≤ 200

x ≤ 200/25.50

x ≤ 7.84

Answer:

7 Games

Step-by-step explanation:

Number of games (g)  times price per game (25.50)  has to be less than or equal to what Roberto has to spend ($200).  So

25.50g< or = 200, solving for g = 7.8 so he can buy 7 games with some left over for a milk shake.

The total distance traveled by the particle over the time interval [1, 5] is 12 units.

To find the total distance traveled, we need to consider both the magnitude and direction of the velocity function. Since the velocity function given is in meters per second (m/sec), the total distance traveled will be measured in meters.

To calculate the total distance, we need to consider the intervals where the velocity function changes its sign. In this case, the velocity function is linear and increasing, starting at t = 1 with a velocity of 3 m/sec. From t = 1 to t = 3, the particle moves in the positive direction, covering a distance of (3t - 9) × (t - 1) = 12 units. From t = 3 to t = 5, the particle moves in the negative direction with the same magnitude, covering a distance of (-1) × (3t - 9) × (t - 3) = 12 unit

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Answer:

(10, - 6)

Step-by-step explanation:

P = (7, - 5)

T(P) = [x +3, y + (-1)]

T(P) = [7 +3, - 5+ (-1)]

T(P) = [7 +3, - 5 -1]

T(P) = (10, - 6)

The translated coordinates of the points  (7,-5) will be  (10, 2).

Two-dimensional figures can be transformed mathematically in order to travel about a plane or coordinate system.

Dilation: The preimage is scaled up or down to create the image.

Reflection: The picture is a preimage that has been reversed.

Rotation: Around a given point, the preimage is rotated to create the final image.

Translation: The image is translated and moved a fixed amount from the preimage.

The image point of (7,-5)after a translation right 3 units and down 1 unit will be,

= [(7+3), (3-1)].

= (10, 2).

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38.

f(3)

= 5(3) - 2

= 15 - 2

= 13

39.

5x - 20 = 0

=> 5x = 0 + 20

=> 5x = 20

=> x = 20/5

=> x = 4

38.)

option H

F(3) = 13

39.)

option C

40.)

{-4 , 8}

The solution to the given system of linear equations is x = 4, y = 20

From the question, we are to determine solution to the given system of equations

The given system of equations is

x+y=6x=y+4

Thus, we can write that

x + y = 6x ----------- (1)

and

6x = y + 4 ------------(2)

Solve the two equations simultaneously

From equation (1)

x + y = 6x

y = 6x - x

y = 5x --------- (3)

Substitute into equation (2)

6x = y + 4

6x = 5x + 4

6x - 5x = 4

x = 4

Substitute the value of x into equation (3)

y = 5x

y = 5(4)

y = 20

Hence, the solution to the given system of linear equations is x = 4, y = 20

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The probability that exactly one out of six randomly chosen female cats weighs more than 4.5 kg is approximately 0.3487, or 34.87%.

a) To find the proportion of female cats with weights between 3.7 and 4.4 kg, we need to calculate the z-scores for these weights and then find the corresponding probabilities using the standard normal distribution.

For a weight of 3.7 kg:

z = (3.7 - 4.1) / 0.6 ≈ -0.67

For a weight of 4.4 kg:

z = (4.4 - 4.1) / 0.6 ≈ 0.50

Using a standard normal table or a calculator, we can find the probabilities associated with these z-scores. The probability of a z-score less than -0.67 is approximately 0.2514, and the probability of a z-score less than 0.50 is approximately 0.6915.

Therefore, the proportion of female cats with weights between 3.7 and 4.4 kg is approximately 0.6915 - 0.2514 = 0.4401, or 44.01%.

b) To find the proportion of female cats that are heavier than a certain cat with a weight 0.5 standard deviations above the mean, we can find the probability associated with the z-score of that weight.

z = (4.1 + 0.5 * 0.6 - 4.1) / 0.6 ≈ 0.50

Using the standard normal distribution, the probability of a z-score greater than 0.50 is approximately 0.3085.

Therefore, the proportion of female cats that are heavier than the cat in question is approximately 0.3085, or 30.85%.

c) The 80th percentile corresponds to a z-score that has an area of 0.80 to its left under the standard normal distribution. Using a standard normal table or calculator, we find that the z-score associated with the 80th percentile is approximately 0.84.

To find the weight corresponding to this z-score:

z = (weight - 4.1) / 0.6 ≈ 0.84

Solving for the weight, we have:

weight ≈ 0.84 * 0.6 + 4.1 ≈ 4.604 kg

Therefore, a female cat whose weight is at the 80th percentile weighs approximately 4.604 kg.

d) To find the probability that a randomly chosen female cat weighs more than 4.5 kg, we need to calculate the z-score for a weight of 4.5 kg and find the probability associated with that z-score being greater than zero.

z = (4.5 - 4.1) / 0.6 ≈ 0.67

Using the standard normal distribution, the probability of a z-score greater than 0.67 is approximately 0.2514.

Therefore, the probability that a randomly chosen female cat weighs more than 4.5 kg is approximately 0.2514, or 25.14%.

e) The probability that exactly one out of six randomly chosen female cats weighs more than 4.5 kg can be calculated using the binomial distribution.

Let p be the probability of a cat weighing more than 4.5 kg, which we found to be 0.2514. The probability of one cat weighing more than 4.5 kg and the other five weighing less can be calculated as:

P(X = 1) = (6 choose 1) * p^1 * (1-p)^5

Using this formula, we can substitute the values and calculate the probability. The result is approximately 0.3487, or 34.87%.

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Answer:

exponential decay

Step-by-step explanation:

because the value that is being multiplied 0.85 is less then 1 then the value decreases.

Ex. when x=0, y=2770, then when x=1, y=2770(0.85) = 2354.5...

Answer:

cant see the pic

Step-by-step explanation:

Answer:

C.) SAS

Step-by-step explanation:

When the marks on a triangle are the same as another, they have a congruent measure.

In the given triangles, the red line and arch on both mean they have a congruent side and angle.

Since they share a side, that side is congruent for both.

So now we have a congruent side, angle, and side. This is the SAS theorem,

Answer:

true

Step-by-step explanation:

your welcome

Answer:

False

Step-by-step explanation:

A negative multiplied by another negative will give you a positive. The answer to -7 x -8 would be positive 56.

Answer:

A) The amount of gas they bought on each coast;

East Coast = 35 gallons

Mid-US = 100 gallons

West Coast = 15 gallons

B) The amount of gas they bought on each coast on the return journey;

East Coast = 37 gallons

Mid-US = 116 gallons

West Coast = 21 gallons

Step-by-step explanation:

Complete Question

Maxis taking a cross-country road trip. Gas prices vary as the friends travel across the US from $4 dollars per gallon on the east coast to $3 in the mid-US, to $5 on the west coast.

(a) If they used twice as much gas in the mid-US than on either coast combined, and they spend $515 on gas to purchased 150 gallons of gas, how many gallons of gas did they buy at each price?

The answer to this question is East Coast - 35 gal, Mid-US - 100 gal, West Coast - 15 gal.

(b) On their way back they had more baggage in the car and spend $601 for 174 gallons of gas. Based on the same ratio as in Part (a), how many gallons of gas did they buy at each price? I don't know the answer to this one

Solution

Let the amount of fuel bought on the east coast = x gallons

Let the amount of fuel bought on the mid-coast = y gallons

Let the amount of fuel bought on the west coast = z gallons

a) - They used twice as much gas in the mid-US than on either coast combined

y = 2(x + z) = 2x + 2z (eqn 1)

- They spend $515 on gas to purchase 150 gallons of gas.

Total gallons purchased = x + y + z = 150

Total amount spent = 4x + 3y + 5z = 515

From eqn 1, y = 2x + 2z, inserting this value for y in the 2 other equations

x + y + z = x + 2x + 2z + z = 150

3x + 3z = 150

Divide through by 3

x + z = 50 (eqn *)

4x + 3y + 5z = 4x + 3(2x + 2z) + 5z = 515

4x + 6x + 6z + 5z = 515

10x + 11z = 515 (eqn **)

x + z = 50

10x + 11z = 515

Solving the simultaneous equation,

x = 35 gallons

z = 15 gallons

y = 2x + 2z = 2(35 + 15) = 100 gallons

B) On the return journey, the ratio between x, y and z is still the same, but the total gallons and total amount spent is now different.

They used twice as much gas in the mid-US than on either coast combined

y = 2(x + z) = 2x + 2z (eqn 1)

- They spend $601 on gas to purchase 174 gallons of gas.

Total gallons purchased = x + y + z = 174

Total amount spent = 4x + 3y + 5z = 601

From eqn 1, y = 2x + 2z, inserting this value for y in the 2 other equations

x + y + z = x + 2x + 2z + z = 174

3x + 3z = 174

Divide through by 3

x + z = 58 (eqn *)

4x + 3y + 5z = 4x + 3(2x + 2z) + 5z = 601

4x + 6x + 6z + 5z = 601

10x + 11z = 601 (eqn **)

x + z = 58

10x + 11z = 601

Solving the simultaneous equation,

x = 37 gallons

z = 21 gallons

y = 2x + 2z = 2(37 + 21) = 116 gallons

Hope this Helps!!!

Answer:

m Angle PQS = 7x -6

m Angle SQR = 4x +15

m Angle PQS + m Angle SQR =11x +11 = m Angle PQR

Angle PQR +Angle PQT = 180⁰

=) 11x +11 =180⁰

=) 11x =169⁰

=) x = 169/11 = 15.3

Answer:

m Angle PQS = 7x -6

m Angle SQR = 4x +15

m Angle PQS + m Angle SQR =11x +11 = m Angle PQR

Angle PQR +Angle PQT = 180⁰

=) 11x +11 =180⁰

=) 11x =169⁰

=) x = 169/11 = 15.3

Step-by-step explanation:

Give brainliest

Answer: The answer is B

Step-by-step explanation:

Answer:

Step-by-step explanation:

Both x and y have the same numerical coefficients so they are parallel. Even the signs are the same. That means that the lines are parallel. To show this, I've included the graph below. So there are NO solutions which is C

Red: x + 2y = -2

Blue: x +2y = - 4

The required value of x is 22 degrees for the given figure.

Adjacent angles are a sort of additional angle. Adjacent angles share a common side and vertex, such as a corner point. Their points do not overlap in any manner.

As we know that supplementary angles are defined as when pairing of angles addition to 180° then they are called supplementary angles.:

According to the given figure, it can be written as follows:

2x + 24 + 6x - 20 = 180

8x + 4 = 180

8x = 180 - 4

8x = 176

x = 176/8

x = 22

Therefore, the required value of x is 22 degrees for the given figure.

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The complete question is as follows:

Find the value of x for the below figure.

The distance the slower and faster car travelled are 360 km and 432 km respectively.

Two cars start at the same time from two towns 792 kilometres apart and meet in 9 hours.

One car can travel 8 km faster than the other car.

let

x = speed of the slower car

x + 8 = speed of the faster car

The cars meet in 9 hours and both cover a distance of 792 km.

Therefore,

speed = distance / time

distance = time × speed

Hence,

9x + 9(x + 8) = 792

9x + 9x + 72 = 792

18x = 792 - 72

18x = 720

divide both sides by 18

x = 720 / 18

x = 40

Therefore,

speed of the slower car = 40 km per hour

speed of the faster car = 48 km per hour

Hence,

how far the slower car go(distance) = 40 × 9 = 360 km

how far the faster car go(distance) = 48 × 9 = 432 km

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