The length of MA is 28 units.
To solve for y, we need to set the equation for MA equal to the equation for AK since they are equal:
5y + 8 = 6y + 4
By simplifying the equation, we can solve for y:
5y - 6y = 4 - 8
-y = -4
y = 4
Therefore, y equals 4.
To find the length of MA, we can substitute y = 4 into the equation for MA:
MA = 5y + 8 = 5(4) + 8 = 28
Hence, the length of MA is 28.
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Approximately 78.9% of high school students in the United States have an iPhone. if a random sample of 50 students is selected what is the probability that less than 75% of the sample students have iPhones?
The probability that less than 75% of the sample students have iPhones is approximately 0.2478.
What is probability?
This is a binomial probability problem, where each student either has an iPhone or does not have an iPhone, and the probability of success (having an iPhone) is 0.789.
Let X be the number of students in the sample who have an iPhone. We want to find P(X < 0.75 * 50) = P(X < 37.5)
Using the binomial probability formula, we have:
P(X < 37.5) = Σ P(X = k), for k = 0, 1, 2, ..., 37
However, this is a tedious calculation. Instead, we can use a normal approximation to the binomial distribution, since n * p = 50 * 0.789 = 39.45 > 10 and n * (1 - p) = 50 * 0.211 = 10.55 > 10.
Using the normal approximation, we can standardize the random variable X:
Z = (X - μ) / σ
where μ = n * p = 39.45 and σ = √(n * p * (1 - p)) = √(50 * 0.789 * 0.211) = 2.88.
Then, we have:
P(X < 37.5) = P(Z < (37.5 - 39.45) / 2.88) = P(Z < -0.68)
Using a standard normal table or calculator, we find that P(Z < -0.68) is approximately 0.2478.
Therefore, the probability that less than 75% of the sample students have iPhones is approximately 0.2478.
Binomial probability is a type of probability distribution that describes the number of successes in a fixed number of independent trials, where each trial has only two possible outcomes: success or failure. It assumes that the probability of success in each trial is constant, and the trials are independent of each other. The binomial distribution is characterized by two parameters: the number of trials and the probability of success in each trial.
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HELP ME OUT PLS!!!!!!!
1) Why was the narrator surprised when she walked to the carnival?
A) She heard noises coming from the park.
B) She saw shadows on the walls of the tent.
C) The moonlight lit up the streets in the town.
D) It seemed as if she was alone on the streets.
Find the Area of the shaded region. Round your answer to the nearest tenth.
Answer:
610m^2
Step-by-step explanation:
first we find the total area:
25*42=1050
then, we find the area of the white rectangle:
20*22=440
to find the area of the shaded region (which i'm assuming is the blue part), we can subtract the total area by the area of the white rectangle:
1050-440=610
so, the total area is 610m^2.
Hugo and Viviana work in an office with ten other coworkers. Out of these 12 workers, their boss needs to choose a group of four to work together on a project. Suppose Hugo and Viviana absolutely refuse, under any circumstances, to work together. Under this restriction, how many different working groups of four can be formed
Answer:
450
Step-by-step explanation:
The total number of possible working groups of 4 workers selecting from 12 workers is the number of ways of selecting 4 persons from 12 persons
\(=\binom{12}{4}=\frac{12\times 11 \times 10 \times 9}{1\times 2 \times 3\times 4}=495\)
The total number of possible groups of 4 workers in which 2 persons (Hugo and Viviana) always come together
\(= \binom {12-2}{4-2}=\binom {10}{2}=\frac{10\times9}{1\times2}=45\)
So, the total number of possible working groups in which Hugo and Viviana are not working together in any of the groups \(= 495-45=450\).
please refer to the image
29. Assertion :7√5, √2+21 are the irrational number. Reason: every integer is an rational number 30.
The assertion is true. Both 7√5 and √2 + 21 are irrational numbers because they cannot be expressed as fractions.
The assertion is true. Both 7√5 and √2 + 21 are irrational numbers.
An irrational number is defined as a number that cannot be expressed as a fraction of two integers and has an infinite non-repeating decimal representation.
In the case of 7√5, the square root of 5 is an irrational number because it cannot be expressed as a fraction. Multiplying it by 7 does not change its irrational nature.
Similarly, √2 is also an irrational number because the square root of 2 cannot be expressed as a fraction. Adding 21 to √2 does not alter its irrationality.
The reason provided, that every integer is a rational number, is not relevant to the given assertion. While it is true that every integer is a rational number because it can be expressed as a fraction (e.g., 3 can be written as 3/1), it does not contradict the fact that 7√5 and √2 + 21 are irrational numbers.
In conclusion, the assertion is valid, and both 7√5 and √2 + 21 are irrational numbers.
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I’ll give brainliest! Please help
Answer:
65
Step-by-step explanation:
The lines are parallell so m1 = m5, and m3=m8. 180-115 is 65
Mrs. O'Dell has 8 different
vegetables to plant in her
garden. She wants to divide
her garden into 8 squares. Each
square should be the same size.
Help Mrs. O'Dell divide her
garden into 8 squares. What is
the measurement of each side
of the squares?
The measurement of each of the squares will guarantee Mrs. O'Dell has 8 different squares and they are all the same size are 75 centimeters by 100 centimeters.
How to divide the total area into 8 squares which are the same size?To begin, let's identify the best way to divide the total area. For this, there are 2 options:
Create two rows each with 4 squares = 4 x 2 = 8Create four rows each with 2 squares = 2 x 4 8=Let's use the first pattern:
Length: 3 meters / 4 = 0.75meters or 75 centimetersWidth= 2 meters / 2 = 1 meter or 100 centimetersBased on this, the dimensions for each section should be 75 centimeters by 100 centimeters.
Note: This question is incomplete; here is the missing section:
Dimensions of the garden: 3 meters x 2 meters
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What is the present value of R13 000 p.a. invested at the beginning of each year for 8years at 10%p.a. compound interest? (NB Use the compound interest tables provided or work to three decimal places only.)
Given statement solution is :- The present value of R13,000 per year invested for 8 years at 10% compound interest is approximately R69,776.60.
To calculate the present value of an investment with compound interest, we can use the formula for the present value of an annuity:
PV = A *\((1 - (1 + r)^(-n)) / r\)
Where:
PV = Present value
A = Annual payment or cash flow
r = Interest rate per period
n = Number of periods
In this case, the annual payment (A) is R13,000, the interest rate (r) is 10% per year, and the investment is made for 8 years (n).
Using the formula and substituting the given values, we can calculate the present value:
PV = \(13000 * (1 - (1 + 0.10)^(-8)) / 0.10\)
Calculating this expression:
PV = \(13000 * (1 - 1.10^(-8)) / 0.10\)
= 13000 * (1 - 0.46318) / 0.10
= 13000 * 0.53682 / 0.10
= 6977.66 / 0.10
= 69776.6
Therefore, the present value of R13,000 per year invested for 8 years at 10% compound interest is approximately R69,776.60.
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Use the figure below to answer the question that follows:
What must be given to prove that ABIJ~ ABDF? (6 points)
Answer:
To prove that ABIJ ~ ABDF, we must show that the corresponding angles are congruent and the corresponding sides are proportional.
From the figure, we can see that:
- ∠ABI ≅ ∠DBF (corresponding angles)
- ∠BAI ≅ ∠FBD (corresponding angles)
- ∠ABJ ≅ ∠DFB (corresponding angles)
To show that the corresponding sides are proportional, we can use the following ratios:
- AB/AB = 1 (common side)
- AI/DF = 2/3 (given)
- BJ/BF = 2/3 (given)
Therefore, if we can prove that the corresponding angles are congruent and the corresponding sides are proportional, we can conclude that ABIJ ~ ABDF.
Step-by-step explanation:
Graph the linear equation.
x - 2y = - 2
The graph of the linear equation can be seen in the image below.
How to graph the linear equation?Here we have the linear equation:
x - 2y = -2
To graph it, we need to find two points that belong to the line, and then we can graph these and connect them with a line.
If x = 0, we have:
0 - 2y = -2
y = -2/-2 = 1
if x = 1 then:
1 - 2y = -2
1 + 2 = 2y
3 = 2y
3/2 = y
Then we have the points (0, 1) and (1, 3/2), now just graph these points on a coordinate axis and then connect them with a line, we will get:
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The taxi fare in a city is as follows: For the first kilometer, the fare is Rs. 18 and for the subsequent
distance it is Rs. 15 per kilometer. Taking the distance covered as x km and total fares as Rs. y, write a
linear equation for this information, and draw its graph.
please a answer this question!
Answer:
y = 15x +3
Step-by-step explanation:
If the rate were a straight Rs15 per km, then the equation would be ...
y = 15x . . . . fare for x km
However, the first km has an additional Rs3 added to the fare. So, the equation is ...
y = 15x +3 . . . . . fare in Rs for x km
If ll m, find the value of each missing variable(s) .
Answer:
1. m=5
2. 2(8x+11)
3.m=7
Step-by-step explanation:
grace thought of a number, added 7, multiflied by 3, took away 5 and divided by 4 to give an answer of 7
Answer:
Step-by-step explanation:
To find the number that Grace thought:
We'll represent the unknown number as "x."
"Added 7": This can be represented as (x + 7).
"Multiplied by 3": This becomes 3 * (x + 7).
"Took away 5": This is represented as 3 * (x + 7) - 5.
"Divided by 4": This gives (3 * (x + 7) - 5) / 4.
"To give an answer of 7": The equation is (3 * (x + 7) - 5) / 4 = 7.
Now we can solve for x:
(3 * (x + 7) - 5) / 4 = 7
Multiply both sides by 4 to eliminate the denominator:
3 * (x + 7) - 5 = 28
Simplify the left side:
3x + 21 - 5 = 28
Combine like terms:
3x + 16 = 28
Subtract 16 from both sides:
3x = 12
Divide both sides by 3:
x = 4
Therefore, the number that Grace thought of is 4.
how many parts of pat's garden do not have flowers. Explain? Fractions
Answer:GIVE A BETTER DETAILED QUESTION sorry for caps
Step-by-step explanation:
Determine the end behavior of the given polynomial function: f(x)=-x^2(1-2x)(x+2)
Solution
Given
\(\begin{gathered} f(x)=-x^2(1-2x)(x+2) \\ \\ \Rightarrow f(x)=-x^2(-1)(2x-1)(x+2) \\ \\ \Rightarrow f(x)=x^2(2x-1)(x+2) \end{gathered}\)The correct option is C
Identify the axis of symmetry, vertex, and range for the quadratic function.
Marine biologists are concerned that pollution from a nearby factory has affected the health of local sea urchins. Which of the following is most likely to be the population of interest?
Choose the correct answer below
A 4 sea urchins with abnormal coloration
B. All of the sea urchins near the plant
C. All of the sea urchins in the entire ocean
D. 20 sea urchins gathered from tidal pools
Answer:
its C. all of the sea urchin in the entire ovean is the most likely to be the population of interest
The population of interest will most likely be option B. all of the sea urchins near the plant.
The term 'population of interest' refers to the group or number from which inference is made or done for research purposes. And from this group, the researcher will try to draw conclusions from his/her study.
A population of interest is generally taken for studies or statistical references.In the given scenario, the biologists found that the nearby factory is directly affecting the health of the local urchins.And in conducting the research, the population of sea urchins near the plant will be taken or regarded as the population of interest.For the marine biologists to determine the extent of the factory's effect on the sea urchins, they would consider or take the sea urchins near the factory population as the population of interest. Thus, the correct answer is option B.
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5(8-70) + 29 nt (n=4
Answer:
5 x 8 = 40
5 x -70 = -350
40 - 350
29 x 4 = 116t
therefore it would be 40 - 350 + 116t
I think
What is the standard deviation of the exponential distribution whose density function is f(x)=10*e^(-10x)?
The standard deviation of the exponential distribution is of 0.1.
-----------------
The exponential probability distribution, with mean and standard deviation m, is described by the following equation:
\(f(x) = \mu e^{-\mu x}\)
In which \(\mu = \frac{1}{m}\) is the decay parameter.
-----------------
The distribution is described by:
\(f(x) = 10e^{-10x}\)
Which has \(\mu = 10\)Thus, the mean and standard deviation are given by:
\(m = \frac{1}{\mu} = \frac{1}{10} = 0.1\)
The standard deviation is of 0.1.
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We are required to find the standard deviation of the exponential distribution.
The standard deviation of the exponential distribution whose density function is f(x)=10*e^(-10x) is 0.1.
By convention, exponential probability distributions have density function in the form:
f(X) = f(x)=μ*e^(-μx)............... equation 1.
Where μ = decay parameter.
However, the decay parameter is related to the standard deviation of the distribution by the formular:
μ = 1/m
Where m = Standard deviation of the distribution.
Therefore, by comparison of equation 1 with f(x)=10*e^(-10x).
It is evident that the decay parameter, μ = 10
Therefore, the standard deviation, m = 1/μ = 1/10 = 0.1.
The standard deviation of the exponential distribution whose density function is f(x)=10*e^(-10x) is 0.1
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solve for brainliest A keem measured the capacity of a glass as
2 7 0 mL and the capacity of a Th e rm o s® a s
1 L. He said that the ratio 270 :1 compare s
the capacity of the glass with the cap a c i t y
of the Th e rm o s®. Is his reasoning corre c t ?
E x p l a i n .
Answer:
\(his \: reasoning \: is \: correct.\)
Step-by-step explanation:
\(since \: the \: ratio \: of \: the \: glass \: to \:that \\ \: of \: the \: thermos \: is \: in \: the \: fraction : \\ \frac{2 7 0 mL }{1mL} \: which \: is \:270 mL : 1mL \\ then \: the \: keem \: is \: right.\)
In 1950, a U.S. population
model
was y = 151. (1.013)^t-1950 million
people, where t is the year. What did
the model predict the U.S. population
would be in the year 2000?
In a case whereby In 1950, a U.S. population model was y = 151. (1.013)^t-1950 million people, where t is the year, the model predict the U.S. population would be 288 million in the year 2000.
What is population model ?Population models are mechanical theories that link alterations in population structure and density to responses at the individual level (life history features in eco-evolutionary theory or vital rates in demographic theory).
The model was given as y=151x(1.013)^t-1950
where the future time t = 2000
Then we can substitute the given year 2000 as the value of 't'
then we will have y=[151x(1.013)^(2000-1950)] = 288 million
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A plane took off at a point that is 42 meters from the control tower. The flight path takes the plane over the control tower that is 98 meters high. After traveling 83 meters, which statement is most accurate?
A. The plane needs to be about 15 meters higher to clear the tower.
B. The plane clears the tower with about 27 meters to spare.
C. The plane clears the tower with about 15 meters to spare.
D. The plane needs to be about 27 meters higher to clear the tower.
Answer:
D. The plane needs to be about 27 meters higher to clear the tower.
Step-by-step explanation:
In this scenario a triangle is being formed. The base the plane's takeoff point to the tower base which is 42 meters (x).
The hypothenus is the distance travelled by the plane which is 83 meters (h)
The height of the tower is 98 Meters
We want to calculate the height of our triangle (y) so we can guage if the plane scaled the tower.
According to Pythagorean theorem
(x^2) + (y^2) = h^2
y = √ (h^2) - (x^2)
y = √ (83^2) - (42^2)
y= √(6889 - 1764)
y= 71.59 Meters
The height from the plane's position to the top of the tower will be
Height difference = 98 - 71.59 = 26.41 Meters
So the plane should go about 27 Meters higher to clear the tower
The 5-lb collar slides on the smooth rod, so that when it is at A it has a speed of 10 ft/s. A) if the spring to which it is at- tached has an unstretched length of 3 ft and a stiffness of k-= 10 lb/ etermine the normal force on the collar at this instant. B)Determine the acceleration of the collar at this instant.
The acceleration of the collar at point A is 5 ft/s^2.
A) To determine the normal force on the collar at point A, we need to consider the forces acting on the collar. The only force acting on the collar in the vertical direction is the weight of the collar (5 lb), which is balanced by the normal force exerted by the rod. Therefore, we can write:
N - 5 = 0
where N is the normal force. Solving for N, we get:
N = 5 lb
B) To determine the acceleration of the collar at point A, we need to use Newton's second law, which states that the net force acting on an object is equal to its mass times its acceleration. The net force on the collar is given by the force exerted by the spring, which is equal to the spring constant times the displacement of the collar from its unstretched length. At point A, the displacement of the collar is:
x = L - y = 3 - 0 = 3 ft
where L is the length of the rod and y is the position of the collar on the rod. Therefore, the force exerted by the spring is:
F = kx = 10 lb/ft × 3 ft = 30 lb
The weight of the collar is:
W = mg = 5 lb
where g is the acceleration due to gravity. The net force on the collar is therefore:
Fnet = F - W = 30 - 5 = 25 lb
Using Newton's second law, we can write:
Fnet = ma
where a is the acceleration of the collar. Solving for a, we get:
a = Fnet / m = 25 lb / 5 lb = 5 ft/s^2
Therefore, the acceleration of the collar at point A is 5 ft/s^2.
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A +3b identity each part of the algebraic expression
Answer:
3=coeffcient
b=variable
A=constant
Solve for x in the equation e2x = e7x−5.
The value of x in the equation e^2x = e^7x−5 is 1
How to solve for x in the equation?The equation is given as:
e^2x = e^7x−5.
Next, we compare the exponents
2x = 7x - 5
Evaluate the like terms
-5x = -5
Divide by -5
x = 1
Hence, the value of x in the equation e^2x = e^7x−5 is 1
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The box plots display data collected when two teachers asked their classes how many pencils they lose in a school year.
A box plot uses a number line from 5 to 47 with tick marks every one unit. The box extends from 8 to 14 on the number line. A line in the box is at 11. The lines outside the box end at 7 and 45. The graph is titled Mr. Johnson's Class, and the line is labeled Number Of Pencils.
A box plot uses a number line from 0 to 51 with tick marks every one unit. The box extends from 12 to 21 on the number line. A line in the box is at 14.5. The lines outside the box end at 0 and 50. The graph is titled Mr. Simpson's Class, and the line is labeled Number Of Pencils.
Which class lost the most pencils overall based on the data displayed?
Mr. Simpson's class; it has a larger median value 14.5 pencils
Mr. Johnson's class; it has a larger median of 11 pencils
Mr. Simpson's class; it has a narrow spread in the data
Mr. Johnson's class; it has a wide spread in the data
Answer:
A) Mr. Simpson's class; it has a larger median value 14.5 pencils.
Step-by-step explanation:
A box plot is a visual display of the five-number summary:
Minimum value = The value at the end of the left whisker.Lower quartile (Q₁) = The left side of the box.Median (Q₂) = The vertical line inside the box.Upper quartile (Q₃) = The right side of the boxMaximum = The value at the end of the right whisker.From inspection of the box plots (attached), the measures of central tendency (median) and dispersion (range and IQR) are:
Mr Johnson's class:
Median = 11IQR = Q₃ - Q₁ = 14 - 8 = 6Range = max - min = 45 - 7 = 38Mr Simpson's class:
Median = 14.5IQR = Q₃ - Q₁ = 21 - 12 = 9Range = max - min = 50 - 0 = 50In a box plot, the median is a measure of central tendency and tells us the location of the middle value in the dataset. It divides the data into two equal halves, with 50% of the values falling below the median and 50% above it.
The median number of pencils lost in Mr Simpson's class is greater than the median number of pencils lost in Mr Johnson's class. Therefore, Mr. Simpson's class has a larger median value.
The spread of data in a dataset can be measured using both the range and the interquartile range (IQR).
As Mr Simpson's class has a greater IQR and range than Mr Johnson's class, the data in Mr Simpson's class is more spread out than in Mr Johnson's class.
In summary, as Mr Simpson's class has a larger median 14.5 and a wider spread of data, then Mr Simpson's class lost the most pencils overall.
A company manufacturing a roadside lighting system wants to estimate the average illuminance (brightness) at sunset. The illuminance at sunset for the past 10 days was as follows: 406, 385, 389, 383, 352, 379, 388, 343, 368, 387 lux. Construct a 95% confidence intervals for the average illuminance at sunset. Assume that the illuminance at sunset is approximately normally distributed.
Answer:
(364.595 ; 391.405)
Step-by-step explanation:
Given the sample data:
406, 385, 389, 383, 352, 379, 388, 343, 368, 387
Using calculator :
Sample mean, xbar = 378
Standard deviation, s = 18.74
Confidence interval :
Xbar ± Margin of error
Margin of Error = Tcritical * s/√n
TCritical at df = 24 ; 0.05 = 2.262
Margin of Error = 2.262 * 18.74/√10 = 13.405
Lower boundary = (378 - 13.405) = 364.595
Upper boundary = (378 + 13.405) = 391.405
(364.595 ; 391.405)
Find the total in the retirement account given the following conditions:
Monthly contributions = $225
Interest rate = 4.99%
Years invested = 38
To find the total in the retirement account after 38 years of investing with monthly contributions and an interest rate of 4.99%, we can use the compound interest formula.
The formula for the future value of an investment with regular monthly contributions is given by:
FV = P * [(1 + r)^n - 1] / r
Where:
FV is the future value or the total in the retirement account.
P is the monthly contribution amount.
r is the monthly interest rate (annual interest rate divided by 12).
n is the number of monthly contributions (years invested multiplied by 12).
Let's calculate the total:
P = $225
r = 4.99% / 100 / 12 = 0.0041583 (monthly interest rate)
n = 38 * 12 = 456 (number of monthly contributions)
FV = $225 * [(1 + 0.0041583)^456 - 1] / 0.0041583
Using a financial calculator or spreadsheet, we can evaluate this expression to find the future value or total in the retirement account.
The calculated total may vary depending on the compounding frequency and rounding used.
Use algebra to write a quadratic equation that passes through points (1/2, 9/16) (1,9/2) (-1, 11/2)
Please help tyy!
The quadratic equation that passes through points (1/2, 9/16) (1,9/2) (-1, 11/2) are 1/2 = 81 a/256 - 9b/16 + c ,9/2= a + b + c and 11/2 = -a - b + c .
What is quadratic equation?Any equation containing one term in which the unknown is squared and no term in which it is raised to a higher power. The quadratic formula to solve a quadratic equation ax2 + bx + c = 0 is x = [-b ± √(b2 - 4ac)]/2a.
Given:
The given points are
(1/2, 9/16) (1,9/2) (-1, 11/2)
According to given question we have
We know the basic quadratic equation are
\(y = ax^{2} + bx + c\)
We have 3 points we can plug in for (x, y) to create 3 simultaneous equations
The equation are at the points
1. (1/2, 9/16)
1/2 = 81 a/256 - 9b/16 + c
The equation are at the points
2. (1,9/2)
9/2= a + b + c
The equation are at the points
3. (-1, 11/2)
11/2 = -a - b + c
Therefore, the quadratic equation that passes through points (1/2, 9/16) (1,9/2) (-1, 11/2) are 1/2 = 81 a/256 - 9b/16 + c ,9/2= a + b + c and 11/2 = -a - b + c .
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