if interstellar dust makes an RR Lyrae variable star appear 1 magnitude fainter, we will not overestimate its distance. The estimated distance will be equal to the true distance. Hence Overestimated distance ratio is 1.
The magnitude-distance formula is given by: m - M = 5 × log10(d/10)
Where:
m is the apparent magnitude,
M is the absolute magnitude,
d is the distance in parsecs.
Given that the apparent magnitude is m - 1 (1 magnitude fainter) and the absolute magnitude is M, we can write the equation for the true distance as:
m - 1 - M = 5 × log10(d\(_{true}\)/10)
Similarly, for the estimated distance, we have:
m - M = 5 × log10(d\(_{estimated}\)/10)
We can rearrange both equations to isolate the distance:
d\(_{true}\) = \(10^{((m - 1 - M) / 5 + 1)}\)
d\(_{estimated}\) = \(10^{((m - M) / 5)}\)
To calculate how much we will overestimate the distance, we can find the ratio of the to the true distance:
Overestimated distance ratio = d\(_{estimated}\) / d\(_{true}\)
Overestimated distance ratio = \(10^{((m - M) / 5)}\) / 10^\(10^{((m - 1 - M) / 5 + 1)}\)
Simplifying the expression: Overestimated distance ratio = \(10^{((m - M)}\) / 5) / \(10^{((m - 1 - M) / 5)}\) * \(10^{(-1/5)}\)
Overestimated distance ratio = 10\(^{((m - M - m + 1 + M) / 5)}\) * 10\(^{(-1/5)}\)
Overestimated distance ratio = 10\(^{(1/5)}\) * 10\(^{(-1/5)}\)
Overestimated distance ratio = 10\(^{(1/5 - 1/5)}\)
Overestimated distance ratio = \(10^{0}\)
Overestimated distance ratio = 1
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Write out the isotropic form of Hooke’s law relating stress to strain using ij notation and in matric form (i.e. write out the terms). What are the elastic constants in the equation? Do they have a physical meaning and if so what is it?
The isotropic form of Hooke's law relating stress to strain in ij notation and matrix form is:
σ_ij = C_ijkl * ε_kl
Hooke's law is a fundamental concept in solid mechanics that describes the linear relationship between stress and strain in an elastic material. In the isotropic form, stress (σ) and strain (ε) are represented using tensor notation, where the subscripts i and j denote the components of stress or strain along different directions.
The equation is given as σ_ij = C_ijkl * ε_kl, where C_ijkl represents the elastic constants or stiffness coefficients. In this notation, the indices i, j, k, and l can take values from 1 to 3, representing the three spatial dimensions.
The elastic constants C_ijkl represent the material's response to applied stress and provide information about its mechanical properties. These constants define the material's stiffness and determine how it deforms under stress. The specific values of the elastic constants depend on the material being considered.
The elastic constants have physical meanings related to the material's properties. For example, the elastic constant C_1111 represents the material's Young's modulus, which measures its resistance to linear deformation. The constants C_1212 and C_1122 represent the shear modulus, reflecting the material's resistance to shear deformation.
Understanding the values and physical meanings of the elastic constants is crucial in characterizing the behavior of materials under stress. By determining the elastic constants experimentally or through theoretical modeling, engineers and scientists can predict and analyze the material's response to applied forces and design structures accordingly.
Hooke's law and the elastic constants play a vital role in various fields such as materials science, civil engineering, and mechanical engineering. By studying the relationship between stress and strain, researchers can analyze the behavior of materials under different loading conditions and make informed decisions about material selection, structural design, and performance optimization. The elastic constants provide essential information about the mechanical properties of materials, enabling the development of reliable and efficient structures and systems.
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6. A balloon gathers -0.973 μC of charge as the wind blows it directly East through
Earth's magnetic field (BE = 5.01 x 10-5 T). If the magnetic force on the balloon is
8.11 x 10-10 N West.
what is the
velocity of the balloon?
a.-16.6 m/s
c. 8.44 m/s
b. 3.95 x 10-20 m/s
d. 16.6 m/s
Answer:
Explanation:
To determine the velocity of the balloon, we can use the formula for the magnetic force on a charged particle moving in a magnetic field:
F = qvB
Where:
F is the magnetic force,
q is the charge,
v is the velocity of the balloon, and
B is the magnetic field strength.
Given:
F = -8.11 x 10^-10 N (West)
q = -0.973 μC = -0.973 x 10^-6 C (the negative sign indicates the charge is negative)
B = 5.01 x 10^-5 T
We can rearrange the formula to solve for v:
v = F / (qB)
Substituting the given values:
v = (-8.11 x 10^-10 N) / (-0.973 x 10^-6 C * 5.01 x 10^-5 T)
v ≈ 16.6 m/s
Therefore, the velocity of the balloon is approximately 16.6 m/s. Option (d) is the correct answer.
Explain one way in which friction actually helps people
Answer:
Friction creates warmth
What is the science behind Infrared thermometer ?
Answer:
Infrared thermometers employ a lens to focus the infrared light emitting from the object onto a detector known as a thermopile. The thermopile is nothing but thermocouples connected in series or parallel. When the infrared radiation falls on the thermopile surface, it gets absorbed and converts into heat.
A quantity of helium gas at room temperature is placed in a cylinder with a moveable piston. If the cylinder is locked in place so that the volume cannot change and a quantity of heat Q0Q0 is added to the gas, the temperature of the gas increases by ΔT0ΔT0. Now the gas is cooled to its original temperature and the piston is unlocked so that the gas is free to expand. If the pressure exerted on the gas by the piston is held constant and the same quantity of heat Q0Q0 is added to the gas, what will be the temperature change of the gas?
The temperature change of the gas when the pressure exerted on the gas by the piston is held constant and the same quantity of heat Q0 is added to the gas will be less than ΔT0.Suppose the volume of the cylinder remains constant, the system will be isolated from the surrounding, no work will be done on the piston. Therefore, according to the first law of thermodynamics:ΔE = Q0 + W= Q0.
Where W is the work done, ΔE is the change in internal energy. For an ideal gas, the internal energy is given by U = 3/2 nRT, where R is the gas constant. Therefore, the change in internal energy for a given amount of gas will be given byΔE = 3/2 nRΔT0By the principle of conservation of energy, the heat given to the gas when it expands will be equal to the change in internal energy.
If the gas expands to a volume V1, then the new internal energy will be given byU1 = 3/2 nRT1where T1 is the new temperature of the gas. Therefore, the increase in internal energy when the gas expands will be given byΔE1 = 3/2 nR(T1 - T0)Equating the change in internal energy when the gas expands to the heat added we getQ0 = 3/2 nRΔT1.
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Explain why the power of a train's engine must be increased to maintain the speed while travelling up a slope
Answer:
the power (outside) of the train must be increased for the increase in resistance by the weight component.
Explanation:
We analyze the movement of the train at constant speed, on flat ground the force of the motor must counteract the friction force that opposes the movement, therefore to maintain the constant speed the two forces must be of the same magnitude.
When the train goes up a slope, it is subjected to two forces: the friction force that opposes the movement and a component of the weight in the opposite direction to the movement, therefore the power (outside) of the train must be increased for the increase in resistance by the weight component.
How many amperes of current will flow through a circuit that has 4.0 ohms of resistance and js powers by a 16 volt battery
The current flowing in the circuit is 4 A.
What is the current flowing in the circuit?
The current flowing in the circuit is the rate of flow of charges per second.
The magnitude of the current flowing in the circuit can be calculated by applying Ohm's law as shown below.
V = IR
where;
I is the current flowing in the circuitR is the resistance of the circuitThe magnitude of the current is calculated as;
I = V/ R
I = 16 V / 4 ohms
I = 4 A
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If the surface of a moon is impacted by meteorites at a constant rate, the density, or quantity per unit of area, of impact craters on the moon’s surface will increase over time. How can this information be used to determine the relative age of a moon’s surface?.
The number of impact craters on a moon's surface can be used to determine the relative age of that surface. This is because the rate at which impact craters are formed is roughly constant over time. Therefore, the more impact craters a surface has, the older it is.
To determine the relative age of a moon's surface, scientists can compare the number of impact craters on that surface to the number of impact craters on other surfaces of known age. For example, the Moon's surface is covered in impact craters, and the oldest parts of the Moon's surface have the most impact craters. The youngest parts of the Moon's surface have the fewest impact craters.
Scientists can also use the size of impact craters to determine the relative age of a moon's surface. Larger impact craters are formed by more energetic impacts, and these impacts are less frequent than smaller impacts. Therefore, older surfaces are more likely to have larger impact craters.
The relative age of a moon's surface can also be determined by studying the composition of the surface material. Older surfaces are more likely to be covered in material that has been modified by the impacts of meteorites. This material is often more heavily cratered and has a different composition than the material on younger surfaces.
By combining all of these methods, scientists can get a good estimate of the relative age of a moon's surface. This information can be used to study the history of the moon and to understand the processes that have shaped its surface.
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derive the first equation of motion by graphical representation
the first equation of motion, is determined as v = u + at.
What is the first equation of motion?The derivation of the first equation of motion by graphical representation is determined as follows;
Consider the diagram in the image attached;
Let, OE = time (t)
From the graph:
BE = AB + AE
v = DC + OD (QAB = DC and AE = OD)
v = DC + v [QOD = u]
v = DC + v -------(1)
Now, Acceleration, a= Change in Velocity/ Time taken
a = (v – u)/ t
a = (OC – OD)/ t = DC/ t
at = DC --------(2)
By substituting the value of DC from (2) in (1):
We get:
v = at + u
v = u + at
Thus, the first equation of motion, is the relationship between the final velocity, initial velocity, acceleration and time of motion.
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When a boxer is moving away from a punch, the force experienced is reduced because______
When a boxer is moving away from a punch, the force experienced is reduced because C) increased.
What is force of impact of collision?The force created when things collide is known as the force of impact. The impact or hitting power of your vehicle increases as you increase your speed. The force of impact rises with the square of the increase in speed, according to the rules of physics.
When you throw a punch, you'll apply force to the target by using the momentum that was built during the action and the addition of the snap. This results in impulse (force x time). You may transfer a lot of impulse to the target area and build momentum if you do so.
Therefore, option C is correct.
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missing options
A) no different, but the timing is different
B) decreased
C) increased
D) all of the above
If the wavelength is 7.52m and the speed is 8.99m/s for a series of waves, what is the frequency of the waves?
Answer: 1.195479Hz
I think
A charge of 3.877 nC is moved from a position on the y axis of 8.856 cm to a position on the x axis of 1.619 cm while there is a charge 21.524 nC located at the origin. How much work in micro-Joules did it take to move the charge?
Answer:
sa64
Explanation:
1. The first thing to do in the event of brake failure is to a. use the parking brake to stop your carb. pump the brake pedal rapidlyc. shift to a lower geard. steer against the curb 2. Engine failure can be caused by a. a broken timing gearb. a lack of fuelc. extreme heatd. all of the above 3. If your engine stalls a. your power brakes won't work at allb. your power steering won't work at allc. your power brakes and power steering won't work very welld. you should pump your power brakes 4. If your engine is flooded, you will probably a. smell gasolineb. see steam coming out from under the hoodc. have your engine stall after going through a large puddle of waterd. all of the above 5. The most common kind of steering failure is a. total system failureb. power-assist failurec. both a
Answer:
The correct answers are -
1. b. pump the brake pedal rapidly
2. d. all of the above
3. c. your power brakes and power steering won't work very well
4. a. gasoline
5. b. power-assist failure
Explanation:
Brakes help in stopping the vehicle by causing resistance to wheels. IF brake failure it is advised to pump the breaks rapidly in order to cause resistance. Engine failure can be caused by various reasons such as a broken timing gear, no fuel, or getting extremely heated.
In the case of stalling of engine most common effects as power steering not working properly or power brakes not working well. The flooded engine means the engine has too much gasoline that it wont starts.
Un móvil viaja inicialmente con una velocidad de 55 m/s, al cabo de cierto tiempo, su velocidad es de 115 m/s, de repente frena bruscamente con una desaceleración de 14, 500 m/s2. ¿qué distancia recorrerá antes de frenar?
Answer:
Distancia, S = 2.84 metros
Explanation:
Dados los siguientes datos;
Velocidad inicial = 55 m/s
Velocidad final = 115 m/s
Deceleración = 14500 m/s²
Para encontrar qué tan lejos viajaría el automóvil, usaríamos la tercera ecuación de movimiento;
V² = U² + 2aS
115² = 55² + 2*14500*S
13225 = 3025 + 29000S
29000S = 13225 - 3025
29000S = 10200
S = 29000/10200
Distancia, S = 2.84 metros
A 2200 kg car traveling at 25 m / s [S] stops in 10 s.
Determine:
the acceleration of the car;
the net force required to produce this acceleration.
Answer:
\(-2.5\ \text{m/s}^2\)
\(-5500\ \text{N}\)
Explanation:
m = Mass of car = 2200 kg
t = Time = 10 s
v = Final velocity = 0
u = Initial velocity = 25 m/s
a = Acceleration
From the kinematic equations of linear motion we have
\(v=u+at\\\Rightarrow a=\dfrac{v-u}{t}\\\Rightarrow a=\dfrac{0-25}{10}\\\Rightarrow a=-2.5\ \text{m/s}^2\)
Acceleration of the car is \(-2.5\ \text{m/s}^2\)
Force is given by
\(F=ma\\\Rightarrow F=2200\times (-2.5)\\\Rightarrow F=-5500\ \text{N}\)
Net force required to produce the acceleration is \(-5500\ \text{N}\).
state the work-energy theorem
We could derive this , as ;
Consider a body of mass m being pushed by a force F acting along the horizontal , due to which it is displaced s m away . Since the angle between the force and the displacement is 0° , work done will be ,\(\sf \longrightarrow Work = F s cos\theta \\ \)
\(\sf \longrightarrow Work = (ma)(s)(cos0^o)\\\)
\(\sf \longrightarrow\pink{ Work = m \ a \ s } \dots (i)\)
Now let's use the third equation of motion namely,\(\sf \longrightarrow 2as = v^2 -u^2\)
where the symbols have their usual meaning.
\(\sf \longrightarrow as =\dfrac{1}{2}(v - u)^2\\ \)
Multiplying both sides by m,
\(\sf \longrightarrow mas = \dfrac{m}{2}(v-u)^2 \)
Now from equation (i),
\(\sf \longrightarrow Work = \underbrace{\dfrac{1}{2}mv^2-\dfrac{1}{2}mu^2} \)
Above term on RHS is change in the Kinetic energy , therefore ,
\(\sf \longrightarrow \underline{\boxed{\bf Work = \Delta Energy_{(Kinetic)} }}\)
Twins Bo and Joe have a combined mass of 200 kg and are zooming along at 10 m/s in a 100 kg amusement park bumper car. They bump into Melinda’s car, which is sitting still. Melinda has a mass of 25 kg and is also in a 100 kg car. After the collision, the twins continue moving with a speed of 4.12 m/s.
a. What is the initial momentum of the system?
b. What must be the final momentum of the system?
c. How fast is Melinda’s car bumped across the floor?
The speed with which Melinda’s car is bumped across the floor is 14 ms-1.
Total mass of the twins and the car = 300 Kg
Initial velocity of the twins car = 10 m/s
Total mass of Melinda and her car = 125 Kg
Initial velocity of Melinda's car = 0 m/s (at rest)
Final velocity of the twins car = 4.12 m/s
Final velocity of Melinda's car = ?
Initial momentum of the system = (300 × 10) + (125 × 0) = 3000 Kgms-1
Final momentum of the system = (300 × 4.12) + (125 × x) = (1236 + 125x) Kgms-1
Using the principle of conservation of linear momentum;
Total momentum before collision = Total momentum after collision
m1u1 + m2u2 = m2v1 + m2v2
(300 × 10) + (125 × 0) = (300 × 4.12) + (125 × x)
3000 = 1236 + 125x
x = 3000 - 1236 /125
x = 14 ms-1
The speed with which Melinda’s car is bumped across the floor is 14 ms-1.
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Which of the five criteria that define minerals explains why polymorphs are actually different minerals?
what would happen in your previous experiments if the wall or building were not perpendicular to the ground? what uncertainty is introduced into the experiment by using a tape measure to measure the sides of the triangle? to what degree of accuracy can you read a protractor?
If the wall or building were not perpendicular to the ground, it would introduce errors in the measurements and calculations, while using a tape measure introduces uncertainty, and the accuracy of reading a protractor depends on the specific protractor and the observer's skill.
If the wall or building were not perpendicular to the ground, it would affect the accuracy of the measurements and calculations in the previous experiments. The angles and distances involved in the calculations would be different, leading to potential errors in the results.
Using a tape measure to measure the sides of the triangle introduces uncertainty due to potential measurement errors, such as parallax or slight stretching of the tape measure. These errors can affect the accuracy of the triangle's side lengths and consequently the calculated values.
The degree of accuracy when reading a protractor depends on the precision of the protractor and the observer's ability. Protractors typically have markings for every degree and sometimes subdivisions for half or quarter degrees. With careful observation and estimation, it is possible to read a protractor to the nearest degree or even estimate angles within a few degrees of accuracy. However, the exact degree of accuracy would depend on the specific protractor and the skill of the person using it.
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I need help plzz help I’ll mark you brainliest
Answer:
a b c d
Explanation:
Which sound wave would travel at the fastest speed?.
A sound wave with a higher frequency and a shorter wavelength would have a faster speed.
The sound wave that would travel at the fastest speed is a sound wave with a higher frequency and a shorter wavelength.
This is because the speed of sound in air is directly proportional to the frequency and inversely proportional to the wavelength.
Therefore, a sound wave with a high frequency and a short wavelength would travel at the fastest speed.
This is because the sound wave's frequency will determine how fast the wave's particles vibrate, while the wavelength will determine the distance between the wave's particles.
In summary, the speed of a sound wave is given by the equation:
speed = frequency x wavelength
So, a sound wave with a higher frequency and a shorter wavelength would have a faster speed.
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During a collision with another car, the occupants of a minivan initially travelling at 4.0 m/s come to a complete stop in 0.5 s. What was the acceleration of the occupants of the minivan?
a) 8.0 m/s2
b) –8.0 m/s2
c) 2.0 m/s2
d) –2.0 m/s2
Answer: b) - 8.0 \(m/s^{2}\)
Explanation: Acceleration is a vector indicating a rate an object's velocity changes over time:
a = \(\frac{v}{t}\)
and its SI unit is \(m/s^{2}\)
For the minivan to stop, it takes a period of 0.5s:
a = \(\frac{4.0}{0.5}\)
a = 8.0 \(m/s^{2}\)
As a vector, acceleration has magnitude (8\(m/s^{2}\)) and direction. Since it is stopping, the minivan has a direction opposite to the other car, which means acceleration is negative. So: a = \(- 8.0 m/s^{2}\).
2. Grace drives her car 40 km in 75 minutes. What is her average speed in
kilometers per hour?
Answer:
k
Explanation:
k
Is a shadow a real or a virtual image? Thank you!
Answer:
Virtual image..................
A 57 kg pole vaulter running at 11 m/s vaults over the bar. Her speed when she is above the bar is 1.1 m/s. The acceleration of gravity is 9.8 m/s 2 . Find her altitude as she crosses the bar. Neglect air resistance, as well as any energy absorbed by the pole. Answer in units of m.
Answer:
Her altitude as she crosses the bar, h₂ is approximately 6.1 m
Explanation:
The given parameters of the motion of the pole vaulter are;
The mass of the pole vaulter, m = 57 kg
The speed with which the pole vaulter is running, u = 11 m/s
The speed of the pole vaulter when she crosses the bar, v = 1.1 m/s
The acceleration due to gravity, g = 9.8 m/s²
From the total mechanical energy, M.E. equation, we have;
M.E. = P.E. + K.E.
Where;
P.E. = The potential energy of the motion = m·g·h
K.E. = The kinetic energy of the motion = 1/2·m·v²
By the principle of conservation of energy, we have;
The change (loss) in kinetic energy, ΔK.E. = The change (gain) in potential energy, ΔP.E.
ΔK.E. = 1/2·m·(v² - u²)
ΔP.E. = m·g·(h₂ - h₁)
Where;
h₁ = The ground level = 0 m
h₂ = The altitude with which she crosses the bar
∴ 1/2·m·(v² - u²) = m·g·(h₂ - h₁)
(h₂ - h₁) = (v² - u²)/(2·g) = (11² - 1.1²)/(2·9.8) = 6.11173469388
h₂ = 6.11173469388 + h₁ = 6.11173469388 + 0 = 6.11173469388
h₂ = 6.11173469388
Her altitude as she crosses over the bar, h₂ ≈ 6.1 m.
differentiate between loadstone and bar magnet
what is the difference between passive and active solar heating
Passive solar heating utilizes design and natural processes to capture and distribute solar energy without mechanical devices, while active solar heating uses mechanical systems to collect and distribute solar heat, requiring external energy inputs.
Passive solar heating and active solar heating are two different approaches to utilizing solar energy for heating purposes. Here's a brief explanation of each:
1. Passive Solar Heating:
Passive solar heating refers to the design and use of building materials to capture, store, and distribute solar energy without the use of mechanical or electrical devices. It relies on natural processes and elements to maximize solar gain and heat transfer. Some common passive solar heating techniques include:
Orienting buildings to maximize exposure to the sun's rays.Incorporating large south-facing windows to allow sunlight into the building.Utilizing thermal mass materials, such as concrete or brick, to absorb and store heat during the day and release it gradually at night.Using natural ventilation and shading techniques to control heat gain and loss.Passive solar heating systems do not require active mechanical components like pumps or fans and are generally considered more energy-efficient and cost-effective.
2. Active Solar Heating:
Active solar heating involves the use of mechanical and electrical devices to collect, store, and distribute solar energy for heating purposes. It typically utilizes solar collectors, such as solar panels or solar thermal systems, to capture sunlight and convert it into heat energy. The collected heat is then transferred to a heat storage system or directly used to provide space heating or water heating. Active solar heating systems may involve pumps, fans, and controls to circulate the heated fluid or air throughout the building.
Active solar heating systems require external energy inputs, such as electricity for powering pumps or fans, and often involve more complex installation and maintenance compared to passive solar heating. However, they can offer greater control and efficiency in heating applications, especially in larger or more demanding spaces.
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WILL GIVE BRAINLY TO CORRECT ANSWER
the second and third one
if you can answer all of these questions, you are a genius.
1. What is matter made of?
2. Define matter.
3. Give 3 examples of things that are made of matter.
4. What is the difference between solid, liquid, and gas?
5. What is a chemical reaction?
6. Explain the difference between the reactants and products.
7. Do you have any plans for Halloween and the break?
Answer:
1.matter made of mass and volume
2.matter is any substance that has mass and takes up a space by having a volume
3.table, coffee, and perfume
4.solid has a strong bonds, liquid has weak bond, and gas no bond
5
a 1300-kg cannon suddenly fires a cannonball at what is the recoil speed of the cannon? assume that frictional forces are negligible and the cannon is fired horizontally.
The recoil speed of the cannon after firing the cannonball is 0.0061 m/s.
What is the frictional forces?To determine the recoil speed of the cannon, we can use the principle of conservation of momentum. According to this principle, the total momentum before the firing must be equal to the total momentum after the firing.
Given that the cannonball is fired horizontally, the vertical components of momentum are negligible. Therefore, we only need to consider the horizontal momentum.
The initial momentum of the system (cannon and cannonball) is zero since both are at rest. After the cannonball is fired, it gains momentum in one direction, causing the cannon to recoil in the opposite direction.
The magnitude of the momentum gained by the cannonball is given by:
momentum of cannonball = mass of cannonball × velocity of cannonball
Since the cannonball is not provided in the question, we cannot calculate this value directly. However, we can determine the recoil speed of the cannon using the mass of the cannonball.
By setting the momentum gained by the cannonball equal to the recoil momentum of the cannon, we can solve for the recoil velocity of the cannon.
Recoil momentum of the cannon = momentum of cannonball
recoil velocity of the cannon × mass of the cannon = mass of cannonball × velocity of cannonball
recoil velocity of the cannon = (mass of cannonball × velocity of cannonball) / mass of the cannon
Plugging in the given values, assuming the mass of the cannonball is 1 kg and the velocity of the cannonball is 200 m/s, and the mass of the cannon is 1300 kg:
recoil velocity of the cannon = (1 kg × 200 m/s) / 1300 kg
recoil velocity of the cannon ≈ 0.0061 m/s
Therefore, the recoil speed of the cannon after firing the cannonball is approximately 0.0061 m/s.
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