If I clapped someone 11 - 0 in a Rocket League match (which I did), and the matches are 5 minutes long (which they are), what is the average time that it took me to score 1 goal against the kid who got clapped by me.

Explanation:

The data from the stem-and-leaf plot is:

10,

24,25,26,

30,30,32,33,

40,45,46

Add up those values

10+24+25+26+30+30+32+33+40+45+46 = 341

Then divide over n = 11 which is the sample size.

341/11 = 31 is the arithmetic mean.

Answer:

341/11 = 31 is the arithmetic mean.

Step-by-step explanation:

Split up the interval [0, 2] into n equally spaced subintervals:

\(\left[0,\dfrac2n\right],\left[\dfrac2n,\dfrac4n\right],\left[\dfrac4n,\dfrac6n\right],\ldots,\left[\dfrac{2(n-1)}n,2\right]\)

Let's use the right endpoints as our sampling points; they are given by the arithmetic sequence,

\(r_i=\dfrac{2i}n\)

where \(1\le i\le n\). Each interval has length \(\Delta x_i=\frac{2-0}n=\frac2n\).

At these sampling points, the function takes on values of

\(f(r_i)=7{r_i}^3=7\left(\dfrac{2i}n\right)^3=\dfrac{56i^3}{n^3}\)

We approximate the integral with the Riemann sum:

\(\displaystyle\sum_{i=1}^nf(r_i)\Delta x_i=\frac{112}n\sum_{i=1}^ni^3\)

Recall that

\(\displaystyle\sum_{i=1}^ni^3=\frac{n^2(n+1)^2}4\)

so that the sum reduces to

\(\displaystyle\sum_{i=1}^nf(r_i)\Delta x_i=\frac{28n^2(n+1)^2}{n^4}\)

Take the limit as n approaches infinity, and the Riemann sum converges to the value of the integral:

\(\displaystyle\int_0^27x^3\,\mathrm dx=\lim_{n\to\infty}\frac{28n^2(n+1)^2}{n^4}=\boxed{28}\)

Just to check:

\(\displaystyle\int_0^27x^3\,\mathrm dx=\frac{7x^4}4\bigg|_0^2=\frac{7\cdot2^4}4=28\)

Step-by-step explanation:

I got C

Answer:

A) 0

Step-by-step explanation:

If the line keeps going it will never hit y

Answer:

-5

-3

-2

0

1

Step-by-step explanation:

just put the number they give you for x and solve and the answer you get is the answer for y

Answer:

Step-by-step explanation:

Given the slope-intercept form:\(y=\frac{1}{3}x-2\)

Slope-intercept form: \(y=mx+b\)

We substitute our x-values (-9, -3, 0, 6, and 9) for x in \(y=\frac{1}{3}x-2\) to find the y-values.

For -9:

\(y=\frac{1}{3}x-2 < ==substitute\ -9\ for\ x\\\\y=\frac{1}{3}(-9)-2\\\\y=\frac{-9}{3}-2 < ==divide\ (don't\ forget\ the\ signs)\\\\y=-3-2 < ==add\ or\ subtract\\\\y=-5 < =value\ of\ y\\\\(-9,-5)\)

For -3:

\(y=\frac{1}{3}x-2 < ==substitute\ -3\ for\ x\\\\y=\frac{1}{3}(-3)-2\\\\y=\frac{-3}{3}-2 < ==divide\ (don't\ forget\ the\ signs)\\\\y=-1-2 < ==add\ or\ subtract\\\\y=-3 < =value\ of\ y\\\\(-3,-3)\)

For 0:

\(y=\frac{1}{3}x-2 < ==substitute\ 0\ for\ x\\\\y=\frac{1}{3}(0)-2 < ==any\ number\ multiplied\ by\ 0\ equals\ zero\\\\y=\frac{0}{3}-2 < ==divide\ (don't\ forget\ the\ signs)-zero\ divided\ by\ any\ \#\ equals\ 0\\\\y=0-2 < ==add\ or\ subtract\\\\y=-2 < =value\ of\ y\\\\(0,-2)\)

For 6:

\(y=\frac{1}{3}x-2 < ==substitute\ 6\ for\ x\\\\y=\frac{1}{3}(6)-2\\\\y=\frac{6}{3}-2 < ==divide\ (don't\ forget\ the\ signs)\\\\y=2-2 < ==add\ or\ subtract\\\\y=0 < =value\ of\ y\\\\(6,0)\)

For 9:

\(y=\frac{1}{3}x-2 < ==substitute\ 9\ for\ x\\\\y=\frac{1}{3}(9)-2\\\\y=\frac{9}{3}-2 < ==divide\ (don't\ forget\ the\ signs)\\\\y=3-2 < ==add\ or\ subtract\\\\y=1 < =value\ of\ y\\\\(9,1)\)

*View the attached graph to verify these answers*

Hope this helps!

Answer:

!. -15 i think im not sure

2. 39

Step-by-step explanation:

Answer:

75 hairs/ day =  525 hairs / week

Step-by-step explanation:

so your base question for this is 75 hairs/ day =? h/ week. how? if the dog is losing 75 hairs per day, then you would do 75 x 7 becuase there are 7 days in a week. the answer to that would give you how many hairs the dog was losing per week. (see attached image for reference)

Hope this helps!

#MRS

Explanation:

C. Perimeter of Trapezium

= sum of all sides

=  8 + 4 + 4 + 6

= 22

D. Area of Trapezium

= 1/2 × (a + b) × height

= 1/2 × (8 + 6) × √15

= 7√15

E. Perimeter of square

= 4(side)

= 4(5)

= 20

F. Area of square

= side × side

= 5 × 5

= 25

I. Answer

The area will be 4 times more than the current area of about 64 units².

side² = 16

side = √16

side = 4

If the side is doubled, new side = 4 × 2 = 8

New Area: 8² = 64 units²

We can conclude that exists 211680 ways.

We know that the three research department is have 8, 10, and 7 members.

We choose a delegate and an alternate to represent the department.

First case: department have 8 members.

So, for a delegate, we have 8 options, and for a alternate 7, so a total of

\(8 \times 7 = 56 \ \text{options}\)

Second case: department have 10 members.

So, for a delegate, we have 10 options, and for a alternate 9, so a total of

\(10\times 9 =90 \ \text{options}\)

Third case: department have 7 members.

So, for a delegate, we have 7 options, and for a alternate 6, so a total of

\(7\times6 = 42 \ \text{options}\)

Therefore, we get:

\(56 \times 90 \times 42 = \bold{211680}\)

Hence, we conclude that exists 211680 ways.

For a similar problem about this, please click the link below:

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Answer:

16 cookies are left.

Step-by-step explanation

2/3 of 48 is 32

48-32=16

Answer: the speed of the current is 5 miles an hour

Step-by-step explanation:

9-4=5

Answer:

91ft^2

Step-by-step explanation:

A = w*l

first, solve for the bottom rectangle

w = 7ft

l = 8ft

7ft * 8ft = 56ft^2

then for the second rectangle

l = 5ft

w = 7ft

5ft*7ft = 35ft^2

total area = rectangle 1+2

so 35ft^2+56ft^2=91ft^2

Answer:

The answer for the Area of the shape is 91ft²

Step-by-step explanation:

Area of the shape =Area of Bigger rectangle+ Area of small rectangle

A=L×B+l×b

A=7×8+5×7

A=56+35

A=91ft²

Answer:

22.9

Step-by-step explanation:

4.58 drops every 10 minutes

What would happen if it dropped 50 minutes

4.58x5 = 22.9

Answer:

22.9

Step-by-step explanation:

4.58x5 = 22.9

The requried, bat will cost Finley $35.00 on clearance with an additional 30% off discount.

The percentage is the ratio of the composition of matter to the overall composition of matter multiplied by 100.

Here,
The bat is marked down to $50.00, but with an additional 30% off clearance discount, the final price that Finley will pay is,

Final price = $50.00 - (30% of $50.00)

To calculate the discount, we first need to find 30% of $50.00, which is:

0.30 × $50.00 = $15.00

So the discount is $15.00.

Substituting this value into the equation, we get:

Final price = $50.00 - $15.00 = $35.00

Therefore, the bat will cost Finley $35.00 on clearance with an additional 30% off discount.

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An isosceles triangle has 2 sides that are equal.

I plotted these points. See attached screenshot.

The first side's distance is 5. You can just count those units along the x axis. (0,0) and (5,0) share the same y coordinate, so the difference in x coordinates is 5-0 = 5.

The next sides's distance is also 5. You can count that distance on the coordinate plane. (5,5) and (5,0) share the same x coordinate, so the difference in y coordinates is 5-0 = 5.

These two sides make a right triangle and are equal length. This is an isosceles right triangle.

Answer:

35 ig it is correct i tried my best

Step-by-step explanation:

Answer:

scale 1-1in=3ft

scale 2-1in=4ft

Answer:

Step-by-step explanation:

I feel like its C

Answer: The answer is false!

Step-by-step explanation: You may think its true but NO, its not true!

Answer: false

Step-by-step explanation:

the correct answer is a dialect of spanish, chilean spanish.

Answer: A

Step-by-step explanation:

median: 7+7=14

14/2=7✅

mode: 7 shows up the most (twice)

Answer:

the first one is A The second on C the third one D and last one B

Step-by-step explanation:

Answer:

A, C

Step-by-step explanation:

If it is inversely proportional then y = k/x

Let's try one by one for the options. (im replacing y and x in the equation and finding k to see if k is the same all throughout)

A.

6 = k/1 (k=6)

3 = k/2 (k=6)

2 = k/3 (k=6)

1.5 = k/4 (k=6)

Yes! It's the same everywhere so this is correct!

B.

7.5 = k/2 (k=15)

5 = k/3 (k=15)

3 = k/5 (k=15)

2 = k/7 (k=14)

For the last one k is not the same so nope. It is wrong.

C.

24 = k/1 (k=24)

8 = k/3 (k=24)

k = 6×4 = 24

k = 24×1 = 24

This is correct too.

D.

k = 0.1×200 = 20

k = 0.3×40 = 12

k = 0.8 × 25 = 20

We can already see that k is not the same everywhere.

Only A and C, x and y are inversely proportional for all of the values

Answer: c

Step-by-step explanation:

Answer:

The cost is $81.32

Step-by-step explanation:

Answer: $81.32

Step-by-step explanation:

Answer:

Step-by-step explanation:

QUESTION 7:

We are trying to find angles 1 and 2.

Known angle: 107˚.

In this question, we have 2 parallel lines with a transversal. A transversal is a line that passes through 2 parallel lines making it so that the angles on both sides are exactly the same.

Step 1: Find the measures of all the angles using the one we already know.

I will start with the angle adjacent (right next to) the angle that measures 107˚. As you can see, it is a supplementary angle because both of them form a straight line, or 180˚.

Therefore,

107+x= 180

x= 180-107

x= 73˚

Next, I will find the measure of the angle that is vertical to the one that measures 107˚. Note that angles that are vertical to each other are always identical, or in other words they have the same measure. Hence, the angle "vertical", or opposite to the one that measures 107˚ has to measure 107˚ as well.  You can also tell this is true because they look the same.

Now I'll find the measure of the angle vertical to the one that measures 73˚. As we know, vertical angles are identical, so the one vertical to it is 73˚.  

Here, I'll solve for angles 1 and 2. Like I said earlier, when a transversal crosses through 2 parallel lines, there will be 2 sets of angles that all have the same measurements.  

To solve for angle 1, simply know what angle is right below it, and that is the one that measures 107˚. (If you look at the 2 lines, you will see that both angle sets are essentially duplicates of each other.) Likewise, angle 2 has to be 73˚ because the one under it is also 73˚.

Angle 1: 107˚

Angle 2: 73˚

QUESTION 8:

Again, we have a transversal that passes through 2 parallel lines. One angle measures 95˚.  When there are 3 seperate angles along a straight line,  the one next to the one with the given measurement will be the same as that one.

So angle 3 is 95˚. To find angle 4, find the angle measurement that's vertical to angle 3, which is 95˚. Now, since that angle and angle 4 are supplementary (both form a straight line which is always 180˚), 95+x= 180.

(x stands for angle 4)

x+95= 180

x= 180-95

x= 85

Angle 4= 85˚.

QUESTION 9:

ANGLE 5: 49˚

When there is a transversal, there are 2 identical pairs of angles. Therefore, angle 5 must be 49˚.

ANGLE 6: 131˚

angle 5 and angle 6 form a straight line which means they are supplementary angles. Therefore, both angles must add up to 180˚. So 49+x= 180

x= 180-49= 131

(x stands for angle 6)

Hope this helps!! Also I worked pretty hard on this so brainliest would be appreciated :D

Practice problems if it helps :) : https://www.khanacademy.org/math/cc-eighth-grade-math/cc-8th-geometry/cc-8th-angles-between-lines/e/parallel_lines_1

To find when the rocket will be at a certain height, we can set the equation for height, h(t), equal to the given height and solve for t.

For 24 meters:

-9.8t^2 + 36t = 24

-9.8t^2 + 36t - 24 = 0

We can solve for t using the quadratic formula:

t = (-b ± sqrt(b^2 - 4ac)) / 2a

where a = -9.8, b = 36, and c = -24. Plugging in these values, we get:

t = (-36 ± sqrt(36^2 - 4(-9.8)(-24))) / 2(-9.8)

t ≈ 1.87 seconds or t ≈ 3.14 seconds

So the rocket will be at a height of 24 meters approximately 1.87 seconds after launch and again approximately 3.14 seconds after launch.

For 36 meters:

-9.8t^2 + 36t = 36

-9.8t^2 + 36t - 36 = 0

Using the quadratic formula again, we get:

t = (-36 ± sqrt(36^2 - 4(-9.8)(-36))) / 2(-9.8)

t ≈ 1.16 seconds or t ≈ 3.66 seconds

So the rocket will be at a height of 36 meters approximately 1.16 seconds after launch and again approximately 3.66 seconds after launch.

The interest earned is $60 and the balance of the account is $460. The interest and the balance of the account will be both calculated with their given formulas.

An expense or payment for using borrowed money is interest; it is occasionally stated as a percentage of the principal borrowed. It could also be applied to the returns on investments or savings. Interest is the cost that a borrower typically reimburses a lender for the use of their funds.

A. We must use the formula-

Interest = Principal x Rate x Time, to calculate the interest earned.

Here, Interest = $400 divided by 0.03 and multiplied by 5.

Earned interest is $60.

B. We must utilize the formula-

Balance = Principal + Interest, to determine the account's balance.

Balance = $400 + computed interest in this instance.

Balance: $400 + $60.

The account's balance is $460.

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Answer:

          /\

\(\sqrt{20}\) /     \\(\sqrt{20}\)

     /         \

     \         /

\(\sqrt{20}\)  \     / \(\sqrt{20}\)

          \/

Step-by-step explanation:

i hope this is right it took me 30 min for the ascii

Answer:

4(5-3) can be written some ways like this

2*4

(5-3)4

(6-4)*4

x=4*(12-10)

I would solve 4(5-3) using PEMDAS (parentheses, exponents, multiplication, division, addition, subtraction)

4*(5-3)

4*(2)

4*2

8

Step-by-step explanation:

Hope this helps! BH

The ordered pair which is the solution to the linear equations is given by relation S = ( 5 , -2 ) , ( 3 , 1 ) , ( 4 , 2 )

An equation is said to be linear equation in two variables if it is written in the form of ax + by + c=0, where a, b & c are real numbers and the coefficients of x and y, i.e a and b respectively, are not equal to zero.

The linear equations in one variable is an equation which is expressed in the form of ax+b = 0, where a and b are two integers, and x is a variable and has only one solution

On a graph, a linear equation forms a straight line. On a graph, a nonlinear equation produces an S-curve, a bell curve, or another nonlinear shape.

Given data ,

Let the linear function be represented as A

Now , the value of A is

y > -1/2x   be equation (1)

y < 1/2x + 1   be equation (2)

Now , on simplifying , we get

Let the ordered pairs be A ( 5 , -2 ) , B ( 3 , 1 ) and C ( 4 , 2 )

when x = 5 and y = -2

-2 > ( -1/2 )5

-2 > -2.5

And , -2 < ( 1/2 )(5) + 1

-2 < 3.5

Therefore , the inequality is true

when x = 3 and y = 1

1 > ( -1/2 )3

1 > -1.5

And , 1 < ( 1/2 )(3) + 1

1 < 2.5

Therefore , the inequality is true

when x = 4 and y = 2

2 > ( -1/2 ) ( 4 )

2 > -2

And , 2 < ( 1/2 ) ( 4 ) + 1

2 < 3

Therefore , the inequality is true

Hence , the solution to the linear inequality are ( 5 , -2 ) , ( 3 , 1 ) , ( 4 , 2 )

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