if dustin travels 2.42 km clockwise along the ski trail, what is the angle's measure in radians?

The reason why a delivery truck filled with birds sitting on the floor be heavier than a truck with the same birds flying around is because when the birds are sitting on the floor, they are adding their weight to the truck.

Meanwhile, if the birds are flying around they aren't resting on the truck or touching it, so therefore their weight wouldn't be added to the truck.

The mass of the truck will remain the same as you cannot change the mass but the weight will vary depending on the items and objects placed in it.

God created all things in the beginning of time

Explanation:

He said the things he wanted to make an they came into existence.

Im christian so if u dont like the answer or get mad i'm sorry i couldnt help you

Answer:

Final velocity = 19 m/s

Explanation:

Initial velocity (u) = 4 m/s

Acceleration (a) = 0.5 m/s²

Time (t) = 30 s

Final velocity (v) = ?

In this question, you must use the formula:

v = u + at

Substitute the values into the formula.

v = 4 + (0.5 × 30)

v = 4 + 15

v = 19 m/s

1. With N = Newtons, m = meters, we have

\(F = -kx \iff \mathrm N = -k (\mathrm m) \implies k = \dfrac{\rm N}{\rm m}\)

N itself can be broken down according to Newton's second law,

\(F=ma \iff \mathrm N = \mathrm{kg} \, \dfrac{\rm m}{\rm s^2}\)

so the dimension of the force \(F\) is

\([F] = [M\cdot L\cdot T^{-2}]\)

(where M = mass, L = length, T = time) and hence the dimension of \(k\) is

\([k] = \left[\dfrac{M\cdot L\cdot T^{-2}}{L}\right] = \boxed{[M\cdot T^{-2}]}\)

2.

a. With N = Newtons, A = amperes, and m = meters,

\(F = \dfrac{k I_1 I_2}d \iff \mathrm N = \dfrac{k \,\mathrm A\,\mathrm A}{\rm m} \implies k = \boxed{\dfrac{\rm Nm}{\rm A^2}}\)

b. The dimension of \(k\) is

\([k] = \left[\dfrac{(M\cdot L\cdot T^{-2})\cdot L}{I^2}\right] = \boxed{[M\cdotL^2\cdot T^{-2}\cdot I^{-2}]}\)

(where I = current, with "I" as in capital i)

Answer: As the variable resistance increases its resistance, the current which flow through the lamp will decrease and therefore its brightness decreases. ... If the resistors are very large, they have no impact and the lamps will be the same brightness.

Explanation:

Answer:

The intensity or brightness of the bulb increases as more dry cell is added in the circuit.

Explanation:

Hope it helps :)

Answer:

100mm²

Explanation:

the other side: (50 - 20 × 2) ÷ 2 = 5

5 × 20 = 100

Answer:

Subtract given lengths: 50 - 20 = 30

Divide by 2 since there are 2 missing sides that need a length: 30 divided by 2 = 15

With the given side lengths multiply all of them to get your area.

15 x 20 = 300 is your area I am pretty sure.

1. The energy required is 513 kJ to boil 0.60kg of ethanol.

2. The density of gold is  19,300 kg/\(m^3\) if it has a volume of 2.00 x \(10^-^5\)\(m^3\) and a mass of 0.386kh.

Question 1: The energy required to boil a substance can be calculated by multiplying the mass of the substance by its specific latent heat of evaporation. In this case, the specific latent heat of evaporation for ethanol is given as 855 kJ/kg, and the mass of ethanol to be boiled is 0.60 kg.

Energy required = Mass × Specific latent heat of evaporation

Energy required = 0.60 kg × 855 kJ/kg

Energy required = 513 kJ

Therefore, the energy required to boil 0.60 kg of ethanol is 513 kJ.

Question 2: The density of a substance is calculated by dividing its mass by its volume. In this case, the volume of the gold is given as 2.00 x\(10^-^5\) \(m^3\) and the mass of the gold is 0.386 kg.

Density = Mass / Volume

Density = 0.386 kg / 2.00 x \(10^-^5\) \(m^3\)

Density = 19300 kg/\(m^3\)

Therefore, the density of gold is 19300 kg/\(m^3\).

In summary, the energy required to boil 0.60 kg of ethanol is 513 kJ, and the density of gold is 19300 kg/m^3.

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The power, the resistor and time is I²₀R e-2Rt/L and - I₀²R  e-2Rt/L .

Work rate or energy delivery time is expressed as W/t, where W is the quantity of work completed or energy delivered, and t is the time interval.

A passive electrical device with two terminals that controls or limits the flow of electricity across electrical circuits. The main function of a resistor is to lower the voltage and reduce the current flow in a specific area of the circuit.

a) L di/dt + iR = 0 -Rt/L

= I = I₀ e

At t=0.  I = I₀

= Pr = I²R = I₀ R e = -2Rt/t

= Pr (t) = I²₀R e-2Rt/L

b) Energy of inductor = 1/2 L I²

= 1/2 L I₀²    e-2Rt/L

Power, Pl (t) = dE/dt

= d/dt (1/2 LI₀² e-2Rt/L)

= 1/2 t I₀² ( e-2Rt/L) e-2Rt/L

Pl (t) = - I₀²R  e-2Rt/L

Therefore, the power, the resistor and time is I²₀R e-2Rt/L and - I₀²R  e-2Rt/L .

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The projectile launch allows to find the results for questions about the movement are:

   a) The initial velocity is: vo = 20 m/s with an angle of θ = 51.4º

   b) The maximum height of the ball is:  y = 12.5 m

   c) The final velocity is: vo = 20 m/s with θ = 308.3º

The launch of projectiles is an application of kinematics where there is no acceleration on the x axis and the y axis is the gravity acceleration.

In the attachment we see a diagram of movement, the x-axis is horizontal and the y-axis is vertical.

They indicate that the range was x = 40 m and the ball was in the air t=3.2s.

a) Let's find the horizontal velocity, as there is no acceleration.

         x = v₀ₓ t

         v₀ₓ = \(\frac{x}{t}\)x / t

let's calculate

         v₀ₓ = \(\frac{40}{3.2}\)  

         v₀ₓ = 12.5 m / s

We look for the vertical speed, when the ball reaches the destination its height is zero.

          y = \(v_o_y\) t - ½ g t²

          0 = \(v_o_y\) t - ½ g t²

          0 = t ( \(v_o_y\) - ½ g t)

The solution to this equation is:

           t = 0 s         Exit time.

           \(v_o_y\) - ½ g t = 0

           \(v_o_y\)  = ½ g t

It indicates the time in the air that, because it is a scalar, is the same for the two movements.

Let's calculate

           \(v_o_y\)  = ½ 9.8 3.2

            \(v_o_y\)  = 15.68 m / s

We use the Pythagoras' theorem for the initial velocity modulus.

          v₀ = \(\sqrt{v_{ox}^2 + v_{oy}^2 }\)  

          v₀ = \(\sqrt{12.5^2 + 15.68^2}\)  

          v₀ = 20 m / s

We use trigonometry for the angle.

        tan θ = \(\frac{v_o_y}{v_o_x}\)  

        θ = tam⁻¹ \(\frac{v_o_y}{v_o_x}\)  

        θ = tan⁻¹  \(\frac{15.68}{12.5}\)  

        θ = 51.4º

b) For the maximum height the vertical speed is zero.

           \(v_y^2 = v_{oy}^2 -2g y\)  

           0 = \(0 = v_{oy}^2 -2 g y\)  

           y = \(\frac{v_{oy}^2}{2g}\)

Let's calculate

           y = \(\frac{15.68^2}{2 \ 9.8}\)

           y = 12.5 m

C) The final velocity of the ball.

Since the x-axis there is no acceleration, the velocity is constant.

          vₓ = 12.5 m / s

Let's find the final vertical speed.

         \(v_y = v_{oy} - g t\)

         \(v_y\) = 15.68 - 9.8 3.2

         \(v_y\) = - 15.68 m / s

We are looking for the module.

         v = vₓ² + \(v_y^2\)  

speed gives the same value.

         v = 20 m / s

We use trigonometry for the angle.

        θ'= tan⁻¹  \(\frac{-15.68}{12.5}\)

        θ' = -51.66º

This angle measured from the positive side of the x-axis counterclockwise is:

       θ = 360 - θ'

       θ = 360 - 51.66

       θ = 308.3º

In conclusion, using the launch of projectiles we can find the results for questions about the movement are:

   a) The initial velocity is: vo = 20 m / s with an angle of θ = 51.4º

   b) The maximum height of the ball is: y = 12.5 m

   c) The final velocity is: vo = 20 / s with θ= 308.3º

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The dielectric constant, εᵣ, of a material is 4.73 x 10². It describes how well the material can store electrical energy and affects its capacitance in an electric field.

The capacitance of a capacitor with concentric conducting spherical shells is given by the formula C = (4πε₀a)/(1/b - 1/a), where a and b are the radii of the inner and outer shells, respectively, and ε₀ is the vacuum permittivity.

Rearranging the formula, we have ε₀ = (1/4πC)(1/a - 1/b).

Given the values of a, b, and C, we can substitute them into the formula and calculate ε₀. Taking the reciprocal of ε₀ gives us the dielectric constant εᵣ.

Using the given values:

ε₀ = (1/4π(5.8 x 10⁻⁶))(1/1.8 - 1/2.5) ≈ 2.54 x 10⁻¹¹ F/m

εᵣ = 1/ε₀ ≈ 4.73 x 10²

Magnitude of free charge q: 8.67 x 10⁻⁴ C.

The capacitance of a capacitor is given by the formula C = q/V, where q is the magnitude of the charge on the plates and V is the potential difference between the terminals.

Rearranging the formula, we have q = CV.

Substituting the given values, we have q = (5.8 x 10⁻⁶ F)(45 V) = 8.67 x 10⁻⁴ C.

Magnitude of induced charge q': 3.48 x 10⁻⁵ C.

The magnitude of the induced charge on the inner surface of the dielectric can be determined using the formula q' = q - CV, where q is the magnitude of the free charge on the plates and C is the capacitance.

Substituting the given values, we have q' = (8.67 x 10⁻⁴ C) - (5.8 x 10⁻⁶ F)(45 V) ≈ 3.48 x 10⁻⁵ C.

Magnitude of electric field at the midpoint: 1.02 x 10⁶ V/m.

The electric field between the plates of a capacitor is given by the formula E = V/d, where V is the potential difference between the plates and d is the distance between the plates.

Since the point is at the midpoint, the distance d is half the distance between the shells.

Substituting the given values, we have E = (45 V)/(0.035 m) = 1.02 x 10⁶ V/m.

Maximum safe voltage: 30.6 MV.

The maximum safe voltage that can be applied across the capacitor before it is ruined is determined by the dielectric strength.

The dielectric strength is given as 6 kV/mm, which is equivalent to 6 x 10⁶ V/m.

Multiplying this value by the thickness of the dielectric layer (b - a = 0.7 m), we have the maximum safe voltage as (6 x 10⁶ V/m)(0.7 m) = 4.2 x 10⁶ V. Converting to megavolts, we get 4.2 MV.

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Eddy believes that aliens make him walk 2 miles every day from his house to the store. this is an example of Hallucinations.

Hallucinations are sensory impressions that come from the mind yet seem realistic. Every one of the five senses may be affected by hallucination. One could, for instance, hear a voice that nobody else in the area can hear or see of a fake image. When someone is hallucinating, they will perceive things in their brains that they believe to be real but are actually not. Only the mind can produce these ideas. These symptoms could be brought on by medical conditions like seizures or alcoholic use problems, drug side effects, or mental diseases. The perception of hearing, smell, touch, vision, or physiological sensations may all be affected by hallucinations. A person may have hallucinations with or without knowledge that they are hallucinations. It is regarded as a psychotic sign when someone believes their delusion to be genuine.

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Answer:

Explanation:

The mass of the object can be found by using the formula

\(m = \frac{2KE}{ {v}^{2} } \\ \)

v is the velocity

KE is the kinetic energy

From the question we have

\(m = \frac{2 \times 100000}{ {20}^{2} } = \frac{200000 }{400} = \frac{2000}{4} \\ \)

We have the final answer as

Hope this helps you

Answer:

A) earth

B) live

C) live

D) earth

Explanation:

hope i help

Answer:

yes it is

Explanation:

Viscosity is the drag force applied by the layer of liquid on a body.

When a liquid settles down it usually forms a layer by layer structure in it.

When another body of any shape goes between these layer a drag force is applied on the body in the direction opposite to the motion of the body. This drag force is what we call the viscosity of the liquid.

The viscosity depends on the compressive and adhesive forces present in the particle of the liquid. It also depends on the density of the liquid.

If the body has higher density than it is expected to have a higher viscosity in it.

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Explanation:

800 km per her because you have to divide 7200 by 9

Answer:

800 km/hr

Explanation:

7200 km divided by 9 hr=800 km/hr :)

Answer:

I believe the answer is B

Answer:

false

Explanation:

Answer:

32.5 miles

Explanation:

65/2=32.5

Hope this helps!

Answer:

32.5

Explanation:

Ratio of mass of brick to mass of pebble is 25:9 is speed is given.

Kinetic energy of object is given by the formula:

\(KE = (1/2)mv^2\)

KE: kinetic energy,

m: object's mass

v: object's speed

For brick:

V = 3 m/s

Therefore,

Kinetic Energy of brick = 1/2 * M1 * (9)

For pebble:

V = 5 m/s

Therefore,

Kinetic Energy of brick = 1/2 * M2 * (25)

Ratio can be found by dividing:

Therefore,

Ratio is:

M1/M2 = 25/9

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Answer:

The car is speeding up in a negative direction.

Explanation:

Answer:

ummmmmwm whattt

Explanation:

wuhsnnsnsnsnms

Answer:

medicines

band-aids

aqua liquid

paracetamol

Explanation:

Extra items:

alcohol

cottons

bitadine

cotton buds

mask

During capillary action, the water will rise higher in a narrower tube or channel with a smaller diameter.

This is because the smaller diameter creates a greater surface tension, which pulls the water upward against gravity. Additionally, a surface with a higher degree of attraction to the water molecules will also enhance capillary action, allowing the water to rise higher.
                                     This is because the adhesive forces between the water molecules and the tube's surface, as well as the cohesive forces between the water molecules themselves, are stronger in smaller diameter tubes, leading to a greater capillary rise.

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Answer:

energy is the ability to do work

Explanation:

this is explained because you need to put more effort to work which is known as energy

Answer: The action of something moving or being moved

Explanation:

The statement that is a quantitative observation is that bird has four different colors on it (option B).

A quantitative research is a systematic scientific investigation of quantitative properties and phenomena and their relationships, using statistical methods.

A quantitative observation has to do with numbers or numeric analysis.

This suggests that the statement that is a quantitative observation is that bird has four different colors on it.

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Calculate the specific heat capacity of the lime juice.

The heat of fusion indicates the energy required to convert 1 g of solid to liquid at the same temperature. 250 x 332 Joules are required to melt 250 g of ice. For example, let's look at the energy required to melt 1 kg of ice at 0°C to produce 1 kg of water at 0°C.

For example, consider the energy required to melt 1 kg of ice at 0 °C to produce 1 kg of water at 0 °C. Using the temperature change equation and the water values ​​in Table 1, we find that Q = mLf = 1.0 kg,  334 kJ/kg = 334 kJ is the energy to melt 1 kilogram of ice. The specific heat capacity of lemonade is about the same as that of water c = 4186 J/kg°C.

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(a) The energy needed to melt the ice is 27200 J.

(b) The formula to calculate the energy gained by the melted ice is Q = mCΔT.

(c) The energy gained by the melted ice from lemonade is 2688 J.

(d) The lost energy by the lime juice is 29888 J.

(e) The specific heat capacity of the lime juice is 4.447 J/ g °C.

The mass of ice is 80 grams.

The temperature of lemonade decreases from 29 °C to 8 °C.

The mass of lemonade, M = 0.32 kg = 320 g

The specific latent heat of fusion of ice = 3.4 × 10⁵ J/kg

Specific heat capacity of water = 4.2 × 10³ J/kg °C

a) The heat energy required to melt 1 kg of ice = 3.4 × 10⁵ J

So, the heat energy to melt 1 gram of ice = 340 J

Therefore, the energy required to melt 80 grams of ice = 340 × 80 = 27200 J

b) The formula for the energy gained by the melted ice from the lemonade is:

Q = mCΔT

Where m is the mass, C is the specific heat capacity, and ΔT is the change in temperature.

c) The energy gained by the melting of ice at 0 °C, Q = mCΔT

Q = 80 × 4.2 × ( 8 °C - 0 °C)

Q = 2688 J

d) The energy lost by the lime juice is energy gained by ice and water.

Lost energy by lime juice = 27200 J + 2688 J = 29888 J

e) Let's say C' is the specific heat capacity of the lime juice.

Then,

Q = MC'ΔT

Q = 320 g × C' × ( 29 - 8 )

Q = 6720C'

In equilibrium,

Heat lost = heat gained

6720C' = 29888 J

C' = 4.447 J/ g °C

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This setup cannot power the device because the voltage from the two 1.5 volt batteries is only 3 volts, which is not enough to power the device that requires 9 volts.

Even after stepping up the voltage using the 1:3 transformer, the output voltage would only be 9 volts if the input voltage is 3 volts, but the transformer cannot create energy, so the power output will be lower than the input power, leading to a lower voltage than needed. Additionally, the two 1.5 volt batteries may not be able to supply enough current to the device, leading to a lower power output and possible damage to the device. Therefore, this setup will not work to power the device.

In this case, even with the step-up transformer, the voltage is still not high enough to power the device. Additionally, the current supplied by the batteries may not be sufficient to meet the device's power requirements, which can cause the device to malfunction or not work at all. Finally, connecting batteries in series can be dangerous if they are not matched properly, as it can lead to overloading and possible overheating or explosion of the batteries.

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Answer:

5.26 m/s

Explanation:

Given that,

The frequency of mosquito's wings, f = 1050 Hz

The observed frequency = 1034 Hz

We need to find the velocity of the mosquito travelling with respect to you. We have a formula to find it such that,

\(v=\dfrac{v}{\dfrac{f'}{f}}-v\)

Where

v is the speed of sound

So,

\(v=\dfrac{340}{\dfrac{1034}{1050}}-340\\\\v=5.26\ m/s\)

So, the required velocity is equal to 5.26 m/s/

The angular resolution of the circular lens used in the experiment is approximately 0.0527. A smaller angular resolution indicates a higher ability to distinguish fine details in the observed object or system.

To calculate the answer of experiment that uses blue light of wavelength 650nm and a circular lens with a diameter of 15mm we need to find the angular resolution of the circular lens. The angular resolution can be determined using the formula:

Angular resolution = 1.22 * (wavelength / diameter)

Plugging in the values, we have:

Angular resolution = 1.22 * (650 nm / 15 mm)

To ensure consistent units, we convert the wavelength to millimeters:

Angular resolution = 1.22 * (0.65 mm / 15 mm)

Performing the calculation, we get:

Angular resolution ≈ 0.0527

Therefore, the angular resolution of the circular lens in this experiment is approximately 0.0527, without units.

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