If during an experiment zinc was found to be more reactive than lead or copper, zinc would be considered the strongest _____.
a. oxidizing agent
b. reducing agent
c. spectator ion
d. All of the above

Calcium sulfate (CaSO4) is a chemical compound made from calcium, oxygen, and sulfur.

The major sources of calcium sulfate naturally happen are gypsum and anhydrite, which occur at many position worldwide as evaporites.

A simple procedure for preparing acicular calcium sulfate dihydrate is on condition that in which a slurry of calcium carbonate carrying 100 to 800 grams per lite of calcium carbonate is assorted with a solution of sulphuric acid carrying 80 to 500 grams per liter sulphuric acid in proportions that construct calcium sulfate.

So we can conclude that Calcium sulfate, CaSO4, is a natural happen calcium salt.

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Answer: Clouds need two things to form: cool air and particles on which water vapor can condense. Clouds form as air cools. Cold air cannot hold as much water vapor, so the water vapor condenses. Water vapor condenses on small particles in the atmosphere, such as smoke, salt, and dust. As a result, clouds form.

Explanation: correct on edge

Answer:

C

Explanation:

Answer:

Hey, you have to solve it by Stichiometry.....answer is option A.... I have explained every option for your understanding.

Explanation:

(a.)**For option A, the volume of CO2 produced at STP will be 5.6 not 30.8 by solving equation for part I

By Stichiometry,

moles of CO2, n=11.2/22.4 = 0.5

Volume of CO2, V=11.2×0.5 =5.6

(b.)**For option B, the statement is correct

n(moles) of O2 =32/32 = 1 mol

we have to use stichiometry to find moles of CO2

n= 1/2 × 1 (coefficient of CO2/coefficient of O2) × mol of O2 (coz O2 is limiting reagent in 2nd option)

n= 0.5 mol

Mass= n × Molecular Mass

Mass= 0.5 × 44

Mass= 22g

(c.)**option C, is correct acc. to statement

(d.)**option D, is correct acc. to statement

(e.)**option E, is correct acc. to statement

Answer to this question is A part.

Hope it helps......

Answer:

If Earth were to change its orbit – maybe because the sun somehow disappeared or another, larger object entered the solar system and exerted a stronger pull – it would very likely mean the end of life as we know it. Without any orbit, Earth would likely go crashing directly into the sun.

Explanation:

Hope this helped! Please give brainly if you want!

Explanation:

If Earth were to change its orbit – maybe because the sun somehow disappeared or another, larger object entered the solar system and exerted a stronger pull – it would very likely mean the end of life as we know it. Without any orbit, Earth would likely go crashing directly into the sun.

From the stoichiometry of the reaction, 0.74 moles of aluminium oxide is produced.

The equation of the reaction is;

4Al + 3O2 --> 2Al2O3

Number of moles of Al =  40.0/27 g/mol = 1.48 moles

Number of moles of O2 = 19.0 g/32 g/mol = 0.59 moles

Now;

4 mols of Al reacts with 3 moles of O2

1.48 moles of Al reacts with  1.48 moles ×  3 moles/4 mols

= 1.11 moles

We can see that O2 is the reactant in excess.

Hence;

4 moles of Al produces 2 moles of aluminium oxide

1.48 moles of Al produces 1.48 moles ×  2 moles/4 moles = 0.74 moles of aluminium oxide

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The result of an increase in temperature at constant pressure will (1) The equilibrium will shift to the left, and the concentration of NO2(g) will decrease.

To determine the effect of an increase in temperature on the given equilibrium reaction, we need to analyze the reaction's heat as well as its stoichiometry.

The given reaction is an endothermic reaction as it absorbs heat (58.1 kJ) on the product side. According to Le Chatelier's principle, an increase in temperature will cause the equilibrium to shift in the direction that absorbs heat, i.e., to the left in this case.

Option 1 states that the equilibrium will shift to the left, which is correct. As the temperature increases, the equilibrium will shift to counteract the increase in heat. This means that more reactants, N₂O₄(g), will be formed, and the concentration of NO₂(g) will decrease.

Option 2 incorrectly suggests that the concentration of NO₂(g) will increase. However, since the equilibrium is shifting to the left, the concentration of NO₂(g) will actually decrease.

Option 3 correctly states that the equilibrium will shift to the right. This is an incorrect answer because an increase in temperature causes the equilibrium to shift in the direction that absorbs heat, which is to the left in this case.

Option 4 incorrectly mentions CO₂(g), which is not present in the given reaction. Therefore, this option is incorrect.

In summary, the correct answer is option 1: The equilibrium will shift to the left, and the concentration of NO₂(g) will decrease when the temperature is increased at constant pressure.
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Answer:oxygen

Explanation:

In order to solve this question, we will use the Molarity formula, which is:

M = n/V

Where:

M = molarity

n = number of moles

V = volume in liters

We don't have the number of moles, but we have the formula for molarity to help us find it, now we add the values into the formula:

3.50 = n/1.00

n = 3.50 moles of H2SO4

Now we have the number of moles, and the molar mass for H2SO4 is 98.079g/mol, now we can find the mass in grams:

98.079g = 1 mol

x grams = 3.50 moles

x = 343.3 grams of H2SO4

Answers:

Na+ HCl=NaCl+H2

Acids( HCl) reacts with Metal( Na) to give hydrogen gas(H2) and salt NaCL

The bidental chelators that have two donor atoms are species (1), (2) and  (3)

We know that ligands are compounds that have one or more lone pairs which are able to interact with another compound. In effect, Ligands are Lewis bases because they are able to share an electron pair with another specie.

We know that the number of donor atoms that we have in a ligand is what we call the denticity of the ligand. The denticity has to do with the number of bonding atoms that the ligands have that can be able to donate a lone pair of electrons.

In this case, we are looking for the species that are able to donate two donor atoms and they are the ones that we say are bidental chelators. These ones are able to bond to the ligand by the means of two donor atoms.

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The balanced equation is: 4 \(H_2S\)+ 3 \(O_2\)→ 4 \(SO_2\)+ 8 \(H_2O\)

The given chemical equation is unbalanced. To balance it, we need to adjust the coefficients in front of each chemical species until the number of atoms on both sides of the equation is equal.

The unbalanced equation is:

2 \(H_2S\)+ 3 \(O_2\)→ \(SO_2\)

Let's start by balancing the sulfur (S) atoms. We have two sulfur atoms on the left side and one sulfur atom on the right side. To balance the sulfur, we can place a coefficient of 2 in front of the \(SO_2\):

2 \(H_2S\)+ 3 \(O_2\)→ 2 \(SO_2\)

Now, let's balance the hydrogen (H) atoms. We have four hydrogen atoms on the left side (2 from each \(H_2S\)) and none on the right side. To balance the hydrogen, we can place a coefficient of 4 in front of the water (H2O) on the right side:

2 \(H_2S\)+ 3 \(O_2\)→ 2 \(SO_2\)+ 4 \(H_2O\)

Finally, let's balance the oxygen (O) atoms. We have six oxygen atoms on the right side (3 from \(O_2\) and 3 from 2 \(SO_2\)) and three on the left side (2 from \(H_2S\)). To balance the oxygen, we can place a coefficient of 3/2 in front of the O2:

2 \(H_2S\)+ (3/2) \(O_2\)→ 2 \(SO_2\)+ 4 \(H_2O\)

To remove the fractional coefficient, we can multiply all coefficients by 2:

4 \(H_2S\) + 3 \(O_2\)→ 4 \(SO_2\)+ 8 \(H_2O\)

Now the equation is balanced, with an equal number of atoms on both sides. The balanced equation is:

4 \(H_2S\)+ 3 \(O_2\)→ 4 \(SO_2\)+ 8 \(H_2O\)

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Units of the SI System

There are seven base units in the SI system:

the kilogram (kg), for mass

the second (s), for time

the kelvin (K), for temperature

the ampere (A), for electric current

the mole (mol), for the amount of a substance

the candela (cd), for luminous intensity

the meter (m), for distance

Answer:

Wt. Avg. Atomic Weight => 63.35457 amu

Explanation:

Given              Isotopic             %Abundance     fractional          Wt Avg

                  At. Mass (amu)                                  abundance      contribution                    

Cu-63              62.93                      69.09              0.6909            43.4783

Cu-65              64.9278                  20.0668        0.200668        20.0668

Wt Average of all isotopes = ∑Wt Avg Contributions

=  43.4783 amu + 20.0668 amu = 63.35457 amu

Answer:

5.83g C4H10 x (1 mol C4H10/58.05 g (molar mass of C4H10) x (10 mol H2O/ 2 mol C4H10) x (18.002 g H2O (molar mass of H2O)/ 1 mol H2O=

Answer: 9.04 g of H2O

Explanation:

First set up equation: C4H10 (g)+ O2(g) -> CO2(g) + H2O(g)

Next balance it: 2C4H10 (g)+ 13O2(g) -> 8CO2(g) + 10H2O (g)

Use equation to get moles and plug given

5.83g C4H10 x (1 mol C4H10/58.05 g (molar mass of C4H10) x (10 mol H2O/ 2 mol C4H10) x (18.002 g H2O (molar mass of H2O)/ 1 mol H2O

Answer:

The enthalpy change for the solution process \(\Delta H_{rxn}\) = - 158.34 kJ/mol

Explanation:

Given that:

The mass of salt AX = 2.499 g

The mass of water = 135.3 g

The mass of the solution = ( 2.499 + 135.3 ) g = 137.799 g

The specific heat of salt solution s is known to be = 4.18 J/g° C

The change in temperature i.e. ΔT = 35.2 °C -  23.6 °C = 11.6 °C

Thus, the amount of heat raised is equal to the heat absorbed by the calorimeter.

∴

\(q_{reaction} = q_{solution}\)

\(q_{reaction} = -ms_{solution} \Delta T\)

\(q_{reaction} = -137.799 \ g \times 4.18 \dfrac{J}{g^0C}\times 11.6^0C\)

\(q_{reaction} = - 6682 \ J\)

\(q_{reaction} = - 6.682 \ kJ\)

Recall that the mass of the salt = 2.499 g

The number of moles of the salt = \(2.499 \ g \times \dfrac{1 \ mol \ of \ AX}{59.1097 \ g}\)

= 0.0422 mol of AX

Finally the enthalpy change, \(\Delta H_{rxn} = \dfrac{- 6.682 \ kJ}{ 0.0422 \ mol}\)

= - 158.34 kJ/mol

The enthalpy change for the solution process \(\Delta H_{rxn}\) = - 158.34 kJ/mol

Answer:

While weathering and erosion are similar processes, they are not synonymous. Weathering involves the breakdown of rocks and minerals on Earth, whereas erosion involves the removal of soil and rock materials.

Answer: inside

Explanation:

Answer:

direct and indirect contact

Explanation:

if you touch a doorknob right after an infected person than you make be exposed to the disease.

Answer:

See explanation

Explanation:

Hydrogen has only one valence electron. Sometimes, hydrogen is included as part of group 1 or 17 in the periodic table. Is this correct? Well, the answer to this question is not so straight forward!

Let us remember that hydrogen forms a univalent positive ion H^+ just like the group 1 elements, but it also forms a univalent negative ion H^- just like group 17 elements. Also, hydrogen is a gas and forms a molecular diatomic compound just like group 17 elements. This is not the case with other group 1 elements. We can see that hydrogen is chemically and physically dissimilar to other group 1 elements hence one can logically argue against its inclusion in group 1. Also, it is not a halogen, so we can also argue against its inclusion in group 17.

However, it is convenient to include hydrogen in the main groups 1 or 17 when discussing its chemical properties in order to make it easier to assimilate. If we place hydrogen in group 1, we can understand that it forms univalent positive ions. Similarly, if we place it in group 17, we understand that it forms univalent negative ions.

Most times hydrogen is just written separately at the top right corner of the periodic table and not as a member of any group because of the issues outlined above.

Hydrogen is placed in the main group of the periodic table since it has only one electron in it and it also behaves like alkali metal properties.

Hydrogen forms a univalent positive ion \(H^+\)group 1 elements, but it also forms a univalent negative ion \(H^-\)group 17 elements. Also, hydrogen is a gas and forms a molecular diatomic compound just like group 17 elements.

This is not the case with other group 1 elements. We can see that hydrogen is chemically and physically dissimilar to other group 1 elements hence one can logically argue against its inclusion in group 1. Also, it is not a halogen, so we can also argue against its inclusion in group 17.

If we place hydrogen in group 1, we can understand that it forms univalent positive ions and if it is placed in halogen group it will form univalent negative ion.

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According to the VSEPR theory, a molecule or ion of CO2 will have a flat linear shape. Option A

In CO2, the carbon atom forms double bonds with each oxygen atom. The carbon-oxygen double bonds consist of two pairs of electrons, which are arranged linearly, leading to a linear molecular shape.

The VSEPR theory suggests that electron pairs in the valence shell of the central atom repel each other and try to position themselves as far apart as possible, resulting in the linear shape.

The VSEPR theory allows us to predict the molecular geometry based on the arrangement of bonding and non-bonding electron pairs around the central atom. In the case of CO2, there are no lone pairs of electrons on the carbon atom, and the molecule has a symmetrical arrangement, leading to a linear shape. Option A

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Answer:

the water.

Explanation:

well the water makes things look larger than due to ( the surface of a water drop curves outwards to make a dome. this outward or convex, curature light rays inward. the result is an enlarge ment image on the eye. / makes it look larger) + more mass.

First, we have to remember the equation to calculate the heat of evaporation:

Q is the heat, ΔH is the vaporization heat of the substance, and m is the mass.

If we have the vaporation heat in terms of moles (as in this case), we have to multiply it by the number of moles instead of the mass. For that purpose, we have to calculate the molecular weight of the water:

Then, we can pass the grams to moles:

And we can finally calculate the heat:

The answer is that the necessary heat to evaporate the water is 63.9894 kJ approx.

1. It is also known as the dark reaction of photosynthesis: Off.

2. Primary acceptor of carbon is Photosystem I and II: On.

3. Site of the process is in the stroma: Off.

4. Photolysis of water does not occur: Off.

5. Process type is both cyclic and non-cyclic processes: On.

6. It is a release of oxygen that gives off aldehydes and hydrogen upon dehydrogenation: On.

7. It is a process that converts solar energy into chemical energy: On.

8. It is a light dependent process: On.

9. Process type is cyclic only: Off.

10. Primary acceptor of carbon is Rubiscobisphosphate: Off.

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H12 ⟶ H11 + p in this nuclear reaction, a proton (p) is emitted.Cu2961 ⟶ Z0n3061 + y In this nuclear reaction, a gamma ray (y) is emitted.Po84210 ⟶ Pb82206 + a.

In nuclear reactions, the particle that is emitted depends on the reactants involved. The following are the completed nuclear reactions with the particle that is emitted.In the above nuclear reaction, an alpha particle (a) is emitted.A nuclear reaction is a process that alters the nucleus of an atom, resulting in a change in the atom's composition.

The stability of the nucleus determines which kind of decay a certain nucleus will undergo. In nuclear decay reactions, the identity of the atom changes as a result of the decay process. In a nuclear decay, a nucleus may emit particles such as alpha or beta particles, gamma rays, or neutrons, resulting in the creation of a new nucleus.

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The balanced chemical equation for the reaction is:

PCl5 + H2O → H3PO4 + HCl

To balance this equation, we need to make sure that the number of atoms of each element is equal on both sides of the equation.

To do this, we can start by balancing the phosphorus (P) and chlorine (Cl) atoms. There is one P atom and five Cl atoms on the left side of the equation, and one P atom and one Cl atom on the right side of the equation. We can balance these by adding a coefficient of 5 in front of HCl:

PCl5 + H2O → H3PO4 + 5HCl

Now we have five Cl atoms on both sides of the equation. Next, we can balance the hydrogen (H) atoms. There are two H atoms on the left side of the equation and five H atoms on the right side of the equation. We can balance these by adding a coefficient of 2 in front of H2O:

PCl5 + 2H2O → H3PO4 + 5HCl

Now we have two H atoms on both sides of the equation. Finally, we can balance the oxygen (O) atoms. There are two O atoms on the left side of the equation and four O atoms on the right side of the equation. We can balance these by adding a coefficient of 2 in front of H3PO4:

PCl5 + 2H2O → 2H3PO4 + 5HCl

Therefore, to balance this reaction, we need to use this balanced chemical equation:

PCl5 + 2H2O → 2H3PO4 + 5HCl

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Answer:

Earth's thin outer shell is broken into big pieces called tectonic plates. These plates fit together like a puzzle, but they're not stuck in one place. They are floating on Earth's mantle, a really thick layer of hot flowing rock. The flow of the mantle causes tectonic plates to move in different directions.

Explanation:

Despite having polar bonds, the molecule of carbon dioxide (CO2) is nonpolar. The linear structure of CO2 is. Due to their identical amplitude and opposite polarity, the distinct bond dipoles cancel one another.

A polar covalent molecule is water.

A water molecule has two poles: a positive charge on the hydrogen pole (side) and a negative charge on the oxygen pole due to the unequal sharing of electrons between the atoms and the asymmetrical form of the molecule (side).

CO and NH3; NH4+ and HCl; and Polar covalent bonds are present in all of the species.

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The statement that is true regarding the solution prepared by adding 0.10 mol of potassium acetate to 1.00 L of water is that it is acidic (option B).

pH refers to the measure of the acidity or alkalinity of a solution. It can be calculated by using the following expression:

pH = - log {H}

Where;

The concentration of the acetate solution must first be calculated by dividing the number of moles by its volume as follows:

Molarity = no of moles ÷ volume

Molarity = 0.10 mol ÷ 1L = 0.1M

pH = - log {0.1}

pH = 1

1 indicates that the solution is acidic, hence, option B is correct.

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When a substance or radiation's heat is stated quantitatively, it is called its temperature.

Three different categories of temperature scales exist:

those, like Kelvin's original definition, that solely rely on macroscopic characteristics and thermodynamic concepts;

those that rely on actual, empirical particle qualities as opposed to theoretical concepts;

Additionally, there are scales like the SI scale that are determined by the typical translational kinetic energy per freely moving tiny particle, such as an atom, molecule, or electron in a body.

The equation q = mcΔT, where m is the sample mass, c is the specific heat, and T is the temperature change, can be used to determine how much heat a a sample gains or loses (q).

Therefore,

q = m*c*ΔT

2072.87 = 335 * 4.184 * ΔT

ΔT = 1.479 °c

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