If an object is in motion and experiences no others forces it will stay in
motion.
FALSE
TRUE

Answer: b

Explanation: 50% comes from one parent and 50% comes from the other

Answer

1.0 mol

Explanation

Given:

Volume, V = 5.0 L

Temperature, T = 215 K

Pressure, P = 342 kPa

The gas constant, R = 8.31 L kPa/mol K

What to find:

The number of moles of the gas sample.

Step-step-solution:

The number of moles of the gas can be determine using the ideal gas equation formula:

Put the given values into the formula and calculate for n:

The number of moles of the gas sample is 1.0 mol.

Answer:

B  3.70 mol NH2

Explanation:

Answer:

A. 0.0717 L
B. 82.9 L
C. 21.5 L

A compound is a substance that can only be split into two or more compounds chemically.  

Compounds are compounds made up of two or more chemically coupled components that can only be broken down chemically into simpler substances. Compounds are compounds made up of two or more chemically coupled components that can only be broken down chemically into simpler substances. For instance, pure water is a compound since it contains solely H2O molecules. A compound is a substance that, due to the presence of multiple elements, can be divided into chemically simpler components. For instance, water is a substance made up of the elements oxygen and hydrogen. a material consisting of two or more components mixed chemically in a predetermined ratio.

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Answer:

cohesion

Explanation: the sticking together of particles of the same substance

A model of the force between two negatively charged particles is attached in the image below.

Force is defined as a cause which is capable of changing the motion of an object. It can cause an object which has mass to change it's velocity. It is also simply a push or a pull . It has both magnitude as well as direction.Hence, it is a vector quantity.

It has SI units of Newton and is represented by'F'.Newton's second law states that force which acts on an object is equal to momentum which changes with time. If mass of object is constant, acceleration is directly proportional to net force acting on an object.

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The -log of the [H+] and the -log of the Ka are equal. Therefore, option (B) is correct.

Equal concentrations of a weak acid and its conjugate base result in a balanced ratio of proton donors and acceptors, reducing the ability of the buffer to resist pH changes. The -log of the [H+] and the -log of the Ka (acid dissociation constant) are equal because at equilibrium, the concentrations of the weak acid and its conjugate base are equal.

However, in this scenario, the system is not at equilibrium as the reaction can still occur in either direction. Overall, equal concentrations of the weak acid and its conjugate base limit the buffer's effectiveness, affecting its ability to maintain a stable pH.

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Volume is the amount of space taken up by an object

The instrument used to measure liquid volume is called a graduated cylinder.

The formula used to calculate the volume of a solid object such as a rectangular prism is: V =  length, *  width * height

Volume is a measure of the amount of space that a substance or object occupies. It is typically measured in units such as liters, cubic meters, gallons, or cubic feet.

The instrument used to measure liquid volume is called a graduated cylinder. It is a cylindrical tube made of glass or plastic, with volume markings along its length that allow for the accurate measurement of liquids.

The formula used to calculate the volume of a solid object depends on its shape. Here are some common formulas for finding the volume of different types of solid objects:

Cube: V = s³ (where s is the length of one side of the cube)

Rectangular prism: V =  length, *  width * height

Sphere: V = 4/3πr³ (where r is the radius of the sphere)

Cylinder: V = πr^2h (where r is the radius of the cylinder and h is its height)

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The typical values for the diameter in meters are: nucleus (1.6 x 10^(-15) to 16 x 10^(-15)), atom (0.1 nanometers to a few nanometers), and red blood cell (6 to 8 micrometers).

The typical diameter values in meters for a nucleus, an atom, and a red blood cell vary significantly due to the vast differences in size between these entities. A nucleus, which is the central region of an atom and contains protons and neutrons, is extremely tiny. On average, the diameter of a nucleus ranges from about 1.6 x 10^(-15) meters to 16 x 10^(-15) meters (1.6 to 16 femtometers).

Moving to the scale of individual atoms, their diameters are even smaller. Atoms consist of a nucleus surrounded by electrons. The size of an atom is primarily determined by the arrangement of its electrons. For example, a hydrogen atom has a diameter of about 0.1 nanometers or 1 x 10^(-10) meters. In comparison, larger atoms like uranium can have diameters of approximately 3.5 x 10^(-10) meters.

Transitioning to a larger biological scale, red blood cells are much larger than nuclei and atoms. They are essential components of our circulatory system and carry oxygen throughout the body. The typical diameter of a red blood cell is around 6 to 8 micrometers, which is equivalent to 6 x 10^(-6) to 8 x 10^(-6) meters.

In summary, the typical diameter of a nucleus ranges from about 1.6 x 10^(-15) meters to 16 x 10^(-15) meters, atoms have diameters around 0.1 nanometers to a few nanometers, and red blood cells measure approximately 6 to 8 micrometers in diameter.

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Answer:

When moving from left to the right of a period, the number of electrons increases and the strength of shielding increases. As you move across period the number of shells remain same, the shielding effect will also remain constant.

Explanation:

Answer:

Combustion, or burning,[1] is a high-temperature exothermic redox chemical reaction between a fuel (the reductant) and an oxidant, usually atmospheric oxygen, that produces oxidized, often gaseous products, in a mixture termed as smoke. Combustion does not always result in fire, because a flame is only visible when substances undergoing combustion vapourise, but when it does, a flame is a characteristic indicator of the reaction. While the activation energy must be overcome to initiate combustion (e.g., using a lit match to light a fire), the heat from a flame may provide enough energy to make the reaction self-sustaining. Combustion is often a complicated sequence of elementary radical reactions. Solid fuels, such as wood and coal, first undergo endothermic pyrolysis to produce gaseous fuels whose combustion then supplies the heat required to produce more of them. Combustion is often hot enough that incandescent light in the form of either glowing or a flame is produced. A simple example can be seen in the combustion of hydrogen and oxygen into water vapor, a reaction commonly used to fuel rocket engines. This reaction releases 242 kJ/mol of heat and reduces the enthalpy accordingly (at constant temperature and pressure):



The flames caused as a result of a fuel undergoing combustion (burning)



Air pollution abatement equipment provides combustion control for industrial processes.

2H

2(g) + O

2(g) → 2H

2O(g)

Combustion of an organic fuel in air is always exothermic because the double bond in O2 is much weaker than other double bonds or pairs of single bonds, and therefore the formation of the stronger bonds in the combustion products CO

2 and H

2O results in the release of energy.[2] The bond energies in the fuel play only a minor role, since they are similar to those in the combustion products; e.g., the sum of the bond energies of CH4 is nearly the same as that of CO

2. The heat of combustion is approximately −418 kJ per mole of O2 used up in the combustion reaction, and can be estimated from the elemental composition of the fuel.[2]

Uncatalyzed combustion in air requires relatively high temperatures. Complete combustion is stoichiometric concerning the fuel, where there is no remaining fuel, and ideally, no residual oxidant. Thermodynamically, the chemical equilibrium of combustion in air is overwhelmingly on the side of the products. However, complete combustion is almost impossible to achieve, since the chemical equilibrium is not necessarily reached, or may contain unburnt products such as carbon monoxide, hydrogen and even carbon (soot or ash). Thus, the produced smoke is usually toxic and contains unburned or partially oxidized products. Any combustion at high temperatures in atmospheric air, which is 78 percent nitrogen, will also create small amounts of several nitrogen oxides, commonly referred to as NOx, since the combustion of nitrogen is thermodynamically favored at high, but not low temperatures. Since burning is rarely clean, fuel gas cleaning or catalytic converters may be required by law.

Fires occur naturally, ignited by lightning strikes or by volcanic products. Combustion (fire) was the first controlled chemical reaction discovered by humans, in the form of campfires and bonfires, and continues to be the main method to produce energy for humanity. Usually, the fuel is carbon, hydrocarbons, or more complicated mixtures such as wood that contains partially oxidized hydrocarbons. The thermal energy produced from combustion of either fossil fuels such as coal or oil, or from renewable fuels such as firewood, is harvested for diverse uses such as cooking, production of electricity or industrial or domestic heating. Combustion is also currently the only reaction used to power rockets. Combustion is also used to destroy (incinerate) waste, both nonhazardous and hazardous.

Oxidants for combustion have high oxidation potential and include atmospheric or pure oxygen, chlorine, fluorine, chlorine trifluoride, nitrous oxide and nitric acid. For instance, hydrogen burns in chlorine to form hydrogen chloride with the liberation of heat and light characteristic of combustion. Although usually not catalyzed, combustion can be catalyzed by platinum or vanadium, as in the contact process.

180 grams of acetic acid are in a 1.50 qt q t sample of this vinegar.

No of moles of \($\mathrm{NaOH}=45.0 \mathrm{~mL} \times \frac{1 \mathrm{~L}}{1000 \mathrm{~mL}} \times \frac{0.110 \mathrm{~mol} \mathrm{NaOH}}{1 \mathrm{~L}}=0.00495 \mathrm{~mol} \mathrm{NaOH}$\)At equival ence point, \($n_{\mathrm{CH}_3 \mathrm{COOH}}=n_{\mathrm{NaOH}}=0.00495 \mathrm{~mol}$\)

Concentration of \($\mathrm{CH}_3 \mathrm{COOH}=\frac{0.00495 \mathrm{~mol}}{3.90 \mathrm{~mL} \times \frac{1 \mathrm{~L}}{1000 \mathrm{~mL}}}=1.27 \mathrm{~mol} / \mathrm{L}=1.27 \mathrm{M}$\)

Volume of \($\mathrm{CH}_3 \mathrm{COOH}=1.50 \mathrm{qt} \times \frac{0.946353 \mathrm{~L}}{1 \mathrm{qt}}=1.42 \mathrm{~L}$\)

Amount of \($\mathrm{CH}_3 \mathrm{COOH}=1.42 \mathrm{~L} \times \frac{1.27 \mathrm{~mol} \mathrm{CH}_3 \mathrm{COOH}}{\mathrm{L}} \times \frac{60.05 \mathrm{~g} \mathrm{CH}_3 \mathrm{COOH}}{1 \mathrm{~mol} \mathrm{C \textrm {CH } _ { 3 } \mathrm { COOH }}}$\)\($=108 \mathrm{~g} \mathrm{CH}_3 \mathrm{COOH}$\)

Acetic acid, officially known as ethanoic acid, is an organic molecule with the chemical formula CH3COOH that is acidic and colourless. Apart from water and other trace ingredients, vinegar has at least 4% acetic acid by volume, making acetic acid its primary ingredient.

Acetic acid is a sour ingredient that can be used to sauce, vinegar, pickled vegetables, and as a raw material for spices. Acetic acid can be identified when employed as a food additive by its group name, substance name, or abbreviated term depending on the use.

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Answer:

I hate to not answer and have you repost this if you could repost it with the choices by clicking the arrow I can figure it out a lot faster and I'll copy and paste to show you that it's right

Explanation:

I'm good with history biology sum math so if you want to do what I asked and reposted I can give you the answers and I will show that they are correct I won't just guess like some people do just to get points cuz I don't care about points I just get on here to help people

Answer: The answer for the blanks is initial appearance and than final appearance.

Explanation:

The equilibrium constant for the reaction Cu2+(aq)+Zn(s)→Cu(s)+Zn2+(aq) at 25 °C is 4.96 × 10^15.

The standard electrode potentials for Cu2+/Cu and Zn2+/Zn half cells are +0.34 V and -0.76 V, respectively. Using these standard electrode potentials, let us calculate ΔG∘ and use its value to estimate the equilibrium constant for the following reaction:Cu2+(aq)+Zn(s)→Cu(s)+Zn2+(aq)The standard electrode potential for Cu2+/Cu half cell is +0.34 VThe standard electrode potential for Zn2+/Zn half cell is -0.76 V.

The value of ΔG∘ can be calculated as follows:ΔG∘= -n FE ∘cell Where, n is the number of electrons exchanged, F is the Faraday constant and E∘ cell is the standard cell potential. Substituting the values, we getΔG∘= -2 × 96485 × (1.1) = -212118.7 J/mol = -212.12 kJ/mol The equilibrium constant Kc can be obtained from the relationshipΔG∘= -RT ln Kc where, R is the gas constant and T is the temperature in Kelvin.

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Answer:

a.One or more electrons will move to a higher energy orbit

Explanation:

Absorbing energy means that the electron gets excited and jumps to a higher level.

Answer:

electrolyte

Explanation:

Answer:

sdfs

Explanation:

dfssdf

When 1-bromo-2-methylpropane is reacted with methoxide the same product 1-methylprop-2-ene is obtained. This reaction is attached in image below:

The SN2 reaction is a nucleophilic substitution reaction that breaks one bond while forming another. The rate-determining step of the reaction involves two reacting species. SN2 is an abbreviation for Substitution Nucleophilic Bimolecular.

The reaction is bimolecular because two molecules are present in the transition state, as indicated by the number 2 in the SN2 symbol. As a result, the rate of the reaction is affected by the concentrations of both the nucleophile and the substrate.

The SN2 reaction is a nucleophilic substitution with two components in the rate determining step. -SN2 reactions are bimolecular, with bond-forming and bond-breaking steps occurring simultaneously. There is no intermediate in -SN2 reactions.

Thus, product 1-methylprop-2-ene is obtained.

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The pH of the gastric juice is approximately 1.08.

To determine the pH of the gastric juice, we need to calculate the concentration of H+ ions in the solution. Since the gastric juice was titrated with NaOH to neutrality, the moles of H+ ions in the gastric juice should be equal to the moles of OH- ions added by NaOH.

Given that 7.2 mL of 0.1 M NaOH was required to reach neutrality, we can calculate the moles of OH- ions added:

Moles of OH- ions = Volume of NaOH (L) * Concentration of NaOH (mol/L)

Moles of OH- ions = 7.2 mL * (0.1 mol/L / 1000 mL/L)

Moles of OH- ions = 0.0072 mol

Since the H+ and OH- ions react in a 1:1 ratio, the moles of H+ ions in the gastric juice are also 0.0072 mol.

The volume of the gastric juice sample used was 10.0 mL, which is equivalent to 0.010 L.

Now we can calculate the concentration of H+ ions in the gastric juice:

Concentration of H+ ions = Moles of H+ ions / Volume of gastric juice (L)

Concentration of H+ ions = 0.0072 mol / 0.010 L

Concentration of H+ ions = 0.72 mol/L

To find the pH, we can use the formula: pH = -log[H+]

pH = -log(0.72)

pH ≈ 1.08

The pH of the gastric juice, as determined from the titration with NaOH, is approximately 1.08. This indicates a highly acidic environment in the stomach.

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Ice sheets, ice caps, glaciers, icebergs, bogs, ponds, lakes, rivers, streams, and groundwater are the sources of freshwater.

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The equation that can be used to find the pressure of the gas when the volume is changed is P(v) = 500/v.

An inverted container filled with water can be used to collect the gas produced during a chemical reaction and estimate its volume. Water is forced out of the container by the gas, and the amount of liquid expended serves as a gauge for the gas's volume.

Boyle's law, which states that the volume of a given quantity of gas held at constant temperature is inversely proportional to the pressure under which it is measured, encapsulates this principle.

p(v) = pressure of a gas

v = volume of the gas

P(v) varies inversely with v

let k = constant of proportionality

P(v) = k/v

If P(v) = 25 kg/cm² and v = 200cm²

Therefore,

P(v) = k/v

25 = k / 200

25 × 200 = k

k = 5,000

substitute the value of k into the equation

So, P(v) = 500/v

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The combination of isoclines that lead to competitive exclusion and competitive coexistence is the zero population growth isocline (ZPGI) and the resource axis (RA).Competitive exclusion and coexistence are both population dynamics terms.

Competitive exclusion is a situation whereby one species dominates a particular niche to the detriment of another species that requires the same resources. This occurs when the population of one species is larger than that of another in a given ecosystem .Competitive coexistence, on the other hand, is the opposite of competitive exclusion, where two or more species share the same niche or habitat and do not exclude one another. This is possible through resource partitioning, which occurs when species evolve different feeding behaviors or physical adaptations to consume different food types or occupy different areas in a shared ecosystem. Zero Population Growth Isocline (ZPGI) and the Resource Axis (RA) are the combination of isoclines that lead to competitive exclusion and competitive coexistence, respectively. They both play a significant role in population dynamics in ecology.

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The pH of a solution that has a concentration of \(2.78 * 10^{-3}\)M is 2.56. The aqueous solution is acidic because it is less than 7 on the pH scale.

pH is a figure expressing the acidity or alkalinity of a solution on a logarithmic scale on which 7 is neutral, lower values are more acid and higher values more alkaline.

The pH is equal to −log {H}

According to this question, \(2.78 * 10^{-3}\) of hydrogen bromide is given. The pH can be estimated as follows:

pH = \(- log\) {\(2.78 * 10^{-3}\)}

pH = 2.56 (acidic)

The complete question is as follows:

What is the hydronium ion concentration for an aqueous solution with a hydroxide ion concentration of 2.78x10^-10 M? Is the solution acidic basic or neutral?

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According to the graph presented, we can see that NaNO3 has a higher solubility at 30°C, as we can see more than 100 grams of NaNO3 can be dissolved in 100 grams of water, whereas all other solutes will have a way lower value. Letter D

When an atom of carbon-14 (C-14) undergoes radioactive decay in which a neutron is converted into a proton, the resulting atom produced is nitrogen-14 (N-14).

Carbon-14 is an isotope of carbon that contains 6 protons and 8 neutrons in its nucleus. During radioactive decay, one of the neutrons in the C-14 nucleus is converted into a proton. Since the number of protons determines the identity of the element, the resulting atom will have 7 protons. Therefore, it becomes nitrogen-14, which has an atomic number of 7 and 7 neutrons in its nucleus.

The process of converting a neutron into a proton is known as beta decay, which is a common type of radioactive decay observed in isotopes. This conversion leads to a change in the atomic number of the nucleus, resulting in the formation of a different element.

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The appropriate expression for entropy change is ΔS = nR ln(V₂/V₁) + nCp ln(T₂/T₁).

The expression for calculating the entropy change (ΔS) of an ideal gas during a process involving temperature and volume changes is given by the equation above. Here, n represents the number of moles of the gas, R is the ideal gas constant, Cp is the molar heat capacity at constant pressure, V₁ and V₂ are the initial and final volumes respectively, and T₁ and T₂ are the initial and final temperatures respectively.

To calculate the value of ΔS, we substitute the given values into the equation:

ΔS = (3.00 mol)(8.314 J/(mol·K)) ln(120.0 L / 90.0 L) + (3.00 mol)(Cp) ln(345 K / 298 K)

The value of Cp depends on the specific gas involved, as it represents the molar heat capacity at constant pressure. The specific value of Cp would need to be provided to calculate the exact numerical value of ΔS.

By using the provided expression and plugging in the given values, along with the specific heat capacity value, you can calculate the entropy change associated with heating and expanding the ideal gas from the initial conditions to the final conditions.

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This problem is providing the length in inches of a rod and it is being required to convert it to centimeters. According to the following, the answer will be 43.7 cm:

In science, we use units conversion to represent measurements in different types of units depending on a specific requirement. To do so, we use conversion factors based on equivalence statements, relating the required unit with the given one.

In this case, the equivalence statement between inches and centimeters is 2.54 cm = 1 in and we can use it to get the answer as shown below:

\(17.2in*\frac{2.54cm}{1in} \\\\=43.7 cm\)

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The correct answer is option (D)

If 40 grams of MgCl2 is dissolved in 1000 grams of water then the percent by mass of the solute is 3.85%.

To calculate the percent by mass of the solute, we need to divide the mass of the solute by the total mass of the solution (solute + solvent) and then multiply by 100.

Mass of solute (MgCl2) = 40 grams
Mass of solvent (water) = 1000 grams

Total mass of solution = 40 grams + 1000 grams = 1040 grams

Percent by mass of solute = (40 grams / 1040 grams) x 100% = 3.85%


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