which requires more energy: lifting a 50 kg sack vertically 2 meters or lifting a 25 kg sack vertically 4 meters?
a. lifting the 50 kg sack
b. lifting the 25 kg sack
c. both require the same amount of work
Answer:
c. Both require the same amount of work
Explanation:
GPE = mgh
50 * 10 * 2 = 1000 J
25 * 10 * 4 = 1000 J
Therefore, both are same and require the same amount of work.
Thenk and mark me brainliest :)
Both require the same amount of work. The correct option is C.
What is gravitational potential energy?The potential energy that a massive object has in relation to another massive object due to gravity is known as gravitational energy or gravitational potential energy. When two objects fall toward one another, potential energy associated with the gravitational field is released.
Given that there are two activities,
1) lifting a 50 kg sack vertically 2 meters.
2) lifting a 25 kg sack vertically 4 meters.
The energy required to lift the weight will be calculated as:-
GPE = mgh
50 x 10 x 2 = 1000 J
25 x 10 x 4 = 1000 J
So we can conclude that both activities require the same amount of work.
Therefore, both require the same amount of work. The correct option is C.
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In the inertial system S, an event is observed to take place at point A on the x-axis and 10−6S later another event takes place at point B, 900 m further down. Find the magnitude and direction of the velocity of S with respect to S in which these two events appear simultaneous
The magnitude of the velocity of S with respect to S' is 0.866 times the speed of light, and it is in the negative x-direction (i.e., opposite to the direction of motion of S').
Explanation:
The problem can be solved using the concept of relativity of simultaneity and the Lorentz transformation equations. Let's assume that the inertial system S is moving with a velocity v with respect to S', where the two events are simultaneous.
Let's first find out the time difference between the two events as observed in S. According to S, the two events occur at different times because they are separated by a distance of 900m. Let's call this time difference Δt.
Δt = 900m / c = 3 × 10^−6 S
where c is the speed of light.
Now, let's apply the Lorentz transformation equations to relate the time difference Δt in S to the time difference Δt' in S':
Δt' = γ(Δt - vΔx/c^2)
where Δx is the distance between the two events as measured in S, and γ is the Lorentz factor given by:
γ = 1 / sqrt(1 - v^2/c^2)
Since the two events are simultaneous in S', we have Δt' = 0. Also, Δx = 900m, and Δt = 3 × 10^−6 S.
Solving for v, we get:
v = Δx / (γΔt)
Substituting the values of Δx, Δt, and γ, we get:
v = 0.866c
State Graham's law and state in which sector it falls
Graham's law states that the rate of diffusion or effusion of two gases is inversely proportional to the square root of their molar masses
If two gases be x and yFor diffusion:-
\(\\ \sf\longmapsto \dfrac{V_x}{V_y}=\sqrt{\dfrac{m_y}{m(x}}\)
m means molar massFor effusion
\(\\ \sf\longmapsto \dfrac{R_x}{R_y}=\sqrt{\dfrac{m_y}{m_x}}\)
Each circled letter in the circuit diagram represents a meter that is used to
measure a quantity in the circuit. Which meters show the amount of charge
passing a point each second?
A
C
m
A. C and D
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(В
There are meters created to precisely measure the fundamental values of voltage, current, and resistance for analyzing and testing circuits.
What exactly is a circuit schematic for a meter?Any apparatus designed to precisely detect and present an electrical quantity in a way that can be understood by a human is referred to as a meter. The majority of the current flows via one branch, while the remainder flows through the other branch. At the point of meter insertion, an ammeter is used to measure the amount of current (in amps or milliamps) flowing in a circuit. The circuit element you are measuring is always linked in series with an ammeter. The most frequent measurements in an electrical circuit are typically made with a meter. Current is measured by an ammeter.
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weather meaning of physics
Answer:
1. The day-to-day conditions of the atmosphere at a place with respect to elements like humidity, temperature, wind speed, rainfall, etc. is called the weather of that place.
2. Weather can be cloudy, sunny, rainy, stormy or clear. It is a part of the natural phenomenon which maintains the equilibrium in the atmosphere.
3. But conditions can be worse sometimes. When the atmospheric conditions are extreme or intense enough to cause property loss or life loss, such weather is termed as severe weather.
4. These also vary according to the altitudes, latitudes, and region and pressure differences. Tornadoes, cyclones, heavy rainfall, fog, winter storms come under this category. They are disastrous and hazardous. Proper disaster management and strategies are required to handle these conditions.
Rectangular frames are easy to build but can get pulled out of shape. What are two solutions to this problem?
Answer: Rectangular frames are easy to make but can get pulled out of shape. so if the sides are still attached , then the figure formed is parallelogram. useing the given measurement use the formula of a parallelogram.
formula : A = BASE X HEIGHT
Explanation:
If a box has a length of 10.0 cm, a width of 20.0 cm, and a height of 5.00 cm, then what is its volume in m^3?
1.00 x 10^-4
1.00 x 10^-3
5.00 × 10^2
1.00 × 10^4
Explanation:
Solution,
Given:-
Length=10 cmWidth= 20 cmHeight= 5 cmVolume =?Now,
By using the formula of volume of a cuboid, we have
volume=length×width×heightvolume=10 cm×20 cm×5 cmvolume=1000 cm³volume= 1×10×10×10×10 cm³volume=(1×10⁴) cm³Hence, last option is the correct answer.
Based on the diagram, what is the difference in how economic decisions are made in a mixed economy and a market economy? E.1.2
How Economic Decisions are Made
By the Government,
command
economy
By the Consumers
mixed
economy
market.
economy
O Consumers make all economic decisions in a mixed economy, while the government makes all economic decisions in a market economy.
Government and consumers make economic decisions in a mixed economy, while consumers make economic decisions in a market economy.
Government makes all economic decisions in a mixed economy, while consumers make all economic decisions in a market economy.
O Consumers make economic decisions in a mixed economy, while consumers and government make economic decisions in a market economy.
Based on the diagram, the correct statement is: Government and consumers make economic decisions in a mixed economy, while consumers make economic decisions in a market economy.
How do we explain?In a mixed economy, economic decisions are made by both the government and consumers.
The government plays a significant role in regulating and influencing economic activities through policies, regulations, and interventions.
In market economy, economic decisions are primarily made by consumers. The market forces of supply and demand dictate the allocation of resources, production levels, and pricing.
The freedom to buy and sell whatever they choose is what ultimately determines how commodities and services are produced and distributed.
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A 1.70 m tall woman stands 5.00 m in front of a camera with a 50.00 cm focal
length lens. Calculate the size of the image formed on flim
Answer:
18.89cm
Explanation:
As we know that the person is standing 5m in front of the camera
\(d_0=5m=500cm\)
The focal length of the lens =50cm
f=50 cm
By Lens formula we have:
\(\dfrac{1}{f} = \dfrac{1}{d_i} + \dfrac{1}{d_o}\\\dfrac{1}{50} = \dfrac{1}{d_i} + \dfrac{1}{500}\\\dfrac{1}{d_i} =\dfrac{1}{50}-\dfrac{1}{500}\\\dfrac{1}{d_i}=0.018\\d_i=55.56cm\)
By the formula of magnification
\(\dfrac{h_i}{h_o} = \dfrac{55.56}{500}\\\\h_i = \dfrac{55.56}{500} \times h_o\\\\ h_o=1.70m=170cm\\\\Therefore: h_i=\dfrac{55.56}{500} \times$ 170 cm\\\\h_i =18.89 cm\)
The height of the image formed is 18.89cm.
Explain the process of refraction of light
The process of refraction of light occurs when light rays bends when travelling between media of different densities.
What is refraction of light?
Refraction of light is the bending of light rays or the change in the direction of light rays as it travels between media of different densities.
Light waves travel faster in media of less density than media of more density.
The change in density of the media makes light waves to be bend towards or away from the normal.
For example, when light travels from less dense air to more dense water, the light rays are bent towards the normal. However, when light rays travel from water to air, the light rays are refracted away from the normal.
In conclusion, refraction of light waves occur when light crosses the boundary of media of different densities.
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The motion of a ball on an inclined plane is described by the equation Ax = 1/2a(At)^2. This statement implies which of the following quantities has a value of zero?
Answer: Initial Velocity
Explanation:
The formula is:
Δx = Vit + 1/2at^2
Therefore the initial velocity is zero
7 x 7 x 7 x.........x 7 = n (30 times)
7 is multiplied 30 times to get a number n. Which of the following will be a factor of n?
The vapor pressure of liquid ethanol, C2H5OH, is 100. mm Hg at 308 K.
A sample of C2H5OH is placed in a closed, evacuated 529 mL container at a temperature of 308 K. It is found that all of the C2H5OH is in the vapor phase and that the pressure is 67.0 mm Hg. If the volume of the container is reduced to 344 mL at constant temperature, which of the following statements are correct?
Choose all that apply.
a. The pressure in the container will be 103 mm Hg.
b. Some of the vapor initially present will condense.
c. Liquid ethanol will be present.
d. Only ethanol vapor will be present.
e. No condensation will occur.
B
The statements that apply are;
The pressure in the container will be 103 mm Hg. Some of the vapor initially present will condense.Liquid ethanol will be present.What is the new pressure?We know that the pressure can be taken as the force with which the molecules of the substance are able to hit the walls of the container in this case, we need to obtain the pressure of the ethanol vapor when the volume has been reduced.
Using
P1 = initial pressure
P2 = final pressure
V 1 = initial volume
V2 = final volume
By the use of the Boyle's law we have;
P1V1 = P2V2
P2 = P1V1 /V2
P2 = 67.0 * 529/344
P2 = 103 mmHg
Thus, as the volume is reduced there would be an increase in the pressure and some of the ethanol would condense and we would have liquid ethanol in the system.
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how can the starch be removed from the leaves of potted plants
Answer:
Explanation:
There are two main ways to de-starch leaves of a plant - the 'Light Exclusion' Method and the 'Carbon Dioxide Deprivation' Method. The 'Light Exclusion' method is a simpler procedure and is used often. Leaves can be destarched by depriving them of light for an extended period of time, usually 24-48 hours.
magnitude of the gravitational field midway between the Earth and Moon? Ignore effects of the Sun.
Answer:
1.07×10−2m/s2 towards the center of the Earth.
At what temperature the velocity of sound is 2/3 of the velocity of sound at127’C?
Answer: 56.4
Explanation:
v=√γRTM
v=√xT T=127
2/3v = 2/3 √xT √127 = 11.
7.51 x 7.51 = 56.4
hope this helps!
Three people pull simultaneously on a stubborn donkey. Jack pulls eastward with a force of 80.5 N, Jill pulls with 81.7 N in the northeast direction, and Jane pulls to the southeast with 131 N. (Since the donkey is involved with such uncoordinated people, who can blame it for being stubborn
Answer:
F = 233.52 N, θ' = 351.41º
Explanation:
In this exercise we must find the net force applied on the donkey.
For this we use Newton's second law, where we create a reference frame with the horizontal x axis
let's decompose the forces
Jack
= 80.5 N
Jill
cos 45 = F_{2x} / F₂2
sin 45 = F_{2y} / F₂2
F_{2x} = F₂ cos 45
F_{2y} = F₂ sin 45
F_{2x} = 81.7 cos 45 = 57.77 N
F_{2y} = 81.7 sin 45 = 57.77 N
Jane
cos (270 + 45) = F_{3x} / F₃3
sin 315 = F_{3y} / F₃
F_{3x} = 131 cos 315 = 92.63 N
F_{3y} = 131 sin 315 = -92.63 N
the force can be found in each axis
X axis
F_{x} = F_{1x} + F_{2x} + F_{3x}
F_{x} = 80.5 +57.77 + 92.63
F_{x} = 230.9 N
Axis y
F_{y} = F_{1y} + F_{2y} + F_{3y}
F_{y} = 0 + 57.77 -92.63
F_{y} = -34.86 N
we can give the result in two ways
a) F = (230.9 i ^ - 34.86 j ^) N
b) in the form of module and angle
we use the Pythagorean theorem
F = √(Fₓ² + F_{y}²
F = √(230.9² + 34.86²)
F = 233.52 N
let's use trigonometry for the angle
tan θ = \(\frac{F_y}{F_x} }\)
θ = tan⁻¹ (\frac{F_y}{F_x} })
θ = tan⁻¹ (-34.86 / 230.9)
θ = -8.59º
if we measure this angle from the positive side of the x-axis counterclockwise
θ' = 360 -θ
θ‘= 360- 8.59
θ' = 351.41º
what is the value of pi(8.104)^2 written with correct significant numbers
Answer:206.3
Explanation:
Ex 11 ) A salmon jumps vertically out of the water at an initial velocity of 6 m/s. What is
the height it will jump?
Answer:
1.84m
Explanation:
Given parameters:
Initial velocity = 6m/s
Unknown:
height of jump = ?
Solution:
To solve this problem, we have to apply the right motion equation:
V² = U² - 2gH
V is the final velocity
U is the initial velocity
g is the acceleration due to gravity = 9.8m/s²
H is the height
Final velocity is 0
Solve;
0² = 6² - 2x9.8xH
-36 = -19.6H
H = 1.84m
A flat sheet of paper of area 0.450 m2 is oriented so that the normal to the sheet is at an angle of 600 to a uniform electric field of magnitude 18 N C-1. What is the magnitude of the electric flux through the sheet? A. 3.22 N m2 C-1 B. 21.42 N m2 C-1 C. 5.04 N m2 C-1 D. 11.72 N m2 C-1 E. 4.05 N m2 C
The magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹ (Option E).
The electric flux through a surface is given by the product of the electric field strength and the area of the surface projected perpendicular to the electric field.
In this case, the electric field strength is 18 N C⁻¹, and the area of the sheet projected perpendicular to the electric field is 0.450 m²
(since the normal to the sheet makes an angle of 60° with the electric field). Multiplying these values gives the electric flux:
Electric flux = Electric field strength × Area
Electric flux = 18 N C⁻¹ × 0.450 m²
Electric flux = 8.1 N m² C⁻¹
In summary, the magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹. This value is obtained by multiplying the given electric field strength by the projected area of the sheet perpendicular to the electric field.
The angle of 60° is taken into account to determine the effective area for calculating the flux.(Option E).
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Consider a double-paned window consisting of two panes of glass, each with a thickness of 0.500 cm and an area of 0.760 m2 , separated by a layer of air with a thickness of 1.65 cm . The temperature on one side of the window is 0.00 ∘C; the temperature on the other side is 23.0 ∘C. In addition, note that the thermal conductivity of glass is roughly 36 times greater than that of air. Approximate the heat transfer through this window by ignoring the glass. That is, calculate the heat flow per second through 1.65 cm of air with a temperature difference of 23.0 ∘C . (The exact result for the complete window is 24.4 J/s .)
The approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.
To approximate the heat transfer through the air layer in the double-paned window, we can assume that the glass layers have a negligible impact on the heat flow. The heat transfer can be calculated using Fourier's Law of Heat Conduction, which states that the heat flow (Q) is proportional to the temperature difference (ΔT) and inversely proportional to the thickness (L) and thermal conductivity (k) of the material.
First, we need to calculate the effective thermal conductivity of the air layer due to its thickness and the thermal conductivity ratio between air and glass. Let's denote the thermal conductivity of air as k_air and the thermal conductivity of glass as k_glass. Since glass has a thermal conductivity roughly 36 times greater than air, we have k_glass = 36 * k_air.
Next, we calculate the effective thermal conductivity of the air layer as:
k_eff = (k_air * L_air) / (L_air + k_glass)
Substituting the given values, we have:
k_eff = (k_air * 0.0165 m) / (0.0165 m + 0.005 m) = 0.01309 * k_air
Now, we can calculate the heat flow per second through the air layer using the formula:
Q = (k_eff * A * ΔT) / L_air
Substituting the given values, we get:
Q = (0.01309 * k_air * 0.760 m^2 * 23.0 K) / 0.0165 m = 24.4 J/s
Therefore, the approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.
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12. By convention (agreement of the scientific community for consistency)
magnetic field lines...
A. always start on the north pole and terminate (end) on the South Pole
B. start at infinity and point toward each pole
C. start at each pole and go outward
D. always start on the south pole and terminate (end) on the north pole.
Answer:
. always start on the north pole and terminate (end) on the South Pole
Explanation:
How can land that was formerly used as dumps, mines, or factory sites be.
rehabilitated?
Answer:
clear out the junk, and plant some stuff
Explanation:
clear out all of the nasties, unless it is biodegradable, or you could get some mushrooms to break everything down, then you can go and plant some stuff or do whatever. You could turn it into a playground, park, whatever.
Roughly speaking, the radius of an atom is about 10,000 times greater than that of its nucleus. If an atom were magnified so that the radius of its nucleus became 2.0 cm, about the size of a marble, what would be the radius of the atom in miles
Answer:
0.124 miles
Explanation:
Since the radius of the atom R = 10000r where r = radius of nucleus. Now, if r = 2.0 cm = 0.02 m,
R = 10000r
= 10000 × 0.02 m
= 200 m
We know that 1 mile = 1609 m.
So the radius of the atom in miles is R = 200 m × 1 mile/ 1609 m = 0.124 miles
So, the radius of the atom in miles is 0.124 miles
20. In the figure, voltmeter V1 reads 600 V, voltmeter V2 reads 580 V, and ammeter A reads 100 A. The power wasted in the transmission line connecting the power house to the consumer is
The power wasted in the transmission line connecting the power house to the consumer is 2kW.
The equation Power = Potential difference*Current, or P = VI, can be used to compute the amount of energy that is wasted.
We can see that it is given,
V1 = 600 V
V2 = 580 V
Current= I = 100 A
We need to figure out how much energy is lost in the transmission line that runs from the generator to the consumer.
In physics, power is the amount of energy that is transferred or transformed in a given amount of time.
The International System of Units uses the watt, or one joule per second, as the unit of power.
The formula for the voltage across the transmission line is V = V1 - V2.
Thus, V = 600 - 580
V = 20V
We've been told that I equals 100 A.
The power loss equation is given by P = VI, where V is the potential difference and I is the current.
Power loss = VI, therefore becomes
P = 20 × 100
P = 2000 W
P = 2kW
Therefore, 2 kW of power is lost in the transmission line that connects the power source to the customer.
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Use the graph to answer the following questions.
Answers have a 5 % tolerance to allow for estimation.
Note that slope may be positive or negative.
What is the y-intercept of the graph?
What is the slope of the graph?
What is the area under the graph?
It is to be noted that the y-intercept of the graph is 20. The slope is -0.2; while the area under the graph is: 840
How do you find the intercept?At x = 0, the value of y is 20. Hence the intercept of the graph is 20.
To compute the slope, recall that the graph passes through points (0, 20) and (60, 8) hence the solution of the graph is given as:
Change in y coordinate/Change in x coordinate
= (8-20)/60-0)
= -12/60
= -1/5 or -0.2
The area under the graph compares a right-angled triangle and a rectangle. To get the area under the graph we need to find the sum of the areas of both shapes.
Recall that Area of a Right Angled Triangel is given as 1/2 B*H
Hence
⇒ 1/2 * 12 * 60
= 360
The area of a rectangle is L x B
Hence
⇒ 8 x 60
= 480
Thus, the area under the graph is
360 + 480
= 840
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at what speed is the top of the ladder along w the electrician sliding down the wall at that instant
The given problem can be exemplified in the following diagram:
We are given that a ladder is against a wall. According to the diagram, the ladder, the wall, and the floor form a right triangle, therefore, if "T" is the distance from the top to the floor and "B" is the distance from the bottom to the wall we can apply the Pythagorean theorem and we get:
\(T^2+B^2=14^2\)Now, since we want to know the speed, we will derivate implicitly with respect to time on both sides of the equation:
\(2T\frac{dT}{dt}+2B\frac{dB}{dt}=0\)Now we solve for the value of the speed of the top of the ladder, this is dT/dt:
\(2T\frac{dT}{dt}=-2B\frac{dB}{dt}\)The 2 cancels out:
\(T\frac{dT}{dt}=-B\frac{dB}{dt}\)Now we divide both sides by "T":
\(\frac{dT}{dt}=-\frac{B}{T}\frac{dB}{dt}\)Now, since we determine the value of "T" from the Pythagorean theorem, we get:
\(T^2+B^2=14^2\)Subtracting B squared from both sides:
\(T^2=14^2-B^2\)Taking the square root:
\(T=\sqrt[]{14^2-B^2}\)Now we replace these values in the formula for the velocity:
\(\frac{dT}{dt}=-\frac{B}{\sqrt[]{14^2-B^2}}\frac{dB}{dt}\)Now we have an expression for the velocity of the top of the ladder. Replacing the given values:
\(\frac{dT}{dt}=-\frac{6ft}{\sqrt[]{14^2-(6ft)^2}}(1\frac{ft}{s})\)Solving the operations we get:
\(\frac{dT}{dt}=-0.47\frac{ft}{s}\)Therefore, the speed of the top of the ladder is -0.47 feet per second.
When rubbing two insulators together, the one that gets a positive charge has had:______.a) protons added. b) protons removed. c) electrons added. d) electrons removed.
Answer:
d) electrons removed.
Explanation:
Two insulators are electrically neutral, that is, the number of electrons and protons are equal. When one insulator is rubbed against another, electrons are removed from one of the insulators due their high mobility. The insulator which lost the electrons becomes positively charged while the one that gained the electron becomes negatively charged.
Therefore, when rubbing two insulators together, the one that gets a positive charge has had electrons removed.
A child on a bridge throws a rock straight down to the water below. The point where the child released the rock is 74 m above the water and it took 2.7 s for the rock to reach the water. Determine the rock's velocity (magnitude & direction) at the moment the child released it. Also determine the rock's velocity (magnitude & direction) at the moment it reached the water. Ignore air drag.
The rock's altitude y at time t, thrown with initial velocity v, is given by
\(y=74\,\mathrm m+vt-\dfrac12gt^2\)
where \(g=9.80\frac{\rm m}{\mathrm s^2}\) is the acceleration due to gravity.
After t = 2.7 s, the rock reaches the water (0 altitude), so
\(0=74\,\mathrm m+v(2.7\,\mathrm s)-\dfrac12g(2.7\,\mathrm s)^2\)
\(\implies v=-\dfrac{74\,\mathrm m-\frac g2(2.7\,\mathrm s)^2}{2.7\,\mathrm s}\approx-14.177\dfrac{\rm m}{\rm s}\)
so the rock was thrown with a velocity with magnitude 14 m/s and downward direction.
Its velocity at time t is \(v-gt\) (with no horizontal component), so that at the moment it hits the water, its velocity is
\(v-g(2.7\,\mathrm s)\approx-40.637\dfrac{\rm m}{\rm s}\)
That is, its final velocity has an approximate magnitude of 41 m/s, also directed downward.
The velocity time graph of an object mass 50 g is shown in figure study graph and answer
1)calculate force acting on object in time interval 0-3 seconds
2)calculate the force acting on the object in the time interval 6-10 seconds
3)Is there any time interval in which no force acts on object.Justify
1) The force acting on the object during the time interval 0-3 seconds is 1/3 N.
2) The force acting on the object during the time interval 6-10 seconds is -0.5 N.
3) There is no time interval in which no force acts on the object.
(i) Force acting on the object in time interval 0-3 seconds. Force acting on the object is equal to the product of its mass and acceleration, i.e.,F = ma.
In the given velocity-time graph, the acceleration of the object can be determined by determining the slope of the velocity-time graph from 0 to 3 seconds.
Slope = (change in velocity) / (change in time)= (20-0) / (3-0) = 20/3 m/s^2
Acceleration, a = slope= 20/3 m/s^2
Mass of the object, m = 50 g = 0.05 kg
∴ Force acting on the object, F = ma= 0.05 × 20/3= 1/3 N.
Therefore, the force acting on the object during the time interval 0-3 seconds is 1/3 N.
(ii) Force acting on the object in time interval 6-10 seconds. Similar to the first question, the force acting on the object in time interval 6-10 seconds can be determined by determining the acceleration of the object during this time interval.
The slope of the velocity-time graph from 6 seconds to 10 seconds can be determined as follows:
Slope = (change in velocity) / (change in time)= (-20-20) / (10-6) = -40/4= -10 m/s^2 (negative sign indicates that the object is decelerating)
Mass of the object, m = 50 g = 0.05 kg
∴ Force acting on the object, F = ma= 0.05 × (-10)= -0.5 N.
Therefore, the force acting on the object during the time interval 6-10 seconds is -0.5 N.
(iii) Time interval in which no force acts on the object. There is no time interval in which no force acts on the object. This is because, as per Newton's first law of motion, an object will continue to remain in a state of rest or uniform motion along a straight line unless acted upon by an external unbalanced force.In other words, if the object is moving with a constant velocity, there must be a force acting on the object to maintain its motion.
Therefore, there is no time interval in which no force acts on the object.
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