if a solution looks blue, it is absorbing light with around a 600nm wavelength. This statement is true.
This is because the blue appearance is a result of the solution absorbing the complementary color of blue, which is in the range of 600nm, and reflecting or transmitting the blue light that our eyes perceive.
Wavelength is the distance between identical points (adjacent crests) in the adjacent cycles of a wave form signal propagated in space or along a wire. In wireless systems, this length is usually specified in meters (m), centimeters (cm) or millimeters (mm).In the case of infrared (IR), visible light, ultraviolet (UV), and gamma radiation (γ), the wavelength is more often specified in nanometers (nm), which are units of 10⁻⁹ m, or angstroms (Å), which are units of 10⁻¹⁰ m.
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What are two ways to create a negative ion?
What are two ways to create a positive ion?
Answer:
what that guy said
Explanation:
because he provides evidence
calculate the magnetic force on an airplane which has acquired a net charge of 1540 μc and moves with a speed of 100 m/s perpendicular to the earth's magnetic field of 5.0×10−5t .
Answer:
7.7 × 10^-10 N
Explanation:
To calculate the magnetic force on the airplane, we need to use the formula:
F = qvBsinθ
where:
F = magnetic force
q = net charge
v = velocity of the airplane
B = strength of the magnetic field
θ = angle between the velocity and magnetic field
In this case, the net charge is given as 1540 μc, which we can convert to Coulombs:
q = 1540 μC = 1.54 × 10^-6 C
The velocity of the airplane is given as 100 m/s, and the strength of the Earth's magnetic field is 5.0 × 10^-5 T. However, we also need to know the angle between the velocity and magnetic field. If the airplane is moving perpendicular to the magnetic field, then θ = 90°, which means that sinθ = 1.
Now we can plug in the values and calculate the magnetic force:
F = qvBsinθ
F = (1.54 × 10^-6 C)(100 m/s)(5.0 × 10^-5 T)(1)
F = 7.7 × 10^-10 N
Therefore, the magnetic force on the airplane is 7.7 × 10^-10 N.
*IG:whis.sama_ent
the spring-like property that returns muscle to its original length after a contraction ends is
The spring-like property that returns a muscle to its original length after a contraction ends is known as muscle elasticity. When a muscle contracts, it generates force and shortens in length. This contraction is achieved by the sliding of actin and myosin filaments within the muscle fibers.
However, once the contraction is over and the force is no longer applied, the muscle has the remarkable ability to return to its original length.
Muscle elasticity is attributed to two main factors: the structural arrangement of proteins within the muscle fibers and the connective tissue surrounding the muscle.
The proteins act as molecular springs that can be stretched and then recoil back to their original position when the force is released. This property allows the muscle to efficiently generate and transmit forces during movement.
Additionally, the connective tissue, such as tendons and fascia, surrounding the muscle acts as a supportive framework. It stores and releases energy during muscle contractions, assisting in the recoil and restoration of the muscle's original length.
Overall, muscle elasticity is essential for the proper functioning of our musculoskeletal system, allowing us to move efficiently and smoothly while maintaining the integrity of our muscles.
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what units is time measured in
Answer:
The base unit for time is the second (the other SI units are: metre for length, kilogram for mass, ampere for electric current, kelvin for temperature, candela for luminous intensity, and mole for the amount of substance). The second can be abbreviated as s or sec.
Explanation:
If € ₁ 4. 0 V. & 2 = 12. 0 V, R₁ = 40, R₂ = 1202, C-3 μF, Q = 18 μC, and I = 2. 5 A, what is the potential difference V, - V? b- 5. 0 V O-5. 0 V 30 V O-30 V & - 1. ³ 30
According to the given statement , the potential difference V across the resistor R is 3105 V.
To find the potential difference V, we can use Ohm's Law and the formula for the potential difference across a capacitor.
First, let's calculate the current flowing through the circuit. We are given that I = 2.5 A.
Next, we can calculate the total resistance in the circuit using the formula R = R₁ + R₂. Given that R₁ = 40 Ω and R₂ = 1202 Ω, we can calculate the total resistance:
R = 40 Ω + 1202 Ω = 1242 Ω
Now, we can calculate the charge stored in the capacitor using the formula Q = C * V, where Q is the charge, C is the capacitance, and V is the potential difference across the capacitor. We are given that Q = 18 μC and C = 3 μF. Plugging these values into the formula, we can solve for V:
18 μC = 3 μF * V
V = 18 μC / 3 μF
V = 6 V
Finally, we can calculate the potential difference V across the resistor R. Using Ohm's Law, we can use the formula V = I * R:
V = 2.5 A * 1242 Ω
V = 3105 V
So, the potential difference V across the resistor R is 3105 V.
In conclusion, the potential difference V across the resistor R is 3105 V.
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When the car was stopped by the tree, its change in velocity during the collision was -6 meters/second. This change in velocity occurred in 2 seconds. What was the acceleration of the car?
.) What force is causing the ball to speed up down the ramp?
the answer is gravity
gravity pulls things down
1. sounds are produced ___________by ?
Sounds are produced by vibrations.
Sounds are produced by vibration.
Hope it helps! byeeee
To explore the bottom of a 25-m-deep lake, your friend Tom proposes to get a long garden hose, put one end on land and the other in his mouth for breathing underwater, and descend into the depths. Susan, who overhears the conversation, reacts with horror and warns Tom that he will not be able to inhale when he is at the lake bottom.
Why is Susan so worried?
The pressure at a depth 01 25 m is 3 x 10^5 Pa. This is almost three times greater than atmospheric pressure. But he air pressure in the hose will be only slightly higher than atmospheric pressure, because the density of air is so low. So Tom will have great difficulty breathing in the low-pressure air when the large pressure of the water is pressing in on his chest.
The pressure at a depth 01 25 m is 3.5 x 10^5 Pa. This is almost 3.5 times greater than atmospheric pressure. But he air pressure in the hose will be only slightly higher than atmospheric pressure, because the density of air is so low. So Tom will have great difficulty breathing in the low-pressure air when the large pressure of the water is pressing in on his chest.
The pressure at a depth 01 25 m is 2 x 10^5 Pa. This is almost two times greater than atmospheric pressure. But he air pressure in the hose will be only slightly higher than atmospheric pressure, because the density of air is so low. So Tom will have great difficulty breathing in the low-pressure air when the large pressure of the water is pressing in on his chest.
The pressure at a depth 01 25 m is 2.5 x 10^5 Pa. This is almost 2.5 times greater than atmospheric pressure. But he air pressure in the hose will be only slightly higher than atmospheric pressure, because the density of air is so low. So Tom will have great difficulty breathing in the low-pressure air when the large pressure of the water is pressing in on his chest.
Answer:
The pressure at a depth 01 25 m is 2.5 x 10^5 Pa. This is almost 2.5 times greater than atmospheric pressure. But he air pressure in the hose will be only slightly higher than atmospheric pressure, because the density of air is so low. So Tom will have great difficulty breathing in the low-pressure air when the large pressure of the water is pressing in on his chest.
Explanation:
The depth is h = 25 m
The density of water p = 1000 kg/m^3
Acceleration due to gravity g = 9.81 m/s^3.
Pressure due to a depth is gotten from
P = pgh
P = 1000 x 9.81 x 25 =245250 Pa
==> 2.45 x 10^5 Pa
Approximately 2.5 x 10^5 Pa
Atmospheric pressure = 1.01325 x 10^5 Pa
Dividing the pressure at the bottom of the pond by the atmospheric pressure gives a value of about 2.5,which means that the pressure is 2.5 times the atmospheric pressure.
a 4.40-m-long, 500 kg steel uniform beam extends horizontally from the point where it has been bolted to the framework of a new building under construction. a 70 kg construction worker stands at the far end of the beam.
The magnitude of the torque about the bolt due to the worker and the weight of the beam is 13,798.4 Nm
What is the magnitude of the torque?The length of the steel = \(r_{2}\) = 4.4 m
The mass of the steel= \(m_{1}\) = 500 kg
The mass of the worker = \(m_{2}\) = 70 kg
Let , the total torque = \(\tau_{t}\)
The centre of gravity = \(r_{1}\)
=4.4/2
= 2.2
\(\tau_{t} = \tau_{1} +\tau_{2}\\\\\tau_{t} = F_{1}r_{1} + F_{2}r_{2} \\\\\text{We know that},F = mg \\\\\tau_{t} = m_{1}gr_{1} + m_{2}gr_{2}\\\\\tau_{t} = (500* 9.8* 2.2) +(70*9.8* 4.4)\\\\\tau_{t} = 13,798.4 Nm\)
The magnitude of the torque about the bolt due to the worker and the weight of the beam is 13,798.4 Nm.
What is torque?The force that may twist an item about its axis is measured as torque. Torque is what causes an object to acquire angular acceleration, just as force is what causes an object to accelerate in linear kinematics. Torque is a vector quantity.Torque is a twisting or turning force that frequently results in rotation around an axis, which may be a fixed point or the centre of mass. The ability of something rotating, such as a gear or a shaft, to overcome turning resistance is another way to think of torque.The complete question is:
A 4.40-m-long, 500 kg steel uniform beam extends horizontally from the point where it has been bolted to the framework of a new building under construction. A 70 kg construction worker stands at the far end of the beam. What is the magnitude of the torque about the bolt due to the worker and the weight of the beam?
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Coincidence?
stu(died)
stu(dying)
stu(dies)
when a 0.30 kg mass is suspended from a massless spring, the spring stretches a distance of 2.0 cm. let 2.0 cm be the rest position for the mass-spring system. the mass is then pulled down an additional distance of 1.5 cm and released.calculate the period of resulting oscillation in si units.
When a 0.30 kg mass is suspended from a massless spring, the spring stretches a distance of 2.0 cm, with an additional distance of 1.5cm,
Mass m= 0.30 kg
Distance x = 2.0 + 1.5 cm = 0.035 m
Since spring constant k = \({\frac{mg}{x}\) , (g=9.81)
k = \({\frac{0.3*9.81}{0.035}\) = 84.085 N/m
ω = \(\sqrt{\frac{k}{m} }\) = \(\sqrt{\frac{84.085}{0.3} }\) = 16.74 rad/sec
T = \(\frac{2\pi }{w}\) = \(\frac{2*3.14}{16.74}\) = 0.375 sec
The spring constant is the force required to stretch or compress the spring divided by the distance the spring is lengthened or shortened. It is used to determine the stability or instability of a spring and thus the system for which it is intended.
Therefore the time period of resulting oscillation is 0.375 sec.
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pls help asap!!
physics
need an answer
Answer:
double
Explanation:
ASAP I WILL GIVE BRAINLIEST A big wheel with triple the circumference of a smaller wheel will rotate with ____ the force. Group of answer choices
Answer:
A big wheel with triple the circumference of a small wheel will rotate with triple the force.
Explanation:
when this circumference is tripled, it means triple the force (they are directly correlated)If an owl produces two pellets every 24 hours and each pellet contains the remains of 3 prey, how much does it eat in a week? A month?
The owl eats 42 prey in a week and 180 prey in a month.
To calculate how much the owl eats in a week and a month, we need to determine the number of prey consumed in each time period.
In a week:
The owl produces two pellets every 24 hours. So, in one day, it consumes 2 * 3 = 6 prey (since each pellet contains the remains of 3 prey).
In a week (7 days), the owl consumes 6 * 7 = 42 prey.
In a month:
Assuming a month has 30 days (though some months have 31 days or 28/29 days), we can calculate the number of prey consumed in a month.
In a day: 6 prey
In a month (30 days): 6 * 30 = 180 prey.
Hence, the owl eats 42 prey in a week and 180 prey in a month.
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ocean waves are hitting a beach at a rate of 3.2 Hz. What is the period of the waves?
\( \Large\begin{gathered} {\underline{\boxed{ \rm {\purple{Period \: = \: \frac{1}{Frequency} }}}}}\end{gathered} \)
Solution :Now , put the values in the given formula
\(\rm \large \red \rightarrow \:Period \: = \: \cancel\frac{1}{3.2} \: = \: 0.31s \\ \)
The period of the ocean waves hitting the beach is 0.3125 s.
What is period of oscillation?The period of an oscillation is the time taken for an oscillating particle to complete a cycle.
The period of an oscillation is inversely proportional to the frequency of an oscillation.
\(T = \frac{1}{f} \\\\ T = \frac{1}{3.2} \\\\ T = 0.3125 \ s\)
Thus, the period of the ocean waves hitting the beach is 0.3125 s.
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Which of the following has potential but not kinetic energy? (2 points)
a roller coaster zooming down a hill
b child riding their bike
c bird flying from a tree
d ball sitting on a shelf
Answer:
D
Explanation:
If the ball was in motion there would be kinetic energy but as there is no movement there is no kinetic energy only potential
Two waves have the same frequency. What other characteristic must be the same for these waves?.
The wave characteristic that is the same for both waves is wavelength.
Two waves with the same frequency will also have the same wavelength, amplitude, speed, and period. When two waves are travelling at the same frequency, it denotes that their duration and amplitude are also the same.When two waves of the same frequency and amplitude interfere constructively, their peaks and troughs align as shown in diagram A above. As a result, the original waves' amplitude is doubled, resulting in a sound wave that is twice as loud.Thus, Equal frequencies are shared by two waves moving through the same region in the same direction.
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which three workers use technologies that apply the Doppler effect
A. an ultrasound technician
B. a pilot who needs to avoid bad weather
C. an insurance building inspector
D. a race-car mechanic
The three workers that use technologies that apply the Doppler effect are;
an ultrasound techniciana pilot who needs to avoid bad weathera race-car mechanicWhat is the Doppler effect?The term Doppler effect has to do with an increase or decrease in the frequency of sound as the observer moves towards or away from the source of the sound.
We know that;
fo = (v + vo/v + vs) fs
fo = frequency of the observer
v = velocity of sound
vs = velocity of source of sound
vo = velocity of observer
fs = true velocity of sound
The three workers that use technologies that apply the Doppler effect are;
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What needs to be done to balance this equation?
Question 4 options:
Do nothing (equation is balanced).
Change O 2 to O 4 on the left side of the equation.
Add coefficient 2 to O 2 on the left side of the equation.
Remove coefficient 2 in front of H 2O on the right side of the equation.
Answer:
Add the coefficient 2 to O2 on the left side of the equation. (O2 represents a molecule of oxygen gas)
The equation shows an equal number of H atoms and C atoms on either side, but the number of O atoms must also balance.
Based on einstein's theory of gravity, if the sun and its mass were suddenly to disappear, earth would:________
Based on Einstein's theory of gravity, if the sun and its mass were to suddenly disappear, earth would stay in its current orbit for a few minutes before taking off into space.
What would occur to our world if the sun were to suddenly vanish?
The Earth would be drawn to a new center of gravity if the sun disappeared. Earth's gravity would change, as would that of the rest of the solar system, and Earth would begin to drift into space since there would no longer be a steady source of energy from the sun. It is a foolish dream to think that life could exist without the sun forever. Humans could be able to survive for a while in some sort of base, such as a nuclear-powered dome.
The good news is that there wouldn't be many living things for the radioactive waste to endanger; however, there also probably wouldn't be any liquid water to cool the power system. All photosynthetic species, including plants and algae, would die if just the sun's light persisted.
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a student pushed a 100 N bicycle over a distance of 15 m in 5 s. calculate the power generated.
The catch in this one is: We don't know how much force the student used to push the bike.
It wasn't necessarily the 100N. That's just the weight of the bike. But you know that you can push a car, a wagon, or a bicycle hard, you can push it not so hard, you can give it a little push, you can give it a big push, you can push it strong, you can push it weak, you can push it medium. The harder you push, the more it'll accelerate, but it's completely up to you how hard you want to push. That's what's so great about wheels ! That's why they were such a great invention ! This is where I made my biggest mistake. This guy came into my store one day and said he's got this great invention, it's definitely going to take off, it'll be a winner for sure, he called it a "wheel". I looked at it, I turned it over and I looked on all sides. I thought it was too simple. I didn't know then it was elegant. I threw him out. I was so dumb. I could have invested money in that guy, today I would have probably more than a hundred dollars.
Anyway, can we figure out how much force the student used to push with ? Stay tuned:
-- The bike covered 15 meters in 5 seconds. Its average speed during the whole push was (15m/5s) = 3 meters/sec.
-- If the bike started out with no speed, and its average speed was 3 m/s, then it must have been moving at 6 m/s at the end of the push.
-- If its speed increased from zero to 6 m/s in 5 seconds, then its acceleration was (6m/s / 5 sec) = 1.2 m/s²
-- The bike's weight is 100N.
(mass) x (gravity) = 100N
Bikemass = (100N) / (9.8 m/s²)
Bikemass = 10.2 kilograms
-- F = m A
Force = (mass) x (acceleration)
Force = (10.2 kg) x (1.2 m/s²)
Force = 12.24 N
-- Work = (force) x (distance)
Work = (12.24 N) x (15 m)
Work = 183.67 Joules
-- Power = (work done) / (time to do the work)
Power = (183.67 joules) / (5 seconds)
Power = 36.73 watts
The absorption of longwave radiation by certain gases in the lower atmosphere is responsible for: A) photon effect. B) atmospheric window effect. C) greenhouse effect.
The absorption of longwave radiation by certain gases in the lower atmosphere is responsible for the greenhouse effect, which is a key contributor to global warming and climate change. The atmospheric window effect and photon effect are related phenomena but do not directly contribute to the greenhouse effect.
The absorption of longwave radiation by certain gases in the lower atmosphere is responsible for the greenhouse effect. This effect occurs when gases such as carbon dioxide, water vapor, and methane trap heat from the sun in the Earth's atmosphere, preventing it from escaping into space. This trapped heat leads to an increase in the average temperature of the Earth's surface, causing global warming and climate change.
The atmospheric window effect, on the other hand, refers to the phenomenon where certain wavelengths of radiation are not absorbed by the Earth's atmosphere, allowing them to pass through and escape into space. This occurs in the region of the electromagnetic spectrum where the atmosphere is relatively transparent, such as in the visible and near-infrared portions.
The photon effect, on the other hand, refers to the behavior of photons, which are packets of energy that make up electromagnetic radiation. The absorption of radiation by gases in the atmosphere occurs through the interaction of photons with molecules in the air. When a photon is absorbed, its energy is transferred to the molecule, causing it to vibrate and rotate. This can lead to changes in the temperature and chemical composition of the atmosphere.
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What does NOT experience gravity?
Answer:
Astronauts who are orbiting the Earth often experience sensations of weightlessness. These sensations experienced by orbiting astronauts are the same sensations experienced by anyone who has been temporarily suspended above the seat on an amusement park ride. Not only are the sensations the same (for astronauts and roller coaster riders), but the causes of those sensations of weightlessness are also the same. Unfortunately however, many people have difficulty understanding the causes of weightlessness.
2.
The direction of the electric field vector is defined as
Answer:
The direction of the field is defined by the direction of the force it would put on a positive charge. So if it tells you that the force on a positive charge will be in the same direction as the field, but the force on a negative charge will be in the opposite direction.
Answer: F= qE
Explanation:
The electric field from a positive charge points away from the charge; the electric field from a negative charge points toward the charge. Like the electric force, the electric field E is a vector. F= qE If q is positive, the force is in the same direction as the field; if q is negative, the force is in the opposite direction as the field.
A small 8. 00-kg rocket burns fuel that exerts a time-varying upward force on the rocket. This force obeys the equation F = α + βt2. Measurements show that at t = 0, the force is 100. 0N, and at the end of the first 2. 00 s, it is l50. 0N. Find the net force on this rocket and its acceleration the instant after the fuel ignites
The net force on the rocket at the instant after the fuel ignites can be found by using the equation F = α + βt2. We are given that at t = 0, the force is 100.0N, and at t = 2.00s, the force is 150.0N. We can use these values to find the constants α and β.
At t = \0, F = 100.0N:
100.0N =\ α + β(0)^2
α = \100.0N
At t = \2.00s, F = 150.0N:
150.0N =\ α + β(2.00s)^2
150.0N = 100.0N + β(4.00s^2)
β =\ 12.5N/s^2
ow we can plug these values back into the equation to find the net force at the instant after the fuel ignites (t = 0):
F = α + βt^2
F = \100.0N + 12.5N/s^2(0)^2
F = 100.0N
The acceleration of the rocket can be found by using Newton's second law, F = ma:
100.0N = 8.00kg(a)
a = 12.5m/s^2
Therefore, the net force on the rocket at the instant after the fuel ignites is 100.0N, and its acceleration is 12.5m/s^2.
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An ice skater spins at 2.5 rev/s when his arms are extended. He draws his arms in and spins at 10.0 rev/s. By what factor does his moment of inertia change in the process?
Answer:
The moment of inertia decreased by a factor of 4
Explanation:
Given;
initial angular velocity of the ice skater, ω₁ = 2.5 rev/s
final angular velocity of the ice skater, ω₂ = 10.0 rev/s
During this process we assume that angular momentum is conserved;
I₁ω₁ = I₂ω₂
Where;
I₁ is the initial moment of inertia
I₂ is the final moment of inertia
\(I_2 = \frac{I_1 \omega_1}{\omega_2} = \frac{I_1*2.5}{10} \\\\I_2 = 0.25I_1 = \frac{1}{4}I_1\)
Therefore, the moment of inertia decreased by a factor of 4
technician a says the charging system is needed to keep the battery fully charged and recharge the battery after starting. technician b say the charging system supplies all the vehicle's electrical current needs after the engine starts. who is correct?
Answer:
Technician A is correct
Explanation:
The statement "charging system is needed to keep the battery fully charged and recharge the battery after starting" is correct
from technician's B point of view, that the charging system supplies electrical current needs after engine start is incorrect.
In-fact the charging system is dedicated to the battery alone, the electrical needs of the system is gotten from the battery.
hewoooooo pweese help ill do anything
A bus slows from 40 m/s to a stop in 8 seconds. How far does it travel while braking?
Answer:
320 m/s
Explanation:
40 miles per second and 8 seconds makes 40 times 8
hii! help asap. i’ll give brainliest thanks!
Answer:
a i believe
Explanation: