Enzyme reaction rates Consider the illustration below. What variable might be on the horizontal axis? (Click on all that apply) Temperature pH
Activation energy Competitive inhibitor concentration Rate of reaction Noncompetitive inhibitor concentration Salt concentration
In general, a reaction is sped up by increasing temperature and slowed down by decreasing temperature. But extremely high temperatures can denature an enzyme, causing it to lose its form and cease functioning.
How is the rate of reaction affected by variations in pH or temperature?As enzymes have a maximum temperature and pH at which their rate is maximal, temperature and pH can both raise or reduce the enzyme reaction rate. The pace of reaction for the enzyme will be slowed down by changes in temperature and pH that are not optimal.
Which of the following factors will speed up an enzyme reaction?An enzyme's concentration increases along with the speed of an enzyme-catalyzed process. An enzyme-catalyzed process accelerates with rising temperatures at low temperatures. The protein is denatured at higher temperatures, which also causes a sharp drop in reaction rate.
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A response is typically sped up by rising temperature and slowed down by falling temperature. However, exceedingly hot temperatures can denature an enzyme, causing it to lose its shape and stop working.
Temperature and pH have the ability to increase and decrease the rate of an enzyme reaction since enzymes have a maximum temperature and pH at which they function at their highest rate. Unfavorable variations in temperature and pH will cause the enzyme's reaction to proceed more slowly. The rate of an enzyme-catalyzed process increases as the concentration of the enzyme rises. When temperatures are low, an enzyme-catalyzed reaction speeds up as they rise. At higher temperatures, the protein is denatured, which also results in a dramatic decrease in response rate.
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A person throws a ball from height of 6 feet with an initial
vertical velocity of 48 feet per second. Use the vertical motion
model, h = - - 16t2 + vt +s, where v is the initial velocity in
feet per second and s is the height in feet, to calculate the
amount of time the ball is in the air before it hits the ground
again. Round your answer to the nearest tenth if necessary.
time in air: _____ seconds
Answer:
3.1 s
Explanation:
use the quadratic formula
x = −b + √(b2 − 4ac)/2a
where a=-16 b=48 (the velocity) and c=6 (the height)
You apply a net force on a soccer ball of 15 N. If the acceleration it has is 5 m/s2 what is the mass of the ball?
Answer:
3 kgExplanation:
The mass of the ball can be found by using the formula
\(m = \frac{f}{a} \\ \)
f is the force
a is the acceleration
We have
\(m = \frac{15}{5} = 3 \\ \)
We have the final answer as
3 kgHope this helps you
What is a pendulum?
A.)A pendulum is a grandfather clock.
B.)A pendulum is a mass suspended on the bottom of a string.
C.)A pendulum is several weights tied together and arranged in a circle.
D.) A pendulum is the time it takes for a bob to swing back and forth one time.
B) A pendulum is a mass suspended on the bottom of a string.
A pendulum is a simple mechanical device that consists of a mass (known as the bob) suspended from a fixed point by a string, wire, or rod. When the bob is pulled to one side and released, it swings back and forth under the influence of gravity, forming a regular pattern of motion. The time it takes for the pendulum to complete one full swing (i.e., from one extreme position to the other and back again) is known as its period. The period of a pendulum is affected by the length of the string and the strength of gravity. The longer the string, the longer the period, and the stronger the gravity, the shorter the period.Pendulums have a wide range of practical applications, such as timekeeping, as seen in grandfather clocks. They are also used in scientific experiments to measure time intervals and gravitational acceleration.
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Graph. See text version for more detail.
The graph above represents the nuclear decay of a radioactive element, measured using a radiation-detecting device. What is the half-life, in days, of this hypothetical element?
If the half-life of a given substance is 65 days, how long will it take for a 100-gram sample of the substance to decay until there is only 25 grams of the radioactive material remaining?
If a sample of radioactive isotopes takes 60 minutes to decay from 200 grams to 50 grams, what is the half-life of the isotope? Hint: First, determine how many times the sample has lost half of its mass, which tells you how many half-life cycles have occurred.
If a 500.0 g sample of technetium-99 decays to 62.5 g of technetium-99 remaining in 639,000 years, what is the half-life of technetium-99?
The half-life of hypothetical element technetium-99 is 210,936 years.
Half-life of the hypothetical element From the graph provided in the question, the half-life of the hypothetical element can be obtained by finding the time taken for the element to reduce to half its original quantity. Here, it can be seen from the graph that the quantity of the element reduces from 40 to 20 on day 4. Therefore, the half-life of the hypothetical element is 4 days.2. Time taken for a sample to decay from 100 grams to 25 gramsIf the half-life of a given substance is 65 days, then the quantity of the substance reduces to half every 65 days. From 100 grams to 50 grams, it takes one half-life cycle. From 50 grams to 25 grams, it will take another half-life cycle.
Therefore, it will take two half-life cycles, which is 2 × 65 = 130 days, for a 100-gram sample of the substance to decay until there is only 25 grams of the radioactive material remaining.3. Half-life of a sample that decays from 200 grams to 50 grams in 60 minutesIt is given that the sample of radioactive isotopes takes 60 minutes to decay from 200 grams to 50 grams. To find the half-life, we need to determine how many times the sample has lost half of its mass, which tells you how many half-life cycles have occurred.At 30 minutes, the sample reduces to half its original quantity, which is 100 grams. At 45 minutes, it reduces to 50 grams, which is half of 100 grams. Therefore, it takes two half-life cycles to reduce from 200 grams to 50 grams in 60 minutes. Hence, the half-life of the isotope is 15 minutes.4. Half-life of technetium-99 that decays from 500.0 g to 62.5 g in 639,000 yearsIt is given that a 500.0 g sample of technetium-99 decays to 62.5 g of technetium-99 remaining in 639,000 years. We can use the half-life formula to find the half-life of technetium-99.t1/2 = (t × log2) / log(N0 / Nt) Where,t1/2 = half-life of the substanceN0 = initial quantity of the substance Nt = quantity of the substance left after time t (in years)t = time (in years)From the given data,t1/2 = (639000 × log2) / log(500.0 / 62.5)t1/2 = 210,936 years.
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A body of mass 1.0 kg initially at rest slides down an incline plane that is 1.0 m high and 10.0 m long. If the body experiences a constant resistive force of 0.5 N over the slope, what is the KE of the body at the base of the plane?
Answer:
answer is
Explanation:
because
A system consists of two uncharged metal spheres, each suspended on an insulating string and connected to the other by a thin
conducting wire. A positively charged rod is brought near, but does not touch, the left sphere, and the sphere is attracted to the rod. Which
of the following is correct about the net charge on the right sphere as a result?
The right sphere will acquire an equal and opposite net positive charge to balance the negative charge on the left sphere.
Electrostatic attractionSince the left sphere is attracted to the positively charged rod, it means that the left sphere acquires a temporary negative charge due to induction.
The positive charge on the rod repels electrons in the left sphere, causing them to move away from the rod side and accumulate on the opposite side, resulting in a net negative charge on the left sphere.
According to the principle of charge conservation, the net charge on the system must remain zero. Therefore, the right sphere acquires an equal and opposite net positive charge to balance the negative charge on the left sphere.
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Soda from a mS = 12 oz can at temperature TS = 12.5°C is poured in its entirety into a glass containing a mass mI = 0.17 kg amount of ice at temperature TI = -19.5°C. Assume that ice and water have the following specific heats: cI = 2090 J/(kg⋅°C) and cS = 4186 J/(kg⋅°C), and the latent heat of fusion of ice is Lf = 334 kJ/kg. In this problem you can assume that 1 kg of either soda or water corresponds to 35.273 oz.
The final temperature of the mixture of ice and soda is equal to 5 °C with a specific heat of soda and ice.
From the given,
mass of soda = 12 oz
temperature (Ts) = 12.5 °C
mass of ice (Mice) = 0.17 Kg
The temperature of ice (Tice) = -19.5°C
Specific heat of ice (Cice) = 2090 J/kg°C
Specific heat of water (Cwater) = 4186 J/kg°C
Latent heat of fusion of ice (Lf) = 334 kJ/kg.
The final temperature (T₂)=?
Mass of water = 12 / 35.274 = 0.34 kg
The heat lost by soda = heat gained by the ice
heat (Q) = m×c×ΔT where m is mass, C is specific heat and ΔT is a change in temperature.
M(soda)×C(water)×ΔT = M(ice)×Lf + M(ice)×C(ice)(T₂-T₁) + M(ice)×C(w)(T₂-0)
0.34×4186×(T₂-12.5) = (0.17×334) + (0.17× 2090×(T₂ + 19.5)+ (0.17×4186×T₂)
17790.5 - 1423.24 (final temp)= 6985.13 + 711.62 (final temp)
10805.37 = 2134.56 (final.temp)
T₂= 10805.37 / 2134.56
= 5 °C.
Thus, the final temperature of the mixture is 5°C.
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A 4-foot spring measures 8 feet long after a mass weighing 8 pounds is attached to it. The medium through which the mass moves offers a damping force numerically equal to 2 times the instantaneous velocity. Find the equation of motion if the mass is initially released from the equilibrium position with a downward velocity of 7 ft/s. (Use g
Correct question is;
A 4-foot spring measures 8 feet long after a mass weighing 8 pounds is attached to it. The medium through which the mass moves offers a damping force numerically equal to √2 times the instantaneous velocity. Find the equation of motion if the mass is initially released from the equilibrium position with a downward velocity of 7 ft/s. (Use g = 32 ft/s²)
Answer:
x(t) = 7te^(-2t√2)
Explanation:
We are given;
Weight; W = 8 lbs
mass; m = W/g
g = 32 ft/s²
Thus;
m = 8/32
m = ¼ slugs
From Newton's second law we can write the equation as;
m(d²x/dt²) = -kx - β(dx/dt)
Rearranging this, we have;
(d²x/dt²) + (β/m)(dx/dt) + (k/m)x = 0
Where;
β is damping constant = √2
k is spring constant = W/s
Where s = 8ft - 4ft = 4ft
k = 8/4
k = 2
Thus,we now have;
(d²x/dt²) + (√2/(¼))(dx/dt) + (2/(¼))x = 0
>> (d²x/dt²) + (4√2)dx/dt + 8x = 0
The auxiliary equation of this is;
m² + (4√2)m + 8 = 0
Using quadratic formula, we have;
m1 = m2 = -2√2
The general solution will be gotten from;
x_t = c1•e^(mt) + c2•t•e^(mt)
Plugging in the relevant values gives;
x_t = c1•e^(mt) + c2•t•e^(mt)
At initial condition of t = 0, x_t = 0 and thus; c1 = 0
Also at initial condition of t = 0, x'(0) = 7 and thus;
Since c1 = 0, then c2 = 7
Thus,equation of motion is;
x(t) = 7te^(-2t√2)
Input. Output and storage devices are part of a computer hardware.
O True
O False
The block A and attached rod have a combined mass of 50 kg and are confined to move along the guide under the action of the 796-N applied force. The uniform horizontal rod has a mass of 15 kg and is welded to the block at B. Friction in the guide is negligible.
Required:
Compute the bending moment M exerted by the weld on the rod at B. The bending moment is positive if counterclockwise, negative if clockwise.
Answer:
The bending moment is 459.16 N.m
Explanation:
From the given information;
Let's assume that the angle is 66°
Then, the free body diagram is draw and attached in the file below.
Now, the calculation of the acceleration from the first part of the free body diagram is:
\(\sum F_x = ma_x \\ \\ 796 - 50(9.81) sin 66=50a \\ \\ 796 - 448.094 = 50 a \\ \\ a = \dfrac{347.906}{50} \\ \\ a = 6.96 \ m/s^2\)
Bending moment M:
From the second part of the diagram:
\(\sum M_B = mad \\ \\ M - (15 \times 9.81) (1.5) = (25 \times 6.96)(1.5 sin 66) \\ \\ M - 220.725 = 238.435 \\ \\ M = 238.435 + 220.725 \\ \\ \mathbf{M = 459.16 \ N.m}\)
When a skater pulls her arms in, it
reduces her moment of inertia from
2.12 kg m² to 0.699 kg-m². If she was
initially spinning 3.25 rad/s, what is
her final angular velocity?
The skater's final angular velocity is approximately 9.86 rad/s.
The skater's final angular velocity can be calculated using the principle of conservation of angular momentum. The equation for angular momentum is given by:
L = Iω
where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity.
Initially, the skater has an angular momentum of:
L_initial = I_initial * ω_initial
Substituting the given values:
L_initial = 2.12 kg m² * 3.25 rad/s
The skater's final angular momentum remains the same, as angular momentum is conserved:
L_final = L_initial
The final moment of inertia is given as 0.699 kg m². Therefore, the final angular velocity can be calculated as:
L_final = I_final * ω_final
0.699 kg m² * ω_final = 2.12 kg m² * 3.25 rad/s
Solving for ω_final:
ω_final = (2.12 kg m² * 3.25 rad/s) / 0.699 kg m²
Hence, the skater's final angular velocity is approximately 9.86 rad/s.
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Which image represents a transverse mechanical wave?
Answer:
A
Explanation:
It is kinda like a spring.
The image which represents a transverse mechanical wave is A.
What is a mechanical wave?The wave has motion if all points on a wave vibrate at right angles to the direction of the wave propagation.
A transverse wave is a mechanical wave which is much like sinusoidal wave which has particles vibrating about their equilibrium position perpendicular to the direction of the motion of the wave.
Hence, the image which represents a transverse mechanical wave is A.
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A motorcycle stoop is at a traffic light, when the light turns green, the motorcycle accelerates to a speed of 78 km/h over a distance of 50 m. What is the average acceleration of the motorcycle over this distance?
The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².
To calculate the average acceleration of the motorcycle, we can use the formula:
Average acceleration = (final velocity - initial velocity) / time
First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.
Converting the final velocity:
Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s
Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:
Average acceleration = (21.67 m/s - 0 m/s) / time
To find the time taken to reach this velocity, we need to use the formula for average speed:
Average speed = total distance/time
Rearranging the formula:
time = total distance / average speed
Plugging in the values:
time = 50 m / 21.67 m/s ≈ 2.31 seconds
Now we can calculate the average acceleration:
Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²
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Solve ez points. I cant rlly get but i guess most of u do, so its ez
Answer:
A: nucleus
D: neutron
hope this helps :D
Answer:
A: nucleus
D: neutron
Explanation: hope this helps! <3
Select the correct answer.
A boat moves 60 kilometers east from point A to point B. There, it reverses direction and travels another 45 kilometers toward point A. What are the total
distance and total displacement of the boat?
O A.
OB.
O C.
O D.
The total distance is 105 kilometers and the total displacement is 45 kilometers east.
The total distance is 60 kilometers and the total displacement is 60 kilometers east.
The total distance is 105 kilometers and the total displacement is 15 kilometers east.
The total distance is 60 kilometers and the total displacement is 45 kilometers east.
The total distance is 105 kilometers and the total displacement is 15 kilometers east. Option C
How to solve for the total distanceTo calculate the total distance, we add the distances traveled in each leg of the journey: 60 kilometers (from A to B) + 45 kilometers (from B back to A) = 105 kilometers.
However, displacement refers to the change in position of an object in a straight line from its starting point to its ending point. In this case, since the boat starts and ends at the same point (A), the total displacement is zero.
Hence The total distance is 105 kilometers and the total displacement is 15 kilometers east.
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How far does a roller coaster travel if it accelerates at 2.83 m/s2 from an initial
velocity of 3.19 m/s for 12.0 s?
Answer:
b
Explanation:
How does the slope of your velocity versus time graph compare to the accepted value of the acceleration of a free falling object (g=9.8 m/s^ 2 )
The slope of your velocity versus time graph is acceleration.
What is acceleration?The rate at which an item changes its velocity is known as acceleration, a vector quantity. If an object's velocity is changing, it is acceleration.
The net acceleration that objects get as a result of the combined action of gravity and centrifugal force is known as the Earth's gravity, or g. It is a vector quantity whose strength or magnitude is determined by the norm and whose direction correlates with a plumb bob.
The slope of your velocity versus time graph is acceleration.
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A uniform bar has a mass of 2.2 kg and the angle shown is 30 degrees. Calculate the net torque about the point P for the bar. Do not ignore the weight of the bar.
The free body diagram of the bas is shown below:
The torque is given by:
\(\tau=r_{\perp}F\)where F is the force and:
\(r_{\perp}\)is the perpendicular distance between the rotation axis and the line of action of the force, which we called the moment arm. We know that the torque follows the principle of superposition then to find the total torque we need to add the torque each force exert. Before we do this we need to find the correct sign of the torque so we need to remember that if a force makes an object rotate counterclockwise then the torque is positive; otherwise it is negative. In this case Force two will exert a positive torque while the other two forces acting on the bar exert a negative torque.
For force one and the weight the moments arms are 5 m and 2.5 m, respectively. This comes from the fact that the forces are perpendicular to the rod.
For force two the moment arm is given as:
\(r_{\perp}=2\sin 30=1\)Hence the total torque is given by:
\(\begin{gathered} \tau=F_2r_{\perp2}+Wr_{\perp w}+F_1r_{\perp1} \\ \tau=(150)(1)-(9.8)(2.2)(2.5)-(20)(5) \\ \tau=-3.9 \end{gathered}\)Therefore, the total torque on the bar is -3.9 Nm (this means that the bar will rotate clockwise).
the weight of an object is measured in air to be 7N the object is then immersed in water and its apparent weight is measured to be 4N determined the buoyant force and state whether or not the object float
The buoyant force can be determined by subtracting the apparent weight of the object in water from its weight in air. In this case, the buoyant force would be 7N - 4N = 3N.
Based on the information provided, since the buoyant force (3N) is less than the weight of the object (7N), the object will not float.
Floating occurs when the buoyant force is greater than or equal to the weight of the object.
In this scenario, the object will experience a net downward force, indicating that it will sink rather than float in water.
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The moon appears to rise in the _______ and set in the ______ each day because the Earth rotates _____________.
Because the Earth revolves counterclockwise, the moon seems to rise as in east & set in west every day.
Why rise in the eastern and sets in the western do the stars?The rotation of the Earth is what causes this motion. Stars can be seen rising in the east, flying near, and sinking in the west as the Earth spins us eastward at a speed of about a thousand miles per hour. The Sun, Luna, and jupiter all seem to travel through the sky in a manner similar to how the stars do.
What does it mean when the stars rise and set?image outcome
The day on which the star arises in the am at the same moment as the Sun is known as the cosmos rising or genuine morning rising.
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If an EM wave has a wavelength of 595 nm, what is its frequency?
5.02 x 10^5 s
1.99 x 10^-6 Hz
5.02 x 10^14 Hz
1.99 x 10^-15 s
None of the above
Explanation:
1.9If an EM wave has a wavelength of 595 nm, what is its frequency9 x 10^-6 Hz
Explanation:
aah cmmon just come over to my meet
The result of the evolutionary process that preserves traits that enhance the adaptation of an organism and suppresses traits that do not is called
Answer:
Natural selection.
Explanation:
Natural selection can be defined as a biological process in which species of living organisms having certain traits that enable them to adapt to environmental factors such as predators, competition for food, climate change, sex mates, etc., tend to survive and reproduce, as well as passing on their genes to subsequent generations.
Simply stated, natural selection entails the survival of the fittest. Therefore, the species that are able to adapt to the environment will increase in number while the ones who can't adapt will die and go into extinction.
On the other hand, artificial selection is also known as selective breeding and it is a process that involves humans (breeders) selecting the animal or plant with desirable traits in order to reproduce favorable offspring having phenotypic traits.
1. A base-ball of mass 0.3kg approaches the bat at a speed of 30 miles/hour and when the ball hits the bat for 0.5 s, it started to move away from the bat at a speed of 60 miles/hour. Find the impulse
Answer:
I = 27kg.mi/h
Explanation:
In order to calculate the impulse of the ball, you use the following formula:
\(I=m\Delta v\) \(=m(v-v_o)\) (1)
m: mass of the ball = 0.3kg
v: speed of the ball after the bat hit it = 60mi/h
vo: speed of the ball before the bat hit it = 30mi/h
You replace the values of all parameters in the equation (1):
\(I=(0.3kg)(60mi/h-(-30mi/h))=27kg\frac{mi}{h}\)
where the minus sign of the initial velocity means that the motion of the ball is opposite to the final direction of such a motion.
The imulpse of the ball is 27 kg.miles/hour
A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm,find the emf of the cell.
A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm, the electromotive force (emf) of the cell is approximately 14.5 volts.
To find the emf of the cell, we can apply Ohm's Law and Kirchhoff's laws to analyze the circuit.
Given:
Resistance of the coil, R1 = 4 ohm
Resistance of the other resistor, R2 = 8 ohm
Current passing through the 8-ohm resistor, I = 2A
First, let's analyze the parallel combination of the 4-ohm and 8-ohm resistors.
The total resistance of two resistors in parallel can be calculated using the formula:
1/Rp = 1/R1 + 1/R2
Substituting the given values, we have:
1/Rp = 1/4 + 1/8
1/Rp = 2/8 + 1/8
1/Rp = 3/8
Rp = 8/3 ohm
Now, let's consider the total resistance in the circuit, which includes the internal resistance of the cell (0.5 ohm) and the parallel combination of the resistors (8/3 ohm).
R_total = R_internal + Rp
R_total = 0.5 + 8/3
R_total = 1.833 ohm
Now, we can find the emf of the cell using Ohm's Law:
emf = I * R_total
emf = 2 * 1.833
emf ≈ 3.667 volts
Therefore, the emf of the cell is approximately 3.667 volts.
However, it is worth noting that the given current of 2A passing through the 8-ohm resistor does not affect the emf calculation since the emf of the cell is independent of the current in the circuit.
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A 20kg block slides a cross a horizontal surface. If the coefficient of kinetic friction between the block and the surface is 0.20, what is the force of kinetic friction that acts on the block?
Compute the block's weight:
w = m g = (20 kg) (9.8 m/s²) = 196 N
The net vertical force is 0, so the normal force has the same magnitude:
n + (-w) = 0 → n = 196 N
The frictional force (mag. f ) is proportional to the normal force by a factor of µ = 0.20 such that
f = 0.20 (196 N) = 39.2 N ≈ 39 N
The force of kinetic friction acting on the block of mass 20 Kg having a coefficient of kinetic friction of 0.2 is 39.2 N
We'll begin by calculating the the normal reaction (N). This can be obtained as follow:Mass (m) = 20 Kg
Acceleration due to gravity (g) = 9.8 m/s²
Normal reaction (N) =?N = mg
N = 20 × 9.8
N = 196 NFinally, we shall determine the force of kinetic friction. This can be obtained as follow:Coefficient of kinetic friction (µ) = 0.2
Normal reaction (N) = 196
Force of kinetic friction (F) =?F = µN
F = 0.2 × 196
F = 39.2 NTherefore, the force of kinetic friction acting on the block is 39.2 N
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The _________ rule says the ball must bounce one on each side before either team may start volleying the ball in the air. Double Bounce
Volley Bounce
Bounce
Two Bounce
PLEASE HELP ASAP! WILL GIVE BRAINLIEST TO CORRECT ANSWER! HELP!! HELP!!
The diagram shows the structure of an animal cell.
The image of an animal cell is shown with some organelles labeled numerically from 1 to 6. The outer double layer boundary of the cell is labeled 1. A stacked disc like structure is labeled 2. A broad rod shaped structure with an irregular shape inside it is labeled 3. The entire plain section that forms the background of the cell and is within the outer boundary is labeled 4. A small circular shape within the large circular shape is labeled 5. The large central circular shape is labeled 6.
Which number label represents the cell membrane?
1
2
4
6
(this is middle school science)
Answer:
1. cell membrane
2. golgi body
3. mitochondrion
4. cytoplasm
5. nucleolus
6. nucleus
Explanation:
The correct answer to this question is Option A; 6.
Why?
In a plant cell, the nucleus surrounds the nucleolous, which would be number 5. Therefore, number 6 would be your correct answer.
~Thank you~
What is the work required to stretch a spring with a spring constant k of 2500 N/m by 8 cm?
Answer:
the work required to stretch the spring is 8 J.
Explanation:
Given;
spring constant, k = 2500 N/m
extension of the spring, x = 8 cm = 0.08 m
The work required to stretch the spring is calculated as;
\(W = \frac{1}{2} kx^2\\\\W = \frac{1}{2} \times 2500 \times 0.08^2\\\\W = 8 \ J\)
Therefore, the work required to stretch the spring is 8 J.
People are good at learning to recognize _______________. *
A.stars
B.constellations
C. patterns
D. Orion
E. Casseopia
F.look
G. distance
H.rotates
*Fill in the blank*
help <3 Please and thanks :>
Answer:
A
Explanation: