If a jackhammer exerts a force of 125N on the concrete. What is the magnitude of the force exerted back on the Jack Hammer?

A promising evidence of a habitat that might support life on the planet Mars is water.

There is evidence supporting the existence of liquid water on Mars from numerous sources. The finding of repeated black streaks on Martian slopes and the presence of hydrated minerals suggest the potential of seasonal or location-specific briny water flows. A necessary component of life as known is liquid water.

Additionally, Mars possesses underground ecosystems that could provide defence against radiation and severe surface conditions. Researchers have found evidence of ancient underground hydrothermal systems as well as beneath ice. These settings might offer consistent conditions for the development of microbial life.  Methane gas has been found in the Martian atmosphere, along with variations over time, and this has led to questions regarding its origin. Both geological and biological processes can result in the production of methane.

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Therefore, we cannot calculate the exact time for one cycle without more information.

The time for one cycle of a planet around the Sun is determined by its orbital period, which is related to the average distance of the planet from the Sun. In this case, if the average distance of the planet from the Sun is 21 astronomical units (A.U.), we can use Kepler's Third Law to calculate the orbital period.

Kepler's Third Law states that the square of the orbital period (T) is proportional to the cube of the average distance (r) between the planet and the Sun. Mathematically, it can be expressed as:

T^2 = k * r^3

Where k is a constant.

Given that the average distance is 21 A.U., we can set up the following equation:

T^2 = k * 21^3

To solve for T, we need the value of the constant k. However, without further information or additional equations, we cannot determine the specific value of k. Therefore, we cannot calculate the exact time for one cycle without more information.

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Answer:

the current flowing through the battery is 4 A.

Explanation:

Given;

resistance of the three resistors in parallel, R₁, R₂ and R₃ = 3.0 Ω, 12 Ω, and 4.0 Ω

voltage of the battery, V = 6.0 V

The equivalent resistance is calculated as follows;

\(\frac{1}{R_T} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} \\\\\frac{1}{R_T} = \frac{1}{3} + \frac{1}{12} + \frac{1}{4} \\\\\frac{1}{R_T} = \frac{4 \ + \ 1 \ + \ 3}{12} \\\\\frac{1}{R_T} = \frac{8}{12} \\\\\frac{1}{R_T} = \frac{2}{3} \\\\R_T = \frac{3}{2} \\\\R_T = 1.5 \ ohms\)

The current flowing through the battery is calculated as follows;

\(I = \frac{V}{R_T} \\\\I = \frac{6}{1.5} \\\\I = 4 \ A\)

Therefore, the current flowing through the battery is 4 A.

The change in total energy of a closed system, apart from changes in kinetic and potential energies, is accounted for by the change in internal energy.

Internal energy includes the sum of all microscopic forms of energy within the system, such as the energy associated with the motion of particles and their interactions.

When there are no changes in kinetic or potential energies, any change in the total energy of the system can be attributed to the change in internal energy.

This change can occur due to various factors, such as heat transfer or work done on or by the system.

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Answer:

Triangulation

Distance

Baseline

Far away

Parsec

Hipparcos

Astronomers are known to estimate the distance of nearby objects in space through the use of stellar parallax, or trigonometric parallax.

They often measure a star's  movement using the background of more distant stars as Earth revolves around the sun.

With the use of Parallax, one can get the best way to have the distance in astronomy,

Triangulation is often used instead of parallax to know the terrestrial distances by forming triangles with a predefined base and measuring the angles formed with the other two sides.

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The force is  1.1 * 10^-32 N

Coulomb's law is a fundamental law in physics that describes the electrostatic interaction between charged particles. It states that the force between two point charges is proportional to the product of their charges and inversely proportional to the square of the distance between them. Mathematically, Coulomb's law can be written as:

F = k * q1 * q2 / r^2

where F is the electrostatic force between the charges q1 and q2, r is the distance between the charges, and k is the Coulomb constant, which is approximately equal to 9 x 10^9 N * m^2 / C^2. The force F is a vector quantity, meaning that it has both magnitude and direction, and is directed along the line joining the two charges.

We have that;

F = Kq1q2/r^2

F = 9 * 10^9 * 1.6*10^ -19 * 3.2*10^ -19/(0.02)^2

F = 1.1 * 10^-32 N

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A certain lake, filled with fresh water, is 40 m deep and located at sea level. The absolute pressure (in kpa) at the bottom of the lake will be 492.1 kPa

P1 = rho * g * h

rho = density of water

g = acceleration due to gravity

h = depth

P1 = rho * g * h

   = 997 * 9.8 * 40 = 390824  N / \(m^{2}\) = 390.8 kPa

P(absolute pressure) =  Po + P1

  =   101.3 + 390.8  = 492.1 kPa

The absolute pressure (in kPa) at the bottom of the lake will be 492.1 kPa

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Answer:

t

Explanation:

Answer:

False

Explanation:

Answer:

Speed greater than 4 m/s

Explanation:

Given that Ms. Kasper is in a panic. Her cat, Penny, is stuck in a tree and about to jump out. In order to save her cat, Ms. Kasper needs to run to the tree, 12 meters away. If it takes her cat, 3 seconds to fall, how fast would Ms. Kasper have to run to save her cat?

The distance = 12 m

Time = 3s

Speed = distance/time

Speed = 12/3

Speed = 4 m/s

Ms Kasper must run at speed more than 4m/s for her to save the cat.

The energy of one photon of the light is 1.19 x \(10^{-11}\) J.

What is Planck's equation?

According to this, electromagnetic radiation from heated bodies emits in discrete energy units or quanta, the size of which depends on a fundamental physical constant (Planck's constant).

We know that,

E = hν

Where,

E = Energy

h = Planck's constant

ν = Frequency

Note: Planck's constant has value of 6.63 × \(10^{-3}\)\(\frac{J}{s}\)

Putting values in the given formula

E = 6.63 × \(10^{-3}\) \(\frac{J}{s}\) × 1.8 × \(10^{13}\) \(s^{-1}\)

E = 1.19 x \(10^{-11}\) J.

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Isaac Newton did not attribute the harmonious and orderly functioning of the universe to any specific philosophical or theological belief. Instead, he sought to understand and describe the laws of nature through his scientific investigations, particularly in the field of physics.

Newton's laws of motion and his law of universal gravitation provided a mathematical framework to explain the motion of celestial bodies and other physical phenomena. He believed that these laws were applicable throughout the universe and that they governed the interactions and behaviors of objects.

According to Newton, the harmony and order observed in the universe were a result of these fundamental laws of nature. He proposed that the motion of celestial bodies, such as planets orbiting the sun, could be described by mathematical equations and explained by the gravitational attraction between masses.

It is important to note that Newton's scientific explanations focused on describing and understanding natural phenomena based on empirical observations and mathematical formulations, rather than ascribing metaphysical or philosophical reasons for the harmonious functioning of the universe.

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The momentum of the electron is approximately \(87.67 keV/c.\)

Use the equation

\(p = h / \lambda\),

where p is the momentum,

h is Planck's constant \((6.626 * 10^{-34} J.s)\),

and λ is the wavelength.

Substitute the given wavelength \(\lambda = 0.471 nm\)

\(= 0.471 * 10^{-9} m\) into the equation:

\(p = (6.626 * 10^{-34} J.s) / (0.471 * 10^{-9} m).\)

Calculate the momentum:

\(p = 14.05 * 10^{-25} kg.m/s.\)

Convert the momentum to keV/c using the conversion factor:

\(1 kg.m/s = 6.242 * 10^{18} keV/c.\)

Calculate the momentum in keV/c:

\(p = (14.05 * 10^{-25} kg.m/s) * (6.242 * 10^{18} keV/c / 1 kg.m/s) \\\\= 87.67 keV/c.\)

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Answer: 1050 m

Explanation: 300 + 250x3 = 1050.

Answer:

d = 68.18 m

Explanation:

Given that,

Initial velocity, u = 15 m/s

Finally it comes to stop, v = 0

Acceleration, a = -1.65 m/s²

Time, t = 2.5 s

We need to find the distance covered by the hayride before coming to a stop. Let d is the distance covered. Using third equation of motion to find it :

\(v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{-(15)^2}{2\times -1.65}\\\\d=68.18\ m\)

So, the hayride will cover a distance of 68.18 m.

In the case of uniform accelerated motion, the graph of velocity versus time is a straight line. Therefore, option C is correct.

When a body experiences an acceleration constantly for a period of time, the velocity of the body changes. If we draw a graph the velocity on the vertical axis and time on the horizontal axis. A straight line is drawn which indicates that the velocity is increasing or decreasing uniformly.

This velocity increases or decreases uniformly depending upon the equal intervals of time. The slope line indicates the acceleration of the object and it also indicates the change in velocity per unit of time.

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Explanation:

Find an energy is E =mgh, so E = 45*10*19=8550j

Explanation:

tan(theta)=(v^2)/(length of string × g)

=(1.4^2)/(0.84 × 9.8m/s )

=1.96/(8.232)

=0.2380952381

theta=arctan(0.2380952381)

=13.4°

After considering the given data the height from which the gannet dived is approximately 51.84 m.

To evaluate the height from which a gannet dived if it hits the water at 32 m/s, assuming that the gannet was motionless before starting its dive, we can apply the law of conservation of energy, which projects  that the initial potential energy of the gannet is equivalent to its final kinetic energy prior to hitting the water. Then, we can write:
\(mgh = (1/2)mv^2\)
Here:
m = mass of the gannet
g = acceleration due to gravity
h = height from which the gannet dived
v = velocity of the gannet just before hitting the water
Considering that the mass of the gannet is 1 kg, and applying substitution of the given values, we get:
\((1 kg)(9.8 m/s^2)(h) = (1/2)(1 kg)(32 m/s)^2\)
\(h = (1/2)(32 m/s)^2 / (9.8 m/s^2)\)
h = 51.84 m
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The complete question is
A gannet is a seabird that fishes by diving from a great height. If a gannet hits the water at 32 m/s , what height did it dive from? Assume that the gannet was motionless before starting its dive.

Answer:

3) D: 31 m/s

4) D: 84.84 metres

Explanation:

3) Initial velocity along the x-axis is;

v_x = v_o•cos θ

Initial velocity along the y-axis is;

v_y = v_o•sin θ

Plugging in the relevant values, we have;

v_x = 31 cos 60

v_x = 31 × 0.5

v_x = 15.5 m/s

Similarly,

v_y = 31 sin 60

v_y = 31 × 0.8660

v_y = 26.85 m/s

Thus, magnitude of the initial velocity is;

v = √(15.5² + 26.85²)

v ≈ 31 m/s

4) Formula for horizontal range is;

R = (v² sin 2θ)/g

R = (31² × sin (2 × 60))/9.81

R = 84.84 m

airflow lifts a 3.6 kg bird 50 m up. how much work was done by the flow is 2,025,000J.

What is the purpose of airflow?

Data pipelines or workflows are scheduled and coordinated using Apache Airflow. The management, sequencing, coordination, and scheduling of intricate data pipelines from several sources is referred to as orchestration of data pipelines.

Airflow: A Python or Not?

The platform for creating, planning, and managing batch-oriented workflows is called Apache Airflow. With the help of the Python framework of Airflow, you may create workflows that connect to almost any technology.

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Answer:

combustibility

Explanation:

generally observe as the identity of a substance change and one or more new substance form

Answer:

2NH3 --> N2 + 3H2 decomposition

The input power required for a mass flow rate of 60 kg/min is calculated to be 871.35 kW.

Given that,

Initial temperature T₁ = 295 K

Final temperature T₂ = 460 K

Initial pressure P₁ = 105 k pa

Final pressure P₂ = 700 k pa

The specific heat loss from the compressor Q = 15 kJ/kg

The mass flow rate m = 60 kg/min

Refer to the properties of element to determine the specific heat of helium.

Cp = 5.19 kJ/kg.K

Apply the energy balance equation for calculating the input power.

W - m Q = m h₁ - m h₂

W - m Q = m (h₁ - h₂)

W - m Q = m Cp (T₁ - T₂)

where,

W is the input power

h₁ and h₂ are the initial and final enthalpy

Placing the values in the above expression, we have,

W - 60 kg/min (1 min/60 sec) × (-15 kJ/kg) = 60 kg/min (1 min/60 sec) × 5.19 kJ/kg.K (295 K - 460 K)

W = -871.35 kJ.s (1kW/1kJ) = -871.35 kW

Thus, the input power = 871.35 kW.

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Answer:

Explanation:

In order for one to carry something, they need to be exerting a force that is equal to the weight of the object. For Antonio therefore to hold the 1-pound bag, he needs to apply a 1-pound force.

Pounds measure the mass of an object. On his left hand Antonio has 1 pound and on the right he has 2. He is therefore carrying more mass on his right hand than on his left.

The momentum of the probe after the retrorocket ceases to fire is 9.9 * 10^7 Kg m/s

We know that the momentum of an object has to do with the product of the mass and the velocity of an object. The momentum of an object is a vector quantity and the direction of the momentum is the direction of the velocity of the object that is in motion.

According to the Newton second law of motion, we know that the rate of change of the momentum is equal to the impressed force that is acting on the body.

We know that;

\(F_{t}\) = \(p_{f}\) -\(p_{i}\)

F = force

t = time taken

\(p_{f}\)= final velocity

\(p_{i}\) = initial velocity

\(p_{f}\) = \(F_{t}\)  + -\(p_{i}\)

\(p_{f}\) = (2.0 * 10^6 * 12 s) + 7.5 * 10^7

\(p_{f}\)  = 2.4 * 10^7 + 7.5 * 10^7

\(p_{f}\)  = 9.9 * 10^7 Kg m/s

Hence, the momentum of the retrorocket is 9.9 * 10^7 Kg m/s.

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Missing parts;

A  space probe is traveling in outer space with a momentum that has a magnitude of  7.5 * 10^7 kgm/s. A retrorocket is fired to slow down the probe. It applies a force to the probe that has a magnitude of 2.0  * 10^6 N and a direction opposite to the probe's motion. It fires for a period of 12 s. Determine the momentum of the probe after the retrorocket ceases fire.

Answer:

0.0083km or 8.3m

Explanation:

Given parameters:

Distance  = 5km

Time  = 10min

Unknown:

Distance moved in 1sec  = ?

Solution:

To solve this problem, let us first find the speed of the motorbike.

   Speed  = \(\frac{distance}{time}\)  

  Speed  = \(\frac{5}{10}\)  = 0.5km/min

So;

   In 1sec:

               60 sec  = 1 min

                 1 sec  = \(\frac{1}{60}\)min

    Distance moved in 1sec  = speed x time

    Distance moved  = 0.5km/min  x  \(\frac{1}{60}\)min  = 0.0083km or 8.3m

The average force on our body when  jump off a step, having a stiff-legged landing is 10 time smaller. Thus, the correct answer is option D, reduced by 10.

The average force is the force exerted by an object moving at a given rate of speed, i.e. velocity, over a given time period. The term "average" is used here to indicate that the velocity is not instantaneous or precisely measured.

When we jump from a certain height and bend our knees upon reaching the ground, the time it takes to come to complete rest is increased by ten times , and the impact force is reduced to one-tenth of its initial value. This is consistent with Newton's second law of motion, which states that the rate of change in velocity is proportional to the force applied to the body.

Therefore, if you make the time of the impact about 10 times as great as for a stiff-legged landing, the average force that you experience would be 10 times smaller.

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A 0.1mm diameter glass tube is inserted into an ethyl alcohol at 20 degrees centigrade in a cup. The angle of alcohol with the tube is 0 degrees. D = 0.1 mm = 0.001m, alcohol angle is 0 degrees, ethyl alcohol

\(η=1.1×10^-3 N⋅sec/ m², s_g\)

=0.79.

We have to determine how much glycerin rises in the tube. The force that moves the liquid through the tube is the difference between the downward force of gravity on the liquid column and the upward capillary force produced by the surface tension of the liquid against the walls of the tube.

The height to which the fluid rises in a capillary tube may be measured by balancing the capillary force against the force of gravity on the column.

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A toy car that is 0.12 m long is used to model the actions of an actual car that is 6 m long. So, The acceleration of the actual car is 1515.15 m/s².

The solution to this question can be achieved through the use of the equation: F = ma Where F is force, m is mass, and a is acceleration.

Step 1: Calculating the mass of the toy car using the ratio of lengths m1/m2 = l1/l2, where m1 and m2 are the masses of the toy car and actual car, and l1 and l2 are their respective lengths.

Rearranging, we have:m1 = (l1/l2)m2 = (0.12 m)/(6 m) m2 = 0.02 m2

Step 2: Using the equation, F = ma, we can determine the mass of the toy car: F = ma2 N = (0.02 m2) a a = 2 N / 0.02 m2 = 100 m/s²

Step 3: Using the same force of 5 N, the acceleration of the actual car can be calculated:F = ma5 N = ma m = m2/l2 m = 0.02 m2 / 6 m = 0.0033 kg a = F/m a = 5 N / 0.0033 kg = 1515.15 m/s²

Therefore, the acceleration of the actual car is 1515.15 m/s².

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The probable question may be:

A toy car that is 0.12 m long is used to model the actions of an actual car that is 6 m long. The toy car is pushed with a force of 5 N, causing it to accelerate at a rate of 2 m/s². Assuming the same force is applied to the actual car, calculate the acceleration of the actual car.