if a dog ages 7 years for 1 human year, what would be the relative velocity, if these relative clocks were phrased kinematically (ie. using the lorentz time dilation transformation formula)?

The term refractve index refers to the value that shows the extent of bending of light waves as it travels from one medium to another.

a) Recall that;

n = 1/sinC

where C = critical angle

C = sin-1(1/n)

C = sin-1 (1/1.62)

C = 38.1 degrees

b) Since the angle of incidence has exceeded the critical angle, then there is total internal reflection of light.

c) If the flint glass id replaced by diamond;

C = sin-1(1/n)

C = sin-1 (1/2.42)

C = 24.4

The critical angle further decreases.

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Answer:

the potential energy is 114 J.

Explanation:

Given;

total mechanical energy, E = 400 J

kinetic energy, K.E = 286 J

The potential energy is calculated as follows;

E = K.E +  P.E

where;

P.E is the potential energy

P.E = E - K.E

P.E = 400 J - 286 J

P.E = 114 J

Therefore, the potential energy is 114 J.

Answer:

b. d. f.

Explanation:

Got it right on Edge

Answer:

2. Gina gathers information about a court case.

4. Hana interviews and advises a person who has been accused of a crime.

6. Dewayne creates the paperwork for a business contract.

The electric force between the two balloons is approximately 1.04 x \(10^{-12}\) N.

Coulomb's Law:

The electric force between two charged objects can be calculated using Coulomb's Law, which states that the magnitude of the electric force F between two charged objects is directly proportional to the product of their charges (q1 and q2) and inversely proportional to the square of the distance (r) between them:

F = k * (q1 * q2) / r²

where k is the Coulomb constant, which has a value of approximately 9.0 x \(10^{9}\) N*\(m^{2}\)/\(C^{2}\).

In this case, each balloon acquires a charge of 1.2 x \(10^{-7}\) C, so the total charge on both balloons is 2 * 1.2 x \(10^{-7}\)C = 2.4 x \(10^{-7}\)C. The distance between the balloons is 0.5 m.

Plugging in these values into Coulomb's Law, we get:

F = (9.0 x \(10^{9}\) N*\(m^{2}\)/\(C^{2}\)) * [(1.2)²x (\(10^{-7}\) C)²/ (0.5m)²]

Simplifying this expression gives:

F = 1.0368 x \(10^{-12}\) N

Therefore, the electric force between the two balloons is approximately 1.04 x\(10^{-12}\)    N.

What is magnitude?

Magnitude refers to the size or extent of something, usually measured in numerical or quantitative terms. It can refer to a physical quantity, such as length, mass, or volume, or it can refer to other measurable attributes, such as brightness, intensity, or force. In general, magnitude is a relative measure, meaning that it is typically expressed as a comparison between two or more things.

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Answer:

Both vehicles move east at 3.97 m/s

Explanation:

Law Of Conservation Of Linear Momentum

It states that the total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and speed v is:

P=mv.

If we have a system of two bodies, then the total momentum is the sum of both momentums:

\(P=m_1v_1+m_2v_2\)

If a collision occurs and the velocities change to v', the final momentum is:

\(P'=m_1v'_1+m_2v'_2\)

Since the total momentum is conserved, then:

P = P'

\(m_1v_1+m_2v_2=m_1v'_1+m_2v'_2\)

Assume both masses stick together after the collision at a common speed v', then:

\(m_1v_1+m_2v_2=(m_1+m_2)v'\)

The common velocity after this situation is:

\(\displaystyle v'=\frac{m_1v_1+m_2v_2}{m_1+m_2}\)

Assuming east direction to be positive, we have an m1=1459 kg car traveling west at v1=-43 m/s. An m2=9755 kg truck is traveling east at v2=11 m/s. They collide head-on and stick together after that.

Computing the resultant velocity after the collision:

\(\displaystyle v'=\frac{1459*(-43)+9755*11}{1459+9755}\)

\(\displaystyle v'=\frac{44568}{11214}\)

v' = 3.97 m/s

Both vehicles move east at 3.97 m/s

Nuclear, gravitational potential, thermal and chemical energy are types of stored energy.

Energy is defined as the capacity of a physical system to perform work.A abrupt release of collected energy, known as "stored energy," has the potential to result in severe harm or even death.

Gravitational potential energy, pressurized gases and liquids, stored mechanical energy, and stored electrical energy are only a few examples of the many different types of stored energy. Nuclear energy is potential energy stored inside the nucleus of an atom. Chemical energy is energy stored in the bonds of atoms and molecules.

Nuclear, gravitational potential, thermal and chemical energy are types of stored energy

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The angle A using the appropriate sine or cosine law is 43.29 degrees.

To find angle A, we can use the cosine law, which states that $a^2 = b^2 + c^2 - 2bc \cos{A}$. We have $b=5.3$, $c=7$, and $a=8.2$, so we can plug in and solve for $\cos{A}$:$$8.2^2 = 5.3^2 + 7^2 - 2(5.3)(7) \cos{A}$$$$\cos{A} = \frac{8.2^2 - 5.3^2 - 7^2}{-2(5.3)(7)} = 0.509$$$$A = \cos^{-1}{(0.509)} \approx 43.29^\circ$$The length of side x using the appropriate sine X is 61.32 units.

We can use the sine law, which states that $\frac{a}{\sin{A}} = \frac{b}{\sin{B}} = \frac{c}{\sin{C}}$. We know that $A=101^\circ$ and $a=x$, so we can use the ratio $\frac{a}{\sin{A}}$ to solve for $x$:$$\frac{x}{\sin{101}} = \frac{c}{\sin{38}}$$$$x = \sin{101} \cdot \frac{c}{\sin{38}} \approx 61.32$$Therefore, the length of side x is approximately 61.32 units.

In geometry, the Cosine Decide says that the square of the length of any side of a given triangle is equivalent to the amount of the squares of the length of different sides short two times the result of the other different sides duplicated by the cosine of point included between them.

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If the presently accepted value of ω0=0.3 is indeed correct, then the universe will most likely expand forever.

This is based on the current understanding of the universe's composition and the rate of expansion. ω0 is a measure of the density parameter, which describes the relative contributions of matter, radiation, and dark energy to the total energy density of the universe. A value of 0.3 suggests that the universe is dominated by dark energy, which is causing it to expand at an accelerating rate.

If the universe were to collapse into the next cosmic cycle, this would suggest that it is a closed system with a finite size and finite lifespan. However, current evidence suggests that the universe is flat or open, meaning that it will continue to expand indefinitely.

The option of expanding to the critical size for the Steady State model and becoming static is also unlikely. This model suggests that the universe maintains a constant size and density by continuously creating matter. However, this theory has been largely discredited by observational evidence.

This has implications for the ultimate fate of the universe, including the possibility of a "Big Freeze" or "Heat Death" scenario in which all matter becomes too diffuse and spread out to sustain life.

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As stars get bigger and brighter, the closer they are to their end of life.

Because they have already used all the elements they can in nuclear fusion. Iron cannot be fused, its too heavy.

The most accurate graph here would be the third one.

After slowing down by 15 miles per hour and reducing the speed by one third, you are now going at 60 miles per hour.

If you are initially driving at a rate of one and a half miles per minute, it means you are traveling at a speed of 90 miles per hour (since there are 60 minutes in an hour).

In the second step, you slow down by 15 miles per hour. This reduces your speed to 75 miles per hour.

Finally, you reduce your speed by one third, which means you need to subtract one third of 75 from 75. One third of 75 is 25, so subtracting 25 from 75 gives you a speed of 50 miles per hour.

Therefore, after slowing down by 15 miles per hour and then reducing your speed by one third, you are now traveling at a speed of 50 miles per hour.

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Answer:

in the nucleus of the atom

Explanation:

a p 3 x

Explanation:

key to this problem is the impulse-momentum theorem which states that the change in the momentum of an object is equal to the impulse applied into it.

J

=

Δ

p

,

where

J

is the impulse and

Δ

p

is the change in momentum. Basically, the impulse is the product of force and time duration, that is,

J

=

F

Δ

t

In this problem, the impulse would be the product of the force stopping the rock and

0.7

s

.

On the other hand, momentum

p

is the product of the mass

m

and velocity

v

. Therefore, the change in momentum is given by

Δ

p

=

m

2

v

2

−

m

1

v

1

.

Starting with the impulse-momentum equation, we have

J

=

Δ

p

F

Δ

t

=

m

2

v

2

−

m

1

v

1

Divide both sides by

Δ

t

,

we get

F

Δ

t

Δ

t

=

m

2

v

2

−

m

1

v

1

Δ

t

F

=

m

2

v

2

−

m

1

v

1

Δ

t

Finally, substitute the values and we get

F

=

(

2

kg

)

(

0

)

−

(

2

kg

)

(

6

m

s

)

(

0.7

s

)

F

≈

−

20

kg

m

s

2

Since

1

N

=

1

kg

m

s

2

,

then

F

≈

−

20

N

Therefore, using the correct significant figures (in this case, we need one significant figure since 2 kg, 6 m/s and 0.7 s all have one) in the final answer, we would need to have approximately

20

N

force to stop the rock in

0.7

s

.

Note: The negative sign is referring to the direction of the force opposite of the direction of the velocity

v

1

.

Answer:

4.0 kg

Hope it helps

Please mark me as the brainliest

Thank you

Answer:

she is going to be mad dude

When entering the interstate on a short entrance ramp where there is no acceleration lane, you should Speed up and enter the interstate only after you have identified a gap in traffic.

one of the major thoroughfares that make up the US system of expansive roadways that traverse states and connect numerous cities is interstate highways. The safest way to enter is to stop and wait for a significant gap in traffic if the entrance lane is too narrow to allow acceleration to highway speed. Then get on the highway and drive rapidly and such type of narrow entrance lane is called short entrance ramp.

When entering the interstate on a short entrance ramp where there is no acceleration lane, you should speed up and then enter the interstate only after you have identified a gap in traffic as you should wait for the gap between short lane to appear and then speed the vehicle.

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When entering the interstate on a short entrance ramp where there is no acceleration lane, you should Speed up and enter the interstate only after you have identified a gap in traffic.

One of the major thoroughfares that make up the US system of expansive roadways that traverse states and connect numerous cities is interstate highways. The safest way to enter is to stop and wait for a significant gap in traffic if the entrance lane is too narrow to allow acceleration to highway speed. Then get on the highway and drive rapidly and such type of narrow entrance lane is called short entrance ramp.

When entering the interstate on a short entrance ramp where there is no acceleration lane, you should speed up and then enter the interstate only after you have identified a gap in traffic as you should wait for the gap between short lane to appear and then speed the vehicle.

The question is incomplete. The complete question is 'A) Immediately enter the far-right traffic lane on the interstate and speed up to match the flow of traffic. B) Use the shoulder of the main road to get up to the speed of traffic. C) Speed up and enter the interstate only after you have identified a gap in traffic.'

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Chewing is an example of mechanical digestion.Mechanical digestion refers to the process by which food is physically broken down into smaller pieces to improve digestion and absorption.

The process begins in the mouth and is carried out by a number of organs such as the tongue, teeth, and stomach. Chemical digestion occurs next, in which enzymes break down food molecules to their essential components, allowing them to be absorbed into the bloodstream and delivered to the cells that need them.

What is an example of mechanical digestion?As stated earlier, mechanical digestion involves the physical breakdown of food into smaller particles. Here are some examples of mechanical digestion:Chewing - Your teeth grind food into smaller pieces, making it easier to digest and absorb.

Your saliva, which contains enzymes that start the chemical digestion process, also softens the food and helps to break down starch into simpler sugars.Grinding - After you swallow, your food moves to the stomach, where it is further broken down by contractions of the stomach muscles.

Mixing - The stomach's muscular walls contract to create churning movements that mix food with gastric juices, resulting in a semi-solid substance known as chyme that can be transported to the small intestine for further digestion and absorption.In conclusion, chewing is an example of mechanical digestion.

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The man moves across the ice with a velocity of -1 m/s.

Formula:

To calculate the velocity we would be using the formula,

M₁U₁ + M₂U₂ = M₁V₁+ M₂V₂

Given:

After applying the law of linear momentum, we get the following value before the throw;

M₁ = Man's initial mass= 80kg,

U₁ = Initial velocity of Man = 0,

M₂= Initial mass of Book  = 4kg,

U₂= Initial velocity of Book = 0.

After the throw, the book's velocity will be

M₁ = Man final mass = 80kg,

V₁ = Man's final velocity = V.

M₂ = Final mass of Book = 4kg,

V₂ = Final velocity of Book = 20 m/s

After substituting the values in the formula, we get,

M₁U₁ + M₂U₂ = M₁V₁+ M₂V₂

Or, (80 x 0) + (4 x 0) = (80V) + (4 x 20)

Or, 0 = 80V + 80

Or, 80V = -80

Or, V = -80/80

V= -1m/s

[Note: The -ve sign shows the opposite direction]

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Answer:

C. Both force and displacement

Explanation:

Hope this helps

Answer:

I think it is 1,200.

Explanation:

In the research I found, It says in a paragraph it is 1,200. I don't know if this is wrong or correct. I hope this helps!!!

Answer:

there isn't anything else posted to the question when you ask a question put a picture or write it out so people can see it

Explanation:

Answer:

   I = 2 A

Explanation:

Electric current is defined as the amount of face per unit of time

         I = Q / t

where Q is the charge and t is the time

let's reduce the time to the SI system

         t = 1 min (60s / 1 min) = 60 s

let's calculate

         I = 120/60

         I = 2 A

The spring stiffness, or spring constant, of the given perfect spring is approximately 137.9623 N/m. This means that for every meter of extension, the spring will exert a force of 137.9623 N.

This value was obtained by applying Hooke's Law and calculating the ratio of the change in force to the change in extension using two data points from the table.

To determine the spring stiffness, we need to calculate the spring constant (k) using Hooke's Law, which states that the force applied on a spring is directly proportional to the extension it undergoes.

Hooke's Law can be represented as F = kx, where F is the applied force and x is the extension of the spring.

In the given table, we have the applied forces (F) and corresponding extensions (x). We can use any two data points from the table to find the spring constant.

Let's choose the first and last data points from the table:

(x1, F1) = (0.43 m, 59.34 N) and (x2, F2) = (0.96 m, 132.48 N).

Using Hooke's Law, we can calculate the spring constant (k) as follows:

k = (F2 - F1) / (x2 - x1)
  = (132.48 N - 59.34 N) / (0.96 m - 0.43 m)
  = 73.14 N / 0.53 m
  ≈ 137.9623 N/m (rounded to 4 decimal places)

Therefore, the spring stiffness, or spring constant, is approximately 137.9623 N/m.

Hooke's Law is a fundamental concept in physics that describes the relationship between the force applied on a spring and the resulting extension it undergoes.

The formula F = kx represents this relationship, where F is the applied force, k is the spring constant, and x is the extension of the spring.

By using two data points from the table, we can calculate the spring constant by finding the ratio of the change in force to the change in extension.

This calculation allows us to quantify the stiffness of the spring.
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No, oscilloscopes cannot measure current directly.

Oscilloscopes are electronic instruments that are used to measure the characteristics of electrical signals. They can measure voltage, frequency, time, and phase of the signal. However, current cannot be measured directly using an oscilloscope. This is because an oscilloscope measures voltage by displaying the voltage waveform on the screen, and then converts it into a visual representation. In order to measure current, a current probe is required.

A current probe is an external device that can be connected to an oscilloscope to measure current. The probe uses a magnetic field to detect the current flowing through a conductor. The probe then converts the magnetic field into a voltage signal, which can be displayed on the oscilloscope.

Oscilloscopes are versatile and powerful tools for electrical engineers, technicians, and hobbyists. They allow us to measure a wide range of characteristics of electrical signals, including voltage, frequency, time, and phase. However, when it comes to measuring current, things get a bit more complicated.

Measuring current directly using an oscilloscope is not possible. This is because current is the flow of electrons through a conductor, and it does not produce a voltage waveform that can be displayed on the screen of an oscilloscope. Instead, we need to use a current probe to measure current.

A current probe is a device that is used to measure current flowing through a conductor. It is an external device that is connected to the input of an oscilloscope. The probe uses a magnetic field to detect the current flowing through the conductor. The magnetic field is then converted into a voltage signal, which is displayed on the screen of the oscilloscope.

There are different types of current probes available, including passive and active probes. Passive probes are simple and affordable, but they have a limited frequency range and may introduce noise into the signal. Active probes are more complex and expensive, but they offer better performance and accuracy.

In conclusion, oscilloscopes cannot measure current directly. A current probe is required to measure current using an oscilloscope. Current probes come in different types and offer varying levels of performance and accuracy. When selecting a current probe, it is important to consider the frequency range, accuracy, and noise characteristics of the probe to ensure that it is suitable for the application at hand.

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Answer:

The silk has become negatively charged

By ideal gas theory, cylinder b has the higher temperature.

We need to know about the ideal gas theory to solve this problem. The ideal gas can be represented by

P . V = n . R . T

where P is the pressure, V is volume, n is the number of molecules, R is the ideal gas constant and T is temperature.

From the question above, we know that

Pa = Pb = P

na = 3nb

Find the temperature of the cylinder a

P . V = n . R . Ta

Ta = P . V /( na . R )

Substitute na

Ta = P . V /( (3nb) . R )

Ta = (1/3) x (P . V /( (nb . R ))

Find the temperature of the cylinder b

P . V = n . R . Tb

Tb = P . V /( nb . R )

The cylinder a temperature is 3 times smaller than the temperature in cylinder b.

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the answer is definitely A.

Answer:

Approximately \(9.64\; {\rm m\cdot s^{-1}}\) (assuming that the velocity of the exhaust is \((-100)\; {\rm m\cdot s^{-1}}\).

Explanation:

When an object of mass \(m\) travels at a velocity of \(v\), the momentum \(p\) of this object will be \(p = m\, v\).

Assume that there is no external force on this spaceship. The total momentum of the ship and the exhaust will be conserved. In other words,

\(\begin{aligned}& (\text{Momenum of Spaceship, before}) \\ &+ (\text{Momentum of Exhaust, before}) \\ =\; & (\text{Momenum of Spaceship, after}) \\ &+ (\text{Momentum of Exhaust, after})\end{aligned}\).

Rearrange to find the momentum of the spaceship after releasing the exhaust:

\(\begin{aligned} & (\text{Momenum of Spaceship, after}) \\ =\; & (\text{Momenum of Spaceship, before}) \\ &+ (\text{Momentum of Exhaust, before}) \\ &- (\text{Momentum of Exhaust, after})\end{aligned}\).

It is given that the spaceship and the exhaust were initial stationary. Hence, initial momentum will be \(0\; {\rm kg \cdot m\cdot s^{-1}}\) for both the ship and the exhaust.

\(\begin{aligned} & (\text{Momenum of Spaceship, after}) \\ =\; & (0\; {\rm kg \cdot m\cdot s^{-1}}) \\ &+ (0\; {\rm kg \cdot m\cdot s^{-1}}) \\ &- (\text{Momentum of Exhaust, after})\end{aligned}\).

Since the exhaust is of mass \(10600\; {\rm kg}\) and velocity \((-100)\; {\rm m\cdot s^{-1}}\), the momentum of the exhaust after release  will be:

\(\begin{aligned} & (\text{Momenum of Exhaust, after}) \\ =\; & (\text{mass of Exhaust})\, (\text{Velocity of Exhaust, after}) \\ =\; & (10600.0\; {\rm kg})\, ((-100)\;{\rm m \cdot s^{-1}}) \\ =\; & (-1.06000\times 10^{6})\; {\rm kg \cdot m\cdot s^{-1}}\end{aligned}\).

Divide the momentum of the spaceship by mass to find velocity:

\(\begin{aligned} & (\text{Velocity of Spaceship, after}) \\ =\; & \frac{(\text{Momentum of Spaceship})}{(\text{mass of Spaceship})} \\ =\; & \frac{((-1.06000\times 10^{6})\; {\rm kg \cdot m\cdot s^{-1}})}{(110000.0\; {\rm kg})} \\ \approx\; & 9.64\; {\rm m\cdot s^{-1}}\end{aligned}\).

Answer: 1960 kPa

Explanation:

The pressure exerted on a body at a certain depth in a fluid can be calculated using the equation:

Pressure = Density x Gravity x Depth

Where Density is the density of the fluid, Gravity is the acceleration due to gravity and Depth is the distance below the surface of the fluid.

In this case, the density of the fresh water is 1000 kg/m³, the depth of the body is 200m and the acceleration due to gravity is 9.8 m/s².

So the pressure exerted on the body can be calculated as:

Pressure = 1000 kg/m³ x 9.8 m/s² x 200m

Pressure = 1960000 N/m²

Pressure = 1960 kPa

Therefore, the pressure exerted on the body with a mass of 75 kg at 200m below the surface of fresh water with a density of 1000 kg/m³ is 1960 kPa.

The Reynolds number for a 1-foot diameter sphere moving at 2.3 miles per hour through seawater is approximately 218,835. This value represents the relative importance of inertial and viscous forces in the fluid flow around the sphere.

To calculate the Reynolds number, we can use the following formula: Re = (ρvL)/μ, where Re is the Reynolds number, ρ is the fluid density, v is the velocity of the object, L is the characteristic linear dimension (diameter in this case), and μ is the dynamic viscosity of the fluid.

First, we need to convert the given velocity from miles per hour to meters per second. 2.3 miles per hour is approximately 1.028 meters per second.

Next, we can find the density of seawater by multiplying its specific gravity by the density of water. The density of water is approximately 1,000 kg/m³, so the density of seawater is: 1,000 kg/m³ x 1.027 = 1,027 kg/m³.

Now we can substitute the values into the Reynolds number formula:

Re = (ρvL)/μ
Re = (1,027 kg/m³ x 1.028 m/s x 0.3048 m) / (1.07 x 10⁻³ Ns/m²)
Re ≈ 218,835

The Reynolds number for the given scenario is approximately 218,835.

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