If a 5kg ball is rolling to the left and has a momentum of -25kg*m/s what is the velocity (not just speed) of the ball

Answer:

18,000 j

Explanation:

the lightbulb dissipates 5W of power

P = ΔE / Δt

rearrange to solve for energy

ΔE = PΔt

P = 5W

t =  1 hour = 60 minutes = 3600 seconds

ΔE = 5 * 3600

ΔE = 18000 J

Answer: the answer is b “The warmer a region of the atmosphere is, the more infared radiation it emits”

Explanation:

Answer:

a

Explanation:

i got it right

The reading on the scale is 882.6 N when the elevator accelerates upwards with an acceleration of 4.90 m/s².

Given that the mass of a person is 60.0 kg and the elevator accelerates upwards with an acceleration of 4.90 m/s², we have to determine the reading on the scale.

Let F be the force exerted by the scale on the person. Then, by Newton's second law of motion, the net force acting on the person is Fnet= m * a

where m = 60.0 kg is the mass of the person and a = 4.90 m/s² is the acceleration of the elevator. Hence, the net force acting on the person is given by;

Fnet = 60.0 kg * 4.90 m/s²

Fnet = 294.0 N

Therefore, the scale reading is equal to the force exerted by the scale on the person. Since the elevator is accelerating upwards, the force exerted by the scale on the person is greater than the weight of the person, which is the force of gravity acting on the person.

The force of gravity acting on the person is given by;

Fg = m * g, where g = 9.81 m/s² is the acceleration due to gravity. Hence, the force of gravity acting on the person is given by;

Fg = 60.0 kg * 9.81 m/s²Fg = 588.6 N

Therefore, the scale reading is given by the sum of the force of gravity acting on the person and the net force acting on the person;

F = Fg + Fnet

F = 588.6 N + 294.0 N

F = 882.6 N

Thus, the reading on the scale is 882.6 N when the elevator accelerates upwards with an acceleration of 4.90 m/s².

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The plane travels a distance of 325 miles if the airplane travels for 2.5 hours at an average speed of 130 miles per hour. Using the distance formula (d = rt), we can calculate the distance.

To find the distance traveled by the airplane, we can use the distance formula, which is represented as d = rt. In this formula, "d" represents the distance, "r" represents the rate or speed at which the object is traveling, and "t" represents the time taken for the travel.

Given that the airplane travels for 2.5 hours at an average rate of 130 miles per hour, we can substitute these values into the formula. The rate of the airplane is 130 miles per hour, and the time taken is 2.5 hours.

Using the formula, we can calculate the distance traveled as follows:

d = rt

d = 130 mph × 2.5 hours

Multiplying the rate (130 mph) by the time (2.5 hours) gives us:

d = 325 miles

Therefore, the airplane travels a distance of 325 miles during the 2.5 hours of travel at an average rate of 130 miles per hour.

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Explanation:

55×60=3300

2×60=120

3300+120=3420

speed=distance/time

speed=3420/217

x=15.6ms^-1

Her speed is approximately 1.24 meters/second.

To calculate Michelle's speed, you need to convert the time to a single unit (seconds) and then use the formula:

Speed = Distance / Time

Given that Michelle walked 217 meters in 2 minutes and 55 seconds:

Time in seconds = 2 minutes * 60 seconds/minute + 55 seconds = 120 seconds + 55 seconds = 175 seconds

Now, let's calculate her speed:

Speed = 217 meters / 175 seconds = 1.24 meters/second

Rounded to two decimal places, her speed is approximately 1.24 meters/second.

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The graph that corresponds to 0.1 s in one complete cycle is graph D.

option D is the correct answer.

The period of a wave is the time for a particle on a medium to make one complete vibrational cycle. Period, being a time, is measured in units of time such as seconds, hours, days or years.

Also, the period of a wave is the amount of time it takes for a wave to complete one wave cycle or wavelength.

From the given parameter, the coil rotates 10 times in one second. The period of the coil is calculated as;

Period = 1 s / 10

Period = 0.1 s

From the graphs, the only option that has one complete cycle in one second is option D.

Check option D, half cycle is 0.05 s and one full cycle is 0.1 s.

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The graph shown in the first option nicely plots the lion's and gazelle's velocities as a function of time, so option A is the correct answer.

Velocity is the rate of change of displacement over time.

As mentioned in the problem of running at a constant speed towards a gazelle with a standing lion as shown above.

So option A is correct.

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Explanation:

F = k |q1| |q2| / r^2

k = 9 * 10^9

q1 = - 2.5 C

q2 = 2 C

r = 100

r^2 = (10^2)^2 = 10^4

F = (9*10^9) * ( 2.5 ) ( 2) / ( 100)^2

F = 45* 10^9 / 10^4

F = 45 * 10^9 * 10 ^ -4 = 45 * 10^5 N

F = 45 * 10 ^ 5 N

Answer:

B.rate of convection

Explanation:

Answer:

P=33.6 \ W

Explanation:

Mechanical Work and Power

Work is the amount of energy transferred by a force. It's a scalar quantity, with SI units of joules.

Being \(\vec F\) the force vector and \(\vec s\) the displacement vector, the work is calculated as:

\(W=\vec F\cdot \vec s\)

If both the force and displacement are parallel, then we can use the equivalent scalar formula:

\(W=F.s\)

Mechanical Power is the amount of energy transferred or converted per unit of time. The SI unit of power is the watt, equal to one joule per second.

The power can be calculated as:

\(\displaystyle P=\frac {W}{t}\)

Where W is the work and t is the time.

If an object of mass m has an acceleration a, the net force is:

F=m.a

The go-kart and rider have a mass of m=14 kg and accelerate at \(6 m/s^2\), thus the net force applied is:

\(F=14\cdot 6 = 84\ N\)

The work done by the cart when traveling d= 40 m is:

\(W=84\cdot 40\)

\(W=3,360\ J\)

Finally, the power for t= 100 seconds is:

\(\displaystyle P=\frac {3,360}{100}\)

P=33.6 \ W

The effect that this will have on the amplitude of your oscillation.is b.) The amplitude of oscillation will decrease.

The amplitude of an oscillating system is the magnitude of change in the oscillating variable with each oscillation. Sound waves in air, for example, are oscillations in atmospheric pressure, and their amplitudes are proportional to the pressure change during one oscillation.

When a wave travels through a medium, it loses energy as it moves. As the distance between the wave and its source grows, it spreads out over a larger and larger area. As the wave spreads through the medium, it loses energy and its amplitude decreases.

In this case, at the point of equilibrium, the cart and the skater will have maximum kinetic energy. By dropping the same bag, the energy is reduced. The amplitude of an oscillating pendulum decreases with time because of friction due to air

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On a whim, you are trying to stand in a cart attached to a strong spring. The spring is compressed and then released, and you oscillate back and forth, trying to maintain your balance. There is a sand bag in the cart.

At the instant you pass through the equilibrium (x=0) location of the spring, you drop the sandbag onto the ground, out of the cart.

Question: If you drop the sand bag out of the cart right at the equibrium location, what effect will that have on the amplitude of your oscillation? (choose correct choice):

a.) The amplitude of oscillation will increase.

b.) The amplitude of oscillation will decrease.

c.) There will be no effect on the amplitude.

The Cessna Citation V can fly 650 miles in 1.3 hours. In 2 hours, it can fly approximately 1,000 miles.

To find out how far the Cessna Citation V can fly in 2 hours, we can use a proportion. If the plane can fly 650 miles in 1.3 hours, then we can set up the proportion:

650 miles / 1.3 hours = x miles / 2 hours

To solve for x, we can cross-multiply and simplify:

650 miles * 2 hours = 1.3 hours * x miles

1300 miles = 1.3x

x = 1000 miles (rounded to the nearest hundred)

Therefore, the Cessna Citation V can fly approximately 1,000 miles in 2 hours. It's important to note that this calculation assumes a constant speed, which may not be the case in real-world conditions. Additionally, factors such as wind speed and direction can affect the plane's range.

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Answer:

The kinetic energy of the system does not change.

When two horseshoe magnets are placed next to each other, then they either attract or repel each other, depending on the position of their poles. if the poles are opposite they attract, if they are same they repel with other.

In case, if the poles of two horseshoe magnets are attracted to each other, indicating poles are opposite to each other. when the magnets are brought together then the work must be done to oppose the magnetic field between poles. This increases the potential energy of the system.

However, the question is about the kinetic energy of the system, which is related to the motion of the objects in the system. In this case, once the magnets are brought together they attract each other, they will have zero potential. Therefore, the kinetic energy will not change.

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Answer:

.

Explanation:

Answer:

D

Explanation:

D

Part A: The magnetic field strength at a distance r₀/2 from the wire’s center is 2B₀.

magnetic field at any point at a distance r is given as B = μI/2πd

According to the formula, the magnetic field strength at a point along the axis of a current-carrying wire is directly proportional to the current in the wire and inversely proportional to the distance from the wire.

Since the current is unchanged, and the distance from the wire has been halved, the magnetic field strength will be doubled.

Part B: The magnetic field strength at a distance 3r₀ after the current is increased to 6I₀ is 2B₀.

magnetic field at any point at a distance r is given as B = μI/2πd

According to fromula, the magnetic field strength at a point along the axis of a current-carrying wire is directly proportional to the current in the wire and inversely proportional to the distance from the wire.

Since the current has been increased by a factor of 6 and the distance from the wire is increased by a factor of 3, the magnetic field strength is increased by a factor of 6/3 = 2.

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Answer: -31039 J

Explanation:

Answer:

Explanation:

The answers are Static electricity, gravity, and magnetism.

Static electricity:

This force is very similar to gravitational force, the main difference being that gravitational force acts between masses, and electrostatic force acts between two charged bodies.

This force can be generated by rubbing the comb against clothing and then holding it close to tiny pieces of paper. You can watch the pieces of paper standing on their ends being attracted to the comb.

Gravity:

Gravitational force is a type of attractive force that exists between all bodies of mass, and the gravitational force of the sun keeps the sun and all the other planets of the solar system in a fixed orbit. Gravitation force is not required to be contacted to excerpt its downward force.

Magnetism:

Remember that if you push the ends of the magnet together, the other magnet will bounce off due to the magnetic force. It is also responsible for attracting iron with the force of magnets. The magnetic force of a magnet decreases as the distance between magnets increases.

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Answer:

a

Explanation:

The term "ferromagnetic" refers to iron or oxide of irons.

Ferromagnetism is a physical phenomenon in which certain electrically uncharged materials strongly attract others.

Two materials found in nature, lodestone (or magnetite, an oxide of iron, Fe3O4) and iron, have the ability to acquire such attractive powers, and they are often called natural ferromagnets

ferromagnetic materials are used in making magnets such as electromagnets for electronic devices. And it is a very important industrial raw material.

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The value of force is 1.7 × 10⁻³ N, with the direction opposite to that of the bat's motion.

When an object collides with another object, they exchange energy. For example, a baseball and bat collision or a car collision. When two objects collide, the force of the collision has to be equal on both sides of the collision according to Newton's Third Law. So, to find the value of force, we will apply the equation:

F = ΔP / ΔT

where F is the force, ΔP is the change in momentum, and ΔT is the time of collision. The equation represents the impulse momentum theorem.

Now, let's apply the given values to the above equation.

Final momentum (p2) = mass × final velocity (v2)

p2 = 0.15 kg × (-50 m/s)

p2 = -7.5 kg.m/s

Initial momentum (p1) = mass × initial velocity (v1)

p1 = 0.15 kg × (40 m/s)

p1 = 6 kg.m/s

Change in momentum (ΔP) = p2 - p1

ΔP = -7.5 kg.m/s - 6 kg.m/s

ΔP = -13.5 kg.m/s

Time of collision (ΔT) = 8.0 × 10³ s

Now, putting the values of ΔP and ΔT in the equation of impulse momentum theorem, we get:

F = ΔP / ΔT

F = -13.5 kg.m/s ÷ 8.0 × 10³ s

F = -1.7 × 10⁻³ N

Thus, the value of force is 1.7 × 10⁻³ N, with the direction opposite to that of the bat's motion.

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Answer:

D

Explanation:

The decrease in potential energy is equal to the increase in kinetic energy.

mgh

250 x 9.8 x 30

=73, 500

Answer:

73,500 J

Explanation:

100% Correct

The diffraction grating in the experimental apparatus is used to split white light into its component colors (i.e. spectral colors) through the process of diffraction. The resulting pattern of colored lines (spectral lines) can then be analyzed to determine the composition or characteristics of the light source.

Here is a step-by-step explanation of how the diffraction grating works in the experimental apparatus:
1. Light from a source enters the apparatus and encounters the diffraction grating.
2. The grating, which consists of a series of parallel lines or slits, diffracts the incoming light.
3. The diffraction process separates the light into its constituent wavelengths, creating a spectrum.
4. The dispersed light can then be analyzed by a detector or observer, allowing for the determination of various properties of the light source.

In summary, the diffraction grating plays a crucial role in an experimental apparatus by dispersing light into its constituent wavelengths, enabling the analysis of the light's properties.

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Being made of charged particles, plasmas can do things gases cannot, like conduct electricity. And since moving charges make magnetic fields, plasmas also can have them. In an ordinary gas, all the particles will behave roughly the same way. Auroras, lightning, and welding arcs are also plasmas; plasmas exist in neon and fluorescent tubes, in the crystal structure of metallic solids, and in many other phenomena and objects. The Earth itself is immersed in a tenuous plasma called the solar wind and is surrounded by a dense plasma called the ionosphere.

Plasma is a type of matter in which many electrons freely roam around the nuclei of atoms.

Although plasma is commonly thought of as a subset of gases, the two states behave very differently. Plasmas, like gases, have no definite shape or volume and are denser than solids or liquids.

Plasma is a sort of matter in which numerous electrons freely roam around the nuclei of atoms.

Plasma has been described as the fourth state of matter, alongside solid, liquid, and gas.

Normally, electrons in a solid, liquid, or gaseous sample of matter remain bound to the same nucleus.

Thus, plasma is considered a distinct phase because it does not conform to the standard descriptions and physical laws that are used to describe the standard three states of matter.

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Measurements that are closely grouped around the mean are precise.

When measurements are closely grouped around the mean, it means that the data points are clustered together and are not spread out widely.

This indicates that the measurements are consistent and that the values are similar to one another. This consistency in the measurements is what we refer to as precision.

In other words, precision refers to the degree of closeness of individual measurements to each other. The more precise the measurements, the less variation there is between the individual data points.

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Answer:"precise"

Explanation:

Precision is different from accuracy. Measurements that are very close to each other, but not close to the true value would be precise, but not accurate.

When a resistor (R) is connected across a source of a potential difference (V), a current (i) flows through it and power is dissipated in the resistor.

This power is given by the equations P=i2R and P=V2/R.
We can break down these equations. The first equation, P=i2R, tells us that the power dissipated in the resistor is directly proportional to the square of the current flowing through it and the value of the resistance. This means that if the current increases, the power dissipated in the resistor will increase as well, and if the resistance increases, the power dissipated will decrease.
The second equation, P=V2/R, tells us that the power dissipated in the resistor is also directly proportional to the square of the voltage across it and inversely proportional to the value of the resistance. This means that if the voltage increases, the power dissipated in the resistor will increase as well, and if the resistance increases, the power dissipated will decrease.
When a resistor is connected across a source of potential difference, the power dissipated in the resistor can be calculated using either P=i2R or P=V2/R. The power dissipated is directly proportional to the square of the current and voltage, and inversely proportional to the resistance.

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