If a 1-gram sample of carbon from a long dead tree is 1/8 as radioactive as 1-gram sample of a living tree, then the old tree died about
a.22,920 years ago.
b.11,460 years ago.
c.17,190 years ago.
d.5,730 years ago.

The concentration measures will change in value as the temperature of a solution changes is molarity. The correct option is 4.

The molarity of a substance refers to how much of it is present in a given volume of solution (M). Molarity is the measure of how many moles of a solute are present per liter of a solution. Molarity is also referred to as a solution's molar concentration.

To find the equation for molarity, divide the volume of solvent used to dissolve the given solute by the number of moles of that solute. M = n V

Since the volume of the solution rises as the temperature rises, molarity decreases. Therefore, molarity is normally affected when therefore is a change in temperature of a solution either when it increases or decreases.

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Answer:

its FALSE

Explanation:

FAKE   ITS NOT REAL

Answer:

2H2(g]+O2(g]→2H2O(l]]. Notice that the reaction requires 2 moles of hydrogen gas and 1

Explanation:

Answer: 35/13

Explanation:

Answer:

17.03052 mutiple by 2

34.06104grams

We need to use stoichiometry to determine the number of moles of oxygen required to produce 2.33 moles of water. From the balanced chemical equation, we can see that the ratio of moles of oxygen to moles of water is 1:4. Therefore, we need to multiply 2.33 moles of water by the ratio of moles of oxygen to moles of water, which is 1/4.
2.33 moles of water x (1 mole of oxygen/4 moles of water) = 0.5825 moles of oxygen
Therefore, we need 0.5825 moles of oxygen to produce 2.33 moles of water in this reaction, assuming there is excess C3H7SH present.

In the given reaction, C3H7SH reacts with oxygen (O2) to produce CO2, SO2, and H2O. To determine how many moles of oxygen are required to produce 2.33 moles of water, we need to first balance the reaction:
C3H7SH(l) + 9/2 O2(g) → 3 CO2(g) + SO2(g) + 4 H2O(l)
From the balanced equation, we can see that 4 moles of H2O are produced from 9/2 moles of O2. To find the moles of O2 needed for 2.33 moles of H2O, we can use the stoichiometry:
(2.33 moles H2O) * (9/2 moles O2 / 4 moles H2O) = 5.2425 moles O2
So, 5.2425 moles of oxygen are required to produce 2.33 moles of water in this reaction, given there is excess C3H7SH present.

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hi <3

for this conversion, you need to multiply by 10^6

thus, your answer would be 75000 mm

hope this helps :)

The average rate of disappearance of CH3NC over the time period from t = 342 s to t = 513 s is -2.92×10-5 M s-1.

To calculate the average rate of disappearance of CH3NC over the time period from t = 342 s to t = 513 s, we can use the formula:

Average rate = (change in concentration) / (change in time)

First, we need to calculate the change in concentration of CH3NC over the time period from t = 342 s to t = 513 s:

[CH3NC]342s = 9.96×10-3 M

[CH3NC]513s = 5.97×10-3 M

Change in concentration = [CH3NC]513s - [CH3NC]342s

= 5.97×10-3 M - 9.96×10-3 M

= -4.99×10-3 M

(Note that the concentration has decreased, so the change in concentration is negative)

Next, we need to calculate the change in time:

Change in time = 513 s - 342 s

= 171 s

Now we can calculate the average rate of disappearance of CH3NC:

Average rate = (change in concentration) / (change in time)

= (-4.99×10-3 M) / (171 s)

= -2.92×10-5 M s-1

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Concepts from chemistry, such as biochemical reactions and acid-base balance, can provide a foundation for understanding various aspects of human anatomy and physiology.

1. Biochemical Reactions: The study of biochemical reactions, including enzyme kinetics, can provide insights into the metabolic processes occurring in the human body. Understanding concepts like enzyme-substrate interactions, reaction rates, and enzyme regulation can help explain how cells produce and utilize energy, synthesize essential molecules, and carry out various physiological functions. This knowledge is applicable to understanding processes such as cellular respiration, digestion, protein synthesis, and hormone regulation.

2. Acid-Base Balance: The concept of acid-base balance, including pH and buffering systems, is crucial in maintaining homeostasis in the human body. Understanding how acids and bases interact and how the body regulates pH is essential for comprehending physiological processes like blood gas exchange, renal function, and acid-base disorders. This knowledge is particularly relevant in fields such as nephrology, respiratory medicine, and critical care.

The hydrophobic effect phenomenon has significance in biological systems. It plays a role in the folding of proteins, the formation of cell membranes, and the assembly of biomolecules. However, it may require a more detailed understanding of biochemistry and molecular biology to fully appreciate its implications in human anatomy and physiology.

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Negative ions, designated by the notation (OH ), are always present in any acid or base. The concentration. [OH"] of these ions is related to H by the equation OH H = 10-14 moles per liter.

Find the concentrations of OH and Hl in moles per liter for the substances with the following pH value pH = 7.8

The pH of a solution is given by the expression:\(pH = -log[H+],\)

where [H+] is the hydrogen ion concentration in mol/L.

To find the concentration of [H], we use the equation:

pH = -log[H+]7.8

= -log[H+]H+

= 10^-7.8H+

= 1.58 x 10^-8 moles per liter

Now, let's find the concentration of [OH-] by using the formula:

OH- H+ = 10^-14[H+]

= 1.58 x 10^-8OH- (1.58 x 10^-8)

= 10^-14OH-

= (10^-14) + (1.58 x 10^-8)OH-

= 1.0000000000000158 x 10^-14 moles per liter

OH- = 1.00 x 10^-14 moles per liter (rounded to two decimal places)

Concentration of [H] is 1.58 × 10⁻⁸ moles per liter and the concentration of [OH] is 1.00 × 10⁻¹⁴ moles per liter.

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When the equilibrium mixture is cooled to 298 K, more sulfur trioxide (SO3) will not be produced. Instead, the reverse reaction will be favored at lower temperatures, causing the amount of sulfur trioxide to decrease, according to Le Chatelier's principle.

We have a gaseous mixture consisting of and in a 250-ml container that was heated to 500 K and allowed to reach equilibrium. We need to find if more sulfur trioxide will be formed if that equilibrium mixture is cooled to 298 K. Now, we will find out the effect of temperature change on the formation of sulfur trioxide.

The given reaction: 2SO2 (g) + O2 (g) ⇌ 2SO3 (g).

Let’s write down the expression for the equilibrium constant, Kc using the law of mass action as below:  

Kc = ( [SO_3]^2 ) / ( [SO_2]^2 [O_2] )`Where [SO2], [O2] and [SO3] represent the molar concentrations of the respective reactants and products at equilibrium. According to Le Chatelier's principle, if we alter any of the conditions of a system at equilibrium, the position of equilibrium will shift in such a way as to counteract the change made to the system. This indicates that the equilibrium position will shift in response to any change in temperature, pressure, or concentration, as we have stated before.

Let’s analyze the effect of a temperature change on the position of equilibrium for the given reaction: At a high temperature of 500 K, the value of the equilibrium constant Kc is calculated as Kc > 1, indicating that the forward reaction is favored at higher temperatures. At 298 K, however, the value of the equilibrium constant Kc is calculated as Kc < 1, indicating that the reverse reaction is favored at lower temperatures.

As a result, when the equilibrium mixture is cooled to 298 K, more sulfur trioxide (SO3) will not be produced. Instead, the reverse reaction will be favored at lower temperatures, causing the amount of sulfur trioxide to decrease, according to Le Chatelier's principle.

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Answer:

True

Explanation:

Phislosophy does not accept something even though it is a khown fact unless it can proves it's true .

Descartes sais that in philosophy we must doubt the facts we khow , we must start from the beginning to reach the truth

0.0085 moles

Explanation:

To find the quantity in moles of KCl in 50.0 mL of 0.170 M KCl, you can use the formula:

moles = volume (in liters) × molarity

Step 1: Convert the volume to liters.

Since there are 1000 mL in 1 L, you can convert 50.0 mL to liters by dividing by 1000:
50.0 mL ÷ 1000 = 0.050 L

Step 2: Multiply the volume in liters by the molarity to find the moles of KCl:
moles = 0.050 L × 0.170 M = 0.0085 mol

So, there are 0.0085 moles of KCl in 50.0 mL of 0.170 M KCl solution.

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Answer:

A mixture is the blending of two or more dissimilar substances. A major characteristic of mixtures is that the materials do not chemically combine. Mixtures can be divided into those that are evenly distributed (homogeneous) and those that aren't (heterogeneous).

Explanation:

To answer this question we have to use the rule of dilutions:

Where V1 is the initial volume, C1 is the initial concentration, V2 is the final volume and C2 is the final concentration. In this case we need to find V1.

Solve the equation for V1 and replace C1 for 4.00M, V2 for 665mL and C2 for 0.350M

It means that the volume required is 58.2mL.

Answer:

The answer is 21.5 L

Explanation:

Answer:

Granite Solid

Milk Liquid

Neon is gas

Wood Is solid

Paper is solid

Helium is Gas

Water is liquid

Air is Gas

Alcohol is liquid

Metal is solid

Nitrogen is gas

Juice is liquid

Oil is liquid

Water Vapor is Gas

Brick is Solid

Propane is Gas

Fabric is solid

Gasoline is Liquid

Explanation:

Hope Dis helped :D :3

Answer:

what is in your chemistry home work I can try for...

Answer:

1: A substance made by mixing other substances together.

2: Solutions, Suspensions, Colloids and Emulsion.

3: A particular kind of matter with uniform properties.

4: A homogenous mixture is that mixture in which the components mix with each other and its composition is uniform throughout the solution. A heterogenous mixture is that mixture in which the composition is not uniform throughout and different components are observed.

5: A solution is a homogeneous mixture of two or more components in which the particle size is smaller than 1 nm. Common examples of solutions are the sugar in water and salt in water solutions, soda water, etc. In a solution, all the components appear as a single phase.

6: A solution forms when one substance dissolves in another. The substance that dissolves is called the solute. The substance that dissolves it is called the solvent. For example, polar solvents dissolve polar solutes, and nonpolar solvents dissolve nonpolar solutes.

7: Common examples of suspension include the mixture of chalk and water, muddy water, the mixture of flour and water, a mixture of dust particles and air, fog, milk of magnesia, etc. Q2. Give the definition of suspension. Ans: A suspension is a heterogeneous mixture of two or more substances.

8: The Tyndall effect is light scattering by particles in a colloid or in a very fine suspension.

Explanation:

The enthalpy is the amount of heat present in a system. The enthalpy change of a reaction is given by the difference between the enthalpy of formation of products and reactants

The change in enthalpy for the combustion reactions are;

The reason the above values are correct are as follows:

ΔHrxn = The sum of enthalpies of formation of the products - The sum of enthalpies of formation of the reactants

a. The combustion of isooctane is presented as follows;

2C₈H₁₈ + 25O₂ → 16CO₂ + 18H₂O

The thermodynamic data required (obtained from a similar question) are;

H₂(g) + (1/2)O₂(g) → H₂O(g) ΔH⁰ = -241.8 kJ

C(s)  + O₂(g) → CO₂(g) ΔH⁰ = -393.5 kJ

8C(s) + 9H₂(g) → C₂H₁₈(l) ΔH⁰ = -224.13 kJ

Therefore, we get;

(-224.13 kJ) + ΔH = 8 × (-393.5 kJ) + 9 × (-241.8 kJ)

ΔH rxn = 5,100.07 kJ

b. The mass one gallon of isooctane, m = 2.6 kg - 2,600 g

The molar mass of isooctane = 114.23 g/mol

The number of moles of isooctane in 2,600 g of isooctane is given as follows

n = 2,600 g/(114.23 g/mol) ≈ 22.76 moles

The enthalpy change for the combustion of one gallon of isooctane is therefore;

ΔH = n × ΔH rxn = 22.76 moles × 5,100.07 kJ/mol ≈ 116,083.183 kJ

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In order to calculate the mass of carbon dioxide formed during the combustion of acetone, we need to balance the chemical equation first. Combustion of acetone takes place in the presence of oxygen gas to produce carbon dioxide and water.

The balanced chemical equation is given as:2C3H6O + 9O2 → 6CO2 + 6H2OFrom the equation, we can see that for every 2 moles of acetone burned, 6 moles of carbon dioxide are produced. Now, we need to calculate the number of moles of acetone present in 78.7 g.

To do this, we divide the mass of acetone by its molar mass: Molar mass of acetone (C3H6O) = 3 x 12.01 + 6 x 1.01 + 16.00 = 58.08 g/mol Number of moles of acetone = mass / molar mass = 78.7 / 58.08 = 1.354 moles Now that we know the number of moles of acetone, we can calculate the moles of carbon dioxide formed.

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No, the volume of water in a beaker is not an extensive property.

Extensive properties are those that depend on the amount or size of the substance being measured. In other words, they are properties that change with the quantity of the substance. Examples of extensive properties include mass, volume, and total energy.

In the given scenario, the volume of water in the beaker is 50 milliliters. This volume remains the same regardless of the quantity of water present. Whether it's 50 milliliters or 500 milliliters, the volume measurement does not change. Therefore, the volume of water in the beaker is an example of an intensive property.

Intensive properties are independent of the amount or size of the substance. They are characteristics that remain constant regardless of the quantity of the substance. Examples of intensive properties include temperature, density, and color.

It's important to note that the distinction between extensive and intensive properties depends on the specific property being considered. While volume is typically an extensive property for a bulk substance, in the case of a fixed volume of water in a beaker, it becomes an intensive property.

In summary, the volume of water in a beaker is not an extensive property but rather an intensive property because it does not change with the quantity of the substance.

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The pH after the addition of 81 mL of 0.40 M NaOH to 80.0 mL of 0.40 M HClO4 is 13.30

The balanced chemical equation for the reaction between HClO4 and NaOH is:

HClO4 + NaOH → NaClO4 + H2O

First, let's find the moles of HClO4 and NaOH present before the reaction:

moles HClO4 = 0.40 mol/L x 0.080 L = 0.032 mol

moles NaOH = 0.40 mol/L x 0.081 L = 0.0324 mol

Since the moles of NaOH added are greater than the moles of HClO4 initially present, NaOH is the limiting reagent. Therefore, all of the NaOH will react with the HClO4, and we need to find the number of moles of HClO4 that react with the NaOH.

According to the balanced equation, 1 mole of NaOH reacts with 1 mole of HClO4. Therefore, 0.0324 mol of HClO4 will react with the 0.0324 mol of NaOH.

The remaining moles of HClO4 after the reaction is given by:

moles HClO4 remaining = 0.032 mol - 0.0324 mol = -0.0004 mol

Since the resulting moles of HClO4 is negative, this means that all the HClO4 has been used up and the solution is basic. The excess NaOH reacts with water to produce hydroxide ions:

NaOH + H2O → Na+ + OH- + H2O

The total volume of the solution after the reaction is:

V = 80.0 mL + 81 mL = 0.161 L

The concentration of OH- ions produced is given by:

[OH-] = moles NaOH / V = 0.0324 mol / 0.161 L = 0.201 M

Using the expression for the ion product of water, we can calculate the concentration of H+ ions:

Kw = [H+][OH-] = 1.0 x 10^-14

[H+] = Kw / [OH-] = 1.0 x 10^-14 / 0.201 M = 4.975 x 10^-14

The pH of the solution is given by:

pH = -log[H+] = -log(4.975 x 10^-14) = 13.30

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The standard emf for the given cell reaction is 2.32.

The standard emf calculation and its significance in determining the feasibility of a redox reaction. The standard emf, also known as the standard electromotive force or cell potential, measures the driving force of an electrochemical cell under standard conditions. It represents the potential difference between the two electrodes when they are connected by a conducting medium.

To calculate the standard emf for a cell, we need to use the standard reduction potentials of the half-reactions involved in the overall cell reaction. Table 20.1 provides the necessary data for this calculation. The standard emf of the cell is determined by subtracting the reduction potential of the anode from the reduction potential of the cathode.

In this case, the overall cell reaction is 2Al(s) + 3I2(s) -> 2Al3+(aq) + 6I-(aq). By looking up the standard reduction potentials for the half-reactions of Al and I2 in the table, we find that the reduction potential for Al3+ + 3e- -> Al is -1.66 V, and the reduction potential for I2 + 2e- -> 2I- is 0.54 V.

To calculate the standard emf, we subtract the anode's reduction potential from the cathode's reduction potential: 0.54 V - (-1.66 V) = 2.32 V. Therefore, the standard emf for the cell employing the given overall cell reaction is 2.32 V.

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Answer:

Explanation:Due to the mental pressure,

                       Due to peer pressure,

                      Lack of love and affection from the family members.

                      Influence from the T.V advertisement.

Answer:

1. fission

2. both

3. fusion

4. fusion

5. fission

Explanation:

Fission refers to the splitting of a single nucleus into two or more small nuclei while fusion refers to the combination of two or more small nuclei into one heavy nucleus.

When a single heavy nucleus splits, energy is released and the end products are 2 or more lighter nuclei. On the other hand, when several light nuclei fuse into one nucleus, energy is absorbed and the end product is one heavy nucleus. Both fission and fusion result in a nuclear change.

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Answer: 2.5 moles of Argon, Ar contains 15.055 x 10^23 particles. ✅

Explanation:

To find the number of particles in 2.5 moles of Argon, we can use the Avogadro's number. Avogadro's number is the number of atoms, ions or molecules in one mole of a substance. It is defined as 6.022 x 10^23 particles per mole.

To convert moles to particles, we can multiply the number of moles by Avogadro's number.

2.5 moles x 6.022 x 10^23 particles/mole = 15.055 x 10^23 particles

So, 2.5 moles of Argon, Ar contains 15.055 x 10^23 particles.