If 7 4/5 of the total came to 109,200, what is the total?

The length of the arc WX is the number of units on the arc

The length of the arc WX is \(\frac{8}{9} \pi\)

The given parameters are:

Central angle, m<WVX = 20 degrees

Radius, VW = 8

The length (L) of the arc is calculated as:

\(L = \frac{\theta}{360} * 2\pi r\)

Substitute known values

\(L = \frac{20}{360} * 2\pi *8\)

Evaluate the product

\(L = \frac{320}{360} \pi\)

Simplify the fraction

\(L =\frac{8}{9} \pi\)

Hence, the length of the arc is \(\frac{8}{9} \pi\)

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Answer: parallelograms

Step-by-step explanation:

Step-by-step explanation:

Can you please attach the picture of the prism.

The polar coordinates of the point (4, −4) are ($4\sqrt 2$, $\frac {7π}4$).

The rectangular coordinates (4,−4) are need to be converted to polar coordinates (r,θ), where r is positive and θ is expressed in radians and in the interval [0,2π).

Step 1: Finding r using the formula $r = \sqrt {x^2 + y^2}$.Here, x = 4 and y = -4.

Hence, r = $\sqrt {4^2 + (-4)^2}$ = $\sqrt {16 + 16}$ = $\sqrt {32}$ = $4\sqrt 2$.Therefore, r = $4\sqrt 2$

Step 2: Finding θ using the formula $θ = tan^{-1}\frac yx$Here, x = 4 and y = -4.

Hence, θ = $tan^{-1}\frac {(-4)}4$ = $tan^{-1}(-1)$

Note: When $\frac yx$ is negative, θ lies in either the second or fourth quadrant.

To determine which quadrant θ lies in, we must use the signs of x and y. Here, x is positive, and y is negative. Hence, θ lies in the fourth quadrant. To find θ in the interval [0,2π), we add 2π to the angle obtained above, since this angle is negative.

θ = $tan^{-1}(-1) + 2π$= $-\frac π4$ + $2π$= $\frac {7π}4$

Therefore, the polar coordinates of the point (4, −4) are ($4\sqrt 2$, $\frac {7π}4$)

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Answer:

C.  \(f(x)=(x+1)^2-4\)

Step-by-step explanation:

A. the graph is a straight line with slope 1.  It goes up/down infinitely far so the range is all real numbers.  Not A!

B. The graph is a straight line with slope -4, so, like the function in A, the range is all real numbers.  Not B!

D. The graph is an absolute value function  y = |x|, reflected over the x-axis, shifted right 3 units, then shifted down 4 units.  So the graph starts witha "vee" shape opening up, becomes a vee opening down, then ultimately gets shifted down 4 units.  The range is all real numbers less than or equal to -4.

See the attached graphs.  image2 is the function in answer choice D.

The tangent of y(x) at x = 1 is y'(1) = 4 + C₁, and the value of f(1) is 5, we can solve for C₁ to get C₁ = 1. Therefore, the function y(x) = x⁴ / 4 + x + C₂, where C₂ is another constant.

The given equation is  f (x) = 5, and it is the tangent of the function y = x³ / 3 at x = 1.To get y = x (x² / 2 + C), we integrate the second derivative of y with respect to x.∫(d²y/dx²)dx = ∫(12x²)dx => y = 4x³ + C₁ Solve for C₁ by applying the point-slope equation at the point x = 1:f(1)

= 5

= y(1)

= 4(1)³ + C₁

=> C₁ = 1Therefore, the equation of y is: y = 4x³ + 1.For a more in-depth and better explanation, here are 150 words: A second derivative represents the rate of change of the first derivative with respect to x.

Therefore, if we have a second derivative of y with respect to x, we can integrate it twice to get a function of y with respect to x. Given y''(x) = 12x², we can integrate it once to obtain y'(x) = 4x³ + C₁, where C₁ is a constant. We integrate y'(x) once again to get y(x) = x⁴ / 4 + C₁x + C₂, where C₂ is another constant. Now, to find C₁ and C₂, we need to use the fact that the function f(x) = 5 is tangent to y(x) at x = 1.

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The tangent of y(x) at x = 1 is y'(1) = 4 + C₁, and the value of f(1) is 5, we can solve for C₁ to get C₁ = 1. Therefore, the function y(x) = x⁴ / 4 + x + C₂, where C₂ is another constant.

The given equation is  f (x) = 5, and it is the tangent of the function

y = x³ / 3 at x = 1.

To get y = x (x² / 2 + C),

we integrate the second derivative of y with respect to x.

∫(d²y/dx²)dx = ∫(12x²)dx

=> y = 4x³ + C₁

Solve for C₁ by applying the point-slope equation at the point

x = 1:f(1)

= 5

= y(1)

= 4(1)³ + C₁

=> C₁ = 1Therefore, the equation of y is: y = 4x³ + 1

.For a more in-depth and better explanation, here are 150 words: A second derivative represents the rate of change of the first derivative with respect to x.

Therefore, if we have a second derivative of y with respect to x, we can integrate it twice to get a function of y with respect to x.

Given y''(x) = 12x²,

we can integrate it once to obtain

y'(x) = 4x³ + C₁, where C₁ is a constant.

We integrate y'(x) once again to get

y(x) = x⁴ / 4 + C₁x + C₂, where C₂ is another constant.

Now, to find C₁ and C₂, we need to use the fact that the function

f(x) = 5 is tangent to y(x) at x = 1.

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The hypotheses for the test are H₀: σ₁² = σ₂² and H₁: σ₁² ≠ σ₂². This is a two-tailed test to assess if there is a difference in the standard deviations of sound levels between the areas designated as "casualty doors" and operating theaters. The claim being investigated is whether or not there is a difference in the standard deviations.

The hypotheses for the test are:

H₀: σ₁² = σ₂² (There is no difference in the standard deviations of the sound levels between the areas designated as "casualty doors" and operating theaters.)

H₁: σ₁² ≠ σ₂² (There is a difference in the standard deviations of the sound levels between the areas designated as "casualty doors" and operating theaters.)

This hypothesis test is a two-tailed test because the alternative hypothesis is not specifying a direction of difference.

To substantiate the claim that there is a difference in the standard deviations, we will conduct a two-sample F-test at a significance level of 0.10, comparing the variances of the two groups.

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The system of equations to determine the cost of a shirt and the cost of a pair of pants is 3s - 2p = $5 and 4s + 3p = $120

Define System of Equation

A set of simultaneous equations, also known as a system of equations or an equation system, is a finite set of equations for which common solutions are sought.

Given,

Jane bought 3 shirts and returned 2 pairs of pants

Laura bought 4 shirt and 3 pairs of pants.

Let, s = cost of shirt

and, p = cost of a pair of pants

The equation for Jane is

3s - 2p = $5

Here, -ve sign because Jane returned 2 pairs of pants and then bill was $5.

Now, the equation for Laura is

4s + 3p = $120

Here, +ve sign because Laura bought 4 shirt and 3 pairs of pants and then bill was $120.

So, the system of equation we get

3s - 2p = $5

4s + 3p = $120

After solving  simultaneously we get the values s = 15 and p = 20.

Now, if you want to cross check then put the values of s and p in equations and it should be equal to RHS value like this,

for 1st equation,

3 * 15 - 2 * 20 ⇒ 45 - 40 = 5 (which is correct)

for 2nd equation,

4 * 15 + 3 * 20 ⇒ 60 + 60 = 120 (which is correct)

Hence, The system of equations to determine the cost of a shirt and the cost of a pair of pants is 3s - 2p = $5 and 4s + 3p = $120.

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There are 5 different quadrilaterals that can be drawn using the given points A, B, C, D, and E.

To determine the number of different quadrilaterals that can be drawn using the given points A, B, C, D, and E, we need to consider the combinations of these points.

A quadrilateral consists of four vertices, and we can select these vertices from the five given points.

The number of ways to choose four vertices out of five is given by the binomial coefficient "5 choose 4," which is denoted as C(5, 4) or 5C4.

The formula for the binomial coefficient is:

C(n, r) = n! / (r!(n-r)!)

Where "n!" denotes the factorial of n.

Applying the formula to our case, we have:

C(5, 4) = 5! / (4!(5-4)!)

= 5! / (4!1!)

= (5 * 4 * 3 * 2 * 1) / ((4 * 3 * 2 * 1) * 1)

= 5

Therefore, there are 5 different quadrilaterals that can be drawn using the given points A, B, C, D, and E.

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Answer:

Area of shaded rectangle = 42 cm²

55%

Step-by-step explanation:

The length of the shaded area is equal to the length of the white rectangle.

Therefore, length of shaded rectangle = 7 cm

The width of the shaded rectangle is equal to the length of the white rectangle minus two widths of the white rectangle.

Therefore, width = 7 - (2 x 0.5) = 6 cm

Area of shaded rectangle = width x length

                                          = 6 x 7

                                          = 42 cm²

----------------------------------------------------------------------------------------------

Perimeter of a square = 4 × side length

If the perimeter of the square is 40 cm,
then the side length = 40 ÷ 4 = 10 cm

Area of a square = side length x side length

⇒ area of this square = 10 x 10 = 100 cm²

To determine the shaded area, calculate the areas of the 2 white triangles and subtract these from the area of the square.

Area of a triangle = 1/2 x base x height

⇒ area of left triangle = 1/2 x (10 - 7) x 10 = 15 cm²

⇒ area of right triangle = 1/2 x 10 x (10 - 4) = 30 cm²

Therefore, shaded area = 100 - 15 - 30 = 55 cm²

To calculate the percentage, divide the shaded area by the area of the square and multiply by 100:

(55 ÷ 100) × 100% = 55%

Answer:

(4, -5)

Step-by-step explanation:

completing the square:

x^2 - 8x + 11 = 0

(x-4)^2 + 11 - (-4)^2 = 0

(x-4)^2 + 11 - 16 = 0

(x-4)^2 -5 = 0

minimum point = (4, -5)

Answer:

-5

Step-by-step explanation:

Use the vertex form, y=a(x−h)2+ky=a(x-h)2+k, to determine the values of aa, hh, and kk.

a=1a=1

h=−4h=-4

k=−5

Answer:

x / 7 = -8

D) -56

-56/7 = -8

Answer:

Step-by-step explanation:

To solve this problem, first, you have to isolate by the x from one side of the equation.

Multiply by 7 from both sides of an equation.

x/7=-8

\(\sf\dfrac{7x}{7}=7(-8)\)

Solve.

7(-8)=-56

\(\large\boxed{x=-56}\)

Therefore, the correct answer is d. x=-56.

The engine in Edward's car is less efficient, so it uses more gas than the engine in Molly's car.

The efficiency of a car is a term that refers to the relationship between the distance the car travels and the amount of fuel it requires for that displacement.

Based on the above, we can infer that Molly's engine is more efficient than Edward's engine because it consumes less fuel and travels a greater distance.

Some factors that can affect the efficiency of cars are:

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A relation that contains no repeating groups and has nonkey columns solely dependent on the primary key but contains determinants is in the third normal form (3NF).

In this form, every monkey column of the relation is determined by the primary key and has no transitive dependencies on any other monkey column. This means that every column in the relation is uniquely identified by the primary key, and there are no redundant data in the relation. Therefore, the relation is free from anomalies such as update, deletion, and insertion anomalies. The third normal form is considered the most commonly used normal form in the relational database design, and it ensures data integrity and consistency. In summary, a relation that meets the criteria mentioned in the question is in 3NF.

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Answer:

25k - 150

Step-by-step explanation:

Equation:-

(k-6) x 25

=> 25k - 150

Answer:

32

Step-by-step explanation:

Lets work it out.

First we combine the two equations to get 5x-10. That is equal to 70 so we get out x = 16 we put that into the equation 3x-10 and get 32

The probability of ruin at or before time 3 with initial surplus 3 is 0.6915

The probability of ruin at or before time 3 with initial surplus 3, given the claim severity per period follows a binomial normal distribution with mean 4 and standard deviation 0.2, is calculated as follows:

Determine the z-score from the normal distribution corresponding to a surplus of 3 and a mean of 4.

z-score = (3-4)/0.2 = -0.5

Hence, the z-score result is -0.5

The next step is to use the cumulative probability density function to calculate the probability of ruin.

Probability of ruin = 1 - CDF(-0.5) = 1 - 0.3085 = 0.6915

Therefore, the probability of ruin at or before time 3 with initial surplus 3 is 0.6915.

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Answer:

Option C

Step-by-step explanation:

Since it's draining, it means it must start at a certain value and end at a maximum of 0 since water cannot ever be less than 0. Since it's original amount is 40, it can only start draining from 40 and end at max 0 hence 0 ≤ y ≤ 40

Topic: inequalities

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Bag one currently holds 25 kilograms of sugar, while bag two contains 75 kilograms of sugar.

Let's represent the initial amount of sugar in bag one as x and bag two as y. According to the given information, bag one has used 3 times as much sugar as bag two. This can be expressed as:

Bag one: x - 3y

Bag two: y

Furthermore, we are told that after using this amount of sugar, bag one has half as much sugar as bag two. Mathematically, we can express this as:

(x - 3y) = (1/2)y

Simplifying the equation, we get:

2(x - 3y) = y

2x - 6y = y

2x = 7y

Since we also know that the initial amount of sugar in each bag is 50 kilograms, we can set up another equation:

x + y = 100

We now have a system of two equations:

2x = 7y

x + y = 100

By solving these equations simultaneously, we find that x = 25 and y = 75. Thus, bag one currently holds 25 kilograms of sugar, while bag two contains 75 kilograms of sugar.

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Answer:

2

+

8

+

6Step-by-step explanation:

Answer:

Step-by-step explanation:

\(x^2+8x+6 =\\\\=\underline{x^2+2\cdot x\cdot 4+4^2}-4^2+6=\\\\=(x+4)^2-16+6=\\\\=(x+4)^2-10\)

Answer:

pretty sure it's 25° :))

Answer:

Step-by-step explanation:

Given data:

Q1

Q3

IQR is the difference of the above two numbers:

Correct choice s D

Answer:

D.  9 - 4 = 5

Step-by-step explanation:

Given data set:  1, 4, 5, 6, 6, 9, 11

To find the Interquartile Range (IQR):

Step 1

Place the data values in order from smallest to largest:

1, 4, 5, 6, 6, 9, 11

Step 2

To find the position of the lower quartile, count how many data values there are, add 1, and divide by 4:

\(\implies \sf \textsf{Position of lower quartile}= \dfrac{7\:data\:values+1}{4}=2nd\:position\)

Therefore, the lower quartile is 4.

Step 3

To find the position of the upper quartile, count how many data values there are, add 1, multiply by 3, and divide by 4:

\(\implies \sf \textsf{Position of upper quartile}= \dfrac{(7\:data\:values+1) \times 3}{4}=6th\:position\)

Therefore, the upper quartile is 9.

Step 4

\(\begin{aligned}\textsf{Interquartile range (IQR)} & = \textsf{upper quartile} - \textsf{lower quartile}\\& = \sf 9-4\\& = \sf 5 \end{aligned}\)

Answer:X\(x^{2} +2x-15\)

Step-by-step explanation:   you do it by multiplying  out the brackets and then you  simplify the result expression by collecting the like terms.

By Simpson's rule approximation, n should be at least 17 to guarantee that the Simpson's rule approximation is accurate to within 0.00001.

To guarantee that the Simpson's rule approximation to the integral ∫₀¹ e^(x²) dx is accurate to within 0.00001, you need to consider the error bound formula for Simpson's rule:

Error ≤ (K * (b - a)⁵) / (180 * n⁴)

In this case, a = 0, b = 1, and the desired error bound is 0.00001. The function to integrate is f(x) = e^(x²). To find the value of K, you need to determine the maximum value of the fourth derivative of f(x) on the interval [0, 1].

After calculating the fourth derivative, you'll find that K is less than or equal to 12 (K ≤ 12). Plug these values into the error bound formula:

0.00001 ≥ (12 * (1 - 0)⁵) / (180 * n⁴)

Solve for n:

n⁴ ≥ (12 * 1⁵) / (180 * 0.00001)

n⁴ ≥ 66666.67

n ≥ ∛√66666.67

n ≥ 16.10

Since n must be an integer, round up to the nearest whole number. Thus, n should be at least 17 to guarantee that the Simpson's rule approximation is accurate to within 0.00001.

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Answer:

d = 76 m

Step-by-step explanation:

It is given that, the speed of 4 ft per second when it takes off and flies upward

We need to find how far away from the surface of the water will the seagull be after 9 seconds.

Speed is distance over time.

So,

Distance, d = vt

d=4 ft/s × 19 s

d=76 meters

So, the seagull will be at a distance of 76 m from the surface of water.

Answer:

10.35

Step-by-step explanation:

23% is also means 0.23 so you just need to

0.23 * 45 = 10.35

pls brainiest

Answer:

10.35

Step-by-step explanation:

Eleven less than the product of five times a number "n" will be the 5*n - 11.

The mathematical symbol 5n can be used to represent the phrase "the product of five times an integer "n".

We can deduct 11 from 5*n in order to determine "eleven less than the product of five times an integer "n": 5*n - 11

As a result, the expression eleven less than the product of five times an integer "n" can be represented by the number 5*n - 11.

The phrase the product of five times a number "n" can be translated into the mathematical expression 5*n.

The mathematical symbol 5n can be used to represent the phrase "the product of five times an integer "n". We can deduct 11 from 5*n in order to determine "eleven less than the product of five times an integer "n": 5*n - 11.

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The value of c so that cx-d=2x+4 has No Solution is c=2.

In the given question ,

we have

cx-d=2x+4       ....(i)

Given that d = 2 ,

We substitute the value of d=2 in equation (i)

On substituting we get

cx-2=2x+4

Simplifying further we get

cx=2x+4+2

cx=2x+6

cx-2x=6

x(c-2)=6

x=6/(c-2)

For x to have NO SOLUTION the denominator should be 0.

because when denominator becomes 0 the value becomes not defined , hence will have no solution.

Substituting the denominator = 0

we get c-2=0

c=2.

Therefore , the value of c so that cx-d=2x+4 has No Solution is c=2.

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The event the student could run a mile in less than 8.27 minutes in terms of the value of the random variable y. The Probability of Y< 6 of 6.68%.

Random Variable:

A random variable is a variable whose value is unknown or a function that assigns a value to each outcome of an experiment. Random variables are often denoted by letters and can be classified as either discrete (variables that have a specific value) or continuous (variables that can take any value in a continuous range).

In probability theory and statistics, random variables can have many values ​​because they are used to quantify the outcome of random events. Random variables must be measurable and are usually real numbers. For example, the letter X can represent the sum of the numbers after rolling three dice. In this case, X can be 3(1 + 1 + 1), 18(6 + 6 + 6), or between 3 and 18. This is because the highest number on the dice is 6 and the lowest number is 1.

Given information.  

We have mean 7.11 minutes and standard deviation 0.74 minute.

We have to find the value of z.

Now,

    z = (x - μ/ σ)z

      = (6 - 7.11/ 0.74) z

      ≈ -1.50

Now,

The probability of Y < 6

P(Y< 6) = P(Z < -1.50)

            = 0.0668

            = 6.68%

Complete Question:

Running a mile A study of 12000 able-bodied male students at the University of Illinois found that their times for the mile run were approximately Normal with mean 7.11 minutes and standard deviation 0.74 minute. 7 Choose a student at random from this group and call his time for the mile Y. Find P(Y < 6) . Interpret this value.

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