Rounded up to the nearest whole number, we need 3 loads.
Assuming that each load has the same volume, we can calculate the volume of the material needed after compaction and shrinkage adjustments:
Swell of 15% means that the material will increase in volume by 15% after excavation and before compaction. So, the total volume needed after excavation is:
500 cubic yards / (1 + 0.15) = 434.78 cubic yards
Shrinkage of 95% means that the material will decrease in volume by 95% after compaction. So, the total volume needed after compaction is:
434.78 cubic yards * 0.05 = 21.74 cubic yards
Therefore, we need a total of 21.74 cubic yards of material after compaction and shrinkage adjustments. If each load has a volume of, say, 10 cubic yards, then we need:
21.74 cubic yards / 10 cubic yards per load = 2.174 loads
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0ten random numbers are drawn from a uniform distribution on . what is the probability that at least one will exceed 4.55? round your answer to three decimal places.
The probability that at least one random number is greater than 4.55 is 0.718 (rounded to three decimal places).
The probability of at least one number exceeding 4.55 can be calculated as the complement of the probability that all ten numbers are less than or equal to 4.55.
The probability density function of a uniform distribution on the interval [0, 5] is:
f(x) = 1/5, 0 <= x <= 5
The probability that one number is less than or equal to 4.55 is given by:
P(X <= 4.55) = ∫₀⁴.₅₅ f(x) dx = ∫₀⁴.₅₅ (1/5) dx = (1/5) * (4.55 - 0) = 0.91
So, the probability that all ten numbers are less than or equal to 4.55 is:
P(X₁ <= 4.55, X₂ <= 4.55, ..., X₁₀ <= 4.55) = (0.91)^10 = 0.2824
Therefore, the probability that at least one number exceeds 4.55 is:
P(at least one number > 4.55) = 1 - P(all numbers <= 4.55) = 1 - 0.2824 = 0.7176
So the probability that at least one random number is greater than 4.55 is 0.718 (rounded to three decimal places).
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Determine whether the relation "is child of" on the set of all people is (a) reflexive, (b) irreflexive, (c) asymmetric, (d) antisymmetric, (e) symmetric, (f) transitive. Justify your answers.
The relation "is child of" on the set of all people is (a) reflexive, (b) irreflexive, (c) asymmetric, (d) antisymmetric, (e) symmetric, (f) transitive.
Let's determine each of these properties one by one.
(a) Reflexive property of the relation "is child of": The relation "is child of" cannot be reflexive. It is not possible for a person to be their own child. Thus, for any person "x", there does not exist any pair of "x" and "x" such that x is the child of x.
(b) Irreflexive property of the relation "is child of": The relation "is child of" can be irreflexive. It is not possible for a person to be their own child.
Thus, for any person "x", there does not exist any pair of "x" and "x" such that x is the child of x. Therefore, the relation "is child of" is irreflexive.
(c) Asymmetric property of the relation "is child of": The relation "is child of" can be asymmetric. If person "a" is a child of person "b", then "b" cannot be a child of "a". Thus, the relation "is child of" is asymmetric.
(d) Antisymmetric property of the relation "is child of": The relation "is child of" cannot be antisymmetric. If person "a" is a child of person "b", then it is possible that "b" is a child of person "a" (just not biologically). Thus, the relation "is child of" is not antisymmetric.
(e) Symmetric property of the relation "is child of": The relation "is child of" cannot be symmetric. If person "a" is a child of person "b", then it is not necessary that person "b" is the child of person "a". Thus, the relation "is child of" is not symmetric.
(f) Transitive property of the relation "is child of": The relation "is child of" can be transitive. If person "a" is a child of person "b", and person "b" is a child of person "c", then it follows that person "a" is a child of person "c". Therefore, the relation "is child of" is transitive.
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Mike and Molly are participating in a canned food drive at school. There is a prize for whoever collects the most cans. Mike brought 10 cans from home and collected 7 cans a day from family and friends. Molly brought 12 cans from home and collected 7 cans a day from her neighbors. If they continued at the same rate, who won the contest?
Answer:
Molly would win
Step-by-step explanation:
Because she gets 19 cans a day and mike gets 17 cans a day
can someone please help me in this question
Answer:
a. 26 cm²
b. 55 cm²
c. 78 cm²
d. 89.27 cm²
Step-by-step explanation:
a. The shape can be decomposed into two rectangles
Area of the larger rectangle = L*W
L = 7 cm
W = 2 cm
Area of the larger rectangle = 7*2 = 14 cm²
Area of the smaller rectangle = L*W
L = 4 cm
W = 5 - 2 = 3 cm
Area of the larger rectangle = 4*3 = 12 cm²
Area of the compound shape = 14 + 12 = 26 cm²
b. The shape can be decomposed into a rectangle and a triangle.
Area of the compound shape = area of rectangle + area of triangle
= L*W + ½*b*h
L = 8 cm
W = 5 cm
b = 5 cm
h = 14 - 8 = 6 cm
Plug in the values
Area = 8*5 + ½*5*6
Area = 40 + 15
= 55 cm²
c. The shape can be decomposed into a rectangle and a trapezoid
Area of the compound shape = area of the rectangle + area of the trapezoid
= L*W + ½(a + b)h
L = 12 cm
W = 3 cm
a = 12 cm
b = 9 cm
h = 4 cm
Plug in the values
Area = 12*3 + ½(12 + 9)4
Area = 36 + 42
Area = 78 cm²
d. The shape can be decomposed into a rectangle and a semicircle
Area of the compound shape = area of the rectangle + area of the semicircle
= L*W + ½(πr²)
L = 10 cm
W = 5 cm
r = ½(10) = 5 cm
Plug in the values
Area = 10*5 + ½(π*5²)
Area = 50 + 39.27
Area = 89.27 cm²
in a survey of 9000 people, 4000 likes tea,4500 like coffee. among them 2500 dont like tea and coffee. find number of people who like tea and coffee both
Step-by-step explanation:
No of people likes tea = 4000
No of people like coffee = 4500
Total = 8500
No of people don't like tea and coffee = 2500
No of people like tea and coffee = 8500 - 2500 = 6000
Answer:
500
Step-by-step explanation:
n(t)=4000
n(c)=4500
n(tea only )= 4000-x
n(coffee only )= 4500-x
n(coffee and tea )= x
note...using Venn diagram ..all together must add up to 9000
(4000-x)+(4500-x) +x = 9000
..............
...........collect like terms
9500-9000 = x
x = 500
Find the global maximum and the global minimum values of function f(x, y) = x² + y² + x²y + 4 y²+x²y +4 on the region B = {(x, y) € R² | − 1 ≤ x ≤ 1, R2-1≤x≤1, -1≤ y ≤1}.
Therefore, the global maximum value of the function on the region B is 12, and the global minimum value is 4.
To find the global maximum and minimum values of the function f(x, y) = x² + y² + x²y + 4y² + x²y + 4 on the region B = {(x, y) ∈ R² | −1 ≤ x ≤ 1, -1 ≤ y ≤ 1}, we need to evaluate the function at its critical points within the given region and compare the function values.
1. Critical Points:
To find the critical points, we need to find the points where the gradient of the function is zero or undefined.
The gradient of f(x, y) is given by:
∇f(x, y) = (df/dx, df/dy) = (2x + 2xy + 2x, 2y + x² + 8y + x²).
Setting the partial derivatives equal to zero, we get:
2x + 2xy + 2x = 0 (Equation 1)
2y + x² + 8y + x² = 0 (Equation 2)
Simplifying Equation 1, we have:
2x(1 + y + 1) = 0
x(1 + y + 1) = 0
x(2 + y) = 0
So, either x = 0 or y = -2.
If x = 0, substituting this into Equation 2, we get:
2y + 0 + 8y + 0 = 0
10y = 0
y = 0
Thus, we have one critical point: (0, 0).
2. Evaluate Function at Critical Points and Boundary:
Next, we evaluate the function f(x, y) at the critical point and the boundary points of the region B.
(i) Critical point:
f(0, 0) = (0)² + (0)² + (0)²(0) + 4(0)² + (0)²(0) + 4
= 0 + 0 + 0 + 0 + 0 + 4
= 4
(ii) Boundary points:
- At (1, 1):
f(1, 1) = (1)² + (1)² + (1)²(1) + 4(1)² + (1)²(1) + 4
= 1 + 1 + 1 + 4 + 1 + 4
= 12
- At (1, -1):
f(1, -1) = (1)² + (-1)² + (1)²(-1) + 4(-1)² + (1)²(-1) + 4
= 1 + 1 - 1 + 4 + (-1) + 4
= 8
- At (-1, 1):
f(-1, 1) = (-1)² + (1)² + (-1)²(1) + 4(1)² + (-1)²(1) + 4
= 1 + 1 - 1 + 4 + (-1) + 4
= 8
- At (-1, -1):
f(-1, -1) = (-1)² + (-1)² + (-1)²(-1) + 4(-1)² + (-1)²(-1) + 4
= 1 + 1 + 1 + 4 + 1 + 4
= 12
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Find the length of each arc. Round your answer to the nearest tenth
Does this graph represent a function? Why or why not?
Answer:
I think it's a function because it passes the vertical line test
________________
Additional Comment
If you find the answer helpful, please mark Brainliest! :)
On Earth with a gravitational acceleration g , the potential energy stored in an object varies directly with its mass m and its vertical height h .
b. The acceleration due to gravity is g=-9.8m/s² . What is the height of the ramp if the skateboard has a potential energy of -39.2 kg m² /s² ?
The height of the ramp if the skateboard has a potential energy of -39.2 kg m² /s² = 2 m
What is gravitational acceleration ?Gravitational acceleration can be defined as the acceleration of any object when the object is in free fall. or we can say that the gravitational acceleration is the quantity which describes the acceleration of free falling object within vacuum. It is denoted by g .
What is Potential Energy ?Potential energy is the stored energy of the object which is generally based on the relative position of the various parts of the object. It is also known as gravitational energy.
Formula of potential energy :
U = mgh
where, U = gravitational energy
m = mass of object
g = gravitational acceleration
h = vertical height of object
In the question given,
g= -9.8m/s² , U = -39.2 kg m² /s²
as, U = mgh
h = U / mg
put the values in this equation
h = -39.2 / 2 (-9.8 )
h = 2
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The complete question is :
On Earth with a gravitational acceleration g , the potential energy stored in an object varies directly with its mass m and its vertical height h .
a. What is an equation that models the potential energy of a 2 -kg skateboard that is sliding down a ramp?
b. The acceleration due to gravity is g=-9.8m/s² . What is the height of the ramp if the skateboard has a potential energy of -39.2 kg m² /s² ?
how to find greatest common factor with variables and exponents
Answer:
Factoring Expressions With Exponents - Video & Lesson ...
To do this, take the greatest common factor of the numbers and the smallest exponent of each variable. 2. Divide the original expression by the greatest common factor. To do this, divide the coefficients, and subtract the exponents of the variables
Pls give brainliest
The greatest common factor (GCF) with variables and exponents is found by identifying the highest power of each variable that appears in the given expressions and choosing the one with the highest power. If a variable or exponent is not common to all the terms, it is not included in the GCF.
When finding the greatest common factor (GCF) with variables and exponents, we need to consider the highest power of each variable that appears in the given expressions. To find the GCF, we identify the common factors and choose the one with the highest power. If a variable or exponent is not common to all the terms, it is not included in the GCF.
Let's consider an example to illustrate this:
Given expressions: 2x^3y^2 and 4x^2y^3
To find the GCF, we look at the variables and exponents:
The variable 'x' appears in both expressions with exponents 3 and 2. The highest power of 'x' is 2.The variable 'y' appears in both expressions with exponents 2 and 3. The highest power of 'y' is 2.Therefore, the GCF is 2xy^2, as it is the highest power common to both expressions.
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find the critical numbers of the function on the interval 0 ≤ θ < 2π. g(θ) = 4 θ - tan(θ)
The critical numbers of g(θ) on the interval 0 ≤ θ < 2π are: θ = π/3, 2π/3, 4π/3, 5π/3, 7π/3, 8π/3, 10π/3, and 11π/3.
To find the critical numbers of g(θ) = 4θ - tan(θ) on the interval 0 ≤ θ < 2π, we need to find the values of θ where the derivative of g(θ) is equal to 0 or undefined.
First, we find the derivative of g(θ) using the chain rule and quotient rule:
g'(θ) = 4 - sec²(θ)
To find where g'(θ) is equal to 0, we set the derivative equal to 0 and solve for θ:
4 - sec²(θ) = 0
sec²(θ) = 4
Taking the square root of both sides, we get:
sec(θ) = ±2
Since sec(θ) = 1/cos(θ), we can rewrite this as:
cos(θ) = ±1/2
We know that on the interval 0 ≤ θ < 2π, the cosine function is positive in the first and fourth quadrants and negative in the second and third quadrants.
Therefore, we need to find the values of θ in the first and fourth quadrants where cos(θ) = 1/2, and the values of θ in the second and third quadrants where cos(θ) = -1/2.
For cos(θ) = 1/2, we have:
θ = π/3 or 5π/3 in the first quadrant
θ = 7π/3 or 11π/3 in the fourth quadrant
For cos(θ) = -1/2, we have:
θ = 2π/3 or 4π/3 in the second quadrant
θ = 8π/3 or 10π/3 in the third quadrant
Therefore, the critical numbers of g(θ) on the interval 0 ≤ θ < 2π are:
θ = π/3, 2π/3, 4π/3, 5π/3, 7π/3, 8π/3, 10π/3, and 11π/3.
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Plan 2 is a better deal for more than 8 cards purchased
Plan 1 is a better deal for more than 8 cards purchased
Plan 1 is a better deal for more than 5 cards purchased
Plan 2 is a better deal for more than 5 cards purchased
Where the above conditions are given, the correct option is: Plan 1 is a better deal for more than 5 cards purchased.
How is this so?
To determine which pricing plan is a better deal,we need to compare the total cost for a certain number of game cards purchased.
Let's calculate the total cost for different numbers of game cards.
For Plan 1 -
- Admission fee - $5 (fixed)
- Cost per game card - $1
For Plan 2 -
- Admission fee - $2.50 (fixed)
- Cost per game card - $1.50
Now, let's compare the total cost for different numbers of game cards -
1. If you purchase 1 game card -
- Plan 1 - $5 (admission fee) + $1 (cost per game card) = $6
- Plan 2 - $2.50 (admission fee) + $1.50 (cost per game card) = $4
2. If you purchase 5 game cards -
- Plan 1 - $5 (admission fee) + $5 (cost for 5 game cards) = $10
- Plan 2 - $2.50 (admission fee) + $7.50 (cost for 5 game cards) = $10
3. If you purchase 8 game cards -
- Plan 1 - $5 (admission fee) + $8 (cost for 8 game cards) = $13
- Plan 2 - $2.50 (admission fee) + $12 (cost for 8 game cards) = $14.50
Based on these calculations, we can conclude that -
- Plan 1 is a better deal for more than 5 cards purchased.
- Plan 2 is a better deal for more than 8 cards purchased.
Therefore, the correct option is - Plan 1 is a better deal for more than 5 cards purchased.
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Angel buys a two-pint bottle of juice for $3.84. What is the unit rate of the cost of the juice per fluid ounce?
How many fluid ounces of juice did Angel buy?
Answer:
I believe it is $0.12
Step-by-step explanation:
there are 16 oz in a pint and because there are 2 pints double that to equal 32 and then divide the price by the quantity which in this case would be 3.84/32 which is equal to 0.12, so it should be $0.12
Answer: the unit rate or how much each fl ounce cost would be $0.12
becuase she bought 32 fl oz
Step-by-step explanation:
Matemáticas tema: cuantas veces con base alas actividades de los días anteriores responde las preguntas
Respuesta:
53 1/3 g
600 gramos
$ 3200
1125 onzas
233 1/3
1500
300 pulg
Explicación paso a paso:
1.) 2/3 * 80 g = (2 * 80) / 3 = 160/3 = 53 1/3 g
2.) 6/8 * 800 g = (6 * 800) / 8 = 4800/8 = 600 g
3.) 4/5 * 4000 = (4 * 4000) / 5 = 16000/5 = $ 3200
4.) 3/4 * 1500 = (3 * 1500) / 4 = 4500/4 = 1125 oz
5.) 2/3 * 350 = (2 * 350) / 3 = 700/3 = 233 1/3 m
6.) 2/8 * 6000 = (2 * 6000) / 8 = 12000/8 = 1500
7.) 3/5 * 500 = (3 * 500) / 5 = 1500/5 = 300 pulgadas
I will give brainliest if correct !!
Answer:
58
Step-by-step explanation:
can someone tell me the answer to. 16 = 2(2x + 4)
Answer:
16= 4x+8
16-8=4x
x=8/4
x= 2
Step-by-step explanation:
16=2(2x+4) 16=(2×2x) + (4×2) 16= 4x+8. 16-8=4x+8-8. 8=4x. 8/4=4x/4. 2=x
so I kina need answers for all 4 problems.
The percentage markup and the profit for each statement is given below
What is a percentage?The percentage is calculated by dividing the required value by the total value and multiplying by 100.
Example:
Required percentage value = a
total value = b
Percentage = a/b x 100
Example:
50% = 50/100 = 1/2
25% = 25/100 = 1/4
20% = 20/100 = 1/5
10% = 10/100 = 1/10
We have,
1)
Purchase price = $3.25
Resold price = $9.50
Percentage markup.
= (9.50 - 3.25)/3.25 x 100
= 192.31%
Profit.
= 9.50 - 3.25
= $6.25
2)
Purchase price = $5
Resold price = $8.50
Percentage markup.
= (8.50 - 5)/5 x 100
= 3.50/5 x 100
= 70%
Profit.
= 8.50 - 5
= $3.50
3)
Purchase price = $50
Resold price = $88
Percentage markup.
= (88 - 50)/50 x 100
= 38/50 x 100
= 76%
Profit.
= 88 - 50
= $38
4)
Purchase price = $12.50
Resold price = $23.75
Percentage markup.
= (23.75 - 12.50)/12.50 x 100
= 90%
Profit.
= 23.75 - 12.50
= $11.25
Thus,
Each statement is solved above.
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The first three terms of a sequence are given. Round to the nearest thousandth (if
necessary).
10, 17, 24, ...
Find the 33rd term.
Answer:
234
Step-by-step explanation:
The consecutive terms of the sequence have a common difference d
d = 17 - 10 = 24 - 17 = 7
This indicates the sequence is arithmetic with n th term
\(a_{n}\) = a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = 10 and d = 7 , thus
\(a_{33}\) = 10 + (32 × 7) = 10 + 224 = 234
write the product in standard form: (x+4)(x-4)
Answer:
x² - 16
Step-by-step explanation:
Use the FOIL method here where
F = first
O = outer
I = inner
L = last
F = x * x = x²
O = -4 * x = -4x
I = 4 * x = 4x
L = -4 * 4 = -16
Combine the terms to get x² - 16.
determine whether the sequence converges or diverges. if it converges, find the limit. (if the sequence diverges, enter diverges.) an = n4 n3 − 4n
The limit of {an} as n approaches infinity is infinity, the sequence {an} diverges.
How to find sequence of an n⁴ / n³ - 4n?To determine whether the sequence {an} converges or diverges, we can take the limit as n approaches infinity and see what happens.
lim(n→∞) an = lim(n→∞) (n⁴ / n³ - 4n)
We can simplify this by dividing both the numerator and denominator by n³:
lim(n→∞) an = lim(n→∞) (n⁴/ n³ - 4n) = lim(n→∞) (n / (1 - 4/n²))
As n approaches infinity, the denominator 1 - 4/n^2 approaches 1, so we can simplify further:
lim(n→∞) an = lim(n→∞) (n / (1 - 4/n²)) = lim(n→∞) (n / 1) = ∞
Since the limit of {an} as n approaches infinity is infinity, the sequence {an} diverges
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Evelyn has $638.54 in her checking account. She must maintain a $500 balance to avoid a fee. She wrote a check for $159.50 today. Write and solve an inequality that would be used for the least amount of money she needs to deposit to avoid a fee.
Inequality to represent the amount in checking account is $638.54 with check written for $159.50 and maintained balance of $500 to avoid fee is given by $638.54 -$159.50 + y ≥ $500 and the least amount of money deposited by Evelyn to avoid fee is $20.96.
As given in the question,
Total amount in Evelyn checking account = $638.54
Amount for which check written = $159.50
Balance amount to avoid fee = $500
Let y be the amount needs to be deposited by Evelyn to avoid fee
Required inequality is given by :
$638.54 -$159.50 + y ≥ $500
⇒ 479.04 + y ≥ $500
⇒ y ≥ $(500 - 479.04)
⇒ y ≥ $20.96
Therefore, inequality to represent the amount in checking account is $638.54 with check written for $159.50 and maintained balance of $500 to avoid fee is given by $638.54 -$159.50 + y ≥ $500 and the least amount of money deposited by Evelyn to avoid fee is $20.96.
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Good luck everyone if this is your last bit of school. :)
Answer:
thanks good luck to u too
Step-by-step explanation:
Can i get help y=7x-2 A.(3,15) B.(-1,-10) C. (3,15) and (-1,-10) D. Neither
Answer:
D. Neither.
Step-by-step explanation:
y = 7x + 2.
I am not sure what you want to find, but I assume you put the coordinates into the equation and find whether they fit.
A. (3, 15).
y = 7 * 3 - 2 = 21 - 2 = 19
y is not equal to 19, so A does not work.
B. (-1, -10).
y = 7 * -1 -2 = -7 - 2 = -9
y is not equal to -9, either, so B does not work.
C. A combination of the two coordinates, which we know do not work.
D. Neither. Neither of the coordinates work, so this is the answer.
Hope this helps!
Answer:
neither
Step-by-step explanation:
y=7x-2 for (3,15)
y=7(3)-2
y=19 not solution
(-1.10)
y=-7-2=-9 not a solution
Verify that P = (1, −1) is the same distance from A = (5, 1) as it is from B = (−1, 3).
It is customary to say that P is equidistant from A and B. Find two more points that are equidistant from A and B. Can points equidistant from A and B be found in every quadrant? Explain.
The given statement is true that the distance of P to A is equal to the distance from P to B.
Given that,
To verify that P = (1, −1) is the same distance from A = (5, 1) as it is from B = (−1, 3).
Coordinate, is represented as the values on x axis and y-axis of the graph
Here,
According to the question,
AP = PB
√[(5-1)² + (1+1)²] = √[(1+1)² + (3 + 1)²]
√[16 + 4] = √[16 + 4]
√20 = √20
it implies the distance of point P from Point A is equal to the distance of P from B.
Thus, the given statement is true that the distance of P to A is equal to the distance from P to B.
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Which of the following transforms this non-statistical question into a statistical question? How much food does your dog eat?
Answer:
A) Not statistical /this question is answered by counting the number of days in March. This produces a single number. This number is not answered by collecting data that vary.
B) Not Statistical/ this question is answered by a single number. It is not answered by collecting data that vary.
C) Statistical/ this question would be answered by all collecting data, and there would be variability in that data.
D) statistical/ this question would be answered by collecting data, and there would be variability in that data
E) Not Statistical/ this question is answered by a single response. It is not answered by collecting data that vary.
F) not statistical/ this question would be answered by counting the bricks. This produces a single number. This question is not answered by collecting data that very
G) non-statistical/ there is only one temperature
Answer:I think it’s possibly A it’s what I got on my test and got it right.
f(x1, x2) 421 +222 3x² +213 5x11² (√₁+√₂)² 10ln(₁) (x₁+x₂)(x² + x3) min(3r1, 10√2) max{5x1,2r2} MP1(x1, x₂) MP2(X1, X₂) TRS(x1, x₂) Output (2,4)
The given mathematical expression is evaluated for the input values (2, 4). The result of the expression is calculated using various operations such as addition, multiplication, square root, natural logarithm, minimum, maximum, and function composition.
The expression f(x1, x2) involves several mathematical operations. Let's evaluate each part of the expression step by step:
1. The first term is 421 + 222, which equals 643.
2. The second term is 3x² + 213. Plugging in x1 = 2 and x2 = 4, we get 3(2)² + 213 = 3(4) + 213 = 12 + 213 = 225.
3. The third term is 5x11². Substituting x1 = 2 and x2 = 4, we have 5(2)(11)² = 5(2)(121) = 1210.
4. The fourth term is (√₁+√₂)². Replacing x1 = 2 and x2 = 4, we obtain (√2 + √4)² = (1 + 2)² = 3² = 9.
5. The fifth term is 10ln(₁). Plugging in x1 = 2, we have 10ln(2) = 10 * 0.69314718 ≈ 6.9314718.
6. The sixth term is (x₁+x₂)(x² + x3). Substituting x1 = 2 and x2 = 4, we get (2 + 4)(2² + 4³) = 6(4 + 64) = 6(68) = 408.
7. The seventh term is min(3r1, 10√2). As we don't have the value of r1, we cannot determine the minimum between 3r1 and 10√2.
8. The eighth term is max{5x1,2r2}. Since we don't know the value of r2, we cannot find the maximum between 5x1 and 2r2.
9. Finally, we have MP1(x1, x2), MP2(X1, X2), and TRS(x1, x2), which are not defined or given.
Considering the given expression, the evaluated terms for the input values (2, 4) are as follows:
- 421 + 222 = 643
- 3x² + 213 = 225
- 5x11² = 1210
- (√₁+√₂)² = 9
- 10ln(₁) ≈ 6.9314718
- (x₁+x₂)(x² + x3) = 408
The terms involving min() and max() cannot be calculated without knowing the values of r1 and r2, respectively. Additionally, MP1(x1, x2), MP2(X1, X2), and TRS(x1, x2) are not defined.
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Ayden earned a score of 50 on Exam A that had a mean of 75 and astandard deviation of 10. He is about to take Exam B that has a meanof450 and a standard deviation of 20. How well must Ayden score onExam B in order to do equivalently well as he did on Exam A? Assumethat scores on each exam are normally distributed.
For the first exam we know that:
\(\begin{gathered} \mu_{1\text{ }}=75 \\ \sigma_1\text{ = 10} \\ \text{score}_1\text{ = 50} \end{gathered}\)So, Ayden was 2.5 five standard deviation away from the mean:
\(50\text{ = }\mu_1\text{ - 2.5}\sigma_1\text{ = 75 - 2.5}\cdot10\text{ = 75 - 25}\)For the second exam, we know that:
\(\begin{gathered} \mu_2\text{ = 450} \\ \sigma_2\text{ = 20} \end{gathered}\)To do equivalently, Ayden score must be 2.5 standar deviations away from the mean, so:
\(\text{score}_2\text{ = }\mu_2-2.5\sigma_2\text{ = 450-2.5}\cdot20\text{ = 450-50 = 400}\)Solve for x.
x = [?]
4x + 4 4x - 32
Simplify:
4a - (-3b) + (-2c)
Answer: 4a+3b-2c
this is the answer
Use the distributive property to remove the parentheses.
(w+12)8
Answer:
(8w+96)
Step-by-step explanation:
(w+12)8
8(w+12)
8•w
8•12
(8w+96)