If 4.23 mol of ethane (C2H6) undergo combustion according to the unbalanced equation
C2H6 + O2 −→ CO2 + H2O ,
how many moles of O2 is required?

Answer:

don't know really and don't know at alll

6.02 x \(10^{20\) formula units of MgCl₂ is equal to 0.1 moles of MgCl₂.

To convert formula units of MgCl₂ to moles of MgCl₂, we need to use Avogadro's number, which relates the number of formula units to the number of moles.

Avogadro's number (NA) is approximately 6.022 x 10^23 formula units per mole.

Given that we have 6.02 x 10^20 formula units of MgCl₂, we can set up a conversion factor to convert to moles:

(6.02 x 10^20 formula units MgCl₂) * (1 mol MgCl₂ / (6.022 x 10^23 formula units MgCl₂))

The formula units of MgCl₂ cancel out, and we are left with moles of MgCl₂:

(6.02 x 10^20) * (1 mol / 6.022 x 10^23) = 0.1 mol

Therefore, 6.02 x 10^20 formula units of MgCl₂ is equal to 0.1 moles of MgCl₂.

It's important to note that this conversion assumes that each formula unit of MgCl₂ represents one mole of MgCl₂. This is based on the stoichiometry of the compound, where there is one mole of MgCl₂ for every one formula unit.

Additionally, this conversion is valid for any substance, not just MgCl₂, as long as you know the value of Avogadro's number and the number of formula units or particles you have.

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Answer:

\(Q=2091J=2.091kJ\)

Explanation:

Hello,

In this case, the formula we use to compute the heat Q by increasing the temperature, in terms of the mass and the heat capacity is:

\(Q=mCp(T_2-T_1)\)

Titanium's heat capacity is 0.544284 J/g°C, thus, the for such temperature increase, the heat results positive as shown below:

\(Q=22.6g*0.544284\frac{J}{g^oC}*(1590^oC-1420^oC) \\\\Q=2091J=2.091kJ\)

Best regards.

The number of mole of tin (Sn) that you have is 0.058 mole

6.02×10²³ atoms = 1 mole of tin (Sn)

With the above information, we can obtain the number of mole ot tin. Details below

We can obtain the number of mole of tin as follow:

6.02×10²³ atoms = 1 mole of tin (Sn)

Therefore,

3.5×10²² atoms = (3.5×10²² atoms × 1 mole) / 6.02×10²³ atoms

3.5×10²² atoms = 0.058 mole of tin (Sn)

Thus, the number of mole of tin (Sn) you have is 0.058 mole

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Answer:

C) 0.457

Explanation:

The ratio between O2 and H2O is 1:2 according to the balanced equation. You can find how many moles is O2 by : 5.12/22.4 = 0.22857 ( 1 mole = 22.4 litters)

Moles of H2O will be 0.22857 * 2 = 0.457142.

Therefore answer C)

Answer:

CH4

Explanation:

if it is wrong, i blame my brain

Answer:

1. Matter

2. Atom

3. Proton

4. Nucleus

5. Electron

6.Neutron

Answer:Chlorine:

It is an element that belongs to the p-block and non-metal.

It shows a variable oxidation state.

The oxidation number of chlorine can be - 1, 0, + 1, + 3, + 4, + 5, or + 7 which depends on the substance containing the chlorine.

Explanation:

Cl has a -1 oxidation number, except when bonded to a F or an O.

Answer:

Mathematical Literacy refers to the ability to reason with quantitative expressions in comparative, proportional and percentage terms. It is this definition that most lends itself to an examination of skill levels across Canada's education system - which ones are required for success in society (in the simplest sense) and which ones are superfluous.

*ANSWER MADE BY AN AI*

Answer:

8

Explanation:

Answer:

True

Explanation:

Copper has the highest electrical conductivity rating of all non-precious metals: the electrical resistivity of copper = 16.78 nΩ•m at 20 °C. Specially-pure Oxygen-Free Electronic (OFE) copper is about 1% more conductive (i.e., achieves a minimum of 101% IACS).

True is the correct answer.

The half-life of the radioactive substance is approximately 2.06 hours.

The half-life of a radioactive substance is the amount of time required for half of the initial amount of the substance to decay. If the rate of decay is proportional to the amount of the substance present at time t, the half-life of the substance can be determined as follows:

Let t be the half-life of the substance, then after t hours, the amount of the substance present will be 100 mg × (1/2) = 50 mg.

At time 4 hours, the amount of the substance present is 100 mg × (1 - 3%) = 97 mg.

Since the rate of decay is proportional to the amount of substance present, the half-life can be calculated as follows: t = 4 hours × (50 mg / 97 mg) = 2.06 hours.

Therefore, the half-life of the radioactive substance is approximately 2.06 hours.

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The maximum possible efficiency of the heat engine that uses reservoirs at 800°C and 0°C is 74%.

Maximum efficiency is mainly calculated for heat engines.

Let the starting temperature be T1 and the 2nd temperature is T2.

Since the given temperatures are in Celcius form, we have to first convert the temperatures into Kelvin form for proper calculation of maximum efficiency.

So, T1 = 0 + 273 = 273 K

T2 = 800 + 273 = 1073 K

We know,

Maximum efficiency = (T2- T1)/T2

= (1073 - 273) / 1073

= 800 / 1073

= 0.74

= 74 %

Therefore, the maximum efficiency of the heat engine will be 74%.

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Answer:

It detects negative static electricity when protons are drawn down into the

Explanation:

electroscope, instrument for detecting the presence of an electric charge or of ionizing radiation, usually consisting of a pair of thin gold leaves suspended from an electrical conductor that leads to the outside of an insulating container.

The IUPAC name and molecular formula for the following are,

a) prop-1-yne, C3H4

b) non-4-yne, C9H16

c) hex-3-yne, C6H10

What is IUPAC name?

International Unit for Pure and Applied Chemistry (IUPAC) is the method of naming the organic compounds in chemistry. It creates a standardized naming for the chemical compounds. There are prefixes, suffixes and parent chain considered while naming a compound.

The IUPAC name can be written by counting the parent chain carbons and considering the functional group present which is a triple bond in the given compounds. The molecular formula can be written by counting the number of different atoms present in the compound.

Therefore, the IUPAC name and molecular formula of the given compounds can be written as,

a) prop-1-yne, C3H4

b) non-4-yne, C9H16

c) hex-3-yne, C6H10

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Answer:

1 - Gravitational.

2 - Normal

3 - Tension

4 - Frictional

5 - Centripetal

Explanation:

1. If you drop something, gravity pulls it down to the Earth, So falling towards the earth is gravity.

2. Pushing back on another object is normal, Newton's law: Every action has an equal and opposite reaction.

3. When two forces are pulled on opposite sides, the object must stretch which creates tension. Think of a rubber band. If it is pulled more than the object can stretch, it will tear. Tensile strength refers to how much pulling force an object can withstand before it tears.

4. When objects or molecules rub against other objects or molecules they create friction.

5. Last two options go together.

Answer:

1632 Hz

Explanation:

We'll begin by calculating the frequency of each wave. This can be obtained as follow:

1st wave:

Velocity (v) = 340 m/s.

Wavelength 1 (λ₁) = 5 m

Frequency 1 (f₁) =?

v = λ₁f₁

340 = 5 × f₁

Divide both side by 5

f₁ = 340 / 5

f₁ = 68 Hz

2nd wave:

Velocity (v) = 340 m/s.

Wavelength 2 (λ₂) = 0.2 m

Frequency 2 (f₂) =?

v = λ₂f₂

340 = 0.2 × f₂

Divide both side by 0.2

f₂ = 340 / 0.2

f₂ = 1700 Hz

Finally, we shall determine the difference in the frequency of both waves.

This can be obtained as follow:

Frequency 1 (f₁) = 68 Hz

Frequency 2 (f₂) = 1700 Hz

Difference =?

Difference = f₂ – f₁

Difference = 1700 – 68

Difference = 1632 Hz

Answer:

Explanation:

The new volume can be found by using the formula for Boyle's law which is

\(P_1V_1 = P_2V_2\)

Since we are finding the new volume

\(V_2 = \frac{P_1V_1}{P_2} \\\)

From the question we have

\(V_2 = \frac{4 \times 1.1}{3.4} = \frac{4.4}{3.4} \\ =1.294117647... \)

We have the final answer as

Hope this helps and

The amount, in kJ, of heat needed to completely vaporize 50.0g of water at 100°C is 118.8 kJ.

The heat needed to completely vaporize 50.0g of water at 100°C can be calculated using the following formula:

q = m x Hv

where:

First, we need to convert 50.0g to moles by dividing by the molar mass of water which is approximately 18.015 g/mol3:

moles of water = 50.0 g / 18.015 g/mol moles of water = 2.776 mol

Thus:

q = (2.776 mol) x (40.65 kJ/mol) q = 112.8 kJ

In other words, 112.8 kJ of heat is needed to completely vaporize 50.0g of water at 100°C.

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The heating curve of water is the temperature of a given volume of water changes as heat is added at a consistent pace, as shown by the water heating curve. The temperature of the water does not vary throughout a phase shift, creating a plateau on the graph.

A meniscus is a curvature that appears on the surface of a molecular substance (water, of course) when it comes into contact with another material. You may imagine that happening with water when it adheres to the interior of a glass.

Hence, The relationship between the supply temperature of the heating system and the outside air temperature is known as the heating curve. The CH boiler's ability to heat water to a specific temperature at a specific outside temperature is determined by the heating curve.

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The combined gas law equation is:

(P1 * V1) / (T1) = (P2 * V2) / (T2)

The volume of the gas at 30 °C is approximately 760.67 mL.

To determine the volume of the gas at 30 °C, we can use the combined gas law equation, which relates the initial and final conditions of temperature and volume for a gas.

The combined gas law equation is:

(P1 * V1) / (T1) = (P2 * V2) / (T2)

Where:

P1 and P2 are the initial and final pressures, respectively

V1 and V2 are the initial and final volumes, respectively

T1 and T2 are the initial and final temperatures in Kelvin, respectively

We need to convert the temperatures from Celsius to Kelvin by adding 273.15 to each value.

Given:

V1 = 550 mL

T1 = -55 °C = 218.15 K

T2 = 30 °C = 303.15 K

Assuming the pressure remains constant, we can rearrange the equation to solve for V2:

V2 = (P1 * V1 * T2) / (P2 * T1)

Since the pressure is not specified in the problem, we can assume it remains constant, allowing us to cancel out the pressure terms. Thus, the final equation becomes:

V2 = (V1 * T2) / T1

Plugging in the given values:

V2 = (550 mL * 303.15 K) / 218.15 K

Simplifying the calculation, we find:

V2 ≈ 760.67 mL

Therefore, the volume of the gas at 30 °C is approximately 760.67 mL.

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Answer:

200.0lg

Explanation:

please give a brainliest

Answer:

Compound

Explanation:

Compounds – Compounds are chemical substances made up of two or more elements that are chemically bound together in a fixed ratio.

Example of compounds includes water (H2O), Hydrogen Peroxide (H2O2), etc. You could see water’s chemical formula, it says it has 2 atoms of Hydrogen combined with 1 atom of oxygen and in hydrogen peroxide, it has 2 atoms of hydrogen and two atoms of oxygen.

Glycolysis and photosynthesis are fundamental processes that are necessary for the survival of living organisms. They are similar in that they both involve the conversion of energy, but differ in the source of energy used, the location of the process, and the requirement for oxygen.

Glycolysis and photosynthesis are two necessary fundamental processes. Glycolysis is a metabolic pathway that occurs in the cytoplasm of cells. The glycolysis process is necessary because it produces ATP, which is the energy required for all cellular activities.

The energy is produced by breaking down glucose into two pyruvate molecules.Photosynthesis is the process by which green plants make their food. During photosynthesis, light energy is converted into chemical energy, which is stored in glucose molecules. This process is also necessary as it provides food and oxygen for most living organisms to survive.In terms of similarities, both glycolysis and photosynthesis are processes that involve the conversion of energy.

In glycolysis, glucose is converted into pyruvate and ATP, while in photosynthesis, light energy is converted into chemical energy. Both processes are also vital to the survival of living organisms.The primary difference between the two processes is the source of energy used. Glycolysis uses glucose as the primary energy source while photosynthesis uses light energy from the sun.

Glycolysis occurs in the cytoplasm of cells while photosynthesis takes place in the chloroplasts of plant cells. Glycolysis is an anaerobic process that does not require oxygen, while photosynthesis is an aerobic process that requires oxygen and releases it as a byproduct.

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The grams of magnesium hydroxide needed to yield 8.00 moles of magnesium chlorate is approximately 466.64 g. None of the options provided match the calculated value of 466.64 g.

To determine the grams of magnesium hydroxide (Mg(OH)2) needed to yield 8.00 moles of magnesium chlorate (Mg(ClO3)2), we need to consider the balanced chemical equation for the reaction between magnesium hydroxide and chlorine.

The balanced equation is as follows:

2 Mg(OH)2 + 6 Cl2 → 2 Mg(ClO3)2 + 2 H2O

From the balanced equation, we can see that 2 moles of Mg(OH)2 react with 6 moles of Cl2 to produce 2 moles of Mg(ClO3)2.

Therefore, the stoichiometric ratio is 2 moles of Mg(OH)2 : 2 moles of Mg(ClO3)2.

To calculate the grams of Mg(OH)2 needed, we can use the stoichiometric ratio and the given moles of Mg(ClO3)2.

Given:

Moles of Mg(ClO3)2 = 8.00 moles

Using the stoichiometric ratio, we have:

8.00 moles Mg(ClO3)2 × (2 moles Mg(OH)2 / 2 moles Mg(ClO3)2) = 8.00 moles Mg(OH)2

To convert moles to grams, we need to multiply by the molar mass of Mg(OH)2.

The molar mass of Mg(OH)2 = (24.31 g/mol) + (2 * 16.00 g/mol) = 58.33 g/mol

Grams of Mg(OH)2 = 8.00 moles Mg(OH)2 × 58.33 g/mol = 466.64 g

Therefore, the grams of magnesium hydroxide needed to yield 8.00 moles of magnesium chlorate is approximately 466.64 g.

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Answer:

To determine the change in mass of A over the given time period, we need to find the difference between the initial mass of A and the final mass of A.

From the given table, we can see that the initial mass of A at t = 0 (start time) is 12.4 g and the final mass of A at t = 60 minutes (end time) is 6.2 g.

Therefore, the change in mass of A over 60 minutes is:

Final mass of A - Initial mass of A

= 6.2 g - 12.4 g

= -6.2 g

The negative sign indicates that the mass of A decreased over time, which means that A underwent some kind of reaction or process that caused it to lose mass.

The change in mass of A over 60 minutes is -6.2 grams.

To determine the change in mass of A over 60 minutes, we need to compare the initial mass to the final mass.

From the given information, we can see that the mass of A decreases over time.

Let's calculate the change in mass.

Initial Mass of A: 12.4 g

Final Mass of A: 6.2 g

Change in Mass of A = Final Mass of A - Initial Mass of A

= 6.2 g - 12.4 g

= -6.2 g

The change in mass of A over 60 minutes is -6.2 grams.

Note that the negative sign indicates a decrease in mass.

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Explanation:

this explanation may help u to understand:)