If 4.0 L of a 4.8 M SrCl22 solution is diluted to 50 L, what is the molarity of the diluted solution?

Answers

Answer 1

If 4.0 L of a 4.8 M SrCl22 solution is diluted to 50 L, the molarity of the diluted solution is 0.384 M SrCl2.

The given solution has a volume of 4.0 L and a concentration of 4.8 M SrCl2. It is diluted to a volume of 50 L. We need to calculate the molarity of the diluted solution:

We know that

Molarity = Moles of solute/Volume of solution

Moles of solute in the given solution= Volume of solution × Concentration of solution

Moles of SrCl2 in the given solution = 4.0 L × 4.8 M= 19.2 mol SrCl2

Since we know the moles of SrCl2 in the given solution, we can find the molarity of the diluted solution using the equation, Molarity = Moles of solute/Volume of solution

Moles of SrCl2 in the diluted solution = Moles of SrCl2 in the given solution

Volume of diluted solution = 50 L= 19.2 mol SrCl2/ 50 L= 0.384 M SrCl2

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Related Questions

how is atp used within the cell? a. hydrolysis of the phosphoanhydride bonds releases energy that can be used to power chemical reactions b. phosphorylation of adp stores energy that can be used later to power chemical reactions c. as an energy currency in the cell d. all of the above

Answers

ATP used within the cell d)all of the above . It is involved in various processes, such as a) hydrolysis of the phosphoanhydride bonds releases energy that can be used to power chemical reactions b. phosphorylation of adp stores energy that can be used later to power chemical reactions c. as an energy currency in the cell .

When a cell requires energy for various chemical reactions and processes, it utilizes ATP. This is achieved through the hydrolysis of phosphoanhydride bonds in ATP, which releases energy. The breaking of these bonds converts ATP into ADP (adenosine diphosphate) and an inorganic phosphate (Pi), releasing energy in the process.


As a result of its involvement in both energy release and energy storage, ATP serves as an energy currency within the cell. In summary, ATP is utilized in the cell through the hydrolysis of phosphoanhydride bonds, phosphorylation of ADP, and as an energy currency, supporting various chemical reactions and processes crucial to cellular function.The correct answer is d).

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Question 4 An incompressible fluid flows down a vertical cylindrical pipe of length L and radius R, according to the laminar flow regime. a) Derive an expression for the velocity profile of the fluid using an appropriate Navier-Stokes equation. State all assumptions. b) If the pipe is 6 m in length, 5 cm in diameter, has a friction factor of 0.01 and the density of the fluid is 1020 kg/m³, calculate the pressure drop if a constant flow rate of 3 m³/hr is maintained.

Answers

The velocity profile of an incompressible fluid flowing down a vertical cylindrical pipe can be derived using the Navier-Stokes equation under certain assumptions. With a pipe length of 6 m, diameter of 5 cm, friction factor of 0.01, and a constant flow rate of 3 m³/hr, we can calculate the pressure drop using the given information.

a) To derive the velocity profile of the fluid in the pipe, we can start with the Navier-Stokes equation, which describes the motion of a fluid. Under the assumption of laminar flow and incompressibility, the equation simplifies to:

dP/dz = (32μLQ) / (πR^4)

where dP/dz is the pressure gradient, μ is the dynamic viscosity of the fluid, L is the pipe length, Q is the volumetric flow rate, and R is the pipe radius. By integrating this equation, we can obtain the velocity profile of the fluid.

b) To calculate the pressure drop, we need to convert the flow rate from m³/hr to m³/s. Given that 1 m³/hr is equal to 1/3600 m³/s, the flow rate becomes Q = 3 / 3600 m³/s. By substituting the values of μ, L, Q, and R into the derived equation, we can calculate the pressure gradient. Finally, the pressure drop can be obtained by multiplying the pressure gradient by the length of the pipe (6 m).

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circular tracks. Ana's brother rode in a blue car that travels a total distance of 220 feet around the track. Ana's sister rode in a green car that travels a total distance of 126 feet around the track. Ana drew a sketch of the ride. Green car Blue car What is the difference between the radii of the two circular tracks? Answer the questions to find out. ​

circular tracks. Ana's brother rode in a blue car that travels a total distance of 220 feet around the

Answers

If Ana's brother rode in a blue car that travels a total distance of 220 feet around the track. the difference between the radii of the two circular tracks is 15 feet.

What is the difference between the radii of the two circular tracks?

To find the difference between the radii of the two circular tracks, we can use the formula for the circumference of a circle, which is:

C = 2πr

where C is the circumference and r is the radius.

Let r1 be the radius of the blue car's track and r2 be the radius of the green car's track. We know that the blue car travels a total distance of 220 feet around its track, so:

2πr1 = 220

Simplifying this equation, we get:

r1 = 35 feet (rounded to the nearest whole number)

Similarly, we can find the radius of the green car's track:

2πr2 = 126

r2 = 20 feet (rounded to the nearest whole number)

Finally, we can find the difference between the radii of the two tracks:

r1 - r2 = 35 - 20 = 15 feet

Therefore, the difference between the radii of the two circular tracks is 15 feet.

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Identify the compounds that should rearrange following the same mechanism as the pinacol rearrangement?

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The pinacol rearrangement is a well-known organic reaction that involves the rearrangement of vicinal diols, which are compounds that have two hydroxyl groups (-OH) attached to adjacent carbon atoms.

The reaction typically occurs under acidic conditions and results in the formation of ketones or aldehydes.

The mechanism of the pinacol rearrangement begins with protonation of one of the hydroxyl groups, usually the more acidic one, by an acid catalyst.

This protonation leads to the formation of a carbocation intermediate, which is a carbon atom with a positive charge due to the loss of a proton.

The adjacent hydroxyl group then attacks the carbocation, forming a carbon-oxygen bond and leading to the formation of a cyclic intermediate.

This cyclic intermediate is unstable and rearranges through migration of the alkyl group or hydrogen atom from the carbocation to the adjacent carbon atom, forming a new carbocation intermediate.

This rearrangement is typically facilitated by the presence of neighboring electron-withdrawing or electron-donating groups that stabilize the intermediate carbocation through resonance or inductive effects.

The rearranged carbocation intermediate is then deprotonated, leading to the formation of a ketone or an aldehyde, depending on the conditions and the specific structure of the starting compound.

The final product of the pinacol rearrangement is typically a ketone or an aldehyde with a carbonyl group (C=O) in the position where the original hydroxyl group was attached.

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What mass of HCI is needed to
generate 45.2 g of AICI3?
2AI + 6HCI → 2AlCl3 + 3H₂
AICI3: 133.33 g/mol
HCI: 36.46 g/mol

Answers

Answer:

37.1g of HCl

Explanation:

rate as brainliest

What mass of HCI is needed togenerate 45.2 g of AICI3?2AI + 6HCI 2AlCl3 + 3HAICI3: 133.33 g/molHCI: 36.46

A transformer has 150 turns in its primary coil and 50 turns in its secondary coil. If the input voltage is 12 V, what is the output voltage?​

Answers

Answer:

36V

Explanation:

Given parameters:

Number of turns in primary coil  = 150turns

Secondary coil turn = 50turns.

Input voltage  = 12V

Unknown:

Output voltage  = ?

Solution:

For this transformer problem, we use the expression;

   

   \(\frac{N_{s} }{N_{p} }\)   = \(\frac{V_{s} }{V_{p} }\)  

Insert the parameters and solve;

        Ns is the number of secondary turns

        Np is the number of primary turns

         Vs is the secondary voltage

          Vp is the secondary voltage

Insert the parameters and solve;

          \(\frac{150}{50}\)   = Output voltage / 12

          Output voltage = 12 x 3  = 36V

calculate the solubility in g/l of agbr in (a) pure water and (b) 0.0019 m nabr.

Answers

The solubility of AgBr in pure water is (a) 0.00034 g/L. (b) The solubility of AgBr in 0.0019 M NaBr is 1.6 x 10⁻⁷ g/L.

(a) The solubility of a compound depends on its ionic strength and the nature of the solvent. In pure water, AgBr partially dissolves according to the equation AgBr(s) ⇌ Ag⁺(aq) + Br⁻(aq).

The solubility product expression for AgBr is given by Ksp = [Ag⁺][Br⁻]. At equilibrium, the concentration of AgBr is equal to its solubility (S), and the concentration of Ag⁺ and Br⁻ ions are equal to S.

Substituting these values in the Ksp expression, we get Ksp = S², and solving for S gives S = sqrt(Ksp). Therefore, the solubility of AgBr in pure water is S = sqrt(7.7 x 10⁻¹³) = 0.00034 g/L.

In the presence of NaBr, AgBr dissolves according to the equation AgBr(s) + Na⁺(aq) + Br⁻(aq) ⇌ NaAgBr₂(aq). The addition of Na⁺ and Br⁻ ions from NaBr increases the ionic strength of the solution, which decreases the solubility of AgBr.

(b) The solubility of AgBr in the presence of NaBr can be calculated using the common ion effect. The concentration of Br⁻ ion from NaBr is 0.0019 M, and the concentration of Ag⁺ ion from AgBr is negligible compared to Na⁺ concentration.

Therefore, we can assume that the concentration of Br⁻ ion is constant and subtract it from the solubility product expression for AgBr. The new expression is Ksp = [Ag⁺][Br⁻] - S[Br⁻]. Solving this expression for S gives S = Ksp/[Br⁻] = 1.6 x 10⁻⁷ g/L.

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in the lab you found the acrylic density cube was found to have a volume of 1.01 cm3. what would you predict the volume to be in milliliters using the water displacement method?

Answers

Because a flux-pressure curve is initially measured before the pore size distribution is determined, the liquid displacement method is an indirect approach for determining the pore size distribution of a membrane.

Water displacement method - To do this, all you need to do is place the food in a resealable zipper-lock bag, and then carefully lower the bagged food into the cooking vessel filled with water. Air is forced through the top of the bag by the water's pressure. Carefully seal the bag once the majority of the air has been removed, just above the water line.

Total volume minus liquid volume equals volume of the thing.

6.2 mL minus 5.5 mL equals 0.7 mL.

Now, the object's density will be;

Mass / volume equals density (Liquid - Displacement).

We swap out

Density = 0.66 g / 0.7 mL (Liquid - Displacement)

Density = 0.942857 0.94 g/mL (Liquid - Displacement).

As a result, the cube's density for the liquid displacement method is 0.94 g/mL.

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What is the name of the Group 17 elements ?

Answers

Answer:

Halogen, any of the six nonmetallic elements that constitute Group 17 (Group VIIa) of the periodic table. The halogen elements are fluorine (F), chlorine (Cl), bromine (Br), iodine (I), astatine (At), and tennessine (Ts).

The name of the Group 17 elements is called halogens

What is the name of group 17 elements?

The group 17 elements are very reactive elements. Members of this group include:

Fluorine (F)Chlorine (Cl)Bromine (Br)Iodine (I)Astatine (At)

The group 17 element are known to produce salts as they react with metals. Hence, they are called halogens

The group 17 elements are have 7 valence electrons and they required one electron to attain the stable octet configuration of the noble gas family.

From the above, we can see that the name of group 17 elements is halogens

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Organisms that make their own food, release carbon dioxide during ?

Answers

Answer:

photosynthesis

Explanation:

Photosynthesis I think

Calculate the decrease in temperature when 6.00 L at 20.0 °C is compressed to 4.00 L.

Answers

To calculate the decrease in temperature when 6.00 L at 20.0 °C is compressed to 4.00 L, we need to use the ideal gas law, PV = nRT.

How do you calculate temperature drop due to pressure drop?You subtract the final temperature from the starting temperature to find the difference. So if something starts at 50 degrees Celsius and finishes at 75 degrees C, then the change in temperature is 75 degrees C – 50 degrees C = 25 degrees C. For decreases in temperature, the result is negative.Use the formula: k = T1/P1. For example, if a gas at an initial temperature of 300 K and an initial pressure of 100 Pa, drops by 50 Pa, the proportionality constant k = 3 K/Pa = 300/100 = T1/P1. Multiply the drop in pressure by the proportionality constant k to obtain the drop in temperature.First, we need to convert the temperature from Celsius to Kelvin: 20.0 °C + 273.15 = 293.15 KNext, we need to find the initial pressure, using the ideal gas law: P1V1 = nRT, where P1 = initial pressure, V1 = initial volume, n = number of moles, R = ideal gas constant, T = temperature in Kelvin. We know that V1 = 6.00 L, T = 293.15 K, and R = 8.314 J/mol·K. We do not know the value of n, so we can assume it is 1 mole. Therefore, P1 = (nRT) / V1 = (1 x 8.314 x 293.15) / 6.00 = 476.89 J/LFinally, we can calculate the final pressure, using the same equation: P2V2 = nRT, where P2 = final pressure, V2 = final volume. We know that V2 = 4.00 L, T = 293.15 K, and R = 8.314 J/mol·K. Substituting these values into the equation, we get P2 = (nRT) / V2 = (1 x 8.314 x 293.15) / 4.00 = 715.34 J/LTo find the decrease in temperature, we subtract the final pressure from the initial pressure: P1 - P2 = 476.89 J/L - 715.34 J/L = -238.45 J/LSo the decrease in temperature when 6.00 L at 20.0 °C is compressed to 4.00 L is -238.45 J/L.

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Algae blooms are most often caused by?

Answers

Algae blooms are most often caused by eutrophication.

What are algae blooms?

Algae blooms are are dense layers of tiny green plants that occur on the surface of lakes and other bodies of water when there is an overabundance of nutrients (primarily phosphorus) on which algae depend.

Algae species tend to proliferate in growth (bloom) in the presence of abundance nutrients. This abundance of nutrients is as a result of a process called eutrophication.

Eutrophication is the ecosystem's response to the addition of artificial or natural nutrients, mainly phosphates, through detergents, fertilizers, or sewage, to an aquatic system.

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Acetic acid (CH 3 COOH) reacts with water to form the acetate ion and the hydronium ion: CH 3 COOH(aq)+H 2 O(l) leftrightarrow CH 3 COO^ - (aq)+H 3 O^ + (aq) At equilibriumthe concentration of CH 3 COOH is 2. 0 * 10 ^ - 1 * M the concentration of CH 3 COO^ - 1. 9 * 10 ^ - 3 * M and the concentration of H 3 O^ + is 1. 9 * 10 ^ - 3 * M What is the value of K eq for this reaction? 1. 8 * 10 ^ - 5 5. 5 * 10 ^ 4 9. 5 * 10 ^ - 3 1. 1 * 10 ^ 2

Answers

The value of K_eq for this reaction is approximately 1.805 × 10^-5.

To find the value of the equilibrium constant (K_eq) for the given reaction, we can use the equilibrium concentrations of the species involved. The equilibrium constant expression for the reaction is:

K_eq = [CH3COO-][H3O+] / [CH3COOH]

Given the following concentrations at equilibrium:

[CH3COOH] = 2.0 × 10^-1 M

[CH3COO-] = 1.9 × 10^-3 M

[H3O+] = 1.9 × 10^-3 M

Substituting these values into the equilibrium constant expression, we get:

K_eq = (1.9 × 10^-3)(1.9 × 10^-3) / (2.0 × 10^-1)

K_eq = 3.61 × 10^-6 / 2.0 × 10^-1

K_eq = 3.61 × 10^-6 × 5.0 × 10^0

K_eq = 1.805 × 10^-5

Therefore, the value of K_eq for this reaction is approximately 1.805 × 10^-5.

None of the provided answer choices match this value exactly.

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How many molecules are in 7.50 mol of SO2

Answers

Answer:

45.165  ×  10²³ molecules

Explanation:

Given data:

Number of moles of SO₂ = 7.50 mol

Number of molecules = ?

Solution:

Avogadro number:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.  The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ molecules

7.50 mol  ×  6.022 × 10²³ molecules

45.165  ×  10²³ molecules

name two methods of resolving a racemic mixture into its individual components?

Answers

There are several methods to resolve racemic mixtures into individual components, but two of the most common methods of resolving racemic mixtures into their individual components are Chromatography and Crystallization

Chromatography is a physical separation method that separates mixtures into their individual components based on their different affinities towards a stationary phase and a mobile phase. The separation is based on the principle of adsorption (solid/liquid) or partitioning (liquid/liquid) of the components of the mixture between two phases. This method is widely used for separating and purifying organic compounds. Various types of chromatography, such as gas chromatography, liquid chromatography, and thin-layer chromatography, are used to separate racemic mixtures into individual components.

Crystallization is a separation technique that is based on the solubility of the enantiomers of a racemic mixture in different solvents. One enantiomer is usually more soluble in one solvent than the other enantiomer, resulting in the separation of the racemic mixture. This method is relatively simple and inexpensive. It is commonly used in the pharmaceutical industry to separate chiral compounds.

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need help w this question

need help w this question

Answers

Answer:

ok you got it you just need to add.

Explanation:

add 5 times and she what you get.

How would this model be like after being separated chemically?

How would this model be like after being separated chemically?

Answers

A separation method known as chemical extraction depends on the difference between an element's solubility in an organic solvent and an aqueous solution.

What exactly are organic solvents?

Organic solvents are chemicals with a carbon structure that can dissolve or disperse one or more other compounds. Organic solvents have the potential to be neurotoxins, genital poisons, and carcinogens. The organic solvents benzene, carbon tetrachloride, and trichloroethylene are carcinogenic. The boiling point of organic solvents is low – Organic solvents are known to have very low boiling points.

Is oil a type of organic solvent?

Vegetable oil is analysed and weighed for use as an organic solvent for wastewater treatment in liquid membrane systems.e vegetable oil as a more sustainable organic solvent is highlighted.

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Burning a candle melts the wax, but also burns the wick. Explain how burning a candle involves both physical and chemical changes.

Answers

Answer:

Burning of the candle is both physical and chemical change. Burning of the candle melts the wax and hence physical state of wax has changed from solid to liquid.  

Again the wax combines with the atmospheric oxygen and changes to carbon dioxide, heat and light.  

Thus both the changes are accompanied by the burning of the candle.

Explanation:

hope this helps!

~mina

What are the microstructal products of 4340 alloy steel that are first completely transformed to austenite

Answers

When 4340 alloy steel is first completely transformed to austenite, it undergoes a process called homogenization.

This process involves heating the steel to a high temperature, typically around 1700°F, for a specific amount of time to ensure that the carbon and other alloying elements are evenly distributed throughout the material. Once the homogenization process is complete, the steel is cooled rapidly to room temperature.

The microstructural products that are formed during this process include a uniform distribution of fine pearlite, martensite, and austenite grains. The fine pearlite and martensite grains result from the rapid cooling of the steel, while the austenite grains are formed during the homogenization process. These microstructures provide the steel with excellent strength, toughness, and wear resistance, making it ideal for use in high-stress applications such as aircraft landing gear, crankshafts, and gears. Overall, the homogenization process plays a critical role in ensuring that 4340 alloy steel possesses the desired microstructural properties.

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Which part of project management involves determining possible risks?

Answers

Answer:

Resources

Explanation:

Answer:

Explanation:

M

If an object weighs 2,354 N on Earth, what is the objects mass?

Answers

Answer:

4.0 kg

Explanation:

M = W/g = 39.2/9.8 = 4.0 kg

sorry if its wrong-

A climatograph of the Western Sahara is depicted here which shows the average rainfall, low and high temperatures over the course of a year. Which features of the Earth most directly contribute to the climate observed in the Western Sahara? Select ALL that apply.
A The convection currents in the atmosphere deposit warm, dry air at the latitudes that contain the Western Sahara.The convection currents in the atmosphere deposit warm, dry air at the latitudes that contain the Western Sahara.
B The tilt of the Earth on its axis gives the Western Sahara direct sunlight during the summer.The tilt of the Earth on its axis gives the Western Sahara direct sunlight during the summer.
C The gravitational pull of the Moon on the Earth diverts water from desert areas to the oceans.The gravitational pull of the Moon on the Earth diverts water from desert areas to the oceans.
D The revolution of the Earth around the Sun prevents rainfall in the areas on the western parts of large continents.The revolution of the Earth around the Sun prevents rainfall in the areas on the western parts of large continents.
E The rotation of the Earth generates winds that are deflected as the Earth moves.

A climatograph of the Western Sahara is depicted here which shows the average rainfall, low and high

Answers

The features of the Earth that most directly contribute to the climate observed in Western Sahara are:

"The convection currents in the atmosphere deposit warm, dry air at the latitudes that contain Western Sahara.The convection currents in the atmosphere deposit warm, dry air at the latitudes that contain Western Sahara." (Option A) ; and "The rotation of the Earth generates winds that are deflected as the Earth moves." (Option E).

What is Climate?

Climate is an area's long-term weather trend, often averaged over 30 years.

More precisely, it is the average and variability of climatic variables across temporal periods ranging from months to millions of years.

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Giving brainliest please help with this question

Giving brainliest please help with this question

Answers

Answer:

B! Hope this helps! :)

Explanation:

14.87 moles of Magnesium should form 14.87 moles of Magnesium Chloride. 14.77 moles of Hydrochloric acid should form 7.97 moles of Magnesium Chloride. Only 1.78 moles of Magnesium chloride is obtained. What is the percent yield?
PLEASE HELP and teach please

Answers

According the question the Percent yield is 11.99%

What is yield?

Yield is an economic term referring to the income generated by an investment over a period of time. It is usually expressed as a percentage of the initial investment and is calculated by taking the total income earned and dividing it by the initial investment. Yield is an important measure of the performance of an investment, and is a key factor in determining the attractiveness of an investment. Yields can be calculated for individual investments, or for portfolios of investments. Yields can also be calculated for different types of investments, such as stocks, bonds, and mutual funds. Yields are also used to compare investments with different levels of risk, so investors can make informed decisions about their investments. Yields are affected by a variety of factors, including interest rates, inflation, and market conditions.

The percent yield can be calculated using the formula:

Percent yield = (Actual yield / Theoretical yield) * 100

For Magnesium Chloride, the theoretical yield is 14.87 moles, and the actual yield is 1.78 moles.

Therefore, the percent yield is:

Percent yield = (1.78 / 14.87) * 100 = 11.99%

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Please help serious answers only

Please help serious answers only

Answers

Answer:

Neptune and Saturn although Neptune isn't on there so just Saturn.

hope it'll help ya out!

If a cubic container has a side length of 50.0cm ,what is the volume in the liter?

Answers

Answer:

0.05 Liter

Explanation:

Conversion factor: 1/1000

1) Liter = Cubic Centimeter / 1000

2) Liter = 50 / 1000

3) Liter = 0.05

What are the conditions that are required for electrical energy to be present in an electrical circuit?

Answers

Answer:

 a supply of electric charges which are free to flow, some form of push to move the charges through the circuit and a pathway to carry the charges.

Explanation:

There's your answer have a good day

Please help with my chemistry homework

Please help with my chemistry homework

Answers

Answer:

amu, atomic number, electrons, atomic mass

Explanation:

0.3747x + 11.598 pls help meeeeeeeeeeeeeeeeeeeeeeeeeeee

Answers

Answer:

that isn't a full equation but I will assume this is = to 0

that makes x 30.95

Explanation:

If you want to lower water's freezing point 18 degrees C by adding NaCl, what must the molality of the salt solution be? (K(f) for water ris 1.86 degree C/m)

Answers

Answer:

4.84 m

Explanation:

To solve this problem we need Frezing point depression.

Formula is: ΔT = Kf . m . i

ΔT = 18°C

This is data. ΔT is the difference, Freezing T° of pure solute - Freezing T° of solution.

Kf = 1.86 °C/m

m = molality. Our unknown.

i = Ions dissolved in solution, also called Van't Hoff factor.

NaCl → Na⁻  +  Cl⁻

Sodium chloride can produce 2 moles of ions.

We replace data: 18°C = 1.86 °C/m  .  m   .  2

18°C / (1.86 °C/m) . 2 = m

molality = 4.84

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Material and information flows. 2. Materials and unit loads. Material characteristics. Unit load principle. Unitizing, Load units and transport units in the logistics chain. 3. Transportation modes & materials handling equipment. Metrics in logistics engineering. Distances in space and time. 4. Transportation- trans-modal, multimodal and intermodal concepts. 5. Basic flow element. Simple conveyor routes and areas. Performance measures for conveying. Throughput and inter arrival time. 6. Basic flow element. Simple transportation connection. Performance measures for trucks, cranes and fork lifts. Throughput and inter arrival time. 17. Performance measures for stochastic flows. Random variables, Probability density function (pdf) and cumulative distributions function (cdf), expected values and variance. Some important random distributions. 8. Traffic flow. Average speed types and measuring. Speed-flow-density relationships. Fundamental law of traffic flow. 9 Traffic flow. Intersections with traffic lights. Conservation law for intersections. Average deterministic waiting time. 10. Logistics nodes. Connectivity. Ranking. Decomposition. Basic law of material flows for logistics nodes. Branching nodes. Discrete and partially-continuous branching. Estimation of a partial limiting throughput. Throughput condition. 12. Branching nodes. Partial limiting throughput by continuous branching. Estimation of a switching probability and switching frequency. Throughput limiting condition. 13. Integration node. Dispatching rules. Dispatching with restrained and with absolute priority. Throughput calculations. 14 Models of material flows. Sankey-diagrams and from/to matrices. Graph representation. 15. Calculation of transport distances in networks. Shortest path problem - Dijkstra algorithm Loads and transport flow matrices. Estimation of number of vehicles, required in a logistics network 16. page 1 of 2 Logistics Engineering - conspectus 17. Queueing systems. Characteristics of a queue. Single server and multi servers. Arrival, waiting and service processes. Measures of performance. Queue descriptors - Kendall's notation. 18. Ergodicity condition for single stage queueing systems. Little's Theorem. 19. Basic parameters for queueing systems. Utilization. Internal and external characteristics. Fundamental dependencies. 20. Models with Markov's chains for queueing systems M/M/1 and M/M/s. Derivation of basic parameters. Buffer size sufficiency. 21. Queueing systems with arbitrary distribution of an arrival and/or service time. Influence of the variation coefficients. 22. Logistics chains as multistage queueing models. Parameters of the departure process. Influence of the blocking. 23. Simulation modelling of logistics systems. Random numbers generation. Levels of simulation languages. Universal simulation languages. Specialized simulation environments. 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