if 3(x+1)=7 find the value of 3x

Answer:

1.) 42/55 x = the quotient. 2.) x = -1

Step-by-step explanation:

Answer:

x = - 7/9 and x = - 1

Step-by-step explanation:

Equation 1:

Step 1:

22 + 54x = - 20    Equation

Step 2:

54x = - 42   Subtract 22 on both sides

Step 3:

- 42 ÷ 54   Divide

Answer:

x = - 42/54 or - 7/9

Equation 2:

Step 1:

- 5x - 16 = 8x - 3   Equation

Step 2:

- 16 = 13x - 3   Add 5x on both sides

Step 3:

- 13 = 13x   Add 3 on both sides

Step 4:

- 13 ÷ 13   Divide

Answer:

x = - 1

Hope This Helps :)

Answer:

its c

Step-by-step explanation:

Answer:

i dont get it

Step-by-step explanation:

Answer:

The area of the lateral surface of the cube is 12.96 cm²

Step-by-step explanation:

The lateral surface area

4 × (1.8 cm)²

An objects lateral surface are the surfaces of the object that exclude the top and bottom surfaces

In a cube, the lateral surface are the vertically oriented (with respect to the base and the top which are then oriented horizontally) surfaces of the cube

Therefore, the lateral surface area of the cube consist of four vertically oriented equal sized faces, each with side 1.8 cm

The area of the lateral surface of the cube = The area of the four vertically oriented faces of the cube

∴ The area of the lateral surface of the cube = 4 × 1.8 cm × 1.8 cm = 12.96 cm.²

Answer:

(2, 9)

Step-by-step explanation:

I took the quiz

The number that represents the second term as an ordered pair is (2, 9)

Given that,

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Notice that for the first altered function we have that:

Therefore the +7 would directly affect the x-values, so the graph would shift horizontally.

For the next function we have that:

Therefore the +7 would directly affect the y-values, so the graph would shift vertically.

Answer:

(2, –3) is a solution to the system of linear equations.

Step-by-step explanation:

Given: Equations:

3x - y = 9 --------(1),

4x + y = 5 --------(2),

Add Equation (1) + Equation (2),

3x + 4x = 9 + 5

7x = 14  ( Combine like terms )

x = 2   ( Divide both sides by 7 ),

From equation 1:

3(2) - y = 9

6 - y = 9

-y = 9 - 6    ( Subtraction 6 on both sides )

-y = 3

y = - 3     ( Multiplying -1 on both sides )

As the consumption rate of 1997  estimated 2,000 billion barrels of oil last in 74.34 approx 75 year .

As here the rate of 1997 is not given which will be find in the below link which is 73.7000 millions barrels per day was the consumption of oil. here we have awalible the data of per days and we have to calculate for year so in year 1997 there was 365 days  so comsumption of oil yearly was .

1997 consumption = 73.700 million barrels per day

so for 1 year 73.700 million *365 =26,900.5 million barrels per day

her we find the rate of yearly so by this rate we will calculate the consumption of 2000 billion barrels of oil

2000 billion = 2,000,000 millions

here we are calculation this in million

so for 2,000,000 million will be

2,000,000 million /26,900.5 million =74.34 year

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Answer: k = √27-i

Step-by-step explanation:

the volume of the silo is approximately 11,657.88 cubic meters.

To find the volume of the silo, we need to calculate the volumes of the cylinder and the cone separately, and then add them together.

The radius of the base of the silo is half the diameter, so it's 10 meters / 2 = 5 meters.

The height of the cylinder is given as 27 meters. Since the height of the cone is half the height of the cylinder, the height of the cone is 27 meters / 2 = 13.5 meters.

The volume of a cylinder is calculated using the formula:

Volume of Cylinder = π * radius^2 * height

Plugging in the values, we get:

Volume of Cylinder = π * 5^2 * 27 = 3375π cubic meters (approximately 10,598.07 cubic meters)

The volume of a cone is calculated using the formula:

Volume of Cone = (1/3) * π * radius^2 * height

Plugging in the values, we get:

Volume of Cone = (1/3) * π * 5^2 * 13.5 = 337.5π cubic meters (approximately 1059.81 cubic meters)

Adding the volumes of the cylinder and the cone, we get:

Volume of Silo = 3375π + 337.5π = 3712.5π cubic meters (approximately 11,657.88 cubic meters)

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hope it helps.I was reading the same chapter

{a}, {b}, {c}, {a, b}, {a, c} and {b, c} are proper subset of the set {a,b,c}.

A proper subset is a subset of a set that contains some, but not all, of the elements of the original set.

In the case of the set m = {a, b, c}, we can find all the proper subsets by considering all the possible combinations of its elements.

The possible proper subsets of m are:

{a}: This subset contains only the element 'a' from the original set m.

{b}: This subset contains only the element 'b' from the original set m.

{c}: This subset contains only the element 'c' from the original set m.

{a, b}: This subset contains both elements 'a' and 'b' from the original set m, but not 'c'.

{a, c}: This subset contains both elements 'a' and 'c' from the original set m, but not 'b'.

{b, c}: This subset contains both elements 'b' and 'c' from the original set m, but not 'a'.

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Answer:

The polls were open for 9 hours on election day.

Step-by-step explanation:

10167 - 6504 = 3663

3663 / 407 = 9

The two most generic and widely used valuation multiples in finance and investment analysis are the price-to-earnings (P/E) ratio and the enterprise value-to-earnings before interest, taxes, depreciation, and amortization (EV/EBITDA) multiple.

1. Price-to-Earnings (P/E) Ratio: The P/E ratio is calculated by dividing the market price per share of a company's stock by its earnings per share (EPS). It provides a measure of how much investors are willing to pay for each dollar of earnings generated by the company.

A high P/E ratio suggests that investors have high expectations for future growth and are willing to pay a premium for the stock. On the other hand, a low P/E ratio may indicate that the stock is undervalued or that investors have low expectations for future growth.

2. Enterprise Value-to-EBITDA (EV/EBITDA) Multiple: The EV/EBITDA multiple is calculated by dividing the enterprise value (EV) of a company by its earnings before interest, taxes, depreciation, and amortization (EBITDA).

The EV is the total market value of a company's equity and debt, minus its cash and cash equivalents. EBITDA represents the company's operating earnings before accounting for interest, taxes, depreciation, and amortization.

The EV/EBITDA multiple is commonly used in evaluating the valuation of companies, especially in the context of mergers and acquisitions. It provides a measure of a company's overall value relative to its earnings, without being affected by capital structure or tax considerations.

Both the P/E ratio and EV/EBITDA multiple are widely used because they are relatively easy to calculate and understand. However, it's important to note that these multiples have limitations and should be used in conjunction with other valuation methods and qualitative analysis to make informed investment decisions.

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Answer:

3.375 cm^2

Step-by-step explanation:

The area of a parallelogram is given by

A = bh  where b is the base and h is the height

A = 2.25 * 1.5

A =3.375 cm^2

Area = length x height

Area = 2.25 x 1.5

Area = 3.375 cm^2

The product of (3 - √5)(7 - √5) simplifies to 26 - 10√5.

To multiply and simplify the expression (3 - √5)(7 - √5), we can use the distributive property of multiplication over addition. Here are the steps:

1. Start by multiplying the first terms in each set of parentheses: 3 * 7 = 21.

2. Then multiply the outer terms: 3 * (-√5) = -3√5.

3. Next, multiply the inner terms: -√5 * 7 = -7√5.

4. Finally, multiply the last terms: -√5 * -√5 = 5.

Now we can combine these terms to simplify the expression:

21 + (-3√5) + (-7√5) + 5

Combine the like terms: 21 + 5 - 3√5 - 7√5

Combine the constants: 21 + 5 = 26.

Combine the radical terms: -3√5 - 7√5 = -10√5.

The final simplified expression is: 26 - 10√5.

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The general solution of the differential equation y''(x) + y(x) = sec(x) tan(x) is y(x) = c₁cos(x) + c₂sin(x) + (-ln|sec(x) + tan(x)| + C₁)cos(x) + (-ln|sec(x) + tan(x)| + C₂)sin(x); here c₁ and c₂ are constants.

To solve the differential equation y''(x) + y(x) = sec(x) tan(x) using variation of parameters, we first need to find the solutions to the homogeneous equation y''(x) + y(x) = 0.

The auxiliary equation for the homogeneous equation is r² + 1 = 0, which has complex roots r = ±i.

The corresponding solutions to the homogeneous equation are y₁(x) = cos(x) and y₂(x) = sin(x).

Next, we need to find the particular solution using the method of variation of parameters. Let's assume the particular solution has the form y_p(x) = u(x)cos(x) + v(x)sin(x).

Now, we need to find u(x) and v(x) by substituting this form into the original differential equation and solving for u'(x) and v'(x).

Differentiating y_p(x), we get y_p'(x) = u'(x)cos(x) - u(x)sin(x) + v'(x)sin(x) + v(x)cos(x).

Taking the second derivative, y_p''(x) = -u(x)cos(x) - u'(x)sin(x) + v(x)sin(x) + v'(x)cos(x).

Substituting these derivatives into the original differential equation, we have:

(-u(x)cos(x) - u'(x)sin(x) + v(x)sin(x) + v'(x)cos(x)) + (u(x)cos(x) + v(x)sin(x)) = sec(x)tan(x).

Simplifying, we get:

u'(x)sin(x) + v'(x)cos(x) = sec(x)tan(x).

To find u'(x) and v'(x), we solve the following system of equations:

u'(x)sin(x) + v'(x)cos(x) = sec(x)tan(x),

u(x)cos(x) + v(x)sin(x) = 0.

We can solve this system using various methods such as substitution or elimination.

Solving the system, we find:

u'(x) = sin(x)sec(x),

v'(x) = -cos(x)sec(x).

Integrating these expressions, we obtain:

u(x) = -ln|sec(x) + tan(x)| + C₁,

v(x) = -ln|sec(x) + tan(x)| + C₂.

Finally, the particular solution is given by:

y_p(x) = (-ln|sec(x) + tan(x)| + C₁)cos(x) + (-ln|sec(x) + tan(x)| + C₂)sin(x).

The general solution to the differential equation is the sum of the homogeneous and particular solutions:

y(x) = c₁cos(x) + c₂sin(x) + (-ln|sec(x) + tan(x)| + C₁)cos(x) + (-ln|sec(x) + tan(x)| + C₂)sin(x).

Here, c₁ and c₂ are constants.

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The probability that a package shipped in a small size box will weigh more than 6 pounds is 0.9236, or 92.36%.

To find the probability that a package shipped in a small size box will weigh more than 6 pounds, we need to convert the weight of 6 pounds to the same unit as the mean and standard deviation given in the problem, which is pounds.

Since 1 pound is equal to 16 ounces, 6 pounds can be expressed as 6 * 16 = 96 ounces. Converting 96 ounces to pounds gives us 96 / 16 = 6 pounds.

Now that we have the weight in pounds, we can use the normal distribution to calculate the probability.

The mean weight of small packages is given as 6.9 pounds, and the standard deviation is 10 ounces, which is equivalent to 0.63 pounds. To find the probability that a package weighs more than 6 pounds, we need to calculate the area under the curve to the right of 6 pounds.

To do this, we can use a standard normal distribution table or a statistical calculator. Using the standard normal distribution table, we can find the corresponding z-score for 6 pounds by subtracting the mean from 6 pounds and dividing by the standard deviation:

z = (6 - 6.9) / 0.63 = -1.429

Looking up the z-score of -1.429 in the standard normal distribution table, we find that the corresponding area to the right of -1.429 is 0.9236.

Therefore, the probability that a package shipped in a small size box will weigh more than 6 pounds is 0.9236, or 92.36%.

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The correct statement among the given options is A. "Research cannot use both qualitative and quantitative methods in a study."

This statement is not correct because research can indeed use both qualitative and quantitative methods in a study. Qualitative research focuses on collecting and analyzing non-numerical data such as observations, interviews, and textual analysis to understand phenomena in depth. On the other hand, quantitative research involves collecting and analyzing numerical data to derive statistical conclusions and make generalizations.

Many research studies employ a mixed methods approach, which combines both qualitative and quantitative methods, to provide a comprehensive understanding of the research topic. By using both qualitative and quantitative data, researchers can gather rich insights and statistical evidence, allowing for a more comprehensive analysis and interpretation of their findings.

Therefore, option A is the statement that is not correct concerning qualitative and quantitative research.

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The amount each contestant will receive is as follows:

This year $52,000 college scholarship is being divided between the top two contestants .

Therefore,

Total amount to share to the top winners = 52000 dollars

The winner receives three times as much as the runner-up.

Therefore,

let

x = Amount received by the runner-up

Hence,

Amount the winner received = 3x

Therefore,

52,000 = 3x + x

52,000 = 4x

divide both sides by 4

4x / 4 = 52,000 / 4

x = 13000 dollars

Hence,

Amount the winner received =3(13000) = $39000

Amount received by the runner-up = $13,000

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Answer:

yes its correct

Step-by-step explanation:

you dont really need work because its really just substitution.

Answer:

4th option

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

calculate m using the slope formula

m = \(\frac{y_{2}-y_{1} }{x_{2}-x_{1} }\)

with (x₁, y₁ ) = (2, 12) and (x₂, y₂ ) = (6, 6) ← 2 points on the line

m = \(\frac{6-12}{6-2}\) = \(\frac{-6}{4}\) = - \(\frac{3}{2}\)

the line crosses the y- axis at (0, 15 ) ⇒ c = 15

y = - \(\frac{3}{2}\) x + 15 ← approximate equation of line of best fit

If we let Z = 3 - X, then Z is another exponential random variable with mean 1 that is negatively correlated with X.

Let Y = 2 - X, where X is an exponential random variable with mean 1.

To show that Y is negatively correlated with X, we need to show that Cov(X,Y) < 0.

Cov(X,Y) = E[XY] - E[X]E[Y]

Since X and Y are both exponentially distributed with mean 1, we have:

E[X] = 1, E[Y] = 2 - E[X] = 1

E[XY] = E[X(2-X)] = 2E[X] - E[X^2] = 2 - Var(X)

Var(X) = E[X^2] - (E[X])^2 = 1 - 1^2 = 0

Therefore, Var(X) = 0, which means that E[XY] = 2, and Cov(X,Y) = E[XY] - E[X]E[Y] = 2 - 1*1 = 1 > 0.

Since Cov(X,Y) > 0, we know that Y is positively correlated with X. To find a random variable that is negatively correlated with X, we can use Y = 3 - X instead.

Therefore, if we let Z = 3 - X, then Z is another exponential random variable with mean 1 that is negatively correlated with X.

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Answer:

Step-by-step explanation:

12(x + 5) = 4x

12x + 60 = 4x

12x - 12x + 60 = 4x - 12x

60 = -8x

60/-8 = -8x/-8

-7.5  =  x

Answer: The general solution of the differential equation is in the screenshot provided

Step-by-step explanation:

Answer:

30 students they are including the students that are also planning to participate in other sports to.

Answer:

2) \(\frac{1}{\sqrt[6]m^{5}}\)

Step-by-step explanation:

As per the laws of indices:

\(\frac{x^{a} }{x^{b} } = x^{a - b} \\\\and \\ \\(x^{a})^b = x^{ab}\)

Therefore:

2-(1/3) = 5/3

So m ^(5/3)

5/3 multiplied by -1/2 = -5/6

so m^(-5/6)

Another law of indices:

\(x^{\frac{a}{y} } = \sqrt[y]{x^{a} }\)     and when there is something raised to a negative fraction do the reciprocal.

Answer:

1.)x=-2

2.)-3/4 simplified

3.)\(3x^2-a/x^3-27\)

4.)\(x^2-4y/2x^3-16y^6\)

Answer:

1. x=-2

2. -3/4 simplified

3. 3x^2 - a/ x^3 - 27

4. X^2 - 4y / 2x^3 - 16y^6

Step-by-step explanation:

When b does not equal 0, an ordered pair of numbers a and b, represented as a / b, is said to be a ratio.

A comparison between two items by means of a number. (arithmetic) comparing two quantities' relative magnitudes (usually expressed as a quotient).

When the second number in the ordered pair, b, is not equal to 0, the ratio is expressed as a/b. An equation in which two ratios are made equal is known as a percentage. As an illustration, you could express the ratio as 1: 3 if there is 1 guy and 3 girls (for every one boy there are 3 girls) 40% are girls, and 14% are boys.

Comparing two numbers by dividing them is how ratios work. Your formula would be A/B if you were contrasting one data point (A) with another data point (B). By doing so, you are multiplying information A by information B. Your ratio will be 5/10, for instance, if A is 5 and B is 10.

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ANSWER

My answer is in the photo above

EXPLANATION

For all the equations I have used the cross multiplication method although you can also use the LCM method