If 3a-4=26 what is the value of 2/5a?

Answer:

20 miles

Step-by-step explanation:

Let

x = total number of miles she wish to run the end of this month

If Carrie is 55% of the way to achieving her goal and she has already run 11 miles

55% of her total miles = 11 miles

55% of x = 11 miles

55/100 * x = 11 miles

0.55x = 11

Divide both sides by 0.55

x = 11 / 0.55

= 20

x = 20 miles

x = total number of miles she wish to run the end of this month = 20 miles

She is trying to run 20 miles by the end of this month

Answer:

\(\large \boxed{\sf \ \ \dfrac{8}{7} \ \ }\)

Step-by-step explanation:

Hello, please consider the following.

The solutions are, for a positive discriminant:

   \(\dfrac{-b\pm\sqrt{\Delta}}{2a} \ \text{ where } \Delta=b^2-4ac\)

Here, we have a = -21, b = -11, c = 40, so it gives:

\(\Delta =b^2-4ac=11^2+4*21*40=121+3360=3481=59^2\)

So, we have two solutions:

\(x_1=\dfrac{11-59}{-42}=\dfrac{48}{42}=\dfrac{6*8}{6*7}=\dfrac{8}{7} \\\\x_2=\dfrac{11+59}{-42}=\dfrac{70}{-42}=-\dfrac{14*5}{14*3}=-\dfrac{5}{3}\)

We only want x > 0 so the solution is

   \(\dfrac{8}{7}\)

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

The area of the sector of a circle with a radius of 10 inches and a central angle of 260° is approximately 226.9 square inches.

To find the area of a sector of a circle, you can use the formula:

Area = (θ/360) * π * r^2

where θ represents the central angle in degrees, π is a mathematical constant approximately equal to 3.14159, and r is the radius of the circle.

In this case, the radius is given as 10 inches and the central angle is 260°. Let's substitute these values into the formula:

Area = (260/360) * π * 10^2

= (0.7222) * 3.14159 * 100

≈ 226.893 square inches

Rounding to the nearest tenth, the area of the sector is approximately 226.2 square inches.

Therefore, the area of the sector of a circle with a radius of 10 inches and a central angle of 260° is approximately 226.9 square inches.

To learn more about area of sector visit:

https://brainly.com/question/22972014

#SPJ11

Therefore, the present value of the perpetuity that pays $1,800 per year forever, assuming a 5% interest rate, is $36,000. To find the present value of a perpetuity that pays $1,800 per year forever, we can use the formula:
Present Value = Cash Flow / Interest Rate

In this case, the cash flow is $1,800 and the interest rate is 5%. Plugging these values into the formula, we get:
Present Value = $1,800 / 0.05. Simplifying this equation, we find that:
Present Value = $36,000

To know more about perpetuity visit:

https://brainly.com/question/28205403

#SPJ11

The third term of the arithmetic sequence presented is given as follows:

14.

An arithmetic sequence is a sequence of numbers in which each term is obtained by adding a constant value, called the common difference (d), to the previous term.

From the sequence in this problem, the terms are given as follows:

More can be learned about arithmetic sequences at https://brainly.com/question/6561461

#SPJ1

The correct sum of the polynomial is \(\rm 6x^3 + 3x - 6\).

We have to determine

The correct sum of the polynomials.

Sum of the polynomials is just a matter of combining like terms, with some order of operations.

Then,

The correct sum of the polynomial is;

\(\rm (4x^3 - 2x - 9) + (2x^3 + 5x + 3) \\\\ 4x^3 - 2x - 9 + 2x^3 + 5x + 3\\\\ 6x^3 + 3x - 6\)

Hence, the correct sum of the polynomial is \(\rm 6x^3 + 3x - 6\).

To know more about the sum of the polynomial click the link is given below.

https://brainly.com/question/9465649

The appropriate frame size for the given task set is 140.

The frame size is the length of a time interval in which all the tasks in the system are scheduled to be executed. The frame size must be a multiple of the period of each task in the system.

In this case, the periods of the tasks are 5, 7, 12, and 45. The smallest common multiple of these periods is 140. Therefore, the appropriate frame size for the given task set is 140.

Here is a more detailed explanation of the calculation of the frame size:

The first step is to find the least common multiple of the periods of the tasks. The least common multiple of 5, 7, 12, and 45 is 140.

The second step is to check if the least common multiple is also a multiple of the execution time of each task. The execution time of each task is equal to its period in this case. Therefore, the least common multiple is also a multiple of the execution time of each task.

Therefore, the appropriate frame size for the given task set is 140.

Learn more about multiple here: brainly.com/question/14059007

#SPJ11

The conical surface is the correct answer as it allows for slopes ranging from 20:1 to 50:1. The FAR Part 77 imaginary surface that has slopes that may range from 20:1 to 50:1 is the conical surface.

The conical surface is a three-dimensional surface defined by a combination of horizontal and inclined planes. It extends upward and outward from the end of the primary surface and has varying slope requirements. The slope of the conical surface represents the ratio of the change in elevation to the horizontal distance. A slope of 20:1 indicates that for every 20 units of horizontal distance, there is a 1-unit increase in elevation.

Similarly, a slope of 50:1 means that for every 50 units of horizontal distance, there is a 1-unit increase in elevation. Therefore, the conical surface is the correct answer as it allows for slopes ranging from 20:1 to 50:1.

To learn more about   conical surface click here: brainly.com/question/29129362

#SPJ11

The probability of getting all three tosses to head is 1/8.

We have,

When a coin is tossed, there are two possible outcomes:

heads (H) or tails (T).

Since there are three tosses, the total number of possible outcomes.

2³ = 8.

The probability of getting heads on one toss is 1/2.

The probability of getting heads on all three tosses is the product of the probabilities of getting heads on each individual toss:

P(HHH) = P(H) x P(H) x P(H) = (1/2) x (1/2) x (1/2) = 1/8.

Therefore,

The probability of getting all three tosses to head is 1/8.

Learn more about probability here:

https://brainly.com/question/14099682

#SPJ1

The trigonometric function gives the ratio of different sides of a right-angle triangle. The given problems can be solved as given below.

The trigonometric function gives the ratio of different sides of a right-angle triangle.

\(\rm Sin \theta=\dfrac{Perpendicular}{Hypotenuse}\\\\\\Cos \theta=\dfrac{Base}{Hypotenuse}\\\\\\Tan \theta=\dfrac{Perpendicular}{Base}\\\\\\Cosec \theta=\dfrac{Hypotenuse}{Perpendicular}\\\\\\Sec \theta=\dfrac{Hypotenuse}{Base}\\\\\\Cot \theta=\dfrac{Base}{Perpendicular}\\\\\\\)

where perpendicular is the side of the triangle which is opposite to the angle, and the hypotenuse is the longest side of the triangle which is opposite to the 90° angle.

1st.) x = 5 /Sin(30°)

x = 10

!) sin(45°) = 4/x

x = 4/sin(45°)

x = 4√2

I) Cos(45°) = √3 / x

x = √3 / Cos(45°)

x = √6

E) Tan(60°) = 3√3 / x

x = 3√3 / 3

W) For isosceles right-triangle, the angle made by the legs and the hypotenuse is always 45°.

x = 45°

N) x² + x² = (7√2)²

x = 7

V) Tan(60°) = 7 / x

x = 7√3/3

K) x² + x² = (9)²

x = 9/√2

Y) Sin(60°) = 7√3/x

x = 14

M) Sin(30°) = x/11

x = 11/2

T) Sin(45°) = x/√10

x = √5

A) x + 2x + 90° = 180°

x = 30°

O) Sin(45°) = √2 / x

x = 2

R) Tan(30°) = x / 4

x = 4/√3 = 4√3 / 3

S) Sin(60°) = x / (10/3)

x = 5√3 / 3

Learn more about Trigonometric functions:

https://brainly.com/question/6904750

#SPJ1

Answer:

step-by-step explaination

Data :- 0.2 , 0.5 , 0.01 , 0.03 , 0.6 , 1

therefore,

range = highest value - lowest value = 1 - 0.03

= 0.97...ans

Answer:

c) f = 28

Step-by-step explanation:

Given problem,

→ f³ = 21952

Now the value of f will be,

→ f³ = 21952

→ f = ³√21952

→ [ f = 28 ]

Let's check the following,

→ 28³

→ (28 × 28) × 28

→ 784 × 28 = 21952

Hence, option (c) is correct.

Main answer:A set of values that shows the exact position of a point in a two-dimensional coordinate plane

supporting answer:  

what is coordinate system?

An arrangement of reference lines or curves used to locate points in space. The Cartesian (after René Descartes) system is the most common two-dimensional system.

body  of the answer:

final answer: by following the above steps we can find the coordinates

to learn more about coordinates system from the given link

https://brainly.in/question/2974270

#SPJ4

A set of values that shows the exact position of a point in a two-dimensional coordinate plane

What is a coordinate system?

An arrangement of reference lines or curves used to locate points in space. The Cartesian (after René Descartes) system is the most common two-dimensional system.

Navigate to the coordinate graph with the lines X'OX, Y'OY.

Determine which quadrant of the graph contains an ordered pair or a point.

Measure the distance between the point and the x-axis to get the abscissa.

Similarly, to obtain the ordinate value, measure the point's distance from the y-axis.

By following the above steps we can find the coordinates.

To learn more about the coordinates system from the given link:

https://brainly.com/question/29791401

#SPJ4

In three-dimensional graphing, we use three axes (x, y, and z) to divide the space into eight sections or intervals.(option d)

In three-dimensional graphing, we use three axes to represent the three dimensions: x, y, and z. These axes are typically labeled as x-axis, y-axis, and z-axis, respectively. The x-axis represents the horizontal direction, the y-axis represents the vertical direction, and the z-axis represents the depth or distance from the viewer's perspective.

When we combine these three axes, they create a three-dimensional space or a graph. Each axis is perpendicular to the other two axes, forming a right-handed coordinate system. The x, y, and z axes intersect at a point called the origin, usually denoted as (0, 0, 0). The origin serves as the reference point from which we measure distances and positions in three-dimensional space.

Each axis is divided into smaller sections or intervals, just like the number line on a two-dimensional graph. These divisions, also known as units or ticks, help us locate and label specific points or positions in the three-dimensional space accurately. The number of sections or intervals on each axis depends on the scale or range of values being represented.

The correct answer to the question is D) 3,8, as there are three axes (x, y, and z) and each axis is divided into eight sections or intervals, depending on the scale or range being represented.

To know more about triangle here

https://brainly.com/question/8587906

#SPJ4

Answer:

13/4 or 3 1/4

Step-by-step explanation:

Make into improper fractions:

4x3+1 = 13, 1x3+1 = 4

13/3 ÷ 4/3

Dividing fractions rule: ALWAYS make the second one a reciprocal (flip the fraction) and then change the sign. Remember KCC, Keep, Change, Change.

So: 13/3 x 3/4

The 3's cancel leaving you with 13/4 or 3 1/4

Hope that helps. Brainliest is appreciated

the solution to the given differential equation with the initial conditions is:

y1(t) = (1/2)e^(5t/6) + (1/2)e^(-5t/6)

y2(t) = (5/6)e^(5t/6) - (5/6)e^(-5t/6)

W(t) = 150 * sinh^2(5t/6)

Given the differential equation 36y″ - 25y = 0, we need to find the solution with the initial conditions y1(0) = 1, y1′(0) = 0 and y2(0) = 0, y2′(0) = 1.

First, we find the roots of the characteristic equation 36r² - 25 = 0 to obtain the values of m: r = ±5/6. Therefore, m1 = 5/6 and m2 = -5/6.

The general solution of the differential equation is given by y = c1e^(5t/6) + c2e^(-5t/6).

Let's find y1(t) with the initial conditions y1(0) = 1 and y1′(0) = 0:

y1(t) = c1e^(5t/6) + c2e^(-5t/6)

Differentiating y1(t), we get:

y1'(t) = (5/6)c1e^(5t/6) - (5/6)c2e^(-5t/6)

Substituting t = 0 and y1(0) = 1, we get:

1 = c1 + c2

Substituting t = 0 and y1'(0) = 0, we get:

0 = (5/6)c1 - (5/6)c2

Solving these equations, we find c1 = c2 = 1/2. Therefore, y1(t) = (1/2)e^(5t/6) + (1/2)e^(-5t/6).

Now, let's find y2(t) with the initial conditions y2(0) = 0 and y2′(0) = 1:

y2(t) = c1e^(5t/6) + c2e^(-5t/6)

Differentiating y2(t), we get:

y2'(t) = (5/6)c1e^(5t/6) - (5/6)c2e^(-5t/6)

Substituting t = 0 and y2(0) = 0, we get:

0 = c1 + c2

Substituting t = 0 and y2'(0) = 1, we get:

1 = (5/6)c1 - (5/6)c2

Solving these equations, we find c1 = 5/6 and c2 = -5/6. Therefore, y2(t) = (5/6)e^(5t/6) - (5/6)e^(-5t/6).

Now, let's find the Wronskian W(t) = W(y1, y2):

W(t) = | y1 y2 |

| y1' y2' |

Substituting the expressions for y1(t), y2(t), y1'(t), and y2'(t), we have:

W(t) = | (1/2)e^(5t/6) + (1/2)e^(-5t/6) (5/6)e^(5t/6) - (5/6)e^(-5t/6) |

| (5/6)e^(5t/6) - (5/6)e^(-5t/6) (25/12)e^(5t/6) + (25/12)e^(-5t/6) |

Simplifying, we find:

W(t) = 150 * sinh^2(5t/6)

To know more about differential equation

https://brainly.com/question/32645495

#SPJ11

Answer:

12 units

Step-by-step explanation:

the perimeter = AB+AC+BC=

3+4+5 = 12

Answer:

12 units

Step-by-step explanation:

AB = 3 units

BC = 5 units

CA = 4 units

Perimeter of triangle,

→ AB + BC + CA

→ 3 + 5 + 4

→ 12 units is the answer.

Answer:

Step-by-step explanation

2xy² +8y

= 2y (xy+8)

Just see what is the maximum common numbers u can find

Answer:

2y(xy+4)

Step-by-step explanation:

y is in both 2xy^2 and 8y

2 is in 2xy^2 and 8y which is 4×2=8

The correct option is D, The relationship is not proportional because the ratio of pages to days is not constant.

A linear relationship is a relationship in which each term has at max one degree. Linear equation in variable x and y can be written in the form y = mx + c.

A linear relationship with two variables, when graphed on the cartesian plane with axes of those variables, gives a straight line.

For the given relationship to be proportional, the number of pages read should be the same every day. Therefore, the ratio of the number of pages to the number of days should be equal.

85/1 = 85

170/2 = 85

249/3 = 83

340/4 = 85

435/5 = 87

Hence, the correct option is D, The relationship is not proportional because the ratio of pages to days is not constant.

Learn more about Linear relationships:

https://brainly.com/question/27465710

#SPJ1

Answer:

22.05

Discount = Original Price x Discount %/100

Discount = 24.5 × 10/100

Discount = 24.5 x 0.1

You save = $2.45

24.50 - 2.45

22.05!

Answer:

5.83 ft

Step-by-step explanation:

Given that

Scale factor, n = 10

Wall in blueprint = 7 in

To find:

Length of actual wall = ?

Solution:

Whenever a blueprint is created for any house or building, it is made smaller by a scale factor.

Here this factor is 10 times.

That means, the blueprint size is 10 times smaller than that of its actual size.

Or we can say that actual wall of building is 10 times the wall of blueprint.

So, wall of building = 10 \(\times\) 7 = 70 inches

Now, we know that 12 inches = 1 ft

1 inch = \(\frac{1}{12}\ ft\)

70 inches = \(\frac{1}{12}\times 70\ ft = 5.83\ ft\)

so, the answer is Wall of building is 5.83 ft.

(a) Given that G = {1, a, b, c} be the Klein 4-group. Label 1, a, b, c with the integers 1, 2, 3, 4, respectively and we are to prove that under the left regular representation of G into S_4 the non-identity elements are mapped as follows: a → (12)(34), b → (13)(24), c → (14)(23). Proof: Let ρ be the left regular representation of G into S_4. We know that there is a one-to-one correspondence between G and the permutation group on G induced by ρ.Thus, we have that (1)ρ = e, (a)ρ = (1234), (b)ρ = (1324), (c)ρ = (1423). Therefore, the non-identity elements are mapped as follows: (a) → (12)(34), b → (13)(24), c → (14)(23).b)In this case, we are supposed to relabel 1, a, b, c as 1, 3, 4, 2, respectively and compute the image of each element of G under the left regular representation of G into S_4. We are also supposed to show that the image of G in S_4 is the same subgroup as the image of G found in part a, even though the nonidentity elements individually map to different permutations under the two different labellings. Proof: Let G' = {1, 3, 4, 2} be the group with the given relabeling. Then, G' is isomorphic to G via the isomorphism ϕ such that ϕ(1) = 1, ϕ(a) = 3, ϕ(b) = 4, and ϕ(c) = 2.The left regular representation of G' into S_4 is defined by the permutation group induced by the isomorphism ρ ◦ ϕ. Let f = ρ ◦ ϕ. Then, f satisfies:f(1) = (1)f(a) = (13 24)f(b) = (14 23)f(c) = (12 34)Therefore, the non-identity elements in G are mapped to the same permutations in S_4 under the relabeling (1, a, b, c) and (1, 3, 4, 2). Hence, the image of G in S_4 is the same subgroup in both cases.

To know more about Permutations, click here:

https://brainly.com/question/3867157

#SPJ11

For cross-sectional slicing of the three-dimensional figure is that is a square. Thus option C is correct.

As per the figure, cross-sectional slicing means the division of the three-dimension into half and they are divided into the 3D view thus forming a square.

All the 3 dimension figures include the cone, rectangle, and triangle. The volume of space that the cross-section of the plane makes tells us about the figure.

Hence the options square is correct as it makes the 3D view from the base of the triangle figure.

Find out more information about the cross-section.

brainly.com/question/12192005.

Answer: 85

Step-by-step explanation:

y = 5 - x. is the linear equation in point-slope form.

Points  (1,4) and (6,-1).

The formula for finding slope from two points (x₁, y₁) and (x₂, y₂) on a line is m = (y₂ - y₁) / (x₂ - x₁).

where , m = slope of the line. x₁ = the x-coordinate of the first point.

m = (-1 - 4) / (6 - 1 ).

m= -1

Substitute the values into the point-slope form,

y − y 1 = m ( x − x 1 ) .

y − 4 = -1 ( x − 1) .

y − 4 =  1 - x.

y = 5 - x.

complete question : Write the linear equation in point-slope form that passes through the given points. (1, 4) and (6, -1).

To learn more about  slope-intercept form  refer,

https://brainly.com/question/20965885

#SPJ1

Answer:

Slope: 24 cookies/ 1 hour or 24

Y-intercept (from given info): 0 (they never said she started with a certain amount of cookies)

The answer to the cryptarithmetic puzzle is HANGER = 920614

ALGEBRA = 2761842

A = 2 B  = 8 E = 1 G = 6   H = 9  L = 7  R = 4

In this puzzle, we are given that the letters of the alphabet represent digits 0-9.

We are tasked to find which digits correspond to the letters A, B, E, G, H, L, N, and R in the equation HANGER + HANGER + HANGER = ALGEBRA.

To solve this, we first realize that HANGER is a 6-digit word and ALGEBRA is a 7-digit word.

Therefore, H must be at least 3 and A can only be 1 or 2. After trying both cases, we find that A=2 and R=4.

Plugging these in and solving the equation, we find that HANGER=920614 and ALGEBRA=2761842.

Thus, we can conclude that A=2, B=8, E=1, G=6, H=9, L=7, and R=4.

Read more about puzzles here:

https://brainly.com/question/28994707

#SPJ1

In a cryptarithmetic puzzle, the digits 0–9 are represented with letters of the alphabet. Use your understanding of addition to find which digits go with the letters A, B, E, G, H, L, N, and R. HANGER + HANGER + HANGER = ALGEBRA example: T:2, W:1, O:5 then the word TWO is 215(two hundred fifteen), not 2+1+5

The specific expressions for f₂, f₃, f₄, f₅, and f₆ are not provided in the given information. To obtain the final expression for f(z) and determine the transformation of U₀ into an annulus f(U₀), the specific functions f₂, f₃, f₄, f₅, and f₆ need to be known.

a) To show that f₁(z) is a one-to-one (injective) and analytic function on U₀, we can demonstrate that it has a non-zero derivative throughout U₀. The function f₁(z) can be rewritten as:

f₁(z) = (1 - z) / (z + 1)

To find its derivative, we apply the quotient rule:

f₁'(z) = [(1 + z) - (1 - z)] / (z + 1)²

= (2z) / (z + 1)²

The derivative f₁'(z) is non-zero for all z in U₀, indicating that f₁(z) is analytic on U₀.

To prove that f₁(z) is one-to-one, we need to show that if f₁(z₁) = f₁(z₂), then z₁ = z₂. Let's assume f₁(z₁) = f₁(z₂) and proceed with the algebraic manipulation:

(1 - z₁) / (z₁ + 1) = (1 - z₂) / (z₂ + 1)

Cross-multiplying, we have:

(1 - z₁)(z₂ + 1) = (1 - z₂)(z₁ + 1)

Expanding and rearranging, we get:

z₁ - z₂ + z₁z₂ + 1 - z₁ = z₂ - z₁ + z₁z₂ + 1 - z₂

Simplifying, we obtain:

z₁ = z₂

This shows that if f₁(z₁) = f₁(z₂), then z₁ = z₂, proving the one-to-one property of f₁(z).

Now, let's consider the transformation f₁(U₀) and show that it maps U₀ to the right half-plane, i.e., f₁(U₀) = {z ∈ C: Re(z) > 0}.

To determine f₁(U₀), we substitute z = x + yi, where x and y are real numbers, into f₁(z) and analyze the resulting expression:

f₁(z) = (1 - (x + yi)) / ((x + yi) + 1)

= (1 - x - yi) / (x + yi + 1)

= [(1 - x - yi) / (x + 1 + yi)] * [(x + 1 - yi) / (x + 1 - yi)]

= [(1 - x - yi)(x + 1 - yi)] / [(x + 1)² + y²]

Expanding the numerator, we have:

[(1 - x - yi)(x + 1 - yi)] = (1 - x - yi)(x + 1) + (1 - x - yi)(-yi)

= (1 - x)(x + 1) + (1 - x)(-yi) + (-y)(x + 1) + (-y)(-yi)

= (1 - x²) - (xi) - (x + 1)y - y²

= 1 - x² - y² - xi - xy - y

Simplifying the denominator, we get:

[(x + 1)² + y²] = x² + 2x + 1 + y²

Now, the expression for f₁(z) becomes:

f₁(z) = [1 - x² - y² - xi - xy - y] / [x² + 2x + 1 + y²]

To determine the real part of f₁(z), we focus on the terms without the imaginary unit "i":

Re[f₁(z)] = [1 - x² - y² - y] / [x² + 2x + 1 + y²]

To show that Re[f₁(z)] > 0, we observe that the numerator is always positive (1 - x² - y² - y > 0) for z in U₀ because x² + y² < 1. The denominator is also positive (x² + 2x + 1 + y² > 0) for z in U₀. Therefore, Re[f₁(z)] > 0 for all z in U₀, implying that f₁(z) maps U₀ to the right half-plane.

b) Given the function f(z) = e^(-i ln{[(i(1 - z)/(z + 1))^2] / 1}), we can express it as a composition of six analytic functions:

f(z) = f₆∘f₅∘f₄∘f₃∘f₂∘f₁(z)

To determine f₁(U₀), f₂∘f₁(U₀), f₃∘f₂∘f₁(U₀), and so on, we can calculate the successive compositions as follows:

f₁(U₀) = {z ∈ C: Re(f₁(z)) > 0}

f₂∘f₁(U₀) = {z ∈ C: Re(f₂(f₁(z))) > 0}

f₃∘f₂∘f₁(U₀) = {z ∈ C: Re(f₃(f₂(f₁(z)))) > 0}

f₆∘f₅∘f₄∘f₃∘f₂∘f₁(U₀) = f(U₀)

Each successive composition can be determined by applying the respective function to the result of the previous composition.

Note: The specific expressions for f₂, f₃, f₄, f₅, and f₆ are not provided in the given information. To obtain the final expression for f(z) and determine the transformation of U₀ into an annulus f(U₀), the specific functions f₂, f₃, f₄, f₅, and f₆ need to be known.

To know more about expressions visit

https://brainly.com/question/14083225

#SPJ11

Answer:

Inequality Form:

x<−5 or x>−1

Interval Notation:

(−∞,−5)∪(−1,∞)

Step-by-step explanation: