If 0.795 mol of ammonia gas occupies 24.5 L at 0.853 atm, what is the Celsius temperature? (R = 0.0821 atm L/mol K) -71 degree C 5 degree C 47 degree C 278 degree C 320 degree C

Answer:

A

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Answer:

calcium

Explanation:

you can check on the periodic table

The atom's mass number, 13, is the sum of the neutrons and protons in the nucleus. The atomic number, 6, is the number of protons in the nucleus.

Here, correct answer will be

Therefore, the number of neutrons in the nucleus is equal to the mass number minus the atomic number. In this case, the number of neutrons is 13 - 6 = 7.

Neutrons are particles found in the nucleus of an atom. They have no charge and play an important role in keeping the nucleus together. Neutrons interact with protons via the strong nuclear force and help to keep the nucleus stable.

They also play an important role in nuclear reactions, such as fusion and fission, which are used to generate energy and create the elements found in nature.

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. How many joules of heat are absorbed to raise

the temperature of 37 grams of water from 25°C

to 75°C?

The enthalpy of vaporization (ΔHvap) of benzene is determined to be approximately 4983.46 kJ/mol.

To find the enthalpy of vaporization (ΔHvap) of benzene, we can use the Clausius-Clapeyron equation:

ln(P2/P1) = -ΔHvap/R × (1/T2 - 1/T1)

Given:

P1 = 224 mmHg (vapor pressure at 45 °C)

P2 = 648 mmHg (vapor pressure at 75 °C)

T1 = 45 °C + 273.15 = 318.15 K (temperature in Kelvin)

T2 = 75 °C + 273.15 = 348.15 K (temperature in Kelvin)

R = 8.314 J/(mol·K) (gas constant)

Substituting the values into the equation:

ln(648/224) = -ΔHvap/(8.314) × (1/348.15 - 1/318.15)

To solve the equation, let's substitute the given values and calculate the enthalpy of vaporization (ΔHvap) of benzene.

ln(648/224) = -ΔHvap/(8.314) × (1/348.15 - 1/318.15)

Taking the natural logarithm:

ln(2.8929) = -ΔHvap/(8.314) * (0.002866 - 0.003142)

Simplifying:

0.1652 = -ΔHvap/(8.314) × (-0.000276)

Rearranging the equation:

0.1652 = ΔHvap × (0.000276/8.314)

Solving for ΔHvap:

ΔHvap = 0.1652 × (8.314/0.000276)

ΔHvap ≈ 4983.46 kJ/mol

Therefore, the enthalpy of vaporization of benzene is approximately 4983.46 kJ/mol.

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Therefore, the constancy in color intensity can be an indicator of a dynamic equilibrium, where the rates of the forward and reverse reactions are equal and the concentrations of reactants and products remain constant over time.

Chemical equilibrium occurs when a reversible reaction takes place, where the reactants can form products and the products can also react to form reactants. At the beginning of the reaction, the reactants are transformed into products, and as the reaction progresses, the concentration of the reactants decreases while the concentration of the products increases. Eventually, a point is reached where the rate of the forward reaction is equal to the rate of the reverse reaction, and the concentrations of the reactants and products remain constant. This state is called chemical equilibrium.

Here,

The constancy in color intensity can indicate the dynamic nature of equilibrium in certain cases. In a chemical equilibrium, the forward and reverse reactions are occurring simultaneously, but at equal rates, resulting in a constant concentration of reactants and products. Many chemical reactions involve colored species, and changes in the intensity of the color can indicate a change in the concentration of the species involved. For example, consider the reaction between iodine and starch:

I2 + starch ⇌ I2-starch complex

In this reaction, the iodine-starch complex is a blue-purple color, while the reactants (iodine and starch) are colorless. As the reaction proceeds, the concentration of the complex increases, leading to an increase in color intensity. However, if the reaction reaches equilibrium, the forward and reverse reactions will be occurring at equal rates, and the concentration of the complex will remain constant. This will result in a constant color intensity, indicating the dynamic nature of the equilibrium.

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Answer:

In naming the transition metal ion, add a Roman numeral in parenthesis after the name of the transition metal ion. The Roman numeral must have the same value as the charge of the ion. In our example, the transition metal ion Fe2+ would have the name iron(II). Add the name of the anion to the transition metal ion.

Explanation:

The statement 'Science provides only a limited understanding of the supernatural issues such as art, philosophy, or religion" is TRUE because it is based on empirical evidence.

Science can be defined as a body of knowledge derived from applying the scientific method, which allows us to collect empirical evidence about the real world.

Supernatural issues such as art, philosophy, or religion cannot be scientifically explained because they are often based on a subjective point of view.

In conclusion, the statement 'Science provides only a limited understanding of the supernatural issues such as art, philosophy, or religion" is TRUE because it is based on empirical evidence.

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A double displacement reaction is a type of chemical reaction where two compounds react, and positive ions (cation) and the negative ions (anion) of the two reactants switch places, forming two new compounds or products.

Na2S+2HCl→2NaCl+H2S

hope it's helpful :)

Answer:

Explanation:

3618

To combine ions to form ionic compounds, we need the combine in such a way that it gets neutral charge.

We can combine each anion with each cation to get the 4 compounds we need.

To combine SO₄²⁻ with Pb⁴⁺ we first find the Least Common Multiple of their charges, 2 and 4.

They have the factor 2 in common, so the LCM is 4. This is the final charge of each that will cancel out.

To get 4+, we only need 1 Pb⁴⁺.

To get 4-, we need 2 SO₄²⁻.

So, the formula is:

Pb(SO₄)₂

To combine SO₄²⁻ with NH₄⁺ is easier because one of them has single charge. In this case, we can simply pick one of the multiple charge ion and the same amount that will cancel its charge of the single charged one.

So, we picke 1 SO₄²⁻, ending with 2-.

And we picke 2 NH₄⁺, ending with 2+.

The formula:

(NH₄)₂SO₄

To combine C₂H₃O₂⁻ with Pb⁴⁺ we do the same, because the anion is single charged.

Pick 1 Pb⁴⁺, ending with 4+.

Pick 4 C₂H₃O₂⁻, ending with 4-.

The formula:

Pb(C₂H₃O₂)₄

To combine C₂H₃O₂⁻ with NH₄⁺, both have same charge, so we just need one of each and their charges will cancel out.

The formula:

NH₄C₂H₃O₂

So, the formulas are:

Pb(SO₄)₂

(NH₄)₂SO₄

Pb(C₂H₃O₂)₄

NH₄C₂H₃O₂

The word problem format to the task given above is: When magnesium reacts with steam, it produces magnesium hydroxide and liberate hydrogen gas.

It happens that magnesium is an alkali earth metal and react with water in the gaseous state to librate hydrogen gas, when this reaction occurs, it results in the formation of magnesium hydroxide.

The chemical equation between magnesium and water is given below:

Mg + 2H₂O -----> Mg (OH)₂ + H₂

So therefore, we can accurately deduced that magnesium hydroxide is produced when magnesium is disolved in water.

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The spheres are likely made of lipids, which are a type of macromolecule. Lipids are molecules that are composed of fatty acids and glycerol, and are essential for life.

The oily sphere likely contains a core of fatty acids and glycerol, surrounded by a hydrophobic (water-repellent) coating that is formed by the non-polar tails of the fatty acids, which interact with each other and form a sphere-like structure. Lipids have a variety of functions in cells, including serving as structural components of membranes, energy storage molecules, and hormone precursors. Many lipids are made from fatty acids, which are chains of carbon atoms with hydrogen atoms attached. They are important components of cell membranes and are used as energy storage molecules.

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Molarity is the molar concentration of the solute dissolved in a volume of a solution. The molarity of the solution prepared by dissolving barium chloride will be 0.085 M.

Molarity is the ratio of the moles of the solute to that of the volume of the solution in Liters. It can be given as,

\(\rm Molarity = \dfrac{moles}{Volume}\)

Here, moles of the barium chloride can be given by the mass and the molar mass and volume is given as 0.450 L.

Substituting values in the equation:

\(\begin{aligned}\rm Molarity &= \rm \dfrac{mass}{Molar \;mass\times Volume}\\\\&= \dfrac{8}{208.23\times 0.450}\\\\&= 0.085\;\rm M\end{aligned}\)

Therefore, 0.085 M barium chloride is the molar concentration.

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If the initial pressure of (CH3)20, is 135 torr, the final pressure after 1420s is 51.4torr .the half life is 1019s.

We know ,

For the 1st order reaction we have the reaction in terms of pressure is

Pₓ = P₀ e⁻kt

lnPₓ = lnP₀ - kt

kt = lnP₀ -lnPₓ  = 2.303log P₀/Pₓ

t = (2.303/k) logP₀/Pₓ

Where ,

k = rate constant = 6.8×10⁻4 s⁻1

P₀ = initial pressure = 135torr

Pₓ= final pressure

t = time taken = 1420s

putting the values in the places of the symbol ,

1420 =( 2.303 / 6.8 ×10⁻4 ) log 135/Pₓ

1420 = (2.303×10^4/6.8 ) ×log 135/Pₓ

(1420×6.8 / 2.303×10^4) = log 135/Pₓ

0.41928 = log 135/Pₓ

135/Pₓ = 10^0.41928 = 2.6259

Pₓ = 135/2.6259 = 51.4 torr

Hence , the final pressure after 1420s is 51.4torr .

b) the half life formula is given by ,

T1/2 = 0.693/k = 0.693 / 6.8×10⁻4 = 0.1019×10^4 =1019s

Hence , the half life is 1019s .

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answer and explanation

to correctly answer this question we first need to look at the mol ratio of the balanced stoichiometric equation

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

from this balanced equation we see that 2 mols of NaOH will be neutralized by 1 mol of sulfuric acid. therefore the mols ratio is

H₂SO₄: NaOH

1:2

if we have 0.70 mol of NaOH then we need :

(0.70 x1)/2 = 0.35 mols of sulfuric acid

The difference in mass between sample A and sample B could be due to the difference in concentration of NaCl in each solution.

When a solute, such as NaCl, is dissolved in a solvent, it forms a homogeneous mixture known as a solution. The concentration of the solution is usually expressed in terms of the amount of solute dissolved in a given amount of solvent. In this case, the student discovered two NaCl solutions, each containing evidence of NaCl solid.

When the student removed exactly 10.0 ml of liquid from each solution and weighed the samples, sample A had a mass of 11.998 g while sample B had a mass of 12.202 g. This difference in mass could be due to the difference in concentration of NaCl in each solution.

It is possible that sample B had a higher concentration of NaCl than sample A, which would explain its higher mass. This difference in concentration could be due to a number of factors, such as the amount of NaCl solid that was initially added to each solution or the amount of solvent used to dissolve the NaCl solid.

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The volume needed to make 1.98 M of the solution is 2.12L

Molarity of a given solution is defined as the total number of moles of solute per litre of solution. One molar is the molarity of a solution where one gram of solute is dissolved in a litre of solution. As we know, in a solution, the solvent and solute blend to form a solution, hence, the total volume of the solution is taken.

Given,

Molarity = 1.98m

Moles = 4.2 mol

Molarity = number of moles of solute / volume of solution in L

Volume = moles / molarity

= 4.2 / 1.98

= 2.12 L

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Answer: Water won't boil at normal atmospheric pressure until 100 C so it will appear fairly neutral until then. Pure water is completely translucent and colorless. It is also tasteless and odorless. Because completely pure water has no electrolytes, it will be a poor conductor of electricity.

Answer:

True

Explanation:because of the motion

Answer: Use the formula F= k q1q2/r^2 where k= 1/4π€ and it's value in air is 9× 10^9.

q1=q2= 2.4×10^-6C

F= 0.5N

You will get the value of r^2 and then will have to find the squre root of that value.

Explanation:

Number of moles = 8.3 x 10⁻¹³

The mole is the number of particles(molecules, atoms, ions) contained in a substance

1 mol = 6.02.10²³  particles

Can be formulated

N=n x No

N = number of particles

n = mol

No = Avogadro's =  6.02.10²³

5 x 10¹¹ atoms of Silver :

\(\tt mol=\dfrac{5\times 10^{11}}{6.02\times 10^{23}}=8.3\times 10^{-13}\)

Answer:

It is either B or D, and I believe the answer is D.

Explanation:

Deepwater drilling relies on mud being pumped into the drill well for pressure purposes. Without the mud, gas and oil would just rise up uncontrollably because without counteracting the pressure from the sea and the rock, it would be spewing out. The mud helps the drill create the heavy column of downward force needed to maintain control of the output of gas and oil.

The answer choices that would best match the description would be B or D. Since the mud is there for provide pressure and downward force, I would go with choice D as my answer.

In reaction 4 on page 76, NH4Cl cannot be analyzed gravimetrically because it is soluble in aqueous solution. Option D.

Gravimetric analysis involves precipitating a substance out of solution and measuring its mass, but since NH4Cl dissolves in water, it cannot be effectively isolated for measurement. In contrast, an inert substance would not react or dissolve in the solution, making it suitable for gravimetric analysis. Additionally, the stability or solubility of NH4Cl does not affect its ability to be analyzed gravimetrically, as long as it is not soluble in the solvent used for precipitation. Therefore, the correct answer is D.

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Answer:

gas vibrate and move freely at high speeds. liquid vibrate, move about, and slide past each other. solid vibrate (jiggle) but generally do not move from place to place.

Answer:

The soilds vibrate in a fixed position and are very packed together whilst in liquids they are close together but they can move around and gases are widely spaced and move around randomly

Explanation:

The mass of anhydrous copper(II) sulfate in 55 cm³ of a 0.20 mol/dm³ solution is approximately 1.76 grams.

To calculate the mass of anhydrous copper(II) sulfate in a given solution, we need to consider the molar concentration of the solution and the volume of the solution.

Given:

Molar concentration of the solution (c) = 0.20 mol/dm³

Volume of the solution (V) = 55 cm³

First, we need to convert the volume from cm³ to dm³:

1 dm³ = 1000 cm³

55 cm³ = 55/1000 dm³ = 0.055 dm³

Next, we can use the formula:

Mass = Molar concentration × Volume × Molar mass

The molar mass of anhydrous copper(II) sulfate (CuSO₄) is:

Atomic mass of Cu = 63.55 g/mol

Atomic mass of S = 32.07 g/mol

4 × Atomic mass of O = 4 × 16.00 g/mol = 64.00 g/mol

Total molar mass = 63.55 + 32.07 + 64.00 = 159.62 g/mol

Now we can calculate the mass:

Mass = 0.20 mol/dm³ × 0.055 dm³ × 159.62 g/mol

Mass ≈ 1.76 grams

Therefore, the mass of anhydrous copper(II) sulfate in 55 cm³ of a 0.20 mol/dm³ solution is approximately 1.76 grams.

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Answer:

Give a brief question

Not an awful question

The following are true statements regarding reversible reactions is a. a reversible reaction might proceed in only one direction, with negligible contribution from the reverse reaction, depending on conditions and c. the forward and reverse reactions may occur simultaneously.

Reversible reactions are reactions that can proceed in either direction. In reversible reactions, the products of the forward reaction can react to produce the original reactants. A reversible reaction is a chemical reaction that can go in either direction. The forward and reverse reactions occur simultaneously.

The equilibrium constant describes the relative concentrations of the reactants and products at equilibrium. The equilibrium constant will provide information about how far the reversible reaction goes.

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The EDTA species can bind to a transition metal site up to four times.  It can also be used to determine the stoichiometry of a reaction or the electron transfer processes involved.

In the cobalt chloride hexahydrate starting material, the oxidation state of cobalt is +2. This is because the compound is composed of Co2+ cations (cobalt ions with a positive charge of 2+) and chloride anions (negatively charged ions) in a 1:2 ratio. The six water molecules in the compound do not affect the oxidation state of cobalt. Overall, knowing the oxidation state of a metal ion is important in understanding its chemical reactivity and behavior in reactions. It can also be used to determine the stoichiometry of a reaction or the electron transfer processes involved.

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