Identify the TRUE statements about energy.

A; Energy can transform from electrical energy to heat.

B; Energy can be created and destroyed.

C; Higher potential energy can change into higher kinetic energy.

D; Energy changes are 100% efficient.

Answer:

Explanation:

Given:

m = 5·10⁻²⁷ kg

V₁ = 2·10⁵ m/s

V₂ = 4·10⁵ m/s

D = 10cm = 0.10m

_______________

a - ?

The change in kinetic energy is equal to the work:

Ek₂ - Ek₁ = F·D

m·V₂² / 2 - m·V₁² / 2 = F·D

(m/2)·(V₂² - V₁²)  = F·D

Force:

F = (m/2)·(V₂² - V₁²) / D

F =   m·(V₂² - V₁²) / (2·D)

F = (5·10⁻²⁷)·( (4·10⁵)² - (2·10⁵))/ (2·0.10) ≈ 3·10⁻¹⁴ N

The velocity of the object is  23.24 m/s.

An attribute of an object moving in a circular route is centripetal acceleration. Any object moving in a circle with an acceleration vector pointing in the direction of the circle's center is said to be experiencing centripetal acceleration.

Given that an object is experiencing a centripetal acceleration of 36m/s^2.

Radius of the circle: r = 15 m.

Then, the velocity of the object is = √(36×15) m/s = 23.24 m/s.

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The tension in rope 2 (T2) = 288 N.

Newton's second law of motion states that the acceleration of an object is directly proportional to the net force applied to it, and inversely proportional to its mass. Mathematically, this can be expressed as:

      F = ma

where F is the net force, m is the mass of the object, and a is its acceleration.

T2 = μmg

= μg(m + m2)

= 0.10 * 9.8 m/s^2 * (60 kg + 20 kg)

= 288 N

When analyzing the motion of objects, it is often useful to consider the forces acting on them. These forces can include gravity, friction, tension, and others. By analyzing the forces, we can determine the net force acting on an object and use Newton's second law to calculate its acceleration.

In the problem you provided, we are given the coefficient of friction between the sleds and the snow, and we are asked to calculate the tension in rope 2 given the tension in rope 1. By considering the forces acting on the sleds and using Newton's second law, we can determine the relationship between the tensions in the ropes and the force of friction, and calculate the tension in rope 2.

Understanding the relationship between forces, acceleration, and mass is essential in many areas of science and engineering, including physics, mechanics, and aerospace engineering. By applying Newton's laws of motion, we can design and optimize systems and devices to perform specific functions and achieve desired outcomes.

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The wavelength of the sound wave is equal to 0.333 m. Therefore, option (c) is correct.

The frequency of the wave can be defined as the number of oscillations that occur in one second and can be expressed in hertz. The wavelength can be defined as the distance between the two adjacent points of a wave such as two crests or troughs.

The relationship between frequency (ν), speed of sound waves (V), and  wavelength (λ):

V = νλ

Given, the frequency of the sound wave, ν = 10 Hz

The speed of the sound wave,\(V = 340 m/s\)

The wavelength of the sound waves can determine as follows

λ = V/ν = 340/1020 = 0.333 m.

Therefore, the wavelength of the sound wave is 0.333 m

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As a star's temperature increases, it becomes hotter. Its color changes from orange, through yellow, to white.

Answer:

3rd choice

Explanation:

heat is transfered causing it to melt

Answer:

C

Explanation:

The frictional force acting on the block is completely static in nature and is equal to 90 Newton's.

Friction is a force that acts opposite to the direction of motion of body in order to oppose its motion.

Given in the question is a box of weight 120 N initially resting on a horizontal table. From the data given, we can write -

Weight of box [W] = 120 Newton

Coefficient of static friction (μ[s]) = 0.75

Coefficient of Kinetic friction (μ[k]) = 0.40

Horizontal push (F[h]) = 84 N

The frictional force is given by -

For Static friction - F[s] = μ[s] N

For Kinetic friction - F[k] = μ[k] N

Now, initially the box is at rest. When a horizontal force of 84 Newton is applied on it, the static friction will try to oppose the motion. For forward motion of the block -

F[h] - F[s] ≥ 0

F[h] - μ[s] N ≥ 0

84 - 0.75 x 120 ≥ 0            (Normal Reaction [N]  = Weight)

84 - 90 ≥ 0

- 6 ≥ 0

which is false.

This means that the static frictional force is greater than horizontal push and opposes the motion. The force due to static friction will only exist since, the body was able to move, so kinetic friction is of no use here.

So, the frictional force on the block will be = F[s] =  μ[s] N = 90 Newtons.

Therefore, the frictional force acting on the block is completely static in nature and is equal to 90 Newton's.

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Answer:

Certainly! Using the lens formula:

1/f = 1/v - 1/u

where f is the focal length of the lens, v is the distance between the lens and the image, and u is the distance between the lens and the object.

We can rearrange the formula to solve for v:

1/v = 1/f + 1/u

Substituting the values given, we get:

1/15 = 1/v - 1/50

Solving for v, we get:

v = 30cm

Therefore, the distance between the object and the screen is:

u + v = 50cm + 30cm = 80cm

Explanation:

Answer:

It's D: None of the above.

Explanation:

I looked up the components of soil and all of them were, and I also took the test and got it correct.  

Answer: It's lack of mass production

It is biodegradable. It does not harm landfills. It doesn't cost much to recycle.

I cannot find anything about mass production or if it costs a lot to recycle.

From the information I know, operating costs were expensive. Cellulose is always recycled and is good for the environment meaning it can't cost much to recycle

Since operating costs were high, it most likely won't be mass produced because it's too expensive.

Therefore I think the answer is its lack of mass production.

Answer:

its lack of mass production

Explanation:

Answer:

A physical property is any property that is measurable, whose value describes a state of a physical system.

Explanation:

How this helps.

the temporary change in which only physical properties like shape,size,colour are changed is called physical properties

Answer:

The speed of the airplane after it has travelled 800 meters is approximately 85.632 meters per second.

Explanation:

From statement, we obtain the equation of equilibrium associated with the airplane:

\(\Sigma F = T - R = m\cdot a\) (1)

Where:

\(T\) - Thrust force from engines, measured in newtons.

\(R\) - Force of air resistance, measured in newtons.

\(m\) - Mass of the airplane, measured in kilograms.

\(a\) - Net acceleration of the airplane, measured in meters per square second.

If we know that \(T = 7.5\times 10^{4}\,N\), \(R = 4.0\times 10^{4}\,N\) and \(m = 1.5\times 10^{4}\,kg\), then the net acceleration of the airplane is:

\(a = \frac{T-R}{m}\)

\(a = \frac{7.5\times 10^{4}\,N-4.0\times 10^{4}\,N}{1.5\times 10^{4}\,kg}\)

\(a = 2.333\,\frac{m}{s^{2}}\)

Lastly, the final speed of the airplane is calculated by the following kinematic equation:

\(v_{f} = \sqrt{v_{o}^{2}+2\cdot a \cdot \Delta s}\) (2)

Where:

\(\Delta s\) - Travelled distance, measured in meters.

\(v_{o}\), \(v_{f}\) - Initial and final speeds of the aircraft, measured in meters per second.

If we know that \(v_{o} = 60\,\frac{m}{s}\), \(a = 2.333\,\frac{m}{s^{2}}\) and \(\Delta s = 800\,m\), then the final speed of the aircraft is:

\(v_{f} = \sqrt{\left(60\,\frac{m}{s} \right)^{2}+2\cdot \left(2.333\,\frac{m}{s^{2}} \right)\cdot (800\,m)}\)

\(v_{f} \approx 85.632\,\frac{m}{s}\)

The speed of the airplane after it has travelled 800 meters is approximately 85.632 meters per second.

Answer: A. When half the parent nuclei in a sample have become daughter nuclei

Explanation:

Answer:

Explanation:   To breakdance, ask a friend or a professional, surf the internet, or invent your own moves. You don't have to master other breakdancers' moves to be a breakdancer yourself. You breakdancing by ...

Answer:

a moderate base

Explanation:

Milk of magnesia is popularly known as magnesium hydroxide. Magnesium hydroxide Mg(OH)₂ is used as an anti-acid in toothpaste and medically as a mild laxative.

Its pH values range between 10- 11 on the pH scale.

A solution with pH value of 7 is neutral(i.e. neither acidic nor basic.

A pH value which is less than 7 is acidic while a pH value greater than 7 is basic.

For a pH value between 12 -14 on the pH scale is said to be a strong base.

Since Milk of magnesia Mg(OH)₂ pH values ranges between 10- 11 on the pH scale, it is known to be moderately basic.

The work done by the friction force on the car's tires that allows it to turn is approximately -942.5 Joules.

The centripetal force required to keep the car moving in a circular path is provided by the friction force between the tires and the road surface. The work done by this friction force can be calculated using the following formula:

Work = Force * Distance * cos(θ)

In this case, the force is the friction force, the distance is the arc length of the turn, and θ is the angle between the force vector and the direction of motion.

Given that the car goes 3/4 around the turn (270 degrees), we can calculate the arc length of the turn:

Arc Length = (3/4) * 2π * radius

Arc Length = (3/4) * 2π * 40m

Arc Length = 3π * 10m

Arc Length ≈ 94.25m

The force required to maintain the car's circular motion is the centripetal force, which can be calculated using the formula:

Force = Mass * (\(Velocity^2\) / Radius)

The mass of the car does not affect the force required, as it cancels out in the calculation. Therefore, we can ignore the mass in this case.

Using the given values, we have:

Force =\((20m/s)^2\) / 40m

Force = 10 N

Now we can calculate the work done by the friction force:

Work = Force * Distance * cos(θ)

Work = 10 N * 94.25m * cos(270°)

Work ≈ -942.5 J

The negative sign indicates that the work done is in the opposite direction of the car's motion.

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Answer:

Explanation:

This problem bothers on the simple harmonic motion of a loaded spring

Given data

mass attached, m= 0-.675 kg

spring constant, k= 72.4 N/m

the period of oscillation can be solved for using the formula bellow

\(T= 2\pi \sqrt{\frac{m}{k} }\)

Substituting the given data into the expression above we have

\(T= 2*3.142\sqrt{\frac{0.675}{72.4} }\\T= 6.284*\sqrt{0.0093 }\\T= 0.6\)

T= 0.6 sec

Answer:

0.607

Explanation:

Trust me

Answer: The sound will increase in pitch.

Explanation:

According to the Doppler Effect, sounds will increase in pitch as they are nearing the listener, and then decrease in pitch as the sound moves further away. This is because when sound waves travel a shorter distance, the waves are more compact (higher frequency), producing a higher pitch. The further a listener is from the sound, the lower the pitch because the sound waves are more spread apart (lower frequency).

Based on damage in the photo, it is possible that the movement responsible could be from an earthquake.

Seismic waves spread through the ground in different ways when an earthquake occurs which often results to different types of waves. They includes:

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The motion of the 300 kg ball attached to a light string that is swinging rapidly in a complete vertical circle can be described using these key terms: centripetal force, centripetal acceleration, and gravitational force.

We're dealing with a situation where a 300 kg ball is attached to a light string and is swinging rapidly in a complete vertical circle.

This type of motion is known as circular motion, and it can be described using a few key terms. The first term is the centripetal force, which is the force that keeps an object moving in a circle.

In this case, the tension in the string is providing the centripetal force that keeps the ball moving in its circular path.

The second term is centripetal acceleration, which is the acceleration that occurs when an object moves in a circle. This acceleration is directed towards the center of the circle and is proportional to the square of the object's speed and inversely proportional to the radius of the circle.

So, as the ball swings faster, the centripetal acceleration increases, and as the radius of the circle decreases, the centripetal acceleration also increases.

Finally, we can also talk about the gravitational force that is acting on the ball as it swings. Because the ball is moving in a vertical circle, the gravitational force is changing direction constantly, and this can affect the ball's motion.

Specifically, at the top of the circle, the gravitational force is acting downwards and opposing the ball's upward motion, while at the bottom of the circle, the gravitational force is acting upwards and aiding the ball's downward motion.

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Therefore, the speed of the satellite must be 7.471 km/s to stay in this circular orbit 785 km above earth's surface.

A rocket releases a satellite into a circular orbit 785 km above the earth's surface. To stay in this orbit, the satellite must be going at a certain speed. To calculate this speed:

`v = sqrt(GM/r)`

where: v is the velocity of the satellite,

GM is the universal gravitational constant (6.67 x 10^-11 Nm^2/kg^2) multiplied by the mass of the earth,

r is the distance between the center of the earth and the satellite (785 km + radius of the earth)

Using the given values:

v = sqrt(6.67 x 10^-11 * 5.97 x 10^24 / (785 + 6,371))v

  = sqrt(3.99 x 10^14 / 7,156)v

  = sqrt(55,825,822)

The velocity of the satellite must be approximately 7,471 m/s or 7.471 km/s to stay in this orbit.

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After release, the magnitude of the net torque on the meterstick about the fulcrum is  nearly 1 N middot  m.

The term fulcrum refers to the point or support on which a lever rotates, or to the center of a key activity.

Given, distance between fulcrum and mark , d = 0.4 m

mass hung with fulcrum , m = 1 kg.

Value of another mass , m = 0.5 kg.

distance kept , d' = 1.0 m.

torque= F d- F1 (d1- d)

Torque = m g - m g(d1 - d)

= 1 * 9.8 * 4 - 0.5 * 9.8(1 - 0.4)

Torque = 1N

Thus,  the magnitude of the torque on the meterstick about the fulcrum is  nearly 1 N middot  m.

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Answer:

2.6 seconds

Explanation:

You have to divide the distance by the velocity to find the time:

46/18 = 2.55 ≈ 2.6 seconds

The answer you are looking for is approximately 2.6 seconds.

Solution/Explanation:

To get the correct answer, you must divide the distance and velocity.

This means that 46÷18=2.5556.

2.5556≈2.6.

So, therefore, the final answer is approximately 2.6 seconds.

I hope that this has helped you. Enjoy your day, and take care.

Therefore, the magnitude of the displacement vector is approximately 162.9 m. The magnitude of the displacement vector is approximately 162.9 m, and its direction is approximately 48.1 degrees with respect to the negative x-axis.

(a) Magnitude of the displacement vector:

The magnitude of the displacement vector can be found using the Pythagorean theorem:

|d| = √(dx²+ dy²)

Given the x-vector component magnitude is 107 m and the y-vector component magnitude is 125 m:

|d| = √((107 m)² + (125 m)²)

|d| = 162.9 m

Therefore, the magnitude of the displacement vector is approximately 162.9 m.

(b) Direction of the displacement vector:

The direction of the displacement vector can be found using trigonometric functions. We can use the arctan function to calculate the angle θ between the negative x-axis and the displacement vector:

θ = tan⁻¹(dy / dx)

Given the x-vector component points along the negative x-axis and the y-vector component points along the negative y-axis:

dx = -107 m

dy = -125 m

θ = tan⁻¹((-125 m) / (-107 m))

θ = tan⁻¹(1.1682)

θ = 48.1 degrees

The angle θ represents the positive angle with respect to the negative x-axis. Therefore, the direction of the displacement vector is approximately 48.1 degrees with respect to the negative x-axis.

Hence, the magnitude of the displacement vector is approximately 162.9 m, and its direction is approximately 48.1 degrees with respect to the negative x-axis.

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Answer:

hi I am Manasi

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In a stable ecosystem, the number of predators increases if the number of prey increases.

Predators are the species that are dependent upon prey for their foods. predators actually hunt the prey for their food.

predators are the species that depend upon other living species like deer fish goats etc for example lions depend upon deer, zebras, etc.

while the preys are the species who depend upon the plants for their food so if the number of preys will be higher then the number of the predators will also be higher.

Thus In a stable ecosystem, the number of predators increases if the number of prey increases.

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a) The motion of the object between 15 s to 30 s is increasing velocity, to a constant velocity and finally a decreasing velocity.

(b) The average velocity of the object between 0 and 15 seconds is 0.167 m/s.

(c) The position of the object at 5.0 seconds is 0.5 m.

(d) Between 30 and 40 seconds, the velocity of the object is decreasing and the object is decelerating.

(a) The motion of the object between 15 s to 30 s can be described as increasing velocity, to a constant velocity and finally a decreasing velocity.

(b) The average velocity of the object between 0 and 15 seconds is calculated as;

average velocity = total displacement / total time

average velocity = (2.5 m - 0 m ) / ( 15 s - 0 s ) = 0.167 m/s

(c) The position of the object at 5.0 seconds is calculated as follows;

at 5.0 seconds, the position of the object is traced from the graph as 0.5 m.

(d) The motion of the object between 30 and 40 seconds is calculated as;

velocity = ( 0 m - 4 m ) / ( 40 s - 30 s ) = - 0.4 m/s

Between 30 and 40 seconds, the velocity of the object is decreasing and the object is decelerating.

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Answer:

Explanation:

time =d/s

therefore, t =8.5/2.8

t=3.02s