identify the sampling technique used, based on 12500 responses from 48000 questionaires sent to its alumni, a major university estimated that the annual salary of its alumni was 78500 per year

The least squares regression line (LSRL) is a line that best fits the data by minimizing the sum of the squared residuals (the difference between the predicted value and the actual value). It is commonly used in linear regression analysis to estimate the relationship between two variables. In this context, the LSRL has some characteristics that distinguish it from other regression lines.

Firstly, the LSRL goes through more of the data points than other lines. This is because the line is fitted by minimizing the sum of the squared residuals, so it is a line that is as close as possible to all the data points. In other words, the LSRL is the line that passes closest to the most data points.
Secondly, relative to other lines, the LSRL has the smallest sum of squared errors (SSE). The SSE is a measure of how well the line fits the data. It is calculated by summing the squares of the residuals (the differences between the actual values and the predicted values) and is used to assess the accuracy of the line. The LSRL is the line that has the smallest SSE, which means it is the line that provides the best fit to the data.

However, it is not accurate to say that the LSRL gives the smallest predictions relative to other lines. The predictions made by the LSRL are based on the data and the line of best fit, so they may not be the smallest or largest predictions depending on the values of the independent variable. The LSRL provides the best estimate of the dependent variable given the independent variable, but it is not necessarily the line that provides the smallest predictions.

In conclusion, the LSRL is a line that best fits the data by minimizing the sum of the squared residuals. It goes through more of the data points and has the smallest sum of squared errors compared to other lines. However, it does not necessarily give the smallest predictions relative to other lines.

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To find the maximum value of z, solve the linear programming problem

We can use the Simplex method.

Convert the inequality constraint to an equality constraint by introducing a slack variable, s1:

2x1 + 3x2 + x3 + s1 = 50

Convert the second inequality constraint to an equality constraint by introducing a slack variable, s2:

4x1 + 2x2 + 5x3 + s2 = 40

1) Write the augmented matrix:

| 2 3 1 1 0 0 | 50 |

| 4 2 5 0 1 0 | 40 |

|-1 -4 -5 0 0 1 | 0 |

2) Select the pivot element, which is the most negative entry in the objective row. In this case, the pivot element is -2 in the first column.

| 1.5 2 0.5 0.5 0 0 | 25 |

| 1 0 -0.5 0.5 0.25 0 | 5 |

| 2.5 4 3.5 -0.5 0 1 | 10 |

3) Use row operations to eliminate the negative entries in the first column, while keeping the other entries in the objective row non-negative.

| 1.5 2 0.5 0.5 0 0 | 25 |

| 0.5 -2 -1 1.5 0.25 0 | 20 |

| 2.5 4 3.5 -0.5 0 1 | 10 |

4) Select the next pivot element, which is the most negative entry in the objective row. In this case, the pivot element is -2 in the third column.

| 2 2/3 0 1/3 1/6 0 | 30 |

| 1 -2/3 -0.5 3/4 1/8 0 | 10 |

| 3 4/3 3.5 -1/3 -1/6 1 | 20 |

5) Use row operations to eliminate the negative entries in the third column, while keeping the other entries in the objective row non-negative.

| 7/3 0 0.5 1/3 5/6 0 | 35 |

|-1/3 1 0.5 -3/4 -1/8 0 | 5 |

| 1/3 0 3 1/3 -1/6 1 | 5 |

All the entries in the objective row are now non-negative, so the optimal solution has been found. The maximum value of Z is 35, which occurs when X1 = 7/3, X2 = 0, and X3 = 1/3.

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Answer:

117 megabytes

Step-by-step explanation:

Por regla de tres:

72 mb son a 8 mins

D mb son a 13 minutos

D = 13*72/8

D = 117 mb

Answer:

<G = <R

Step-by-step explanation:

The second option

The required missing piece of information for the congruency of the triangles is ∠G = ∠R. OP[tion B is correct.

Given that,
The missing piece of information is needed to prove the triangles congruent using SAS is to be determined.

In congruent geometry, the shapes that are so identical. can be superimposed to themselves.

Here,
Since sides, FG and Gh are congruent with sides QR and RS respectively,
So, the angle between these sides will also be congruent.

Thus, the required missing piece of information for the congruency of the triangles is ∠G = ∠R. OP[tion B is correct.

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Answer:y=0

Step-by-step explanation: 5(4)+5(0)=20

Answer:

3/250

Step-by-step explanation:

21/35 divided by 50 = 21/1750

Simplify this into 3/250

The general formula that describes the variation is T² = 18a³/d²

          x ∝ y.

          This can then be written as;

           x = ky

           Where;

           k = constant rate of change.

            x ∝ (y/z)

           This can then be written as;

            x = k (y/z)

           Where;

           k = constant rate or variation

The square of T varies directly with the cube of a and inversely with the square of d.

Note that

square of T = T²

cube of a = a³

square of d = d²

Therefore, we can write;

T² ∝ a³/d²

T² = k (a³/d²)

Since;

T = 4 when a = 2 and d = 3

We can find the constant of proportionality k, by substituting the values of T=4, a = 2 and d = 3 into equation (i) and solve as follows;

(4)² =  k (2³/3²)

16 =  k (8/9)

8k = 16 x 9

8k = 144

k = 144/8

k = 18

Therefore, The overall formula for describing the variation is

T² =  18 a³/d²

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Answer:

using cos=adjacent/hypotenuse

Step-by-step explanation:

in this case cos(60)=x/4√3

x=cos(60)*4√3

x=3.46

Answer:

y=3x-7

Step-by-step explanation:

Answer:

85,696

Step-by-step explanation:

4 x 104 = 416

2 x 103 = 203

No sign between parentheses means that you have to multiply the two outcomes of the parentheses.

416 x 203 = 85,696

The statement that represents the ratio of cars to trains would be = 3 over 1. That is option C.

A ratio is defined as the expression that represents the comparison between two values.

The collection of vehicle models of Alex include the following:

The number of airplane = 8

The number of trains = 4

The number of cars = 12

Therefore, the ratio of cars to train = 12:4

This is further reduced to a simplest form;

= 12:4 ( divide through by 4)

= 3:1

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To find the eigenvalues of the given matrix, we need to solve the characteristic equation. The characteristic equation is obtained by subtracting the scalar λ from the diagonal elements of the matrix and setting the determinant of the resulting matrix equal to zero.

The given matrix is:

[-8 -9

-4 k]

Subtracting λ from the diagonal elements:

[-8-λ -9

-4 k-λ]

Setting the determinant equal to zero:

det([-8-λ -9

-4 k-λ]) = 0

Expanding the determinant:

(-8-λ)(k-λ) - (-9)(-4) = 0

Simplifying:

(-8-λ)(k-λ) + 36 = 0

Expanding and rearranging:

λ^2 - (8+k)λ + 8k + 36 = 0

For the matrix to have 0 as an eigenvalue, the characteristic equation must have a solution of λ = 0. Therefore, we can substitute λ = 0 into the characteristic equation:

0^2 - (8+k)(0) + 8k + 36 = 0

Simplifying:

8k + 36 = 0

Solving for k:

k = -4.5

So, for the matrix to have 0 as an eigenvalue, k must be equal to -4.5.

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Answer:

Can you post the picture pls

Step-by-step explanation:

Answer:

five because 5×3 is 15 and 5×1 is 5

Cⁿ₁ is always positive, then the second term has negative sign.

What does binomial expansion mean?

Theorem that states that any power of a binomial (a + b) can be expanded as a specific sum of products (aibj), such as (a + b)2 = a2 + 2ab + b2.

The i-th term of the binomial expansion \((x- y)^{n}\)

Ti = nCi - 1 . (x)ⁿ+¹⁺i  . (-y)i - 1

For any n, when i=2,

T₂ = nC₂₋₁  . xⁿ⁺¹⁻² . (-y)²⁻¹  = -Cⁿ₁ xⁿ⁻¹ . y

Given that is consistently positive, the second term has a negative sign.

Cn1 is consistently positive, and the second term is always negative.

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Answer:

y = 19

Step-by-step explanation:

the value of Y is 19

Answer:

80 megabytes

Step-by-step explanation:

768/384= 2 megabytes per photo

40 x 2 = 80 megabytes

The scale factor of dilation is 1/40 and the coordinates of F" are (1440, 600)

The image of the label is attached

Given that

D'E' = 36 units

Then, we have

D"E" = 0.9 units

The scale factor is calculated as

Scale factor = D"E"/D'E'

So, we have

Scale factor = 0.9/36

Evaluate

Scale factor = 1/40

So, the scale factor of dilation is 1/40

This is calculated as

F = F'/Scale factor

So, we have

F = (36, 15)/(1/40)

F = (1440, 600)

The trigonometry ratios are calculated as

sin(D") = EF/DF

cos(D") = DE/DF

tan(D") = EF/DE

So, we have the following approximated values

sin(D") = 15/39 = 0.36

cos(D") = 36/39 = 0.92

tan(D") = 0.36/0.92 = 0.39

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On that date, 77.65 dollars is worth 3,870.08 rupees.

On that date, 82.12 rupees is worth  $1.65.

Exchange rate is the rate at which one currency is exchanged for another currency.

In order to convert rupees to dollars, multiply the value of the rupees by the exchange rate:

value of the rupees x exchange rate

77.65 to rupees = 77.65 x 49.84 = 3,870.08 rupees

In order to convert dollars to rupees, divide the value o the dollars by the exchange rate:

value of the dollars / exchange rate

82.12 to dollars = 82.12 / 49.84 = $1.65

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Based on the given equation of b -4/6=b/2, the value of the variable b, can be found to be -2

The variable can be found by solving the equation through the operations of mathematics.

First, cross-multiply:

b -4/6 = b/2

b - 4 = 6b / 2

After cross-multiplying, collect like terms:

b - 4 = 3b

b - 3b = 4

-2b = 4

b = 4 / -2

b = -2

In conclusion, the variable is -2.

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Answer:

y = -5/7x + 27/7

Step-by-step explanation:

y2 - y1 / x2 - x1

1 - 6 / 4 - (-3)

-5 / 7

= -5/7

y = -5/7x + b

1 = -5/7(4) + b

1 = -20/7 + b

27/7 = b

The correct statements are: The sequence Xn =(1+n^2), n∈N is increasing and bounded and Every Cauchy sequence in R{0} converges.

The sequence Xn =(1+n^2), n∈N is increasing and bounded: This statement is true because for any n, Xn is greater than Xn-1, and the sequence is bounded above by n^2 + 1. Therefore, Xn is increasing and bounded.

The sequence Xn= ex₁ = (1+n^2)^n, n∈N does not converge: This statement is false because the sequence Xn does converge to infinity as n approaches infinity. This can be seen by taking the limit of Xn as n approaches infinity, which is infinity.

Sequence {n} that satisfies condition [Xn+1-xml < (3) n: This statement is incomplete and doesn't provide enough information to determine its correctness.

If Xn+Yn->0 and Xn->X, then Yn->-X: This statement is false because if Xn+Yn->0 and Xn->X, then we can't conclude anything about the convergence of Yn. For example, if Xn=1/n and Yn=-1/n, then Xn+Yn->0 and Xn->0, but Yn->0, not -X.

Every Cauchy sequence in R{0} converges: This statement is true. In fact, this is the definition of completeness of the real numbers. If a sequence is Cauchy, it means that its terms are getting closer and closer together, and if the sequence is in R{0}, then it converges to a nonzero limit.

Sequence {n} that satisfies condition [Xn+1-xml < (3) n: This statement is incomplete and doesn't provide enough information to determine its correctness.

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Answer:

1/ $ 4.08

2/ $675.92

Step-by-step explanation:

Take 68 times 0.06% = $4.08

680 - 4.08= 675.92

Answer:

Step-by-step explanation:

40.80 it told me the answer

Answer:

he paid a lot of money ouch

"From a table of integrals, we know that for \(\(a \neq 0\)\) and \(\(b \neq 0\):\)

\(\[\int \cos(at) \, dt = \frac{1}{a} \cdot \cos(at) + \frac{1}{b} \cdot \sin(bt) + C\]\)

and

\(\[\int e^a t \cos(bt) \, dt = \frac{e^{at}}{a} \cdot \cos(bt) + \frac{b}{a^2 + b^2} \cdot \sin(bt) + C\]\)

Use this antiderivative to compute the following improper integral:

\(\[\int_{-\infty}^{0} \cos(3t) \, dt = \lim_{{T \to \infty}} \int_{0}^{T} e^t \cos(3t) \, e^{-st} \, dt = \lim_{{T \to \infty}} \text{ if } s \neq 1, \, \text{ or } \lim_{{T \to \infty}} \text{ if } s = 1.\]\)

For which values of \(\(s\)\) do the limits above exist? In other words, what is the domain of the Laplace transform of \(\(\frac{1}{\cos(3)} \cdot e^t \cos(3t)\)\)?

Evaluate the existing limit to compute the Laplace transform of  on the domain you determined in the previous part:

\(\[L\{e^t \cos(3t)\\).

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