Identify some sports or activities you can do to improve your overall health and explain how physical activity can improve your

Answer:

Here's a list of a few reasons behind cracked or chipped walls:

Moisture-laden walls

Weather conditions

Incompatibility with the surface

Inferior-quality paints

Let’s discuss each of them one by one.

Explanation:

Lots of moisture

In a house, bathroom and kitchen are the two places where there is a lot of moisture and dampness. Therefore, you will see that these places are the first to report the problem of flaky paint. When moisture is absorbed, it passes through various coats of paint, removing the adhesive that sticks the paint to the wall. Therefore, you can spot paint coming off in the form of flakes or like a banana peel. This shows the extra moisture in the walls need to be addressed immediately.

Too much sunlight

Paint often chips off walls due to high temperatures. If direct sunlight hits the walls all day, it can cause the paint to dry out faster. The oil paints start to crack, while latex paints lose their quality to stick to the walls.

Incompatible paints

When painting, it is extremely important to use the same kind of paint on the surface that’s being coated. For instance, if it is latex paint, it isn’t compatible with oil-based paints and shouldn’t be painted on top of each other. If you are planning to use the leftover oil-paint as a second coat over the base coat of latex paint, then be prepared to see the paint coming off sooner than expected.

Also, make sure the surface on which you are about to paint is compatible with the paint you are using. For instance, smooth surfaces require a certain kind of paint and layering that keeps the coating intact. For uneven surfaces, it’s better to go for textured paint. It is important to prime and prep the surface first before applying a coat of paint to make sure the paint doesn’t come off easily.

Low-quality paints

Some paints seem good, especially to your wallet, but once you use them, you will face bad consequences. Inferior-quality paints do not adhere to the walls properly and also do not give a nice finish once the paint job is done. To avoid cracks in the walls, do not use low-quality or expired paints.

Answer:

a) The vertical component of the helicopters speed relative to the air = 0 m/s

The horizontal component of the helicopters speed relative to the air = -42.5 m/s

The vertical component of the wind speed relative to the ground = -21.65 m/s

The horizontal component of the wind  speed relative to the ground = 12.5 m/s

b) The x-component of the helicopter speed relative to the wind speed =  -30 m/s

The y-component of the helicopter speed relative to the wind speed =  -12.5 m/s

c) The resultant speed of the helicopter relative to the ground is 32.5 m/s in the direction of W 22.6° S

Explanation:

The speed of the helicopter = 42.5 m/s

The direction of flight of the helicopter = West

The wind speed = 25.0 m/s

The direction of the wind = E30°S

a) The velocity components of the helicopters speed relative to the air are;

Vertical component = 0 m/s

Horizontal component = -42.5 m/s

The velocity components of the wind speed relative to the ground are;

Vertical component = -25 × cos(30) = -21.65 m/s

Horizontal component = 25 × sin(30) = 12.5 m/s

b) To find the speed of the helicopter relative to the wind we have;

x-component of the helicopter speed = -42.5 m/s

y-component of the helicopter speed = -0

x-component of the wind speed relative to the ground = 25×sin(30) = 12.5 m/s

y-component of the wind speed relative to the ground = -25×cos(30) = -21.65 m/s

Therefore, the x-component of the helicopter speed relative to the wind speed = -42.5 + 12.5= -30 m/s

the y-component of the helicopter speed relative to the wind speed = 0 +  (-12.5) = -12.5 m/s

c) The resultant speed of the helicopter relative to the ground is given by the relation;

\(v_{h, ground} =\sqrt{(v_{h,horizontal})^2 + (v_{h,vertical})^2}\)

= √((-30)² + (-12.5)²) =32.5 m/s

The direction of motion from the x-axis is given as follows;

\(tan(x) = \dfrac{Vertical \ velocity \ component}{Horizontal \ velocity \ component} = \dfrac{-12.5}{-30} = \dfrac{5}{12}\)

\(x = tan^{-1} \left (\dfrac{5}{12} \right ) = 22.62 ^{\circ}\)

Therefore, the helicopter is flying at 32.5 m/s in the direction of W 22.6° S.

The centre of mass of the region is bounded by y=9-x^2 y=5/2x, and the z-axis is (3.5, 33/8). Formulae used to find the centre of mass are as follows:x bar = (1/M)*∫∫∫x*dV, where M is the total mass of the system y bar = (1/M)*∫∫∫y*dVwhere M is the total mass of the system z bar = (1/M)*∫∫∫z*dV, where M is the total mass of the systemThe region bounded by y=9-x^2 and y=5/2x, and the z-axis is shown in the attached figure.

The two curves intersect at (-3, 15/2) and (3, 15/2). Thus, the total mass of the region is given by M = ∫∫ρ*dA, where ρ = density. We can assume ρ = 1 since no density is given.M = ∫[5/2x, 9-x^2]∫[0, x^2+5/2x]dAy bar = (1/M)*∫∫∫y*dVTherefore,y bar = (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]y*dA= (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]ydA...[1].

The limits of integration in the above equation are from 5/2x to 9-x^2 for x and from 0 to x^2+5/2x for y.To evaluate the above integral, we need to swap the order of integration. Therefore,y bar = (1/M)*∫[0, 3]∫[5/2, (9-y)^0.5]y*dxdy...[2].

The limits of integration in the above equation are from 0 to 3 for y and from 5/2 to (9-y)^0.5 for x.Substituting the values and evaluating the integral, we get y bar = (1/M)*[(9-5/2)^2/2 - (9-(15/2))^2/2]= (1/M)*(25/2)...[3].

Also, the x coordinate of the center of mass is given by,x bar = (1/M)*∫∫∫x*dVTherefore,x bar = (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]x*dA= (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]xdA...[4].

The limits of integration in the above equation are from 5/2x to 9-x^2 for x and from 0 to x^2+5/2x for y.To evaluate the above integral, we need to swap the order of integration. Therefore, x bar = (1/M)*∫[0, 3]∫[5/2, (9-y)^0.5]xy*dxdy...[5].

The limits of integration in the above equation are from 0 to 3 for y and from 5/2 to (9-y)^0.5 for x.

Substituting the values and evaluating the integral, we get x bar = (1/M)*[63/8]= (1/M)*(63/8)...[6]Thus, the centre of mass of the region is bounded by y=9-x^2 y=5/2x, and the z-axis is (3.5, 33/8).

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Answer: power, renewable, extinct, solar, wind

Would appreciate brainliest <3

Answer:

chemical

mechanical

electrical

nuclear

thermal

brainliest ?

Answer:

2nd law of motion

Explanation:

Answer:

Newton's 2nd Law of Motion

Explanation:

The amount of force needed to make an object change its acceleration depends on the mass of the object. In other words, the amount of force thrown by a professional quarter-back has more acceleration from his mass.

The harmonics are sometimes referred to as the overtone series.

The frequencies that are capable of forming standing waves on a string attached at both ends from the fundamental frequency on up are called harmonics. In music, harmonics are overtones that accompany a sound wave's fundamental frequency.

These waves are at frequencies that are whole number multiples of the fundamental frequency (f₀).

These waves are at frequencies that are whole number multiples of the fundamental frequency (f₀).

2f₀ is twice f₀, 3f₀ is three times f₀, and so on.

These harmonics exist in a series of discrete frequencies that are proportional to the frequency of the fundamental pitch. Therefore, the harmonics are sometimes referred to as the overtone series.

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Answer:

The car moving with speed 50 mph

Explanation:

We are given that

Distance, s=280 feet=85.3 m

1 feet=0.3048 m

Coefficient of kinetic friction=\(\mu_s=0.3\)

1 m/s=2.237 mph

We have to find the speed of car moving.

Speed, v=\(\sqrt{2\mu_s gs}\)

Where \(g=9.8ms^{-2}\)

Using the formula

Speed of the car,v=\(\sqrt{2\times 0.3\times 9.8\times 85.3}\)

Speed of the car,v=22.4 m/s

Speed of the car, v=\(22.4\times 2.237\approx 50 mph\)

Hence, the car moving with speed 50 mph

Option  d is true.

Answer:

1 / f = 1 / o + 1 / i

1 / image distance + 1 / object distance = 1  focal length

If the object distance is large the image will be at about the focal length

The value of 1 / f is fixed for any one particular lense

As the object distance decreases the image must increase

The above equation can also be written as

o i / (i + o) = f    or i / (i / o + 1)  = f

If for instance o was very large the image would be at the focal length

A. The velocity of the rock after 9.4 seconds is 92.12 m/s.

B. The elevation of the rock after 9.4 seconds is 4396.72 m.

a) The velocity of the rocket at t = 20 sec is 2026 m/s to the right.

b) The velocity of the rocket at t = 80 sec is 1024 m/s to the right.

Given, Height, h = 370 meters Time, t = 9.4 seconds Acceleration, a = g = 9.8 m/s².

Formula Used:

The equations of motion for a freely falling body are,

v = u + gt (Initial velocity) u = 0m/s(initially at rest)

v² = u² + 2gh (final velocity)

h = ut + 1/2 gt².

We have to calculate the velocity and elevation of the rock after 9.4 seconds.

A) Calculation of Velocity Using the equation of motion v = u + gt where u = 0 (as the rock is dropped from rest)v = gt.

Now, putting the value of g and t, we get v = 9.8 m/s² × 9.4 s= 92.12 m/s. Therefore, the velocity of the rock after 9.4 seconds is 92.12 m/s.

B) Calculation of Elevation. Using the equation of motion

h = ut + 1/2 gt² where u = 0 (as the rock is dropped from rest)

h = 1/2 gt²

Putting the value of g and t, we get h = 1/2 × 9.8 m/s² × (9.4 s)²= 4396.72 m. Therefore, the elevation of the rock after 9.4 seconds is 4396.72 m.

Given,Initial velocity, u = 2360 m/s Deceleration, a = 16.7 m/s² Velocity at (a) t = 20 sec and

(b) t = 80 sec is to be calculated.Formula Used:

The velocity-time relationship is given by, v = u - at Where,v = final velocity u = initial velocity a = acceleration t = time elapsed.

We have to calculate the velocity at (a) t = 20 sec and (b) t = 80 sec.

a) Calculation of Velocity at t = 20 sec

Using the formula of velocity-time relationship,

v = u - at where u = 2360 m/sa = -16.7 m/s² (as the rocket is decelerating)v = ? (to be calculated)t = 20 s.

Putting the values,

we get,v = 2360 m/s - (16.7 m/s²) × 20 s= 2360 - 334= 2026 m/s.

Therefore, the velocity of the rocket at t = 20 sec is 2026 m/s to the right.

b) Calculation of Velocity at t = 80 sec.

Using the formula of velocity-time relationship,v = u - at where u = 2360 m/s a = -16.7 m/s² (as the rocket is decelerating)v = ? (to be calculated)t = 80 s.

Putting the values, we get,v = 2360 m/s - (16.7 m/s²) × 80 s= 2360 - 1336= 1024 m/s.

Therefore, the velocity of the rocket at t = 80 sec is 1024 m/s to the right.

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Answer:

Workdone = 17482.36 Joules

Explanation:

Given the following data;

Force, F = 120 N

Angle, d = 28.0°

Distance, x = 165 m

To find the work done, we would use the following formula;

Workdone = FxCosd

Substituting into the formula, we have;

Workdone = 120*165*Cos(28)

Workdone = 19800 * 0.8830

Workdone = 17482.36 Joules

The part of the microscope that the objectives are attached to is called the (C) nosepiece.

The nosepiece is a rotating mechanism located below the microscope's body tube. It holds the objectives, which are the lenses responsible for magnifying the specimen. The nosepiece typically has multiple positions, allowing the user to switch between different objective lenses for varying levels of magnification.

This convenient feature eliminates the need to manually remove and replace objectives when changing magnification. By rotating the nosepiece, different objectives can be brought into position above the specimen. This allows for quick and efficient adjustments in magnification without disrupting the viewing process.

Hence, the nosepiece plays a critical role in the microscope's functionality by providing a convenient way to switch between objectives and adjust the magnification level.

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Here is the complete question:

What is the name of the part of the microscope that the objectives are attached to? (Choose the best answer)

A. Ocular

B. Stage

C. Nosepiece

D. Arm

Answer:

  5.60 m/s

Explanation:

His initial potential energy is equal to his final kinetic energy.

  mgh = 1/2mv^2

  2gh = v^2 . . . . . . . multiply by 2/m

  v = √(2gh) = √(2(9.81 m/s²)(1.6 m)) = √(31.392 m²/s²)

  v ≈ 5.60 m/s

_____

Additional comment

The mass is irrelevant in the equations we typically use for this purpose.

The speed at which the paper clip be launched horizontally, given that the paper clip has a mass of 0.01 Kg is 5.81 m/s

We'll begin by obtaining the energy stored in the stored in rubber. This is shown below:

E = ½Ke²

E = ½ × 15× 0.15²

E = 7.5 × 0.0225

E = 0.16875 J

Finally, we shall determine the speed. Details below:

KE = ½mv²

0.16875 = ½ × 0.01 × v²

0.16875 = 0.005 × v²

Divide both side by 0.005

v² = 0.16875 / 0.005

Take the square root of both side

v = √(0.16875 / 0.005)

v = 5.81 m/s

Thus, the speed is 5.81 m/s

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Answer:

a = F/m = 4000/1500 = 2.66m/s^2

Explanation:

A tow truck pulls a mass of 1500 kg with a force of 2000 N then the acceleration of the truck will be equal to 1.33 m/s².

A force in physics is an input that has the power to change an object's motion. A mass-containing object's velocity can vary, or accelerate, as a result of a force. Intuitively, a push or a pull can also be used to describe forces.

Being such a vector quantity, a force does have magnitude and direction. The SI unit metric newton is used to measure it (N). The letter F stands for force.

According to Newton's second law's original formulation, an object's net force is equal to the speed that its momentum is changing over time.

As per the given information in the question,

Mass of car, m = 1500 kg

Force, F = 2000 N

Then, the acceleration will be,

F = m × a

a = 2000/1500

a = 1.33 m/s²

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Answer:

B. Tomatos reflect red light

Explanation:

The only reason colors exist is because the objects with color reflect all other light except for what they are portrayed as. White reflects all colors, and black absorbs all colors.

If you have any questions feel free to ask :)

Answer:

Explanation: the pigment atoms in the skin absorb photons of all energies except those that correspond to red wavelengths of light, which they reflect back to your eye.

B is more likely the answer

The required equation for the sine function can be written as; V = 120sin120πt

A sine function is a regular repeating function. We know that the voltage is represented using a sine function of the general form V= V-o sin2πft

Hence;

f = 60 cycles per second

V-o = 120 volts

So from the values that we have stated above;

V = 120sin120πt

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Answer:

A 2.5 g bullet traveling at 350 m/s hits a tree and slows uniformly to a stop while penetrating a distance of 12 cm into the tree's trunk. What is the initial kinetic energy of the bullet? 153.125 J Correct: Your answer is correct.Jan 8, 2020

Explanation:

The Lightning Component bundle framework is a UI framework for developing single page applications for mobile devices and desktop devices like for windows and laptops.

A Lightning Component bundle developed with the Aura programming model can have three JavaScript files. A created lightning component is a bundle of code. The bundle contain all that resources related which are required  to a component like java script controller, java script helper, renderer, CSS styles, etc. A basic lightning component bundle contains the design of a page with some kinds of lightning tags.

So we can conclude that: The Lightning Component bundle framework is a UI framework for developing single page applications for mobile devices and desktop devices like for windows and laptops.

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According to Law of Conservation of energy ,

One form of energy is transformed into another form of energy and there is no loss of energy in the transformation process.

The law of conservation of energy states that the energy can neither be created nor be destroyed only converted from one form of energy to the other form of energy means that the system always has the same amount of energy , unless its's added from the outside.

The only way to use energy is to transform energy from one form to another form.

example - Heat energy is transformed into Kinetic and Potential energy.

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I think its a secret!!

Answer:

uhh, uhh i think it's a carrot?

nah a secret

Explanation:

Answer:

9.26 km/h

Explanation:

Applying,

V' = D'/t'............... Equation 1

Where V' = Average speed, D' = Total distance, t' = total time.

Given: D' = 5 km

But,

v = d/t............ Equation 2

Where v = speed , d = distance, t = time

t = d/v............ Equation 3

Given: d = 4.5 km, v = 9 km/h, and d = 0.5 km, v = 12.5 km/h

Therefore,

t₁ = 4.5/9 = 0.5 hours

t₂ = 0.5/12.5

t₂ = 0.04 hours

Therefore,

V' = 5/(0.5+0.04)

V' = 5/0.54

V' = 9.26 km/h

Answer:

Nuclear energy comes from splitting atoms in a reactor to heat water into steam, turn a turbine and generate electricity. Ninety-three nuclear reactors in 28 states generate nearly 20 percent of the nation's electricity, all without carbon emissions because reactors use uranium, not fossil fuels.

Answer:

Movement

Explanation:

In its orbit around the Sun, Earth has an angular momentum of 2.661 1040 kg/m2/s.

A rotating object's property that is determined by its moment of inertia multiplied by its angular velocity is known as angular momentum. It is a characteristic of rotating bodies determined by their combined moments of inertia and angular velocities.

In the equation for angular momentum, L stands for angular momentum, I for rotational inertia, and (the Greek symbol omega) for angular velocity. This can be put more simply by saying how an entity's angular momentum is equal to the sum of its mass, speed, and separation from the point of rotation.

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The accurate title for the graph is; "A graph of distance against time" and the scale on the x axis is 2cm:1 unit while the scale on the y axis is 2cm: 5 units.

The term scale has to do with the way that we can be able to represent information on paper. It is common that the information that we are trying to depict is too large that we can not easily show the information on paper. This is why we need a graph so that it can be compressed and still be readable by all.

In this case, we are being asked to get a good title for the graph and also to suggest a scale that would be very good for us to be able to present the information and make it intelligible. We must consider the magnitude pf the data so as to do this.

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Answer:

Equivalent Resistance of Resistors in Parallel is

1/R = 1/r1 + 1/r2 .....

1/R = 1/7 + 1/7 + 1/7

R= 7/3

R=2.33ohms

how am I supposed to know

Gravity operates as the action force, pulling the book toward the table, and the normal force of the table, acting as the reaction force, pushing the book higher.

A massive object's potential energy in relation to another massive object because of gravity is known as gravitational energy or gravitational potential energy. The energy that is released when the items fall toward one another is the potential energy associated with the gravitational field.

The potential energy associated with gravitational force is known as gravitational energy because it takes effort to lift items out of the gravitational pull of the Earth. Water in an elevated reservoir or kept behind a dam is evidence of gravitational potential energy, which is the potential energy resulting from elevated locations.

The book is being pulled toward the table by gravity, which acts as the action force, and is being pushed upward by the table's normal force, which acts as the reaction force.

When an object is present in a gravitational field, it has or can acquire gravitational potential energy, which is the energy that results from a change in position. Gravitational potential energy is an energy that is connected to gravitational force or gravity, to put it simply.

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To solve this problem, we need to use the Pythagorean theorem to find the distance between the two cars.

After two hours, the car traveling south will have gone 56*2 = 112 miles, and the car traveling west will have gone 42*2 = 84 miles. If we draw a right triangle with the two cars at the vertices of the right angle, then the distance between them is the hypotenuse of the triangle. Using the Pythagorean theorem, we have:

distance^2 = 112^2 + 84^2
distance^2 = 12,544 + 7,056
distance^2 = 19,600
distance = sqrt(19,600)
distance = 140 miles

To find the rate at which the distance between the cars is increasing, we need to take the derivative of the distance equation with respect to time. Since both cars are moving at a constant speed, we can use the chain rule to get:

d(distance)/dt = (d(distance)/dx) * (dx/dt) + (d(distance)/dy) * (dy/dt)

where x is the distance traveled by the car traveling west, y is the distance traveled by the car traveling south, and t is time. Taking the derivatives, we have:

d(distance)/dx = 2x/2(distance) = x/distance
d(distance)/dy = 2y/2(distance) = y/distance
dx/dt = 42 mph
dy/dt = 56 mph

Substituting in the values we know, we get:

d(distance)/dt = (84/140) * 42 + (112/140) * 56
d(distance)/dt = 0.6 * 42 + 0.8 * 56
d(distance)/dt = 25.2 + 44.8
d(distance)/dt = 70

Therefore, the rate at which the distance between the two cars is increasing two hours later is 70 miles per hour.

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