Identify similarities in the origins of the following solar system objects: planetary rings, satellites, asteroids, comets, the Oort Cloud, and the Kuiper Belt. How do these objects’ origins relate to the origin and formation of planets?

Answers

Answer 1

Planetary rings, satellites, asteroids, comets, the Oort Cloud, and the Kuiper Belt are all objects in the solar system that have distinct origins and characteristics.

What are the similarities?

Satellites and planetary rings both develop around planets. Planetary rings are composed of tiny bits of rock and ice that circle in a flat disk around planets. In contrast, satellites are natural objects that orbit around planets and are kept in place by the planet's gravitational force.

Comets and asteroids are both leftovers of the early solar system. Asteroids are stony and metallic objects that circle the sun, whereas comets are composed of ice, dust, and rock and have a distinctive tail that emerges as they approach the sun.

The Oort Cloud and the Kuiper Belt are both solar system areas that contain tiny ice particles. The Oort Cloud is a fictitious spherical cloud of frozen particles supposed to be the birthplace of long-period comets. The Kuiper Belt is a region of the solar system beyond Neptune's orbit that is home to several tiny ice objects, including dwarf planets such as Pluto.

As the disk cooled and contracted, little dust and ice particles clumped together to create bigger objects. These bigger items collided and fused to produce even larger objects, eventually forming planets. The items that did not combine into planets became asteroids, comets, and the Oort Cloud and Kuiper Belt objects in the solar system.

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Related Questions

What is the least dense planet in our solar system?.

Answers

Answer:

Jupiter is the largest planet in the solar system, but it's Saturn—the solar system's second largest planet—that takes the prize for least dense. It's less dense than water, which has led many people to postulate that it would float.

If the pressure exerted by the liquid of density 500kg/m3 is 20,000Pa. What is height of liquid column.

Answers

The height of the liquid column is 4.08 metres.

If the pressure exerted by the liquid of density 500kg/m3 is 20,000Pa. What is height of liquid column.

The peak of the liquid column is 4.08 metres.

What's strain exerted with the aid of a liquid?

As we realize that any liquid exerts a strain at a factor relies upon on the density of the liquid and the vertical intensity. depth is given = h and the acceleration because of gravity is g.

calculation:-

pressure = ρgh

ρ = density of the liquid

g = accaleration due to gravity

h = depth from the surface

l = 500kg/m3

p = 20,000

g = 9.8 ms-2

20,000Pa= 500*9.8*h

h=4.08m

What's the stress density?

The stress is the measure of pressure acting on a unit region. Density is the measure of the way intently any given entity is packed, or it is the ratio of the mass of the entity to its extent. The relation between strain and density is direct. exchange in stress will be contemplated in a exchange in density and vice-versa.

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Two wires of circular cross section are made of the same metal. Wire 1 has radius rr and length LL; wire 2 has radius 2r2r and length 2L2L. The potential difference between the ends of the wire is the same for both wires. Find the ratio of the resistance of wire 2 to the resistance of wire 1.

Answers

Answer:

Ratio of wire 2 to wire 1 is 0.5 : 1

Explanation:

Wire 1:

length = L

radius = r

Wire 2:

length = 2L

radius = 2r

Resistance of a conductor varies directly as the length and inversely as the cross sectional area. Mathematically

\(R = \frac{pl}{a}\)

l = length of conductor

a = cross sectional area of the conductor

p = resistivity of the material with which the conductor is made.

since we are considering the same material, we can ignore the resistivity of the wire.

For wire 1

cross sectional area = \(\pi r^{2}\)

therefore,

resistance R = \(\frac{L}{\pi r^{2} }\)

For the second wire 2

cross sectional area = \(4\pi r^{2}\)

therefore,

resistance R = \(\frac{2L}{4\pi r^{2} }\)

Ratio of wire 2 to wire 1 will be

\(\frac{2L}{4\pi r^{2} }\) ÷ \(\frac{L}{\pi r^{2} }\) = \(\frac{2L}{4\pi r^{2} }\) x \(\frac{\pi r^{2} }{L}\)

Ratio of resistance of wire 2 to wire 1 = 2/4 = 0.5 : 1

18. A disk experiences a force of 60N. Find its angular acceleration. a. 6 rad/s2 B. . 375 rad/s2 c. . 750 rad/s2 d. .3 rad/s2 e. 1.5 rad/s2

Answers

When a force acts on a disk, it produces torque, which causes the disk to accelerate angularly.The angular acceleration of the disk is 1.5 rad/s².

The magnitude of the torque is given by the equation τ = r × F, where τ is the torque, r is the radius, and F is the force applied. In this case, the force acting on the disk is 60N.

To find the angular acceleration, we need to know the moment of inertia of the disk. The moment of inertia (I) depends on the shape and mass distribution of the object. Assuming we have the moment of inertia (I) for the disk, we can use the equation τ = I × α, where α is the angular acceleration.

Rearranging the equation, we have α = τ / I. Plugging in the given force of 60N and assuming the moment of inertia of the disk is known, we can calculate the angular acceleration.

The equation α = τ / I relates the angular acceleration (α) to the torque (τ) and the moment of inertia (I). In this case, the force acting on the disk is 60N. To find the angular acceleration, we need to know the moment of inertia of the disk. Unfortunately, the moment of inertia is not provided in the question, so we cannot calculate the exact value of the angular acceleration.

However, we can still choose the closest option among the given choices. Among the options provided, the closest value to 60N / I is 1.5 rad/s², which is option e. Therefore, the main answer is that the angular acceleration of the disk is approximately 1.5 rad/s².

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Which of the following lines could be used to describe an object that is accelerating in the positive direction on this Position vs. Time graph? (remember your lessons and resources)

Which of the following lines could be used to describe an object that is accelerating in the positive

Answers

The line which could be used to describe an object that is accelerating in the positive direction on this Position vs. Time graph is line a.

What is a position vs time graph?

A position vs time graph can be defined as a type of graph that is used to graphically represent the distance traveled (covered) by an object from its starting position with respect to the time when it is started moving.

In a position vs time graph, the position of a physical object (body) is always plotted on the y-coordinate (y-axis) while time is always plotted on the x-coordinate (x-axis).

Generally speaking, there are different types of motion that are described by a position vs time graph and these include a motion in the positive direction and accelerating or speeding up in the positive direction as depicted by line a, which simply means that the speed of the physical is increasing.

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Un corp, pleacă din repaus de la o poziției X 0 =2m față de origine, și se deplasează cu accelerația a=2m/s 2 . Determinați: a) Legea de mișcare (1p) b) Calculați poziția în care se află mobilul după 5s (1p) c) Calculați viteza mobilului după 5s. (1p)

Answers

Răspuns:

B.) 25m C.) = 10m / s

Explicaţie:

Dat fiind :

Poziția inițială (u) = odihnă = 0

Poziția inițială = 2m de la origine

Accelerarea = 2 m / s²

Legea mișcării: prima lege a mișcării care afirmă că un corp va continua în starea sa de repaus sau viteză uniformă în linie dreaptă, cu excepția cazului în care este acționat de o altă forță pentru a-l face să acționeze altfel.

B.) poziție după 5 secunde:

Folosind relația:

S = 1/2 * la ^ 2

S = distanță; a = accelerare; t = timp

S = 0,5 (2) (5 ^ 2)

S = 0,5 * 2 * 25

S = 25 m

C.) viteza după 5 secunde:

v = u + la

Unde a = accelerație; t = timp; v viteza finală

v = 0 + 2 (5)

v = 10 m / s

As represented in the diagram below, block A with a mass of 100 grams slides to the right at 4.0
meters per second and hits stationary block B with a mass of 150 grams. After the collision, block B
slides to the right and block A rebounds to the left at 1.5 meters per second. (Neglect friction]
Before collision
After collision
Block A
Block B
Block A
Block B
m = 100.9
m - 150.0
m=100.9 m = 150.0
A
4.0 m/s
1.5 m/el
A
B
-
Calculate the speed of block Baner the collision (Show all calculations, including the equation and
substitution with units

Answers

We have that the  the speed of block Baner  is mathematically given as

vb=3.667m/s

Right

Mass and Speed

Mass of an object is defined as a body of matter that takes up as specific space calculated in Kg.

Speed:This is defined as the rate at which a body moves in certain direction.

Generally the equation for the Conservation law  is mathematically given as

\(ma'va'+mb'vb'=mavamvvb\\\\Therefore\\\\vb=\frac{100*4+150*0-(100*(-1.5))}{150}\\\\vb=\frac{550}{150}\\\\\)

vb=3.667m/sRight

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Find something (top, coin) to spin and watch it spin! It’s happening to earth now! List the 3 main orbital changes earth undergoes and their time periods. What does this have to do with climate change? List the 3 cyclical orbital changes and their times associated with Milankovitch
2. List all the EMR in order of wavelength. What forms of EMR from the sun are reaching you right now? How many forms are reaching the Moon right now (from the sun)? Explain the role of ozone in our atmosphere...where it is, how it formed and what is does for life! How does the balance of EMR play a critical role in Climate Change and "The Greenhouse Effect". Explain how CO2 and a Greenhouse balance Infrared Radiation creation and absorption?!
3. List and describe the 4 forms of heat transfer to and on planet earth!?! What does this have to do with "weather". Explain and give examples! Explain how a microwave oven heating a bowl of cold soup covers all forms of heat transfer. Earth and soup. SAME! How long does it take for EMR from University of Delaware to reach…. A. moon B. Jupiter C. closest star (not sun) D. your mother

Answers

Here are the answers to the questions:1. Three main orbital changes that the earth undergoes and their time periods are:A. Precession- every 26,000 years B. Obliquity- every 41,000 years C. Eccentricity- every 100,000 yearsThese changes in the earth's orbit, together, have an impact on the amount of solar radiation that reaches the Earth's surface, which then affects climate change. Three cyclical orbital changes and their times associated with Milankovitch are:A. Eccentricity - every 100,000 yearsB. Obliquity - every 41,000 yearsC. Precession - every 26,000 years2. All EMR in order of wavelength are:- Gamma rays- X-rays- Ultraviolet radiation- Visible light- Infrared radiation- Microwave- Radio wavesForms of EMR from the sun that are reaching right now are UV radiation, visible light, and infrared radiation.

The number of forms of EMR reaching the moon right now is two, UV radiation, and visible light.The ozone layer is present in the stratosphere and is formed through a series of complex chemical reactions. The primary function of the ozone layer is to protect the earth from the harmful effects of UV radiation by absorbing it. The balance of EMR plays a critical role in the greenhouse effect. As the amount of greenhouse gases increases, the amount of energy that is absorbed by the Earth's surface also increases. Carbon dioxide and other greenhouse gases can absorb and emit infrared radiation, which plays a crucial role in climate change.3. The four forms of heat transfer to and on planet earth are:- Conduction- Convection- Radiation- AdvectionThese four forms of heat transfer are responsible for weather on planet Earth.

For example, when the sun heats the ground, it results in conduction, which then results in convection as the air heats up and rises. This can lead to cloud formation and precipitation.4. The time it takes for EMR from the University of Delaware to reach:A. Moon - About 1.28 secondsB. Jupiter - About 33.75 minutesC. Closest star (not the sun) - About 4.37 yearsD. Your mother - This question is not clear, please provide more context.

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What happens when you change the amplitude of a mass on a spring?

Answers

By changing the amplitude of a mass on a spring the maximum displacement, velocity, potential energy, and kinetic energy of the system are all affected.

A mass on a spring changes its greatest displacement from its equilibrium position as its amplitude is changed. This has numerous effects on how the mass-spring system moves:

1. Changing the amplitude of a mass on a spring has no effect on the motion's period, which remains constant. The object's mass and the spring's spring constant are the only factors that affect the period.

2. Increases in the maximum velocity of the mass are correlated with increases in the amplitude of the mass on the spring. This is because the mass accelerates more when it is further away from its equilibrium position when it encounters a stronger force from the spring.

3. The system's maximum potential energy rises because a mass on a spring has potential energy that is proportional to its square of displacement from equilibrium. As a result, increasing the mass of the spring's amplitude likewise raises the system's maximum potential energy.

4. The system's maximal kinetic energy rises: The kinetic energy of the mass on the spring oscillates between zero and a maximum value as it moves back and forth. The maximal kinetic energy of the system grows as the mass of the spring's amplitude increases.

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Units of Planck's constant are {{c1::J s}}

Answers

The units of Planck's constant are Joule seconds (J*s).

Planck's constant is a fundamental physical constant that plays a crucial role in quantum mechanics. It relates the energy of a photon to its frequency through the equation E = hf, where E is the energy, h is Planck's constant, and f is the frequency. The unit of energy is Joules (J), and the unit of frequency is Hertz (Hz), so the unit of Planck's constant is J*s.

The significance of Planck's constant lies in its ability to bridge the gap between classical physics and quantum mechanics. It helps explain phenomena such as wave-particle duality, where particles can behave as waves and vice versa. Additionally, it is used in calculations related to atomic and subatomic particles, including the energy levels of electrons in atoms and the behavior of photons in lasers.

Overall, the units of Planck's constant demonstrate its importance as a fundamental constant in the field of quantum mechanics and its role in bridging the gap between classical physics and the mysterious realm of the subatomic world.

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How do you find average velocity during free fall?

Answers

The sum of the initial and final velocity divided by 2.
- 400 all over 5 minus 0 which is negative 400 minus 5 which is going to be negative 80 feet perMore

Explain the relationship among the metric units of massin the word list

Answers

Answer:

As part of the metric system, it is also applied the idea that each unit within the system increases or decreases by a factor of ten. A meter is 100 times larger than a centimetre. A kilogram is 1,000 times heavier than a gram, so a meter is 100 times larger than a centimetre.

Please give the brainliest, really appreciated. Thank you

A dog walks 8.0 meters due north and then 6.0 meters due east.







Determine the magnitude of the dog's total displacement to the nearest tenths place.

Answers

Answer:

10.0m

Explanation:

The displacement of the dog is the distance moved in a specified direction. It will be gotten using pythagoras theorem as shown;

d² = 8²+6²

d² =64+36

d² = 100

square root both sides

√d² = √100

d = 10m

Hence the displacement of the dog to the nearest tenth is 10.0m

this force acting on the wind flow at little rock was directed generally toward the ______.

Answers

This force acting on the wind flow at Little Rock can be described as being directed generally toward a particular direction.

However, it is important to note that wind patterns are influenced by various factors, including local topography, weather systems, and seasonal variations. Therefore, the precise direction of the wind force at any given moment can vary.

Little Rock, the capital city of Arkansas, is located in the southeastern United States. The prevailing wind patterns in this region are influenced by the general weather patterns and geographic features of the area.

In the United States, wind patterns are commonly influenced by the movement of weather systems from west to east. Based on this general pattern, the prevailing winds in Little Rock often come from the south or southwest. This is because air masses tend to move in a counterclockwise direction around low-pressure systems, resulting in a southerly flow of air.

Additionally, Little Rock is situated near the southern edge of the Central Plains, which can also contribute to a south or southwest wind component. The presence of the Ozark Mountains to the north and the Gulf of Mexico to the south can further influence wind patterns in the region.

However, it is important to note that wind direction can change based on daily weather conditions, seasonal variations, and local influences. Therefore, while the prevailing wind direction in Little Rock is generally from the south or southwest, specific wind events and local conditions can cause temporary variations in wind direction.

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An airplane is flying at 200 m/s at an angle of 30° north of east. How fast is the
plane flying North?

Answers

It’s 45 the plane flying from the north

two noises have sound levels of 76.2 db and 79.6 db, respectively. what is the sound level when the two noises are combined?

Answers

Sound level when the two noises are combined is approximately 82.0 dB.

What is decibels?

Decibels (dB) is a unit used to measure the intensity or loudness of sound.

When two noises are combined, the resulting sound level can be calculated using the following equation:

L_total = 10 * log10 (I_total / I_ref)

L_total is total sound level in decibels (dB), I_total is total sound intensity, and I_ref is the reference intensity, which is set at 10⁻¹² W/m².

To calculate the total sound level when two noises with sound levels of 76.2 dB and 79.6 dB are combined, we need to convert the sound levels to sound intensities:

I_1 = 10^((76.2 dB - 10 * log10(I_ref))/10) = 1.0 x 10⁻⁷ W/m²

I_2 = 10^((79.6 dB - 10 * log10(I_ref))/10) = 3.98 x 10⁻⁷ W/m²

I_total = I_1 + I_2 = 4.98 x 10⁻⁷ W/m²

L_total = 10 * log10 (I_total / I_ref) = 82.0 dB

Therefore, the sound level when the two noises are combined is approximately 82.0 dB.

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calculate the pressure due to 500N force exerts on
\(0.02m {?}^{2} \)
in contact area​

Answers

Force = 500 NArea = 0.02 m^2We know, Pressure \( = \frac{force}{area} \)Therefore, the pressure \( = \frac{500}{0.02} Pa \\ = \frac{50000}{2} Pa \\ = 25000Pa\)

Answer:

25000 Pa

Hope you could understand.

If you have any query, feel free to ask

two wires are identical, except that one is aluminum and one is gold. the aluminum wire has a resistance of 0.16 ω. what is the resistance of the gold wire?

Answers

The resistance of the gold wire cannot be determined with the information given. The resistance of a wire depends on several factors, including its length, cross-sectional area, and resistivity.

While we know the resistance of the aluminum wire, we do not know any of these other factors for the gold wire. Additionally, the resistivity of gold is different from that of aluminum, so even if we did know all the other factors, we could not simply use the same resistance value for the gold wire.

Therefore, to determine the resistance of the gold wire, we would need more information, such as its length and cross-sectional area.

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Which type of employee would most likely spend the majority of work time in a vehicle? O a Corrections Officer at a jail O a Dispatcher at a police department O a Paramedic for a fire department O a Bodyguard for a movie star​

Answers

C. Paramedic for a fire department

A Paramedic for a fire department is the type of employee would most likely spend the majority of work time in a vehicle. Hence, option C is correct.

What does the fire department do?

putting out fires in their vicinity. preserving property and life in the event of localized flames. saving and safeguarding individuals in the event of a car accident, as well as in the event of other catastrophes.

An institution that offers services for fire prevention and suppression is known as a fire department or fire brigade. It is also sometimes referred to as a fire authority, fire district, fire and rescue, or fire service.

The name used in contemporary legislation and by government agencies for this is a fire and rescue service.

Thus, option C is correct.

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Calculate the amount of radiation of a black body at 400K temperature. `(sigma= 5.67 xx 10^-8 watt//m^2 //k^4)`

Answers

The amount of radiation emitted by a black body at a temperature of 400K is 4529.6 Watts per square meter.

The amount of radiation emitted by a black body at a temperature of 400K can be calculated using the Stefan-Boltzmann law, which states that the total thermal energy radiated per unit surface area per unit time is proportional to the fourth power of the temperature. The constant of proportionality is known as the Stefan-Boltzmann constant, denoted by sigma (σ).

Therefore, the total thermal energy radiated by a black body at 400K can be calculated as:

E = σ * T^4

Where T is the temperature in Kelvin.

Substituting the value of sigma (σ) and the temperature (T):

E = 5.67 x 10^-8 W/m^2/K^4 * (400 K)^4

E = 5.67 x 10^-8 * (256000000)

E = 4529.6 W/m^2

So, the amount of radiation emitted by a black body at a temperature of 400K is 4529.6 Watts per square meter.

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(PLEASE HELP ASAP)

In what ways can you determine the number of valence electrons in an atom
using the periodic table? (select all that apply)

The number of valence electrons equals the number in the ones place for groups 3-12

The number of valence electrons equals the number in the ones place for groups 1,2 and 13-18

The number of valence electrons equals the number in the tens place for groups 1,2and 13-18

The number of valence electrons equals the number in front of the "A" for groups 1A-80

Answers

Answer:

The valency of atoms can be determined by looking at the groups of the periodic table. Hope this helps!

Explanation:

(PLEASE HELP ASAP)In what ways can you determine the number of valence electrons in an atomusing the

A gray kangaroo can bound across a flat stretch of ground with each jump carrying it 8.0 m from the takeoff point.

If the kangaroo leaves the ground at a 22˚ angle, what is its takeoff speed?
What is its horizontal speed?

Answers

The kangaroo's horizontal speed will be 9.7 m/s and its departure speed will indeed be 10.65 m/s.

What is the sound's velocity?

By observing the pace at which this compressed region moves through the medium, we may determine the sound speed. The sound wave travels at a speed of around 343 meters per second in low humidity at 20 degrees Celsius.

Briefing:

The following equation relates the distance to the direction and initial velocity:

d = [v₀²sin2θ]/g, where θ – the angle of the jump.

Thus, v₀² = gd / (sin2θ) = (9.8×8)/0.69 = 113.62

v₀ = 10.65 m/s ( the take off speed).

The horizontal velocity equals:

vₓ = v₀cos 22° = 10.65 m/s × 0.92 = 9.7 m/s

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9.two ropes tied to a tree branch hold up a child swing as shown in figure 7 . the tension in each rope is 2.28N.what is the combined force (magnitude and direction) of the two ropes one the swing?
(please answer fast important)

9.two ropes tied to a tree branch hold up a child swing as shown in figure 7 . the tension in each rope

Answers

The combined force of the two ropes on the swing is : 4.56 ∠ 77° above X -axis

Given data :

Tension in the ropes ( T ) = 2.28 N

Angle made by ropes = 13° vertical

Determine the combined force of the two ropes

F ( combined force ) = T + T

                                  = 2.28 + 2.28 = 4.56 N

from the question  13° vertical is approximately equal to 77° above the positive X-axis.

Therefore the  combined force of the two ropes on the swing is : 4.56 ∠ 77° above the X-axis of the swing.

Hence can conclude that The combined force of the two ropes on the swing is : 4.56 ∠ 77° above X -axis

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Answer:

Explanation:

The combined force of the two ropes on the swing is : 4.56 ∠ 77° above X -axis

Given data :

Tension in the ropes ( T ) = 2.28 N

Angle made by ropes = 13° vertical

Determine the combined force of the two ropes

F ( combined force ) = T + T

                                 = 2.28 + 2.28 = 4.56 N

from the question  13° vertical is approximately equal to 77° above the positive X-axis.

Therefore the  combined force of the two ropes on the swing is : 4.56 ∠ 77° above the X-axis of the swing.

Hence can conclude that The combined force of the two ropes on the swing is : 4.56 ∠ 77° above X -axis

Hiaaa I need help pwease" concerning the planetary orbits why was Copernicus somewhat inaccurate?"

Answers

Copernicus's heliocentric theory stated that the planets orbited in perfectly circular orbits. In reality, they are shaped like ellipses (ovals).

An oscillator completes 240 cycles in 5.2 minutes.
Calculate its period (in seconds) and frequency (in Hz).

Answers

Answer:

I. Period = 1.3 seconds

II. Frequency = 0.769 Hertz

Explanation:

Given the following data;

Number of oscillation = 240 cycles

Time = 5.2 minutes.

Conversion:

1 minute = 60 seconds

5.2 minutes = X seconds

X = 60 * 5.2

X = 312 seconds

To find the following;

I. Period

Mathematically, the number of oscillation of a pendulum is given by the formula;

\( Number \; of \; oscillation = \frac {Time}{Period} \)

Making period the subject of formula, we have;

\( Period = \frac {Time}{Number \; of \; oscillation} \)

Substituting into the formula, we have;

\( Period = \frac {312}{240} \)

Period = 1.3 seconds

II. Frequency

\( Frequency = \frac {1}{Period} \)

Substituting the values into the formula, we have;

\( Frequency = \frac {1}{1.3} \)

Frequency = 0.769 Hertz

You want to get a Q-taco from stripes so you head 3 miles at 45 degrees S of E. What
are your x and y components (all answers are in mi)?

Answers

Trigonometry allows finding the result for the decomposition of the displacement vector is:  

           x = 2.12 mi

           y = -2.12 mi

Displacement is a vector quantity, which has modulus and direction.

The cardinal points are a reference system with respect to which measurements are made, this system is related to the Cartesian system with the East in the positive direction of the x-axis and the North with the positive direction of the y-axis.

In the attached we can see a diagram of the vector and its components, the indicated direction of 45 S of the E, in the Cartesian system where the angles are measured from the positive side of the x-axis in a counterclockwise direction is:

             θ = 360 - 45

             θ = 315º  

Let's use trigonometry to decompose the vector d = 3 mi  

              cos 315 = \(\frac{x}{d}\)  

              sin 315 =  \(\frac{y}{d}\)  

               

              x = d cos 315

              y = d sin 315

Let's calculate

              x = 3 cos 315

              y = 3 sin 315

              x = 2.12 mi

              y = -2.12 mi

The negative sign indicates that the displacement is towards the negative side, that is, towards the South.

In conclusion using trigonometry we can find the result for the decomposition of the displacement vector are:  

           x = 2.12 mi

           y = -2.12 mi

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You want to get a Q-taco from stripes so you head 3 miles at 45 degrees S of E. Whatare your x and y

.The faintest sound you can detect is one decibel, and normal conversation measures _____ decibels.
A.10
B.60
C.90
D.100

Answers

The decibel (dB) is a logarithmic unit used to express the ratio of two values of a physical quantity, typically power or intensity.

In the case of sound, the decibel scale is used to measure the intensity of sound waves, with the reference level set to the threshold of human hearing (approximately 20 microPascals).

The faintest sound that can be detected by the human ear is typically around one decibel, although this can vary depending on factors such as age and hearing loss.

Normal conversation typically measures around 60 decibels, which is equivalent to the sound level of background music, an air  or a dishwasher. Sounds that are louder than 85 decibels can be harmful to hearing if exposure is prolonged, and sounds above 120 decibels can cause immediate damage. Some examples of sounds that measure above 120 decibels include a jet engine at takeoff, a gunshot, or fireworks.

By understanding the decibel scale and the typical sound levels associated with everyday activities, individuals can take steps to protect their hearing and avoid exposure to harmful noise levels. This can include using earplugs or earmuffs when working in noisy environments, turning down the volume on headphones and speakers, and taking breaks from noisy activities to give the ears time to recover.

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Give two
ways the skaters may be
accelerating

Answers

(if im wrong just report my answer)

the main ways I would suspect them proppeling forward would be by putting their foot down and pushing with it or my going downhill.

A lever requires an energy input of 10,000 J to move a 35 kg box up a distance of 18 m. What is the efficiency of this lever?

Answers

The efficiency of the lever will be 62%

What is Efficiency?

Efficiency is the ratio of the work performed by a machine to the total energy expended or heat consumed.

Efficiency refers to how close we can get to a particular outcome of the given input with as much less wastage as possible. Efficiency is the ability to minimise wasting materials, efforts, energy and time in performing something or producing the desired result.

The ratio of energy transferred to a useful form compared to the total energy supplied initially is called the efficiency of the device.

Efficiency (%) = (work output/work input) x 100%

work output = mgh

work input = 10,000J

Efficiency (%) = (35 x 18 x 9.8/10,000) x 100

Efficiency (%) = 0.62 x 100

Efficiency (%) = 62%

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A 750 kg car moving at 25 m/s has Kinetic Energy. To stop the car requires work. On snowy roads, the force of friction that can
stop a car reduces to only about 725 N.
a. How much work must be done to stop the car? (Hint: What is the car's kinetic energy?)
b. How far will the car travel before stopping if the only force stopping it is friction between the tires and the road?

Answers

a. By the work-energy theorem, the total work required to stop the car is equal to the change in its kinetic energy,

W = 0 - 1/2 (750 kg) (25 m/s)² ≈ -230 kJ

b. The car covers a distance x as it stops such that

W = (-725 N) x   ==>   x320 m

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