Identify coordinate point c.


(0, 2)

(1, 5)

(6, 7)

(7, 3)

Answer:

Step-by-step explanation:

The function f(x) = 15x² is increasing over the interval x > 0.

To see why, we can look at the values of f(x) as x increases from left to right. We can see that when x is negative, f(x) is positive and increasing. When x is zero, f(x) reaches its minimum value of zero. And as x becomes positive, f(x) continues to increase without bound. Therefore, we can conclude that f(x) is increasing over the interval x > 0.

The function f(x) is decreasing over the interval x < 0.

To see why, we can again look at the values of f(x) as x increases from left to right. We can see that when x is negative, f(x) is positive and increasing. But as x approaches zero from the left, f(x) begins to decrease, reaching its minimum value of zero at x = 0. And as x becomes positive, f(x) continues to increase without bound. Therefore, we can conclude that f(x) is decreasing over the interval x < 0.

Step-by-step explanation:

A = 1/2h(b1 + b2)

2A = h(b1 + b2)

h(b1 + b2) = 2A

h = 2A/(b1 + b2)

1 feet per second = 0.333333 yards per second

Unit conversion is a multi-step process that involves multiplication or division by a numerical factor, selection of the correct number of significant digits, and rounding.

We know that

1 feet per second = 0.333333 yards per second

yd/s =3 ft/s

Using the above formula we can have

1 yd/s = 3ft/s

hence, 1 feet per second to yards per second = 0.333333

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The matrix A of T

a. \(A = [ 0 -1 ]\)

b. \(A = [ 0 -1 ]\)

c. \(A = [ 1/sqrt(2) 1/sqrt(2) ]\)

d. \(A = [ -1/sqrt(2) 1/sqrt(2) ]\)

To find the matrix A of the reflection transformation T in the line \(y = -x\), we can use Theorem 2.6.2 as follows:

Let e1 = [1 0] and e2 = [0 1] be the standard basis vectors of R2. Then, the images of these basis vectors under T are:

\(T(e1) = [-1 0]\) and \(T(e2) = [0 -1]\)

The matrix A of T with respect to the standard basis is:

\(A = [T(e1) T(e2)] = [ -1 0 ]\)

\([ 0 -1 ]\)

To find the matrix A of the transformation \(T(x) = -x\) for each x in R2, we can use Theorem 2.6.2 as follows:

Let e1 = [1 0] and e2 = [0 1] be the standard basis vectors of R2. Then, the images of these basis vectors under T are:

\(T(e1) = [-1 0]\) and \(T(e2) = [0 -1]\)

The matrix A of T with respect to the standard basis is:

\(A = [T(e1) T(e2)] = [ -1 0 ]\)

\([ 0 -1 ]\)

To find the matrix A, we can use Theorem 2.6.2 as follows:

Let e1 = [1 0] and e2 = [0 1] be the standard basis vectors of R2. Then, the images of these basis vectors under T are:

\(T(e1) = [1 1] / sqrt(2)\)  and \(T(e2) = [-1 1] / sqrt(2)\)

The matrix A of T with respect to the standard basis is:

\(A = [T(e1) T(e2)] = [ 1/sqrt(2) -1/sqrt(2) ]\)

\([ 1/sqrt(2) 1/sqrt(2) ]\)

d. To find the matrix A, we can use Theorem 2.6.2 as follows:

Let e1 = [1 0] and e2 = [0 1] be the standard basis vectors of R2. Then, the images of these basis vectors under T are:

\(T(e1) = [1 -1] / sqrt(2)\) and \(T(e2) = [1 1] / sqrt(2)\)

The matrix A of T with respect to the standard basis is:

\(A = [T(e1) T(e2)] = [ 1/sqrt(2) 1/sqrt(2) ]\)

\([ -1/sqrt(2) 1/sqrt(2) ]\)

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Answer:

Hai

Step-by-step explanation:

I guess it's should be the first option

The surveyor determines the angle of the triangular plot by using the inverse cosine function with a given value of cos⁻¹(0.15). The result of approximately 89° represents the approximate measure of the angle at which the surveyor stands in relation to the sides of the plot.

Among the given options for the inverse cosine values, the measure of the angle of the triangular plot at which the surveyor stands is determined by the value of cos⁻¹(0.15), which is approximately 89°.

Each result represents the measure of the angle at which the surveyor stands in relation to the sides of the triangular plot. It's important to note that these results are approximate values rounded to the nearest degree.

By using the given cosine values and applying the inverse cosine function, the surveyor can determine the approximate angle of the triangular plot.

Therefore, The approximate measure of the angle of the triangular plot at which the surveyor stands is 89°.

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Question-

A surveyor measures the lengths of the sides of a triangular plot of land. what is the measure of the angle of the triangular plot at which the surveyor stands? Approximate to the nearest degree.

cos^(-1)(0.75) ≈ 41°

cos^(-1)(0.125) ≈ 83°

cos^(-1)(0.563) ≈ 56°

cos^(-1)(0.15) ≈ 89°

Answer:

• Shanna had $10 in her piggy bank and earned $5 each week in allowance.

Step-by-step explanation:

Week 0 dollars = 10

This means Shanna had $10 her piggy bank before the week started

Week 2 dollars = 20

Her account has increased from 10 to 20 dollars in two weeks. This means she is earning

Amount earned per week = change in earnings / change in week

= 20 dollars - 10 dollars / Week 2 - week 1

= 10 dollars / 2 weeks

= 5 dollars per week

Amount earned per week = $5

Therefore,

• Shanna had $10 in her piggy bank and earned $5 each week in allowance

Answer:

option b

Step-by-step explanation:

cuz its the only one that makes sense

After considering the given data we conclude that there truth table is possible and is placed in the given figures concerning every sub question.

A truth table is a overview that projects  the truth-value of one or more compound propositions for each possible combination of truth-values of the propositions starting up the compound ones.
Every row of the table represents a possible combination of truth-values for the component propositions of the compound, and the count of rows is described by the range of possible combinations.
For instance, if the compound has just two component propositions, it comprises  four possibilities and then four rows to the table. The truth-value of the compound is projected on each row comprising the truth functional operator.
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Answer:

Roger

Step-by-step explanation:

Since he is attending more shows, he will benefit. He will save a net amount of $40

Answer:

roger

Step-by-step explanation:

If we diagonalize the matrix [3 -5; -9 0] as [6 -3; 0 -2] and raise it to the power of n, then [3 -5 -9 -12]n is given by the formula [6n(-3)n; 0 (-2)n].

The problem asks us to find a formula for the matrix [3 -5; -9 0]^n, where n is a positive integer. This formula involves powers of the eigenvalues and can be expressed using complex numbers in integers.

To do this, we first diagonalize the matrix by finding its eigenvalues and eigenvectors.

We obtain two eigenvalues λ1 = (3 + i√21)/2 and λ2 = (3 - i√21)/2, and corresponding eigenvectors v1 and v2.

Finally, we can substitute all the matrices and simplify to get the formula for [3 -5; -9 0]^n as a function of n. This formula involves powers of the eigenvalues and can be expressed using complex numbers in integers.

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Step-by-step explanation:

u need to give the full question

The derivative of y = \(x^(p/q)\) with respect to x is y' =\((p/q)x^(p/q-1)\) and this is proved with the help of power rule using  implicit differentiation

To understand the proof of the power rule using implicit differentiation, let's start by considering the equation y = x^(p/q), where p and q are integers. We want to find the derivative of y with respect to x, denoted as y'.

Step 1: Take the qth power of both sides of the equation.

By raising both sides of the equation y = \(x^(p/q)\) to the power of q, we obtain \(y^q = (x^(p/q))^q = x^p.\)

Step 2: Differentiate both sides of the equation implicitly.

To find the derivative of y with respect to x, we differentiate both sides of the equation \(y^q = x^p\) with respect to x using the rules of differentiation.

On the left-hand side, we have a composition of functions: \(y^q\). By applying the chain rule, we differentiate the outer function \(y^q\) and multiply it by the derivative of the inner function y with respect to x.

On the right-hand side, we have\(x^p\), which we can differentiate directly using the power rule.

Differentiating \(y^q\):

\(d/dx\)\((y^q)\) = \(q(y^(q-1)) * (dy/dx).\)

Differentiating \(x^p\):

\(d/dx (x^p) = px^(p-1).\)

Step 3: Solve for y'.

Setting the derivatives equal, we have \(q(y^(q-1)) * (dy/dx) = px^(p-1).\) Now, we solve for dy/dx (which is y').

Dividing both sides of the equation by \(q(y^(q-1))\), we get:

\((dy/dx) = (px^(p-1))/(q(y^(q-1))).\)

Simplifying further, we can write y' as:

\(y' = (p/q)x^(p-1).\)

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Answer:

v2=U2+2as

v2-U2=U2-U2+2as

v2-U2=2as

(v2-U2)/2a=2as/2a

v2-U2/2a=s

s=(v2-U2)/2a

Hey there! I'm happy to help!

Let's see what we have for each variable.

I = 105

P = 100

r = 0.15

Now, let's plug it in and solve for our t (time)

105=100(0.15)(t)

Swap sides so t is on the left.

100(0.15)(t)=105

Divide both sides by 100.

0.15t=1.05

Divide both sides by 0.15

t=700

So, we see that it takes 700 months to earn this amount.

Have a wonderful day and keep on learning! :D

The number of months that it took to earn this amount will be 84 months.

Simple interest is the concept that is used in many companies such as banking, finance, automobile, and so on.

I = (PRT)/100

Where P is the principal, R is the rate of interest in percentage, and T is the time.

Samuel invested money in his bank account.

He had a principal, P, of $100 in his account at the beginning of the period, which increased at a rate, R, of 0.15 per year.

At the end of the period, he had interest, I, of $105 in his account.

105 = 100 x 0.15 x t

t = 1.05 / 0.15

t = 7 years

The number of months that it took to earn this amount will be

⇒ 7 x 12

⇒ 84 months

The number of months that it took to earn this amount will be 84 months.

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To find the angle θ of the net force at time t = 6.87 s, we need to first find the x and y components of the net force, and then use the inverse tangent function to find the angle.

The x component of the net force is given by:

Fₙₑₜ,ₓ = m aₓ = (8.50 kg)(0.43 m/s² + 0.79 m/s³(6.87 s)) = 3.63 N

The y component of the net force is given by:

Fₙₑₜ,ᵧ = m aᵧ = (8.50 kg)(11.9 m/s² - 0.63 m/s³(6.87 s)) = 92.52 N

The magnitude of the net force is given by:

|Fₙₑₜ| = sqrt(Fₙₑₜ,ₓ² + Fₙₑₜ,ᵧ²) = sqrt(3.63² + 92.52²) = 92.67 N

The angle θ of the net force is given by:

θ = tan⁻¹(Fₙₑₜ,ᵧ / Fₙₑₜ,ₓ) = tan⁻¹(92.52 N / 3.63 N) = 86.5°Therefore, the angle θ of the net force at time t = 6.87 s is approximately 86.5° counter-clockwise from the +x-axis.

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Answer:

you have it correct sir

Step-by-step explanation:

Answer:

50 + 10s > 20 + 15s

Step-by-step explanation:

This is the answer because if James pays for 1 shirt from company C he would be paying $60, but if he were to pay for 1 shirt at company D he would be paying $35. So that's why its >. Anyway, the s goes on the second number because that's the price for every shirt, And the first number is by itself because its a one-time printing fee.

Based on the relationship between the temperature and altitude change, the slope is -3.6 and the y-intercept is 59. The equation of the line is y = - 3.6x + 59.

First find the slope. This can be found by the formula:

= (Y₂ - Y₁) / (x₂ - x₁)

Two points on line:

(0, 59) and (7, 33.8)

Slope is:

= (33.8 - 59) / (7 - 0)

= -3.6

The y intercept is the point the line crosses the y axis which is 59.

The formula is:

y = mx + c

Where;

m = slope

c = y intercept

So the equation is:

y = -3.6x + 59

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Answer:

28+56

Step-by-step explanation:

14(2+4)

Using the distributive property

14*2 + 14*4

28+56

84

Answer:

V = Bh = πr2h

Step-by-step explanation:

Step-by-step explanation:

PDF wont download so i cant see to tell you. sorry dont want yor points i have enough. give me some info if u can?

Answer: you have to go to tutoring

Step-by-step explanation: it not easy tho

The inverse of the function f(x) = 3log(x²) is \(f^{-1}(x) = log_{10}\frac{x}{6}\).

First to be an inverse function that function needs to one to one function, meaning every different preimage must correspond to a different image.

We can obtain the inverse of a function by switching the variables x and y with their respective positions and solving for y in terms of x.

Given, A function f(x) = 3log(x²) for x > 0.

Ley, y = 3log(x²).

y = 2×3log(x).

y = 6log(x).

log(x) = y/6.

log(x) = y/6.

\(10^{log_{10}}(x) = log_{10}\frac{y}{6}\).

\(x = log_{10}\frac{y}{6}\).

\(y = log_{10}\frac{x}{6}\)

\(f^{-1}(x) = log_{10}\frac{x}{6}\).

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Answer:

Yes they are equivalent.

Step-by-step explanation:

$12 divided by 3 is $4
$36 divided by 9 is also $4
Therefore they are equivalent.

Your welcome

Answer:

Yes!

Step-by-step explanation:

You divide 3 by 12 because that's how much they work for an hour. That means they make $36 for 9 hours.
12 ÷ 3 = 4

36 ÷ 9 = 4

They have the same answer which makes them equivalent.

Answer:

The most widely used continuous probability distribution in statistics is the normal probability distribution.

Step-by-step explanation:

The graph corresponding to a normal probability density function with a mean of μ = 50 and a standard deviation of σ = 5 is shown in Figure 3. Like all normal distribution graphs, it is a bell-shaped curve.

p = The doctor prescribed medicine

q = The patient has recovered

The doctor did not prescribe medicine:

The patient recovered:

The truth table is given by:

Answer:

A

The probability that the sample proportion is at least 0.60 is 0.0294.

Given data,

In a local university, 70% of the students live in dormitories. A random sample of 75 students is selected for a particular study The probability that the sample proportion (the proportion living in the dormitories) is at least 0.60 is,

The sample size in this case,

n = 75

The proportion of students living in dormitories p,

⇒ 70% = 0.7

Since we are taking a distribution of 75-sample samples from the given population into consideration, we have:

The mean, p = 0.7

The standard deviation, s = √p * (1 − p)/n

                                           = √0.7 * (1 − 0.7)/75

                                           = 0.0529

Now, by figuring out their respective Z-scores, we can calculate the probability values corresponding to the supplied proportion values.

The Z-score for a proportion value of 0.60;

Z₀.₆₀ = (0.6 - p)/s

        = (0.6 - 0.7)/0.0529

        = -1.890

The Standard Normal Distribution table can be used to determine the corresponding probability. Consequently, the overall likelihood value for,

Z₀.₆₀ = -1.890

P-value from Z-Table,

P(x < 0.6) = 0.029355 = 0.0294

Hence, there is a 0.0294 percent chance that the sample proportion is at least 0.60.

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