The five common acid used in industry are Hydrochloric acid, Sulfuric acid, Nitric acid, Acetic acid, and Phosphoric acid.
Here are the characteristic properties and typical uses of five common acids used in industry:
1. Hydrochloric acid: This acid is a strong mineral acid with the formula HCl. It is highly corrosive and has a pungent smell. Hydrochloric acid is used in the production of PVC, the purification of table salt, and the pickling of steel.
2. Sulfuric acid: This is a strong mineral acid with the formula H2SO4. It is highly corrosive and can cause severe burns. Sulfuric acid is used in the production of fertilizers, detergents, and dyes. It is also used in the manufacturing of lead-acid batteries.
3. Nitric acid: This is a strong mineral acid with the formula HNO3. It is highly corrosive and can be explosive in certain conditions. Nitric acid is used in the production of fertilizers, plastics, and dyes. It is also used to purify metals like gold and silver.
4. Acetic acid: This is a weak organic acid with the formula CH3COOH. It has a sharp and pungent smell and is commonly found in vinegar. Acetic acid is used in the production of textiles, plastics, and paints. It is also used in the food industry as a preservative.
5. Phosphoric acid: This is a weak mineral acid with the formula H3PO4. It is commonly used in the production of fertilizers and detergents. Phosphoric acid is also used in the food and beverage industry as a flavoring agent, and in the pharmaceutical industry as an ingredient in some medications.
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Calcium nitrate and ammonium fluoride react to form calcium fluoride, dinitrogen monoxide, and water vapor. What mass of each substance is present after 13.88 g of calcium nitrate and 14.46 g of ammonium fluoride react completely?
g calcium nitrate =
g ammonium fluoride =
g calcium fluoride =
g dinitrogen monoxide =
g water=
The mass of each substances present after 13.88 g of calcium nitrate and 14.46 g of ammonium fluoride react completely are Calcium nitrate = 0.08146 mole, Ammonium fluoride = 0.37 mole , Calcium fluoride = 6.3538 g, Dinitrogen monoxide=7.16848 g and Water= 5.86512 g
The balanced chemical reaction is given as
Ca(NO₃)₂ + 2 NH₄F → CaF₂ + 2 N₂O + 4 H₂O.
At first, we will convert the given reactant mass into moles.
Calcium nitrate : 13.36/164=0.08146 mole
Ammonium Fluoride : 13.92/37 = 0.37 mole
One mole of Ca(NO₃)₂ completely reacts with 2 moles of
Ammonium Fluoride = 2 x 0.08146 =0.16292.
mole of NH₄F reacts completely with calcium nitrate .
Ammonium Fluoride left = 0.37 - 0.16292 = 0.20708 mole
= 0.20708x 37 = 7.66 g is left.
Here, Calcium nitrate is the limiting reagent:
Therefore, amount of CaF₂ formed = 0.08146 mole × 78 = 6.3538 g.
(since one mole of Calcium nitrate gives one mole of CaF₂).
Amount of dinitrogen monoxide formed = 0.08146x2x44= 7.16848 g
Amount of water formed =0.08146x4x18= 5.86512 g.
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What mass of sucrose needs to be dissolved into water in order to prepare a 15. 0% by mass solution with a total mass of 650g? will give brainliest
To prepare the desired solution, the mass of the solute (sucrose) must be calculated based on the desired percentage concentration and the total mass of the solution.
To prepare a 15% by mass solution with a total mass of 650g, the mass of sucrose needed to be dissolved into water is 97.5 grams. This can be calculated by multiplying the total mass of the solution by the percent by mass concentration as shown below:
Mass of sucrose = 15% x 650g = 97.5g.
Therefore, 97.5g of sucrose needs to be dissolved into water to prepare a 15% by mass solution with a total mass of 650g.
To prepare a 15% by mass solution with a total mass of 650g, 97.5 grams of sucrose needs to be dissolved into water. This is determined by multiplying the total mass of the solution (650g) by the percentage by mass concentration (15%). The resulting mass of sucrose (97.5g) is then dissolved into the water to make the solution.
In conclusion, to prepare the desired solution, the mass of the solute (sucrose) must be calculated based on the desired percentage concentration and the total mass of the solution.
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3. An object that has a volume of 2500 cm³ is dropped into a vat of corn syrup. What is the buoyant force on the object? (The density of corn syrup is 1.38 g/cm³.)
Answer:3.381 X 10^(-11)
Explanation:
The formula for buoyant force is F = -Volume*density*gravitational acceleration. Convert volume and density to SI units and then apply them in the formula where gravitational acceleration is 9.8m/s^2. Done
An old refrigerator is rated at 500 W how many kilowatt hours of electric energy what does refrigerator use in 30 days assume the refrigerator is running 12 hours per day
The refrigerator would use 180 kilowatt-hours (kWh) of electric energy over the course of 30 days, assuming it runs for 12 hours each day.
To calculate the kilowatt-hours (kWh) of electric energy used by the refrigerator in 30 days, we need to multiply the power rating by the total running time.
Given:
Power rating of the refrigerator = 500 W
Running time per day = 12 hours
Number of days = 30
First, we need to convert the power rating from watts to kilowatts:
Power rating = 500 W / 1000 = 0.5 kW
Next, we calculate the total energy used in kilowatt-hours (kWh) over the 30-day period:
Energy used = Power rating × Running time × Number of days
Energy used = 0.5 kW × 12 hours/day × 30 days
Energy used = 180 kWh
Therefore, the refrigerator would use 180 kilowatt-hours (kWh) of electric energy over the course of 30 days, assuming it runs for 12 hours each day.
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Define density, and list two reasons it is important in science
Answer:
The density is the mass per unit volume of a substance.
Density is important when working out if something will float in water, and it can also be useful for calculating the mass of a specific volume of a substance.
Explanation:
270g of glucose no.of molecules
Next question: 40g of ammonium nitrate
Question 1. There are \(9.025*10^{23}\) molecules in 270g of glucose.
Question 2. There are \(3.009*10^{23}\) molecules in 40g of glucose.
Explanation:Question 1. 270g of glucose, no. of molecules.1. Find the chemical formula of glucose.Formula: \(C_{6} H_{12} O_{6}\)
2. Find the molar mass of this compound.Using the molar mass of each element, which can be found in the periodic table, we make the following calculations:
Molar mass of C: 12.011 u
Total mass of C in compound: (12.011 * 6)= 72.066
Molar mass of H: 1.008 u
Total mass of H in compound: (1.008 * 12)= 12.096
Molar mass of O: 15.999 u
Total mass of O in compound: (15.999 * 6)= 95.994
Why did we multiply the molar mass of C, H and O by 6, 12, and 6? This is because the formula contains 6, 12, and 6 atoms of each element, respectively.
Add up all masses:
72.066 + 12.096 + 95.994= 180.156 g/mole
This result means that 1 mole of glucose has a mass of 180.156 grams.
3. Calculate the number of molecules.Furthermore, 1 mole of any compound has a total of \(6.022*10^{23}\) molecules. To find the amount of molecules, find the amount of moles and then the amount of molecules. Do it in the following fashion:
180.156g -----> 1 mole
270g -----------> x
\(\frac{270*1}{180.156} =1.499\)
270 grams of glucose is the equivalent of 1.499 moles of said compound.
Now, find the number of molecules using the amount of moles calculated previously.
180.156g ----> \(6.022*10^{23}\)
270g ---------> x
\(\frac{(270*6.022*10^{23} )}{180.156} =9.025*10^{23}\)
4. Conclusion.There are \(9.025*10^{23}\) molecules in 270g of glucose.
Question 2. 40g of ammonium nitrate, no. of molecules.Repeat the same process explained previously:\(NH_{4} NO_{3}\)
N: 14.007 u
N: 14.007 u
O: (15.999 * 3)= 47.997 u
14.007 + 4.032 + 14.007 + 47.997= 80.043 g/mole
80.043g ----> \(6.022*10^{23}\)
40g -----------> x
\(x=\frac{(40*6.022*10^{23}) }{80.043} =3.009*10^{23}\)
There are \(3.009*10^{23}\) molecules in 40g of glucose.
Answer it answer it answer it
Answer:
\(\Large \boxed{\mathrm{A}}\)
Explanation:
Rust formed from iron and oxygen combining is a chemical change, because in a chemical change, the resulting substance(s) will have different properties from the substance(s) before the chemical change.
I cant comment... So is it Right?
How many grams are in 5. 0 x 10^25 atoms of sodium
A total of 1909 grams of sodium are in 5. 0 x 10²⁵ atoms of sodium
The moles of a substance are given as,
Moles = Mass/Molar mass
Molar mass of sodium is 23 g/mol. We also know that the moles are given as the number of entities divided by Avogadro number.
The atoms of sodium are 5.0 x 10²⁵. The Avogadro number is 6.02 × 10²³
Moles = Number of entity/Avogadro number
So, it should be right to write,
Mass/Molar mass = Number of entity/Avogadro number
Putting all the values,
5.0 x 10²⁵/6.02 x 10²³ = Mass/23
0.83 x 10² = Mass/23
Mass = 1909 grams.
So, 1909 grams of sodium will be contained in 5.0 x 10²⁵ atoms of sodium.
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What do these two changes have in common?
crushing a mineral into powder
picking up a paper clip with a magnet
Select all that apply.
Both are changes of state.
Both conserve mass.
Submit
Both are only physical changes.
Both are chemical changes.
The appearance and observable qualities of matter are considered to be its physical attributes. Colour, smell, taste, solubility, etc. An attribute that appears during a chemical reaction is known as a chemical property. A few examples include pH, reactivity, and flammability, etc. The correct option is B.
The chemical makeup or content of matter are not altered after a physical transformation. The internal makeup is unaffected as molecules rearrange themselves during this transformation. The chemical attribute is unaffected by a physical change.
Here both crushing a mineral into powder and picking up a paper clip with a magnet are physical changes.
Thus the correct option is B.
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What happens if you add a neutron to an atom?
Answer:
if you add or subtract a neutron from an atom it will become a new isotopes of the same element
Answer:
When you add a neutron to an atom you create a new isotope of the same element you had begun with. Neutrons do not carry an electric charge so it doesn't change the charge.
Explanation:
calculate the number of vacancies per cm3 in iron at 950oc. the energy for vacancy formation is 1.08 ev/atom, and the density and atomic weight for fe are 7.65 g/cm3 and 55.85 g/mol, respectively:
The number of vacancies will be 1.18 × 10²⁴ m⁻³.
The vacancy rate is another name for it. The vacancy rate is simple to calculate. By the total number of units in the complex, divide the number of available units. to figure out the rental housing vacancy rate economically.
Number of atoms, Na= 6.022 × 10²³ atoms/mol
Iron's density, ρFe = 7.65 g/cm³
Iron's atomic weight, AFe = 55.85 g/mol
Energy vacancy formation, Qv = 1.08 eV/atom
Boltzmann constant, K = 8.62 × 10⁻⁶ k⁻¹
Temperature, T = 850°C or, 1123 K
We know the formula,
Nv= N x\(e^{\frac{-Qv}{KT} } \\\)
Nv = ((Na xρFe)/ AFe) x \(e^{\frac{-Qv}{KT} } \\\)
Nv = 8.2486 × 10²² × \(e^{\frac{-1.08}{8.62 x 10^{-5} x 1123} } \\\)
Nv = 8.2486 × 10²² × 1.4279 × 10⁻⁵
Nv= 1.18 × 10¹⁸ cm⁻³ or,
Nv= 1.18 × 10²⁴ m⁻³
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which one of the following forces is a contact force force of gravity or force of friction
Answer:
a force of friction would be like something moving that suddenly stops because of the texture of another object while a force of gravity would be something falling and gravity pulling it down :) hope this helps
Explanation:
d)Cho biết khi làm thí nghiệm với dung dịch hóa chất nào dưới đây bóng đèn cháy sáng: dịch dạ dày, nước vôi trong, giấm ăn, nước cốt chanh, nước biển, nước đường.
Answer:
I cant help can you translate to English?
Describe the color change that would be observed in water in left hand beaker
Answer:
is there supposed to be a photo with this?
Explanation:
These two finches share a common ancestor from South America. What is the most likely way that one ancestral finch species will develop into two distinct species?
A The ancestral species was genetically engineered to become two new species
B Groups of the ancestral species became isolated and adapted to different environments.
C. Two individual birds acquired many spontaneous mutations.
D. The ancestral species mated with other species and the offspring resulted in two new species.
Answer:
The correct answer is - B. Groups of the ancestral species became isolated and adapted to different environments.
Explanation:
Two finches Warbler Finch and Woodpecker Finch are two distinct finches are finches from the Galapagos Islands. Both of these finches have a common ancestor from South America.
The most likely explanation of developing two distinct species from an ancestral finch is by bein isolated and developed or adapted according to the challenges and environmental conditions and ultimately become different species after several generations.
select the classification for the following reaction. koh(aq) + hcl(aq) → kcl(aq) + h2o(l) A.None of these choices is correct. B..acid-base C.precipitation D.combination E.redox
The reaction is : KOH + HCl ---> KCl + H₂O is double displacement reaction and it is also the neutralization reaction . So, the correct option is B) acid - base.
The reaction is given below :
KOH + HCl ---> KCl + H₂O
This reaction is the neutralization reaction as well as the double displacement reaction. The neutralization reaction is the reaction in which the acid and base react and produces the salt and the water. This is also called as the acid base reaction.
The double displacement reaction is the reaction in which the reactant ions exchange places and form the new product.
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Which of the following examples is a way to live sustainably?
Responses
Drive your car as much as possible.
Have a nice green, fertilized lawn.
Recycle and reuse materials.
Leave computer screens and light bulbs on.
The correct answer is option 3, that is, recycle and reuse materials.
Sustainable living refers to a lifestyle, which tries to minimize the society's or individual's application of the Earth's natural and personal resources. The environmental sustainability does not signify living in the absence of luxuries but rather being aware of the consumption of resources and minimizing the unnecessary waste.
Recycling and reusing the products are two basic, yet highly efficient approaches, to minimize the filling of wastes in the landfills. Recycling and reusing substances assist the community, economy, and the environment as well.
Recycling inhibits the emission of various greenhouse gases and water pollutants, supplies valuable raw materials to the industry, and saves energy. It not only boosts the economy but also benefits the surroundings.
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What is the ph of a koh solution that has [h ] = 1.87 × 10–13 m?
The pH of a KOH solution that has concentration of H⁺ ion is 1.87 × 10⁻¹³ M, is 12.73 it means given solution is basic in nature.
How do we calculate pH?pH of any solution is define as the negative logarithm of the concentration of H⁺ ion present in the solution, pH value ranges from 0 to 14.
i.e. pH = -log[H⁺]
In the question it is given that,
Concentration of H⁺ ion in the KOH solution = 1.87 × 10⁻¹³ M
pH of KOH solution = -log(1.87 × 10⁻¹³)
pH = -(-12.73)
pH = 12.73
Hence required pH is 12.73.
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PLEASE HELP ME WITH THIS QUESTION 40 POINTS RIGHT ANSWERS ONLY!! :)
What volume in liters of 1.5 m cacl2 solution can be made using 1200.0 g cacl2
sorry ..................
The molar mass of CaCl2 is 110.98 g/mol. So, 1200.0 g of CaCl2 is equal to 1200.0 / 110.98 = 10.88 moles of CaCl2.
A 1.5 M CaCl2 solution contains 1.5 moles of CaCl2 per liter of solution. So, 10.88 moles of CaCl2 can be dissolved in 10.88 / 1.5 = 7.2 liters of solution.
Therefore, 7.2 liters of 1.5 M CaCl2 solution can be made using 1200.0 g of CaCl2.
Here is the solution in equation form:
```
Molarity = moles / volume
1.5 M = 10.88 moles / volume
volume = 10.88 moles / 1.5 M
volume = 7.2 liters
```
Approximately 7.21 liters of a 1.5 M CaCl₂ solution can be made using 1200.0 g of CaCl₂.
To calculate the volume of a 1.5 M CaCl₂ solution that can be made using 1200.0 g of CaCl₂, you need to follow these steps:
Determine the molar mass of CaCl₂: Calcium (Ca) has an atomic mass of 40.08 g/mol, and chlorine (Cl) has an atomic mass of 35.45 g/mol. Since CaCl₂ consists of one calcium atom and two chlorine atoms, the molar mass of CaCl₂ is calculated as follows:
Molar mass of CaCl₂ = (1 * atomic mass of Ca) + (2 * atomic mass of Cl)
= (1 * 40.08 g/mol) + (2 * 35.45 g/mol)
= 40.08 g/mol + 70.90 g/mol
= 110.98 g/mol
Calculate the number of moles of CaCl₂: Divide the given mass of CaCl₂ (1200.0 g) by its molar mass (110.98 g/mol):
Moles of CaCl₂ = Mass of CaCl₂ / Molar mass of CaCl₂
= 1200.0 g / 110.98 g/mol
≈ 10.81 mol
Calculate the volume of the solution: The concentration of the solution is given as 1.5 M, which means there are 1.5 moles of CaCl₂ per liter of solution. You can use the following formula to calculate the volume of the solution:
Volume (in liters) = Moles of solute / Concentration
= 10.81 mol / 1.5 mol/L
≈ 7.21 L
Therefore, approximately 7.21 liters of a 1.5 M CaCl₂ solution can be made using 1200.0 g of CaCl₂.
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does anyone know how to do question nine if can you please show working out. thanks.
Answer:
A. 257600g (i.e 257.6 Kg) of CaO were produced.
B. 202400g (i.e 202.4 Kg) of CO2 were produced.
Explanation:
We'll begin by calculating the mass of CaCO3 present in 5×10² Kg of lime stone. This is illustrated below:
From the question given, the lime stone contains 92% of CaCO3.
Mass of CaCO3 = 92% x 5×10² Kg
Mass of CaCO3 = 92/100 x 5×10² Kg
Mass of CaCO3 = 460 Kg
Therefore, 460 kg of CaCO3 is present in the lime stone.
Next, we shall determine the mass of CaCO3 that was heated and the masses of CaO and CO2 produced from the balanced equation. This is illustrated below:
CaCO3(s) —> CaO(s) + CO2(g)
Molar mass of CaCO3 = 40 + 12 + (16x3) = 100g/mol
Mass of CaCO3 from the balanced equation = 1 x 100 = 100g
Molar mass of CaO = 40 + 16 = 56g
Mass of CaO from the balanced equation = 1 x 56 = 56g
Molar mass of CO2 = 12 + (2x16) = 44g/mol
Mass of CO2 from the balanced equation = 1 x 44 = 44g
Summary:
From the balanced equation above,
100g of CaCO3 were heated to produce 56g of CaO and 44g of CO2.
A. Determination of the mass of quick lime, CaO produced by heating 5×10² Kg of lime stone.
5×10² Kg of lime stone contains 460 Kg (i.e 460×10³ g) of CaCO3.
From the balanced equation above,
100g of CaCO3 were heated to produce 56g of CaO.
Therefore, 460×10³g of CaCO3 will be heated to produce = (460×10³ x 56)/100 = 257600g of CaO.
Therefore, 257600g (i.e 257.6 Kg) of CaO were produced.
B. Determination of mass of carbon dioxide, CO2 produced by heating 5×10² Kg of lime stone.
5×10² Kg of lime stone contains 460 Kg (i.e 460×10³ g) of CaCO3.
From the balanced equation above,
100g of CaCO3 were heated to produce 44g of CO2.
Therefore, Therefore, 460×10³g of CaCO3 will be heated to produce = (460×10³ x 44)/100 = 202400g of CO2.
Therefore, 202400g (i.e 202.4 Kg) of CO2 produced.
Write the nuclear equation for each of the following reactions. Refer to a periodic table.
a. the alpha decay of Radium-226
b. the beta decay of Chlorine-39
Answer:
a. 226/88Ra --> 222/86Rn + 4/2He
Explanation:
Alpha decay you lose four from the mass number and two from the Atomic number. Giving you 222 mass and 86 atomic. Radon has 222 mass and 86 atomic 222/86Rn + the four from the mass we took and the two from the atomic we took. What element has 4 mass and 2 atomic. Helium 4/2He
Wiith the parameters given and hydraulic retention time= 1d, change the question to :
1) what is the BODL concentration in the aerated lagoon?
2) what is the concentration of volatile suspended solids (Xv) in the lagoon?
1. An industry has a soluble wastewater that contains a BODL of 2,000mg/l. They wish to produce an effluent BODL of 1,000mg/l. Pilot studies showed that the appropriate kinetic parameters are: q^KbYfd=27mgBODL/mgVSSa−d=10mgBODL/l=0.2/d=0.5mgVSSa/mgBODL=0.8 The industry wants to treat the wastewater with an aerated lagoon, which can be considered a chemostat with θ=1 d. Will they likely meet the desired effluent quality if they supply adequate O2 ? Recall that the effluent BODL will be comprised of organized substrate, active cell mass, and products. About C HAPTER 7 - Lagoons how much aerator capacity is needed (in kW/1,000 m3 of tank volume), if the field oxygen transfer efficiency is 1 kgO2/kWh ?
The concentration of volatile suspended solids (Xv) in the lagoon to assess the effluent quality. However, the specific aerator capacity needed cannot be determined without additional information or equations.
To determine if the industry will likely meet the desired effluent quality, we can calculate the BODL concentration in the aerated lagoon and the concentration of volatile suspended solids (Xv) in the lagoon.
BODL concentration in the aerated lagoon:
The BODL concentration in the lagoon can be calculated using the equation:
BODL_lagoon = BODL_influent - q * Xv * θ
where BODL_influent is the initial BODL concentration (2,000 mg/l), q is the specific oxygen utilization rate (27 mgBODL/mgVSSa-d), Xv is the concentration of volatile suspended solids (to be determined), and θ is the hydraulic retention time (1 day).
Concentration of volatile suspended solids (Xv) in the lagoon:
The concentration of volatile suspended solids can be calculated using the equation:
Xv = BODL_influent / (q * θ)
where BODL_influent is the initial BODL concentration (2,000 mg/l), q is the specific oxygen utilization rate (27 mgBODL/mgVSSa-d), and θ is the hydraulic retention time (1 day).
By substituting the given values into the equations, we can calculate the BODL concentration in the lagoon and the concentration of volatile suspended solids.
Regarding the aerator capacity needed, the question asks for the amount of aerator capacity in kW/1,000 m3 of tank volume. To calculate this, we need the field oxygen transfer efficiency (1 kgO2/kWh). However, the equation or method to determine the aerator capacity based on the given information is not provided. Without additional information or equations, it is not possible to calculate the specific aerator capacity needed in this scenario.
In summary, we can calculate the BODL concentration in the aerated lagoon and the concentration of volatile suspended solids (Xv) in the lagoon to assess the effluent quality. However, the specific aerator capacity needed cannot be determined without additional information or equations.
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Which sample of matter is classified as a substance
Answer:
Elements and Compounds. Any sample of matter that has the same physical and chemical properties throughout the sample is called a substanceAny sample of matter that has the same physical and chemical properties throughout the sample.
Explanation:
Does ethanol, a polar organic molecule that can hydrogen bond, dissolve in water?
No, because they do not have similar polarities.
No, because they have similar polarities.
Yes, because they have similar polarities.
Yes, because they are both liquids.
No, because they are both liquids.
Yes, ethanol, a polar organic molecule that can hydrogen bond, can dissolve in water. This is because they have similar polarities.
Polarity refers to a property of molecules that arise as a result of the uneven sharing of electrons in a covalent bond. A molecule with a net electrical charge as a result of the presence or absence of one or more electrons is polar. Ethanol, like water, is a polar molecule that is capable of forming hydrogen bonds. This means that they have similar polarities, which makes them capable of dissolving in each other. Ethanol molecules can interact with water molecules via hydrogen bonds, resulting in their dissolution.
In summary, ethanol, a polar organic molecule that can hydrogen bond, can dissolve in water because they have similar polarities.
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i need help on this science question
Answer:
C
Explanation:
The kinetic energy of a body is the energy due to the motion of a body. It is mathematically given as;
Kinetic energy = \(\frac{1}{2}\) m v²
m is the mass of the body
v is the velocity
Now, let us find the K.E from the given choices;
Option C will have the greatest kinetic energy;
mass = 0.14kg , v = 40m/s
Kinetic energy = \(\frac{1}{2}\) x 0.14 x 40² = 112J
5. The density of silver is 10.5 g/mL while that of platinum is 21.45 g/mL. If equal masses of silver and platinum are transferred to equal volumes of water in separate graduated cylinders, which cylinder would show the greatest volume change
When equal masses of silver and platinum are transferred to equal volumes of water, the cylinder with platinum will show the greatest volume change. This is because platinum has a higher density than silver, resulting in a larger volume displacement.
To determine which cylinder would show the greatest volume change when equal masses of silver and platinum are transferred to equal volumes of water, we can compare their densities.
Density is defined as mass per unit volume. Therefore, the ratio of mass to volume can be used to compare the relative volume changes for the two substances.
Transfer the same mass (m) of silver and platinum to equal volumes of water.
For silver:
Density of silver = 10.5 g/mL
Mass of silver = m
Volume of silver = (Mass of silver) / (Density of silver) = m / 10.5
For platinum:
Density of platinum = 21.45 g/mL
Mass of platinum = m
Volume of platinum = (Mass of platinum) / (Density of platinum) = m / 21.45
Comparing the volume changes:
Volume change for silver = Volume of silver - Volume of water = (m / 10.5) - (Volume of water)
Volume change for platinum = Volume of platinum - Volume of water = (m / 21.45) - (Volume of water)
The volumes of water are equal in both cases, we can ignore them for the comparison.
Therefore, the ratio of the volume change for silver to the volume change for platinum is:
(Volume change for silver) / (Volume change for platinum) = [(m / 10.5) - (Volume of water)] / [(m / 21.45) - (Volume of water)]
Since the volume of water is the same in both cases, it cancels out from the equation.
Thus, the ratio simplifies to:
(Volume change for silver) / (Volume change for platinum) = (m / 10.5) / (m / 21.45) = (21.45 / 10.5)
Therefore, the volume change for platinum is greater than the volume change for silver, as the ratio of their densities is greater than 1.
In conclusion, when equal masses of silver and platinum are transferred to equal volumes of water, the cylinder with platinum would show the greatest volume change.
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what is the current best strategy, resulting in the greatest decline, for reducing sulfur dioxide from these industrial emission?
Cap-and-trade programs are the current best strategy, resulting in the greatest decline, in reducing sulfur dioxide from this industrial emission.
The commercial process emits huge quantities of organic compounds carbon monoxide, hydrocarbons, and chemicals into the air. A high amount of carbon dioxide is the motive for the greenhouse impact inside the air.
Greenhouse gas emissions from enterprises mainly come from burning fossil fuels for electricity, in addition to greenhouse gas emissions from certain chemical reactions important to provide items from raw materials.
Burning fossil fuels like oil, natural gas, and petroleum; chemical solvents utilized in dyeing and tanning industries, untreated gas and the liquid waste being released into the surroundings, mistaken disposal of radioactive material are a number of the primary reasons for industrial pollution.
there are many methods to reduce greenhouse gas emissions from the commercial region, such as electricity efficiency, fuel switching, blended warmth and power, use of renewable electricity, and the extra efficient use and recycling of materials.
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How does the melting points of an impure sample of a substance compare to the melting point of a pure sample of the same substance?
a) The two melting points are the same but the impure sample has a broader range.
b) The two melting points are the same but the impure sample has a sharper range.
c) The impure sample has a higher melting point.
d) The impure sample has a lower melting point with a broader range.
e) The impure sample has a lower melting point with a sharper range.
The melting points of an impure sample is a) The two melting points are the same but the impure sample has a broader range.
Impure materials generally tend to have a barely decrease melting factor than the natural substance, and a broader melting temperature range. Pure materials may be diagnosed through evaluating the melting factor located withinside the test with posted reference records of what the melting factor need to be. Impurities, even if found in small amounts, commonly decrease the melting factor and expand the melting factor range. A huge melting factor range (extra than 5°C) commonly shows that the substance is impure; a slim melting factor range (O. 5-2°C) commonly shows that the substance within reason natural.
Thus, option a is the correct choice.
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What is the formula for an ionic compound that is composed of potassium and oxygen?
Answer:
Ty for free points :)
Explanation:
As a result of the interaction of 22 g of higher oxide of the element of the main subgroup of group IV with water, 31 g of acid was formed. Set the name of an unknown chemical element.
Answer:
Carbon (C)
Explanation:
Because the element is the element of the main subgroup of group IV , it has oxidation number +4 in the oxide, and oxide formula is EO2.
reaction:
EO2 + H2O ---> H2EO3
from reaction 1 mol 1 mol 1 mol
31 g acid - 22 g oxide = 9 g water
M(H2O) = 18 g/mol
9g * 1 mol/18 g = 0.5 mol H2O
As we see from reaction molar ratios EO2 : H2O : H2EO3 = 1 : 1 : 1,
so if we have 0.5 mol H2O , we also have 0.5 mol EO2.
0.5 mol EO2 has mass 22 g.
Molar mass(EO2) = mass/ number of moles = 22 g/ 0.5 mol = 44 g/mol
Molar mass (EO2) = M(E) + 2M(O) = 44 g/mol
M(E) + 2 *16 g/mol = 44 g/mo
M(E) = 44-32 = 12 g/mol
Molar mass 12 g/ mol is molar mass of carbon.
So, element is carbon (C).