I
An arrow fired horizontally at 41 m/s travels 23 m horizontally before it hits
the ground. From what height was it fired?

Answers

Answer 1

Answer:

Height = 1.54 m

Explanation:

Given:

Velocity = 41 m/s

Distance = 23 m

Find:

Height

Computation:

We know that

a = 9.8 m/s²

Time = Distance / Velocity

Time = 23 / 41

Time = 0.56 second

Height = (1/2)(9.8)(0.56)²

Height = 1.54 m


Related Questions

A car starts from rest and accelerates at a constant rate in a straight line. In the first second the car moves a distance of 2.0 meters. How much additional distance will the car move during the second second of its motion?

Answers

Since the car is accelerating at a constant rate, the distance it travels during each second of its motion will be directly proportional to the time it has been accelerating.

In the first second, the car moved a distance of 2 meters, and in the second second, it will move twice the distance of the first second, so the car will move additional distance of 2*2 = 4 meters during the second second of its motion.

The distance traveled during the second second of its motion is 1/2 * 2 = 1 meters.

A car that accelerates at a constant rate will move a distance equal to the initial velocity multiplied by time plus 1/2 the acceleration multiplied by the square of time. Since the car starts from rest, the initial velocity is zero.

Therefore, the distance traveled during the second second is 1/2 * acceleration \(* (time)^2 = 1/2 * a * t^2 = 1/2 * a * 1^2 = 1/2 * a\) Since the car moved 2.0 meters in the first second, it means the acceleration is\(2m/s^2\), and the distance traveled during the second second is 1/2 * 2 = 1 meters.

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580 nm light shines on a double slit with d = 0.000125 m. What is the angle of the first bright interference maximum (m=1)?

PLS ANSWER

Answers

The angle of the first bright interference maximum (m=1) can be calculated using the equation: θ = sin-1(mλ/d).

What is equation ?

An equation is a mathematical expression that uses symbols to describe a relationship between two or more variables. Equations are typically used to express relationships between physical quantities, such as forces and masses, or distances and times. They are also used to describe chemical reactions and other phenomena. Equations can be used to solve for unknown values, or to describe patterns or trends in data. Equations are typically written using algebraic notation, which includes variables, constants, and operators.

Substituting the given values, we get,θ = sin-1(1(580 × 10-9m)/(0.000125m)),θ = 0.00463 radians or 0.2637° .

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Engineers work to solve problems. true or false ?

Answers

Answer:

True

Explanation:

They just do!

Good Luck!

Hope this helps!

Tameika makes a table about sensory organs

Eye
skin
brain
tongue
Which organ should be removed from the table?
A. eye
B. skin
C. brain
D. tongue

Answers

Answer:

I think its d

Explanation:

I'm not sure I'm sorry if I'm wrong

A small car of mass 1200 kg traveling east at 60m/s collides at an intersection with a truck of mass 3000 kg that is traveling due north at 40 m/s. The two vehicles are locked together. What is the velocity of the combined wreckage

Answers

v2f= 2⋅m1 (m2+m1) v1i + (m2−m1)(m2+m1) v2i v 2

meaning that

2 x 1200 ( 3000 + 1200) 60 + (3000-1200)(3000+1200) 40f =

2400 (4200) 60 + (1800) (4200) 40f =

10080000 (60) +  75600000 (40)

604800000 + 3024000000

3628800000? this is what i got

f = 2 ⋅ m 1 ( m 2 + m 1 ) v 1 i + ( m 2 − m 1 ) ( m 2 + m 1 ) v 2 i

The velocity of the combined wreckage is equal to 52.86 m/s.

What is law of conservation of linear momentum?

According to the law of conservation of linear momentum, the sum of the momentum of the two objects before and after the collision will be equal.

\(m_1 u_1 +m_2 u_2 =m_1 v_1 + m_2v_2\)

Where m₁ and m₂ is the mass of the objects which are collided, u₁, u₂, v₁ & v₂ is the initial and final velocity.

Linear momentum can be defined as the product of the mass times the velocity of that object.

Given, the initial velocity of the small car is u₁ = 60 m/s

The initial velocity of the truck is u₂ = 40 m/s.

The mass of the car, m₁ = 1200Kg and mass of the truck, m₂ = 3000 Kg

From the law of conservation of momentum, find the velocity of the combined wreckage (v),

m₁ u₁ +  m₂ u₂ =  m₁ v₁ + m₂v₂

1200 × 60 + 3000 ×50 = (1200 + 3000) × v

72000 + 150000 = 4200 × v

v = 52.85 m/s

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A particle performs simple harmonic motion with period Pi/2 seconds and amplitude 12 m. What is the maximum velocity (in m/s)?

Answers

The maximum velocity is 48π m/s.

To solve this problem

The equation: can be used to determine the maximum velocity of a particle in simple harmonic motion.

Vmax = ω * A

Where

Vmax is the maximum velocityω (omega) is the angular frequencyA is the amplitude of the motion

The following formula can be used to get the angular frequency:

ω = 2π / T

Where

T is the motion's period.

Given that the period is π/2 seconds (T = π/2) and the amplitude is 12 m (A = 12), we can find the angular frequency:

ω = 2π / (π/2) = 4π rad/s

Now we can calculate the maximum velocity:

Vmax = ω * A = (4π rad/s) * (12 m) = 48π m/s

Therefore, the maximum velocity is 48π m/s.

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Why do steam burns more than boiling water

Answers

Answer:

The energy required for water to go from a liquid to a gas is called the heat of vaporization. ... This energy release causes a much worse burn than if the same amount of boiling water were to hit your skin where it would decrease in temperature (to your skin's temperature) but would not have to go through a phase change.

Answer:

fewer nutrients lost, retains vegetable color

Explanation:

Multiple Answers For Edmentum

What is the value of the universal gas constant (R) in Sl units?

Answers

3144598 J K - 1 m o l - 1

Jack drops off 10m high red bridge into swimming waters below. Assuming acceleration to be 9.91 m/s^2

A. What Jack speed as he hits the water?

Answers

Jack speed as he hits the water is 14.13m/s

What is speed?
The speed of an object, also known as v in kinematics, is the size of the change in that object's position over time or the size of the change in that object's position per unit of time, making it a scalar quantity. The instantaneous speed is the upper limit of the average speed as the duration of the time interval approaches zero. The average speed of an item in a period of time is equal to the distance travelled by the object divided by the duration of the period. Velocity and speed are not the same thing.

The only force on Jack is gravity, which points straight down, and has an acceleration of 9.91m/s².  Whether he's falling off a bridge or simply standing still on the surface of the earth, the acceleration due to gravity is the same.

If you're looking for the speed of Jack as he hits the water, you just need to solve for v in the equation\($v^2 = v_0^2 + 2ad$\).  
Here,
v is Jack's speed as he hits the water,
\($v_0$\) is Jack's initial speed (which is zero since he's not moving when he jumps),
a is Jack's acceleration (which is 9.91m/s²), and
d is Jack's displacement (which is the height of the bridge, which you said is 10m).  
This gives you an answer of \($v = \sqrt{2ad} = \sqrt{2(9.91)(10)} = 14.13 \ \mathrm{m/s}$\)

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For this assignment, you should mathematically solve and record a video testing your solution for the following prompt: Two rolls of toilet paper, of equal mass and radius, are dropped from different heights so that they hit the ground at the same time. One roll of toilet paper is dropped normally while the other is dropped while a person holds onto a sheet of toilet paper such that the roll unravels as it descends. Determine the ratio of heights h1/h2, where h1 represents the height of the toilet paper dropped normally and h2 represents the height of the toilet paper that unravels, so that both rolls hit the ground at the same time.

Answers

Answer:

h1/h2 = \(\frac{2R^2}{3R^2 + h^2}\)

Explanation:

Using two rolls of tissue paper : One roll dropped normally while the other drops as some holds onto a sheet of the toilet paper ( I.e. the tissue paper drops rotating about its axis )

Determine the ratio of heights  h1/h2

mass of tissues = same

radius of tissues = same

h1 = height of tissue 1

h2 = height of tissue 2

For the first tissue ( Tissue that dropped manually )

potential energy = kinetic energy

mgh = 1/2 mv^2  

therefore the final velocity ( v^2 ) = 2gH  ----- ( 1 )

second tissue ( Tissue that dropped while rotating )

gh = \(\frac{v^2}{u}\) ( 3 + \(\frac{u^2}{R^2}\) ) ------ ( 2 )

To determine the ratio of heights we will equate equations 1 and 2

hence :

gh = \(\frac{2gH}{u}\) ( 3 + \(\frac{u^2}{R^2}\) )

∴ h1/h2 = \(\frac{2R^2}{3R^2 + h^2}\)

Select the correct answer.
Which person is vulnerable to identity theft?
A.
Beverley opens a line of credit to purchase a household appliance.
B.
Deborah fills out her income tax form and includes her Social Security number.
C. Josiah misses three monthly car loan payments in a row.
D.
Randell uses a computer at a public library to view his bank account online.
Reset
Next​

Answers

Answer:

d

Explanation:

Randell uses a computer at a public library to view his bank account online represents one of the cases when a when person is vulnerable to identity theft, therefore the correct answer is option D.

What is identity theft?

Identity theft occurs when criminals steal your confidential info and use it to create fresh accounts, rent or purchase property, file false financial records, or carry out other illegal activities.

This implies that a thief may steal sensitive data such as names, birthdates, Social Security numbers, information from driver's licenses, residences, and credit card or bank account numbers.

Once they have this information, they may use it to buy goods, apply for credit and debit cards, or even utilize it to pay for medical care with the assistance of health coverage.

Thus,the correct answer is option D.

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8) a 20kg box is sliding across the ground. If the coefficient of friction is 0.5, how much friction will the box experience?

A 490 N
B 19.6 N
C 98 N
D 2 N

Answers

Answer:

STOP CHETING

Answer:

C is the answer to your question

Explanation:

Have a great day!!! :)

a ball hits the wall and reverses courses. According to newtons 3rd law which of these must be true

Answers

The ball exerts a force on the wall, and the wall exerts an equal and opposite force on the ball. So, the correct answer is A.

Newton's 3rd law of motion states that for every action, there is an equal and opposite reaction. The action is the force that the ball exerts on the wall, and the reaction is the force that the wall exerts back on the ball. When the ball hits the wall, it exerts a force on the wall. This force is equal in magnitude but opposite in direction to the force that the wall exerts back on the ball. This is why the ball reverses course. Therefore, option A is correct.

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--The complete Question is, Which of the following statements is true according to Newton's 3rd law when a ball hits a wall and reverses course?

A) The ball exerts a force on the wall, and the wall exerts an equal and opposite force on the ball.

B) The ball exerts a force on the wall, but the wall does not exert a force on the ball.

C) The wall exerts a force on the ball, but the ball does not exert a force on the wall.

D) The ball and the wall do not exert any forces on each other. --

A 3.0 kg block is pushed 1.0 m at a constant
velocity up a vertical wall by a constant force
applied at an angle of 26.0
◦ with the horizontal, as shown in the figure.
The acceleration of gravity is 9.81 m/s
2
Drawing not to scale.
If the coefficient of kinetic friction between
the block and the wall is 0.20, find
a) the work done by the force on the block.
Answer in units of J.
b) the work done by gravity on the block.
Answer in units of J.
c) the magnitude of the normal force between
the block and the wall.
Answer in units of N.

A 3.0 kg block is pushed 1.0 m at a constantvelocity up a vertical wall by a constant forceapplied at

Answers

(a) The work done by the applied force is 32.6 J.

(b) The work done by gravity on the block is 29.4 J.

(c) The magnitude of the normal force is 29.4 N.

What is the force applied to the block?

The force applied to the block is determined by applying the formula for the net force on the block.

F(net) = 0

Fcosθ - mg - Fsinθμ = 0

Fcosθ - Fsinθμ = mg

F(cosθ - sinθμ) = mg

F = (mg) / (cosθ - sinθμ)

F = (3 x 9.8) / (cos26  -  0.2 x sin26)

F = 36.25 N

The work done by the applied force is calculated as;

W = Fd cosθ

W = (36.25 x 1) x cos(26)

W = 32.6 J

The work done by gravity on the block is calculated as follows;

W = mgd

W = 3 x 9.8 x 1

W = 29.4 J

The magnitude of the normal force is calculated as follows;

N = mg

N = 3 x 9.8

N = 29.4 N

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When a skater pulls her arms in, it
reduces her moment of inertia from
2.12 kg m² to 0.699 kg-m². If she was
initially spinning 3.25 rad/s, what is
her final angular velocity?

Answers

The skater's final angular velocity is approximately 9.86 rad/s.

The skater's final angular velocity can be calculated using the principle of conservation of angular momentum. The equation for angular momentum is given by:

L = Iω

where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity.

Initially, the skater has an angular momentum of:

L_initial = I_initial * ω_initial

Substituting the given values:

L_initial = 2.12 kg m² * 3.25 rad/s

The skater's final angular momentum remains the same, as angular momentum is conserved:

L_final = L_initial

The final moment of inertia is given as 0.699 kg m². Therefore, the final angular velocity can be calculated as:

L_final = I_final * ω_final

0.699 kg m² * ω_final = 2.12 kg m² * 3.25 rad/s

Solving for ω_final:

ω_final = (2.12 kg m² * 3.25 rad/s) / 0.699 kg m²

Hence, the skater's final angular velocity is approximately 9.86 rad/s.

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please help me out with this​

please help me out with this

Answers

The current flowing through the 1Ω resistor in the circuit is 0.66 A.

The emf of the cells, V = 1.1 V

Internal resistance of the cells, r = Ω

Resistance across the circuit, R = 1 Ω

According to Kirchhoff's current law, the total current flowing into and out of a junction in an electrical circuit is equal.

According to Kirchoff's current law,

(1.1 - V'/2) + (1.1 - V'/2) + (1.1 - V'/2) = V'/1

3/2(1.1 - V') = V'

3.3 - 3V' = 2V'

5V' = 3.3

Therefore, the terminal velocity of the battery is,

V' = 3.3/5

V' = 0.66 V

Therefore, according to Ohm's law, the current flowing through the 1Ω resistor is given by,

I = V'/R

I = 0.66/1

I = 0.66 A

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Give an example of how a bicycle rider would accelerate? Explain the three different ways a bicyclist could
accelerate.

Answers

A cyclist can increase the speed of their bike in various ways such as, changing gears, positioning themselves properly, increase the pedalling rate

Ways in which a cyclist can increase the speed of a bicycle

Bicycle riders could accelerate/ increase their speed in various ways

By Changing the gears and by doing so increasing the speedBy Positioning themselves in a streamlined manner, this is so that they become aerodynamic hence they cut across airflow.By increase the rate at which they are pedalling the bicycle.

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A box of mass 210 kg is pulled from rest with a string of tension 1300n inclined at 35° to the horizontal. if the box moved with a speed of 10m/s and frictional force between the box and surface is 100 n, calculate the distance covered.

Answers

If A box of mass 210 kg is pulled from rest with a string of tension 1300n inclined at 35° to the horizontal. if the box moved with a speed of 10m/s and the frictional force between the box and surface is 100 n, Then the distance covered by the box is 10.89 meters.

To calculate the distance covered by the box, we need to analyze the forces acting on it and apply the work-energy principle.

Given:

Mass of the box, m = 210 kg

Tension in the string, T = 1300 N

The angle of inclination, θ = 35°

Frictional force, f = 100 N

Initial speed, u = 0 m/s

Final speed, v = 10 m/s

First, let's resolve the tension force into components parallel and perpendicular to the incline. The parallel component of the tension force can be calculated as:

T_parallel = T * cos(θ)

Next, let's calculate the net force acting on the box along the incline. The net force is given by:

Net force = T_parallel - f

Now, using Newton's second law, we can calculate the acceleration (a) of the box:

Net force = m * a

From the given information, we have the final velocity (v), initial velocity (u), and acceleration (a). We can use the following kinematic equation to calculate the distance covered (s):

v^2 = u^2 + 2as

Rearranging the equation, we get:

s = (v^2 - u^2) / (2a)

Now, let's plug in the given values and calculate the distance covered:

T_parallel = 1300 N * cos(35°) ≈ 1067.35 N

Net force = 1067.35 N - 100 N = 967.35 N

a = (967.35 N) / (210 kg) ≈ 4.61 m/s^2

s = (10 m/s)^2 - (0 m/s)^2 / (2 * 4.61 m/s^2) ≈ 10.89 m

Therefore, the distance covered by the box is approximately 10.89 meters.

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In empty space, which quantity is always larger for X-ray radiation than for a radio wave?
a) amplitude
b) wavelength
c) frequency
d) speed.

Answers

Answer:

C

Explanation:

Help pleaseeeee!
If a force of 12 N is applied to a 4.0 kg object, what acceleration is produced?

Answers

Answer:

The answer is 3 m/s²

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

\(a = \frac{f}{m} \\ \)

where

f is the force

m is the mass

From the question we have

\(a = \frac{12}{4} \\ \)

We have the final answer as

3 m/s²

Hope this helps you

If a wave has a frequency of say 10 Hz, that means something is oscillating times per second. What is this property that is oscillating for light, described by its frequency?

Answers

The property that is oscillating would be the electric and magnetic fields.

Oscillating properties of light

For light, the property that is oscillating or vibrating at a particular frequency is the electric and magnetic fields.

Light is an electromagnetic wave, which means that it consists of oscillating electric and magnetic fields that are perpendicular to each other and to the direction of wave propagation.

The frequency of the wave corresponds to the number of complete oscillations of the electric and magnetic fields that occur per second, and is measured in hertz (Hz).

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The highness or lowness of a sound is perceived as
a.
compression.
c.
ultrasound.
b.
wavelength.
d.
pitch.

Answers

Answer:

i think its D

Explanation:

Answer:

The highness or lowness of a sound is perceived as pitch. Pitch is a perceptual property of sound that allows us to distinguish between sounds that have the same loudness and duration, but differ in their frequency content. The pitch of a sound is determined by the frequency of the sound wave, with higher frequencies producing higher pitches and lower frequencies producing lower pitches. The pitch is what makes a sound distinguishable and is important in music, language, and communication.

the angular displacement of a rotating object is measured in ____What is the Answer

Answers

Usually, to measure distances, we use the unit "meter".

But since in this case we have an angular distance, the most common unit used in this case is radian.

When measuring the angular displacement, we can imagine a movement on a circle, so it goes from 0 radians to 2π radians:

Another option is using "degree". 2π radians is equivalent to 360 degrees (360°).

the angular displacement of a rotating object is measured in ____What is the Answer

A tennis ball and a bag filled with sand have the same mass. They are dropped from the same height and they hit the ground. The bag of sand stays on the ground, while the tennis ball rebounds. Which experiences the larger impulse from the ground?

Answers

Answer:

The bag of sand

Explanation:

I think it is the bag of sand because according to the definition of impulse, impulse is the average force acting on a particule when an external force is being acted on it.

How does something(the big bang) come from nothing by nothing i mean the first universe although we don't know where the first universe is but we do know that nothing can't come from something.

Answers

The Big Bang theory is the most widely accepted explanation for the origins of the universe, but it does not necessarily imply that the universe emerged from nothing.

It is possible that new discoveries or insights may shed light on this fundamental question in the future. The universe may have arisen from a pre-existing state or through some other natural process that we do not yet understand.

Instead, the theory describes how the universe underwent a rapid expansion from a very dense and hot state. The conditions and laws of physics that applied during the earliest moments of the universe may not necessarily be the same as those we observe today, and there are many unknowns and uncertainties in our understanding of these early stages.

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1. If the distance between the center of the fifth compression and the center of the ninth compression of a longitudinal wave is 4m, then the wavelength of this wave is
a. 9 m. b. 1.2 m. c. 1.5 m. d.)1 m.​

Answers

The wavelength of this wave is 1 meter (option d).

To determine the wavelength of a longitudinal wave, we need to find the distance between two consecutive compressions or rarefactions. In this case, the distance between the center of the fifth compression and the center of the ninth compression is given as 4 meters. Since there are four compressions between the fifth and ninth compression, the total distance covered by these four compressions is 4 meters. Therefore, the average distance between consecutive compressions is 4 meters divided by 4, which is 1 meter. The wavelength of a longitudinal wave is the distance between two consecutive points with the same phase, which, in this case, is the distance between consecutive compressions. It is important to note that the number of compressions or rarefactions does not directly affect the wavelength. The wavelength is determined by the distance between consecutive points with the same phase. In this case, the given information allows us to calculate the average distance between consecutive compressions, giving us the wavelength of the wave. (option d).

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400 kg cart with rubber wheel just stopped in a while asphalt road because it ran out of gas attractive attaches a route to the golf cart to tow it in Post Achurr down the road accelerating the golf cart at three Emperor a Square what is the tension in the rope

Answers

To solve this problem, we will use Newton's second law of motion.

Newton's second law states that the force is equal to mass times acceleration.

Hence, the formula is as follows:Force = mass x acceleration

To calculate the force, we need to know the mass of the cart and the acceleration at which it is being towed.

As per the question, the cart's mass is 400 kg, and it is being accelerated at a rate of 3 m/s^2.

Hence, the force required to accelerate the cart can be calculated as follows:

Force = mass x acceleration \(Force = 400 kg\times3 m/s^2\)

\(Force = 1200 N\)

Therefore, the tension in the rope is 1200 N.

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the set of all vectors which are scalar multiple of a nonzero vector u is a line through u and 0. a column vector in r2 is a 1 x 2 matrix. the operation of vector addition is not commutative. the magnitude of a vector cv is c times the magnitude of v, where c is any scalar. none of the choices is correct.

Answers

The set of all vectors which are scalar multiples of a nonzero vector u is a line through u and 0. a column vector in r₂ is a 1 x 2 matrix. The magnitude of a vector cv is c times the magnitude of v, where c is any scalar. The correct option is Option C.

Vector multiplication may refer to one of several products between two (or more) vectors. Multiplication of vectors is of two types. A vector has both magnitude and direction and based on this the two ways of multiplication of vectors are the dot product of two vectors and the cross product of two vectors. Dot product or "scalar product", is a binary product that takes place with two vectors and returns a scalar quantity. The dot product of two vectors can be defined as the product of the magnitudes of the two vectors and the cosine of the angle between the two vectors. Thus, A ⋅ B = |A| |B| cos θ

Cross product, or the "vector product", is a binary product on two vectors that results in another vector. So, if n is the unit vector perpendicular to the plane determined by vectors A and B,

A × B = |A| |B| sin θ n

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17. Which one of the following temperatures is equal to 5°C?
OA. 278K
ОВ.0К
OC. 418
0D.465K

Answers

Answer:

A. 278K

Explanation:

I look it up it and I used a conversion chart

Please help me with this
10 points
all i have rn :/
thanks <3

Please help me with this10 points all i have rn :/thanks &lt;3

Answers

Answer: c the last one

Explanation:

C because the Sun is a star which always stays in place unlike earth it’s a planet so it’s consistent move
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