i need some help plsss asap

The proportion of average city temperatures higher than that of Cairo is 0.1977 or 19.77%.

To solve this problem, we need to standardize the temperature of Cairo to a z-score and then find the proportion of temperature in the normal distribution that is above this z-score.

The z-score of Cairo's temperature can be calculated as : z = (X - μ) / σ, where X is the temperature of Cairo, μ  is the mean temperature of the normal distribution, and σ is the standard deviation of the normal distribution.Substituting the given values, we get :

z = (21.4 - 19.7) / 2 = 0.85, this means that Cairo's temperature is 0.85 standard deviations above the mean of the normal distribution.To find the proportion of temperature in the normal distribution that is higher than cairo's temperature, we need to find the area under the normal curve to the right of the z-score of 0.85

Using a standard normal table we can look up the area corresponding to a z-score of 0.85 in the right-hand column of the table which is 0.1977. This means that approximately 19.77% of the temperature in the norma; distribution is higher than Cairo's temperature.

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The required sample size to construct a 95% confidence interval to estimate the proportion is 602 students.

a. To estimate the sample size needed to construct a 95% confidence interval with a maximum error of 2.5% when the past few years' graduation rate is 70%, we can use the following formula:

n = [Z² × p × (1-p)] / E²

where:

Z = the Z-value for the desired confidence level (95% in this case), which is 1.96

p = the estimated proportion of students who graduate in 4 years (70%)

E = the maximum error, which is 0.025 (2.5%)

Plugging in the values, we get:

n = [(1.96)² × 0.7 × (1-0.7)] / 0.025²

n = 381.16

Always round up to the next integer, so the sample size needed is 382.

b. To estimate the sample size needed when there is no knowledge of the typical graduation rate, we can use a conservative estimate of 50% for p. Plugging in the values, we get:

n = [1.96² × 0.5 × (1-0.5)] / 0.025²

n = 601.64

Always round up to the next integer, so the sample size needed is 602.

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It is most important to have a random sample in inferential statistics, particularly in making statistical inferences about a population based on the sample data.

Random sampling is a critical component of inferential statistics because it helps to ensure that the sample is representative of the population. When a sample is randomly selected, each member of the population has an equal chance of being included in the sample, which reduces the risk of bias in the results. Without a random sample, the results of statistical analyses may not be accurate or generalizable to the population, and the conclusions drawn from the data may be flawed or misleading.

Therefore, random sampling is crucial in making valid statistical inferences about a population.

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The equation that is equivalent is

-x/4 + 3/4 = 12

Option D is the correct a nswer.

An equation is a mathematical statement that is made up of two expressions connected by an equal sign.

We have,

The equation for Negative one-fourth (x) + three-fourths = 12 is,

(-1/4)x + (3/4) = 12 _____(1)

Now,

-4x + 3/4 = 12

This is not equivalent to (1).

-1(x/4) + 3/4 = 12

This is not equivalent to (1).

-x + 3/4 = 12

This is not equivalent to (1).

1/4 (x + 3) = 12

(1/4)x + 3/4 = 12

This is not equivalent to (1).

-x/4 + 3/4 = 12

This is equivalent to (1).

Thus,

The equation that is equivalent is

-x/4 + 3/4 = 12

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Answer:

The equation can't use any number that isn't 2 and the answer can only have 4 twos. They have to have a combination of addition, subtraction, multiplication, and division. Not all of them have to be used though.

Step-by-step explanation:

The Values of (a+b)ab are undefined.

Given that, a = 3an and db = -2We need to find the values of (a+b)

Now, we have a = 3an... equation (1)Also, we have db = -2... equation (2)From equation (1), we get: n = 1/3... equation (3)Putting equation (3) in equation (1), we get: a = a/3a = 3... equation (4)Now, putting equation (4) in equation (1), we get: a = 3an... 3 = 3(1/3)n = 1

From equation (2), we have: db = -2=> d = -2/b... equation (5)Multiplying equation (1) and equation (2), we get: a*db = 3an * -2=> ab = -6n... equation (6)Putting values of n and a in equation (6), we get: ab = -6*1=> ab = -6... equation (7)Now, we need to find the value of (a+b).For this, we add equations (1) and (5),

we get a + d = 3an - 2/b=> a + (-2/b) = 3a(1) - 2/b=> a - 3a + 2/b = -2/b=> -2a + 2/b = -2/b=> -2a = 0=> a = 0From equation (1), we have a = 3an=> 0 = 3(1/3)n=> n = 0

Therefore, from equation (5), we have:d = -2/b=> 0 = -2/b=> b = ∞Now, we know that (a+b)ab = (0+∞)(0*∞) = undefined

Therefore, the values of (a+b)ab are undefined.

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Answer and Step-by-step explanation:

We want to prove that 0.5555... = 5/9.

First, let's set 0.555... equal to x:

x = 0.555...

Now multiply this by 10:

10x = 5.555...

Now subtract the original from this new one:

   10x = 5.555...

-       x = 0.555...

______________

     9x = 5

Note that we could cancel all the recurring terms because they were the same for both 5.555... and 0.555... since the 5's go up to infinity.

We now have 9x = 5, so divide both sides by 9:

x = 5/9, as desired

Answer:

A, B, D, E, F

Step-by-step explanation:

the perimeter of the triangle=14.38

The coordinates of the triangle (4,1),(2,5),(1,-1);

In geometry, the perimeter of a shape is defined as the total length of its boundary.

The perimeter of the triangle is the sum of all the sides of the triangle =a+b+c (assuming a,b, and c are the sides of the triangle)

By using the distances formula find the length of the sides of the triangle:√[(x₂ - x₁)² + (y₂ - y₁)²],

where (x₁,y₁),(x₂,y₂) are the coordinates ,

a=√[(4 - 2)² + (1- 5)²] = \(\sqrt 20\)=4.7

b=√[(2 -1)² + (5 -(-1))²]=\(\sqrt37\)=6.08

c=√[(1 -4)² + ((-1)-1)²]=\(\sqrt13\)=3.60

the perimeter of the triangle=a+b+c=4.7+6.08+3.60=14.38

hence ,perimeter of the triangle=14.38

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Step-by-step explanation:

2(3 X -4)= x+ 2

2 X -12 = x + 2

-24 =x + 2

collect like terms

-24-2= x

therefore x = -26

Notice that the angles UWV and YWX are vertical angles. Then, they have the same measure.

Additionally, the angles VUW and XYW are specified to have the same measure, as well as the sides VW and WX. Then, the pair of triangles UVW and YXW have two angles in common as well as one side.

Then, the congruence theorem that can be used to identify that ΔUVW ≅ ΔYXW is:

the answer is 3 1\9. thats the lentgh of the boat

3 1/9 this could be done on a calculator

The length of QJ is 4√20 units if the QJ = 4×PQ after using the intersecting chords theorem.

It is described as a set of points, where each point is at the same distance from a fixed point (called the center of a circle)

By intersecting chords theorem:

QM×QL = QJ×PQ

10×8 = QJ(QJ/4)

4×80 = QJ²

QJ = 4√20 units

Thus, the length of QJ is 4√20 units if the QJ = 4×PQ after using the intersecting chords theorem.

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Polynomials form a system like to that of integers hence they are closed under the operations of addition and subtraction.

Exponents of polynomials are whole numbers.

Hence the resultant exponents will be whole numbers , addition is closed for whole numbers. As a result, polynomials are closed under addition.

If an operation results in the production of another polynomial, the resulting polynomials will be closed.

The outcome of subtracting two polynomials is a polynomial. They are also closed under subtraction as a result.

The word polynomial is a Greek word. We can refer to a polynomial as having many terms because poly means many and nominal means terms. This article will teach us about polynomial expressions, polynomial types, polynomial degrees, and polynomial properties.

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The evolution of the function call (things '(11 -2 31)) is as follows:

(things '(11 -2 31)) -> (things '(-2 31)) -> (things '(31)) -> (things '()) -> '() the final result of the given call is '().

The given function is a recursive function called "things" that takes a list as input. It checks if the list is empty (null), and if so, it returns an empty list. Otherwise, it checks if the first element of the list (car x) is greater than 10. If it is, it adds 1 to the first element and recursively calls the "things" function on the rest of the list (cdr x). If the first element is not greater than 10, it subtracts 1 from the first element and recursively calls the "things" function on the rest of the list. The function then returns the result.

Now, let's see the evolution resulting from the call (things '(11 -2 31)):

1. (things '(11 -2 31))

  Since the list is not empty, we move to the next if statement.

  The first element (car x) is 11, which is greater than 10, so we add 1 to it and recursively call the "things" function on the rest of the list.

  The recursive call is (things '(-2 31)).

2. (things '(-2 31))

  Again, the list is not empty.

  The first element (car x) is -2, which is not greater than 10, so we subtract 1 from it and recursively call the "things" function on the rest of the list.

  The recursive call is (things '(31)).

3. (things '(31))

  The list is still not empty.

  The first element (car x) is 31, which is greater than 10, so we add 1 to it and recursively call the "things" function on the rest of the list.

  The recursive call is (things '()).

4. (things '())

  The list is now empty, so the function returns an empty list.

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Step-by-step explanation:

Hope it will help you a lot.

The surface area of the given cylinder is 368π square centimeter.

What is a cylinder?

The cylinder, one of the most basic curvilinear geometric shapes, has long been considered to be a three-dimensional solid. It is regarded as a prism with a circle as its basis in elementary geometry.

We are given a cylinder with following dimensions:

Radius (r) = 8 cm

Height (h) = 15 cm

Now, using the formula, we get

⇒ S = 2πrh + 2π\(r^{2}\)

⇒ S = 2π * 8 * 15 + 2 * π * \(8^{2}\)

⇒ S = 2π * 120 + 2 * π * 64

⇒ S = 240π + 128π

⇒ S = 368π

Hence, the surface area of the given cylinder is 368π square centimeter.

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Since, there are multiple questions so, the question answered above is attached below.

Question: Find the surface area of the given figure. Writh the answer in terms of pi.

Let z be an arbitrary point in A such that z ≠ (0,0). Let ε > 0 be given and consider an ε-neighborhood of z. Let d(z, (0,0))= r and choose r' such that 0 < r' < r. Then the ε-neighborhood of z intersects the region r ≤ x² + y² < 4, which is the region between two circles of radii r and 2.

A subset of a metric space S is said to be a limit point of S if every ε- neighborhood of the point contains some other point of S. Consider the sequence of points {(1/n, 1/n)} n=1∞ in A. As the points are in A, it follows that 0 < (1/n)² + (1/n)² < 4, for all n, and therefore 1/n² < 2, which implies that n > √(1/2). Hence, there exists an infinite number of points of A within an ε- neighborhood of (0,0), for any ε > 0, and it follows that (0,0) is a limit point of A.The function f is continuous on this region and, therefore, satisfies the Lipschitz condition on this region. That is, there exists an L such that |f(x,y) - f(u,v)| ≤ L√(x-u)² + (y-v)² for all (x,y) and (u,v) in the region. Choose (x,y) in the ε-neighbourhood of z and let (u,v) = (0,0). Then, |f(x,y)| = |f(x,y) - f(0,0)| ≤ L√(x-0)² + (y-0)² = L√(x² + y²) < L(2-r'), since x² + y² < 4 and 0 < r' < r. It follows that, given ε > 0, there exists a δ > 0 such that |f(x,y)| < ε whenever (x,y) is in the δ-neighbourhood of (0,0). Therefore, the limit of f(x,y) as (x,y) approaches (0,0) is 0. Hence, limf(x,y) exists and is equal to 0.

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Answer: f(x)=(x+3)^2-13 = (-3|-13)

Step-by-step explanation:

x^2+6x-4

x^2+6x+3^2-3^2-4

(x+3)^2-3^2-4

(x+3)^2-13

Answer:

4.4

Step-by-step explanation:

hope this helps

Answer:

5.9 - 1.5

3.5 pounds of honey

The average speed of car is 14.4 m/s.

We can see that from Photo 1 to Photo 2, the car covers 9 times the 0.8 meter distance. So, calculating the total distance traveled between the time span second photo was clicked.

Total distance traveled = 0.8×9

Performing multiplication

Total distance traveled = 7.2 meters

Now, the time is given as 0.5 seconds.

Finding the average speed using formula -

Average speed = total distance traveled ÷ total time taken

Keep the given values in formula to find the average speed.

Average speed = 7.2 ÷ 0.5

Performing division

Average speed = 14.4 m/s

Hence, the average speed of the car is 14.4 m/s

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The complete question is attached in figure.

Answer:

Step-by-step explanation:

1 soft drink = $3                            35-3=32         32/8=4

therefor each candy bar costs $4

Hope this helped!!! :)))

Answer:

4

Step-by-step explanation:

Sandy got 8 bars and a drink for 3 bucks and ended up wasting 35 dollars what you have to do is 35-3 and that = 32 and what you do to that 32 is ÷ it by 8 which gets you 4

Answer:

55%

Step-by-step explanation:

Answer:

  ⊥ to AB : x +y = 6

  ⊥ to AC : x -3y = 0

  ⊥ to BC : x +3y = 9

  see the attachment for a graph

Step-by-step explanation:

You want the equations and graphs of the perpendicular bisectors of AB, BC, and AC where the points are A(1, 2), B(4, 5), and C(2, -1). You want to relate this to finding the center of a circle through three non-collinear points.

The perpendicular bisector of a segment PQ with P(x1, y1) and Q(x2, y2) can be written as ...

  (x2-x1)(x -(x1+x2)/2) +(y2-y1)(y -(y1+y2)/2) = 0

Applying this to the given segments, we have ...

  ⊥ to AB : (4 -1)(x -(4+1)/2) +(5 -2)(y -(5+2)/2) = 0   ⇒   x +y = 6

  ⊥ to AC : (2 -1)(x -(2+1)/2) +(-1 -2)(y -(-1+2)/2) = 0   ⇒   x -3y = 0

  ⊥ to BC : (2 -4)(x -(2+4)/2) +(-1 -5)(y -(-1+5)/2) = 0   ⇒   x +3y = 9

The attachment shows a graph of the lines and their single point of intersection.

Each perpendicular bisector is the locus of the centers of circles through the end points of the respective segments. Then the intersection of those bisectors is the center of a circle through all of the points.

Solving any pair of these equations simultaneously gives the circle center as (4.5, 1.5). This is point D on the graph.

The given points are non-collinear, and the intersection of the perpendicular bisectors is the center of a circle through them. The method described in this problem is a suitable method for finding the circle center. (If the three points are considered a triangle, this center is called the "circumcenter.")

__

Additional comment

We have written the equations for the lines in standard form, with a positive leading coefficient and mutually prime integers. You will notice the graphing program wrote the same equations for those lines.

The Riemann sum is a method used to approximate the value of a definite integral by dividing the interval into subintervals and evaluating the function at specific points within each subinterval.

In this case, we are given the integral ∫30(4x^2 + 2x + 1)dx and we need to find the Riemann sum using right endpoints and n subintervals.

To calculate the Riemann sum, we first need to determine the width of each subinterval. The total interval is 30, and we will divide it into n subintervals, so the width of each subinterval is Δx = 30/n.

Next, we need to determine the right endpoint of each subinterval. Since we are using right endpoints, the right endpoint of the first subinterval will be x_1 = Δx, the right endpoint of the second subinterval will be x_2 = 2Δx, and so on. The right endpoint of the nth subinterval will be x_n = nΔx.

Now, we can calculate the Riemann sum by evaluating the function at each right endpoint and multiplying it by the width of the subinterval. Let's denote the function as f(x) = 4x^2 + 2x + 1.

The Riemann sum can be written as:

R = Σ[f(x_i)Δx], where i ranges from 1 to n.

Using the right endpoints, the Riemann sum can be expressed as:

R = Σ[f(x_i)Δx] = Σ[(4(x_i)^2 + 2x_i + 1)Δx], where i ranges from 1 to n.

Finally, we can calculate the Riemann sum by substituting the values of x_i and Δx into the above expression and summing up the terms.

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Operant conditioning is the theory that behavior is influenced by consequences. Behaviorists believe that behavior is shaped through reward and punishment, so a behavior that is followed by a favorable outcome is likely to be repeated while a behavior that is followed by an unfavorable outcome is less likely to be repeated.

The example of operant conditioning among the given options is: when a dog learns to roll over toy being rewarded for the behavior.

Operant conditioning, a concept developed by B.F Skinner, consists of three elements: the antecedent (the stimulus that comes before the behavior), the behavior, and the consequence.

In the example given in the question, the antecedent is the dog being taught to roll over, the behavior is the dog rolling over, and the consequence is being rewarded with a toy.

When a dog learns to roll over toy being rewarded for the behavior is an example of operant conditioning.

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The probability of having the sums that would exceed 100 has been calculated to be 0.5

We have the set or the sample space as:{1 , 5 , 10 , 100) It is said that two numbers would be able to be gotten from the set that we have. Given that the total numbers are 4, we would have ⁴C₂ = 6

The two numbers would be gotten from the set of 4 numbers in 6 different ways.

We are to find the numbers which when we add them up would be able to give us a sum that is greater than 100 these values are (100, 1), (100, 5), (100, 10)

Hence three pairs out of the given six that we already have would be able to give us values that are more than 10. We would have to divide through such that 3 / 6 = 1 / 2 = 0.5

Hence the probability that their values when summed would have to be greater than 100 is 0.5

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Answer:

The answer is C.

Step-by-step explanation:

The answer is C because the median plays a big role and is also difficult to find. Once you do find the median, you will have your answer.

Answer:greengrocer should Dell 17 kg before profit. 500$ profit

Step-by-step explanation: