I NEED MORE HELP..........

If we sample the function x(t) = cos(75t) at the Nyquist frequency, the resulting discrete frequency would be half of the Nyquist frequency, which is equal to half of the highest frequency component in the continuous signal.

In this case, the highest frequency component in x(t) is 75 Hz, as determined by the coefficient of t in the cosine function. According to the Nyquist-Shannon sampling theorem, to accurately represent a signal, the sampling frequency must be at least twice the highest frequency component. Therefore, the Nyquist frequency in this scenario would be 2 * 75 Hz = 150 Hz.

Since we are sampling at the Nyquist frequency, the resulting discrete frequency would be half of the Nyquist frequency, which is 150 Hz / 2 = 75 Hz. Hence, when sampling x(t) at the Nyquist frequency, the resulting discrete frequency would be 75 Hz.

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Answer:

(8, - 2 )

Step-by-step explanation:

A translation of 4 units right means add 4 to the x- coordinate

A translation of 5 units up means add 5 to the y- coordinate

(x, y ) → (x + 4, y + 5 ) ← translation rule, then

(4, - 7 ) → A'(4 + 4, - 7 + 5 ) → A'(8, - 2 )

Answer:

the answer is third option

because, 20²+x²=25²

x²=625-400

x²=225

Answer:

less that is it have good day

The relative frequency of the dice landing on a six is 0.74 or 74%.

1. Given that a dice is rolled 50 times and it lands on six 37 times.

2. Use the formula for relative frequency: Relative Frequency = (Number of times the dice lands on a six) ÷ (Total number of times the dice is rolled).

3. Substitute the values into the formula: Relative Frequency of dice landing on six = 37/50 = 0.74 or 74%.

Conclusion: In summary, when a dice is rolled 50 times and it lands on six 37 times, the relative frequency of the dice landing on a six is calculated to be 0.74 or 74%.

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The solution of the equation 2x² + 4x=1 using quadratic formula  is x = 0.22, -2.22

A quadratic formula is a formula that provides the solution(s) to a quadratic equation.

Given a quadratic equation of the form ax²+bx+c=0, where a, b, and c are coefficients. Then, we can put the coefficients in the quadratic formula:

x = (-b±√(b²-4ac))/(2a)

Given: 2x² + 4x=1, we can rewrite it as:

2x² + 4x - 1 = 0  

a = 2, b = 4 and c = -1 . Put these values in the quadratic formula:

x = (-b±√(b²-4ac))/(2a)

x =  (-4±√(4²-4×2×-1))/(2×2)

x = (-4±√(16+8))/(4)

x = (-4±√24)/(4)

x = (-4±√24)/(4)

x = (-4±4.899)/4

x = (-4+4.899)/4, (-4-4.899)/4

x = 0.22, -2.22

Therefore, the solution of 2x² + 4x=1 is x = 0.22, -2.22

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Answer:

C. Producer

Step-by-step explanation:

There are 11/18 miles does the car travel in 1 minute.

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

Given that;

A car travels 2 3/4 miles in 4 1/2 minutes.

Now,

Since, A car travels 2 3/4 miles in 4 1/2 minutes.

Hence, The distance cover by car in 1 minute = 2 3/4 ÷ 4 1/2

                                                                       = 11/4 ÷ 9/2

                                                                       = 11/4 × 2/9

                                                                       = 11/18 miles

Thus, The car travel 11/18 miles in 1 minute.

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the decision rule for rejecting the null hypothesis is, to reject H₀ if t > 1.363.

Right-tailed test: H0µ = k H1:>k P-value = P(z>z x) This indicates the probability of obtaining a test statistic as high as or higher than z x. If the P-value is less than α, we reject H0(null hypothesis) and conclude that the data are statistically significant at the level α. We do not reject H0 if the P-value is greater than α.

H0: µ  = 5.3 , H1: µ> 5.3

it is a right-tailed test

n = 12

α = 0.10

therefore the decision rule for rejecting the null hypothesis is, Reject H0 if t> 1.363.

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Using BODMAS, the solutions of the expressions are: (1) 9, (2)-12, (3) 0.27, and (4) 0.24

We should know that BODMAS is a mathematical approach which means

In each of the expressions, we must follow the approach

1)    \(\frac{(6+3)^{2} }{3*9}\)

Simplifying this we have 9²/9=81/9

=9

2)  \(\frac{3^{2} -6*2}{(12-8)/2^{2} *10}\)

Using BODMAS we have

(9-12)/4/40

-3÷1/9

⇒-3*4

=-12

(3)   \(\frac{4.5+2*2.5^{2}-6 }{8*4+9}\)

Using BODMAS we have

(4.5+2*6.25-6)/32+9

⇒(4.5+12.5-6)/41

=11/41=0.27

4     (\(\frac{3.5+16-2.5^{2} }{10.5-6*11}\))

Using BODMAS we have  

(3.5+16-6.25)/10.5-66

Simplifying

(13.25)/-55.5

=0.24

Therefore, the values when simplified are  (1) 9, (2)-12, (3) 0.27, and (4) 0.24

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Answer: False

Step-by-step explanation:

Hope this helps

9514 1404 393

Answer:

  (a) 2, 6

  (b) 155/8, -155, 8x² -155x -1 = 0

Step-by-step explanation:

(a) The equation in standard form is ...

  x^2 -(4+k)x +4k +1 = 0

Then the discriminant is ...

  (4+k)^2 -4(1)(4k+1) = 4^2 +8k +k^2 -16k -4 = k^2 -8k +12 = (k -2)(k -6)

The roots are equal when the discriminant is zero. The values of k that make the discriminant be zero are k=2 and k=6.

__

(b) a^3 + b^3 = (a +b)(a^2 -ab +b^2) = (a+b)((a+b)^2 -3ab)

  = (5/2)((5/2)^2 -3(-1/2)) = (5/2)(25/4 +3/2) = 155/8 = α³ +β³

  1/a^3 +1/b^3 = (a^3 +b^3)/(ab)^3 = (155/8)/(-1/2)^3 = -155 = 1/α³ +1/β³

The desired equation can be written from ...

  (x -a^3)(x -b^3) = 0

  x^2 -(a^3 +b^3)x +(ab)^3 = 0

  x^2 -155/8x -1/8 = 0 . . . . .substituting known values

  8x^2 -155x -1 = 0

Answer:

Step-by-step explanation:

\(2(x - 3) = 10x - 6 - 8x\)

\(2x-6=2x-6\)

+6        +6

\(2x=2x-0\)

You can't go any further s its b, NO SOLUTION.

Hope this helps :)

Answer:

The answer is B no solution

Step-by-step explanation:

The balance sheet that correctly represents the daycare's income, expenses, and balance is given as follows:

C; Income

Amount

Weekly Income $15,000.00

Total Monthly Income $60,000.00

Expenses

Percent Amount

Employee Wages 40% $24,000.00

Building Rent 5% $3,000.00

Supplies 15% $9,000.00

Equipment 5% $3,000.00

Educational Licensing 2% $1,200.00

Food 13% $7,800.00

Utilities 10% $3,000.00

Maintenance 5% $3,000.00

Emergency/Repair 5% $1,500.00

$60,000.00

Balance

Income $60,000.00

Expenses $60,000.00

Balance $0

The first step in obtaining the balance sheet is obtaining the total monthly income.

The weekly income is of $15,000, while a month is composed by four weeks, hence the monthly income is of:

4 x $15,000 = $60,000.

Then the percentages of each expenses are applied to find the values, for example, 40% of that is for employee wages, hence:

0.4 x 60,000 = $24,000.

From the percentages stated in the problem, 100% of the income is turned into expenses, hence the balance will be of zero and option C is correct.

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There were 20 questions on the quiz.

Let's start by using algebra to solve the problem.

Let x be the total number of questions on the quiz.

If Jianna got 87.5% of the questions correct, then she got 0.875x questions

correct.

We also know that Jianna got 17.5 questions correct.

So we can set up the equation:

0.875x = 17.5

To solve for x, we can divide both sides by 0.875:

x = 20

Therefore, there were 20 questions on the quiz.

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The p-value is a statistical measure used to determine the likelihood of observing a particular result or more extreme results, given the null hypothesis is true.

In this case, the null hypothesis is that the average amount Bob makes in tips per table is indeed $9.60, as claimed by the restaurant.

The p-value of 0.13 indicates that there is a 13% chance of observing an average tip amount as low as $8.95 or lower, assuming the null hypothesis is true.

In other words, if the restaurant's claim is accurate and Bob is just experiencing natural variation, there is a 13% probability of seeing an average tip amount as low as $8.95 or even lower.

Since the p-value is greater than the commonly used significance level of 0.05, which represents a 5% chance of seeing such a result due to random variation alone, we fail to reject the null hypothesis.

This means that the evidence does not provide strong enough support to conclude that Bob's average tip amount is significantly different from the claimed average of $9.60.

However, it is important to note that the p-value does not provide information on the direction of the difference.

It only tells us the likelihood of observing a result as extreme or more extreme than the one observed. So, even though Bob's average tip amount is lower than the claimed average,

the p-value alone does not determine whether the difference is statistically significant.

In summary, a p-value of 0.13 suggests that there is not enough evidence to conclude that Bob's average tip amount is significantly different from the claimed average of $9.60.

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Answer:

1.8400

Step-by-step explanation:

Answer:

195 miles

Step-by-step explanation:

This is because it is closer to the avg. 192.5 miles

Answer:

42p.

Step-by-step explanation:

100-58=42

The change Terry receives is 42 pence

How many pence is one pound?

Pence is the plural form of penny. There are 100 pence in one pound.

Given data ,

Total cost of oranges = 58 pence

Amount Terry gives to pay the oranges = 1 pound

1 pound = 100 pence

And ,

The change Terry receives =
Amount Terry gives to pay the oranges - Total cost of oranges

The change Terry receives = 100 - 58 pence

                                              = 42 pence

Hence , The change Terry receives is 42 pence

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The polynomial function \(\(f(x) = 2(x^2+3)(x+1)^2\)\) has zeros at -3 with multiplicity 1, and -1 with multiplicity 2. The graph of the function crosses the x-axis at -3 and -1.

To find the zeros and their multiplicities, we set \(\(f(x)\)\) equal to zero and solve for \(\(x\).\)

Setting \(\(f(x) = 0\),\) we have:

\(\[2(x^2+3)(x+1)^2 = 0\]\)

Since the product of two factors is zero, at least one of the factors must be zero. Thus, we solve for \(\(x\)\) in each factor separately:

1. \(\(x^2 + 3 = 0\):\)

  This equation does not have real solutions since the square of a real number is always non-negative. Therefore, this factor does not contribute any real zeros.

2. \(\(x + 1 = 0\):\)

  Solving for \(\(x\), we find \(x = -1\).\) This gives us a zero at -1 with multiplicity 1.

Since the factor \(\((x+1)^2\)\) is squared, the zero -1 has a multiplicity of 2.

Therefore, the zeros for the polynomial function are -3 with multiplicity 1 and -1 with multiplicity 2. The graph of the function crosses the x-axis at both zeros.

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For the moving platform shaped in parallelogram, the correct number in each box is

The result is obtained by using the properties of angles in parallelogram.

The properties of angles in parallelogram are:

There are 2 pairs of sides of parallelogram. A pair of sides are parallel to each other and have the same length.

In the picture, we have

Find x, m∠A, AB, and BC!

m∠D and m∠C are consecutive angles. So,

35° + (4x + 5) = 180°

35° + (4x + 5)° = 180°

40° + 4x = 180°

4x = 180° - 40°

4x = 140°

x = 140°/4

x = 35°

m∠A and m∠C are the opposite angles. So, they are equal.

m∠A = m∠C

m∠A = (4x + 5)°

m∠A = (4(35) + 5)°

m∠A = 145°

AB is parallel to DC. So,

AB = DC = 32 ft

BC is parallel to AD. So,

BC = AD = 14 ft

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Answer: −

1

7

−

Step-by-step explanation:

As per the concept of probability,

a) There are 6 handshakes will happen, if there are 4 people at the party.

b) There are 10 handshakes will happen, if there are 5 people at the party.

c) There are 55 handshakes will happen, if there are 11 people at the party.

Probability:

Probability refers the possibility of anything happening.

Given,

Here we know that, at a party, each people shakes hands once with other person in the party.

Here we need to find the number of handshakes will happen if there are 4, 5 and 11 peoples in the party.

According to the situation, le us consider, there are n members in the party. So, if there are n guests then each guest shakes hands with (n − 1)  other guests.

In each time a handshake occurs it counts as 2 handshakes (one for each person involved).

Therefore, the formula to calculate this one is,

\(\frac{n\times(n-1)}{2}\)

Then for 4 people the number of handshake is,

=> 4 x (4-1)/2

=> 2 x 3 = 6

For 5 persons, the number of handshake is,

=> 5 x (5 - 1)/2

=> 5 x 4/2

=> 5 x 2 = 10

Then for 11 person, the handshake count will be,

=> 11 x (11 - 1)/2

=> 11 x 10/2

=> 11 x 5

=> 55

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Answer:

2x + 11

Step-by-step explanation:

We are given

6 - 2x + 5 + 4x

Combining like terms with x, we have

6 + 5 + 2x

Combine like terms again, this time constants

11 + 2x

To find the minimum score required for an A grade, we need to determine the cutoff point that corresponds to the top 13% of scores.

Given that the scores on the test are normally distributed with a mean of 69.5 and a standard deviation of 9.5, we can use the standard normal distribution to calculate the cutoff point. Using a standard normal distribution table or a statistical calculator, we find that the z-score corresponding to the top 13% is approximately 1.04. To find the corresponding raw score, we can use the formula:

x = μ + (z * σ)

where x is the raw score, μ is the mean, z is the z-score, and σ is the standard deviation. Plugging in the values, we have:

x = 69.5 + (1.04 * 9.5) ≈ 79.58

Rounding this to the nearest whole number, the minimum score required for an A grade would be 80. Therefore, a student would need to score at least 80 on the test to achieve an A grade according to the professor's grading scheme.

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Answer:

Step-by-step explanation:

Measure of an inscribed angle intercepted by an arc is half of the measure of the arc.

From the picture attached,

m(∠A) = \(\frac{1}{2}m(\text{arc BD})\)

           = \(\frac{1}{2}[m(\text{BC})+m(\text{CD}]\)

           = \(\frac{1}{2}[55^{\circ}+145^{\circ}]\)

           = 100°

m(∠C) = \(\frac{1}{2}[(360^{\circ})-m(\text{arc BCD})]\)

           = \(\frac{1}{2}(360^{\circ}-200^{\circ})\)

           = 80°

m(∠B) + m(∠D) = 180° [ABCD is cyclic quadrilateral]

115° + m(∠D) = 180°

m(∠D) = 65°

m(arc AC) = 2[m(∠D)]

m(arc AB) + m(arc BC) = 2(65°) [Since, m(arc AC) = m(arc AB) + m(arc BC)]

m(arc AB) + 55° = 130°

m(arc AB) = 75°

m(arc ADC) = 2(m∠B)

m(arc AD) + m(arc DC) = 2(115°)

m(arc AD) + 145° = 230°

m(arc AD) = 85°

Answer:

1214

Step-by-step explanation:

\(\sf Probability\:of\:an\:event\:occurring = \dfrac{Number\:of\:ways\:it\:can\:occur}{Total\:number\:of\:possible\:outcomes}\)

Total number of pizzas sold last week:

= 311 + 250 + 175 + 191

= 927

\(\sf \implies \textsf{Probability of selling thick crust pizza} = \dfrac{250}{927}\)

\(\begin{aligned}\sf \implies \textsf{Expected value}& = \textsf{probabilty} \times \textsf{number}\\ & = \sf \dfrac{250}{927} \times 4500\\ & =\sf 1213.592233 \dots\\ & = \sf 1214\:(nearest\:whole\:number)\end{aligned}\)

Answer:

Step-by-step explanation:

311+250+175+191 = 927

then he sold 250 thick crust out of a total of 927 pizza crust

let x be the number of the thick crust expected to be sold out of the next 4500 pizza crust

Thick crust —————>  Total

 250          —————>   927

   x             —————>  4500

we have to solve this equation:

\(\frac{x}{250} =\frac{4500}{927}\)

\(\Longrightarrow x=\frac{250\times 4500}{927}\)

\(\Longrightarrow x = 1213.59223300971\)

the lower class limit represents the smallest data value that can be included in the classThe statement is true.

The lower class limit is the smallest value that can be included in a class interval.

Therefore, the statement is correct.

The lower class limit represents the smallest data value that can be included in a particular class. In a frequency distribution table, data values are grouped into classes, and each class has a lower and upper class limit. The lower class limit denotes the lowest value within that class, and any data value equal to or greater than the lower limit but less than the upper limit falls into that class.

The statement is true, as the lower-class limit indeed represents the smallest data value that can be included in the class.

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