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The volume of water needed to prepare the solution given the data is 2.16 L

This is defined as the mole of solute per unit litre of solution. Mathematically, it can be expressed as:

Molarity = mole / Volume

Mole = mass / molar mass

Mole of CaCO₃ = 756 / 100.1

Mole of CaCO₃ = 7.55 moles

Volume = mole / molarity

Volume = 7.55 / 3.5

Volume = 2.16 L

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Answer:

Positive

Explanation:

There are more protons than electrons making it positive

Answer:

From the information provided, it seems likely that substance A is an acid, and substance B is a carbonate. The fact that mixing the two substances results in bubbles or effervescence, and that a clear solution is formed, suggests that a chemical reaction is taking place.

Acids and carbonates react together to form a salt, water, and carbon dioxide gas. The reaction is as follow:

Acid + Carbonate → Salt + Water + Carbon Dioxide

The carbon dioxide gas forms bubbles in the solution and causes effervescence, and the clear solution formed is due to the fact that both the acid and the carbonate have reacted together to form the salt and water. This reaction is acid-base neutralization reaction as the acid and base will neutralize each other.

As for the acid, since it is said that B gives pH 3 solution after dissolved, it can be inferred that it is not an acid, otherwise it would be acidic. Therefore A which is insoluble is the acid.

As for the gas given off, it's Carbon dioxide.

Explanation:

The net ionic equation for the reaction between potassium sulfide and magnesium iodide is S2- + Mg2+ -> MgS, as the potassium and iodide ions are spectator ions and do not participate in the reaction.

To determine the net ionic equation for the reaction between potassium sulfide (K2S) and magnesium iodide (MgI2), we first need to identify the ions present in each compound and then determine the products formed when they react.

Potassium sulfide (K2S) dissociates into two potassium ions (K+) and one sulfide ion (S2-):

K2S -> 2K+ + S2-

Magnesium iodide (MgI2) dissociates into one magnesium ion (Mg2+) and two iodide ions (I-):

MgI2 -> Mg2+ + 2I-

Now, we need to determine the possible products when these ions combine. Since potassium (K+) has a +1 charge and iodide (I-) has a -1 charge, they can combine to form potassium iodide (KI):

K+ + I- -> KI

Similarly, magnesium (Mg2+) and sulfide (S2-) can combine to form magnesium sulfide (MgS):

Mg2+ + S2- -> MgS

Now, we can write the complete ionic equation by representing all the ions present before and after the reaction:

2K+ + S2- + Mg2+ + 2I- -> 2KI + MgS

To obtain the net ionic equation, we remove the spectator ions, which are the ions that appear on both sides of the equation and do not participate in the actual reaction. In this case, the spectator ions are the potassium ions (K+) and the iodide ions (I-).

Thus, the net ionic equation for the reaction between potassium sulfide and magnesium iodide is:

S2- + Mg2+ -> MgS

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Answer:

If there are more products than reactants, that means the reaction has shifted towards the left, which is the backward direction. If there are more reactants than products, that means the reaction has shifted towards the right, which is the forward direction.

Q = Ksp = 1 × 10^(-12).

Substituting the values into the Nernst equation, we have:

0.799 V = E° - (RT/2F) * ln(1 × 10^(-12))

Now, solving for E°:

E° = 0.799 V + (RT/2F) * ln(1 × 10^(-12))

The value of R is the ideal gas constant, T is the temperature in Kelvin, and F is the Faraday constant.

To find the standard reduction potential at 25°C for the half-reaction Ag2CrO4(s) + 2e¯ → 2Ag(s) + CrO4²-(aq), we can use the Nernst equation, which relates the standard reduction potential (E°) to the equilibrium constant (K) and the reaction quotient (Q).

The Nernst equation is given as follows:

E = E° - (RT/nF) * ln(Q)

Given information:

Ksp = 1 × 10^(-12)

E = +0.799 V (standard reduction potential of Ag+ to Ag)

Since the reaction involves the dissolution of Ag2CrO4(s), the reaction quotient Q can be expressed as [Ag+]²/[CrO4²-].

Since the stoichiometry of the reaction is 2:1 for Ag2CrO4 to Ag+, we can say that [Ag+]² = Ksp.

Therefore, Q = Ksp = 1 × 10^(-12).

Substituting the values into the Nernst equation, we have:

0.799 V = E° - (RT/2F) * ln(1 × 10^(-12))

Now, solving for E°:

E° = 0.799 V + (RT/2F) * ln(1 × 10^(-12))

The value of R is the ideal gas constant, T is the temperature in Kelvin, and F is the Faraday constant.

Please note that without specific values for temperature (T) and the ideal gas constant (R), the exact standard reduction potential at 25°C cannot be determined.

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The sun contained 99% of the available matter and the rest matter formed smaller clumps inside the spinning disk. These clumps gained enough mass which lead to their gravity shaping them into spheres becoming planets.

A planet can be described as a large, rounded astronomical body that is neither a star nor its remnant. The theory of planet formation is the nebular hypothesis, which tells that an interstellar cloud collapses out of a nebula to generate a young protostar orbited by a protoplanetary disk.

The planet grows in this disk by the accumulation of material driven by gravity and this process is known as accretion. Our solar system has at least eight planets that rotate around an axis tilted with respect to its orbital pole.

All planets possess an atmosphere, although that of Mercury is tenuous.  The Solar System planets create magnetic fields apart from Venus and Mars, and all planets except Venus and Mercury have natural satellites.

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Answer:

(a) The cost of the motors, including shipping charges, for each category are:

1-500 motors: $17.50

501-1,000 motors: $15.70 + $1.40 = $17.10

1,001-2,000 motors: $14.80 + $2.00 = $16.80

501-1,000 motors: $16.00

1,001-2,000 motors: $16.00 - 16% = $13.44 + $1.50 = $14.94

(b) By ordering 800 motors every two months, the total cost would be:

$17.10 x 2 = $34.20 per two months

Cost per motor: $34.20 / 800 = $0.0428

The percent saved per motor compared to purchasing 400 motors per month is:

(1 - $0.0428 / $16) x 100% = 99.73%

(c) By ordering 1,200 motors every three months, the total cost would be:

$14.94 x 1.5 = $22.41 per three months

Cost per motor: $22.41 / 1,200 = $0.0187

The percent saved per motor compared to purchasing 400 motors per month is:

(1 - $0.0187 / $16) x 100% = 99.88%

(d) The total cost of purchasing 400 motors per month for a year is:

$16 x 400 x 12 = $76,800

The total cost of purchasing 1,200 motors every three months for a year is:

$14.94 x 4 = $59.76 per year

$1.50 x 4 = $6.00 per year

Total: $59.76 + $6.00 = $65.76

The amount of money saved in a year is:

$76,800 - $65.76 = $76,734.24

(e) Egregious other factors beyond price that must be taken into consideration before changing your procurement procedures comprise the dependability of the supplier, the duration it takes to receive the products, adroit inventory management, as well as any plausible interference that could impede operations or production.

Answer:

About 14.45 seconds

Explanation:

If a object is going 4.5m/s and its destination is 65m then you need to divide.

65÷4.5 = 14.444444

due to the constant 4 you need to round 14.444 so it would be 14.45 seconds.

This technique has been used to identify the presence of gases such as oxygen, methane, and carbon dioxide in the atmospheres of exoplanets.  

i) To estimate the frequency of the violet (leftmost) emission, we can use the equation v = c/λ, where v is frequency, c is the speed of light (3.00 x 10^8 m/s), and λ is the wavelength of the emission in meters. The wavelength of the violet emission is 400 nm or 400 x 10^-9 m, so the frequency can be calculated as v = (3.00 x 10^8 m/s) / (400 x 10^-9 m) = 7.50 x 10^14 Hz.

ii) To estimate the energy of the violet emission, we can use the equation E = hv, where E is energy, h is Planck's constant (6.63 x 10^-34 Js), and v is frequency in Hz. Substituting the frequency calculated in part (i), we get E = (6.63 x 10^-34 Js) x (7.50 x 10^14 Hz) = 4.97 x 10^-19 J.

b. The spectral lines are produced by the electrons within the atoms of this element, which can absorb or emit specific amounts of energy to move between different energy levels. These energy transitions result in the emission or absorption of photons with specific wavelengths and frequencies, giving rise to the observed emission spectrum.

c. The violet emission line represents the photon with the most energy since it has the shortest wavelength (400 nm) and highest frequency (7.50 x 10^14 Hz) among the lines shown. This highest energy does not necessarily represent the energy of the valence electrons, but rather corresponds to the specific energy transitions occurring within the atoms of the element.

d. Emission spectra can be used to determine the gases present in the atmosphere of a far-away planet by analyzing the specific wavelengths of the emitted or absorbed light from the planet. Each gas has a unique emission or absorption spectrum, allowing scientists to identify the gases present in the planet's atmosphere.

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If ΔH is positive and entropy decreases, the reaction will be non-spontaneous, which means that it requires energy to proceed. The correct answer is D. Endothermic reaction.

What is an endothermic reaction?

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Answer:

D

Explanation:

Answer:

True

Explanation:

In a neutral atom, the number of protons and electrons are equal.

"" ANSWER""

Protons are values ​​of atomic numbers that do NOT change, that is, they are located inside the nucleus of the atom, whereas electrons are located in the electrosphere that can gain or lose electrons, the electron has a negative charge and the Proton positive, that is, if in any atom it wins an electron the atom will be negative and if the atom loses it will be positive because we already know that the number of protons does not change. To calculate the number of neutron we have to make the number of rounded atomic mass which becomes mass less the number of protons for example oxygen gas has 8 protons which is the atomic number and has atomic mass 15,999 which rounding up to 16 to find the number of neutrals we do 16-8 = 8 so now we know that oxygen has: 8 protons, 8 electrons and 8 neutrons but the values ​​will not always be the same but the possibility of protons and neutrals having the same value is 75% by my count .

● ○ ● RULES ○ ● ○ ●

Atomic number = number of protons

Atomic mass ROUNDNESS = mass

Number of neutrons = number of protons - mass number

OBSERVATION- EXPLANATION FOR STUDENTS OF 9 YEARS BECAUSE IN THE HIGH SCHOOL UP SOME CHANGES CHANGE.

■■ GOOD STUDIES ■■

Answer:

t = 37.1 s

Explanation:

The equation for the reaction is given as;

                  2 N2O5(g)  --> 4 NO2 + O2

Initial:          0.110                  -             -

change:        -2x                  +4x        +x

Final:          0.110 - 2x           +4x        +x

But final = 0.150atm;

0.110 - 2x    +  4x   +  x = 0.150 atm

3x = 0.150 - 0.110

x = 0.0133 atm

Pressure in reactant side;

0.110 - 2x

0.110 - 2 (0.0133) = 0.0834 atm

The integral rate law expression is given as;

ln ( [A] / [Ao] ) = -kt

k =  rate constant = 7.48*10^-3*s-1

ln (0.0834/0.11) = (7.48*10^-3)  t

upon solving, t = 37.1 s

In this exercise we have to use the knowledge of chemistry to calculate the necessary time that the pressure can hold the system, in this way we can say that this time corresponds to:

\(t = 37.1 s\)

First we have to use the reaction equation given as:

\(2 N_2O_5(g) \rightarrow 4 NO_2 + O_2\)

This equation can be rewritten in terms of pressure, so it will be;              

\(0.110 - 2X + 4X + X = 0.150 atm\\3X = 0.150 - 0.110\\X = 0.0133 atm\)

Pressure in reactant side, will be:

\(0.110 - 2X \rightarrow 0.110 - 2 (0.0133) = 0.0834 atm\)

The integral rate law expression is given as, knowing that the rate constant is  \(7.48*10^{-3}*s^{-1}\)

\(\int\limits^{0.0834}_{0.11} {(7.48*10^{-3}) t} \, dt = t = 37.1 s\)

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Answer:

3.22m

Explanation:

c=3×10^8m/s=speed of the light

lambda= wavelength=?

frequency=?

lambda=c÷frequency

lambda=(3×10^8)÷(93.1×10^6)

lambda=3.22m

Answer:

The temperature of this sample changes by 1.052 degrees Celsius

Explanation:

As we know

\(Q = mc\Delta T\)

Where m is the mass of the substance

c is the specific heat of the substance

and \(\Delta T\) is the change in temperature

Substituting the given values in above equation, we get -

\(114.6 = 108.9 * 1 * \Delta T\\\Delta T = 1.052\)degree Celsius

The temperature of this sample changes by 1.052 degrees Celsius

Answer:b

Explanation:i just did it

Explanation:

One mole of aluminum atoms has a mass of 26.98 grams, and contains 6.02×1023 atoms. Dividing 26.986.02×1023 yields a mass of 4.48×10−23 g for one aluminum atom.

The mass of the asteroid is C. 1.2 x \(10^{12}\) Kg

To find the mass of the other asteroid, we can rearrange the equation for the gravitational force between two objects:

F = (G * m1 * m2) / \(r^{2}\)

where F is the force of gravity, G is the gravitational constant, m1 and m2 are the masses of the two asteroids, and r is the distance between them.

Given that the distance between the asteroids is 75000 m, the force of gravity between them is 1.14 N, and one asteroid has a mass of 8 x \(10^{7}\) kg, we can substitute these values into the equation and solve for the mass of the other asteroid (m2):

1.14 N = (6.67430 × \(10^{-11}\) N \(m^{2}\)/\(Kg^{2}\) * 8 x \(10^{7}\) kg * \(m2\)) / \((75000 m)^{2}\)

Simplifying and solving the equation, we find that the mass of the other asteroid (m2) is approximately 1.2 x \(10^{12}\) kg. Therefore, Option C is correct.

The question was incomplete. find the full content below:

Two asteroids are 75000 m apart one has a mass of 8 x \(10^{7}\) kg if the force of gravity between them is 1.14 what is the mass of the asteroid

A. 3.4 x \(10^{11}\) kg

B. 8.3 x \(10^{12}\) kg

C. 1.2 x \(10^{12}\) kg

D. 1.2 x \(10^{10}\) kg

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You could form approximately 5.8 grams of methanol (CH3OH) from the given gas mixture at STP.

Using the Ideal gas equation;

n = PV / RT

n = (1 atm * 7.82 L) / (0.0821 L·atm/(mol·K) * 273.15 K)

From the question;

nCO = n / 2

nH2 = n / 2

Then;

n = (1 atm * 7.82 L) / (0.0821 L·atm/(mol·K) * 273.15 K)

n = 0.362 mol

nCO = n / 2 = 0.362 mol / 2 = 0.181 mol

nH2 = n / 2 = 0.362 mol / 2 = 0.181 mol

By stoichiometry;

methanol= nCO = 0.181 mol

Mass of methanol =  0.181 mol * 32.04 g/mol

= 5.8 g

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Answer:

It has 3 significant figures

Explanation:

When the number ends on zero that are to the right to the decimal point

The mass (in grams) of fluorine the sample have is 2.91 g

First, we shall determine the mole of 9 grams of cobalt. Details below:

Mole = mass / molar mass

Mole of cobalt = 9 / 58.93

Mole of cobalt = 0.153 mole

Finally, we shall determine the mass of fluorine the present in the compound. Details below:

Mole = mass / molar mass

0.153 = Mass of fluorine / 19

Cross multiply

Mass of fluorine = 0.153 × 19

Mass of fluorine = 2.91 g

Thus, the mass of fluorine is 2.91 g

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Answer:

its A

Explanation:

The only one that makes sense

Answer:

During complete oxidation of the fatty acid CH3(CH2)14COOH, eight molecules of acetyl-CoA are produced, and the fatty acid goes through the β-oxidation cycle seven times.

Explanation:

In the β-oxidation of fatty acids, an acetyl-CoA molecule is removed from the fatty acid chain after every β-oxidation cycle that the fatty acid undergo, leaving behind a fatty acyl-CoA molecule shortened by two cabon atoms..

The removal of the acetyl-CoA molecule starts from the carboxyl end and shortens the fatty acid molecule by two carbon units. Successive β-oxidation cycles results in the complete oxidaton of the fatty acid molecle to acetyl -CoA molecules.

The compound CH3(CH2)14COOH, is a 16-carbon saturated fatty acid molecule known as palmitic acid.. It undergoes seven passes through the β-oxidation cycle to yield eight molecules of acetyl-CoA with each cycle yielding an acetyl-CoA molecule and a fatty acyl-CoA shortened by two carbon atoms. Finally, the seventh step yields two acetyl-CoA molecules.

During complete oxidation of CH3(CH2)14COOH, eight (8) molecules of acetyl-CoA are produced, and the fatty acid goes through the β-oxidation cycle seven (7) times.

In conclusion, during complete oxidation of CH3(CH2)14COOH, eight (8) molecules of acetyl-CoA are produced, and the fatty acid goes through the β-oxidation cycle seven (7) times.

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Answer:

Convention

Explanation:

Answer:

Because the soup became warm and less dense, so it rose up.

Explanation:

Found on Course Hero is an American education technology website company based in Redwood City, California, which operates an online learning platform for students to access course-specific study resources contributed by a community of students and educators.

The answer choice that best describes this is  C. Peter's brain still received messages from his other sensory receptors, which his brain combined with stored memories in order to move through the darkness.

Here, the sensory organs in Peter's eyes, ears, nose, mouth, and internal organs are specialized organs that allow each receptor type to convey a different sensory modality to eventually integrate into a single perceptual frame.

As a result of these sensory organs, Peter will eventually go stuttering when he wakes up in the middle of the night in complete darkness. However, he was able to make his way to the bathroom without bumping into any objects in his path.

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Peter woke up in the middle of night in darkness. Without being able to see, he was able to make his way to the bathroom without running into any objects in his path.

Which of the following best describes how he is able to do this?

A. Peter's brain received visual information from sensory receptors other than his eyes, so there was no change in how his body responded to the darkness around him.

B. Peter's brain used only stored memories as input when he moved through the darkness, as all sensory receptors are directly tied to the visual system.

C. Peter's brain still received messages from his other sensory receptors, which his brain combined with stored memories in order to move through the darkness.

D. Peter's brain used only messages received from his other sensory receptors when he moved through the darkness, as the visual system is not an important part of the central nervous system.​