Answer: 50% said the person up
Use the relationships between the angles to find the value of . 75° 40 X 15 degrees
Answer:
x = 65
Step-by-step explanation:
All angles in the triangle equal 180
Set up your formula as
180 = x+75+40
180-75-40=x
65=x
Please help me with this graph problem
how do you factor 0 = x^2 - 6?
Answer:
2
+
5
+
6
=
0
Explain whether a triangle exists with side lengths 31 m, 89 m, and 122 m.
Answer:
No
Step-by-step explanation:
The sum of the smaller sides is not bigger than the largest side, 122. ( 31 + 89 = 120 < 122)
pls help if you can asap!!!!
Answer: x= 6
Step-by-step explanation:
Since the shape is a parallelogram, the angles will either be equal to each other or add up to 180.
You can see they do not look the same so they add up to equal 180
12x + 3 +105 = 180
12x + 108 = 180
12x = 72
x = 6
Consider the one-dimensional wave equation Ut = aʻuzr, where u denotes the position of a vibrating string at the point x at time t > 0. Assuming that the string lies between x = 0 and x = L, we pose the boundary conditions u(0,t) = 0, 4,(L, t) = 0, that is the string is "fixed" at x = 0 and "free" at x = L. We also assume that the string is set in motion with no initial velocity from the initial position, that is we pose the initial conditions u(x,0) = f(x), ut(x,0) = 0. Find u(x, t) that satisfies this initial-boundary value problem.
u(x, t) that satisfies this initial-boundary value problem:
u(x,t) = [f(x - at) + f(x + at)]/2
Given the one-dimensional wave equation,
Ut = aʻuzr, where u denotes the position of a vibrating string at the point x at time t > 0.
Assume that the string lies between x = 0 and x = L, we pose the boundary conditions u(0,t) = 0, 4,(L, t) = 0, that is the string is "fixed" at x = 0 and "free" at x = L.
We also assume that the string is set in motion with no initial velocity from the initial position, that is we pose the initial conditions
u(x,0) = f(x), ut(x,0) = 0.
So, the solution of this initial-boundary value problem is,
u(x,t) = [f(x - at) + f(x + at)]/2 + [1/(2a)] ∫(x-at)^(x+at)g(s) ds
Here, g(x) is an arbitrary function that depends on the initial velocity. But here ut(x, 0) = 0. So, g(x) = 0.
Therefore, we get the solution as,u(x,t) = [f(x - at) + f(x + at)]/2
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Given data,We have the following 1-D wave equation Ut = a2uzrWhere, u denotes the position of a vibrating string at the point x at time t > 0. The string lies between x = 0 and x = L.
And pose ,
the boundary conditions u(0,t) = 0, u(L, t) = 0
initial conditions u(x,0) = f(x),
ut(x,0) = 0.
To find the solution of 1-D wave equation Ut = a2uzr as per the given initial-boundary value problem,We use the method of separation of variables, i.e.,
we assume the solution u(x, t) to be of the form u(x, t) = X(x)T(t).
Let's substitute it in the given equation ,
Ut = a2uzr
=> Xt = a2X''T
=> 1/a2T''/T
= X''/X
= k (say).
By solving above differential equation, we getX(x) = Asin(kx) + Bcos(kx)where A and B are constants.
Let's find the value of k, by applying the boundary conditions at x=0,
X(0) = Asin(0) + Bcos(0) = B = 0
Putting X(L) = Asin(kL) + Bcos(kL) = 0we get, k = nπ/Ln=1,2,3,……..
Let's substitute this value of k in X(x),Xn(x) = Asin(nπx/L)Also, substituting k in
T''/T = k/a2, we get T(t) = C1 cos(ωnt) + C2 sin(ωnt),
where ωn = anπ/L.
Let's substitute these values of Xn(x) and Tn(t) in u(x,t)u(x,t) = Σ [Ancos(anπt/L) + Bnsin(anπt/L)] sin(nπx/L)
where A_n and B_n are constants and can be determined by applying initial conditions.
So, the solution of the 1-D wave equation as per the given initial-boundary value problem is,
u(x,t) = Σ [Ancos(anπt/L) + Bnsin(anπt/L)] sin(nπx/L)where n = 1,2,3,....
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dracula purchased a box of cookies for his halloween party. the box is in the shape of a triangular prism (see diagram). if the volume of the box is 3,240 cubic centimeters, what is the height of the triangular face of the box? how much packaging material was used to construct the cracker box?
The height of the triangular face of the box is 6 cm when the Volume of the box is 3,240 cubic cm.
Given Parameters,
The length of the box (l) = 30 cm
The breadth of the box (b) = 18 cm
The height of the box = h
The Volume of the prism = l * b * h
It is given that the volume of the prism is 3,240 cubic cm.
Thus,
l * b * h = 3,240
Putting the values of length and breadth, we have
30 * 18 * h = 3,240
540 * h = 3,240
h = 3,240/540
h = 6
Thus, the height of the triangular face of the box is 6 cm.
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Let X be a Compact metric space and F⊂C(X)
be a compact subset. Show that F is equicontinuous.
Proof- let f∈F
be an arbitrary function. What I want to show is that,
∀ϵ>0 there exists δ>0 suchthat ,if |x−y|<δ then |f(x)−f(y)|<ϵ
for all f∈F and ∀x,y∈X
Since X is a compact metric space, it is complete and totally bounded. Therefore, by the Arzelà-Ascoli theorem, it suffices to show that F is uniformly bounded and equicontinuous.
To show that F is uniformly bounded, let M be a positive number such that |f(x)| ≤ M for all x ∈ X and f ∈ F. Since F is compact, there exist finitely many functions f1, f2, ..., fn ∈ F such that for every f ∈ F, there exists i ∈ {1, 2, ..., n} such that ||f - fi|| < ϵ/3, where ||·|| denotes the supremum norm on C(X). Then, for any x ∈ X, we have
|f(x)| ≤ |f(x) - fi(x)| + |fi(x)| + |fi(x)| - M ≤ ||f - fi|| + |fi(x)| + M ≤ ϵ/3 + M + ϵ/3 = 2ϵ/3 + M.
Therefore, F is uniformly bounded by 2ϵ/3 + M, which does not depend on the choice of f and ϵ.
To show that F is equicontinuous, let ϵ > 0 be arbitrary. For each x ∈ X, there exists δx > 0 such that |f(x) - f(y)| < ϵ/3 for all f ∈ F and y ∈ X with |x - y| < δx, since F is compact and therefore uniformly continuous. Since X is compact, there exists a finite cover {B(x1, δx1/2), B(x2, δx2/2), ..., B(xn, δxn/2)} of X, where B(x, r) denotes the open ball centered at x with radius r. Let δ = min{δx/2 : 1 ≤ i ≤ n}. Then, for any x, y ∈ X with |x - y| < δ, there exists i ∈ {1, 2, ..., n} such that x, y ∈ B(xi, δxi/2), so |f(x) - f(y)| < ϵ/3 for all f ∈ F. Moreover, since |x - y| < δxi/2, we have |f(x) - f(y)| < ϵ/3 for all f ∈ F and x, y ∈ B(xi, δxi/2). Therefore, for any x, y ∈ X with |x - y| < δ, we have
|f(x) - f(y)| ≤ |f(x) - f(xi)| + |f(xi) - f(y)| < ϵ/3 + ϵ/3 = 2ϵ/3.
Thus, F is equicontinuous with respect to δ, which does not depend on the choice of f and ϵ.
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Asx approaches negative infinity, for which of the following functions does f(x) approach positive infinity? Select all that apply. Select all that apply: f(x) =2x5 Ofx)9x +100 f(x)= 6x8 +9x6+32 f(x)=-8x3 + 11 f(x)=-10x +5x+ 26 f(x)=-x +8x4 + 248
Among the provided functions, the ones that approach positive infinity as x approaches negative infinity are:
- f(x) = 2x^5
- f(x) = 6x^8 + 9x^6 + 32
- f(x) = -x + 8x^4 + 248
To determine which functions approach positive infinity as x approaches negative infinity, we need to analyze the leading terms of the functions. The leading term dominates the behavior of the function as x becomes very large or very small.
Let's examine each function and identify their leading terms:
1. f(x) = 2x^5
The leading term is 2x^5, which has a positive coefficient and the highest power of x.
As x approaches negative infinity, this term becomes very large and positive, indicating that f(x) approaches positive infinity.
2. f(x) = 9x + 100
The leading term is 9x, which has a positive coefficient but a lower power of x compared to the constant term 100.
As x approaches negative infinity, the leading term becomes very large and negative, indicating that f(x) approaches negative infinity, not positive infinity.
3. f(x) = 6x^8 + 9x^6 + 32
The leading term is 6x^8, which has a positive coefficient and the highest power of x.
As x approaches negative infinity, this term becomes very large and positive, indicating that f(x) approaches positive infinity.
4. f(x) = -8x^3 + 11
The leading term is -8x^3, which has a negative coefficient and the highest power of x.
As x approaches negative infinity, this term becomes very large and negative, indicating that f(x) approaches negative infinity, not positive infinity.
5. f(x) = -10x + 5x + 26
Combining like terms, we have f(x) = -5x + 26.
The leading term is -5x, which has a negative coefficient but a lower power of x compared to the constant term 26.
As x approaches negative infinity, the leading term becomes very large and positive, indicating that f(x) approaches negative infinity, not positive infinity.
6. f(x) = -x + 8x^4 + 248
The leading term is 8x^4, which has a positive coefficient and the highest power of x.
As x approaches negative infinity, this term becomes very large and positive, indicating that f(x) approaches positive infinity.
Therefore, the correct choices are:
- f(x) = 2x^5
- f(x) = 6x^8 + 9x^6 + 32
- f(x) = -x + 8x^4 + 248
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which graph represents the inequality y≥1/3x-1
Answer: c
Step-by-step explanation:
The correct graph that represents the inequality y ≥ (1/3)x - 1 is the one with the shaded region above the boundary line. Hence, the correct option is C.
To graph the inequality y ≥ (1/3)x - 1, we need to start by graphing the corresponding equality y = (1/3)x - 1, which is the equation of the boundary line. This boundary line represents the points that satisfy the equation y = (1/3)x - 1.
The inequality y ≥ (1/3)x - 1 includes all the points on or above the boundary line, so the shaded region will be above the line.
The boundary line has a slope of 1/3 and a y-intercept of -1. To plot the line, start at the y-intercept (0, -1) and use the slope to find additional points. For example, if x = 3, then y = (1/3) * 3 - 1 = 1 - 1 = 0, giving us the point (3, 0).
All the points in the shaded region satisfy the inequality y ≥ (1/3)x - 1.
So, the correct graph that represents the inequality y ≥ (1/3)x - 1 is the one with the shaded region above the boundary line.
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A ladder 25 feet long is leaning against the wall of a house. The base of the ladder is pulled away from the wall at a rate of 2 feet per second.What is the velocity of the top of the ladder when the base is given below?ALREADY KNOWO 7 feet away from the wall= -7/12O 15 feet away from the wall=-3/2O 20 feet away from the wall=-8/3
The velocity of the top of the ladder is 20.62 feet per second.
We can use the Pythagorean theorem to relate the distance between the wall and the base of the ladder to the height of the ladder. Let h be the height of the ladder, then we have:
h² + 7² = 25²
h² = 576
h = 24 feet
We can then use the chain rule to find the velocity of the top of the ladder. Let v be the velocity of the base of the ladder, then we have:
h² + (dx/dt)² = 25²
2h (dh/dt) + 2(dx/dt)(d²x/dt²) = 0
Simplifying and plugging in h = 24 and dx/dt = -2, we get:
(24)(dh/dt) - 2(d²x/dt²) = 0
Solving for (d²x/dt²), we get:
(d²x/dt²) = (12)(dh/dt)
We can find (dh/dt) using the Pythagorean theorem and the fact that the ladder is sliding down the wall at a rate of 2 feet per second:
h² + (dx/dt)² = 25²
2h(dh/dt) + 2(dx/dt)(d²x/dt²) = 0
Substituting h = 24, dx/dt = -2, and solving for (dh/dt), we get:
(dh/dt) = -15/8
Finally, we can find (d²x/dt²) by plugging in (dh/dt) and solving:
(d²x/dt²) = (12)(dh/dt) = (12)(-15/8) = -45/2
Therefore, the velocity of the top of the ladder is 20.62 feet per second.
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\(171.36 ÷ 4\)
Answer:
42.84
Step-by-step explanation:
I think
this is the answer
Jordan missed 49 questions on his multiple choice math final and earned a grade of 65%. How many total questions were on the final exam?
Answer:
76
Step-by-step explanation:
Answer:
the answer is 140
Step-by-step explanation:
my delta math said it was right lol
Millie needs a total of 7.8 feet of ribbon for a school project. She needs 0.7 more feet of ribbon. How much ribbon, in feet, did Millie already have? Write and solve an equation to find the answer.
6.9
7.1
7.5
8.5
Subtraction is a mathematical operation that reflects the removal of things from a collection. The ribbon that Millie already had is 7.1 feet.
What is subtraction?Subtraction is a mathematical operation that reflects the removal of things from a collection. The negative symbol represents subtraction.
Given Millie needs a total of 7.8 feet of ribbon for a school project. Also, She needs 0.7 more feet of ribbon. Therefore, the ribbon that Millie needs is,
Ribbon Millie had = Total Ribbon - ribbon that is needed
= 7.8 feet - 0.7feet
= 7.1 feet
Hence, the ribbon that Millie already had is 7.1 feet.
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Can a triangle be formed with the sides lengths of 8 cm, 5 cm and 13 cm?
The side lengths of 8 cm, 5 cm and 13 cm _______ form a triangle.
Drop down options:
cannot
can
The rule says that the sum of any two sides has to be smaller than the third side so, no it can't
What is the answer to this question?
will get awarded with brainliest!
(6x-7)(2x+5)
For the matrix A below, find a nonzero vector in Nul A, a nonzero vector in Col A, and a nonzero vector in Row A = 1350 012-7 A nonzero column vector in Nul Ais A nonzero column vector in Col A is A nonzero column vector in Row Ais
As per row echelon form of the matrix, the column space for the given matrix A is { [1 0], [3 1] }
The term row echelon form of the matrix is defined as a matrix is in echelon form if it has the shape resulting from a Gaussian elimination.
Here we have given the following matrix
\(\begin{bmatrix}1 &3 &5 &0 \\0 & 1 & 2 & -3\end{bmatrix}\)
As we all know that the column space is a space spanned by the columns of the initial matrix that correspond to the pivot columns of the reduced matrix.
As per the definition of row echelon the given matrix is already in the row echelon form.
So, the column space is written as, first two columns
=> \(\begin{bmatrix}1 \\0\end{bmatrix}\begin{bmatrix}3 \\1\end{bmatrix}\\\)
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A rectangular yard measuring 29 ft by 45 ft is bordered (and surrounded) by a fence. Inside, a walk that is 4ft wide goes all the way along the fence. Find the area of this walk. Be sure to include the correct unit in your answer
The walkway has a 656 square foot area.
An example of a measure is what?Comparing a quantitative measurement with a recognized standard amount of some kind is the act of measurement. For instance, in the measurement 10 kg, kg is indeed the basic measure used to describe mass of a physical quantity, and 10 is the size of the physical quantity.
In order to determine the size of the walkway, we must first determine the size of the bigger rectangle that includes the yard and the walkway, from which we must then deduct the yard's area.
The dimensions of the bigger rectangle will be:
Length: 29ft + 2(4ft) = 37ft
Width: 45ft + 2(4ft) = 53ft
Hence, the larger rectangle's area is:
37ft x 53ft = 1961ft²
The yard's actual size is:
29ft x 45ft = 1305ft²
As a result, the distinction between the two sections is the size of the walkway:
1961ft² - 1305ft² = 656ft²
Hence, the walkway has a 656 square foot area.
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One of the output functions of a three inputs 3x8 decoder combinational output function in sum-of- minterms form: F = (0,1,2,3,7). What is the c function of this output? a) (x + y) (y+z) b) (x+y)(x+z) c) (y + 2) (x + 2)
The correct option is a) (x + y) (y + z). Given the output function F in sum-of-minterms form as F = (0, 1, 2, 3, 7), we need to determine the corresponding Boolean expression for the output function.
A 3x8 decoder has three input variables (x, y, z) and eight output variables, where each output variable corresponds to a unique combination of input variables. The output variables are typically represented as minterms.
Let's analyze the given output function F = (0, 1, 2, 3, 7). The minterms represent the outputs that are equal to 1. By observing the minterms, we can deduce the corresponding Boolean expression.
From the minterms, we can see that the output is equal to 1 when x = 0, y = 0, z = 0 or x = 0, y = 0, z = 1 or x = 0, y = 1, z = 0 or x = 0, y = 1, z = 1 or x = 1, y = 1, z = 1.
By simplifying the above conditions, we get (x + y) (y + z), which is the Boolean expression corresponding to the given output function F.
In summary, the correct option is a) (x + y) (y + z).
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Determine the slope (-6,5) (3,-3)
Answer: M = -8/3
Step-by-step explanation:
What is a name for the angle below? Do not include the angle symbol in your answer.
help real answers only please
Answer:
The three points are
(-2,1)
(-3,2)
(-4,3)
Step-by-step explanation:
These points solve the problem, you could have other points as well such as (-5,4), (-6,7) and so on
find the area of the triangle
The area of the triangle is:
\(\Large\displaystyle\text{$\begin{aligned}A\triangle &= \dfrac{21+7\sqrt{15}}{2}\\ \\A\triangle &\approx 24.055\\ \\\end{aligned}$}\)
You can easily find the area of a triangle using the formula:
\(\Large\displaystyle\text{$\begin{aligned}A\triangle = \dfrac{bh}{2}\end{aligned}$}\)
Where h is the height of the triangle, and b the base.
Looking at the figure we can see that h = 7, but we need to discover the base, we know that the base is:
\(\Large\displaystyle\text{$\begin{aligned}b = 3 + x\end{aligned}$}\)
Where:
\(\Large\displaystyle\text{$\begin{aligned}8^2 &= x^2 + 7^2\\ \\x^2 &= 8^2 - 7^2 \\ \\x^2 &= 64 - 49\\ \\x^2 &= 15\\ \\x &= \sqrt{15}\end{aligned}$}\)
Therefore, our base length is:
\(\Large\displaystyle\text{$\begin{aligned}b &= 3 + x\\ \\b &= 3 + \sqrt{15}\\ \\\end{aligned}$}\)
Then we can just apply the formula for the area:
\(\Large\displaystyle\text{$\begin{aligned}A\triangle &= \dfrac{(3+\sqrt{15})\cdot 7}{2}\\ \\A\triangle &= \dfrac{21+7\sqrt{15}}{2}\\ \\A\triangle &\approx 24.055\\ \\\end{aligned}$}\)
I hope you liked it
Any doubt? Write it in the comments and I'll help you
Plz Help! I will mark brainliest
Answer:
the answer is C
(5+3i)-(2+9i) = 3-6i
Answer:
C. 3 - 6i
Step-by-step explanation:
Personajes que aportaron ala geometria y que aportaron
Answer:
yes this is the answer lol
Please help? 5) 120 = 4(-6+6n)
Answer:
n=6
Step-by-step explanation:
If corresponding angles are on parallel, then their measure is the same ____. always, sometimes, or never
Answer:
Step-by-step explanation:
Sometimes hope that helps you and hope you pass : >
Answer:
Always
Step-by-step explanation:
- Parallel lines can be defined as two lines in the same plane that are at equal distance from each other and never meet.
- Parallel lines are congruent and so their measure will ALWAYS be the same
A study claims that 25 % of children under the age of 13 in British Columbia have not been vaccinated from the chicken pox. A survey of randomly selected residents of a certain city included 800 children who were under the age of 13 and 185 of them were not vaccinated. Parta What is the approximated probability that sample proportion of non-vaccinated children in a sample of 800 children is more than 185/800? (Please carry answers to at least six decimal places in intermediate steps. Give your final answer to the nearest four decimal places)
The probability of a sample proportion of non-vaccinated children in a sample of 800 children more than 185/800 is approximately 0.7937, or 0.7936 when rounded to four decimal places.
The sample proportion is given by: p-hat = 185/800 = 0.23125So, the probability of a sample proportion of non-vaccinated children in a sample of 800 children more than 185/800 is to be determined.
To determine this probability, we need to find the z-score associated with the given sample proportion. z = (p-hat - p) / √[p(1-p)/n]where n = 800, p = 0.25, and p-hat = 0.23125Substituting these values, we get z = (0.23125 - 0.25) / √[(0.25 x 0.75) / 800]= -0.014559 / 0.017789= -0.81796Using a standard normal distribution table, we can find that the area to the left of this z-score is 0.2063.
Therefore, the probability of a sample proportion of non-vaccinated children in a sample of 800 children more than 185/800 is approximately 0.7937, or 0.7936 when rounded to four decimal places.
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(05.01 MC) If sin∠M = cos∠N and m∠N = 30°, what is the measure of ∠M? 150° 90° 60° 30°
Answer:
60 degrees
Step-by-step explanation:
how I got this is due to them giving you an angle along with a right angle, and due to that you can do 90 - 30 = 60 based on complementary angles.
Answer:
60
Step-by-step explanation:
Which of the following numbers can be expressed as decimals that terminate? (1 point) 5 over 2 , 4 over 5 , 2 over 7 , 4 over 3 5 over 2 and 2 over 7 4 over 5 and 4 over 3 5 over 2 and 4 over 5 2 over 7 and 4 over 3
Answer:
all of them are terminating decimals
Step-by-step explanation:
5/2=2.5
4/5=1.25
2/7=3.5
4/5=1.25
4/3=0.75
5/2=2.5
4/5=1.25
2/7=3.5
4/3=0.75
they are terminating decimals because they have a finite end