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Based on the information, it should be noted that the resistance R is 0.5 Ω.

When S1 and S2 are open, i leads e by 30°. In this case, the circuit consists of only the inductor (L) and the capacitor (C) in series. Therefore, the impedance of the circuit can be written as:

Z = jωL - 1/(jωC)

Since i leads e by 30°, we can express the phasor relationship as:

I = k * e^(j(ωt + θ))

Z = jωL - 1/(jωC) = j(120π)L - 1/(j(120π)C)

Re(Z) = 0

By equating the real parts, we get:

0 = 0 - 1/(120πC)

Let's assume that there is a resistance (R) in series with the inductor and capacitor. The impedance equation becomes:

Z = R + jωL - 1/(jωC)

Z = R + jωL

Im(Z) = ωL > 0

Substituting the angular frequency and rearranging the inequality, we have:

120πL > 0

L > 0

This condition implies that the inductance L must be greater than zero.

When S1 and S2 are closed, i has an amplitude of 0.5 A. In this case, the impedance is:

Z = R + jωL - 1/(jωC)

Since the amplitude of i is given as 0.5 A, we can express the phasor relationship as:

I = 0.5 * e^(j(ωt + θ))

By substituting this phasor relationship into the impedance equation, we can determine the value of R. The real part of the impedance must be equal to R:

Re(Z) = R

Since the amplitude of i is 0.5 A, the real part of the impedance must be equal to 0.5 A: 0.5 = R

Therefore, the resistance R is 0.5 Ω.

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that the relative placements of the charges as well as their multiples affect a set of ions' potential energy. When the specific charge have the same sign or have equal signs, the energy is positive. Or else, it is negative.

The force acting just on two objects affects the potential energy formula. The formula for gravitational force is P.E. (= mgh, where g seems to be the acceleration caused by gravity (9.8 m/s2 at the earth's surface) while h represents the elevation in metres.

As a result, the system's potential energy equals the sum of a work that was done to set up the entire system of two counts. The potential energy that exists in the combination of two charges in such an external field can be stated as follows: q1V(r1) = q2V(r2) + (q1q2/4or12).

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Answer:

D. Bulb 2 will go out but bulbs 1 and 3 will remain lit.

Explanation:

If switch at B is opened then, Bulb 2 will go out but bulbs 1 and 3 will remain lit. This is because the positive and negative current flow still fully passes through the two closed switches at switch A and C which allows the bulbs to receive both currents and thus allowing it to turn on. When Switch B is opened it cuts off access for the negative charge to get to bulb 2 and without it, bulb 2 will not turn on.

Answer:all 3 bulbs will go out

Explanation:

Just did it and got it right

Answer:

5

Explanation:

when you move 3 unit to the right your object is at 3.then when you move 4 units to the left your object is at -1 because

a number line also has negative numbers.Then if you move 6 units your object is at 5

a) The capacitance of the ceramic capacitor is approximately 354.16 pF.

b) The potential difference between the plates of the capacitor will be approximately 3.39 x 10^6 volts.

To calculate the capacitance of the ceramic capacitor, we can use the formula:

C = (ε₀ * εᵣ * A) / d

where:

C is the capacitance,

ε₀ is the vacuum permittivity (approximately 8.854 x 10^(-12) F/m),

εᵣ is the relative permittivity of the ceramic (given as 100),

A is the effective plate area (given as 4 cm², which is equal to 4 x 10^(-4) m²),

d is the separation between the plates (given as 0.1 mm, which is equal to 0.1 x 10^(-3) m).

Let's calculate the capacitance in picofarads (pF):

a) Calculation of capacitance (C):

C = (ε₀ * εᵣ * A) / d

= (8.854 x 10^(-12) F/m * 100 * 4 x 10^(-4) m²) / (0.1 x 10^(-3) m)

= (8.854 x 100 x 4) / 0.1

= 354.16 pF

Therefore, the capacitance of the ceramic capacitor is approximately 354.16 pF.

b) To find the potential difference (PD) between the plates when the capacitor is given a charge of 1.2 μC (microcoulombs), we can use the formula:

PD = Q / C

where:

PD is the potential difference,

Q is the charge (given as 1.2 μC, which is equal to 1.2 x 10^(-6) C),

C is the capacitance (calculated in part a) as 354.16 pF, which is equal to 354.16 x 10^(-12) F).

Let's calculate the potential difference (PD):

b) Calculation of potential difference (PD):

PD = Q / C

= (1.2 x 10^(-6) C) / (354.16 x 10^(-12) F)

= 3.39 x 10^6 V

Therefore, the potential difference between the plates of the capacitor will be approximately 3.39 x 10^6 volts.

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(a) At a corresponding hill on Earth and a lesser gravity on planet Epslion, the height of the hill will cause a reduction in the initial speed of the snowboarder from 4 m/s to a value greater than zero (0).

(b) If the initial speed at the bottom of the hill is 5 m/s, the final speed at the top of the hill be greater than 3 m/s.

The effect of height  and gravity on speed on the given planet Epislon is determined by applying the principle of conservation of mechanical energy as shown below;

ΔK.E = ΔP.E

¹/₂m(v²- u²) = mg(hi - hf)

¹/₂(v²- u²) = g(0 - hf)

v² - u² = -2ghf

v² = u² - 2ghf

where;

when u² = 2gh, then v² = 0,

when gravity reduces, u² > 2gh, and v² > 0

Thus, at a corresponding hill on Earth and a lesser gravity on planet Epslion, the height of the hill will cause a reduction in the initial speed of the snowboarder from 4 m/s to a value greater than zero (0).

v² = u² - 2ghf

where;

Since g on Epislon is less than 9.8 m/s² of Earth;

5² - 2ghf > 3 m/s

Thus, if the initial speed at the bottom of the hill is 5 m/s, the final speed at the top of the hill be greater than 3 m/s.

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Answer:

A person is doing push-ups against a wall (action force), and the wall exerts an equal and opposite force against the person (reaction force).

Explanation:

Answer:

I think that a flat fee amount is an amount that is charged or paid that does not change according to the amount of work done, or the number of times something is used

Explanation:

i could be wrong and if i am , i am truly sorry :(

The final momentum of the artist-clay system immediately after collision is -82 kgm/s.

Assuming that the initial momentum of the clay was 3.0 kgm/s and the initial momentum of the potter was -85 kgm/s, we can use the law of conservation of momentum to find the final momentum of the artist-clay system immediately after the collision:

Initial momentum = Final momentum

(3.0 kgm/s) + (-85 kgm/s) = Final momentum

-82 kg×m/s = Final momentum

Therefore, the final momentum of the artist-clay system immediately after the collision is -82 kgm/s.

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There is a difference in total momentum before collision (3.212) and total momentum after collision (32.007).

The total momentum before and after a collision is conserved in an isolated system, meaning that the total momentum of the objects before the collision is equal to the total momentum of the objects after the collision. This is known as the law of conservation of momentum.

The law of conservation of momentum is a fundamental concept in physics that states that the total momentum of a closed system remains constant, unless acted upon by an external force. This law states that the momentum of an isolated system remains constant, regardless of any internal or external forces. The law of conservation of momentum is a consequence of the law of energy conservation and is a fundamental principle in mechanics, and it applies to both linear and rotational motion.

The law of conservation of momentum can be applied to a wide range of physical systems, including collisions between objects, explosions, and the motion of objects in space. In the case of a collision between two objects, the total momentum of the objects before the collision is equal to the total momentum of the objects after the collision, provided there is no external force acting on the system. This law is used to predict the velocity and direction of objects after a collision, as well as the amount of energy transferred during the collision.

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Complete Question: -

What did you notice about the total momentum before the collision and the total momentum after the collision in each of the above cases?

The principle you should have noted in the previous question is called conservation of momentum. What do you think it means to say something is conserved in the context of physics?

The acceleration of the object can be determined using the force exerted and mass. The acceleration of the object is with the mass of 5 kg having a net force of 20 N is 4 m/s².

Acceleration of an object is the rate of change in its velocity. Like velocity, acceleration is a vector quantity thus having both magnitude and direction.

According to Newton's second law of motion, force exerted on an object is the product of its mass and acceleration. Greater the force, the object will be accelerated more.

F = ma

given m = 5 kg

F = 20 N

a = F/m

 = 20 N/ 5 kg

 = 4 m/s²

Therefore, the acceleration of the object is  4 m/s².

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Answer:

Physical change.

A snowflake is still considered water whether its liquid or solid.

Answer:

mark me as brainliest !! PHYSICAL CHANGE

Explanation:

A snowflake is composed of ice, which is water in the solid phase. Water is a chemical compound of oxygen and hydrogen atoms.

If a person wants to calculate the length of time it takes for a ball to fall from a height of 20m, the correct equation that they should use is:

D. Δt= √2Δd/a

The free fall formula should be used to obtain the length of time that it takes for a ball to fall from a given height. This formula also factors the height or distance from which the fall occurred and this is denoted by the letter d. The small letter 'a' is denotative of acceleration due to gravity and this is a constant pegged at -9.98 m/s².

So, the change in height is obtained and multiplied by two. This is further divided by the acceleration and the square root of the derived answer translates to the time taken for the ball to fall from the height of 20m. Of all the options listed, option D represents the correct equation.

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Answer:

The magnitude of displacement vector 2D-E is approximately 14.49 units. The calculation is done using the Pythagorean theorem after finding 2D-E by multiplying vector D by 2 and subtracting vector E.

Explanation:

The value of 2D-E must first be calculated in order to ascertain the displacement 2D-E's magnitude. Vector D may be multiplied by two to accomplish this, and the result can be obtained by deducting vector E:

2D-E = 2(6i + 3j - k) 4i + 5j + 3k = 8i + 11j - 5k - (4i - 5j + 3k) = 12i + 6j - 2k

We can use the Pythagorean theorem to determine the magnitude of the displacement vector now that we know it:

|2D-E| = √(8² + 11² + (-5)²) = √(64 + 121 + 25) = √210 ≈ 14.49

The displacement 2D-E magnitude is therefore 14.49 units or such. From the object's beginning location to its ultimate position, the displacement's entire length is shown by this. Being a scalar variable, the displacement's magnitude does not reveal the displacement's direction.

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The mechanical advantage is the ratio of the length of the effort arm to the length of the resistance arm. Option A is correct.

Mechanical advantage is a measure of the ratio of output force to input force in a system, it is used to obtain the efficiency of the given mechanical machine.

Mechanical advantage is a measure of how much a machine multiplies the input force.

The equation for the mechanical advantage of a lever is;

MA =length of effort arm/length of resistance arm

\(\rm MA=\frac{L_E}{L_R}\)

The mechanical advantage is the ratio of the length of the effort arm to the length of the resistance arm.

Hence, option A is correct.

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The mechanical advantage is the ratio of the length of the effort arm to the length of the resistance arm. Option A is correct.

What is the mechanical advantage?

Mechanical advantage is a measure of the ratio of output force to input force in a system, it is used to obtain the efficiency of the given mechanical machine.

Mechanical advantage is a measure of how much a machine multiplies the input force.

The equation for the mechanical advantage of a lever is;

MA =length of effort arm/length of resistance arm

The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.

The p-waves travel with a constant velocity of 7 km/s

The time can be calculated by using the formula

t = d / v

where

T1 =  10:05 a.m

d is the distance they take to travel from the epicenter

v is the speed of the p-waves

On average, the speed of p-waves is

v = 7 km/s

d = 5600 km (given)

Substituting the values in the formula;

t = d / v

t = 5600 ÷ 7

t = 800 seconds

Converting into minutes,

t = 800 ÷ 60

t = 13.3

≈ 13 mins

T1 -  13 mins = T2

10:05 - 13 mins = 9.52 am

It means the earthquake occurred prior 13 minutes, that is at 9.52 am.

Therefore, the earthquake occurred at 9.52 am.

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Answer:

Explanation:

For intensity of sound in dB scale , the formula is as follows .

intensity in dB = 10 log ( I / 10⁻¹² )

Putting the values given

100 = 10 log ( I / 10⁻¹² )

10 = log ( I / 10⁻¹² )

I / 10⁻¹²  = 10¹⁰

I = 10¹⁰ X 10⁻¹²

I = 10⁻²

I = .01 W /m²

b)

If 3 toadfish are making sound simultaneously ,

Total intensity = 3 x .01 = .03 W / m²

intensity in decibel

= 10 log (3 x 10⁻² / 10⁻¹² )

= 10 log ( 3 x 10¹⁰)

=10 ( 10 + log 3 )

= 10 ( 10 + .477)

= 104.77 dB

Answer:

F = 240 N

Explanation:

Let the mass of the puck, m = 160 g = 0.16 kg

Initial speed, u = 0 (at rest)

Final speed, v = 5 m/s

Time, t = 0.03 s

We need to find the average force on the hockey puck while it is in contact with the stick. Force is given by the formula as follows :

F = ma, a is acceleration

\(F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{0.16\times (45-0)}{0.03}\\\\F=240\ N\)

So, the average force is 240 N.

The kinetic energy of the book after it is slids a distance of 2 meters will be 10 Joules.

The work-energy theorem states that "the work done on an object is the change in its kinetic energy".

Hence;

Kinetic energy = work done

Note that: work-done is expressed as:

Work done = f × d

Where f is force applied and d is distance traveled.

Given that:

Force applied f = 5 newton

Distance d = 2 meters

Work done = ?

Plug these values into the above formula and solve for the workdone.

Work done = f × d

Work done = 5N × 2m

Work done = 10Nm

Work done = 10 Joules

Therefore, the kinetic energy is 10 Joules.

Option B) 10 J is the correct answer.

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Answer: a) To determine how long the ball is in the air, we can use the equation for the vertical motion of an object under constant acceleration due to gravity:

h(t) = h0 + v0t - (1/2)gt^2

where h(t) is the height of the ball at time t, h0 is the initial height (which we can assume to be 0 since the ball is thrown into the air), v0 is the initial velocity (20 ft/s), g is the acceleration due to gravity (32 ft/s^2), and t is the time in seconds.

Since the ball reaches its maximum height when its vertical velocity becomes 0, we can set v0t - (1/2)gt^2 = 0 and solve for t:

v0t - (1/2)gt^2 = 0

20t - 16t^2 = 0

4t(5 - 4t) = 0

Solving for t, we get t = 0 (which is the time when the ball is thrown) or t = 5/4 seconds. However, the time when the ball is thrown is not the time it is in the air, so we discard t = 0. Therefore, the ball is in the air for 5/4 seconds.

b) To determine how high the ball goes, we can use the equation for the maximum height reached by an object under constant acceleration due to gravity:

h_max = h0 + (v0^2)/(2g)

Plugging in the values for h0, v0, and g, we get:

h_max = 0 + (20^2)/(2 * 32)

h_max = 200/64

h_max = 3.125 ft

Therefore, the ball reaches a maximum height of 3.125 ft.

c) To determine the time when the ball is at a height of 3 ft, we can set h(t) = 3 and solve for t:

h(t) = 0 + 20t - 16t^2 = 3

16t^2 - 20t + 3 = 0

We can solve this quadratic equation for t using the quadratic formula:

t = (-b ± √(b^2 - 4ac)) / (2a)

where a = 16, b = -20, and c = 3. Plugging in these values, we get:

t = (-(-20) ± √((-20)^2 - 4 * 16 * 3)) / (2 * 16)

t = (20 ± √(400 - 192)) / 32

t = (20 ± √208) / 32

We can simplify √208 as approximately 14.387, so we get two possible values for t:

t ≈ (20 + 14.387) / 32 ≈ 1.388 seconds

t ≈ (20 - 14.387) / 32 ≈ 0.183 seconds

Therefore, the ball is at a height of 3 ft at approximately 1.388 seconds or 0.183 seconds.

To determine if you will hit the object before coming to a stop, we can calculate the stopping distance of the car and compare it to the range of your headlights. The stopping distance can be calculated using the equation:

d = (v^2) / (2a)

where d is the stopping distance, v is the initial velocity (100 km/h, which can be converted to m/s), and a is the deceleration due to braking (-7 m/s^2).

Converting the initial velocity to m/s:

v = 100 km/h * (1000 m / 1 km) * (1 h / 3600 s) ≈ 27.78 m/s

Plugging in the values for v and a into the stopping distance equation:

d = (27.78^2) / (2 * -7)

d ≈ 111.12 m

Therefore, the stopping distance of the car is approximately 111.12 meters.

Since the range of your headlights is 30 meters, and the stopping distance of the car is greater than 30 meters, the car will hit the object before coming to a stop.

b) The time it takes to stop can be calculated using the equation:

t = v / a

where t is the time to stop, v is the initial velocity (27.78 m/s), and a is the deceleration due to braking (-7 m/s^2).

Plugging in the values for v and a into the time to stop equation:

t = 27.78 / -7

t ≈ -3.97 s

The negative sign in the time indicates that the car is decelerating, or slowing down. However, time cannot be negative in this context, so we can take the absolute value to get the positive time:

|t| ≈ 3.97 s

Therefore, it will take approximately 3.97 seconds for the car to come to a complete stop.

Answer:

 \(\frac{t}{t_p}\) = 2.29

Explanation:

For this exercise as the muon goes at speeds close to the speed of light we must use relativists

          t =\(\frac{t_p}{\sqrt{1- (\frac{v}{c})^2 } }\)

The proper time is the decay time in the reference frame where the muon is fixed ( laboratory), t_p = 2 10⁻⁶ s and the relation

            v / c = 0.90

let's calculate

          t = \(\frac{2 \ 10^{-6} }{\sqrt{1 \ - \ 0.9^2 } }\)2 10-6 / Ra (1 - 0.9²)

          t = 4.59 10⁻⁶ s

the ralation is

          \(\frac{t}{t_p} = \frac{4.59 \ 10^{-6}}{ 2 \ 10^{-6}}\\\)

          \(\frac{t}{t_p}\) = 2.29

A 66.1-kg boy is surfing and catches a wave which gives him an initial speed of 1.60 m/s. He then drops through a height of 1.59 m, and ends with a speed of 8.51 m/s. The nonconservative work done on the boy is approximately -42.7 kilojoules.

To find the nonconservative work done on the boy, we need to consider the change in the boy's mechanical energy during the process. Mechanical energy is the sum of the boy's kinetic energy (KE) and gravitational potential energy (PE).

The initial mechanical energy of the boy is given by the sum of his kinetic energy and potential energy when he catches the wave:

E_initial = KE_initial + PE_initial

The final mechanical energy of the boy is given by the sum of his kinetic energy and potential energy after he drops through the height:

E_final = KE_final + PE_final

The nonconservative work done on the boy is equal to the change in mechanical energy:

Work_nonconservative = E_final - E_initial

Let's calculate each term:

KE_initial = (1/2) * m * v_initial^2

= (1/2) * 66.1 kg * (1.60 m/s)^2

PE_initial = m * g * h_initial

= 66.1 kg * 9.8 m/s^2 * 1.59 m

KE_final = (1/2) * m * v_final^2

= (1/2) * 66.1 kg * (8.51 m/s)^2

PE_final = m * g * h_final

= 66.1 kg * 9.8 m/s^2 * 0

Since the boy ends at ground level, the final potential energy is zero.

Substituting the values into the equation for nonconservative work:

Work_nonconservative = (KE_final + PE_final) - (KE_initial + PE_initial)

Simplifying:

Work_nonconservative = KE_final - KE_initial - PE_initial

Calculating the values:

KE_initial = (1/2) * 66.1 kg * (1.60 m/s)^2

PE_initial = 66.1 kg * 9.8 m/s^2 * 1.59 m

KE_final = (1/2) * 66.1 kg * (8.51 m/s)^2

Substituting the values:

Work_nonconservative = [(1/2) * 66.1 kg * (8.51 m/s)^2] - [(1/2) * 66.1 kg * (1.60 m/s)^2 - 66.1 kg * 9.8 m/s^2 * 1.59 m]

Calculating the result:

Work_nonconservative ≈ -42.7 kJ

Therefore, the nonconservative work done on the boy is approximately -42.7 kilojoules. The negative sign indicates that work is done on the boy, meaning that energy is transferred away from the boy during the process.

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Sound waves are a type of mechanical wave that propagate through a medium, typically air but also other materials such as water or solids.

Frequency: the frequency of a sound wave refers to the number of cycles or vibrations it completes per second and is measured in Hertz (Hz).

Amplitude: the amplitude of a sound wave refers to the maximum displacement or intensity of the wave from its equilibrium position. It represents the loudness or volume of the sound, with larger amplitudes corresponding to louder sounds and smaller amplitudes corresponding to softer sounds.

Wavelength: the wavelength of a sound wave is the distance between two consecutive points in the wave that are in phase, such as from one peak to the next or one trough to the next. It is inversely related to the frequency of the wave.

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The best example of Newton's third law of motion is, When a passenger stepped from a boat to the shore, the boat moved away from the shore. Thus, option C is correct.

Sir Issac Newton gives three laws of motion. The first law states that an object remains at rest or in continuous motion unless an external force acted on it. The second law stated that the force is directly proportional to the acceleration of the object. Newton's third law states that, for every action, there is an equal and opposite reaction.

From the given, Newton's third law is applicable, When a passenger stepped from a boat to the shore, the boat moved away from the shore. This shows the action and reaction of the boat and shore.

Thus, the ideal solution is option C.

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The airplane will strike the ground at a horizontal distance of 490 meters.

To determine how far the airplane will strike on the ground, we need to consider the horizontal distance traveled by the airplane during its flight.

The horizontal distance traveled by an object can be calculated using the formula:

Distance = Speed × Time

In this case, the speed of the airplane is given as 100 meters per second and the time it takes to cover the distance of 490 meters is unknown. Let's denote the time as t.

Distance = 100 m/s × t

Now, to find the value of time, we can rearrange the equation as follows:

t = Distance / Speed

t = 490 m / 100 m/s

t = 4.9 seconds

Therefore, it takes the airplane 4.9 seconds to cover a horizontal distance of 490 meters.

Now, to calculate the distance on the ground where the airplane will strike, we can use the formula:

Distance = Speed × Time

Distance = 100 m/s × 4.9 s

Distance = 490 meters

It's important to note that this calculation assumes a constant speed and a straight flight path. In reality, various factors such as wind conditions, changes in speed, and maneuvering can affect the actual distance traveled by the airplane.

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Answer:

Photoelectric-type alarms aim a light source into a sensing chamber at an angle away from the sensor. Smoke enters the chamber, reflecting light onto the light sensor; triggering the alarm.

Explanation:

nfpa.org is the website with theanswer

ANSWER:

b. 10V

STEP-BY-STEP EXPLANATION:

The number of coils is the same when there are 3, we can see that in this case the voltage is 10 V.

Therefore, the correct answer is b. 10V

The distance travelled by the vehicle around the circular track is 1,052.4 m.

The distance travelled by the vehicle in one complete cycle is calculated by using the following equation as show below.

d = 2πr

d = πd

Where;

In one complete cycle, the  vehicle will travel the circular track only once.

d = π(335 m)

d = 1,052.4 m

Thus, the distance travelled by the vehicle around the circular track is a function of the diameter of the circular track.

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The complete question is below:

A vehicle, starting from rest, accelerates on a circular track with a 335m diameter. What is the distance travelled by the vehicle when it makes one complete cycle?