I need help with this

Step-by-step explanation:

you can check the answer by putting 5 on the place of B... you will get the lateral surface area

118 m²...

hope it helps

Answer:

letters A,B,D

Step-by-step explanation:

hope this helps

Step-by-step explanation:

Σ^n=1 -144 (1/2)n-1

This is a finite geometric series with n

=4, a₁-144, and r = 2.

S = a₁ (1-r") / (1 − r)

S-144 (1 - (1/2)) / (1 - 1/2)

S=-270

If you wanted to find the infinite sum (n

= ∞0)

:S = a₁ / (1 − r)

S-144/(1-1/2)

S=-288

Note that the graph that represents the above situation is: "graph with the x-axis labeled number of classes and the y-axis labeled monthly amount in dollars and a line going from the point (0, 20) through the point (1, 30)" (option a)

The equation is given, y = 10 + 20x, represents the amount the gymnast pays per month (y) for a certain number of classes attended (x). The equation shows that there is a fixed monthly fee of $10 (the y-intercept) plus an additional fee of $20 per class attended (the slope of the line).

To plot this equation on a graph, we can use the number of classes attended (x) as the independent variable on the x-axis and the monthly amount paid (y) as the dependent variable on the y-axis.

When x = 0 (i.e. the gymnast does not attend any classes), the monthly amount paid (y) would be $10 (the y-intercept). When x = 1 (i.e. the gymnast attends one class), the monthly amount paid would be $30 ($10 fixed fee + $20 fee for attending one class).

Therefore, the graph that represents this situation would have the x-axis labeled "Number of classes" and the y-axis labeled "Monthly amount in dollars," with a line going from the point (0, 10) through the point (1, 30). See the graph attached.

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Answer:

Step-by-step explanation:

d + q = 32

.10d + .25q = 5.00

d + q = 32

10d + 25q = 500

-10d - 10q = -320

 10d + 25q = 500

15q = 180

q= 12 quarters

d + 12 = 32

d = 20 dimes

Answer:

Math sucks dude.

explanation: math hard

The following: (a) λ² + (1/4) = 0. (b)  λ = ±√(-1/4). (c)\(e^{j\frac{\pi}{4n}} \quad \text{and} \quad e^{-j\frac{\pi}{4n}}\). (d) Homogeneous response:\(y_h[n] = C_1 \times e^{\frac{j\pi}{4n}} + C_2 \times e^{-\frac{j\pi}{4n}}\), (e) \(x[n] = (1/2)^n \times u[n]\) as the input, (f) input x[n] (g) \(y[n] = y_h[n] + y_p[n].\)

(a) The characteristic polynomial is obtained by assuming a solution of the form \(y[n] = y_h[n] + y_p[n].\) and substituting it into the difference equation.

(b) To find the characteristic roots, we solve the characteristic polynomial for λ. The roots will be complex conjugates with a negative real part, as indicated by the presence of the square root of a negative number.

(c) The characteristic modes arise from the complex roots and are of the form e^(jωn) and e^(-jωn), where ω is the angle of the roots in polar form.

(d) The homogeneous response is the general solution to the difference equation with the initial conditions set to zero, and it contains the characteristic modes.

(e) The impulse response is found by setting the initial conditions y[-1] and y[-2] to zero and solving the difference equation with x[n] = (1/2)ⁿ × u[n] as the input.

(f) The particular response is the solution to the difference equation with the given input x[n], which can be found using appropriate methods like undetermined coefficients or convolution.

(g) The total response is the sum of the homogeneous and particular responses, which gives the complete output of the system for the given input and initial conditions.

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The series on the right-hand side is a convergent p-series with p = 2. Therefore, by the comparison test, the original series converges as well.

To prove that if lim an/bn = 0 and bn is convergent, then an is also convergent, we can use the limit comparison test. Since bn is convergent, we know that its terms approach 0. Therefore, we can choose a positive number ε such that 0 < ε < bn for all n. Then, we have:

lim (an/bn) = 0
=> for any ε > 0, there exists N such that for all n > N, |an/bn| < ε
=> for all n > N, an < εbn

Since ε is a positive constant and bn is convergent, we know that εbn is also convergent. Therefore, by the comparison test, an is convergent as well.

To show that the series ∑(ln n)/(n^3 ln n^1/2 e^n) converges, we can use the comparison test again. Note that:

ln n^1/2 = (1/2)ln n
ln n^3 = 3ln n

Therefore, we can rewrite the series as:

∑[(1/2)/(n^2 e^(ln n))] = (1/2)∑(1/(n^2 n^ln(e)))

Since n^ln(e) > 1 for all n, we have:

(1/2)∑(1/(n^2 n^ln(e))) < (1/2)∑(1/n^2)

The series on the right-hand side is a convergent p-series with p = 2. Therefore, by the comparison test, the original series converges as well.

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Answer:

f= -16

i gotchu

Answer:

f = - 16

Step-by-step explanation:

f - 20 = - 36

f = - 36 + 20

You can use the fact that whenever bases are same, the product of such quantities end up getting their exponents added.

The product result of given expression is \(^5\sqrt{(2x)^4}\)

Suppose you've got two values to multiply with each other and you have got both value's bases same, then the multiplication will end up with result being that base raised with sum of the exponents of both the initial values.

For example:

\(a^b \times ^c =a^{b+c}\)

You can convert the roots to powers. Then you can use the fact that the bases are same and thus the powers will add.

Remember that if you've got xth root, then the power would be 1/x.

For our case, it will go like this:

\(^5\sqrt{4x^2} \times ^5\sqrt{4x^2} = \: ^5\sqrt{(2x)^2} \times ^5\sqrt{(2x)^2} = {((2x)^2)}^{\frac{1}{5}} \times {((2x)^2)}^{\frac{1}{5}} = (2x)^{\frac{2}{5}} \times (2x)^{\frac{2}{5}}\\\\ ^5\sqrt{4x^2} \times ^5\sqrt{4x^2} = (2x)^{\frac{2}{5} + \frac{2}{5}} = (2x)^{\frac{4}{5}} = \: ^5\sqrt{(2x)^4}\)

Thus, the final product result will be written as \(^5\sqrt{(2x)^4}\)

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Applying law of sine and law of cosine, the unknown values x and y are 16.2 units and 37.1 degrees respectively.

To determine the value of x and y in the given triangle, we can use law of sine or law of cosine depending on the variables available and what we need to determine.

Applying law of cosine;

x² = 15² + 10² - 2(15)(10)cos78

x² = 225 + 100 - 300cos78

x² = 225 + 100 - 62.4

x² = 262.6

x = √262.6

x = 16.2 units

From this, we can apply law of sine to determine y;

x / sin X = y / sin Y

Substituting the values into the formula above;

16.2 / sin78 = 10 / sin y

Cross multiply both sides and solve for y;

16.2siny = 10sin78

sin y = 10sin78 / 16.2

sin y = 0.6038

y = sin⁻¹ (0.6038)

y = 37.14°

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Since KI = KE and IT = IE, KITE is a kite, Kites are two sets of quadrilaterals with identical adjacent edges.

KE = √17

IT = 3√5

TE = 3√5

A kite is a quadrilateral having reflection symmetry across a diagonal in Euclidean geometry.

A kite has two equal angles and two pairs of adjacent equal-length sides as a result of its symmetry.

The name "deltoids" can also refer to a deltoid curve, an unrelated geometric object that is occasionally studied in relation to quadrilaterals.

Kites are also known as deltoids. If a kite is not convex, it may alternatively be referred to as a dart.

So, the quadrilateral KITE's vertices are K(0, -2), I(1, 2), T(7,5), and E. (4,-1).

Using the formula for distance:

KE = √(-1 - (-2))² + (4 - 0)² = √17

IT = √(5 - 2)² + (7 - 1)² = 3√5

TE = √(-1 -5)² + (4 - 7)² = 3√5

Therefore, since KI = KE and IT = IE, KITE is a kite, Kites are two sets of quadrilaterals with identical adjacent edges.

KE = √17

IT = 3√5

TE = 3√5

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Answer:the answer is 22/9 or in mixed form would be 2 4/9 but in decimal it’s 2.4 but the 4 is repeated

The samples of size n = 2 that can be drawn from this population is 28

From the question, we have the following parameters that can be used in our computation:

Population, N = 8

Sample, n = 2

The samples of size n = 2 that can be drawn from this population is calculated as

Sample = N!/(n! * (N - n)!)

substitute the known values in the above equation, so, we have the following representation

Sample = 8!/(2! * 6!)

Evaluate

Sample = 28

Hence, the number of samples is 28

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Complete question

A finite population consists of 8 elements.

10,10,10,10,10,12,18,40

How many samples of size n = 2 can be drawn this population?

Answer:

0

Step-by-step explanation:

4x+ 2( 3 – 3x) = 6

4x+6-6x=6

6-2x=6

6-6=2x

0/2=x

x=0

Answer:

\(x=0\)

Step-by-step explanation:

\(4x+2\left(3-3x\right)=6\)

Expand:

\(4x+2\times3-2\times3x=6\)

\(4x+6-6x=6\)

\(-2x+6=6\)

Subtract 6 from both sides:

\(-2x+6-6=6-6\)

\(-2x=0\)

Divide both sides by -2:

\(\frac{-2x}{-2}=\frac{0}{-2}\)

\(x=0\)

They will need 2 5/12 more pounds to reach their goal.

Given the following information as shown:

If their goal is to collect 14 1/2 pounds of food by the end of the month, the remaining food they need to collect will be expressed as:

y =14 1/2 - (6 1/3 + 5 3/4)

y = 14 1/2 - (19/3  + 23/4)

y = 29/2 - (76+69/12)

y = 29/2 - (145/12)

y = 174-145/12

y = 29/12

y = 2 5/12

Hence they will need 2 5/12 more pounds to reach their goal.

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The maintenance cost expected to be incurred during July is $9,400. This corresponds to option C in the given choices.

To determine the maintenance cost expected to be incurred during July, we need to substitute the planned machine time of 9,000 hours into the cost formula Y = $5,800 + $0.40X.

Plugging in X = 9,000 into the formula, we get:

Y = $5,800 + $0.40(9,000)

Y = $5,800 + $3,600

Y = $9,400

Therefore, the maintenance cost expected to be incurred during July is $9,400. This corresponds to option C in the given choices.

The cost formula Y = $5,800 + $0.40X represents the fixed cost component of $5,800 plus the variable cost component of $0.40 per machine-hour. By multiplying the planned machine time (X) by the variable cost rate, we can determine the additional cost incurred based on the number of machine-hours. Adding the fixed cost component gives us the total maintenance cost expected for a given level of machine-time. In this case, with 9,000 hours of planned machine time, the expected maintenance cost is $9,400.

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Answer:

A. Dependent events

Step-by-step explanation:

Sorry if my answer is wrong

Answer:

D. mutually exclusive events

Step-by-step explanation:

When the occurrence is not simultaneous for two events then they are termed as Mutually exclusive events.

Answer:

-32

Step-by-step explanation:

The first four nonzero terms of the Taylor series for f(x) = 5xex, centered at a = 0, are 5x, \(5x^2\), \(5x^3^/^2, 5x^4^/^6.\)

The Taylor series expansion allows us to express a function as an infinite sum of terms, providing an approximation of the function near a specific point. In this case, we are given the function f(x) = 5xex and the center a = 0.

To find the first four nonzero terms of the Taylor series, we need to compute the derivatives of f(x) at x = 0.

Starting with the first derivative, we differentiate f(x) with respect to x, which gives us f'(x) = 5(1+x)ex.

Next, we evaluate the second derivative by differentiating f'(x) with respect to x. This yields f''(x) = 5(2+x)ex.

Continuing this process, we find the third derivative f'''(x) = 5(3+x)ex and the fourth derivative f''''(x) = 5(4+x)ex.

The terms of the Taylor series are obtained by evaluating each derivative at x = 0 and dividing it by the corresponding factorial term. The first four nonzero terms of the series for f(x) centered at a = 0 are 5x, \(5x^2\), \(5x^3^/^2\), and \(5x^4^/^6\).

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Answer:

area of netball court ≈ 467 m²

Step-by-step explanation:

Each of the 3 sections making up the netball court are the same size , then

area of netball court = 3 × 155.55 m² = 466.65 m² ≈ 467 m² ( nearest m² )

Answer:

218.57

Step-by-step explanation:

Since it is an isoceles triangle, the sides are 32, 32, and 14.

Using Heron's Formula, which is Area = sqrt(s(s-a)(s-b)(s-c)) when s = a+b+c/2,  we can calculate the area.

(A+B+C)/2  = (32+32+14)/2=39.

A = sqrt(39(39-32)(39-32)(39-14) = sqrt(39(7)(7)(25)) =sqrt(47775)= 218.57.

Hope this helps have a great day :)

Check the picture below.

so let's find the height "h" of the triangle with base of 14.

\(\begin{array}{llll} \textit{using the pythagorean theorem} \\\\ a^2+o^2=c^2\implies o=\sqrt{c^2 - a^2} \end{array} \qquad \begin{cases} c=\stackrel{hypotenuse}{32}\\ a=\stackrel{adjacent}{7}\\ o=\stackrel{opposite}{h} \end{cases} \\\\\\ h=\sqrt{ 32^2 - 7^2}\implies h=\sqrt{ 1024 - 49 } \implies h=\sqrt{ 975 }\implies h=5\sqrt{39} \\\\[-0.35em] ~\dotfill\)

\(\stackrel{\textit{area of the triangle}}{\cfrac{1}{2}(\underset{b}{14})(\underset{h}{5\sqrt{39}})}\implies 35\sqrt{39} ~~ \approx ~~ \text{\LARGE 218.57}\)

\(\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}\)

Actually Welcome to the Concept of the Inequalities.

so after solving we get as,

1) -5<3x+4<40

2) 2nd quadrant 3π/4<s/2<π

Answer:

Actually Welcome to the Concept of the Inequalities.

so after solving we get as,

1) -5<3x+4<40

2) 2nd quadrant 3π/4<s/2<π

Step-by-step explanation:

Answer:

The distance between points 8 and -5 is 13

Step-by-step explanation:

We need to find distance between points 8 and -5

The formula used to find the distance is: \(Distance=|b-a|\)

Absolute value is used to get only positive values. i.e |-1|=1 if required.

We are given: b=8 and a=-5

Putting values and finding distance

\(Distance=|b-a|\\Distance=|8-(-5)|\\Distance=|8+5|\\Dstance=|13|\\Distance=13\)

So, the distance between points 8 and -5 is 13

The value of segment of the triangle v is x = 2, and the value of u = 2√2.

A right triangle is a triangle with one right angle, while an isosceles triangle is a sort of triangle with two equal-length sides (90 degrees). An isosceles right triangle is one that has a right angle and two congruent sides. An isosceles triangle has two equal-sized angles on either side of its congruent sides. An isosceles right triangle has one angle that is 90 degrees and two congruent angles.

The given triangle is a special triangle with the angle 45-45-90, thus the side lengths are in ratio x : x: x√2.

The value corresponding to angle 45 is 2.

Thus, the value of side v is x = 2, and the value of u = 2√2.

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Anthony's "hiring process" or "recruitment period" was 30 days.

The blank can be filled with "hiring process" or "recruitment period" to indicate the duration between placing the advertisement for a new assistant on November 1 and hiring Marquis on December 1. This period represents the time it took Anthony to evaluate applicants, conduct interviews, and make the decision to hire Marquis.

The hiring process typically involves several steps, such as advertising the job opening, reviewing applications, conducting interviews, and finalizing the selection. The duration of this process can vary depending on various factors, including the number of applicants, the complexity of the position, and the efficiency of the hiring process.

In this case, the hiring process took 30 days, indicating the length of time it took for Anthony to complete the necessary steps and choose Marquis as the new assistant. This duration provides insight into the timeframe Anthony needed to assess candidates and make a hiring decision.

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The area between the x-axis and the curve \(f(x) = x * e^(-x^2)\)over the interval [1, 2] is approximately 0.379.

To find the area between the x-axis and the curve defined by the function \(f(x) = x * e^(-x^2)\)over the interval [1, 2], we can use the definite integral.

The formula to calculate the area using integration is:

Area = ∫[a,b] f(x) dx

Substituting the given function \(f(x) = x * e^(-x^2) and the interval [1, 2]:Area = ∫[1,2] (x * e^(-x^2)) dx\)

To solve this integral, we can use u-substitution. Let's make the substitution:

\(u = -x^2du = -2x dxdx = -du/(2x)\\\)
Now, let's substitute these values back into the integral:

Area = ∫\([1,2] (x * e^u) (-du/(2x))Simplifying further:Area = ∫[1,2] (e^u)/2 duArea = (1/2) * ∫[1,2] e^u duIntegrating e^u with respect to u gives us:Area = (1/2) * [e^u] evaluated from 1 to 2Area = (1/2) * (e^2 - e^1)\)

Using a calculator to evaluate this expression:

Area ≈ 0.379

Therefore, the area between the x-axis and the curve f(x) = x * e^(-x^2) over the interval [1, 2] is approximately 0.379.

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The probability of picking a number beween 2 and 7 from the numbers placed in the bag is 2/5.

Probability is a statistial measure used to determine the chances that a given event would happen. If the event would happen with certainity, it would have a value of 1. If it is certain the event would not happen, it would have a value of 0.

The probability of picking a number beween 2 and 7 = numbers between 2 and 7 / total numbers in the bag

4/10 = 2/5

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Answer:

The correct answer is B. 20,000

Step-by-step explanation:

To determine the man's total monthly salary, we can set up a simple equation using the given information. Let's denote the total monthly salary as "x."

According to the information provided, 33% of the man's monthly salary is equal to Birr 6600. We can express this relationship mathematically as:

0.33x = 6600

To solve for "x," we need to isolate it on one side of the equation. We can do this by dividing both sides of the equation by 0.33:

x = 6600 / 0.33

Evaluating the right side of the equation gives:

x ≈ 20,000

Therefore, the man's total monthly salary is approximately Birr 20,000.

Hence, the correct answer is B. 20,000.