The missing lengths of BE and IJ using the concept of similar quadrilaterals are:
BE = 32
IJ = 18
How to find the lengths of similar quadrilaterals?Similar quadrilaterals are defined as quadrilaterals that have the same shape, but their sizes may vary. Thus, if two quadrilaterals are similar, then their corresponding angles are congruent and corresponding sides are in equal proportion.
From the image, we are told that Quadrilateral GHIJ is similar to Quadrilateral BCDE.
Thus:
GJ/BE = IJ/DE = HI/CD
Thus:
12/BE = 6/16
BE = (16 * 12)/6
BE = 32
Similarly:
IJ/48 = 6/16
IJ = (48 * 6)/16
IJ = 18
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Solve the initial value problem EXAMPLE 1: Solve the initial value problem. dx -10-x, y (0) = -1
The solution to the initial value problem dx/dy = -10-x, y(0) = -1 is y = e-x-10x-10.
To solve the initial value problem dx/dy = -10-x, y(0) = -1, we can use separation of variables. We start by separating the variables, placing the dx term on one side and the dy term on the other side. This gives us dx = -10-x dy.
Next, we integrate both sides of the equation. On the left side, we integrate dx, which gives us x. On the right side, we integrate -10-x dy, which can be rewritten as -10\(e^{-x}\) dy. Integrating -10\(e^{-x}\) dy gives us -10\(e^{-x}\) + C, where C is the constant of integration.
Now, we solve for y by isolating it. We rewrite -10e-x + C as -10 - e-x + C to match the initial condition y(0) = -1. Plugging in the value of y(0), we have -10 - \(e^{0}\) + C = -1. Simplifying this equation, we find C = 9.
Finally, we substitute the value of C back into our equation -10 - \(e^{-x}\) + C, giving us -10 - \(e^{-x}\) + 9. Simplifying further, we get y = -1 - \(e^{-x}\).
Therefore, the solution to the initial value problem dx/dy = -10-x, y(0) = -1 is y = -1 - \(e^{-x}\).
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Let c represent the value of the hypotenuse. if the hypotenuse is c = astartroot 2 endroot, then 6 = astartroot 2 endroot. in inches, what is the value of a? 3 3 startroot 2 endroot 6 3 startroot 2 endroot
If the hypotenuse is c = astartroot 2 endroot, then 6 = astartroot 2 endroot then the value of a in inches would be 3.
What is right triangle ?
A right triangle is a triangle in which one angle is a right angle (90 degrees). The side opposite the right angle is called the hypotenuse, and the two other sides are called the legs. The Pythagorean Theorem states that the square of the hypotenuse is equal to the sum of the squares of the legs.
The given information is that the hypotenuse, represented by c, is equal to the square root of 2. If we set c = √2 and 6 = √2, we can solve for the value of the other side of the right triangle, represented by a.
To solve for a, we can square both sides of the equation 6 = √2:
\(6^{2}\) = \((\sqrt{2} )^{2}\)
36 = 2
So a = 6/√2 = 6/√2 = 3,
If the hypotenuse is c = astartroot 2 endroot, then 6 = astartroot 2 endroot then the value of a in inches would be 3.
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Answer: The correct answer to this question is 3 square root 2
Step-by-step explanation: Lincoln Edge 2023
Samuel measured a house and it’s a lot and made a scale drawing the scale he used was 14 inches:5 feet in the drawling the porch is 56 inches wide what is width of the actual porch
the width of the actual porch will be 20 feet.
What is a rectangle?
Rectangles are quadrilaterals having four right angles in the Euclidean plane of geometry. Various definitions include an equiangular quadrilateral, A rectangle is a closed, four-sided figure in two dimensions. All of a rectangle's angles are equal to 90 degrees, and its opposite sides are equal and parallel to one another. See the shape, sides, and angles of the rectangle in the illustration below.
The scale of the Drawing was 14:5
If the width of the porch is 56 inches then what is the length of the porch
Since the scale of the drawing is 14:5 this implies that ratio of width of drawing and the original is 14:5.
Let x be the original width of porch and the width of the drawing is given as 56 inches, therefore by the given ratio we have
56:x=14:5
x = 56*5/14 = 20 feet
Hence the width of the actual porch will be 20 feet.
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13.10 − Let Mn be the maximum of n independent U(0,1) random variables. a. Derive the exact expression for P(∣Mn−1∣>ε). Hint: see Section 8.4. b. Show that limn→[infinity]P(∣Mn−1∣>ε)=0. Can this be derived from Chebyshev's inequality or the law of large numbers?
This can be derived using Chebyshev's inequality, as Chebyshev's inequality and the law of large numbers are different in nature.
Let M_n be the maximum of n independent U(0, 1) random variables.
To derive the exact expression for P(|M_n − 1| > ε), we need to follow the below steps:
First, we determine P(M_n ≤ 1-ε). The probability that all of the n variables are less than 1-ε is (1-ε)^n
So, P(M_n ≤ 1-ε) = (1-ε)^n
Similarly, we determine P(M_n ≥ 1+ε), which is equal to the probability that all the n variables are greater than 1+\epsilon
Hence, P(M_n ≥ 1+ε) = (1-ε)^n
Now we can write P(|M_n-1|>ε)=1-P(M_n≤1-ε)-P(M_n≥1+ε)
P(|M_n-1|>ε) = 1 - (1-ε)^n - (1+ε)^n.
Thus we have derived the exact expression for P(|M_n − 1| > ε) as P(|M_n-1|>ε) = 1 - (1-ε)^n - (1+ε)^n
Now, to show that $lim_{n\to\∞}$ P(|M_n - 1| > ε) = 0 , we can use Chebyshev's inequality which states that P(|X-\mu|>ε)≤{Var(X)/ε^2}
Chebyshev's inequality and the law of large numbers are different in nature as Chebyshev's inequality gives the upper bound for the probability of deviation of a random variable from its expected value. On the other hand, the law of large numbers provides information about how the sample mean approaches the population mean as the sample size increases.
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thomas, carrie and lenny each captain a different one of three hockey teams. each captain will choose four players from a pool of 12 players, with each player chosen for only one team. how many different ways can the teams be formed?
Answer:
Thomas can choose any 4 out of 12 players, which is \($\binom{12}{4}$\) distinct possibilities for a team. Carrie can choose any 4 out of the remaining 8 players, which is \($\binom{8}{4}$\) distinct possibilities for a team. Lenny has only 1 choice for his team, whichever 4 have not yet been chosen. Combining all this yields
\(\frac{12\times11\times10\times9}{4\times3\times2}\times\frac{8\times7\times6\times5}{4\times3\times2} &= 11\times 10 \times 9 \times 7 \times 5 \\&= 99\times 35\times 10 \\&= (3500-35)\times 10 \\&= \boxed{34,650\text{ ways}}.\)
which theorem or postulate proves that â–³abc and â–³def are similar?
Angle-Angle (AA) similarity postulate, if two angles of one triangle are congruent to two angles of another, then the triangles are similar.
Similar triangles are the triangles that have corresponding sides in proportion to each other and corresponding angles equal to each other. Similar triangles look the same but the sizes can be different.
As per the diagram,
Triangles RPQ & RST are similar since
∠P = ∠S & ∠Q = ∠T
Side - side - side (SSS) similarity theorem - If the lengths of the corresponding sides of two triangles are proportional, then the triangles are similar.
Triangles RPQ & RST are similar since
RP/RS = RQ/RT = ST/PQ
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Unfortunately, due to a couple of pitiful people (some poor kids who got so lost in life, they resulted to spamming), I’m having to repost this:
OK, so I was learning about how to factorize a quadratic polynomial. And I also wrote notes on it. Now, even though I know that my notes are definitely correct, I’m getting stuck at a certain point. Please look at the attached photo, and explain why the variable X and the number 4 have been removed when we get the factors. I’d greatly appreciate it. Thanks!
Answer:
so when factorising, you first remove the common factors. in this case it is (x+3)
so what is remaining is the x and 4
you group that together.
my teacher explained that when factorising, after removing the common factor then you divide each term by the common factor, and then group the answers to that in brackets.
so it will be,
\(x(x + 3) + 4(x + 3) \\ (x + 3)( \frac{x(x + 3)}{x + 3} + \frac{4(x + 3)}{(x + 3)} \)
so basically whats left after dividing, is x and 4 because the x+3 cancel off.
and thats how you get the answer of
(x+3)(x+4)
hope this helps;)
12 in.
14 in.
14 in.
Find the area of the figure above.
[?] square inches please explain how you got the answer for future questions
Answer:
168 square inches
Step-by-step explanation:
A = BH
or
Area = Base x Height
In other words multiply 12 and 14.
If R is the midpoint of ST, SR = 3x + 8, and RT = 5x - 6, find the measure of SR.
how many gallons of gas would it take to drive to the moon and back
Answer:
239 miles per gallon for a round trip.
Step-by-step explanation:
you'd need to achieve 238,900 / 2000 = 119.5 miles per gallon for a one way trip,
C + 15 = 23c + 2 − 43c What is the value of c that makes the equation true?
The value of c that makes the equation true is: c = -13/21.
What is an Equation?An equation is a mathematical statement whose values on the right and left sides are equal.
Given:
c + 15 = 23c + 2 − 43c
Find the value of c
c + 15 = -20c + 2
c + 20c = -15 + 2
21c = -13
c = -13/21
Thus, the value of c that makes the equation true is: c = -13/21.
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The value of c which makes the equation c + 15 = 23c + 2 − 43c true is –13/21
Data obtained from the question c + 15 = 23c + 2 − 43c Value of c =? How to determine the value of cc + 15 = 23c + 2 − 43c
The value of c in the expression above can be obtained as illustrated below:
c + 15 = 23c + 2 − 43c
Collect like terms
c – 23c + 43c = 2 − 15
21c = –13
Divide both side by 21
c = –13/21
Thus, from the calculation made above, we can conclude that the value of c which makes the equation true is –13/21
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HELPPPPPPPPPP
A) 2
B) 3
C) 4
D)5
Answer:
it's b extra words. extra words. extra words. extra words
Step-by-step explanation:
I took the test
Chapter 3 Pythagorean Relationship What is the following square root of x if x= 506
A.
50.6
B.
22.2
C.
24.2
D.
22.4
Answer:
22.4
Step-by-step explanation:
I plugged it into my calculator and i got 22.49 and 22.4 was closest
Please help!!!!!!!!!!!!!!!!
9514 1404 393
Answer:
15
Step-by-step explanation:
Solving for x, we have ...
\(3x+\dfrac{2}{x}-4=2(x+9)-\left(7-\dfrac{1}{x}\right)\\\\3x+\dfrac{2}{x}-4=2x+18-7+\dfrac{1}{x}\\\\\boxed{x+\dfrac{1}{x}=15} \qquad\text{subtract $2x+\dfrac{1}{x}-4$}\)
A bag contains 4 blue balls, 7 yellow balls and 4 white balls. Event A is defined as drawing a blue ball on the first draw and event B is defined as drawing a white ball on the second draw. If two balls are drawn from the bag, one after the other and not replaced, what is P(B|A) expressed in simplest form? A. B. C. D.
P(B|A) expressed in simplest form is 8/105.
What is the probability?Probability determines the chances that an event would happen. The chance of the event happening lies between 0 and 1.
P(B|A) = (number of blue balls / total number of balls) x (number of white balls / total number of balls - 1 )
(4/15) x 4/14 = 8/105
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What is the surface area of this triangular prism?
6.5 ft
6 ft.
11 ft
5 ft
The surface area of this triangular prism is 258 square units
Calculating the surface area of this triangular prismGiven parameter is
The triangular prism
The surface area of triangular prism is calculated as
Surface area = Perimeter * Length + 2 * Base area
Using the given dimensions, we have
Surface area = (5 + 6.5 + 6.5) * 11 + 2 * 5 * 6
Evaluate
Surface area = 258
Hence, the surface area is 258 square units
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Does anyone know what this is :
x + 2 = 3
Answer:
x = 1
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightEquality Properties
Multiplication Property of Equality Division Property of Equality Addition Property of Equality Subtraction Property of EqualityStep-by-step explanation:
Step 1: Define
Identify
x + 2 = 3
Step 2: Solve for x
[Subtraction Property of Equality] Subtract 2 on both sides: x = 1Answer:
X=1
Step-by-step explanation:
x+2=3
PEMDAS= Parenthesis, Exponents, Multiplication, Division, Addition, Subtraction.
X+2=3
X=3-2
X=1
A negative number x a negative number is always positive true or false
Answer:
True.
Step-by-step explanation:
I don't nessicarly know the explanation behind it, but if a negative number is being multiplied by another negative number, the product will always be positive.
Answer:
True.
Step-by-step explanation:
Negative x Negative=Positive.
I'm not sure why, but it's mathematical law.
Hope I helped!
An artist is selling children's crafts necklaces cost 2.25 each, and brackets cost 1.50 per each select all the combinations of necklaces and braclets that the artist could sell for exactly 12.00
Answer: 4 necklaces 2 bracelets. 8 bracelets. 2 necklaces 5 bracelets
Step-by-step explanation:
Section A: Answer any 2 questions from Q1 to Q3 Q1. (a) An office with dimensions of 20 m (L) x 15 m (W) x 4 m (H) has 50 staff. A ventilation system supplying outdoor air to this office at a designed flow rate of 10 L/s/person. The outdoor CO₂ concentration is 300 ppm. The initial concentration of CO₂ in the office is 350 ppm and the CO₂ emission rate from each person is 0.01 L/s respectively. (i) Determine the CO₂ concentration in ppm in the office at the end of the first 3 hours if it is full house. (10 Marks) (ii) Determine the steady state concentration of CO2 in ppm in the office at full house condition. (4 Marks) (iii) Comment on whether any IAQ class can be achieved in the office in accordance with the IAQ Certification Scheme by Environmental Protection Department (EPD). (2 Marks) (iv) If the office is to achieve Excellent Class at steady state in accordance with the IAQ Certificate Scheme, determine the minimum flow rate of outdoor air (in m³ per hour) required for the ventilation system. (3 Marks) Given: C(t)=Coe^-qv 1/v + CvQv+G/Qv (1-e^-Qv 1/v) (b) Renovation works will be carried out for a customer services centre in a high-rise commercial building at Causeway Bay. The renovation contractor is required to implement necessary preventive measures to reduce the environmental nuisance to the adjacent office units on the same floor. Propose FOUR suitable measures to minimize IAQ problems during renovation works. (6 Marks)
The minimum flow rate of outdoor air required is approximately 14400 m³/h. And we can achieve the desired IAQ class depending on the CO2 concentration.
(i) CO2 concentration after 3 hours if it is full house:
To find the CO2 concentration after 3 hours, we need to use the following formula:
\(C(t)=Coe^-qv 1/v + CvQv+G/Qv (1-e^-Qv 1/v)\)
Here, C(t) is the CO2 concentration after time t, Co is the initial concentration, v is the volume of the room, q is the CO2 emission rate per person, Qv is the outdoor airflow rate, and G is the CO2 generation rate per unit time.
We are given that the initial CO2 concentration is 350 ppm, the outdoor CO2 concentration is 300 ppm, the CO2 emission rate from each person is 0.01 L/s, and the designed outdoor airflow rate is 10 L/s/person.
So, we have:v = 20 × 15 × 4 = 1200 m³q = 0.01 L/s/person × 50 person = 0.5 L/sQ
v = 10 L/s/person × 50 person = 500 L/sG = 0 (because no other CO2 source is mentioned)
Therefore,
C(3 hours) = \(350e^-500×3×3600/1200 + 300×500/1200 + 0.5/1200 (1-e^-500/1200×3×3600)\))≈ 1023 ppm
So, the CO2 concentration in the office at the end of the first 3 hours if it is full house is approximately 1023 ppm.
(ii) Steady-state CO2 concentration at full house condition:To find the steady-state CO2 concentration at full house condition, we need to equate the CO2 generation rate to the outdoor airflow rate times the concentration difference:
Qv(C - C0) = G
Here, C is the steady-state CO2 concentration, and C0, Qv, and G are as given above.
So,C = G/Qv + C0 = 0.5 L/s ÷ 500 L/s × 3600 s/h + 300 ppm ≈ 303 ppm
So, the steady-state concentration of CO2 in ppm in the office at full house condition is approximately 303 ppm.
(iii) IAQ class that can be achieved in the office:
The IAQ Certification Scheme by Environmental Protection Department (EPD) requires that the CO2 concentration in an occupied space should not exceed 1000 ppm.
Since the CO2 concentration in the office is less than 1000 ppm at steady-state, any IAQ class can be achieved in the office.
(iv) Minimum flow rate of outdoor air to achieve Excellent Class:
To achieve Excellent Class, the steady-state CO2 concentration must not exceed 800 ppm. So, we need to solve the equation
Qv(800 - 350) = 0.5 L/s
to find the minimum flow rate of outdoor air required:
Qv = 0.5 L/s ÷ 450 ppm × 3600 s/h ≈ 4 m³/s or 14400 m³/h
These results show the importance of proper ventilation in maintaining good indoor air quality, particularly in densely occupied spaces like offices.
Thus, we can conclude that to maintain indoor air quality, proper ventilation plays a very important role. In case of densely occupied places like offices, the minimum flow rate of outdoor air required is approximately 14400 m³/h. And we can achieve the desired IAQ class depending on the CO2 concentration.
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Examine parallelogram RSTU below.
R
S
(6x-9)⁰
(3y-x)°
0
mZR-27⁰
(2y-1)⁰
Om2S-135°
OmZT=45°
OmZU-99⁰
(4x+39)⁰
Determine which of the following values are correct. Select three that apply.
Ox-15
Oy-23
U
T
Answer:
y = 23 , ∠ S = 135° , ∠ T = 45° are correct
Step-by-step explanation:
the opposite angles of a parallelogram are congruent , then
6x - 9 = 4x + 39 ( subtract 4x from both sides )
2x - 9 = 39 ( add 9 to both sides )
2x = 48 ( divide both sides by 2 )
x = 24 ≠ 15
and
3y - x = 2y - 1 , that is
3y - 24 = 2y - 1 ( subtract 2y from both sides )
y - 24 = - 1 ( add 24 to both sides )
y = 23 ← is correct
∠ R = 3y - x = 3(23) - 24 = 69 - 24 = 45° ≠ 27°
∠ S = 6x - 9 = 6(24) - 9 = 144 - 9 = 135° ← is correct
∠ T = ∠ R = 45° ← is correct
∠ U = ∠ S = 135° ≠ 99°
What do the specific types and sequence of amino acids determine the structure and function of?proteinsstarchesnucleic acidslipids
Answer:
Protein structure and function are governed by the exact types and order of amino acids. The arrangement of glucose molecules in starch determines both its structure and its purpose. The particular nucleotide sequence governs the structure and functionality of nucleic acids, such as DNA and RNA. Contrarily, the arrangement of fatty acid chains and other components determines lipids rather than the order of amino acids directly.
Point T T is located at ( − 1 , − 4 ) (−1,−4) on the coordinate plane. Point T T is reflected over the x x-axis to create point T ′ T ′ . Point T ′ T ′ is then reflected over the y y-axis to create point T ′ ′ T ′′ . What ordered pair describes the location of T ′ ′ ? T ′′ ?
Given:
The point is located at (-1,-4).
Point T is reflected over the x-axis to create point T′.
Point T′ is then reflected over the y-axis to create point T′′.
To find:
The ordered pair describes the location of T''.
Solution:
We have, the given point T(-1,-4).
Point T is reflected over the x-axis to create point T′. So, the rule of reflection is
\((x,y)\to (x,-y)\)
\(T(-1,-4)\to T'(-1,4)\)
Point T′ is then reflected over the y-axis to create point T′′. So, the rule of reflection is
\((x,y)\to (-x,y)\)
\(T'(-1,4)\to T''(1,4)\)
Therefore, the ordered pair (1,4) escribes the location of T′′.
Help, please. I'm stuck.
CD is the altitude to side AB of right \(\triangle\)ABC, where m\(\angle\)ACB = \(90^o\) The value of BC is 7.28 units.
What is value?Value in math is a concept that describes the magnitude, or size, of a number. It can refer to absolute value, which is the actual number, or it can refer to relative value, which is the number compared to other numbers. Value is important in math because it is used to compare and measure different quantities. For example, in addition and subtraction, the value of the numbers being added or subtracted determines the answer. In multiplication, the value of the factors determines the product. Value is also important for performing calculations, such as finding averages, which requires knowledge of numbers and their relative values.
The given triangle is a right triangle, with ∠acb as the right angle. Using the Pythagorean Theorem, we can find the length of the side BC. The Pythagorean Theorem states that the square of the hypotenuse (the longest side) is equal to the sum of the squares of the other two sides.
Therefore, BC² = AC² + BD²
Substituting the given values in the equation,
BC² = 52 + (5 1/3)²
Simplifying the equation,
BC² = 25 + 27.69
Therefore, BC² = 52.69
Taking the square root of both sides,
BC = √52.69
Therefore, BC = 7.28 units.
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#1: ZEGF and LBGC are vertical angles.
True
False
I need a answer fast thanks!
Answer:
Chart:
x y
-6 11
3 5
15 -3
-12 15
Step-by-step explanation:
The only things you can plug in are the domain {-12, -6, 3, 15}
Plug in the domain into equation to find y.
-6 :
y = -2/3 (-6) +7
y = +47
y=11
(-6,11)
3:
y = -2/3 (3) +7
y = -2 +7
y = 5
(3, 5)
15:
y = -2/3 (15) +7
y = -10 +7
y = -3
(15 , -3)
-12:
y = -2/3 (-12) +7
y = 8 + 7
y= 15
(-12,15)
Answer:
1) 11
2) 3
3) -3
4) -12
Step-by-step explanation:
eq(1):
\(y = \frac{-2}{3} x + 7\\\\y - 7 = \frac{-2}{3} x\\\\x = (y - 7)\frac{-3}{2} \\\\x = (7-y)\frac{3}{2} ---eq(2)\)
1) x = -6
sub in eq(1)
\(y = \frac{-2}{3} (-6) + 7\\\\y = \frac{12}{3} + 7\\\\y = 4+7\\\\y = 11\)
2) y = 5
sub in eq(2)
\(x = (7-5)\frac{3}{2} \\\\x = 3\)
3) x = 15
sub in eq(1)
\(y = \frac{-2}{3} 15 + 7\\\\y = \frac{-30}{3} +7\\\\y = -10 + 7\\\\y = -3\)
4)
sub in eq(2)
\(x = (7-15)\frac{3}{2} \\\\x = -8\frac{3}{2}\\ \\x = -12\)
The
square below is the image of a square that was dilated by a scale factor of 1. Find
the area of the preimage, the original square, before its dilation. Figures are not
necessarily drawn to scale.
11
Answer:
I'm not really sure what you're asking because there's no image.
Step-by-step explanation:
please try to reword it and maybe show a picture .
One similar figure has an area that is nine times the area of another. The larger figure must have dimensions that are
times the dimensions of the smaller figure.
three
eighteen
eighty-one
nine
Since the area of a similar figure is proportional to the square of its linear dimensions, if one similar figure has an area that is nine times the area of another, the larger figure must have dimensions that are three times the dimensions of the smaller figure.
This is because the area is the square of the linear dimensions. So, if we increase the linear dimensions by a factor of 3, the area increases by a factor of 3^2 = 9.
Therefore, the answer is 3.
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write the equation of the like that is parallel to y=-x-5 and has a y-intercept at (0,11)
Answer:
y = x + 11
Step-by-step explanation:
A line parallel to y = x - 5, intersecting at (0,11) should have slope equal to 1 and y-intercept equal to 11.
So, using y = mx + b , where m is the slope and b is the y-intercept :-
=> y = (1)x + (11)
=> y = x + 11
BRAINLIEST?
PUH-LEEZ.
If someone leave a 20% tip and the meal is 35$how much was the tip
Answer:
$7
Step-by-step explanation:
Since 100/20 = 5, 20% is 1/5, so 20% of 35 is 35/5, or 7
Answer:
If someone leave a 20% tip and the meal is 35$how much was the tip :
$35.00 ÷ 20% = $7.00