I need help with this ASAP.. please and thank you.. I have to get it done

No, this is not a refraction effect. It is a diffraction effect. Every point on the edge of the building's shadow acts as the origin of a new wavefront.

The act of bending light around corners such that it spreads out and illuminates regions, where a shadow is anticipated, is known as the diffraction of light. In general, since both occur simultaneously, it is challenging to distinguish between diffraction and interference. The diffraction of light is what causes the silver lining we see in the sky. A silver lining appears in the sky when the sunlight penetrates or strikes the cloud.

In Young's experiment, a single narrow slit in place of the double slit produced a broad pattern with a bright patch in the middle. Dark and bright sections alternate on either side of the center. As one moves out from the center, the intensity decreases.

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Answer:

56km

Explanation:

168 ÷ 240 = 0.7

0.7 × 80 = 56km

240 is the amount of minutes in 4 hours.

We divided 168 by 240 to get the distance covered in 1 minute. Afterwards, we needed 80 minutes so we multiplied the answer by 80.

Answer:

D hope this helps plz mark brainliest

Explanation:

Answer:

B

Explanation:

Answer:

c. the acceleration is constant and positive

Explanation:

Answer:

i found this i hope it helps

Explanation:

The magnitude of this force depends upon the mass of each object and the distance between the centers of the two objects. Mathematically, we say the force of gravity depends directly upon the masses of the objects and inversely upon the distance between the objects squared.

ANSWER:

pascal (pa) or newton per square metre

It accelerates at about 32 feet per second every second, so it starts falling at zero feet per second and, one second later it is traveling at 32 feet per second. That means that its average speed is 16 feet per second, so it will fall 16 feet in the first second.

True. An object that is translating can have angular momentum with respect to a point that is not its center of mass. This is because angular momentum is a measure of an object's rotation around a certain point, and does not necessarily depend on the object's center of mass.

An object that is translating can have angular momentum with respect to a point that is not its center of mass. This is because angular momentum depends on the reference point chosen.

When an object is translating, its linear momentum may create a rotational effect around a chosen point, thus generating angular momentum even if the point is not its center of mass.

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Answer:

The energy will be increased by a factor 16

Explanation:

Mathematically, we have it that the energy carried by the sound wave is directly proportional to the square of the amplitude

So we have it that;

E = k * A^2

where E is the wave energy

K is the constant value

A is the amplitude value

So;

If E1 = k * (A1)^2

E2 = k * (A2)^2

But A2 = 4A1

E2 = k * (4A1)^2

E2 = k * 16(A1)^2

Divide E2 by E1

E2/E1 = k/k * 16(A1)^2/(A1)^2

E2/E1 = 16

E2 = 16 * E1

so simply, the energy will be increased by a factor of 16

Answer:

Explanation:

It takes 2.916s for the bicyclist to catch the runner and the runner had ran 17.2m with constant velocity of 3.5m/s

How quickly or slowly an object is moving can be determined by its velocity and speed. The need to determine which of two or more moving objects is moving faster arises frequently in our daily lives.

If both vehicles are traveling down the same road in the same direction, it is simple to determine which is moving more quickly.

To tell who is moving faster, though, is challenging if they are moving in the opposite direction. The idea of velocity is valuable in such circumstances

Lets say runner and bicyclist start at a point vi

The distance bicyclist cover to catch runner  is \(S = (v_i)t = \frac{1}{2} at^2\)

As the initial velocity is zero distance \(S = \frac{1}{2} at^2\)

For the runner, distance he could run before bicyclist overpassed him is

S = vt

Now as athletes was 7m ahead so

= (athlete)S  = (bicyclist)S

= (athlete)S = (bicyclist)S - 7

Substitute the values

= vt = \(\frac{1}{2} at^2\)

= 3.5t = \(\frac{1}{2} (2.4)t^2\)

= 3.5t = 1.2t²

= 3.5 = 1.2t

= t = 2.916s

Distance of runner = 3.5 × 2.916s

                                = 10.206 + 7m

                                = 17.2m

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Answer:

The coin will reach the ground first.

Explanation:

Because feather's mass is very low in comparison to a coin and due to air present in earth's atmosphere it will come down slowly.

hope it helps!

Answer:

The coin

Explanation:

Because the coin is heavier than the feather

Light will reflect at the same angle off a smooth surface as when it first touches it. The direction of reflected light beams for a flat surface is the same. Specular reflection is what is happening here.

When light reflects off of a surface, it happens. Light will reflect at the same angle it was incident upon if the surface is glossy and smooth.

A smooth polished surface is what is referred to as a reflection when a light ray strikes it and bounces back. Surface reflection occurs when a light beam hits it and then leaves it.

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Answer: The part of color that's reflected is the red that bounces off the paper.

Hope this helps you!!!

(☞ﾟヮﾟ)☞      ☜(ﾟヮﾟ☜)

Answer:

mass and distance

Explanation:

force is mass while motion can also be regard as distance or movement

Answer:

False

Explanation:

The greater the size of the mass, the greater the size of the gravitational force/energy.

Now, we are going to find the Thevenin equivalent impedance, Zth:First, we will short the voltage source V to get the short-circuit current. So, the circuit becomes:

[ad_1]

Therefore, the current through 10 Ω resistor is:

[ad_1]

Now, we will open the current source I to find the open-circuit voltage, Vth. So, the circuit becomes:

[ad_1]

Now, the voltage across 10 Ω resistor is:

[ad_1]

Therefore, the Thevenin equivalent circuit of the given circuit is as follows:

[ad_1]

Where,

Thevenin equivalent impedance, Zth = 10 + 40 = 50 ΩThevenin equivalent voltage, Vth = 100 V (as we have found it above).Therefore, the Thevenin equivalent circuit is:

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Answer:

velocity of Trinity = 1m/s

Explanation:

Conservation of Momentum equation

m1u1+m2u2=m1v1+m2v2.

m1 = mass of penguin

u1 = initial velocity of penguin

v1 = final velocity of the penguin

m2 = mass of Trinity

u2 = initial velocity of Trinity

v2 = final velocity of trinity

5kg • 8m/s + 40kg • 0m/s = 5kg • 0m/s + 40kg • v2

40kg•m/s = 40kg • v2

divide each side by 40kg

1m/s = v2

Answer:

The answer is D or Fertilizer, sorry for the late answer

Explanation:

Answer:

D Fertilizer hope this helps ..

Explanation:

Answer: 41.9 below the negative x-axis.

Explanation: To find the direction of the resultant vector, we need to use some trigonometry and vector addition. Here are the steps:

Draw a diagram of the particle’s motion and label the vectors. The particle starts at the origin and moves 7.22 cm in the negative y-direction, which we can call vector A. Then it moves 8.05 cm in the positive x-direction, which we can call vector B. The resultant vector R is the vector that goes from the origin to the final position of the particle.

Find the components of vector A and vector B. Vector A has a magnitude of 7.22cm and a direction of 270 degrees (or -90 degrees) from the positive x-axis. Vector B has a magnitude of 8.05 cm and a direction of 0 degrees (or 360 degrees) from the positive x-axis. Using trigonometry, we can find the x and y components of each vector as follows:

A_x = A cos(270) = 7.22 cos(270) = 0

A_y = A sin(270) = 7.22 sin(270) = -7.22

B_x = B cos(0) = 8.05 cos(0) = 8.05

B_y = B sin(0) = 8.05 sin(0) = 0

Add the components of vector A and vector B to get the components of vector R. Using vector addition, we can find the x and y components of the resultant vector as follows:

R_x = A_x + B_x = 0 + 8.05 = 8.05

R_y = A_y + B_y = -7.22 + 0 = -7.22

Find the magnitude and direction of vector R using Pythagoras’ theorem and inverse tangent function. The magnitude of vector R is given by the square root of the sum of the squares of its components, and the direction of vector R is given by the inverse tangent of its y component divided by its x component, as follows:

R = sqrt(R_x^2 + R_y^2) = sqrt(8.05^2 + (-7.22)^2) = sqrt(114.81) = 10.71 cm

theta = tan^-1(R_y / R_x) = tan^-1(-7.22 / 8.05) = -41.9 degrees

Adjust the direction of vector R according to its quadrant. Since vector R is in the fourth quadrant, where both x and y are positive, we need to add 360 degrees to its direction to get a positive angle measured counterclockwise from the positive x-axis, as follows:

theta = -41.9 + 360 = 318.1 degrees

Alternatively, we can express the direction of vector R as an angle measured clockwise from the negative x-axis, which is equivalent to subtracting its direction from 360 degrees, as follows:

theta = 360 - (-41.9) = 401.9 degrees

However, since angles are periodic with a period of 360 degrees, we can subtract multiples of 360 degrees from this angle to get an equivalent angle between 0 and 360 degrees, as follows:

theta = 401.9 - 360 = 41.9 degrees

Therefore, the direction of vector R is either 318.1 degrees counterclockwise from the positive x-axis or 41.9 degrees clockwise from the negative x-axis.

Hope this helps, and have a great day! =)

Block B is moving downwards at a rate of 2 m/s faster than block A is rising upwards.

To answer this question, we need to use kinematic equations to solve for the time it takes for block A to rise 1 meter and the relative velocity of block B with respect to block A at that time.
a) To find the time it takes for block A to rise 1 meter, we can use the following kinematic equation:
d = vi*t + 1/2*a*t^2
Where d = 1 meter, vi = 0 (since block D starts from rest), a = acceleration of motor D, and t = time.
We can rearrange the equation to solve for t:
t = sqrt(2*d/a)
Plugging in the values given, we get:
t = sqrt(2*1/0.6) = 1.29 seconds (rounded to two decimal places)
Therefore, it takes approximately 1.29 seconds for block A to rise 1 meter.
b) To find the relative velocity of block B with respect to block A at this time, we can use the following kinematic equation:
vf = vi + a*t
Where vf = final velocity, vi = initial velocity, a = deceleration of motor C, and t = time.
Since we know that block B is moving downwards, we can assume that its initial velocity is negative (-2 m/s) and its final velocity is 0 (since it stops when it reaches the ground).
Plugging in the values given, we get:
0 = -2 + (-0.4)*t
Solving for t, we get:
t = 5 seconds
Therefore, the relative velocity of block B with respect to block A at this time is:
vfB - vfA = (-2 m/s) - (0 m/s) = -2 m/s
In other words, block B is moving downwards at a rate of 2 m/s faster than block A is rising upwards.

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The equation PE = mgh relates gravitational potential energy to mass, acceleration due to gravity, and height, gravitational potential energy itself is a distinct concept representing the energy associated with an object's position in a gravitational field.

According to the equation PE = mgh, gravitational potential energy (PE) is the product of mass (m), acceleration due to gravity (g), and height (h). However, gravitational potential energy is not the same thing as any of these individual quantities.

Gravitational potential energy refers to the energy possessed by an object due to its position in a gravitational field. It represents the potential for the object to do work when it is released and allowed to fall or move under the influence of gravity.

Mass (m) represents the amount of matter an object contains, acceleration due to gravity (g) represents the strength of the gravitational field, and height (h) represents the vertical distance from a reference point to the object. These quantities are used together in the equation to calculate the gravitational potential energy of the object.

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The number of ticks of the system clock per second depends on the specific system and its clock frequency. However, in general, one gigahertz (GHz) represents one billion ticks of the system clock per second.

A system clock is responsible for synchronizing and controlling the activities of the different components in a computer. It generates a series of electrical pulses, referred to as ticks, that are used to regulate the timing and speed of operations within the computer. The clock speed is measured in GHz, which represents the number of ticks per second. A higher clock speed means that more operations can be carried out in a shorter time, resulting in faster performance. However, it is important to note that clock speed alone does not determine the overall performance of a computer. The prefix "giga-" denotes a factor of 10^9, so one gigahertz corresponds to 1,000,000,000 ticks per second. It is a measure of the clock frequency, indicating how many cycles the clock completes in one second. One gigahertz (GHz) equals one billion ticks of the system clock per second.

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The all forces acting on the steel beam are weight, tension in the cable and air resistance

The forces acting on the steel beam are:

Weight: The force of gravity acting on the steel beam, pulling it downwards.

Tension in the cable: The force exerted by the cable, which is holding the steel beam up and preventing it from falling.

Air resistance: The resistance of the air to the motion of the steel beam.

To draw a free-body diagram of the object, we represent the object as a point and show all the forces acting on it as arrows pointing away from the point. The size of the arrows represents the magnitude of the forces.

The free body diagram is shown in the figure

Where:

T represents the tension force in the cable

W represents the weight force of the steel beam

Note that the air resistance force is usually neglected in such diagrams, as it is often relatively small compared to the other forces.

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(a)  

Use “saturated refrigerant-134a pressure tableâ€, to find $ , h ,           and of refrigerant-134a, at 320kPa (P) .

     \(h_{1} h_{g}\) = 251.93kJ/kg

    \(s_{1} (s_g}\)) =0.93026 kJ/kg-K

    \(v_{1}(v_{g})\) =0.063681 m/kg

we solve \(h_{6}\) ,

\(h_{6}\) = 282.62 kj/kg

\(h_{3} (h_{f)}\) = 127.25 kJ/kg

We use this formula for finding \(Q_{n}\)

\(Q_n} =( h_{2} - h_{3} )\)

      = 38.8 kw

(b)

Find the COP of the heat pump (\(COP_{R}\)) .

(\(COP_{R}\))  = \(q_{L} /w_{in}\)

\(COP_{R}\) = (282.62 -127.25) / (282.62-251.93)

          = 5.06

What is evaporator pressures ?

Valves for regulating evaporator pressure

Although the compressor suction pressure may be lower, evaporator pressure regulation (EPR) valves can be employed in the suction line to prevent the evaporator pressure from dropping below a set or controlled value.

An EPR valve is used for the following tasks:

1. Prevent potential damage to a liquid chilling evaporator from the liquid freezing.

2. Prevent frost from accumulating on an air-cooling evaporator when it is near freezing point or when operation cannot be interrupted by a brief failure.

3. Permit the operation of two or more evaporators with the same compressor at various load temperatures.

4. Vary the evaporator pressure in accordance with a fluctuating load that is managed by the load temperature.

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Extrasolar Neptune-sized planets likely have big compositional differences when compared to our own Neptune because they have measured densities that span a factor of 1000.

Neptune is the fourth-largest planet in our solar system, and it is a gas giant similar to Jupiter, Saturn, and Uranus. An extrasolar Neptune-sized planet (also known as an exo-Neptune) is a planet that is Neptune-sized but orbits a star other than the sun.

Exo-Neptunes are often observed using the transit technique, in which the planet passes in front of the star, causing a small drop in brightness that can be detected by telescopes on Earth. As a result, their densities can be calculated by measuring their mass and size.

Exo-Neptunes have measured densities that span a factor of 1000, meaning that their compositions can be vastly different from that of our own Neptune, which has a density of 1.64 g/cm³. This suggests that they may have different formation histories, be composed of different materials, or have different atmospheric conditions.

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Data set A corresponds to the uniform line of charge and data set B corresponds to the uniformly charged sphere ar e correct . So, option A is the correct answer.

Data set A corresponds to the uniform line of charge because it shows a linear relationship between the electric field strength and the distance from the center of the object. This is characteristic of a uniform line of charge, where the electric field strength is directly proportional to the distance from the center of the line.

Data set B corresponds to the uniformly charged sphere because it shows a non-linear relationship between the electric field strength and the distance from the center of the object. This is characteristic of a uniformly charged sphere, where the electric field strength decreases as the distance from the center of the sphere increases.

Therefore, as per the above explanaions, option A is correct.

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The question is :

Which of the following options correctly identifies which data set corresponds to the uniform line of charge and which one corresponds to the uniformly charged sphere, and provides an explanation for the answer?

A) Data set A corresponds to the uniform line of charge because it shows a linear relationship between the electric field strength and the distance from the center of the object, while data set B corresponds to the uniformly charged sphere because it shows a non-linear relationship between the electric field strength and the distance from the center of the object.

B) Data set A corresponds to the uniformly charged sphere because it shows a non-linear relationship between the electric field strength and the distance from the center of the object, while data set B corresponds to the uniform line of charge because it shows a linear relationship between the electric field strength and the distance from the center of the object.

C) Both data sets correspond to the uniformly charged sphere because they both show a non-linear relationship between the electric field strength and the distance from the center of the object.

D) Both data sets correspond to the uniform line of charge because they both show a linear relationship between the electric field strength and the distance from the center of the object.

In summary, the amount of time a low mass star will stay on the main sequence is determined by its mass, radius, and temperature. Typically, a low mass star will remain on the main sequence for billions of years.

A low mass star is a star that is small in size, mass, and brightness. It is typically around 0.5-2 solar masses and is relatively cool compared to other types of stars. On the main sequence, which is the period when the star is fusing hydrogen into helium in its core, a low mass star can remain for a very long time. The length of time that a low mass star remains on the main sequence is determined by the rate at which it fuses hydrogen into helium in its core. This rate is determined by the star's mass, radius, and temperature. Generally, the lower the mass of the star, the longer it will remain on the main sequence. For example, a star with a mass of 0.5 solar masses will remain on the main sequence for around 20-30 billion years, while a star with a mass of 1 solar mass will remain on the main sequence for around 10 billion years.

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Answer:

the last one

Explanation:

its the sun when the earth turns towards the sun it gives us heat not solar radiation.