Answer:
4
Step-by-step explanation:
( 5x - 6 ) and ( 3x + 2 ) are alternate interior angles.
Alternate interior angles are equal,
So,
5x - 6 = 3x + 2
5x - 3x = 2 + 6
2x = 8
x = 8 / 2
x = 4
What are 1/4 and 1/2 opposites
Answer:
3/4 and 1/2
Step-by-step explanation:
1/4 is one piece out of four. if you want to make the fraction whole, you add 3. therefor, the opposite is 3/4. same thing for 1/2
Find the equation of the purple line.
Answer:
Y-3/5x+2
Step-by-step explanation:
Part A (4 pt): Fill in the missing steps to solve the
Inequality. x+2 +428
-4-4
1/4
1 x+2
-2
2 ≤
1
-X <
- 2
(0) --
x ≤
-X <
√x+2 2.
- 2
1x ≥ 2
=
>
-2
(0) ²½ × ≥ ²
> 2
x 2
Part B (2 pt): Draw the solution to the equation
on the number line provided. (Remember to
include your open/closed dots)
++++
-24-20-16-12 -8 -4
0 4
+
8 12 16 20 24
The answers are:
Part A: The two values of x are: x > 8 or x < -24
Part B: Closed circles at -24 as well as 8 on the number line.
How to solve inequalities?Inequalities are mathematical formulas with two sides that are unequal. In an inequality, we evaluate two numbers rather than two equations. In place of the equal sign, a less than (less than or equal to), larger than (greater than or equal to), or not equal to sign is used.
The following steps are missing for the inequalities:
Solving the inequalities,
Part A:
|1/4x+2|+4 >= 8
|1/4x+2|>=4
Now when we remove the sign fom the inequality, there would be 2 values:
(1/4) x + 2 > 4 or (1/4) x + 2 < -4
Now subtracting 2 from both side:
\((\frac{1}{4} )x > 2\ or\ (\frac{1}{4} )x < -6\)
Divide both the sides by 4:
4(1/4) x > 4(2) or 4(1/4) x < 4(-6)
Now we get two values of x:
x > 8 or x < -24
Part B:
Closed circles at -24 as well as 8 on the number line. Draw a thick line from -24 to the left arrow and a thick line from 8 to the right arrow.
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56. CHALLENGE Let and be two distinct rational numbers. Find the
d
rational number that lies exactly halfway between and & on a number line
The rational number that lies exactly halfway between a/b and c/d on a number line is x = (ad + bc)/2bd or 1/2(a/b + c/d).
How to calculate the mid-value?To calculate the mid-value of two numbers x and y, find the average of these two numbers. I.e., (x + y)/2
Thus, the average of these two numbers is the mid-value between them.
Calculation:It is given that,
a/b and c/d are the two rational numbers on a number line.
Consider the required rational number that lies exactly halfway between a/b and c/d as 'x'.
Then, the mid-value of these two rational numbers is
(a/b + c/d)/2
⇒ (ad + bc)/2bd ...(i)
To know that the obtained rational number is exactly halfway between a/b and c/d, consider the distance from a/b to x and c/d to x.
So, the distance from a/b to x is - "x - a/b" (x > a/b) and
the distance from x to c/d is - "c/d - x"
From the given condition, the above-obtained distances are equal
⇒ x - a/b = c/d - x
⇒ x + x = a/b + c/d
⇒ 2x = (ad + bc)/bd
⇒ x = (ad + bc)/2bd ...(ii)
From (i) and (ii), it is concluded that the required rational number is
x = (ad + bc)/2bd
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Disclaimer: The given question on the portal was incomplete. Here is the complete question.
Question: CHALLENGE: Let a/b and c/d be two distinct rational numbers. Find the rational number that lies exactly halfway between a/b and c/d on a number line.
system of linear equations
3x − y = −11
−x + y = 5
The system of equations has a solution such that x = -3 and y = 2.
To solve the system of linear equations:
3x - y = -11
-x + y = 5
We can use the method of elimination:
Add the two equations together to eliminate y:
3x - y + (-x + y) = -11 + 5
Simplifying:
2x = -6
Divide both sides by 2:
x = -3
Substitute x = -3 into one of the equations to solve for y:
-x + y = 5
-(-3) + y = 5
3 + y = 5
Subtract 3 from both sides:
y = 2
Therefore, the solution to the system of equations is x = -3 and y = 2.
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There is a$1 entry fee to the fair. The cost of each ride is$3. Nareen spends $10 or less. Write an equality to represent the possible number of tickets Naveen purchase. Solve the equality and make a graph. Same for David that spends less than $10 .
Find the ratio of the volume of the triangular prism
to the volume of the cuboid.
Give your answer in its simplest form.
4 cm
20 cm
9 cm
cm
5 cm
6 cm
The ratio of the volume of the triangular prism to the volume of
the cuboid is 3: 20
What do you mean by prism?
A prism is a three-dimensional solid object with identical ends. It is a result of the elements of flat faces, identical bases, and equal cross-sections. The prism's faces are either parallelograms or rectangles without bases.The base of the triangular prime is a right triangle with legs 5 cm, 4 cm
∴ b = 5 cm and h = 4 cm
∵ Its height is 9 cm
∴ H = 9 cm
→ Substitute them in the rule of the prism above
∵ V = 1/2 * (5)(4) × 9
∴ V = 90 cm³
∵ The dimensions of the base of the cuboid are 6 cm and 5 cm
∴ L = 6 cm and W = 5 cm
∵ Its height is 20 cm
∴ H = 20 cm
→ Substitute them in the rule of the cuboid above
∵ V = 6 × 5 × 20
∴ V = 600 cm³
→ Find the ratio between them
∵ V: V = 90: 600
→ Divide each term of the ratio by 30 to simplify them
∴ V: V = 3: 20
∴ The ratio of the volume of the triangular prism to the volume of
the cuboid is 3: 20
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Describe the transformation of f(x) to g(x).
A. f(x) is shifted up 1 unit to g(x).
B. f(x) is shifted down pi/2 units to g(x).
C.f(x)is shifted up pi/2 units to g(x).
D. f(x) is shifted up 2 units to g(x).
The transformation of f(x) to g(x) is (a) f(x) is shifted up 1 unit to g(x).
Describing the transformation of f(x) to g(x).From the question, we have the following parameters that can be used in our computation:
The functions f(x) and g(x)
In the graph, we can see that
The graph of g(x) passes through y = 1The graph of f(x) passes through y = 0So, we have
Difference = 1 - 0
Evaluate
Difference = 1
This means that the transformation of f(x) to g(x) is (a) f(x) is shifted up 1 unit to g(x).
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A map has a scale of 1 inch equals 100 miles. How many inches is 500 miles?
Answer:
wouldn't it be 5 inches. Not 100% sure
Sketch a graph of f(x)={- 5 if x < -2 2x-1 if-2 < x≤ 2 0 if x>2. (piecewise)
A graph of the given piecewise-defined function is shown in the image below.
What is a piecewise-defined function?In Mathematics and Geometry, a piecewise-defined function simply refers to a type of function that is defined by two (2) or more mathematical expressions over a specific domain.
Generally speaking, the domain of any piecewise-defined function simply refers to the union of all of its sub-domains. By critically observing the graph of this piecewise-defined function, we can reasonably infer and logically deduce that it is constant over several intervals or domains such as x > 2 and x < -2.
In conclusion, this piecewise-defined function has a removable discontinuity.
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Will give brainlist but answerquick
Write 5 facts in a complete sentence , with your own words on what you have learned about Terminating Decimals.
Answer:
Basically put the definitions as two separate sentences and then random facts that I remember.
Step-by-step explanation:
A terminating decimal is a decimal that has an end.
A repeating decimal is a decimal fraction in which a number, or a group of numbers, is repeated indefinitely.
Most repeating decimals contain a nine in the denominator, when written in fraction form.
Both can be written in fraction form.
Both can have a positive or negative value that can be both large and small.
what is the answer for d?
Round 2,746 to the tens
Answer:
2750
Step-by-step explanation:
2750. round the six up to zero and the 4 goes up by one making it 2750
6. Find the surface area of the triangular prism.
3
4.
4
5
Answer:
the answer is 345 4 like it literally says it on the paper like how could you not know that like it's on the
What is the period? Please show work.
Answer:
2πl/3
Step-by-step explanation:
find properties of the trigonometric function:
period 2π/3
Write each word phrase as an algebrale
expression for exercises 66-69
66) ten less than a number
67) the product of x andy
The algebraic expression for ten less than n
66) ten less than a number
Let the number be n
= n - 10
67) the product of x and y
= x × y or xy
68) The algebraic expression for ten less than n
= n - 10
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The following table shows scores obtained in an examination by B.Ed JHS Specialism students. Use the information to answer the questions that follow: Score 20-24 25-29 30-34 35-39 40-44 45-49 50-54 55-59 60-64 65-69 Frequency 10 4 10 20 30 15 3 2 1 5.a. Construct a cumulative frequency curve for the data. b. Find the; i. inter-quartile range. ii. 70th percentile class scores. iii. probability that a student scored at most 50 on the examination
Answer:
(a) The cumulative frequency curve for the data is attached below.
(b) (i) The inter-quartile range is 10.08.
(b) (ii) The 70th percentile class scores is 0.
(b) (iii) the probability that a student scored at most 50 on the examination is 0.89.
Step-by-step explanation:
(a)
To make a cumulative frequency curve for the data first convert the class interval into continuous.
The cumulative frequencies are computed by summing the previous frequencies.
The cumulative frequency curve for the data is attached below.
(b)
(i)
The inter-quartile range is the difference between the third and the first quartile.
Compute the values of Q₁ and Q₃ as follows:
Q₁ is at the position:
\(\frac{\sum f}{4}=\frac{100}{4}=25\)
The class interval is: 34.5 - 39.5.
The formula of first quartile is:
\(Q_{1}=l+[\frac{(\sum f/4)-(CF)_{p}}{f}]\times h\)
Here,
l = lower limit of the class consisting value 25 = 34.5
(CF)\(_{p}\) = cumulative frequency of the previous class = 24
f = frequency of the class interval = 20
h = width = 39.5 - 34.5 = 5
Then the value of first quartile is:
\(Q_{1}=l+[\frac{(\sum f/4)-(CF)_{p}}{f}]\times h\)
\(=34.5+[\frac{25-24}{20}]\times5\\\\=34.5+0.25\\=34.75\)
The value of first quartile is 34.75.
Q₃ is at the position:
\(\frac{3\sum f}{4}=\frac{3\times100}{4}=75\)
The class interval is: 44.5 - 49.5.
The formula of third quartile is:
\(Q_{3}=l+[\frac{(3\sum f/4)-(CF)_{p}}{f}]\times h\)
Here,
l = lower limit of the class consisting value 75 = 44.5
(CF)\(_{p}\) = cumulative frequency of the previous class = 74
f = frequency of the class interval = 15
h = width = 49.5 - 44.5 = 5
Then the value of third quartile is:
\(Q_{3}=l+[\frac{(3\sum f/4)-(CF)_{p}}{f}]\times h\)
\(=44.5+[\frac{75-74}{15}]\times5\\\\=44.5+0.33\\=44.83\)
The value of third quartile is 44.83.
Then the inter-quartile range is:
\(IQR = Q_{3}-Q_{1}\)
\(=44.83-34.75\\=10.08\)
Thus, the inter-quartile range is 10.08.
(ii)
The maximum upper limit of the class intervals is 69.5.
That is the maximum percentile class score is 69.5th percentile.
So, the 70th percentile class scores is 0.
(iii)
Compute the probability that a student scored at most 50 on the examination as follows:
\(P(\text{Score At most 50})=\frac{\text{Favorable number of cases}}{\text{Total number of cases}}\)
\(=\frac{10+4+10+20+30+15}{100}\\\\=\frac{89}{100}\\\\=0.89\)
Thus, the probability that a student scored at most 50 on the examination is 0.89.
Which equation represents a linear function
Answer:
Linear equation: y=mx+b
The answer is: y=2x+1 (equation 1)
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Write the equation in exponential form.
Log3 1/9=-2
O 3=9-2
O 1/9=3^-2
O 9=3^2
O 3=3^1
Answer:
a
Step-by-step explanation:
Answer: The correct answer is B. 1/9=3^-2
Step-by-step explanation:
Question 1 of 10
Which expressions are equivalent to the one below? Check all that apply.
log 2-log 4
A. log(¹)
B. log 1
C. log(2) + log(¹)
D. log 2
"The correct option is C." The only expression that is equivalent to log 2 - log 4 is option C: log(2) + log(¹).
The expression "log 2 - log 4" can be simplified using logarithmic properties. Specifically, the property states that "log(a) - log(b) = log(a/b)." Applying this property to the given expression, we have "log 2 - log 4 = log(2/4) = log(1/2) = -log(2)."
The expression log 2 - log 4 can be simplified using logarithmic properties. Let's analyze each option:
A. log(¹): This expression is not equivalent to log 2 - log 4. The logarithm of 1 is 0, but it does not cancel out the terms log 2 and log 4.
B. log 1: This expression is equivalent to 0, but it does not cancel out the terms log 2 and log 4.
C. log(2) + log(¹): This expression is equivalent to log 2 + 0, which simplifies to just log 2. It is not equivalent to log 2 - log 4.
D. log 2: This expression is not equivalent to log 2 - log 4. It represents the logarithm of 2, but it does not account for the subtraction of log 4.
Option C, "log(2) + log(¹)," again uses an exponentiation notation without an exponent and is not a valid mathematical expression.
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01.01
which of the following is an undefined term
1. angle
2. circle
3. plane
4.ray
b = 1/2 a - 3c rearrange to make a the subject
Answer:
\(\huge \boxed{a = 2b + 6c}\)
Step-by-step explanation:
b = 1/2a - 3c
Add 3c to both sides of the equation.
b + 3c = 1/2a - 3c + 3c
b + 3c = 1/2a
Switch sides.
1/2a = b + 3c
Multiply both sides of the equation by 2.
2(1/2a) = 2(b + 3c)
a = 2b + 6c
Step-by-step explanation:
\(b = \frac{1}{2} a- 3c\)
Multiply both sides ✖ of the equation by 2
\(2b = a - 6c\)
Move the variable to the left-hand side and change its sign
\( - a + 2b = - 6c\)
MOVE THE VARIABLE TO THE RIGHT-HAND SIDE AND CHANGE ITS SIGN
\( - a = - 6c - 2b\)
Change the sign on both sides of the equation
\(a = 6c + 2b\)
Therefore the answer is
\(a = 6c + 2b\)
Find the distance d (P1, P2) between the points P, and P2.
P1 = (-2,5); P2 = (4,0)
(P4, P2) - (Type an exact answer, using radicals as needed.)
Answer:
\(\sqrt{61}\) units
Step-by-step explanation:
We are given that
\(P_1=(-2,5)\)
\(P_2=(4,0)\)
We have to find the distance d (P1, P2) between the points P, and P2
We know that
Distance between two points (x1,y1) and (x2,y2) i
=\(\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\)
Using the formula
The distance d (P1, P2) between the points P, and P2
=\(\sqrt{(4-(-2))^2+(0-5)^2}\)
The distance d (P1, P2) between the points P, and P2
\(=\sqrt{(4+2)^2+(-5)^2}\)
The distance d (P1, P2) between the points P, and P2
=\(\sqrt{6^2+25}\)
The distance d (P1, P2) between the points P, and P2
=\(\sqrt{61}\) units
y=3x-11
y-3x=-13
Solving using systems of equations
Answer: There are no possible solutions because
If you were to plot these two equations on the graph you would notice they are parallel because both have the same slope (3x) but still have different intercepts. This means there are no possible solutions as in order to have a solution for x and y they need to intercept and the point of interception is the solution for x and y but that cannot happen in a system of equations that result in parallel lines ( they’ll never intercept)
Answer:
Ø
Step-by-step explanation:
These equations are parallel, meaning they have SIMILAR rate of changes [slopes]. To prove it, convert the second equation from Standard Form to Slope-Intercept Form:
\(\displaystyle y - 3x = -13 \hookrightarrow y = 3x - 13 \\ \\ \left \{ {{y = 3x - 13} \atop {y = 3x - 11}} \right.\)
As you can see, both equations have a rate of change of 3, meaning we CANNOT obtain a solution here, therefore we have no solution.
I am joyous to assist you at any time.
Which linear equation represents the data given in the table?
A) y - 4x-3
B) y - 3x - 4
y = 3x + 4
D) y = 4x + 3
What is this I have no idea
The polynomial fractions in terms of LCD are
a. 3/(x² + x - 2) = 3/(x - 1)(x + 2)
b. x/(x + 2) = x/(x + 2)
What are polynomial fractions?Polynomial fractions are fractions based on polynomials.
a. We desire to write the fraction 3/(x² + x - 2) in terms of its LCD, we then factorize the denominator. Thus,
x² + x - 2 = x² + 2x - x - 2
= x(x + 2) - (x + 2)
= (x - 1)(x + 2)
So, 3/(x² + x - 2) = 3/(x - 1)(x + 2)
b. We desire to write the fraction x/(x + 2) in terms of the LCD, we note that the denominator has only one factor. So, there is only one LCD which is x + 2
So, in terms of LCD
So, x/(x + 2) = x/(x + 2)
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I’m stuck on this. Help!!!
Answer:
the first one
Step-by-step explanation:
Answer:
Step-by-step explanation:
Since all sides are the same they are congruent.
If ya know how to do this help me
The equation of a line that goes through the point (-8, 7) and is parallel to the line (24 -16).
What is the equation of a line?The equation of a line that goes through the point (-8, 7) and is parallel to the line -9x+8and 24.
Two lines have equal slopes if they are parallel to one another. In other words, both equations have an identical ratio of the x and y coefficients.
For any real value of k, the equation for the line perpendicular to the line axe + by + c = 0 is given by axe + by + k = 0.
Thus, a line parallel to the line 9x + 8y - k = 0 has the equation 9x + 8y + k = 0.
We know that this line intersects at (-8, 7), thus 9(- 8) + 8(7) + k = 0 k= -16 Rightarrow
We obtain 9x + 8y - 16 = 0 by substituting k = - 16 in the line equation.
The solution is 0 for 9x + 8y - 16.
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I really need help on this
Answer:
Congruent
Step-by-step explanation:
I am not 100% sure because there are no measurements but it looks like the two shapes are the same size.
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You work in a hardware store. You have two boxes of nails. The first box weighs 6 pounds, 7 ounces, and the second
box weighs 2 pounds, 9 ounces. Which equation can be used to calculate how much the two boxes weigh in
ounces?
O ounces = 16(6 + 2) + 16
O ounces = 16(6 + 2)
O ounces = 16(6 x 2) + 16
O ounces = 16(6 x 2)
O ounces = 16(6+2)
Done
Answer:
ounces = 16(6+2) + 16
Step-by-step explanation:
First you would have to find the conversion rate of pounds to ounces which is 16 ounces for 1 pound. That means that you would have to multiply 16 by the amount of pounds you have. Then you would have to add the amount of ounces you have onto the equation so A would be the one that does that.