I need help with the fraction thing I’m doing

Answer:

y = 5

Step-by-step explanation:

cos 8° = \(\frac{5}{y} \)

(cos 8°)y = \((\frac{5}{y} )\)y

ycos 8° = 5

\(\frac{ycos 8}{cos 8} \) = \(\frac{5}{cos 8} \)

= 5.049137863

rounded to the nearest tenth is 5.0

Answer:

a.) terry didn't line up the triangle correctly. 4/y = 20/18

b.) (20+16)/18

Step-by-step explanation:

for part a, you have to make sure the angles line up correctly (the angle with one tick mark lining up with the angle with one tick mark, the angle with two tick marks lining up with the angle with two tick marks, etc.)

for part b.) you just put the proportional lengths of the bigger triangle in for the lengths of the smaller triangle.

Answer: Check explanation.

Step-by-step explanation: I think its 0. Not sure. Hope this helped!

The number of centimetres in the 1 yard will be 9.144 cm.

Multiplication or division by a numerical factor, selection of the correct number of significant figures, and unit conversion are all steps in a multi-step procedure.

Given that:-

Metric System Units

1 inch = 2.54 centimetres

1 foot = 0.3048 meters

1 mile = 1.61 kilometres

1 yard = 3 feet

1 yard = 36 inches

First, we will calculate 1 yard to feet.

1 yard = 3 feet

1 feet = 0.3048 meters

1 feet = 3.048 centimeters

1 yard = 3 x 3.048 centimeters

1 yard = 9.144 centimeters

Hence, the length of 1 yard in cm is 9.144 cm.

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Using the vertical angles theorem, the equation created is: 3x - 3 = 2x + 13

The value of x = 16.

To solve the problem given, use the vertical angles theorem to create an equation then find the value of x.

(3x - 3)° and (2x + 13)° are vertical angles, therefore, based on the vertical angles theorem, the equation created is:

3x - 3 = 2x + 13

Combine like terms:

3x - 2x = 3 + 13

x = 16

The value of x is: 16.

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Answer:

(4)

Step-by-step explanation:

you times the thing by the thing and then go boom because 3 x 4 - 2 = 10 ez ez gg

Answer:

8 cm

Step-by-step explanation:

24 ÷ 3

Answer:

Step-by-step explanation:

1 yard = 0.000568 miles

49280 yards = 28 miles

1 mile = 1,760 yards

Divide total feet by 1760

49,280 / 1760 = 28 miles.

Answer: Ndndndndmfmfm

Paosisjjs

Step-by-step explanation: its because you have to  like its the answer Hxoaalsksjkaakw

Step-by-step explanation:

x =7-y

subs x in eqn 2

3(7-y)+y=15

21-3y+y=15

21-2y=15

21-15=2y

6=2y

y=6/2

y=3

Interval notation for increasing and decreasing functions is written as (x, y) where x < y for increasing functions, and (x, y) where x > y for decreasing functions.

To write interval notation for increasing and decreasing functions, you need to analyze the behavior of the function's graph.

For an increasing function, as you move from left to right along the x-axis, the y-values of the function's graph increase. In interval notation, you would write this as:

(x, y) where x < y

For example, if the function is increasing from -3 to 5, the interval notation would be (-3, 5).

On the other hand, for a decreasing function, as you move from left to right along the x-axis, the y-values of the function's graph decrease. In interval notation, you would write this as:

(x, y) where x > y

For example, if the function is decreasing from 7 to -2, the interval notation would be (7, -2).

It's important to note that for both increasing and decreasing functions, the parentheses indicate that the endpoints are not included in the interval.

Remember, when using interval notation, always write the x-value first and then the y-value. This notation helps us understand the direction and range of a function.

In conclusion, interval notation for increasing and decreasing functions is written as (x, y) where x < y for increasing functions, and (x, y) where x > y for decreasing functions.

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Answer:

Step-by-step explanation:

3

Answer:

freindly

Step-by-step explanation:

The transformation of f(x) to g(x) is g(x) = (x + 6)² + 4

From the question, we have the following parameters that can be used in our computation:

The functions f(x) and g(x)

Where, we have

f(x) = x²

The translation 6 units left and 4 units up means that

g(x) = f(x + 6) + 4

So, we have

g(x) = (x + 6)² + 4

This means that the transformation of f(x) to g(x) is g(x) = (x + 6)² + 4

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Answer:

Subtract 11 both sides to isolate the variable and it's cooeficient.

Step-by-step explanation:

Given equation:

The main goal to determine the solution of the equation is to isolate the variable that is present in the equation.

(1) Subtract 11 both sides to isolate the variable and it's cooeficient.

(2) Simplify if possible.

(3) Divide the cooeficient (-3) both sides to remove the cooeficient from the variable.

Once the variable has been isolated, the opposite side of the variable will be the solution to the variable.

Step-1: Subtract 11 both sides

Step-2: Simplify (if possible)

Step-3: Divide the cooeficient of x (-3) both sides

Therefore, the first step in simplifying the expression (11 - 3x = 44) is to subtract 11 both sides to isolate the variable and it's cooeficient. When the expression is simplified, we get the solution x = -11.

Based on the relationship of special angles, the values of x are:

1. x = 34

2. x = 9

3. x = 6

Alternate interior angles are equals and corresponding angles are also equal.

Linear pair angles are supplementary.

1. Angles j and a are linear pair angles, therefore:

3x + 15 + 2x - 5 = 180

5x + 10 = 180

5x = 180 - 10

5x = 170

x = 170/5

x = 34

2. Angles m and g are corresponding angles, therefore:

4x + 12 = 2x + 30

4x - 2x = -12 + 30

2x = 18

x = 9

3. Angles c and v are alternate interior angles, therefore:

6x + 9 = 3x + 27

6x - 3x = -9 + 27

3x = 18

x = 6

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Answer:

\( S_{10} = 135\)

Step-by-step explanation:

Given sequence is:

3 + 6 + 9 +...

Here,

a = 3, d = 6 - 3 = 3, n = 10

\(\because S_n = \frac{n}{2} \{2a + (n - 1)d \} \\ \\ \therefore \: S_{10} = \frac{10}{2} \{2 \times 3 + (10 - 1) \times 3\} \\ \\\therefore \: S_{10} = 5 \{6 + 7 \times 3\} \\ \\\therefore \: S_{10} = 5 \{6 + 21\} \\ \\\therefore \: S_{10} = 5 \times 27 \\ \\ \huge \orange{ \boxed{\therefore \: S_{10} = 135}} \\ \\\)

Type I error is We conclude that the mean is not 34 years when it really is 34 years. The correct option to this question is C.

Rejecting the null hypothesis when it is in fact true is a Type I mistake. It entails drawing conclusions about outcomes that are statistically significant when, in fact, they were just the consequence of chance or unrelated causes.

The significance level you select (alpha or ) determines the likelihood that you will make this mistake. You determined that figure at the start of your research to determine the statistical likelihood of getting your results (p-value).

The typical significance level is 0.05 or 5%. If the null hypothesis is accurate, your results only have a 5% chance or less of occurring.

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PLUG IN THE VALUE 4 IN THE PLACE OF Y AND SIMPLIFY

\( = 6(4) - 78 \\ = 24 - 78 \\ = - 54\)

HOPE THIS HELPS

Answer:

1. 0.25

2. 35

Step-by-step explanation:

1. Total probability of all outcomes put together should be 1. So,

P(4) = 1 - ( P(1) + P(2) + P(3) )

  = 1 - ( 0.2 + 0.35 + 0.2 )

 = 0.25

2. If probability for 2 to come up is 0.35, then expected number of 2 after 100 spins will be 100*0.35 = 35.

Answer:

Option B is correct

Step-by-step explanation:

Given: \(\left | p \right |=7\sqrt{2}\,,\,\left | p+q \right |=12\sqrt{3}\)

To find: interval on which \(\left | q \right |\) must fall

Solution:

\(\left | p \right |=7\sqrt{2}\\-7\sqrt{2}\leq p\leq 7\sqrt{2}\,\,(i)\)

\(\left | p+q \right |=12\sqrt{3}\\-12\sqrt{3}\leq p+q\leq 12\sqrt{3}\,\,(ii)\)

Subtract (ii) from (i)

\(-12\sqrt{3}+7\sqrt{2}\leq p+q-p\leq 12\sqrt{3}-7\sqrt{2}\\-12\sqrt{3}+7\sqrt{2}\leq q\leq 12\sqrt{3}-7\sqrt{2}\\\left | q \right |=12\sqrt{3}-7\sqrt{2}\)

So, \(\left | q \right |\) must fall in interval \([12\sqrt{3}-7\sqrt{2},\infty)\)

Therefore, option B is correct.

Answer:

The coordinates of point P are \((-\frac{2}{7}, -\frac{20}{7})\).

Step-by-step explanation:

Point P:

The coordinates of point P are (x,y).

AP=3/7 AB

So

\(P - A = \frac{3}{7}(B-A)\)

We apply this both for coordinate x and coordinate y.

Coordinate x:

\(x - (-2) = \frac{3}{7}(2 - (-2))\)

\(x + 2 = \frac{12}{7}\)

\(x = \frac{12}{7} - 2 = \frac{12}{7} - \frac{14}{7} = -\frac{2}{7}\)

Coordinate y:

\(y - (-2) = \frac{3}{7}(-4 - (-2))\)

\(y + 2 = -\frac{6}{7}\)

\(y = -\frac{6}{7} - 2 = -\frac{6}{7} - \frac{14}{7} = -\frac{20}{7}\)

The coordinates of point P are \((-\frac{2}{7}, -\frac{20}{7})\).

Abc is your answer

Step-by-step explanation:

you said ABC

Answer:

a)polynomial highest degree of polynomial = 5

b) polynomial highest degree of polynomial = 6

c)polynomial highest degree of polynomial = 4

d)polynomial highest degree of polynomial = 1

e) polynomial highest degree of polynomial = 0

f)polynomial highest degree of polynomial = 5

g)polynomial highest degree of polynomial =4

h)polynomial highest degree of polynomial = 8

i)polynomial highest degree of polynomial =6

j)polynomial highest degree of polynomial =4

k)polynomial highest degree of polynomial =8

i)polynomial highest degree of polynomial =4

Hope it helps

If a differentiable function f: ℝ³ ⟶ ℝ has an absolute maximum value K ≠ 0 and an absolute minimum m, then the function f must have a critical point where the derivative of the function is zero (or undefined).

Given that, suppose f : ℝ³ ⟶ ℝ is a differentiable function which has an absolute maximum value K ≠ 0 and an absolute minimum m.

Since f is continuous on a compact set, it follows that f has a global maximum and a global minimum. We are given that f has an absolute maximum value K ≠ 0 and an absolute minimum m. Then there exists a point a ∈ ℝ³ such that f(a) = K and a point b ∈ ℝ³ such that f(b) = m.Then f(x) ≤ K and f(x) ≥ m for all x ∈ ℝ³.

Since f(x) ≤ K, it follows that there exists a sequence {x_n} ⊆ ℝ³ such that f(x_n) → K as n → ∞. Similarly, since f(x) ≥ m, it follows that there exists a sequence {y_n} ⊆ ℝ³ such that f(y_n) → m as n → ∞.Since ℝ³ is a compact set, there exists a subsequence {x_nk} and a subsequence {y_nk} that converge to points a' and b' respectively. Since f is continuous, it follows that f(a') = K and f(b') = m.

Since a' is a limit point of {x_nk}, it follows that a' is a critical point of f, i.e., ∇f(a') = 0 (or undefined). Similarly, b' is a critical point of f. Therefore, f has at least two critical points where the derivative of the function is zero (or undefined). Hence, the statement is true.

Therefore, the above explanation is verified that if a differentiable function f: ℝ³ ⟶ ℝ has an absolute maximum value K ≠ 0 and an absolute minimum m, then the function f must have a critical point where the derivative of the function is zero (or undefined).

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tan( tehta ) = 2/3

Sin( tetha ) = 2/√13

tan( tetha ) + Sin( tetha ) = 2/3 + 2/√13

= 2√13 + 6 / 3√13